For each graph below, state whether it represents a function.

N = Number of data

x1...xn = Samples

Let's calculate first:

Now:

So:

The true equation is 5 + n = 6.2.

Here we have to find the equation for which n = 1.2.

So the first equation is

10n = 1.2

So for this, we get the value of n as:

n = 1.2/10

  = 0.12

which is not equal to 1.2.

So it is not correct

The second equation is:

n + 1 = 1.2

n = 0.2

which is not equal to 1.2

So it is also not correct.

The third equation is:

5 + n = 6.2

n = 6.2 - 5

  = 1.2

So it is correct.

The fourth equation is:

1.2n = 10

n = 10/1.2

  = 8.33

Here n is not equal to 1.2

So it is also correct.

Therefore the correct equation is 5 + n = 6.2.

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The Solution:

Given:

Required:

To find the value of V - W

Therefore, the correct answer is [option 3]

Answer:7937

Step-by-step explanation:7596

The formula to calculate the volume of a sphere is given to be:

where r is the radius.

From the question, we have the following parameters:

Therefore, the volume is calculated to be:

The volume is 463.0 cm³.

The area of the composite figure will be the sum of the area of the square and the area of the semicircle. The formula for determining the area of a square is expressed as

Area = length^2

From the diagram,

length = 12

Area of square = 12^2 = 144

The formula for determining the area of a semicircle is expressed as

Area = 1/2 * pi * radius^2

Radius = diameter/2

The diameter of the semicircle is 12. Thus,

radius = 12/2 = 6

pi = 3.14

Area of semicircle = 1/2 * 3.14 * 6^2 = 56.52

Area of composite figure = 144 + 56.52 = 200.52 in^2

The first option is the correct answer

Answer:

14x+3 is the answer I think

The solution to the given equation would be [tex]14x+3[/tex].

Hope this helps!

Let's solve for x and see what properties are used

First, add 10 to both sides of the equation

Now, divide by 5 on both sides of the equation

Therefore, the correct answer is C. Adition and division

The probability that a randomly chosen applicant has a graduate degree, given that they are female is 0.236.

Probability refers to a possibility that deals with the occurrence of random events. The probability of all the events occurring need to be 1.

P(E) = Number of favorable outcomes / total number of outcomes

Given that 249 are female and 59 are female and have a graduate degree out of 450 applicants.

We are given following in the question;

M: Applicant is male.

G: Applicant have a graduate degree

F : Applicant is female.

The Total number of applicants = 450

Number of female applicants = 249

Number of female applicants have a graduate degree = 59

Therefore,

P(G/F) = P([tex]G^F[/tex])/P(F)

= 59/207 or 0.236

Hence, the probability that a randomly chosen applicant has a graduate degree, given that they are female is 0.236.

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Explanation

We are given the following:

The table above models the function:

We are required to determine how many offspring there would be for the fifth and sixth generations using the equation.

This is achieved thus:

Hence, the answers are:

The total yards gained or lost is the algebraic sum so the resultant yards is -15 yards thus they lose 15 yards.

Arithmetic operators are four basic mathematical operations in which summation, subtraction, division, and multiplication involve.,

Subtraction = Minus of any two or more numbers.

Summation = addition of two or more numbers or variable

Let's consider all gained yards by positive (+) and all lost yards by negative (-).

Given that,

In the first play = +8 yards (gain)

In second play = -12 yards (lost)

In the third play = 11 yards (Lost)

So total yards = +8 - 12 - 11 = -15 (Lost)

Therefore, the football team lost 15 yards.

Hence "The total yards gained or lost is the algebraic sum so the resultant yards is -15 yards thus they lose 15 yards".

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(1) $50,600 cash implies that $50,600 - $38,400 = $12,200

Hence gets gain of $12,200.

(2) $38,400 cash implies that $38,400 - $38,400 = $0

Hence No profit no loss.

(3) $33,300 cash implies that $33,300 - $38,400 = - $5,100

Hence loss of $5,100.

Depreciation is the gross reduction in the book value of an asset due to regular use or wear and tear.

A capital gain occurs when Garcia Co. receives an amount in excess of the book value of the equipment.

If Garcia Co. receives an amount equal to the book value of the equipment, no profit or loss will result from the disposal.

If Garcia Co. receives an amount below the book value of the equipment, it will experience a capital loss.

In the given question cost of equipment is $81,600 with accumulated depreciation of $43,200 so that the book value will be

$81,600 - $43,200 = $38,400.

Now (1) $50,600 cash implies that $50,600 - $38,400 = $12,200

Hence gets gain of $12,200.

For (2) $38,400 cash implies that $38,400 - $38,400 = $0

Hence No profit no loss.

For(3) $33,300 cash implies that $33,300 - $38,400 = - $5,100

Hence loss of $5,100.

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Answer:

Step-by-step explanation:

The scale factor is:

Find the width of the parking lot in the drawing:

Cross multiply and find the value of x:

The net pay for Lonnie Flanagan is $1065.

From the information, Lonnie weekly gross pay is $1250 and each week she has $64.37 in deductions, plus state tax of 2% of her gross pay, social security taxes of 6.2%, and Medicare taxes of 1.45%.

Her net pay will be:

= Gross pay - Deduction - Tax - Social security - Medicare

= $1250 - $64.37 - (2% × $1250) - (6.2% × $1250) - (1.45% × $1250)

= $1250 - $64.37 - $25 - $$77.50 - $18.125

= $1065

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ANSWER:

7

STEP-BY-STEP EXPLANATION:

We have the following data:

The median is the data value that separates the upper half of a data set from the lower half. Therefore:

In this case, being even, the two data are half, but since the value is the same, that is, 7, the median is equal to 7.

The interpretation of this value is in the middle of the 10 days (days 5 and 6), 7 would be the number of cars in a town given a a speeding ticket.

If a rectangular prism has dimensions of 2cm by 2 cm by 5 cm, then the surface area of the rectangular prism is 48 centimeter square

The length of the rectangular prism = 2 cm

The width of the rectangular prism = 2 cm

The height of the rectangular prism = 5 cm

The surface area of the rectangular prism = 2(lw+lh+hw)

Where l is the length

w is the width

h is the height

Substitute the values in the equation

The surface area of the rectangular prism = 2(2×2+2×5+2×5)

= 2(4+10+10)

= 2×24

= 48 centimeter square
Hence, if a rectangular prism has dimensions of 2cm by 2 cm by 5 cm, then the surface area of the rectangular prism is 48 centimeter square

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Finding the ratio of

a)1:9

b)2 : 7

c) 2 : 5

What is Ratio?

A ratio indicates how often one number contains another number. For example, if a fruit bowl contains 8 oranges and 6 lemons, the ratio of oranges to lemons is 8 to 6. Similarly, the ratio of lemons to oranges is 6:8 and the ratio of oranges to whole fruit is 8:14.

Given,

Total no. of students =  42

a) Students who prefer punk to students who prefer hip-hop

  No. of students in punk = 2

  No. of students in hip-hop = 18

The Ratio will be,

punk : hip-hop = 2:18

                        = 1:9

b) Students who prefer rock to total no. of students that are surveyed

No. of students in rock = 12

Total no. of students =  42

The Ratio will be,

rock : total students = 12 : 42

                                 = 2 : 7

c) Students who prefer rock or classic rock to students who prefer all music

No. of students in rock = 12

Total no. of students who likes other music =  42 - 12

                                                                        = 30

The Ratio will be,

rock : total students with different music = 12 : 30

                                                                    = 2 : 5

Hence, The ratio comparison in three different way

a)1:9

b)2 : 7

c) 2 : 5

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ANSWER:

The value of x is 20

STEP-BY-STEP EXPLANATION:

By properties of the angles we know that these angles are equal, since they are alternative external angles. Thanks to that we can do the following equality to calculate the value of x:

Solving for x:

Answer:

-3

Step-by-step explanation:

4(a) - 2(a + b) + 1 = [?]

4(2) - 2(2+4) + 1

8 - 4 - 8 + 1

appilcation of bodmas

4 - 8 + 1

- 4 + 1

-

3

The diagonal WY bisects the diagonal XV at point D, which means that XV is divided into two equal line segments XD and XV.

Replace the equation above with the given expressions for both line segments:

XD= 2x-6

XV= 3x-6

There is a 5% chance that second graders will be faster than 94.597 wpm.

Sample size = 21

standard deviation = 10 wpm

SE = 10/sqrt(21) = 2.18 as a consequence.

Let X be the average reading speed of 21 second-grade students. z = (X - 91)/2.18 Normal(91,2.18) (91,2.18).

If the 95th percentile of a standard normal variable z is 1.65 [5% probability], the outcome is 91 + 1.65 x 2.18 = 94.597.

So there's a 5% chance that the average reading speed of a random sample of 21 second-graders will be faster than 94.597 wpm.

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a.

From the graph we notice that when x=-1 the value of the function is zero; therefore:

and it is not negative.

b.

The function is positive when its graph is above the x-axis. We notice that this happens in two regions of the graph:

From -4 to -3

From -1 to 4

Therefore, the function is positive in:

c.

The function is zero when the graph intersect the x-axis; from the graph we have that the function is zero for:

the maximum height is 254 feet.

Answer:

a)  0.5 seconds and 3.5 seconds.

b)  5.98 seconds (2 d.p.)

c)  No.

d)  254 feet at 2 seconds.

Step-by-step explanation:

Given equation:

[tex]h=-16t^2+64t+190, \quad t \geq 0[/tex]

where:

To calculate when the object will be 218 feet above the ground, substitute h = 218 into the equation and solve for t:

[tex]\begin{aligned}\implies -16t^2+64t+190 & = 218\\-16t^2+64t+190-218& = 0\\-16t^2+64t-28 & = 0\\-4(4t^2-16t+7) & = 0\\4t^2-16t+7 & = 0\\4t^2-14t-2t+7 &=0\\2t(2t-7)-1(2t-7)&=0\\(2t-1)(2t-7)&=0\\\implies 2t-1&=0\implies t=\dfrac{1}{2}\\\implies 2t-7&=0 \implies t=\dfrac{7}{2}\end{aligned}[/tex]

Therefore, the object will be 218 feet about the ground at 0.5 seconds and 3.5 seconds.

The object strikes the ground when h is zero. Therefore, substitute h = 0 into the equation and solve for t:

[tex]\begin{aligned}\implies -16t^2+64t+190 & = 0\\-2(8t^2-32t-95) & = 0\\8t^2-32t-95 & = 0\end{aligned}[/tex]

Use the quadratic formula to solve for t:

[tex]\implies t=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}[/tex]

[tex]\implies t=\dfrac{-(-32) \pm \sqrt{(-32)^2-4(8)(-95)} }{2(8)}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{1024+3040} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{4064} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{16 \cdot 254} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{16} \sqrt{254} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm 4 \sqrt{254} }{16}[/tex]

[tex]\implies t=\dfrac{8\pm \sqrt{254} }{4}[/tex]

As t ≥ 0,

[tex]\implies t=\dfrac{8+ \sqrt{254} }{4}\quad \sf only.[/tex]

[tex]\implies t=5.98 \sf \; s \; (2 d.p.)[/tex]

Therefore, the object strikes the ground at 5.98 seconds (2 d.p.).

To find if the object will reach a height of 300 feet above the ground, substitute h = 300 into the equation and solve for t:

[tex]\begin{aligned}\implies -16t^2+64t+190 & = 300\\-16t^2+64t+190-300 & =0\\-16t^2+64t-110 & =0\\-2(8t^2-32t+55) & =0\\8t^2-32t+55& =0\end{aligned}[/tex]

Use the quadratic formula to solve for t:

[tex]\implies t=\dfrac{-b \pm \sqrt{b^2-4ac} }{2a}[/tex]

[tex]\implies t=\dfrac{-(-32) \pm \sqrt{(-32)^2-4(8)(55)} }{2(8)}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{1024-1760} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{-736} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{16 \cdot -1 \cdot 46} }{16}[/tex]

[tex]\implies t=\dfrac{32 \pm \sqrt{16} \sqrt{-1} \sqrt{ 46}}{16}[/tex]

[tex]\implies t=\dfrac{32 \pm 4i\sqrt{ 46} }{16}[/tex]

[tex]\implies t=\dfrac{8\pm \sqrt{ 46} \;i}{4}[/tex]

Therefore, as t is a complex number, the object will not reach a height of 300 feet.

The maximum height the object can reach is the y-coordinate of the vertex.  

Find the x-coordinate of the vertex and substitute this into the equation to find the maximum height.

[tex]\textsf{$x$-coordinate of the vertex}: \quad x=-\dfrac{b}{2a}[/tex]

[tex]\implies \textsf{$x$-coordinate of the vertex}=-\dfrac{64}{2(-16)}=-\dfrac{64}{-32}=2[/tex]

Substitute t = 2 into the equation:

[tex]\begin{aligned}t=2 \implies h(2)&=-16(2)^2+64(2)+190\\&=-16(4)+128+190\\&=-64+128+190\\&=64+190\\&=254\end{aligned}[/tex]

Therefore, the maximum height of the object is 254 feet.

It takes 2 seconds for the object to reach its maximum height.

The probability of getting exactly 5 heads in 10 tosses of a coin 24.6%

What is Probability ?

The area of mathematics known as probability deals with numerical representations of the likelihood that an event will occur or that a statement is true. An event's probability is a number between 0 and 1, where, roughly speaking, 0 denotes the event's impossibility and 1 denotes certainty.

Ten times are spent flipping coins.

Total number of results = 2¹⁰ = 1024

C(10, 5) = 252 is the total number of favorable outcomes.

Probability is

252/1024,

which equals :

=0.24, or

=24.6%.

Therefore, the chance of getting exactly 5 "heads" out of a possible 10 is 0.246, or 24.6%.

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Answer:

x equals to 11!!!

Answer:

11.

Step-by-step explanation:

1.02 x 10^11 = 102,000,000,000

Hope this helps!

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The  sample size should be taken as 545.6 to obtain a margin of error of 0.042 for the estimation of a population proportion.

What is sample size?

The process of deciding how many observations or replicates to include in a statistical sample is known as sample size determination. Any empirical study with the aim of drawing conclusions about a population from a sample must take into account the sample size as a crucial component. The sample size chosen for a study is typically influenced by the cost, convenience, or ease of data collection as well as the requirement that the sample size have adequate statistical power.

As given in the question,

Confidence level is 95% and the margin of error is 0.042

So,  

1 - α = 0.95,

α = 0.05,

E = 0.042

planning value (p) = 0.5

To calculate Sample size the formula is:

[tex]n = \frac{p(1-p)(Z_{a/2})^2}{E^2}[/tex]

From the table we can find that:

[tex]Z_{a/2} = 1.96[/tex]

Putting the values given in the question in formula:

[tex]n = \frac{0.5(0.5)(1.96)^2}{(0.042)^2}[/tex]

[tex]n = \frac{(0.25)(1.96)^2}{(0.042)^2}[/tex]

[tex]n = \frac{(0.25)(3.841)}{0.00176}[/tex]

n = 545.6

Hence the sample size is 545.6

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Explanation

Given the equation;

Using a graphing calculator, the graph of the circle becomes;

Answer:

1) Let's verify whether that's true or not, plugging in that point into the equa

(-4,2)

Since this is an identity, in other words, the left side is equal to the right side then we can say that's true.

So that's true y=-5/2x-8 is the equation of the line that has in one of its points the y-coordinate y=-8

The Angle-Side-Angle (ASA) criterion states that any two angles and the side included between them of one triangle are identical to the corresponding angles and the included side of the other triangle if two triangles are congruent. One of the requirements for two triangles to be congruent is angle side angle.

When two parallel lines are intersected by another line, comparable angles are the angles that are created in matching corners or corresponding corners with the transversal.

If the three sides and the three angles of both angles are equal in any orientation, two triangles are said to be congruent.

Given,

M∠1 = M∠2

(On joining BD and CD)

M∠ADB = M∠ADC

In ΔABD and ΔADC

M∠ADB = M∠ADC  (Given)

M∠BAD = M∠DAC  (Given)

AD = AD  (Common Sides)

⇒ ΔABD ≅ ΔADC  (Angle Side Angle Property)

So, BD = CD  (Corresponding sides are equal to a Congruent Triangle)

Hence, proved that BD = CD.

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Consider that there are, generally, the following types of angles pairs,

1. Adjacent Angles: Angles that share a common side and are formed on the same vertex.

2. Complementary Angles: Angles that are adjacent and together form a right angle.

3. Supplementary Angles: Angles that are adjacent and whose sum of degree measures is 180 degrees.

a.

The adjacent angles to angle 4 are angles 1 and 3.

There are no complementary angles associated with angle 4.

The supplementary angles to angle 4, are angles 1 and 3.

Thus, the angle pairs that include angle 4 are,

b.

The adjacent angles to angle 5 are angles 6 and 7.

There are no complementary angles associated with angle 5.

The supplementary angles to angle 5, are angles 6 and 7.

Thus, the angle pairs involving angle 5 are,