For which values of n does K, the complete graph on n vertices, have an Euler cycle? (b) Are there any K, 's that have Euler trails but not Euler cycles? (c) For which values of rand s does the bipartite graph Khave an Euler cycle?

Answer:

{-3, 5}.

Step-by-step explanation:

y = x + 8

x + y = 2

Substitute y = x + 8 in the second equation:

x + x + 8 = 2

2x + 8 = 2

2x = -6

x = -3

Now plug this into the first equation

y = -3 + 8 = 5.

Answer:

The first one

Step-by-step explanation:

Because

Answer:

The answer is D

hope this helps

Answer:

Following are the responses to these question:

Step-by-step explanation:

Because every player has 5 cards handed

The card ratio is 5:1 per player.

So, if there are three teams

5 times 3=15 Cards 

Four players=four times five=20 cards

Five players=5 times five=25 cards

6 cards=6 times 5=30 cards

The card ratio is 5:1 per player.

Answer:

54.25

Step-by-step explanation:

The cash flow stream consisting of $14,000 today followed by $6,000 each year for the next 11 years, discounted at a rate of 7.1%, is worth approximately $52,743 to you today.

To determine the present value of the cash flow stream, we need to discount each cash flow back to the present using the appropriate discount rate.

The present value (PV) of each cashflow can be calculated using the formula:

[tex]PV = CF / (1 + r)^n[/tex]

where PV is the present value, CF is the cash flow, r is the discount rate, and n is the number of periods.

Calculating the present value of each cash flow and summing them up, we get:

[tex]PV = \$14,000 + \$6,000 / (1 + 7.1\% / 100)^1 + \$6,000 / (1 + 7.1\% / 100)^2 + ... + \$6,000 / (1 + 7.1\% / 100)^11[/tex]

Evaluating the expression, we find that the present value of the cash flow stream is approximately $52,743 when rounded to the nearest dollar.

This means that if you discount the future cash flows at a rate of 7.1%, the combined value of all the cashflows today would be approximately $52,743.

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Answer:

what

Step-by-step explanation:

Answer:

Сен қазақ сыңба?

Step-by-step explanation:

қазашшаайтшыааа

Answer:

x = 29

Step-by-step explanation:

We know that those two angles equal 180° so we combine those two equations and set them equal to 180°:

6x + 6 = 180°

Subtract 6 from both sides:

6x = 174°

Divide by 6:

x = 29

Answer:

2/3

Step-by-step explanation:

rise over run

up and over

Step-by-step explanation:

to find the area of a circle, it is pi times radius squared. so 1 times pi squared is pi^2 the area is 4 plus 2pi^2

Answer:

NO

Step-by-step explanation:

If the diameter of the circle is doubled the area will be increased 4 times

The point labeled D is to the right of the intersection of the two linear functions. This means that its x-coordinate is greater than the x-coordinate of the point of intersection.

We can find the point of intersection by setting the two functions equal to each other:

3x + 4 = (-1/2)x - 5

Solving for x, we get:

(7/2)x = -9

x = -18/7

So the point of intersection is (-18/7, -29/7).

Since the x-coordinate of point D is greater than -18/7, we can eliminate options A and C.

Now we need to check whether option B or option D includes point D as a solution. To do this, we can simply plug in the coordinates of D into the two inequalities and see which one holds true.

Option B:

f(x) ≥ 3x + 4

2 ≥ 3(D) + 4

2 ≥ 3D + 4

-2 ≥ 3D

D ≤ -2/3

g(x) ≤ (-1/2)x - 5

2 ≤ (-1/2)(D) - 5

7 ≤ -D

D ≥ -7

Since -2/3 is less than -7, option B does not include point D as a solution.

Option D:

f(x) ≥ 3x + 4

2 ≥ 3(D) + 42 ≥ 3D + 4

-2 ≥ 3D

D ≤ -2/3

g(x) ≥ (-1/2)x - 5

2 ≥ (-1/2)(D) - 5

7 ≥ -D

D ≤ -7

Since -2/3 is less than -7, option D does not include point D as a solution either.

Therefore, neither option B nor option D includes point D as a solution. The correct answer is that neither system of inequalities has point D as a solution.

Answer:

B I think

Step-by-step explanation:

I think it's B because in b it says so on which means his raise keeps going up each year

Answer:

y=k×x

so k =-1/2

ie: -1=-1/2(2)

-1=-1

hope this helps hshshsjjss

Answer:

150

Step-by-step explanation:

'x' = number of students out of 500 who selected math

18/60 = x/500

cross-multiply:

60x = 9000

x = 150

Answer:

yes

Step-by-step explanation:

All of the opposite sides are parallel  to each other.  

The p-value of this test is 0.0294.

a) The absolute value of the critical value of this test is "1.645".

The critical value for the given test can be calculated using the following formula;`

Critical value =

± z_(α/2)`

Where,`α` is the level of significance of the test.

`z_(α/2)`

is the critical value from the standard normal distribution table.

Since, the significance level of the test is 20%,

α = 0.2 or 0.20

Level of Significance = 0.20α/2 = 0.20/2α/2 = 0.10

Now, the critical value of the test can be found from the standard normal distribution table at 0.10 level of significance.

It comes out to be 1.645.

So, the absolute value of the critical value of this test is 1.645.

b) The absolute value of the calculated test statistic is "2.23".

The test statistic for the given test is the t-value calculated using the sample data.

It can be calculated using the following formula;

`t = (x¯1 - x¯2) / [ s_p * √(1/n1 + 1/n2) ]`

Where,`x¯1 and x¯2` are the sample means.

`s_p` is the pooled standard deviation.

`n1 and n2` are the sample sizes.

So, the test statistic of the given test comes out to be 2.23.So, the absolute value of the calculated test statistic is 2.23.

c) The p-value of this test is "0.0294".

The p-value for the given test is the probability of getting a t-value more extreme than the calculated t-value, assuming the null hypothesis is true.

The p-value can be calculated using the t-distribution table.

The degrees of freedom for the given test is

`df = n1 + n2 - 2`.

Substituting the values in the formula, the p-value for the given test comes out to be 0.0294.

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To find the expected amount you would pay for your two raffle tickets, we need to calculate the expected value of the sum of the prices on the tickets.

Let's denote the prices on the tickets as follows:

Ticket 1: $1

Ticket 2: $2

Ticket 3: $3

Ticket 4: $4

Since you are drawing two tickets without replacement, there are a total of 4C2 = 6 possible combinations of two tickets.

The expected value (E) can be calculated by summing up the products of each combination and its corresponding probability. The probability of each combination is 1/6 since all combinations are equally likely.

The expected amount you would pay for your two raffle tickets is given by:

[tex]\[E = \frac{1}{6}(\$1 + \$2) + \frac{1}{6}(\$1 + \$3) + \frac{1}{6}(\$1 + \$4) + \frac{1}{6}(\$2 + \$3) + \frac{1}{6}(\$2 + \$4) + \frac{1}{6}(\$3 + \$4)\][/tex]

Simplifying the expression, we find:

[tex]\[E = \frac{\$3 + \$4 + \$5 + \$5 + \$6 + \$7}{6} = \$5\][/tex]

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Answer:

22

Step-by-step explanation:

if mai scores 5 points and noah scores 3 times that then noah scored 15 points, and if tyler scores four less than noah than he scored 11 points, which you multiply by 2 to get elena's score which is 22

After considering the given data we conclude that the z-score for each situation is
The area concerning left of z is .2119: z = -0.81
The area amongst -z and z is .9030: z = 1.44
The area amongst -z and z is .2052: z = 0.84
The area concerning left of z is .9948: z = 2.59
The area concerning right of z is .6915: z = 0.48

To evaluate the z-score for each situation, we can apply the z-table . Here are the steps to find the z-score for every situation:
The area concerning left of z is .2119:
Applying the z-table, we can evaluate that the z-score is -0.81.
The area amongst -z and z is .9030:
Applying the z-table, we can evaluate that the z-score is 1.44.
The area amongst -z and z is .2052:
Utilising the z-table, we can express that the z-score is 0.84.
The area concerning left of z is .9948:
Applying the z-table, we can calculate that the z-score is 2.59.
The area concerning right of z is .6915:
We need to evaluate the area concerning left of z first, which is

1 - 0.6915 = 0.3085.
Applying the z-table, we can compound that the z-score is 0.48.
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a.The closed-form expression for the given recurrence is: an = 8 * [tex]2^{(n-1)} + 6.[/tex]

b.In the proof by induction, we showed that the closed-form expression for the recurrence, an = 8 * [tex]2^{(n-1)}[/tex] + 6, holds true for both the base case and the inductive step. Thus, confirming its equivalence to the given recurrence.

The closed-form expression for the given recurrence, an = [tex]2^n[/tex] * 8 - [tex]2^1[/tex] + 6, represents a direct formula to calculate the value of each term in the sequence. It involves exponentiation and arithmetic operations to determine the value based on the position (n) in the sequence.

In the proof by induction, we will first establish the base case, which is n = 1. From the recurrence, we have a1 = 8 * [tex]2^{(1-1)}[/tex] + 6 = 8. Substituting n = 1 into the closed-form expression, we also get a1 = 8 * [tex]2^{(1-1)}[/tex] + 6 = 8. The base case holds.

Next, we assume that the closed-form expression is true for an arbitrary positive integer k, i.e., ak = 8 * [tex]2^{(k-1)}[/tex] + 6.

Now, we will prove that it holds for k + 1, i.e., ak+1 = 8 * [tex]2^k[/tex] + 6.

Using the recurrence, we have ak+1 = 2 * ak-1 + 8 = 2 * (8 * [tex]2^{(k-1)}[/tex] + 6) + 8 = 16 * [tex]2^{(k-1)}[/tex] + 12 + 8 = 8 * [tex]2^k[/tex] + 6.

By comparing this with the closed-form expression, we see that ak+1 = 8 * [tex]2^k[/tex] + 6.

Therefore, the closed-form expression holds for k + 1.

By the principle of mathematical induction, we have proven that the closed-form expression, an = 8 * [tex]2^{(n-1)}[/tex] + 6, is equivalent to the given recurrence.

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The solution to the recurrence relation T(n) = T(n-1) + 2, with T(1) = 0, is T(n) = 2k.

To solve the given recurrence relation T(n) = T(n-1) + 2, for n > 0, with the initial condition T(1) = 0, we can use backward substitution.

1. Start with the base case T(1) = 0.

2. Substitute T(n-1) with T(n-2) + 2 in the original recurrence relation:  
T(n) = T(n-1) + 2  
    = (T(n-2) + 2) + 2  
    = T(n-2) + 4

3. Repeat the substitution process until we reach the base case:
T(n) = T(n-1) + 2  
    = (T(n-2) + 2) + 2  
    = ((T(n-3) + 2) + 2) + 2  
    = T(n-3) + 6

4. Continue this process until n - k = 1, where k is a positive integer.

5. Finally, substitute n - k with 1:
T(n) = T(n-1) + 2  
    = (T(n-2) + 2) + 2  
    = ((T(n-3) + 2) + 2) + 2  
    = ...  
    = T(1) + 2k

6. Since T(1) = 0, we have:  
T(n) = 0 + 2k  
    = 2k

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$30500                                                                                                                       ..............................................................................................................................

Answer:

4/15

Step-by-step explanation:

Each fraction is 1/15 less than the previous.

If we make them all the same denominator,

then it would show as:

8/15

7/15

6/15

5/15

The next fraction would be 5/15 - 1/15

which is

4/15

Answer:

4                                                    1

__    because it goes down by ___

15                                                  15

Step-by-step explanation:

Answer:

-5 + 4n

Step-by-step explanation:

-1/2(10 - 8n)

-5 + 4n