The weight of the car on the 12 degree slope is 546.72 lbs. This weight is important to know for various reasons, such as calculating the amount of force and energy required to move the car up the hill.
The weight of a car on a 12 degree slope can be calculated using the formula:
Weight = Force * sin(Slope Angle)
Therefore, the weight of the car on the 12 degree slope can be calculated as follows:
Weight = 650 lbs * sin(12°)
Weight = 546.72 lbs
The weight of a car on a 12 degree slope is important to know for various reasons. For example, if the car is being driven up the slope, it is important to know the weight of the vehicle to ensure that it will be able to make it up the hill. Additionally, knowing the weight of the car on the slope can help engineers and designers to calculate the amount of force and energy required to move the car up the hill.
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Calculate the acceleration of the car in stage A if it has a mass of 1200kg
stage A: 3000N
Answer:
2.5 m/s²
Explanation:
F = ma (Newton's 2nd Law)
a = F/m = 3,000 N / 1,200 kg = 2.5 m/s²
a local am radio station broadcasts at an energy of kj/photon. () calculate the frequency at which it is broadcasting.
The frequency at which it is broadcasting is 875 KHz for a local am radio station broadcasts at an energy of kj/photon
Given,
Energy of a photon = 5.80 x 10-31 kJ x ( 1000 J / 1kJ) = 5.8 x 10-28 J
We know,
E = hv
Here,
"h" is the plank's constant = 6.626 x 10-34 J.s
v = frequency in Hz
Now, rearranging the formula,
v = E / h
Substituting the values,
v = 5.8 x 10-28 J / 6.626 x 10-34 J.s
v = 875340 s-1 or Hz
Now, converting Hz to kHz,
Given, 1kHz = 103 Hz
= 875340 Hz x ( 1 kHz / 103 Hz)
= 875.3 kHz
Frequency = 875 kHz [3S.F]
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Two blocks A and B of masses 5 kg and 1 kg are connected with the help of massless strings
The system is just at the verge of slipping. The coefficient of static friction between the block A and surface below it is
Answer:
The coefficient of friction between all contact surfaces is 0.4. The force, necessary to move the block B with constant velocity, will be (g = 10 m/s)
The coefficient of friction between all contact surfaces is 0.4. The force, necessary to move the block B with constant velocity, will be (g = 10 m/s).
In which condition block B moves?Two blocks A and B of masses 5 kg and 1 kg are connected with the help of massless strings and the system is just at the verge of slipping. The coefficient of static friction between the block A and surface below it is necessary to move the block B.
Static friction is the friction that exists between two surfaces that are not trying to move over each other and which must be overcome before one object starts moving the other.
Two blocks are static equilibrium indicates that the force acting on both blocks is equal.
The frictional force acting on block A is calculated as follows:
Frictional force = coefficient of static friction * normal reaction
Normal reaction on Block A = 30 * 9.8
The coefficient of static friction between block A and the surface = 0.55
Frictional force = 30 * 9.8 * 0.55
Force on Block B = 161.7
Mass of Block B = 161.7 / 9.8
Mass of Block = 18 kg
Therefore, The coefficient of friction between all contact surfaces is 0.4. The force, necessary to move the block B with constant velocity, will be (g = 10 m/s).
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A speaker fixed to a moving platform moves toward a wall, emitting a steady sound with a frequency of 225Hz . A person on the platform right next to the speaker detects the sound waves reflected off the wall and those emitted by the speaker.How fast should the platform move, vp, for the person to detect a beat frequency of 1.00Hz ?
The speed of the platform so that the person detects a beat frequency of 1.00 Hz is 5.286m/s.
The speaker moving towards the wall is emitting the sound of frequency of 115Hz and the platform right next to the speaker is detecting the sound reflected by the wall and emitted by the speaker.
Now, to find the speed of the platform so that the person here the beta frequency pf 1.00Hz, we will use the relation,
F = (c+v/c-v)f
c = Speed of waves in the medium
u = Speed of the receiver relative to the medium
v = Speed of the source relative to the medium
f = emitted frequency
Our values are given,
Beat frequency = 7Hz
Reflective Doppler frequency = 225+7=232Hz
Putting values,
232 = (c+v/c-v)225
solving further,
v = 5.286 m/s.
So, the speed of the platform shoud be 5.286m/s.
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Can someone help me in this question?
Answer:
3×x for both .they did the same amount.
Lab Report( 80 )
Energy
It’s time to complete your Lab Report. Save the lab to your computer with the correct unit number, lab name, and your name at the end of the file name (e.g., U1_ Lab_Energy_Alice_Jones.doc).
Introduction
1. What was the purpose of the experiment?
Type your answer here:
2. What were the independent, dependent, and control variables in your investigation? Describe the variables for the first part of the experiment.
Type your answer here:
Experimental Methods
1. What tools did you use to collect your data?
Type your answer here:
2. Describe the procedure that you followed to collect the data for the first part of the experiment.
Type your answer here:
Data and Observations
1. Record your observations in the data table.
Type your answer here:
Table 1. Measurements Taken from a Simulation of a [insert mass value] kg Ball Released from Various Heights on a Ramp
Mass of ball (kg) Drop height on ramp (m) Potential energy (J) Time to travel 1.0 m (s) Speed (m/s) Kinetic energy (J)
0.5
1.0
1.5
2.0
2.5
3.0
Conclusions
1. What conclusions can you draw about how the amount of potential energy stored in a system changes as a ball is placed at varying heights on a ramp? Write an evidence-based claim.
Type your answer here:
2. Develop a model (diagram) that shows how different amounts of gravitational potential energy (GPE) are stored in the earth-ball system when the ball is raised to different heights on the ramp.
Type your answer here:
3. How did you use what you learned from the first part of the experiment to design a marble run?
Type your answer here:
Pls answers all of these questions quickly
Answer:
Is this a research paper?
how many km would you have to go above the surface of the earth to for your weight to decrease by half
When we go 19113 Km above the surface of earth, the weight of the person will become half.
The weight of the person is given by
W = Mg
Where,
M is mass of the person and g is the gravitational acceleration.
The gravitational acceleration of the earth varies with the height from the surface of the earth as,
g' = g(R/(R+H))²
Where,
R is the radius of earth,
g' is the gravitational acceleration at height H,
For g' = g/2,
g/2 = g(R/(R+H))²
1/√2 = (R/(R+H))²
Solving further,
H = 3R
So, when we go to a distance 3R above the surface of earth the weight of the person will become half.
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When you drop a 0.4 kg apple, Earth exerts a
force on it that accelerates it at 9.8 m/s
2
toward the earth’s surface. According to Newton’s third law, the apple must exert an equal
but opposite force on Earth.
If the mass of the earth 5.98 × 1024 kg, what
is the magnitude of the earth’s acceleration
toward the apple?
Answer in units of m/s
Answer:
Explanation:
a = ΣF/m
a = (0.4kg * 9.8m/s^2)/(5.98 * 10^24kg)
a = 6.56 * 10^-25 m/s^2
what is the effect on current through a circuit of steady resistance when the volatage and resistance is doubled?
When the voltage and resistance is doubled the current will remain constant.
The voltage and resistance are inversely correlated, and the current is directly proportional to both. Any change in voltage will have an equal and opposite effect on current. Therefore, doubling or tripling the voltage will result in doubling or tripling the current.We know that I = V/R where I = current V = voltage and R = resistance such that
Given voltage is doubled so v2 = 2V
and resistance is also doubled so R2= 2R
I2 = V2/R2 = 2V/2R = V/R = I
Hence I2 = I
Therefore the current will remain same when both voltage and resistance are doubled.
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A bicyclist traveling at 24 km/h squeezes the brakes and slows down to a stop in 2.5 seconds. Which of the following statements best describes what happened to the energy of the moving bicycle? A The kinetic energy was converted to thermal energy. B The chemical energy was converted to mechanical energy. C The kinetic energy was converted to chemical energy. D The chemical energy was converted to thermal energy.
Answer:
A The kinetic energy was converted to thermal energy
Explanation:
Friction braking is the most commonly used braking method in modern vehicles. It involves the conversion of kinetic energy to thermal energy by applying friction to the moving parts of a system. The friction force resists motion and in turn generates heat, eventually bringing the velocity to zero.
Answer:
The correct answer is A: The kinetic energy was converted to thermal energy.
When a bicyclist squeezes the brakes and slows down to a stop, the kinetic energy of the moving bicycle is converted to thermal energy. This is because the brakes on a bicycle work by converting the kinetic energy of the moving bike into heat energy through friction. When the brakes are applied, the brake pads clamp down on the brake rotor, which is attached to the wheel. The friction between the brake pads and the brake rotor slows the wheel down and converts the kinetic energy of the moving bicycle into heat energy. This heat energy can then be dissipated through the brake pads and the brake rotor, causing the bicycle to come to a stop.
Explanation:
Johnny finds it difficult to play catch on a planet Binu because the planets escape speed is only 5.00m/s and if jonny throws the ball too hard, it flies away. If planet Binu has a mass of 1.56x10^15kg, what is the radius
Answer:
Approximately [tex]4.16 \times 10^{3}\; {\rm m}[/tex] (or equivalently, [tex]4.16\; {\rm km}[/tex]) assuming this planet is spherical.
Explanation:
Let [tex]m[/tex] denote the mass of the ball. If the speed of the ball is [tex]v[/tex], the kinetic energy of the ball will be [tex](\text{KE}) = (1/2)\, m\, v^{2}[/tex].
Assume that the planet is spherical. Let [tex]r[/tex] denote the radius of the planet. Let [tex]M[/tex] denote the mass of this planet, and let [tex]G[/tex] denote the gravitational constant.
On the surface of this planet, the gravitational potential energy [tex](\text{GPE})[/tex] of this ball will be [tex](\text{GPE}) = (-G\, M\, m) / (r)[/tex]. (Note the negative sign. The ball is trapped inside the gravitational field of the planet, and it takes energy input to bring the ball out of this field.)
The ball is at its escape speed [tex]v_{e}[/tex] if the sum of [tex](\text{KE})[/tex] and [tex](\text{GPE})[/tex] at the surface of the planet is [tex]0[/tex]. In other words:
[tex](\text{KE}) + (\text{GPE}) = 0[/tex].
[tex]\begin{aligned}\frac{1}{2}\, m\, v^{2} + \frac{- G\, M\, m}{r} = 0\end{aligned}[/tex].
Rewrite this equation and solve for radius [tex]r[/tex].
[tex]\begin{aligned}\frac{G\, M\, m}{r} = \frac{1}{2}\, m\, v^{2}\end{aligned}[/tex].
[tex]\begin{aligned}r &= \frac{v^{2}}{2\, G\, M}\end{aligned}[/tex].
[tex]\begin{aligned}r &= \frac{2\, G\, M}{{v_{e}}^{2}} \\ &= \frac{2\, (6.67 \times 10^{-11}\; {\rm m^{3}\cdot kg^{-1} \cdot s^{-2})\, (1.56 \times 10^{15}\; {\rm kg})}}{(5.00\; {\rm m\cdot s^{-1}})^{2}} \\ &\approx 8.32 \times 10^{3}\; {\rm m}\end{aligned}[/tex].
An object is launched at a velocity of 20 m/s in a direction making at an angle of 25⁰ upward with the horizontal. Find
(a) The maximum height reached by the object.
(b) The magnitude of the velocity of the object before it hits the ground.
Answer:
below
Explanation:
Vertical position = vo t + 1/2 at ^2
where vo = 20 sin25 =8.45 and a = -9.81 m/s^2
Vertical position = - 4.905 t^2 + 8.45 t
max will occur at t = -b/2a = -8.45 / (2* -4.905) = .861 s
Plug in this value to find vertical height
vertical position = 8.45(.861) - 1/2 (9.81)(.861)^2 = 6.92 m
b) magnitude when it comes down = magnitude when it went up = 20 m/s
(a) is it possible for a path to also be a circuit? explain your reasoning. (b) is it possible for a path to also be a cycle? explain your reasoning.
(a). A circuit is just a path that ends and begins the same vertex, hence the yes answer. (b). In a graph, a route is a series of nearby sides who cross at the same vertices.
What does the word "circuit" mean?In electronics, a circuit is a completely circular conduit through which electricity travels. A simple circuit comprises a current provider, conductors, and a demand. The term "circuit" refers generally to any ongoing path for the transmission of energy, information, or a signal.
Briefing:(a). Any method of moving over the graph's edges is a route. There is no restriction on the beginning or ending vertices, edges, etc. A path is any feasible path that connects two vertices.
(b). In a cycle, the start and end vertices are the same. As a result, a route can be a cycle if its start and end vertices are similar and a cycle is established during traversal.
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A bungee jumper of 68 kg is attached to a bungee cord with an unstretched length of 20 m. He jumps off a bridge and when he finally stops, the cord has a stretched length of 50.0 m. Treat the stuntman as a point mass, and disregard the weight of the bungee cord. Assuming the spring constant of the bungee cord is 82.6 N/m, what is the total potential energy relative to the water when the man stops falling if the distance between the man and the water is 6m?
Answer:
Below
Explanation:
The man will have Gravitational POTENTIAL energy due to Earth's gravity of mgh
mgh = 68 kg * 9.81 m/s^2 * 6m = 4002 J
The bungee has ELASTIC potential energy of 1/2 k x^2
where x = stretch distance and k = spring constant
= 1/2 (82.6 N/m) ( 50-20 m)^2 = 37170 J
Total = 4002 + 37170 = 41172 J
a runner running the 100 m dash starts from rest and accelerates at a rate of 3 m/s^2 for 6.4s until reaching their maximum speed. they continue for the remainder of the race at the same speed. how long did it take them to complete the entire race
The runner takes 11.61 s to complete the entire race when they continue with same speed.
If the runner accelerated for 6.4 s, the velocity at which they accelerated will be:
Acceleration = velocity/time
3 = V/6.4
Making V the subject and by cross multiplying,
V = 3 × 6.4
V = 19.2 m/s
The runner maintains the speed through out the journey.
Speed = distance/time
Making time as the subject of formula,
Time = distance/speed
Time = 100 / 19.2
Time = 5.21 s
Therefore, a runner will complete the entire race in 6.4 + 5.21 = 11.61 s
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A bowling ball of mass 5.8 kg moves in a
straight line at 1.82 m/s.
How fast must a Ping-Pong ball of mass
3.276 g move in a straight line so that the two
balls have the same momentum?
Answer in units of m/s.
Answer:
v = 3231.09887 m/s
Explanation:
The attached image includes the steps to get to the answer provided.
which law states that an object will continue at its current velocity unless acted upon by an unbalanced force?
Answer:
Newton's First Law of Motion (aka Law of Inertia)
Explanation:
A vehicle undergoes acceleration when it
Speeds up
Slow down
Change direction
All of the above
Answer:
ALL OF THE ABOVE
Explanation:
A vehicle undergoes acceleration when what three things happen?
it gains speed, decreases speed, and changes direction .If there is acceleration, the velocity will change, either increasing or decreasing. The correct answer is D.
What is acceleration?The rate of growth of velocity is defined as acceleration. Acceleration usually indicates that the speed is changing, but this is not always the case. When an object is in motion in a circular track at a steady speed, it is still going to accelerate because its velocity direction changes.
Newton's Second Law states that an object's acceleration is the net result of all force applied to it. Acceleration is measured in meters per second squared.
The formula is given as,
a = Δv / Δt
If acceleration exists, the change of the velocity will be there and it may be increasing or decreasing. Then the correct option is D.
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is there evidence of the diffusion of starch molecules? if so, what evidence and in which direction did starch molecules diffuse?
Iodine molecules are small enough to pass freely through the membrane however, starch molecules are complex and too large to pass through the membrane. Initially, there was a higher concentration of iodine outside than inside the tube.
Thus iodine diffused into the tube with the starch. Iodine is able to pass through the membrane while starch is not. The Glucose-testing strips indicate that glucose has been able to pass out of the tubing and into the external fluid. Thus proving the tubing allows movement in both directions.
Iodine was able to diffuse across the membrane because it is small and hydrophobic and starch was not because it is too large The Dialysis tubing provides a semi-permeable membrane. Only allowing smaller molecules to pass through it. Iodine molecules are small enough to pass freely through the membrane, however, starch molecules are complex and too large to pass through the membrane.
The iodine is a small molecule and can move from outside the tubing to inside it. To test whether iodine or starch has crossed the synthetic membrane, you will look for color change. A solution of iodine is tan and a solution of starch is milky white; when iodine and starch are together in the same solution, they react and the solution turns purple, dark blue, or black.
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you do more work on yourself against gravity when you run up the stairs than when you walk slowly. true false
False; running up stairs really requires less exertion against gravity than leisurely walking up them.
Gravity, which means "weight" in Latin, is a basic interaction in physics that causes all objects with mass or energy to be attracted to one another. By far the weakest of the four basic interactions, gravity is 1038 times weaker than the strong interaction, 1036 times weaker than the electromagnetic force, and 1029 times weaker than the weak interaction. As a result, it has no discernible impact on the level of subatomic particles. The motion of planets, stars, galaxies and even light are all governed by gravity, which is the most important interaction between things at the macroscopic level.
On Earth, gravity imparts weight to tangible objects, and the Moon's gravity is what causes sublunar tides in the seas.
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when a nucleus of 235u undergoes fission, it breaks into two smaller, more tightly bound fragments. - Calculate the binding energy per nucleon for ^235U? (Express with appropriate units)- Calculate the binding energy per nucleon for the fission product ^137 Cs? (Express in appropriate units)
The binding energy per nucleon of 235-U and 137-Cs is given below when a nucleus of 235u undergoes fission
235-U = 7.6 MeV
137-Cs = 8.39 MeV
What is the 235-U and 137-Cs nucleons' binding energy?
The following equation gives a nucleus' binding energy:
mc2 = BE, where BE is the binding energy.
m is a mass defect.
For 235U, c = 931.49 MeV/u is the speed of light.
A=235 m=1.9150664 BE=1.9150664 *931.49 MeV/u BE=1783.8648 MeV
The equation BE/A BE/A = 1738.648 MeV / 235 BE/A = 7.6 MeV determines the binding energy per nucleon.
Binding energy for 137-Cs is:
BE = 1.23383 u * 31.49 MeV/u, where m is the mass defect, giving 1149.3003 MeV.
The binding energy per nucleon, BE/A, is as follows:
A is 137 in the instance of 137-Cs, hence BE/A equals 1149.3003 MeV / 137 BE/A is 8.39 MeV.
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what is the mass of the air in a room measuring sm x 2m x 3m? density of the air is 1.3kg/m³
Answer:
The mass of the air in a room can be calculated by multiplying the volume of the room by the density of the air. The volume of the room can be calculated by multiplying its length, width, and height. So, if the room has dimensions of 1m x 2m x 3m, its volume would be 1m x 2m x 3m = 6 cubic meters. If the density of the air in the room is 1.3kg/m³, the mass of the air in the room would be 6m³ x 1.3kg/m³ = 7.8kg.
two coins are released from the same height in an experiment. the first is dropped vertically. the second slides down a frictionless track. which coin has the greatest speed when they reach the bottom?
Answer:
1/2 m v^2 = E conservation of energy
Both will have the same speed.
v = (s2 - s1) / t holds for both coins
The coin that slides down the frictionless track will take longer to reach the bottom - the speed for both at the bottom will be the same
A 90 kg fullback is running at 5 m/s and is stopped by a tackler. The tackle lasts for 0.5 second.
a. What is the original momentum of the fullback?
b. What is the impulse imparted on the fullback?
c. What is the force exerted on the fullback?
d. What is the force exerted on the tackler?
A. The original momentum of the fullback is 450 Kg.m/s
B. The impulse imparted on the fullback is 450 Ns
C. The force exerted on the fullback is 900 N
D. The force exerted on the tackler is -900 N
A. How do I determine the original momentum?
The original momentum of the fullback can be obtained as follow:
Mass of fullback = 90 KgVelocity of fullback = 5 m/sMomentum of fullback =?Momentum = mass × velocity
Momentum of fullback= 90 Kg × 5 m/s
Momentum of fullback = 450 Kg.m/s
B. How do I determine the impulse imparted?
The impulse imparted, can be obtained as shown below:
Mass (m) = 90 KgInitial velocity = 5 m/sFinal velocity = 0 m/sImpulse =?Impulse = m(v + u) since the came to rest
Impulse = 90 × (0 + 5)
Impulse = 90 × 5
Impulse = 450 Ns
C. How to determine the force exerted on the fullback?
The force exerted on the fullback can be obtain as follow:
Impulse = 450 NsTime = 0.5Force (F) = ?Impulse = force × time
450 = Force × 0.5
Divide both sides by 0.5
Force = 450 / 0.5
Force = 900 N
D. How to determine the force exerted on the tackler?
Force exerted on the fullback = 900 NForce exerted on the tactkler = 900 NFrom Newton's 3rd law of motion which states that to every action, there is an equal an opposite reaction.
Since the force exerted on the fullback is 900 N. Thus, the force exerted on the tackler will be -900N
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calculate the synodic periods of venus and mars relative to earth. what are the implications of these periods for space missions to those planets?
21 and 7 years make up the Earth-Mars synodic period. The ecliptic plane is where the orbits of Earth, Mars, and the cycler trajectory are located.
What makes synodic periods significant?Synodic times are significant because they frequently correspond to direct observables, but physical rotation periods do not. This significance was crucial for determining the planets' orbital periods throughout the history of astronomy.
What exactly is a synodic period?Synodic period: The amount of time it takes for a body in the solar system, such as a planet, the Moon, or a man-made satellite to return to the same or nearly the same location with respect to the Sun as seen from the Earth.
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if a particle undergoes shm with amplitude 0.11 m , what is the total distance it travels in one period? express your answer using two significant figures. s
The total distance it travels in one period is 0.44m
Distance is a numerical or every so often qualitative size of how some distance aside items or factors are. In physics, the distance may check with the physical duration or an estimation primarily based on other criteria.
The space between the two factors in the physical space is the period of an immediate line among them, that's the shortest feasible course.
It reduces the entire or a part of the arena to a small sheet of paper. At the same time of making a map, cartographers have to pay attention to properly constitute the distance between two locations.
Calculation:
amplitude = 0.11m
total distance (s) = 4 (amp)
4 × 0.11 = 0.44m
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A small tropical fish is at the center of a water-filled spherical fishbowl 28.0 cm in diameter.a. Find the apparent position of the fish to an observer outside the bowl. The effect of the thin walls of the bowl may be ignored.b. Find the magnification of the fish to an observer outside the bowl.
To find the apparent position of the fish to an observer outside the bowl, we can use the lens equation:
1/p + 1/q = 1/f
where p is the distance from the object (the fish) to the center of the lens (in this case, the center of the fishbowl), q is the distance from the image to the center of the lens, and f is the focal length of the lens.
The focal length of a lens is given by the formula:
f = (n-1)R/2(n-1)
where R is the radius of the lens (in this case, the radius of the fishbowl) and n is the refractive index of the lens material (in this case, water).
Since the diameter of the fishbowl is 28.0 cm, the radius is 14.0 cm. The refractive index of water is approximately 1.33, so the focal length is approximately 8.5 cm.
To find the apparent position of the fish, we need to find p and q. If we let q be the distance from the image to the center of the lens, then the distance from the fish to the center of the lens is p = R - q.
Substituting these values into the lens equation, we get:
1/p + 1/q = 1/f
1/(R-q) + 1/q = 1/f
Solving this equation for q, we find that q = R/2 = 14.0 cm/2 = 7.0 cm.
This means that the apparent position of the fish is 7.0 cm from the center of the fishbowl.
To find the magnification of the fish to an observer outside the bowl, we can use the formula:
m = -q/p
Substituting the values we found above, we get:
m = -7.0 cm / (14.0 cm - 7.0 cm) = -1/2 = -0.5
This means that the fish is magnified by a factor of -0.5, or half its size.
the larger player on the left and the smaller player on the right push against each other. who fees the greater force?
Answer:
The players feel equal force against one another.
Explanation:
This is known from Newton's Third Law of Motion which states that for every action/force there is an equal and opposite reaction/force. Therefore, even if one player is larger, the force exerted on each player from the other is the same.
an eyepiece with a 2.00 cm focal length is placed 19.0 cm from the objective. where is the final image? (enter the image distance in cm.)
The final image is found to be 2.37cm in front of the eyepiece.
The focal length of the eyepiece is 2.00 cm and it is placed at a distance of 19.00 cm in front of the objective lens.
Now, we can use the lens formula to find the position of the image,
1/v - 1/u = 1/f
Where,
v is the position of the image,
u is the position of the objective in front of the eyepiece,
f is the focal length of the eyepiece.
Now, putting values,
1/v - 1/(-19) = 1/(-3)
The focal length and u are taken negative because of the sign standard sign convention of the lens.
1/v+1/19 = -1/3
Solving further,
v = -2.38 cm
So, the final image is 2.38 cm in front of the eyepiece.
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a red indicator light on a dashboard indicates a. a serious vehicle malfunction needs to be addressed immediately. b. a vehicle malfunction that needs to be addressed but is not urgent. c. a vehicle system that is operating. d. a minor vehicle malfunction.(1 point)
The correct answer is option a. A red indicator light on a dashboard typically indicates a serious vehicle malfunction that needs to be addressed immediately.
This type of light is usually used to indicate a problem that could cause damage to the vehicle or affect its safety if not addressed promptly. It is important to pay attention to a red indicator light and to have the vehicle checked by a mechanic as soon as possible to diagnose and fix the problem.
A red indicator light on a dashboard typically indicates a serious or critical issue with the vehicle that requires immediate attention. Ignoring this light could lead to further damage or safety concerns. It is important to have the vehicle checked by a mechanic as soon as possible.
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