We will have that the value will be:
[tex]\Phi=(0.04m^2)(0.0875T)\Rightarrow\Phi=0.00350m^2T[/tex]If F =GMm/R2
What is the dimension of the stress?
What is the unit of frequency?
The dimension of stress is M1 L-1 T-2 and the unit of frequency is Hz.
What is the frequency?
The frequency with which something happens over a specific time frame or sample
Let us find out the dimension of stress.
Stress = Force/Area
Force = mass * acceleration
Stress= M * L * T-2/ L2
Therefore, Stress = M L-1 T-2
As for the second question,
The unit of frequency is Hz (Hertz)
Hence, the dimension of the stress = M L-1 T-2 and the unit of frequency is hertz.
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Investigation Question: How do objects get energy?Claim 1: Objects make their own energy.Claim 2: Objects get energy from other objects that have energy.Pick one of the claims above and provide evidence and reasoning for why you believe it is correct.
Energy can neither be created nor destroyed. It can only be transferred from one object to another.
Claim 2 is correct.
Energy cannot be created or destroyed. So, objects can not make their own energy.
Energy can be transferred or transformed. Energy can be changed in many ways, such as conversion of kinetic energy into potential energy and vice-versa, when one object moves another object, etc.
For example, to lift an object against the gravity, work is done on the object. This work is converted in the form of potential energy, called as gravitational potential energy. When an object, say an apple falls towards Earth from a tree, gravitational potential energy is converted into kinetic energy.
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What does the top pressure gauge in (Figure 1) read? Express your answer using two significant figures.
Digital manometers can be used to measure liquids, gases, and air, depending on the device. If the instruments have an internal memory, it works quite well.
What does the top pressure gauge indicate?Pressure Gauge in Psig Pressure as a percentage of the surrounding atmospheric pressure. The gauge pressure for this kind of pressure includes the pressure from the weight of the atmosphere because it is zero-referenced against atmospheric pressure.
These gauges typically have a measurement range of 0… 1 mbar to 0… 600 mbar and an accuracy class of 0.1 to 2.5. Although pressure gauges typically require very minimal upkeep, problems can happen.
Therefore, This tool can be used to measure pressure in a variety of locations. Measurements of negative pressure, overpressure, and differential pressure are all possible.
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Artificially produced radioactive isotopes are used in medicine and medical research.Question 1 options:TrueFalse
Artificial isotopes are usually absent by nature because of their unstables nature . The Isotopes usually transit into a stable Isotopes. This Isotopes are produced artificially by bombarding an atom.
Artificially radioactive Isotopes produced from stable Isotopes are used in medicine and medical research. Therefore, the answer is True.
Margie, who weighs 624 N, is standing on a bathroom scale that weighs 51.0 N.
With what magnitude force does the floor push up on the scale?
Answer:
675N
Explanation:
624 + 51 = 675N
as the floor exerts and an equal and opposite force.
For a equilibrium shown. There are two strings are strong enough to withstand a maximum tension of 80 n. what is the largest value of w they can support
The largest value of w (in N)that they can support as shown in equilibrium.
What is equilibrium?
a State of balance between opposing forces or actions that is either static as in nobody acted on by forces whose resultant is zero or dynamic reaction when the rates of reaction in both differentions are equal.
Sol- the total force in x direction is given as,
€Fx=0
T1 sin 37°=T2 sin 53°
100×3/5 =T/2 ×4/5
T2=75 N
The given total force is-
€Fy=0
T1 cos 37°=T2 cos 53°+W
W=80×4/5 -75×3/5
W=19N
Thus
The largest value of W is 19N.
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A ball is rolled uphill a distance of 5 meters before it slows, stops and begins to roll back. The ball rolls downhill 6 meters before coming to a rest against a tree. What is the ball's displacement?
We can calculate the displacement using the following formula:
[tex]\begin{gathered} \Delta x=x_f-x_i \\ Where: \\ x_f=Final_{\text{ }}position \\ x_i=Initial_{\text{ }}position \\ so: \\ \Delta x=6m-5m=1m \end{gathered}[/tex]Answer:
1 m
A ball thrown vertically upwards at a speed 30mls.
a)Calculate ,how high a ball will travel when its speed is 20m/s?
b)Calculate the maximum height of the ball will reach ?
c)Find time the ball in air ?
Ball moving vertically upwards,
initial velocity = 30 m/s
final velocity = 0 m/s [ the ball stops after reaching a certain height ]
Applying v = u + at
0 = 30 + 10t [ We divide the course of the object into an uphill travel and a descending journey by assuming there is no friction and that g is equal to 10 m/s². ]
Therefore, t = 3 seconds
By symmetry, the descent will take the same amount of time.
Therefore, the object needs a total of 6 seconds before it returns.
using, H=(v²−u²)/2a
ultimate velocity = 0 m/s (it stops when maximum height is reached)
beginning speed = 20 m/s
a = −g = −9.8m/s² (acceleration owing to gravity, negative sign because it is acting downward)
Replace the values
Obtaining, H=20.408m
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A cannon ball is shot at 10 m/s at an angle of 30 degrees. It takes 2.2 seconds for the ball to reach the ground. (A) How high is the cliff that the cannonball is shot from? (B) How far from the base of the cliff does the ball land?
A ) The height of cliff from which the cannonball is shot from = 12.72 m
B ) The distance from the base of the cliff = 19.14 m
- H = [tex]u_{y}[/tex] T - 1 / 2 g T²
T = Total time taken
g = Acceleration due to gravity
H = Height above the ground
[tex]u_{y}[/tex] = Y-component of initial velocity
T = 2.2 s
g = 9.8 m / s²
θ = 30°
u = 10 m / s
[tex]u_{y}[/tex] = u sin θ
[tex]u_{y}[/tex] = 10 * sin 30°
[tex]u_{y}[/tex] = 5 m / s
- H = ( 5 * 2.2 ) - ( 0.5 * 9.8 * 2.2 * 2.2 )
- H = 11 - 23.72
H = 12.72 m
R = [tex]u_{x}[/tex] T
[tex]u_{x}[/tex] = u cos θ
[tex]u_{x}[/tex] = 10 * cos 30°
[tex]u_{x}[/tex] = 8.7 m / s
R = 8.7 * 2.2
R = 19.14 m
Therefore,
A ) The height of cliff from which the cannonball is shot from = 12.72 m
B ) The distance from the base of the cliff = 19.14 m
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What happens when data stored digitally are copied?
OA. Each copy made has worse quality than the original data did.
B. Data are copied quickly, easily, and perfectly.
C. Only one value of the digital data is copied perfectly.
D. Data are copied quickly, but they decrease in quality.
When data stored digitally are copied then data are copied quickly, easily, and perfectly.
Data stored digitally are quickly, easily and perfectly copied.
There is no effect on the quality of the data.It just copies the data exactly as the source and it is same with any other file type. The quality would only decrease if the file is transcoded to a different format or to the same format with a different data stream.Data is a collection of quantities, photos or videos, signs or symbols, on which operations are performed by a computer, which can be stored and transmitted in the form of electrical signals and recorded on magnetic, optical or mechanical recording media.
When you copy (or transfer) a file of any type - JPG or TIFF or RTF or DOC or PSD or whatever, you won't lose any quality.Since no quality of the file is lost, copying a data is an easy, quick and a perfect process.
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Best player in nba right now
Best player in NBA right now Giannis Antetokounmpo.
The National Basketball Association, NBA is a professional basketball league in North America. The league consists of 30 teams and is one of the predominant expert sports activities leagues within the united states of America and Canada. It's far the finest guys professional basketball league within the international.
To sell great aware device of technical education where excellence, relevance to market desires and participation with the aid of all stakeholders are prime and principal determinants.
The NBA is a 70-year-vintage employer born from innovation. It turned into June 1946 in the big apple city while Boston garden owner Walter Brown found out that primary ice hockey arenas, which were vacant maximum nights, will be used to host basketball games.
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A car of mass m = 1090 kg is traveling down a θ = 11 degree incline. When the car's speed is v0 = 16 m/s, a mechanical failure causes all four of its brakes to lock. The coefficient of kinetic friction between the tires and road is μk = 0.45.
Calculate the distance the car travels down the hill L in meters until it comes to a stop at the end.
The distance the car of mass 1090 kg travels with a velocity of 16 m / s down the hill having a 11 degree decline until it comes to a stop at the end is 52 m
θ = 11°
m = 1090 kg
g = 9.8 m / s²
μ[tex]_{k}[/tex] = 0.45
W = m g
W = 1090 * 9.8
W = 10682 N
Resolving W into its horizontal and vertical components,
[tex]W_{y}[/tex] = W cos θ
[tex]W_{y}[/tex] = 10682 * cos 11°
[tex]W_{y}[/tex] = 10682 * 0.98
[tex]W_{y}[/tex] = 10468.36 N
[tex]W_{x}[/tex] = W sin θ
[tex]W_{x}[/tex] = 10682 * sin 11°
[tex]W_{x}[/tex] = 10682 * 0.19
[tex]W_{x}[/tex] = 2029.58 N
N = [tex]W_{y}[/tex]
N = 10468.36 N
F[tex]_{k}[/tex] = μ[tex]_{k}[/tex] N
F[tex]_{k}[/tex] = 0.45 * 10468.36
F[tex]_{k}[/tex] = 4710.76 N
∑ [tex]F_{x}[/tex] = m a
[tex]W_{x}[/tex] - F[tex]_{k}[/tex] = m a
2029.58 - 4710.76 = 1090 * a
a = - 2681.18 / 1090
a = - 2.46 m / s²
Acceleration is negative because the car is decelerating in positive direction.
v² = u² + 2 a s
0 = 16² + ( 2 * - 2.46 * s )
4.92 s = 256
s = 52 m
Therefore, the distance the car travels down the hill is 52 m
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why does air pressure decreases with height more rapidly in cold air than in warm air?
the colder air is more dense, then you would go through more mass (density) in a shorter vertical distance,
Explanation
Consider cold and warm air columns with equal weights, and equal amounts of overlying air.
Colder air is denser because the molecules of air are more closely packed together. As a result, pressure decreases more rapidly as you ascend through cold air than through warm air
It takes a shorter column of cold air to exert the same pressure as a taller column of warm air.
so,Since the colder air is more dense, then you would go through more mass (density) in a shorter vertical distance,
Suppose a 60.0-kg gymnast climbs a rope. (a) What is the tension in the rope if he climbs at a constant speed? (b) What is the tension in the rope if he accelerates upward at a rate of 1.50 m/s2?
Use the Newton's Second Law of Motion to find the tension in the rope on each case.
a)
Since the gymnast climbs at a constant speed, then the net force acting on the gymnast must be 0. Since there are only two forces acting on the gymnast, namely the tension of the rope and the weight of the gymnast, then:
[tex]\begin{gathered} F_N=T-W=0 \\ \Rightarrow T=W \end{gathered}[/tex]On the other hand, the weight of the gymnast is equal to the product of its mass times the acceleration of gravity, g=9.81m/s^2:
[tex]\begin{gathered} W=mg \\ =(60\operatorname{kg})(9.8\frac{m}{s^2}) \\ =588N \end{gathered}[/tex]Then, the tension of the rope is:
[tex]T=588N[/tex]b)
The forces acting on the gymnast are 2: the tension of the rope and the gravitational pull:
[tex]F_N=T-W[/tex]From the second law of motion, we know that the net force acting over an object of mass m produces an acceleration a given by:
[tex]F_N=ma[/tex]Then:
[tex]\begin{gathered} T-W=ma \\ \Rightarrow T=W+ma \end{gathered}[/tex]Substitute W=588N, m=60kg and a=1.50 m/s^2 to find the tension of the rope:
[tex]\begin{gathered} T=588N+(60\operatorname{kg})(1.5\frac{m}{s^2}) \\ =588N+90N \\ =678N \end{gathered}[/tex]Therefore, the answers are:
[tex]\begin{gathered} a)T=588N \\ b)T=678N \end{gathered}[/tex]1. An ordinary light bulb is marked “60A, 120V”, its resistance is ______.
In order to calculate the resistance, we can divide the voltage and the current, according to the formula below:
[tex]R=\frac{V}{I}[/tex]Where R is the resistance (in ohm), V is the voltage (in Volt) and I is the current (in Ampere).
So, using V = 120 V and I = 60 A, we have:
[tex]R=\frac{120}{60}=2\text{ ohms}[/tex]Therefore the resistance is 2 ohms.
How many hours would it take a plane to fly 1,500 miles if it was moving at a constant speed of 300 miles/hour. Include units!
Brainliest included
Maria is doing a report on Mathieu Orfila. What fact is she MOST likely to include in her report?
.
AHe solved the first crime that used medical evidence.
BHe studied fingerprints and started to classify them.
CHe was the first person to use bullet comparisons.
DHe explored how poisons affected animals.
??
Answer:
Its B
Explanation:
Answer:
She is most likely to include that he explored how poisons affected animals.
Explanation:
What is the speed at the bottom of the funnel?
We will have the following:
[tex]\begin{cases}I=r^2m \\ \\ L=I\omega \\ \\ \omega=v/r\end{cases}[/tex]So:
We will find the data we can with the given information:
[tex]\omega_1=\frac{0.3m/s}{0.2m}\Rightarrow\omega=\frac{1.5}{s}[/tex]Also:
[tex]I\omega_1=I\omega_2\Rightarrow\omega_1=\omega_2[/tex]So:
[tex]\frac{1.5}{s}=\frac{v}{0.03m}\Rightarrow v=0.045m/s[/tex]So, the velocity at the bottom of the funnel is 0.045m/s.
I can not understand the closed circle and open circle. Please help!
First, take into account that the open circle means that the point is not included into the domain and the range. The closed point means that such a point is included into both domain and range.
In this case, althoug there is a open circle, there is another part of the curve on which the y value is included into the path.
Then, the range of the graph is:
ran f = [2,7]
Which is equivalent to all number from 2 to 7.
If a spring is stretched 4m from its starting length when 20n of force is applied, then how much work (in joules) is done by the spring when it is stretched 10 m?
ANSWER:
250 J
STEP-BY-STEP EXPLANATION:
F = 20N is required to stretch the spring by 4 meters
We know that the force is equal to:
[tex]F=k\cdot x[/tex]We solve for k (spring constant):
[tex]k=\frac{F}{x}=\frac{20}{4}=5\text{ N/m}[/tex]The work done in stretching the spring is given by the following equation (in this case the stretch is 10 meters:
[tex]\begin{gathered} W=\frac{1}{2}k\cdot x^2 \\ \text{ Replacing} \\ W=\frac{1}{2}\cdot5\cdot10^2 \\ W=250\text{ J} \end{gathered}[/tex]The work required is 250 joules.
The differences in air pressure that create a sound wave are the result of differences in the velocities of air particles. Is this true or false?
ANSWER:
true
STEP-BY-STEP EXPLANATION:
The differences in air pressure that create a sound wave are the result of differences in the velocities of the air particles. Due to the Doppler effect, an observer will hear a sound that moves away from her and has a higher pitch. Sound waves will travel faster on a dry day than on a humid day of the same temperature.
Therefore, the statement is true
An oscillator is used to create a wave on a string. The frequency of the oscillator is 4 Hz and the waves measures to be 0.5 m apart. What is the speed of the wave
Given,
Frequency of the wave, f=4 Hz
The wavelength of the wave, λ=0.5 m
The speed of a wave is given by,
[tex]v=f\lambda[/tex]On substituting the known values in the above equation,
[tex]v=4\times0.5=2\text{ m/s}[/tex]Therefore the speed of the standing wave produced is 2 m/s
How did Buddhism and the Maury and contribute to technology in ancient India?
During the Maurya empire, the Indian lifestyle and manner of existence had been deeply stimulated by Buddhism. Buddhism appealed to human beings of decreased castes because it emphasized individuals' course to enlightenment and salvation, which might be attained in this existence.
The Maurya Empire's political cohesion and inner peace endorsed the expansion of trade in India. at some stage in Ashoka's reign, authorities oversaw the building of essential roadways, and the Mauryan international network of exchange multiplied. India's exports to places like Bactria and Persia blanketed silk, textiles, and spices.
The Maurya Empire become centralized through the conquest of the Indo-Gangetic simple, and its capital town become located at Pataliputra (current Patna). outdoor this imperial middle, the empire's geographical volume became dependent on the loyalty of military commanders who managed the armed towns sprinkling it.
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Can you please explain to me what answer would be correct and how?
Newton's third law states that; with every action, there is a direct and opposite reaction. As you walk across the flooor, you are applying a force due to your weight on the floor. The floor would apply an an equal force onto your feet which is in opposite direction and this force pushes you forward. This force is called th normal force. Thus, the correct option is
d)
While experimenting with electromagnets, students oriented two like you see in the diagram here. Predict what will happen and explain
why.
A The two electromagnets will repel; the poles repel.
B The two electromagnets will repel; the electrical current forces them away from each other.
C The two electromagnets will attract; opposite poles attract
D Nothing will happen; electromagnets do not behave like typical bar magnets.
Answer:
C The two electromagnets will attract; opposite poles attract
Explanation:
Electromagnets behave like regular magnets - they have two poles - positive and negative
Like regular magnets, opposite poles attract, similar poles repel
Joe is carrying a load of supplies and likely injuring his back by supporting 882 N of weight. Calculate the mass of what he is carrying.
Since the load Joe is carrying is equal to the supporting weight, the mass of the load will be 90 Kg
What is Weight ?Weight is the gravitational pull of an object under the influence of acceleration due to gravity.
Given that Joe is carrying a load of supplies and likely injuring his back by supporting 882 N of weight.
The load Joe is carrying will be equal to 882 N
To calculate the mass of what he is carrying, let us use the formula
W = mg
Where
Weight W = 882 NAcceleration due to gravity g = 9.8 m/s²Mass m = ?882 = 9.8m
m = 882/9.8
m = 90 Kg
Therefore, the mass of what he is carrying is 90 Kg
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After being pushed away from the departure gate, an aircraft is standing still with the brakes applied and the engine running on very low. When the pilot releases the brakes he finds that the plane still does not start to move. Here are three explanations for why the plane does not move. Which one do you agree with?
Since he pilot releases the brakes and he finds that the plane still does not start to move, the explanation I agree with is option C:
When the pilot releases the brakes two forces act on it. The engines exert a force in one direction and the ground exerts a force on the wheels in the opposite direction. The plane does not move because the force exerted by the ground on the wheels is the same strength as the force of the engines.How do planes fly and stay in the air?The lift of the airplane is provided by the flow of air around the wings. Additionally, the wings' form contributes to lift. The airplane is being pulled toward Earth by weight. The weight of an airplane is distributed evenly from front to back during construction.
Note that the design of an airplane wing is intended to speed up airflow across the top of the wing. Air pressure decreases when it moves more quickly. Therefore, the pressure at the top of the wing is lower than that at the bottom. The pressure differential exerts a force on the wing, lifting it into the air.
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See full question below
After being pushed away from the departure gate, an aircraft is standing still with the brakes applied and the engine running on very low. When the pilot releases the brakes he finds that the plane still does not start to move. Here are three explanations for why the plane does not move. Which one do you agree with?
A. When a single force that is too weak acts on an object it will not move. When the pilot releases the brakes the only force acting on the plane is that of the
engines but because this force is too weak, the plane will not move.
B. When the pilot releases the brakes two forces act on it. The engines exert a force in one direction and the ground exerts a force on the wheels in the opposite direction. The plane does not move because the force exerted by the ground on the wheels is stronger than the force of the engines.
C. When the pilot releases the brakes two forces act on it. The engines exert a force in one direction and the ground exerts a force on the wheels in the opposite direction. The plane does not move because the force exerted by the ground on the wheels is the same strength as the force of the engines.
The contestant now pulls the block of ice with a rope over his shoulder at 25 degrees. Calculate the minimum force F he must exert to get the block moving. (b) What is its acceleration once it starts to move, if that force is maintained?
The minimum force that the contestant must exert to get the block moving is 53.33 N and the acceleration of the block is 0.874m/s² once it starts to move and the force is maintained.
When a force is applied at an angle, the force will have two components, one along the floor and one along the vertical.
If the force is F applied at an angle θ, then the vertical component of force is Fsinθ and the floor component is Fcosθ.
In out case θ = 25°,
A.) There will we a frictional force acting on the body which will be opposite to the component of the force which is along the floor, if the floor component just overcomes the static frictional force than the block will start to move.
So, we can write,
Friction force = Fcosθ
μN = Fcosθ
where,
μ is the coefficient of static friction,
N is the normal reaction by the floor on the block which would be equal to the mg,
F is the minimum force Applied.
Putting all the values,
(0.1)(10)(48) = (F)(cos25°)
48 = F(0.9)
F = 53.33 Newtons.
B.) When the block will start moving,
There will be a kinetic frictional force on it as well as a Fcosθ on it,
The friction will be opposite direction of the motion, Fcosθ will be in the direction of the motion,
So, we can write, The net force on the body
F = Fcosθ - Fr
F = Fcosθ - μN
F = Fcosθ - umgsinθ
When the box is moving the normal reaction N will be equal to the vertical component of the force,
Here, u is the coefficient of kinetic friction,
Putting all the values,
F = 48 - 0.03x10x48x0.42
F = 48 - 6.048
F = 41.95 N
we can also write,
F = ma
where a is the acceleration of the block and m is the mass of the block,
41.95 = 48a
a = 0.874m/s².
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A contestant in a winter games event pushes a 48 kg block of ice across a frozen lake with a rope over his shoulder at a 25 degree angle.
The coefficient of static friction is 0.1 and the coefficient of kinetic friction is 0.03.
A.) Calculate the minimum force F (in N) he must exert to get the block moving.
B.) What is its acceleration (in m/s^2) once it starts to move, if that force is maintained?
Which of the following is true when the kinetic energy of the particles in a sample of matter is lowered?The temperature increases.bThe temperature decreases.cThe sample will absorb less heat.dMore heat flows away from the sample.
Answer: The temperature decreases.
The intern energy is shown with the movement of particles, if the lower the speed then the intern energy decrease, and the temperature too.
Answer: More heat flows away from the sample
This one can be true, when they stop moving the heat (temperature) decreases and that heat energy flows away.
Both are so similar, but the most accurate is the temperature decrease because the heat flows a part away not totaly
The carbon monoxide molecule (CO) consists of a carbon atom and an oxygen atoms separated by a distance of 1.13x10^-10 m, The mass mc of the carbon atom is 0.750 times the mass mo of the oxygen atom, or mc= -0.750mo , Determine the location of the center of the mass of this molecule relative to the carbon atom.
The location of the centre of the mass of the CO molecule relative to the carbon atom is 6.46 ×10⁻¹¹ m.
What is the centre of mass of the molecule?The Centre of Mass of that object is a position that is relative to an object or a system of objects. The average position of all parts of the system that are weighted to their masses is known as the Centre of Mass.
Given, the distance between the carbon and oxygen atoms, r = 1.13 ×10⁻¹⁰m.
The ratio of the mass of the carbon and oxygen:
Mc/Mo = 12/16 = 0.750
Consider that Xc is the position of carbon and Xo is the position of the oxygen atom in CO molecule.
The centre of the mass of the system is equal to the:
[tex]X_{co}=\frac{M_CX_C+M_OX_O}{M_C+M_O}[/tex]
[tex]X_{co}=\frac{(M_C/M_O)X_C+X_O}{M_C/M_O+1}[/tex]
As we are calculating the centre of the mass relative to the carbon atom.
Therefore Xc = 0 and Xo= 1.13 ×10⁻¹⁰m.
[tex]X_{CO} =\frac{1.13\times 10^{-10}}{0.750 +1}[/tex]
Xco = 6.46 ×10⁻¹¹ m
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