For the following exercises, solve each inequality and write the solution in interval notation.
30. 2| v − 7 | − 4 ≥ 42

Using the given exponential function, it is found that the colony would have 852 bacteria after 10 days.

The exponential function for the colonies' size is given as follows:

[tex]F = I(1 + r)^t[/tex]

In which:

The parameters are given as follows:

I = 55, r = 0.73, t = 5, as 10/2 = 5.

Hence the amount will be given by:

[tex]F = 55(1 + 0.73)^5 = 852[/tex]

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Answer:

Axis of symmetry: x = 2

Vertex: (2,4)

Step-by-step explanation:

Answer:

The temperature decreased by 9 degrees.

Step-by-step explanation:

Since the temperature in the morning was 2*C & at night, the temperature was -7*C, the temperature had to decrease using this equation =>  ||-7 + 2|| = x, with -2 being the temperature loss added as well. All we have to do is 7+2 = x & 9 = x, with x being the temperature drop.

Answer:

9 degrees Celcius

Step-by-step explanation:

The difference between 2 and -7 is 9.

Answer:

I think it is 72

Step-by-step explanation:

but the question doesn't make sense because it should tell the number of spoons per 1 cup of sugar, perhaps it was a copy-paste mistake?

Reflecting over y=x maps (x,y) onto (y,x).

So, the answer is A. (-8, 3).

Answer:

Step-by-step explanation:

The following equation simplified by factoring or distributing:

1.) 2(x + 3)

= 2x + 6

2.) 2(x + 3 + y)

= 2x + 6 + 2y

3.) −5 (2x − 3)

= -10x + 15

4.) –5(–8w + p)

= 40w - 5p

5.) 20 + 32w

= 4(5 + 8w)

6.) 84 + 36z

= 12(7 + 3z)

7.) (2x - 6)(5x + 7)

= 10x² + 14x - 30x - 42

= 10x² - 16x - 42

8.) (y - 10)(4y + 2)

= 4y² + 2y - 40y - 20

= 4y² - 38y - 20

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Place name of eights are ten thousands place & tens place & 80000, 80 are the values respectively.

The expanded form of a number is splitting of numbers based on place value. The place are ones, tens, hundreds, thousands, ten thousand etc

that is, the number represented by the sum of each digit multiplied by its place value is called the expanded form of a number.

Example : Expanded form of 4567 is 4000+500+60+7. where 4 is in thousands place, 5 is in hundreds place, 6 is in tens place and 7 is in ones place.

Given that, The speed of light is 186,282 miles per second.

The number is 186282.

Expanding the number, we get,

186282 = 100000+80000+6000+200+80+2

Here in the number 186282, eight present in the ten thousands place and in the tens place.

Since one eight is in ten thousands place, so the value is 80000

And the another eight is in the tens place, so the value is 80.

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If the Height of Eiffel Tower in Paris is 1063 feet tall and we took an elevator 3/4 up the tower then we would be 797.25 feet from the ground.

Given The height of the Eiffel Tower is 1063 feet tall. We have taken an elevator that is 3/4 up the tower.

Height is the measurement of someone  from head to foot or from base to top. It is the distance upward.

Height of The Eiffel tower is 1063 feet.

We have taken 3/4 up the elevator.

Then the height from ground to us can be calculated by multiplying 1063 by 3/4 which will be as under:

=1063*3/4

=729.25 feet

Hence if the height of the Eiffel Tower is 1063 feet then we would be 729.25 up from the ground if we have taken elevator 3/4 up the tower.

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Answers:

Lower bound = 41.3

Upper bound = 41.5

===========================================================

Explanation:

49.15 is the smallest f can be while 49.24 is the largest it can be. Well technically we could have something like 49.2499 or 49.24999 and so on. We slowly approach 49.25 but never actually get there

So the variable f is between 49.15 and 49.25 inclusive of the first value but excluding the second value. We can write it as [tex]49.15 \le f < 49.25[/tex]

For similar reasoning, [tex]7.75 \le g < 7.85[/tex]

-----------------

If we wanted to subtract those variables and get the smallest result possible, then we need to pick values that are closest together. It might help to set up a number line.

This means we'd go for f = 49.15 and g = 7.85

The lower bound for f-g is f-g = 49.15-7.85 = 41.3

In contrast, the upper bound is when the two variables are spaced as far apart as possible. The upper bound is f-g = 49.25 - 7.75 = 41.5

Answer:

See below

Step-by-step explanation:

49.2     could  be       49.15 <= f < 49.25

7.8        could be       7.75 <= f < 7.85

Lower bound of   f- g    would then be    49.15  - 7.85 > 41.3

upper bound     49.25 - 7.75 < 41.5

 41.3  < f-g < 41.5

The complete table is

x -12 -6 3 15

y -6 5 15 15

The domain is given as:

Domain = {-12, -6, 3, 15}.

The incomplete table is given as

x

y -6 5 15 15

Enter the domain in the x values

x -12 -6 3 15

y -6 5 15 15

Hence, the complete table is

x -12 -6 3 15

y -6 5 15 15

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The cars must have had the same Average Speed

Average speed is the mean value of the speed of a body over a period of time. The formula for average speed is needed since the speed of a moving body is not constant and varies across a period of time. Even with varying speed, the values of total time and the total distance covered can be used, and with the help of the formula for average speed, we can find a single value to represent the entire motion.

The average speed of a body is equal to the total distance covered, divided by the total time taken. The formula for average speed is given as:

[tex]\frac{Total distance covered by the object}{Total time taken}[/tex]

Given :-  

Substituting the given values in the formula for A and B respectively we get

Average Speed of A = [tex]\frac{30}{5}[/tex] m/s = 6 m/s

Average Speed of B = [tex]\frac{42}{7}[/tex] m/s = 6m/s

Thus the cars must have had the same Average Speed.

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Answer:

Step-by-step explanation:

Total Students = 20 + 18 = 38 students

For boys percentage = 20/38 * 100

Boys percentage = 52.6%

For girls percentage = 18/38 * 100

Girls percentage = 47.3%

Answer:

(i) 52.631578947368 %

(ii) 47.368421052632 %

Step-by-step explanation:

there are :

20 boys  

18 girls

Total number of students 38

========================

(i) the percentage of boys in the class

[tex]=\frac{20}{38} \times100 = 52.631578947368 \ \%[/tex]

(ii) the percentage of girls in the class

[tex]=\frac{18}{38} \times100 = 47.368421052632 \ \%[/tex]

Answer:

ASA Postulate

Step-by-step explanation:

The two angles and the side included between them of one triangle are equal to the corresponding angles and the included side of the other triangle. (Angle, Common Side, Angle)

The angle ∠14 and angle ∠16 are the supplementary angles. Then the measure of angle ∠16 will be 188° – 5x.

The angle is the distance between the intersecting lines or surfaces. The angle is also expressed in degrees. The angle is 360 degrees for one complete spin.

Supplementary angle - Two angles are said to be supplementary angles if their sum is 180 degrees.

The line l and the line m are parallel to each other.

The angle ∠7 = 4x – 3 and angle ∠14 = 5x – 8.

Then the measure of angle ∠16 will be

The angle ∠14 and angle ∠16 are the supplementary angles. Then we have

    ∠14 + ∠16 = 180°

5x – 8 + ∠16 = 180°

              ∠16 = 180° – 5x + 8

              ∠16 = 188° – 5x

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ATTACHED IS THE SOLUTION!!

Answer:

In polynomial function f(x) = 5x² + 2x³ + 4 the leading coefficient is 5.

The leading coefficient of a polynomial is the coefficient of the leading term 5x².

Step-by-step explanation:

Answer:

1)D 2) Can't see the function

Answer:

The exterior angle is 77

Step-by-step explanation:

The measure of the exterior angle of a triangle is equal to the sum of the two opposite interior angles.

2x+11 = x +44

First we need to find x

Subtract x from each side

2x+11-x = x+44

x +11 = 44

Subtract 11 from each side

x+11-11 = 44-11

x =33

Now we can find the exterior angle

2x+11 = 2(33)+11 = 66+11 = 77

The exterior angle is 77

Answer:

The evaluated function for the indicated values is given below.

The value of f(-3) is 20 .

The value of f(2) is 10 .

The value of f(-a) is [tex]$2|-3 a-1|$[/tex].

The value of -f(a) is [tex]$-2|3 a-1|$[/tex].

The value of f(a+h) is [tex]$2|3 a+3 h-1|$[/tex].

Step-by-step explanation:

A function [tex]$f(x)=2|3 x-1|$[/tex] is given.

It is required to evaluate the function at [tex]$f(-3) ; f(2) ; f(-a) ;-f(a) ; f(a+h)$[/tex].

To evaluate the function, substitute the indicated values in the given function to determine the output values and simplify the expression.

Step 1 of 5

The given function is [tex]$f(x)=2|3 x-1|$[/tex].

To evaluate the function at f(-3), substitute -3 in the given function [tex]f(x)=2|3 x-1|$\\ $f(-3)=2|3(-3)-1|$\\ $f(-3)=2|-9-1|$\\ $f(-3)=2|-10|$\\ $f(-3)=2(10)$\\ $f(-3)=20$[/tex]

Step 2 of 5

To evaluate the function at $f(2)$, substitute 2 in the given function.

[tex]f(x)=2|3 x-1|$\\ $f(2)=2|3(2)-1|$\\ $f(2)=2|6-1|$\\ $f(2)=2(5)$\\ $f(2)=10$[/tex]

Step 3 of 5

To evaluate the function at f(-a), substitute -a in the given function.

[tex]$$\begin{aligned}&f(x)=2|3 x-1| \\&f(-a)=2|3(-a)-1| \\&f(-a)=2|-3 a-1|\end{aligned}$$[/tex]

Step 4 of 5

To evaluate the function at -f(a), substitute a in the given function.

[tex]f(x)=2|3 x-1|$\\ $-f(a)=-2|3(a)-1|$\\ $-f(a)=-2|3 a-1|$[/tex]

Step 5 of 5

To evaluate the function at f(a+h), substitute a+h in the given function. [tex]$f(x)=2|3 x-1|$[/tex]

[tex]$$\begin{aligned}&f(a+h)=2|3(a+h)-1| \\&f(a+h)=2|3 a+3 h-1|\end{aligned}$$[/tex]

The algebraic expression of the given sentence is: 7(x - 1).

Let the unknown number be represented as x.

The word "difference" means subtraction which is "-". Multiplied means times.

We would have the following:

"Difference of x and 1" is: x - 1

x - 1 multiplied by 7 would be: 7(x - 1)

Therefore, the algebraic expression is: 7(x - 1).

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Answer:

2x^2 + 5x - 3

Step-by-step explanation:

Area = length (a) * width (b)

(x + 3) * (2x - 1)

2x^2 + 6x - x - 3 (combine like terms)

2x^2 + 5x - 3

Brainliest, please :)

Answer:

1. Function

2. Not a function

3. Function

4. Not a function

Step-by-step explanation:

A function just means that for each input it outputs only 1 output. This output isn't necessarily unique. So for example if you're just given: f(2) = 3 and f(1) = 3, this is a function since each input only outputs 1 value, even though the output isn't unique, but if you're given: f(3) = 2, f(2) = 1, f(3) = 3. that's not a function since f(3) outputs both 2 and 3.

Anyways now that you hopefully understand this, let's look at each image.

Relation 1: (Function)

   So for each input (the domain) it's only pointing to one output (range), even if multiple input (the domain) are pointing to the same output (the range), it's still a function.

Relation 2: (Not a function)

   This is not a function, since if you look at the input 7 (the range), you'll see it outputs two things (range). It outputs -6 and -7. So this is not a function

Relation 3: (Function)

   This is a function since each x-value (input) has only one y-value (output). So it's a function

Relation 4: (Not a functio)

   This is not a function, since there are multiply coordinates with the same x-coordinate (input) and different y-coordinates (output). The x-coordinate 2 has the output b, y, and m, and since no value is given for these variables, it can be assumed they're different values, thus it's not a function.

Using translation concepts, the function is given by:

C. [tex]y = \sqrt{x - 1} + 4[/tex].

A translation is represented by a change in the function graph, according to operations such as multiplication or sum/subtraction in it's definition.

The graphed function is the square root function shifted one unit to the right(x -> x - 1), and four units up(y -> y + 4), hence the function is:

C. [tex]y = \sqrt{x - 1} + 4[/tex].

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Answer:

C

Step-by-step explanation:

Mean: 9+6+18+2+13+3+5= 56/7 = 8

Median: 2,3,5,6,9,13,18 the middle number is 6

mode:none

In a 30°-60°-90° triangle,  the length of the longer leg is √3 times the length of the shorter leg and  length of the hypotenuse is twice the length of the shorter leg.

ACF is a 30º-60º-90º triangle because of the following reasons;

Based on a theorem, in a 30°-60°-90° triangle, it is said that the length of the longer leg is √3 times the length of the shorter leg and  length of the hypotenuse is twice the length of the shorter leg,

1 → short leg = 1

2 → hypotenuse = 2

√3 → long leg = √3

Using the Pythagorean theorem., we have that

a² + b² = c²

1² + b² = 2²

b² = 2² - 1²

b² = 4 - 1

b² = 3

√b² = √3

b = √3

Thus, in a 30°-60°-90° triangle,  the length of the longer leg is √3 times the length of the shorter leg and  length of the hypotenuse is twice the length of the shorter leg.

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Explanation:

For choice A, order matters. This is because of the positions of first place and second place are different from one another. Since order matters, we have a permutation for choice A and can rule it out.

Choices C and D are ruled out for the same reason.

Choice B is a combination. It doesn't matter what the order of the CDs are. All that matters is the group overall rather than the individual CDs.

Answer:

D. 16, 9, 8

Step-by-step explanation:

sum of any two sides of triangles must be greater than the third side

only the fourth option follows this rule

The the 21st, 26th, 65th, and 75th percentiles are 19.45, 21.7, 27.85, and 29.50.

Here, n=8

P21=(21(n+1)100)th value of the observation

=(21⋅9/100)th value of the observation

=1st observation +0.89[2nd-1st]

=15+0.89[20-15

= 19.45

P26 = (26(n+1)100)th value of the observation

=(26⋅9/100)th value of the observation

=2nd observation +0.34[3rd-2nd]

=20+0.34[25-20]

=20+0.34(5)

= 21.7

P65= (65(n+1)100)th value of the observation

=(65⋅9/100)th value of the observation

=5th observation +0.85[6th-5th]

=27+0.85[28-27

= 27.85

P75 = (75(n+1)100)th value of the observation

=(75⋅9/100)th value of the observation

6th observation +0.75[7th-6th]

=28+0.75[30-28]

= 28 + 1.50

= 29.50

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Answer:

Hence the expression [tex]$$(p+12)(p-5)=p^2+8p-60$$[/tex]

Step-by-step explanation:

Explanation

[tex]$$\frac{\begin{matrix}{} & {} & p & + & 12 \\ \times & {} & p & - & 5 \\ \end{matrix}}[/tex]

____________

[tex]{\frac{\begin{matrix}{} & - & 5p & - & 60 \\ {{p}^2} & + & 12p & {} & {} \\ \end{matrix}}{\begin{matrix}{{p}^2} & + & 8p & - & 60 \\ \end{matrix}}}$$[/tex]