Answer:
Yay fun day :DDDDDD
Step-by-step explanation:
Identify the values of A, B, and C
5x2 + x - 18 = - 9x + 3x2
A=2, B=10, C=-18
A=2, B=9, C=-18
A=5, B=1, C=-18
A=8, B=-8, C=-18
Answer:
A=2, B=10, C=-18
The answer is the first one.
Step-by-step explanation:
[tex]5x^{2} -3x^{2} +x+9x-18=0[/tex]
[tex]2x^{2} +10x-18=0[/tex]
Formula: [tex]f(x)=ax^{2} +bx+c[/tex]
2. Dibuja la mesa de tu casa, denota los puntos evidentes y nombra los siguientes elementos u objetos geométricos.
a) Tres planos.
b) Dos rectas de planos distintos.
c) Dos ángulos de un plano y dos de otro.
d) Dos rayos. e) Dos semirrectas.
Answer:
a) The floor of the room, each edge and the top of the table.
b) The edge of one side and one leg of the table.
c) The angle formed between the sides of the table and the angle between the legs of the table and its edges.
d) The vertices of the top of the table.
e) These are same lines.
Step-by-step explanation:
An angle is the amplitude between the two lines. Plane is an object which consists of two dimensions and infinite points. The segment is a fragmented line. A ray is a line which a starting point and a direction.
A) Tres planos que surgen a partir de la mesa de mi casa son la superficie de la mesa, la superficie del suelo sobre el cual se apoya la mesa, y la superficie de la pared sobre la cual reposa la mesa.
B) Dos rectas de planos distintos pueden ser el borde de la mesa, por una parte, y la pared, por el otro.
C) Dos ángulos de un plano y dos de otro son el vértice de la mesa y el ángulo formado entre el borde de la misma y un vaso, por un lado, y el ángulo formado por una baldosa y la pata de la mesa y el ángulo recto formado por las líneas de una baldosa, por la otra.
D) Dos rayas pueden ser la línea a ras del suelo y la línea a ras de la mesa.
E) Dos semirrectas pueden ser ambas patas de la mesa.
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a mean of 36.8° and a standard
deviation of 0.62°. If 19 people are randomly selected, find the probability that the sample mean
body temperature will be between 36.5° and 37.10?
The probability that the sample mean body temperature will be between 36.5° and 37.10° can be determined using the z-score and the standard normal distribution table.
First, we need to calculate the z-scores for both temperatures using the formula:
z = (x - μ) / (σ / √n)
where x is the sample mean, μ is the population mean, σ is the standard deviation, and n is the sample size.
For the lower temperature of 36.5°:
z1 = (36.5 - 36.8) / (0.62 / √19)
For the higher temperature of 37.10°:
z2 = (37.10 - 36.8) / (0.62 / √19)
Next, we look up the corresponding probabilities associated with these z-scores in the standard normal distribution table. Subtracting the probability of the lower z-score from the probability of the higher z-score will give us the probability of the sample mean body temperature falling between the two values.
Let's calculate the z-scores:
z1 = (36.5 - 36.8) / (0.62 / √19) ≈ -1.350
z2 = (37.10 - 36.8) / (0.62 / √19) ≈ 0.775
Now, we look up the probabilities associated with these z-scores in the standard normal distribution table. The probability corresponding to z1 is approximately 0.0885, and the probability corresponding to z2 is approximately 0.7794.
Finally, we subtract the lower probability from the higher probability:
P(36.5° ≤ sample mean ≤ 37.10°) = 0.7794 - 0.0885 ≈ 0.6909
Therefore, the probability that the sample mean body temperature will be between 36.5° and 37.10° for a sample size of 19 people is approximately 0.6909.
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What is the slope and y-intercept of 9x - 3y = 15?
NO FILES PEOPLE!
slope is 3
y-intercept is 0,-5
Solve the differential equation (D^2 + 4)y=6 sin2x +3x^2 =
The solution to the differential equation (D^2 + 4)y = 6 sin(2x) + 3x^2 is y = (3/4)x^2 + A sin(2x) + B cos(2x).
To solve the given differential equation (D^2 + 4)y = 6 sin(2x) + 3x^2, where D represents the derivative operator, we can use the method of undetermined coefficients.
First, we find the general solution to the homogeneous equation (D^2 + 4)y = 0. The characteristic equation is r^2 + 4 = 0, which has complex roots ±2i. Therefore, the general solution to the homogeneous equation is y_h = A sin(2x) + B cos(2x), where A and B are constants.Next, we find a particular solution to the non-homogeneous equation. By inspection, we can guess that y_p = (3/4)x^2 is a particular solution.Finally, the general solution to the non-homogeneous equation is the sum of the homogeneous and particular solutions:y = y_h + y_p
y = A sin(2x) + B cos(2x) + (3/4)x^2
Here, A and B are arbitrary constants that can be determined by applying initial or boundary conditions, if given.
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Identify the location of the point (6, -2). A. P B. Q C. R D. S
Answer:
Step-by-step explanation:
Determine whether each set of data represents a linear, an exponential, or a quadratic function. (Desmos)
Answer:
Linear: The first and third one. (0,5) & (1,1)
Exponential: The second one (above). (-2, 1/16)
Quadratic function: The last one (below). (-3,35)
Step-by-step explanation:
is the function described by the points in this table linear or nonlinear? x y −3 9 −1 1 0 0 1 1 3 9 responses linear linear nonlinear
The function described by the points in this table is nonlinear.
Based on the given points in the table, we can determine whether the function is linear or nonlinear by examining the relationship between the x and y values.
Let's look at the x and y values:
x y
-3 9
-1 1
0 0
1 1
3 9
If we observe that for every change in x, the corresponding change in y remains constant, then the function is linear. In other words, if the ratio of the change in y to the change in x is constant, the function is linear.
Let's calculate the ratios:
For x = -3 to x = -1:
Change in y = 1 - 9 = -8
Change in x = -1 - (-3) = 2
Ratio = -8/2 = -4
For x = -1 to x = 0:
Change in y = 0 - 1 = -1
Change in x = 0 - (-1) = 1
Ratio = -1/1 = -1
For x = 0 to x = 1:
Change in y = 1 - 0 = 1
Change in x = 1 - 0 = 1
Ratio = 1/1 = 1
For x = 1 to x = 3:
Change in y = 9 - 1 = 8
Change in x = 3 - 1 = 2
Ratio = 8/2 = 4
As we can see, the ratios are not constant. The ratio changes from -4 to -1, then to 1, and finally to 4. Therefore, the function described by the points in this table is nonlinear.
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What is the longest line segment that can be drawn in a right rectangular prism that is 13 cm long 9 cm wide and 7 cm tall
Answer: 17.29 cm
Step-by-step explanation:
Given
The dimension of a rectangular prism is [tex]13\ cm\times 9\times \ cm\times 7\ cm[/tex]
The longest line which can be drawn in the rectangular prism is diagonal across the body which is shown in the figure
Length of rectangular is given by
[tex]\Rightarrow L=\sqrt{l^2+b^2+h^2}[/tex]
Putting values
[tex]\Rightarrow L=\sqrt{13^2+9^2+7^2}\\\Rightarrow L\sqrt{169+81+49}=\sqrt{299}\\\Rightarrow L=17.29\ cm[/tex]
Answer:
17.3
Step-by-step explanation:
The dimension of a rectangular prism is 13x9x7
you would normally get 17.29 but you have to round
which gives us the answer= 17.3
Which set of numbers is infinite?
A) integers between -4 and 7
B) whole numbers between 1 and 17
C) natural numbers between 5 and 10
D) irrational numbers between 10 and 30
Answer:
D). irrational numbers between 10 and 30
Angel is a high school basketball player. In a particular game, he made some free throws (worth one point each) and some two point shots. Angel made a total of 12 shots altogether and scored a total of 16 points. Graphically solve a system of equations in order to determine the number of free throws made, x,x, and the number of two point shots made, yy.
Answer:
w = 8, y = 4.
Step-by-step explanation:
i think this is right i am not sure
Answer:
[tex]x = 8 \\ y = 4[/tex]
Step-by-step explanation:
Let x be the number of one point shots, and y the number of two point shots.
We have
[tex]x + y = 12 \\ y = 12 - x[/tex]
And
[tex]x + 2y = 16[/tex]
Substituting the first equation in we get
[tex]x + 2(12 - x) = 16 \\ x + 24 - 2x = 16 \\ - x = - 8 \\ x = 8[/tex]
Since
[tex]y = 12 - x \\ y = 12 - 8 = 4[/tex]
Use the binomial distribution to determine the probability that 10 rolls of a fair die will show exactly seven fours. Express your answer as a decimal rounded to 4 decimal places.
The probability of getting exactly seven fours in ten rolls of a fair die is approximately 0.0574.
To determine the probability of exactly seven fours in 10 rolls of a fair die, we can use the binomial distribution formula:
P(X = k) = (nCk) * p^k * (1-p)^(n-k)
Where:
P(X = k) is the probability of getting exactly k successes (in this case, rolling a four) in n trials (in this case, rolling a die 10 times),
nCk is the number of combinations of n items taken k at a time,
p is the probability of success on a single trial (rolling a four), and
(1-p) is the probability of failure on a single trial (not rolling a four).
In this case, n = 10, k = 7, p = 1/6 (since there is a 1/6 chance of rolling a four on a fair die), and (1-p) = 5/6.
Plugging these values into the formula:
P(X = 7) = (10C7) * (1/6)^7 * (5/6)^(10-7)
Calculating the combinations:
(10C7) = 10! / (7! * (10-7)!) = 10! / (7! * 3!) = (10 * 9 * 8) / (3 * 2 * 1) = 120
Substituting the values:
P(X = 7) = 120 * (1/6)^7 * (5/6)^(10-7)
Calculating the probability:
P(X = 7) = 120 * (1/6)^7 * (5/6)^3 ≈ 0.0595
Therefore, the probability that exactly seven fours will appear in 10 rolls of a fair die is approximately 0.0595 (rounded to 4 decimal places).
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2.46 strong association but no correlation. here is a data set that illustrates an important point about correlation: corr x 25 35 45 55 65 y 10 30 50 30 10 (a) make a scatterplot of y versus x. (b) describe the relationship between y and x. is it weak or strong? is it linear? (c) find the correlation between y and x. (d) what important point about correlation does this exercise illustrate?
a. In the picture we can see that the scatterplot is given for the data in the given table.
b. It is not linear as we can see from scatterplot.
c. The correlation between y and x is 0.
d. when r = 0 there is no relationship between x and y.
Given that,
The data is given in the table.
We know that,
a. We have to make a scatterplot of y versus x.
In the picture we can see that the scatterplot is given for the data in the given table.
b. We have to describe the relationship between y and x.
When x increases y increases upto certain point after that y start to decrease but x is increases only
Therefore, it is not linear as we can see from scatterplot.
c. We have to find the correlation between y and x.
The formula for the correlation coefficient is
r = [tex]\frac{n\times \sum XY-\sum X \times\sum Y}{\sqrt{[n\sum X^2 - (\sum X)^2][n\sum Y^2 - (\sum Y)^2]} }[/tex]
Now we find summation of all X, Y and XY, [tex]X^2[/tex] and [tex]Y^2[/tex]
X Y XY [tex]X^2[/tex] [tex]Y^2[/tex]
25 10 250 625 100
35 30 1050 1225 900
45 50 2250 2025 2500
55 30 1650 3025 900
65 10 650 4225 100
Now, ∑X = 225
∑Y = 130
∑XY = 5850
∑[tex]X^2[/tex] = 11125
∑[tex]Y^2[/tex] = 4500
Now, Substitute the values in the formula
r = [tex]\frac{5\times 5850-225 \times130}{\sqrt{[5\times 11125 - (225)^2][5\times 4500 - (130)^2]} }[/tex]
r = 0
Therefore, The correlation between y and x is 0.
d. We have to find what important point about correlation does this exercise illustrate.
Therefore, when r = 0 there is no relationship between x and y.
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PLEASE HELP!!!!
Find the volume and surface area of the composite figure. Give four answers in terms of π.
Answer Options
V = 123π in3; S = 78π in2
V = 612π in3; S = 264π in2
V = 153π in3; S = 123π in2
V = 135π in3; S = 105π in2
Answer:
V = 135π in3; S = 105π in2
Step-by-step explanation:
The error of rejecting the null hypothesis, when it is actually true is: alpha beta Type Il error Type I error
The error of rejecting the null hypothesis when it is actually true is known as a Type I error or alpha error. It represents the incorrect rejection of a null hypothesis that is true in reality.
Type I errors are associated with the significance level (alpha) chosen for a statistical test and occur when the test incorrectly concludes that there is a significant effect or relationship when there isn't one.
In hypothesis testing, the null hypothesis represents the assumption of no effect or no relationship between variables. The alternative hypothesis, on the other hand, suggests the presence of an effect or relationship. The significance level (alpha) is the threshold set by the researcher to determine the probability of rejecting the null hypothesis.
A Type I error occurs when the null hypothesis is true, but the statistical test incorrectly rejects it, leading to a false conclusion of a significant effect or relationship. This error is also known as a false positive. The probability of making a Type I error is denoted by alpha.
Type I errors are considered undesirable because they lead to incorrect conclusions and may result in wasted resources or inappropriate actions based on flawed evidence.
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Does anyone know how to work this out step by step?
Answer:
[tex]2x^{3} +10[/tex]
Step-by-step explanation:
[tex]x*2x*x+10=2x^{3} +10[/tex]
Simplify. simplify simplify
[tex]\huge\text{Hey there!}[/tex]
[tex]\mathsf{(\dfrac{4}{9})^2}[/tex]
[tex]\mathsf{= \dfrac{4}{9}\times\dfrac{4}{9}}[/tex]
[tex]\mathsf{= \dfrac{4^2}{9^2}}[/tex]
[tex]\mathsf{\dfrac{4\times4}{9\times9}}[/tex]
[tex]\mathsf{4 \times 4 = \bold{16}\leftarrow \underline{Numerator}}[/tex]
[tex]\mathsf{9\times9 = \bf 81}\leftarrow\mathsf{\underline{Denominator}}[/tex]
[tex]\boxed{\boxed{\large\textsf{Answer: \boxed{{\bf \dfrac{16}{81}}}}}}\huge\checkmark[/tex]
[tex]\text{Good luck on your assignment and enjoy your day!}[/tex]
~[tex]\frak{Amphitrite1040:)}[/tex]
Let X be a random variable with Poisson distribution of
parameter Lamda: Calculate
E (cos (\thetaX))
The expectation is 0.25.
Poisson distribution:Poisson distribution is a discrete distribution which is used to model events that occur in the specified interval of time. Parameter of Poisson distribution is [tex]\lambda[/tex], which describes the average number of events occurring in the given interval of time.
The given information is:
E(X) = In 2
X ~ Poi( [tex]\lambda[/tex] ) where [tex]\lambda[/tex], = In 2
[tex]f(x)=\frac{e^-^\lambda\lambda^x}{x!}[/tex]
It is known that cos([tex]\pi x[/tex])[tex]=(-1)^x[/tex], for x = 1, 2, 3...
To calculate the value of the required expectation.
[tex]E(cos(\pi x))=\sum^\infty_x_=_0 (-1)^xf(x)\\\\E(cos(\pi x))=\sum^\infty_x_=_0(-1)^x\frac{e^-^\lambda(\lambda)^x}{x!}\\ \\E(cos(\pi x))=e^-^\lambda\sum^\infty_x_=_0\frac{(-\lambda)^x}{x!}[/tex]
Expansion of exponential function is as follows
[tex]e^a=\sum^\infty_x_=_0\frac{(a)^x}{x!}[/tex]
Therefore, further calculation can be done as
[tex]E(cos(\pi x))=e^-^\lambda \,e^-^\lambda\\\\E(cos(\pi x))=e^-^2^\lambda\\\\E(cos(\pi x))=e^-^2^(^I^n^ 2^)\\\\E(cos(\pi x))=e^(^I^n^ 2^)^2\\\\E(cos(\pi x))=\frac{1}{4}[/tex]
Therefore, the expectation is 0.25.
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The given question is incomplete, complete question is:
Let X be a Poisson random variable with E(X) =In 2. Calculate [tex]E[cos(\pi x)][/tex].
Which of the following represents y < 2x - 3?
help a girl out please
Answer:
A
Step-by-step explanation:
the y intercept (where x is 0) should be -3 because of y<3x-3
Which of the following conditions is/are necessary to justify the use of t procedures in a significance test for the slope of a regression line? (4 points)
I. For each given value of x, the values of the response variable y are Normally distributed.
II. For each given value of x, the values of the response variable y are independent.
III. For each given value of x, the standard deviation of y is the same.
A. I only
B. II only
C. III only
D. I and II only
E. I, II, and III
The conditions that are required to validate the use of t for the significance test would be:
D). l and ll only
Regression Line"Regression Line" is described as the line that most adequately fits the provided data in order to display the efficacy of the model.
In the given situation, the I and II exemplify the conditions which will validate the process for the significance test.
The normal distribution, and among x and y and the independent response of y over x display that it suits the data successfully.
Thus, option D is the correct answer.
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Answer: Answer is THREE only.
Step-by-step explanation: Took the test. Also for the other guy's solution, he said one and two were REQUIRED. Make sure you read the question first ya'll. He still answered it.
Peter is making an "X marks the spot" flag for a treasure hunt. The flag is made of a square white flag with sides of 12 centimeters. He will make the "X" by stretching red ribbon diagonally from corner to corner.
Answer:
33.94 cms of ribbon
Step-by-step explanation:
Because you need two diagonals to form the x, therefore the amount of ribbon needed is the sum of the distance of both diagonals.
When crossing the diagonal, a rectangular angle is formed, where the diagonal would be the hypotenuse, we know that the distance of the hypotenuse can be calculated by means of the legs, which we know its value (12):
d ^ 2 = a ^ 2 + b ^ 2
a = b = 12
d ^ 2 = 12 ^ 2 + 12 ^ 2
d ^ 2 = 288
d = 288 ^ (1/2)
d = 16.97
16.97 cm is what it measures, a diagonal, therefore tape is needed:
16.97 * 2 = 33.94
A total of 33.94 cms of ribbon is needed
Answer from jmonterrozar
Joanne is making 48 cupcakes for a bake sale.
1/4 of the cupcakes are chocolate.
1/8 of the cupcakes are strawberry.
The remainder of the cupcakes are vanilla.
How many of the cupcakes are vanilla?
There are 30 of the cupcakes are vanilla.
What is mean by Subtraction?Subtraction in mathematics means that is taking something away from a group or number of objects. When you subtract, what is left in the group becomes less.
We have to given that;
Joanne is making 48 cupcakes for a bake sale.
And, 1/4 of the cupcakes are chocolate.
1/8 of the cupcakes are strawberry.
The remainder of the cupcakes are vanilla.
Hence, We get;
Amount of the cupcakes are vanilla is,
⇒ 48 - (1/4 of 48 + 1/8 of 48)
⇒ 48- (12 + 6)
⇒ 48 - 18
⇒ 30
Thus, There are 30 the cupcakes are vanilla.
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Find the roots of the quadratic equation 3x^2+64=2x^2/2 .
what is 2 divided by 1/2
Answer:
4
Step-by-step explanation:
Answer:
4
Step-by-step explanation:
to me when you divide with a farction it already is divsion but when u use it in divson i make nubmer bigger (if it's the 2nd number ) so thats way 2÷1/2=4
The average of a sample of high daily temperature in a desert is 114 degrees F. a sample standard deviation or 5 degrees F, and 26 days were sampled. What is the 90% confidence interval for the average temperature? Please state your answer in a complete sentence, using language relevant to this question.
The average of a sample of high daily temperature, the 90% confidence interval for the average temperature in the desert, based on the given sample data, is within a specific range.
To calculate the 90% confidence interval, we can use the formula:
Confidence Interval = Average ± (Critical Value) * (Standard Deviation / √Sample Size)
Since the sample size is 26 and we want a 90% confidence interval, we need to determine the critical value for a 90% confidence level. By referring to a t-distribution table or using statistical software, we can find that the critical value for a 90% confidence level with a sample size of 26 is approximately 1.708.
Substituting the values into the formula, we get:
Confidence Interval = 114 ± (1.708) * (5 / √26)
Calculating this expression, we obtain the confidence interval for the average temperature. The lower bound of the interval will be 113.36 degrees F, and the upper bound will be 114.64 degrees F. Therefore, we can state that we are 90% confident that the true average temperature in the desert falls within the range of 113.36 to 114.64 degrees F, based on the given sample data.
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The number of requests for assistance received by a towing service is a Poisson process with α = 4 rate per hour.
a. Compute the probability that exactly ten requests are received during a particular 2-hour period.
The probability that exactly ten requests are received during a particular 2-hour period, with a rate of α = 4 requests per hour, is approximately 0.0194 or 1.94%.
Let's denote the random variable X as the number of requests received during a 2-hour period. Since the rate of requests per hour is α = 4, we can calculate the rate for a 2-hour period as λ = α × 2 = 4 × 2 = 8.
The probability mass function (PMF) of a Poisson distribution is given by the formula:
[tex]P(X = k) = (e^{-\lambda} \times \lambda ^k) / k![/tex]
where e is Euler's number (approximately 2.71828), λ is the average number of events (rate) during the given time period, and k is the number of events we are interested in.
In this case, we want to find the probability of exactly ten requests, so k = 10 and λ = 8. Plugging these values into the formula, we get:
P(X = 10) = (e⁻⁸ * 8¹⁰) / 10!
To calculate this probability, we need to evaluate the values of e⁻⁸, 8¹⁰, and 10!.
e⁻⁸ is approximately 0.0003354626 (rounded to 10 decimal places).
8¹⁰ is equal to 1,073,741,824.
10! (10 factorial) is equal to 10 × 9 × 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1, which is 3,628,800.
Plugging these values back into the formula, we have:
P(X = 10) = (0.0003354626 * 1,073,741,824) / 3,628,800
Evaluating this expression gives us the probability that exactly ten requests are received during the two-hour period.
P(X = 10) ≈ 0.0194 or 1.94%.
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what value of x makes the equation -2/3x + 3 1/3x - 1/2 = -1/3x + 5 1/2 true?
A) 2
B) 1/2
C) -2
D) -1/2
Answer:
2
Step-by-step explanation:
Given that coule.us) - EILE DE M2)]. lajure the linearity rule and & (c) = c. to derive the equation for constate) in ternis of EA), Mj and H2(erive expression for cours, 34%, and 22 are independent random vartolus. f(x)= [ (x for 2 exc4 = 56) o elsewhere for a continuon ona random variable &. (a) Compute. P/2 ex <3). (6) Compute Elx), the mean of t. (8) Given (6) For some other random variable & My (t) = e. Determine the mean Ele) for this other random variable. (5* +32+) P.
(a) The probability that X is less than 3, P(X < 3), is 0.
(b) The mean of X, denoted as E(X), is 71/24, which is approximately 2.9583 when rounded off to four decimal places.
(c) Given Y = e^X, the mean of Y, denoted as E(Y), is approximately 15.75 when rounded off to two decimal places.
(a) It is required to compute P(X<3). Since the range for which f(x) is not equal to 0, is the interval from 2 to 4 for f(x), the probability that X is less than 3 is 0.
Similarly, for X > 4, P(X > 4) = 0.
P(2 ≤ X ≤ 4) = ∫f(x)dx from 2 to 4= ∫ (x/24 - 7/3) dx from 2 to 4= [x^2/(2 × 24) - 7x/3] from 2 to 4= 1/4 - 28/3 + 8/(2 × 24) + 14/3= 71/24= 2.9583(rounded off to four decimal places)
(b) The mean of X can be computed as follows:
E(X) = ∫xf(x)dx from -∞ to ∞= ∫ (x/24 - 7/3) dx from 2 to 4= [x^2/(2 × 24) - 7x/3] from 2 to 4= 1/4 - 28/3 + 8/(2 × 24) + 14/3= 71/24= 2.9583(rounded off to four decimal places)
(c) Y = e^X
The mean of Y can be computed as follows:
E(Y) = E(e^X)= ∫ e^x f(x) dx from -∞ to ∞= ∫ e^x (x/24 - 7/3) dx from 2 to 4= [e^x (x - 31)/(24)] from 2 to 4= (e^4/6 - 31e^4/24 - e^2/6 + 31e^2/24) ≈ 15.75(rounded off to two decimal places).
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Find the product.
-7(-a 2)(-5)
Answer:
3
5
(
−
2
)
Step-by-step explanation:
Simplify then multiple the numbers
(2x^(2)+5x+8)/(x+2) by using the synthetic formula
The quotient of (2x^2 + 5x + 8) divided by (x + 2) is 2x + 1, and the remainder is 12.
To divide the polynomial[tex](2x^2 + 5x + 8) by (x + 2)[/tex] using synthetic division, we follow these steps:
1. Set up the synthetic division table by placing the divisor (x + 2) on the left side of the table and writing down the coefficients of the dividend (2x^2 + 5x + 8) in descending order on the top row of the table.
| 2 5 8
-2 |
2. Bring down the first coefficient, which is 2, from the top row and write it underneath the horizontal line.
| 2 5 8
-2 | 2
3. Multiply the divisor (-2) by the number beneath the line (2) and write the result in the next column.
| 2 5 8
-2 | 2 -4
4. Add the result to the next coefficient in the top row and write the sum in the next column.
| 2 5 8
-2 | 2 -4 4
5. Repeat steps 3 and 4 until all coefficients have been processed.
| 2 5 8
-2 | 2 -4 4
___________
2 1 12
The last number in the bottom row, 12, is the remainder. The other numbers in the bottom row represent the coefficients of the quotient.
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