Given: A, C, and F are collinear
Prove: measure of angle s= measure of angle x+measure of angle y

Answer:

[tex]f(x)=-2^x[/tex]

Step-by-step explanation:

So generally an exponential equation is expressed in the form: [tex]f(x)=a(b)^x[/tex] and: [tex]b=1+r\text{ or }b=1-r \text{ depending on whether it's decaying or growing}[/tex]. In this case we see that as x increased by 1, the y-decreases, BUT the absolute value is increasing, so it's really just reflected.

Plug in known values:

[tex]-2=a(b)^1[/tex]

[tex]-4=a(b)^2[/tex]

So if you think about it. you really have

-2 = a * b

-4 = a * b * b

since ab = -2, then we can substitute this into the second equation

-4 = -2 * b

-4 = -2b

Divide both sides by -2

b = 2

You can also deduce that b=2, by realizing to go from -2 to -4, you have to subtract 100% of -2 from -2. This means r=1, so b=1+1, b=2

Anyways, now it's time to solve for a, by plugging in a point as well as b.

-4 = a(2)^2

-4 = 4a

-1 = a

You can verify this by using the other point

-2 = -(2)^1

-2 = -(2)

-2 = -2

So the equation is: [tex]f(x)=-2^x[/tex]

[489.68, 510.32] is the confidence interval for the average amount spent on textbooks in a year if the desired level of confidence is 99%.

n=400

sample mean (x)=500

sample standard deviation (s)=80

99% confidence interval for mean

α=0.01

critical value [tex]Z_{\frac{a}{z} }[/tex] =2.58

Standard error of sample mean Sx = [tex]\frac{s}{\sqrt[]{n} }[/tex] = [tex]\frac{80}{\sqrt[]{400} }[/tex] = [tex]\frac{80}{20}[/tex] = [tex]4[/tex]

∴ Sx = 4

Confidence interval (μ)

μ= [tex]x[/tex] ± [tex]Z_{\frac{a}{z} }[/tex] [tex]\frac{s}{\sqrt[]{n} }\\[/tex]

μ= [tex]x[/tex] ± [tex]Z_{\frac{a}{z} }[/tex] (Sx)

=500 ± 2.58(4)

=500 ±  10.32

lower limit = 500 - 10.32 = 489.68

upper limit= 500 + 10.32= 510.32

Hence, [489.68, 510.32] is the confidence interval for the average amount spent on textbooks in a year if the desired level of confidence is 99%.

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Answer:

A

Step-by-step explanation:

The formula for circumference is π×diameter.

π×12= 37.6991, which can be rounded up to 38.

The triangle that represents the image is; Option B; Triangle X Y Z is reflected across line m and then is dilated to form smaller triangle X prime Y prime Z prime.

From the given transformation as seen in the attached image, we can say that;

In Option A, the triangle is first reflected across m and then reflected across the vertical line. Then, it is dilated.

In Option C, the triangle is reflected across m but the angles are not preserved.

In Option B, the triangle is reflected across m and then dilated and as such is a correct image similar to the original triangle.

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It's Option B.

(You can also call it the middle one, up to you <3)

Answer:

(x-y)²

Since, it's formula of (x+y)² ...

Hello!

This is an identity :

[tex]\boxed {(x - y)^2 = x^2 - 2xy + y^2}[/tex]

∴ The factors are (x - y) and (x - y).

The plan that would cost less in fencing is B. Design 1, because it requires 24 fewer feet of fencing than Design 2.

From the information given, Design 1 would use fencing to surround a square plot of land that has an area of 1,296 square feet and Design 2 would divide a plot of land into two rectangular sections, each 15 feet by 36 feet.

Therefore, the plan that would cost less in fencing is Design 1, because it requires 24 fewer feet of fencing than Design 2.

In conclusion, the correct option is B.

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Answer:

B

Step-by-step explanation:

Answer:

452.389 cubic feet

Step-by-step explanation:

Answer:

Step-by-step explanation:

The formula for finding the volume of the cone: [tex]\pi r^2h/3[/tex]

Height= 12ft

Diameter= 6, radius= [tex]\frac{6}{2}[/tex]= 3

[tex]\frac{22}{7} *3^2*\frac{12}{3} \\\\\frac{22}{7} *3^2*2\\\frac{22}{7} *9*2\\\\\frac{22}{7} *18\\\\56.57[/tex]

The minimum number of flyers of each color distributed is 1.

In order to determine the minimum number of flyers of each color distributed, the common factor of 13 and 20 has to be determined. The factor of a number is a number that divides another number perfectly without any remainder.

Factors of 13 = 1, 13

Factors of 20 = 1, 2, 4, 5, 10, 20

Common factor = 1

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The angle measures in triangle ABC are (d) m∠A = 60°, m∠B = 30°, m∠C = 90°

The side lengths are given as:

AB = 12 inches

BC = 6√3 inches

CA = 6 inches

From the list of options, the angles are 30°, 60° and 90°, respectively.

In a triangle, the angle opposite the largest side is the largest angle and vice versa.

This means that:

∠C = 90° --- opposite AB

∠A = 60° --- opposite BC

∠B = 30° --- opposite CA

Hence, the angle measures in triangle ABC are (d) m∠A = 60°, m∠B = 30°, m∠C = 90°

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Complete question

The length of side AB is 12 inches, the length of side BC is 6√3, and the length of side CA is 6 inches.

See attachment

(C.) m∠A = 90°, m∠B = 60°, m∠C = 30°

Got it wrong, the correct answer was revealed to be C.

The incidence rate of varicella is 13 per 100 if there were 20 students and 5 of whom got vaccinated before fifth grade.

Given Total students of 100 in which 5 had varicella before entering fifth grade and 2 of whom developed  varicella during fifth grade.

We have to find the incidence rate of varicella means requirement of vaccine in proportion form.

So we want the incidence rate, which is the number of people who caught the disease who were at risk to it. So we have 20 people in the class in total. But we said that five of them already had it and they were told that they are immune. So we have 15 people in the class who are at risk, then two people caught it. and so the incidence rate is going to be two divided by 15, which you can check is Not .13 recurring. And so as a percentage We just times by 100 this is going to be 13/ 100.

Hence the incidence of varicella during the fifth grade is 13/100.

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There are 25 males in village 3

The given parameters are:

Total males = 75

                 Male     Female   Total

Village 1   20              25

Village 2  30                            50

Village 3                     30

Total         75

The number of male in village 3 is calculated using:

Male = Total Male - Male in villages 1 and 2

So, we have:

Male = 75- (20 + 30)

Evaluate

Male = 25

Hence, there are 25 males in village 3

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Complete question

An island has three villages and the total number of males is 75. The first village has 20 males and 25 females. The second village has 50 people of whom 30 are males. The third village has 30 females.

Calculate the number of male in third village

Answer:

182 [tex]yd^{2}[/tex]

Step-by-step explanation:

Area of a parallelogram: bh

bh

= 13(14)

= 182 sq. yds

It will take 120 minutes to chop down 100 trees.

Bob chops 10 trees in 30 minutes, so he can chop 100 trees in 300 minutes.

Frank chops 15 trees in 30 minutes, so he can chop 100 trees in 200 minutes.

Solve this using the following equation:

15 / 30 = 100 / x

Solving for x gives 120 minutes.

The unitary approach is a way of solving a hassle via first locating the price of a single unit, after which locating the necessary cost with the aid of multiplying the single unit fee.

The formula of the unitary approach is to find the cost of a single unit after which multiply the cost of an unmarried unit via the quantity of units to get the important price.

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Answer:

a. $16

b. $26

Step-by-step explanation:

a. 6+2(5)= 16

b. im assuming tt means ten 6+2(10)=26

If Audrey leaves her car in the lot for "t" hours, she would have to pay a total of $6 + $2t for parking.

If Audrey leaves her car in the parking lot for 5 hours, she will have to pay the initial fee of $6 plus $2 for each hour she parked. For 5 hours, she will pay:

Initial fee: $6

Additional fee for 5 hours: $2 * 5 = $10

Total parking cost: $6 + $10 = $16

If Audrey leaves her car in the parking lot for "t" hours, the total parking cost can be calculated as:

Total parking cost = Initial fee + Additional fee for "t" hours

Total parking cost = $6 + $2t

So, if Audrey leaves her car in the lot for "t" hours, she would have to pay a total of $6 + $2t for parking.

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Answer:

a. The equation should be

4x + 3y = $11.67

8x + y = $12.89

b. The price of one can of soup and the price of one loaf of bread is $1.355 and $2.09

The calculation is as follows:

here we assume the soup be x and bread be y

So, the equations are

4x + 3y = $11.67 .........(1)

8x + y = $12.89.........(2)

Here we need to multiply by 2 in equation 1

8x + 6x = $23.34

8x + y = $12.89

5y = $10.45

y = $2.09

Now x should be

8($2.09) + y = $12.89

x = $1.355

Hope this helps :)

Answer:

A)

Khalil: 4s + 1b = 11.67

Ronda: 8s + 1b = 12.89

B)

Can of soup = $0.305

Loaf of Bread = $10.45

(Please mark brainliest)

Step-by-step explanation:

Make s a can of soup

Make b a loaf of bread

A)

Khalil: 4s + 1b = 11.67

Ronda: 8s + 1b = 12.89

B)

12.89 - 11.67 = 1.22

1.22 / 4 = 0.305

11.67 - 1.22 = 10.45

Can of soup = $0.305

Loaf of Bread = $10.45

Answer:

A, B, E and F.

Step-by-step explanation:

A triangles side must be larger than the difference of the other sides, and smaller than the sum of the other sides. So in this case we could create an equation such as, 9-7<x<9+7. From this equation we can conclude that this side can be between 2 and 16. So, A, B, E and F all work.

The amount Aisha would pay to paint her living room is £38.50.

The first step is to determine the area of the walls that do not have doors.

Area of a wall = length x width

3 x (2.6 x 3.5) = 27.30 m²

Dimensions of the wall with the door : (2.6m - 2.2m) x (3.5 - 0.8) = 0.4m x 2.7m

Area of the wall with the door : 0.4m x 2.7m = 1.08 m²

Total area of the walls: 27.30 m² +  1.08 m² = 28.38 m²

Number of paint tins needed for the walls : 28.38 / 8 = 3.55 = 4 tins

Cost of the paint tins : (11 x 3) + (0.5 x 11) = £38.50

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Step-by-step explanation:

Newton's second law of motion describes the relationship between force and acceleration. They are directly proportional. If you increase the force applied to an object, the acceleration of that object increases by the same factor. In short, force equals mass times acceleration.

Answer:

23 or 1

Step-by-step explanation:

for answer 23: we considered the segment ABC which means A is the leftest point and C is the rightest point. then AC = AB+BC

for answer 1: we considered the segment CAB which means C is the leftest point, and B is the rightest point. Then AC = CA = BC-AB = 12-11=1

Answer:

The additive identity matrix would be a zero matrix (all its entries are zeros .) The sum between two matrices can be done if and only if the two matrices are similar, that means that they have the same numbers of rows and columns.

Step-by-step explanation:

Answer:

12y + d = -19y + t

31y + d = t

31y= - d + t

y = (- d + t ) / 3 ;)

Answer:

y = (t-d) / 31

Step-by-step explanation:

12y + d = -19y + t

12y + 19y = t - d

31y = t - d

y = (t-d) / 31

[tex]|\Omega|=6^3\\|A|=3^3\\\\P(A)=\dfrac{3^3}{6^3}=\left(\dfrac{3}{6}\right)^3=\left(\dfrac{1}{2}\right)^3=\dfrac{1}{8}=12.5\%[/tex]

The summary of the ruler placement postulate is given as:

This states that the points of a line can be matched and correspond to a set of points on the line and the set of real numbers,

Therefore, based on the fact that your question is incomplete, a general overview of the ruler placement postulate is given to give you a better understanding of the concept.

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Answer: You can measure the positive distance  between points A and B by using either point as zero

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

gradient= change in y intercept ÷change in x intercept

gradient=-2-0 ÷3-0

gradient=

Hello:

Okay, this problem should be taken in a series of steps:

What is the slope's formula?

  [tex]\rm\hookrightarrow \frac{y_2-y_1}{x_2-x_1}[/tex]

Okay, now let's use this knowledge  

10. (5,-19) and (-5,21)

       [tex]Slope = \frac{21--19}{-5-5} =\frac{40}{-10}=-4[/tex]

11. (12,1) and (12, -1)

      [tex]Slope = \frac{-1-1}{12-12} =\frac{-2}{0}[/tex]

12. (8,7) and (4,7)

     [tex]Slope = \frac{7-7}{4-7} =0[/tex]

Answer:

Hopefully that helps!

Hello

x² + 2x + 1 < 0 ⇔ (x + 1)² < 0

S = {∅} because a² ≥ 0

By understanding the proportions of each section with respect to the entire hexagon we have:  

The first row represents the proportion of each section with respect to the entire hexagon, which is shown below:

{1, 1/2, 1/3, 1/6}

The elements of the second row are obtained by mutiplying all the elements of the first row by 6:

{6, 3, 2, 1}

The elements of the third row are calculated by multiplying all the elements of the first row by 3:

{3, 3/2, 1, 1/2}

And the elements of the fourth row are determined by multiplying all the elements of the first row by 2:

{2, 1, 2/3, 1/3}

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The trigonometric expression [tex]\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}[/tex] is equivalent to the trigonometric expression [tex]\sec \alpha \cdot \csc \alpha + 1[/tex].

In this problem we must prove that one side of the equality is equal to the expression of the other side, requiring the use of algebraic and trigonometric properties. Now we proceed to present the corresponding procedure:

[tex]\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}[/tex]

[tex]\frac{\tan^{2}\alpha}{\tan \alpha - 1} + \frac{\frac{1}{\tan^{2}\alpha} }{\frac{1}{\tan \alpha} - 1 }[/tex]

[tex]\frac{\tan^{2}\alpha}{\tan \alpha - 1} - \frac{\frac{1 }{\tan \alpha} }{\tan \alpha - 1}[/tex]

[tex]\frac{\frac{\tan^{3}\alpha - 1}{\tan \alpha} }{\tan \alpha - 1}[/tex]

[tex]\frac{\tan^{3}\alpha - 1}{\tan \alpha \cdot (\tan \alpha - 1)}[/tex]

[tex]\frac{(\tan \alpha - 1)\cdot (\tan^{2} \alpha + \tan \alpha + 1)}{\tan \alpha\cdot (\tan \alpha - 1)}[/tex]

[tex]\frac{\tan^{2}\alpha + \tan \alpha + 1}{\tan \alpha}[/tex]

[tex]\tan \alpha + 1 + \cot \alpha[/tex]

[tex]\frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} + 1[/tex]

[tex]\frac{\sin^{2}\alpha + \cos^{2}\alpha}{\cos \alpha \cdot \sin \alpha} + 1[/tex]

[tex]\frac{1}{\cos \alpha \cdot \sin \alpha} + 1[/tex]

[tex]\sec \alpha \cdot \csc \alpha + 1[/tex]

The trigonometric expression [tex]\frac{\tan^{2} \alpha}{\tan \alpha - 1} + \frac{\cot^{2} \alpha}{\cot \alpha - 1}[/tex] is equivalent to the trigonometric expression [tex]\sec \alpha \cdot \csc \alpha + 1[/tex].

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Answer:

hundreds place in what the place value of the number 4 in 65400 the 6 is the hundred thousand place the 5 is the thounds place the four is the hundred place. The first zero is the 10th place. in the seconds, zero is the one place value

Answer:

The value 4 is in the hundreds place.

Step-by-step explanation:

We have the number 65400. The last digit in the number is 0, the 0 is in the ones place. The next number, which is also 0, is in the tens place. The next number after that is a 4, which is in the hundreds place. This shows that the 4 is in the hundreds place.

ten-thousands    thousands   hundreds  tens   ones

       6                        5                 4              0           0

Hope this helps!

If not, I am sorry.