For this lab you will write a class to create a user-defined type called Shapes to represent different shapes, their perimeters and their areas. The class should have three fields: shape, which is of type string, and perimeter and area of type double. The program will have to be able to calculate perimeters and areas for circles, triangles, squares and rectangles, which are the known shapes.
2.1 Constructors
Write these constructors:
1. Default constructor that sets the shape to "unknown" and the perimeter and area to 0
2. Constructor with one parameter, shape, that sets the shape, other fields are 0
2.2 Accessors & Mutators
Write the following member methods:
1. setShape()
Modifies the shape field
2. getShape()
Returns the shape field
3. getPerimeter()
Returns the perimeter field
4. getArea()
Returns the area field
Arithmetic Methods in Interface
Write the following member methods to perform arithmetic:
1. setPerimeter(Scanner scnr)
Depending on the shape, prompts the user for appropriate variables (ie width & height for a square, radius for a circle, etc.) and calculates the perimeter of the appropriate shape. The perimeter field should be updates with the new value. If the shape is unknown, then print to the screen that the user must first define a shape before a perimeter can be calculated and set the perimeter to 0.
2. setArea(Scanner scnr)
Depending on the shape, prompts the user for appropriate variables (ie width & height for a square, radius for a circle, etc.) and calculates the area of the appropriate shape. The area field should be updates with the new value. If the shape is unknown, then print to the screen that the user must first define a shape before an area can be calculated and set the area to 0.
2.3 Additional Methods
Create two additional methods of your choice. Be sure to clearly label both of these methods as your own.
2.4 Using another .java file called ShapesTest.java that tests that all of your methods work correctly

Answers

Answer 1
Answer:

========= Shape.java  ===========

//import the Scanner class

import java.util.Scanner;

public class Shape{

   //required fields

  private String shape;

   private double area;

   private double perimeter;

   //default constructor

  public Shape(){

       this.shape = "unknown";

       this.area = 0.0;

       this.perimeter = 0.0;

   }

   //constructor with one parameter

   public Shape(String shape){

       this.setShape(shape);

       this.area = 0.0;

       this.perimeter = 0.0;

   }

   //accessors and mutators

  public void setShape(String shape){

       this.shape = shape;

   }

  public String getShape(){

       return this.shape;

   }

   public double getPerimeter(){

       return this.perimeter;

   }

  public double getArea(){

       return this.area;

   }

  public void setPerimeter(Scanner scr){

       if(this.getShape().equals("circle")){

           System.out.println("Enter the radius of the circle");

           double radius = scr.nextDouble();

           this.perimeter = 2 * 3.142 * radius;

       }

       else if(this.getShape().equals("rectangle")){

           System.out.println("Enter the width");

           double width = scr.nextDouble();

           System.out.println("Enter the height");

           double height = scr.nextDouble();

           this.perimeter = 2 * (width + height);

       }

       else if(this.getShape().equals("square")){

           System.out.println("Enter the height or width");

           double height = scr.nextDouble();

           this.perimeter = 4 * height;

       }

       else if(this.getShape().equals("unknown")){

           System.out.println("You must define a shape first before calculating perimeter");

           this.perimeter = 0.0;

       }

       else {

           System.out.println("You must define a shape first before calculating perimeter");

           this.perimeter = 0.0;

       }

   }

   public void setArea(Scanner scr){

       if(this.getShape().equals("circle")){

           System.out.println("Enter the radius of the circle");

           double radius = scr.nextDouble();

           this.area = 3.142 * radius * radius;

       }

       else if(this.getShape().equals("rectangle")){

           System.out.println("Enter the width");

           double width = scr.nextDouble();

           System.out.println("Enter the height");

           double height = scr.nextDouble();

           this.area = width * height;

       }

       else if(this.getShape().equals("square")){

           System.out.println("Enter the height or width");

           double height = scr.nextDouble();

           this.area = height * height;

       }

       else if(this.getShape().equals("unknown")){

           System.out.println("You must define a shape first before calculating area");

           this.area = 0.0;

       }

       else {

           System.out.println("You must define a shape first before calculating area");

           this.area = 0.0;

       }

   }

   //Own methods

   //1. Method to show the properties of a shape

   public void showProperties(){

       System.out.println();

       System.out.println("The properties of the shape are");

       System.out.println("Shape : " + this.getShape());

       System.out.println("Perimeter : " + this.getPerimeter());

       System.out.println("Area : " + this.getArea());

   

   }

   //2. Method to find and show the difference between the area and perimeter of a shape

   public void getDifference(){

       double diff = this.getArea() - this.getPerimeter();

       System.out.println();

       System.out.println("The difference is " + diff);

   }

}

========= ShapeTest.java  ===========

import java.util.Scanner;

public class ShapeTest {

   public static void main(String [] args){

       Scanner scanner = new Scanner(System.in);

       // create an unknown shape

       Shape shape_unknown = new Shape();

       //get the shape

       System.out.println("The shape is " + shape_unknown.getShape());

       //set the area

       shape_unknown.setArea(scanner);

       //get the area

       System.out.println("The area is " + shape_unknown.getArea());

       //set the perimeter

       shape_unknown.setPerimeter(scanner);

       //get the perimeter

       System.out.println("The perimeter is " + shape_unknown.getPerimeter());

       // create another shape - circle

       Shape shape_circle = new Shape("circle");

       //set the area

       shape_circle.setArea(scanner);

       //get the area

       System.out.println("The area is " + shape_circle.getArea());

       //set the perimeter

       shape_circle.setPerimeter(scanner);

       //get the area

       System.out.println("The perimeter is " + shape_circle.getArea());

       //get the properties

       shape_circle.showProperties();

       //get the difference between area and perimeter

       shape_circle.getDifference();

   }

}

Sample output:

The shape is unknown

You must define a shape first before calculating area

The area is 0.0

You must define a shape first before calculating perimeter

The perimeter is 0.0

Enter the radius of the circle

>> 12

The area is 452.448

Enter the radius of the circle

>> 12

The perimeter is 452.448

The properties of the shape are

Shape : circle

Perimeter : 75.408

Area : 452.448

The difference is 377.03999999999996

Explanation:

The code above is written in Java. It contains comments explaining important parts of the code. Please go through the code for more explanations. For better formatting, the sample output together with the code files have also been attached to this response.

For This Lab You Will Write A Class To Create A User-defined Type Called Shapes To Represent Different

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Answer:

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Answer:

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Answer:

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Answers

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Explanation: Hope this helps!

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Answers

Answer:

Following are the code to the given question:

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Output:

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Explanation:

In this code, a method "match_sequence" is declared that takes two string variable "s1 and s2" in its parameters, and inside the method, a loop is declared that checks the range of s1 value and use if block to match each sequence and use a print method that prints it values.

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Solution :

#include [tex]$< \text{stdio.h} >$[/tex]

#include [tex]$< \text{stdlib.h} >$[/tex]

int [tex]$\text{main}()$[/tex]

{

[tex]$\text{FILE}$[/tex] *fp;

[tex]$\text{fp}$[/tex]=fopen("cp4in_1.txt","r");

char ch;

//while(1)

//{

while(!feof(fp))

{

char *[tex]$\text{s1}$[/tex],*[tex]$\text{s2}$[/tex],*[tex]$\text{s3}$[/tex];

[tex]$\text{s1}$[/tex] = (char*) [tex]$\text{malloc}$[/tex]([tex]$20$[/tex] * [tex]$\text{sizeof}$[/tex](char));

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[tex]$\text{s3}$[/tex] = (char*) [tex]$\text{malloc}$[/tex]([tex]$40$[/tex] * [tex]$\text{sizeof}$[/tex](char));

[tex]$\text{int i}$[/tex]=0,j=0,x,y;

while(1)

{

ch=getc(fp);

if(ch=='\n')

break;

*(s1+i)=ch;

i++;

}

while(1)

{

ch=getc(fp);

if(ch=='\n')

break;

*(s2+j)=ch;

j++;

}

for(x=0;x<i;x++)

{

*(s3+x)=*(s1+x);

}

for(y=0;y<j;x++,y++)

{

*(s3+x)=*(s2+y);

}

for(x=0;x<i+j;x++)

{

printf("%c",*(s3+x));

}

printf("\n");

getc(fp);

}

}

Define a class Complex to represent complex numbers. All complex numbers are of the form x + yi, where x and y are real numbers, real numbers being all those numbers which are positive, negative, or zero.

Answers

Answer:

The program in C++ is as follows:

#include<bits/stdc++.h>

using namespace std;

class Complex {

public:

 int rl, im;

Complex(){ }

Complex(int Real, int Imaginary){

 rl = Real;  im = Imaginary;

}

};

int main(){

   int real, imag;

   cout<<"Real: ";    cin>>real;

   cout<<"Imaginary: ";    cin>>imag;

Complex ComplexNum(real, imag);

cout<<"Result : "<< ComplexNum.rl<<" + "<<ComplexNum.im<<"i"<<endl;

}

Explanation:

See attachment for explanation

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Answer:

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public static int findMatch(char array[], int low, int high, char key) {
if (high >= low) {
int mid = low + (high - low) / 2;
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a. (array, 2, 4, key) and (array, 3, 4, key)
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d. (array, 3, 4, key) and (array, 4, 4, key)

Answers

Answer:

The answer is "Option D".

Explanation:

In the given question "(array, 3, 4, key) and (array, 4, 4, key)", the element 'e' to also be searched is concentrated mostly on the right-hand side of the array since it is in the last place. This same middle value is 2 but findMatch(array, mid + 1 high, key) is labeled twice to move the center pointer to its last position, that is, so move that search item's 'e.'

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Explanation:

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Answers

Answer:

Explanation:

The following code is written in Java and creates all the classes as requested with their variables, and methods. Each extending to the Person class if needed. Due to technical difficulties I have attached the code as a txt file below, as well as a picture with the test output of calling the Staff class.

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Answers

Answer:

Digital marketing is the component of marketing that utilizes internet and online based digital technologies such as desktop computers, mobile phones and other digital media and platforms to promote products and services.

Explanation:

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Answers

Answer:

by implementing models that predict compliance with data protection and data privacy policies.

Explanation:

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a. Create a copy of the file and make changes in that new copy

b. Start over from scratch with a new file

c. Once a file has been saved, you cannot change it

d. Reopen the file in your text editor to

Answers

Answer:

d. Reopen the file in your text editor

Answer:

eeeeeeeee

Explanation:

The new software organization requires a new point of sale and stock control system for their many stores throughout Pakistan to replace their aging mini-based systems.
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Answers

Answer:

Arid walu apna v ker luuu

Explanation:

Answer:

hn g

Explanation:

What is output? public class MathRecursive { public static void myMathFunction(int a, int r, int counter) { int val; val = a*r; System.out.print(val+" "); if (counter > 4) { System.out.print("End"); } else { myMathFunction(val, r, counter + 1); } } public static void main (String [] args) { int mainNum1 = 1; int mainNum2 = 2; int ctr = 0; myMathFunction(mainNum1, mainNum2, ctr); } }
a) 2 4 8 16 32 End
b) 2 2 2 2 2
c) 2 4 8 16 32 64 End
d) 2 4 8 16 32

Answers

Answer:

The output of the program is:

2 4 8 16 32 64 End

Explanation:

See attachment for proper presentation of the program

The program uses recursion to determine its operations and outputs.

The function is defined as: myMathFunction(int a, int r, int counter)

It initially gets the following as its input from the main method

a= 1; r = 2; counter = 0

Its operation goes thus:

val = a*r; 1 * 2 = 2

Print val; Prints 2

if (counter > 4) { System.out.print("End"); } : Not true

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 2; r = 2; counter = 1

val = a*r; 2 * 2 = 4

Print val; Prints 4

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 4; r = 2; counter = 2

val = a*r; 4 * 2 = 8

Print val; Prints 8

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 8; r = 2; counter = 3

val = a*r; 8 * 2 = 16

Print val; Prints 16

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 16; r = 2; counter = 4

val = a*r; 16 * 2 = 32

Print val; Prints 32

else { myMathFunction(val, r, counter + 1); }: True

The value of counter is incremented by 1 and the function gets the following values:

a= 32; r = 2; counter = 5

val = a*r; 32 * 2 = 64

Print val; Prints 64

if (counter > 4) { System.out.print("End"); } : True

This prints "End"

So; the output of the program is:

2 4 8 16 32 64 End

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Answers

Monitor
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GPS
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a. True
b. False

Answers

The answer is true not false

Look at the code below and use the following comments to indicate the scope of the static variables or functions. Place the comment below the relevant line.

Module scope
Class scope
Function scope

#include
2
3 static const int MAX_SIZE=10;
4
5 // Return the max value
6 static double max(double d1)
7 {
8 static double lastMax = 0;
9 lastMax = (d1 > lastMax) ? d1 : lastMax;
10 return lastMax;
11 }
12
13 // Singleton class only one instance allowed
14 class Singleton
15 {
16 public:
17 static Singleton& getSingleton() { return theOne; }
18 // Returns the Singleton
19

Answers

Answer:

Explanation:

#include

static const int MAX_SIZE=10; //Class scope

// Return the max value

static double max(double d1) //Function scope

{

static double lastMax = 0;  //Function scope

lastMax = (d1 > lastMax) ? d1 : lastMax; //Function scope

return lastMax; //Module Scope

}

// Singleton class only one instance allowed

class Singleton  

{

public:

static Singleton& getSingleton()  //Function scope

{

return theOne; //Module Scope

}

// Returns the Singleton

Write a program that demonstrates how various exceptions are caught with catch(Exception exception). This time define classes ExceptionA (which inherits from class Exception) and ExceptionB (which inherits from class ExceptionA). In your program, create try blocks that throw exceptions of types ExceptionA, ExceptionB, NullPointerException and IOException. All exceptions should be caught with catch blocks specifying type Exception.

Answers

Answer:

Sorry mate I tried but I got it wrong!

Explanation:

Sorry again

Write a C++ function for the following:
Suppose that Account class has a method called withdraw, which will be inherited by Checking and Savings class. The withdraw method will perform according to account type. So, the late bind is needed. Declare the withdraw method in Account class. The method should take a double input as withdraw amount and output true if the withdraw successfully and false if the withdraw unsuccessfully.

Answers

Solution :

class Account

[tex]$ \{ $[/tex]

public:

[tex]$\text{Account}()$[/tex];

double [tex]$\text{getBalance}$[/tex]();

void [tex]$\text{setBalance}$[/tex]();

[tex]$\text{bool withdraw}$[/tex](double bal);

[tex]$\text{private}:$[/tex]

double [tex]$\text{balance}$[/tex];

}:

[tex]$\text{Account}()$[/tex] {}

double [tex]$\text{getBalance}$[/tex]()

[tex]$ \{ $[/tex]

[tex]$\text{return balance}$[/tex];

}

void [tex]$\text{setBalance}$[/tex](double [tex]$\text{balance}$[/tex])

[tex]$ \{ $[/tex]

this.[tex]$\text{balance}$[/tex] = [tex]$\text{balance}$[/tex];

}

[tex]$\text{boolean}$[/tex] withdraw([tex]$\text{double bal}$[/tex])

[tex]$ \{ $[/tex]

if([tex]$\text{balance}$[/tex] >= bal)

[tex]$ \{ $[/tex]

[tex]$\text{balance}$[/tex] = [tex]$\text{balance}$[/tex] - bal;

[tex]$\text{return}$[/tex] true;

}

[tex]$\text{return}$[/tex] false;

}

}

help asapp!!!!!! give the technical name means (write the name in one word) . the feature of virus which copies itself..​

Answers

Answer:

if a computer is made out of many copies it can cause a virus with a definition of a tro Jan by a virus

Explanation:

what follows is a brief history of the computer virus and what the future holds for this once when a computer is made multiple copies of it's so several reducing malicious intent here but animal and prevade fit the definition of a Trojan buy viruses worms and Trojans paint the name Malwar as an umbrella term

define the term hardwar

Answers

Answer:

tools, machinery, and other durable equipment.

Explanation:hardware in a computer are the keyboard, the monitor, the mouse and the central processing unit.

Answer: tools, machinery, and other durable equipment.

Explanation: the machines, wiring, and other physical components of a computer or other electronic system.

tools, implements, and other items used in home life and activities such as gardening. Computer hardware includes the physical parts of a computer, such as the case, central processing unit, monitor, mouse, keyboard, computer data storage, graphics card, sound card, speakers and motherboard. By contrast, software is the set of instructions that can be stored and run by hardware.

Ling has configured a delegate for her calendar and would like to ensure that the delegate is aware of their permissions. Which option should she configure?

Delegate can see my private Items
Tasks > Editor
Inbox > None
Automatically send a message to delegate summarizing these permissions

Answers

Answer:

Tasks>Editor (B)

Explanation:

I just did the test

Answer:

Tasks > Editor

Explanation:

Did the test

Imagine that you are helping to build a store management system for a fast food restaurant. Given the following lists, write a program that asks the user for a product name. Next, find out if the restaurant sells that item and report the status to the user. Allow the user to continue to inquire about product names until they elect to quit the program.

Answers

Answer:

The program in python is as follows:

def checkstatus(food,foodlists):

   if food in foodlists:

       return "Available"

   else:

       return "Not Available"

foodlists = ["Burger","Spaghetti","Potato","Lasagna","Chicken"]

for i in range(len(foodlists)):

   foodlists[i] = foodlists[i]. lower()

food = input("Food (Q to quit): ").lower()

while food != "q":

   print("Status: ",checkstatus(food,foodlists))

   food = input("Food (Q to quit): ").lower()

Explanation:

The program uses function.

The function is defines here. It accepts as input, a food item and a food list

def checkstatus(food,foodlists):

This check if the food is in the food lists

   if food in foodlists:

Returns available, if true

       return "Available"

Returns Not available, if otherwise

   else:

       return "Not Available"

The main begins here.

The food list is not given in the question. So, I assumed the following list

foodlists = ["Burger","Spaghetti","Potato","Lasagna","Chicken"]

This converts all items of the food list to lowercase

for i in range(len(foodlists)):

   foodlists[i] = foodlists[i]. lower()

Prompt the user for food. When user inputs Q or q, the program exits

food = input("Food (Q to quit): ").lower()

This is repeated until the user quits

while food != "q":

Check and print the status of the food

   print("Status: ",checkstatus(food,foodlists))

Prompt the user for another food

   food = input("Food (Q to quit): ").lower()

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