From the diagram below, if the sides AD = 3 and DC = 27, and BD = X + 3, find x.





Select one:

a.
36


b.
9


c.
16


d.
6

The solutions to the given system of equations are x = 4 and y = -9

From the question, we are to determine the solutions to the given system of equations

The given system of equations are

-8x-4y=4  --------- (1)

-5x-y=-11   --------- (2)

Multiply equation (2) by 4

4 ×[-5x-y=-11 ]

-20x -4y = -44  -------- (3)

Now, subtract equation (3) from equation (1)

-8x -4y = 4  --------- (1)

-(-20x -4y = -44)  -------- (3)

12x = 48

x = 48/12

x = 4

Substitute the value of x into equation (2)

-5x -y = -11

-5(4) -y = -11

-20 -y = -11

-y = -11 + 20

-y = 9

∴ y = -9

Hence, the solutions to the given system of equations are x = 4 and y = -9

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Both distributions are bell-shaped and symmetric but where the peak falls on the number line is determined by the mean.

The given statement is false.

A bell curve is a graph depicting the ordinary distribution, which has a shape harking back to a bell. The top of the curve suggests the mean, mode, and median of the records accrued.

The everyday distribution is a bell-fashioned and symmetrical distribution this is used to calculate the opportunity. in the everyday distribution, the mathematics means, mode, and median are usually the same, and the normal distribution is likewise called the Gaussian distribution.

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Answer:

42

Step-by-step explanation:

    Two tangents from a point outside the circle to some point to a circle are of equal lengths.

CB = 3+ 5 = 8

CD = 3+ 4 = 7

DA = 4 + 9 = 13

AB = 9+ 5 = 14

Perimeter = 8 + 7 + 13 + 14

                = 42

In this example, the sampling interval is 10.

A researcher gets a list of all 500 members of the National Association of Social Work in Yourtown that she wants to include in her study. She only has the funding and time to survey 50 members. She takes her list of members, randomly selects a starting point, and then selects every tenth name from the list to be included in her sample.

In this example, the sampling interval is 10.

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Point A: ( -1, 4 )

Point B: ( 1 ,0 )

To get from Point B to Point A, we must rise 4 and run -2 So using rise over run we have m = -2

Explanation:

After observing:

And

[tex]\sf slope \ (m) : \dfrac{y_2 - y_1}{x_2- x_1} = \dfrac{rise}{run} \ \ \ where \ (x_1 , \ y_1), ( x_2 , \ y_2) \ are \ points[/tex]

[tex]\rightarrow \sf slope \ (m) = \dfrac{rise}{run} = \dfrac{4-0}{-1-1} = \dfrac{4}{-2} = -2[/tex]

Answer:

b. The graph of g(x) is a translation 10 units right and 8 units up from the graph of f(x).

Step-by-step explanation:

See attached image.

The rule that describes a reflection across the line y = x is given as (x, y) ⇒ (y, x)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, translation, rotation and dilation.

Translation is the movement of a point either up, down, left or right on the coordinate plane.

The rule that describes a reflection across the line y = x is given as (x, y) ⇒ (y, x)

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Answer: The average change in elevation is 27 feet per second.

Step-by-step explanation:

 A submarine dives = 378 feet

          Time taken in the total diving = 14 seconds.

So, according to the question, the average change in the elevation  can be calculated by

                            ⇒ Feet per second = feet/ second

                             ⇒ the average change = 378/14

                            ⇒ elevation = 27 feet per second.

Change in elevation is basically the distance covered in one second.

The amount the first charity got is $10.

The amount the second charity got is $20.

The first step is to determine the amount raised by the second fifth grade class: 1.5 x $12 = $18

The total amount raised by the two classes : $18 + $12 = 30

Let x represent the amount gotten by the first charity

Amount gotten by the second charity : 2x

2x + x = $30

3x = $30

x = $30 / 3

x = $10

Amount gotten by the second charity : 2(10) = $20

Two fifth grade classes raised money for their local animal shelters. there are 20 students in class a each student raised $12. there are 26 students in class b each student in class b raised 1.5 times as much as each student in class a. The money raised went to two charity. One charity received two times as much as the other. How much money did each charity receive? Show your work and explain your answer.

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Rate is the distance between the cars increasing two hours later is 52 miles/hr

Let x(t) be distance of first car from starting point at time t

Let y(t) be distance of second car from starting point at time t

Let s(t) be distance between the two cars at time t. We need to evaluate ds/dt at time t = 2.

We know x2(t) + y2(t) = s2(t). Therefore 2x * dx/dt + 2y * dy/dt = 2s * ds/dt. The 2s cancel.

At t=2 hours, x = 96 miles. and y = 40 miles.

We will need the distance between the cars at t=2:

s(2) = √x(2)2 + y(2)2 = √96 2 + 40 2 = √10816 = 104.

Now fill in x * dx/dt + y * dy/dt = s * ds/dt at time t = 3 and solve for ds/dt:

96 * 48 + 40 * 20 = 104 * ds/dt

ds/dt = 5408/104 = 52 miles/hr

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The ratio of the side lengths of the triangle will be 3:10 or 3/10.

From the information given, the first triangle has sides 6 and 9 while the large triangle has sides 20 and 30.

Based on this, the ratio will be:

= 6/20 = 9/20

= 3/10 = 3/10

Therefore, the ratio is 3:10.

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The correct option is (D)

An expression, rule, or law that defines a relationship between one variable (the independent variable) and another variable (the dependent variable).

the complete question is attached below

As, per the data given we can say that

the variation of quantity is 2.

So, the equation can be

y=2x

This equation defined by part (4) of the question.

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Answer:

V = (2,-32)

Step-by-step explanation:

Hello!

The vertex of a quadratic lies on the Axis of Symmetry (AOS). The axis of symmetry is exactly in the middle of the roots of the Quadratic. We can solve for the AOS by finding the average of the two roots.

The two roots of the quadratic are 6 and -2.

The Axis of symmetry of the quadratic is 2.

Since the vertex lies on the AOS, we know the x-value of the vertex. We can solve for the y-value by plugging in the value of the AOS in the equation.

Find the Vertex

The Vertex of the quadratic is at (2,-32).

Using proportions, it is found that between stops the driver averages 57.75 miles.

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In 1,386 miles, the driver had 24 stops, hence the number of miles per stop is found as follows:

1386/24 = 57.75 miles.

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The slope of the line that represents the relationship is 0.7692

The formula for calculating the slope of a line is expressed as;

Slope = y2-y1/x2-x1

Using the coordinate points (1.3, 1) and (2.6, 2)

Substitute

Slope = 2-1/2.6-1.3

Slope = 1/1.3

Slope = 0.7692

Hence the slope of the line that represents the relationship is 0.7692

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Answer:

∠ C = 26°

Step-by-step explanation:

the sum of the 3 angles in a triangle = 180° , that is

∠ A + ∠ B + ∠ C = 180°

120° + 34° + ∠ C = 180°

154° + ∠ C = 180° ( subtract 154° from both sides )

∠ C = 26°

Answer:

9/28 and 32.1%

Step-by-step explanation:

So the sample space consists of all products for (5 * 1, 5 * 2, 5 * 3.... and the same thing for 6, 7, and 8)

This gives you the sample space: {5, 10, 15, 20, 25, 30, 6, 12, 18, 24, 30, 36, 7, 14, 21, 28, 35, 42, 8, 16, 24, 32, 40, 48}.

The size of the sample space is 4 * 6, since for each number (5, 6, 7, 8), there are 6 products (the dice have six numbers). This means the sample space has 24 combinations, you can also verify this by manually counting the sample space.

Now filtering the sample space so you only get a product that is 28 or higher you get: {30, 30, 36, 28, 35, 42, 32, 40, 48} which has 9 possible combinations that have a product greater than or equal to 28. Divide this by the entire sample space and you get a probability of: 9/28, which in decimal form is approximately: [tex]0.3214[/tex]. Multiplying this by 100 gives you: [tex]32.1[/tex]%

The smallest positive integer that has a square root that is greater than 10 is 101

Let the integer be represented by n

The square root is greater than 10.

So, we have:

[tex]\sqrt n > 10[/tex]

Square both sides

n > 100

The above means that the integer is greater than 100.

The smallest integer greater than 100 is 101

Hence, the smallest positive integer that has a square root that is greater than 10 is 101

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Answer:

If AD=AE the the bisector CD. will be the coefficient of AE

Answer:

$64,208.33

Step-by-step explanation:

100% - 33% = 67%

Since she pays 33% in taxes, she will only get 67% of the $23 million.

1 year = 12 months

20 years = 20 × 12 months = 240 months

There are 240 months in 20 years.

monthly amount = 67% of $23 million / 240

monthly amount = 0.67 × $23,000,000 / 240

monthly amount = $64,208.33

Answer:

0.995 centigram

Step-by-step explanation:

divide the mass value by 10

The inequality are –6x + 15 < 10 – 5x and a number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

Inequality are expressions not separated by an equal sign. Given the inequality expression below;

–3(2x – 5) < 5(2 – x)

Expand

-6x  + 15 < 10 - 5x

Collect the like terms

-6x + 5x < 10 - 15

-x < -5

x > 5

Hence the correct representations of the inequality are –6x + 15 < 10 – 5x and a number line from negative 3 to 3 in increments of 1. An open circle is at 5 and a bold line starts at 5 and is pointing to the right.

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The construction is the construction of the Perpendicular bisector.

The steps for the construction of perpendicular bisectors are as follows:

Open the compass more than half of the distance between A and B, and scribe arcs of the same radius centered at A and B.

Call the two points where these two arcs meet X and Y. Draw the line between X and Y.

So, the point where this line meets the line segment; M is called the mid point and the line XY is the perpendicular bisector of the line AB.

The figure is a construction of perpendicular bisector.

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The number of stuffed bears with Su=153181

Total number of bears Erin has=555555

The number of bears Erin took out=777

Remaining number of bears with Erin=555555-777

                                                                 =554778

Now, these remaining stuffed bears are to be divided equally among 333 sisters.

So, each sister gets [tex]\frac{554778}{333}[/tex]=[tex]1666[/tex] stuffed bears.

To find the number of stuffed bears Su has, find the sum of her share of stuffed bears and the number of stuffed bears she already had.

Number of stuffed bears Su already has=151515

Total number of bears she has at present=151515+1666

                                                                     =153181

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It has been proven that the trigonometric Identity (1 - secA + tanA)/(1 + secA + TanA) is equal to; (secA + tanA - 1)/(secA + tanA + 1)

We want to prove that;

(1 - secA + tanA)/(1 + secA + TanA) = (secA + tanA - 1)/(secA + tanA + 1)

We know from trigonometric identities that;

(secA)² – (tanA)² = 1   ----(1)

Also, from algebra we know that;

a² - b² = (a + b)(a - b)

The numerator of LHS of the original given Identity is:

1 - sec A - tan A

Using equation 1, we can say that;

(secA)² – (tanA)² - (sec A + tan A)

⇒ (sec A + tan A)(sec A - tan A) - (sec A - tan A)

This can be factorized to get;

(sec A - tan A)(sec A + tan A - 1)

Similarly, the denominator can be expressed as;

(sec A - tan A)(sec A + tan A + 1)

Thus, combining the numerator and denominator together gives us:

[(sec A - tan A)(sec A + tan A - 1)]/[(sec A - tan A)(sec A + tan A + 1)]

⇒ (secA + tanA - 1)/(secA + tanA + 1)

That expression is equal to the Right hand side and as such the Trigonometric Identity is proved.

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(a) The relation is a function because each value of x maps onto only one value of y.

(b) Domain is [tex](-\infty, 3][/tex], range is [tex][-1, \infty)[/tex].