Mathematics College

For which function and interval can the extreme value theorem be applied?
O f(x) =
Х
(x-6)
over the interval [3, 5)
-5
f(x) =
2(x-7)3
over the interval (6,8)
f(x) = 4 tan(Ttx) over the interval [0, 1]
f(x) = 3e' + 1 over the interval (1,3)

For Which Function And Interval Can The Extreme Value Theorem Be Applied?O F(x) =(x-6)over The Interval

Answers

Answer 1

Answer:

A

Step-by-step explanation:

Answer 2

A function assigns the value. The function on which the extreme value theorem can be applied is f(x)=x/(x-6)².

What is a Function?

A function assigns the value of each element of one set to the other specific element of another set.

In a function for the extreme value theorem to be applicable, the function must be continue between the given interval.

The denominator of the first function will not continue when the value of x= 6, which is not in the interval [3,5). Therefore, the extreme value theorem is applicable.

To verify if the system will continue or not, you can plot the graph of the function, and look between the interval if the function continues or not. As shown below.

Hence, the function on which the extreme value theorem can be applied is f(x)=x/(x-6)².

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For Which Function And Interval Can The Extreme Value Theorem Be Applied?O F(x) =(x-6)over The Interval

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Question: The graph of a second-order polynomial is shown below, and the intercepts with the axes are marked. Explain how you can use the graph to write the polynomial as a product of linear factors (x-a)(x-b). Be sure to state the values of a and b. NEED HELP ASAP​

Answers

Hello!

Here we are given a second-order polynomial, and the root form of the function.

[tex]y=a(x-c)(x-d)[/tex]

Where c and d are zeros of the function, which is where the graph intersects the x-axis.

[tex]y=a(x+4)(x-3)[/tex]

[tex]-6=a(2+4)(2-3)[/tex]

[tex]-6=-6a[/tex]

[tex]a=1[/tex]

Therefore, the equation of this polynomial would be [tex]y=(x+4)(x-3)[/tex], and the values of a and b would be the x-intercepts.

Hope this helps!

The radius of a cylindrical construction pipe is 1.5 ft. If the pipe is 17 ft long, what is the volume?

Use the value 3.14 for π and round your answer to the nearest whole number.

Answers

Answer:

The volume of the cylinder is 120.10 square feet.

Step-by-step explanation:

Given that the radius of a cylindrical construction pipe is 1.5 ft, to determine its volume if the pipe is 17 ft long, the following calculation must be performed, knowing that the volume of a cylinder arises from multiplying the number pi by the radius at square of the cylinder, and that result by the height of the same:

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3.14 x 2.25 x 17 = X

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How much money would you have to invest at 7% compounded semiannually so that the total investment has a value of $2,090 after one year?

Answers

Answer:

$1,951.03.

Step-by-step explanation:

To determine how much money would you have to invest at 7% compounded semiannually so that the total investment has a value of $ 2,090 after one year, the following mathematical calculation must be performed:

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X x 1.071225 = 2,090

X = 2,090 / 1.071225

X = 1,951.03

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Expression:

Simplified (combined) expression:​

Answers

Answer:

Total score → (9p + m - 1)

Step-by-step explanation:

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Points scored in quarter 3 = (p - 4)

Score of quarter 4 = (m + 1)

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                                                          = 9p + m - 1

Expression representing the total score by the team in entire game will be,

(9p + m - 1)

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Answers

9514 1404 393

Answer:

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Step-by-step explanation:

The segments WX and WY are congruent, so ...

  5n -2 = 2n +7

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  n = 3 . . . . . . . . . . . .divide by 3

  WY = 2n +7 = 2(3) +7 . . . . substitute for n in the expression for WY

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Answer:

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Step-by-step explanation:

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Answer:

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Answers

Answer:

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square units

Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

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Answers

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