Find the value of x. Round to the nearest tenth

The null hypothesis of this study is the statement that there is no significant difference between the playfulness of cats and dogs with their owners. In other words, the researcher assumes that both cats and dogs will play with their owners at the same rate. This is option c.

To test this hypothesis, the researcher would need to collect data on the playfulness of both cats and dogs with their owners. This could involve observing the animals during playtime or asking owners to self-report how often their pets play with them. The data would then be analyzed using statistical tests to determine if there is a significant difference in the average rates of playfulness between cats and dogs.

It is important to note that the null hypothesis does not necessarily reflect the researcher's personal beliefs or assumptions about the topic. Instead, it serves as a baseline assumption that can be tested through empirical research. If the data collected suggests that cats and dogs do not play with their owners at the same rate, then the null hypothesis would be rejected, and the researcher would need to explore alternative explanations for the observed differences.

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Null Hypothesis (H0): There is no positive correlation between the rankings of TV shows by husbands and wives in married couples.

Alternative Hypothesis (HA): There is a positive correlation between the rankings of TV shows by husbands and wives in married couples.

In simpler terms, the null hypothesis suggests that there is no relationship or association between the rankings of TV shows by husbands and wives.

The alternative hypothesis, on the other hand, proposes that there is a positive correlation between the rankings, indicating that husbands and wives tend to have similar preferences when it comes to TV shows.

The competing hypotheses in this study aim to determine whether there is evidence to support the idea that husbands and wives tend to like the same TV shows.

The null hypothesis assumes that there is no correlation between the rankings, meaning that the preferences of husbands and wives are independent of each other.

The alternative hypothesis, in contrast, suggests that there is a positive correlation, indicating a tendency for spouses to have similar preferences for TV shows.

To test these hypotheses, the researchers used the Spearman rank correlation coefficient (rs) to quantify the strength and direction of the relationship between the rankings.

The Spearman rank correlation is a statistical measure that assesses the monotonic relationship between two ranked variables, in this case, the rankings of TV shows by husbands and wives. A value of rs = 0.47 indicates a moderate positive correlation between the rankings.

To evaluate the hypotheses, statistical tests can be conducted. The significance level (alpha) is typically set in advance (e.g., 0.05) to determine the threshold for accepting or rejecting the null hypothesis.

If the p-value associated with the test is less than the chosen significance level, the null hypothesis is rejected in favor of the alternative hypothesis, suggesting that there is evidence of a positive correlation between the rankings of TV shows by husbands and wives.

Conversely, if the p-value is greater than the significance level, there is insufficient evidence to reject the null hypothesis, and the data does not provide support for a positive correlation.

It is important to note that the interpretation of the Spearman rank correlation coefficient and the conclusions drawn from the study should consider other factors, such as the sample size, sampling method, and the specific characteristics of the TV shows ranked by the couples.

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Answer:

Positive association is correct

Step-by-step explanation: The dots form are going up, forming a positive line. If they were to go down they would be negative. So in this case positive association is correct

Answer:

Option A

Step-by-step explanation:

To find all missing sides of a right triangle we use the sine, cosine or tangent ratio as below,

sinθ = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

cosθ = [tex]\frac{\text{Adjacent side}}{\text{Hypotenuse}}[/tex]

tanθ = [tex]\frac{\text{Opposite side}}{\text{Adjacent side}}[/tex]

Now we take an angle measuring 60°

sin(60°) = [tex]\frac{6}{y}[/tex]

[tex]\frac{\sqrt{3} }{2}=\frac{6}{y}[/tex]

y = 4√3

tan(60°) = [tex]\frac{6}{x}[/tex]

√3 = [tex]\frac{6}{x}[/tex]

x = 2√3

Therefore, Option A will be the correct option.

Answer:

It’s either A OR B

Step-by-step explanation:

The expressions that are not written correctly in scientific notation are: 48,200, 36.105, 8.7.10-1, and 0.78.10-3

Scientific notation is a way to express numbers in a concise form, using a number between 1 and 10 multiplied by a power of 10. Let's analyze the given expressions and identify the ones that are not written correctly in scientific notation:

48,200: This expression is not written in scientific notation. It should be expressed as 4.82 × 10^4 or 4.82e4.

0.00099: This expression is correctly written in scientific notation. It can be expressed as 9.9 × 10^-4 or 9.9e-4.

36.105: This expression is not written in scientific notation. It should be expressed as 3.6105 × 10^1 or 3.6105e1.

8.7.10-1: This expression is not written correctly in scientific notation. Scientific notation only allows one decimal point in the number. The correct representation would be 8.7 × 10^-1 or 8.7e-1.

0.78.10-3: Similar to the previous expression, this is not written correctly in scientific notation. The correct representation would be 7.8 × 10^-3 or 7.8e-3.

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To compute the next three approximations to the fixed point using Jacobi iteration and Seidel iteration, we will use the initial approximation (p0, q0) = (-0.3, -1.3) for the given nonlinear system.

(a) Jacobi Iteration:

In Jacobi iteration, we update the variables simultaneously using the previous values.

(b) Seidel Iteration:

In Seidel iteration, we update the variables using the most recently computed values.

To compute the next three approximations to the fixed point using Jacobi iteration and Seidel iteration, we will use the initial approximation (p0, q0) = (-0.3, -1.3) for the given nonlinear system.

(a) Jacobi Iteration:

In Jacobi iteration, we update the variables simultaneously using the previous values. The iteration formula for this system is as follows:

p(n+1) = (y(n) + 3x(n)^2 + 3x(n) - 73)/3

q(n+1) = (7y(n)^2 + 2y(n) - x(n) - 2)/92

Using the initial approximation (-0.3, -1.3), we can compute the next three approximations as follows:

Iteration 1:

p(1) = (1 + 3(-0.3)^2 + 3(-0.3) - 73)/3 ≈ -8.300

q(1) = (7(-1.3)^2 + 2(-1.3) - (-0.3) - 2)/92 ≈ -1.317

Iteration 2:

p(2) = (1 + 3(-8.300)^2 + 3(-8.300) - 73)/3 ≈ -209.034

q(2) = (7(-1.317)^2 + 2(-1.317) - (-8.300) - 2)/92 ≈ -2.924

Iteration 3:

p(3) = (1 + 3(-209.034)^2 + 3(-209.034) - 73)/3 ≈ -14314.328

q(3) = (7(-2.924)^2 + 2(-2.924) - (-209.034) - 2)/92 ≈ -6.344

(b) Seidel Iteration:

In Seidel iteration, we update the variables using the most recently computed values. The iteration formula for this system is as follows:

p(n+1) = (y(n) + 3x(n)^2 + 3x(n) - 73)/3

q(n+1) = (7y(n+1)^2 + 2y(n+1) - x(n) - 2)/92

Using the initial approximation (-0.3, -1.3), we can compute the next three approximations as follows:

Iteration 1:

p(1) = (1 + 3(-0.3)^2 + 3(-0.3) - 73)/3 ≈ -8.300

q(1) = (7(-1.3)^2 + 2(-1.3) - (-0.3) - 2)/92 ≈ -1.315

Iteration 2:

p(2) = (1 + 3(-1.315)^2 + 3(-1.315) - 73)/3 ≈ -8.264

q(2) = (7(-8.264)^2 + 2(-8.264) - (-1.315) - 2)/92 ≈ -3.471

Iteration 3:

p(3) = (1 + 3(-3.471)^2 + 3(-3.471) - 73)/3 ≈ -1.252

q(3) = (7(-1.252)^2 + 2(-1.252) - (-3.471) - 2)/92 ≈ -1.100

These are the next three approximations to the fixed point using Jacobi iteration and Seidel iteration with the given initial approximation.

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Answer:

B: 2(5−6)

Step-by-step explanation:

Answer:

Thx u

Step-by-step explanation:

that's not good oof

:3

:)

:0

:>

Answer:

Hi! The answer to your question is x = 27

Step-by-step explanation:

☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆☆*: .｡..｡.:*☆

☁Brainliest is greatly appreciated!☁

Hope this helps!!

- Brooklynn Deka

Answer:

x=27

Step-by-step explanation:

3x+9=90

subtract 9 from both sides

3x=90-9

3x=81

divide by 3

x= 27

checking

3x27 +9= 90

81+9=90

I hope this makes sense

square

its the middle bit that looks darker than the rest.

Answer: 240 in 2

Step-by-step explanation:

just did it

Answer:

18ft

Step-by-step explanation:

15+3=18

33. The box plots have been used successfully to describe the center and spread of a data set, the extent and nature of any departure from symmetry and the identification of "outliers".

Hence, the correct option is (d) All of the choices.

34. We can say with a 95% degree of confidence that the mean compressive strength between 3235 and 3265, the correct option is (c) 95%.

Box plots are an excellent way of representing data, which has a statistical measure like variance, median, mean, mode, etc.

It presents the central tendency, variability, skewness, and even show the outliers.

A box plot, also called a box and whisker plot, shows the five-number summary of a set of data (minimum value, lower quartile, median, upper quartile, maximum value).

34. The given information is

Sample size, n = 10

Mean = 3250

Variance = 1000(psi)²

Standard Deviation = √1000(psi)²

= 31.62 psi

The degree of freedom is calculated as follows:

d. f . = n - 1

= 10 - 1

= 9

At 95% confidence level, the area in each tail is given by

α/2 = 0.05/2

= 0.025

Using the t-table, we can find that the t-value for 9 degrees of freedom and 0.025 area in each tail is 2.262.

Therefore, the critical values of t are

t₁ = -2.262 and

t₂ = 2.262.

We can calculate the confidence interval as follows:

Confidence Interval, CI = x± (t × σ/√n)

Plugging in the values, we get

CI = 3250 ± (2.262 × 31.62/√10)

= (3235, 3265)

Hence, we can say with a 95% degree of confidence that the mean compressive strength between 3235 and 3265.

The correct option is (c) 95%.

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a) The horizontal distance between the fighter jet and the point of impact of the missile is 100 units.

b) The graph of the equation is a downward-opening parabola passing through the points (50, 22500), (100, 0), and (0, 0).

c) The instantaneous rate of change when the missile has half of the horizontal journey left is 0, indicating no change in height with respect to the horizontal distance at that point.

To find the horizontal distance between the fighter jet and the point of impact of the missile, we need to determine the x-coordinate when the missile hits the ground. This can be done by finding the x-intercepts of the equation -x² + 100x + 20000, which represents the path of the missile.

To find the x-intercepts, we set the equation equal to zero:

-x² + 100x + 20000 = 0

Using the quadratic formula, where a = -1, b = 100, and c = 20000, we can calculate the x-coordinate:

x = (-b ± √(b² - 4ac)) / (2a)

Plugging in the values, we get:

x = (-100 ± √(100² - 4(-1)(20000))) / (2(-1))

Simplifying further:

x = (-100 ± √(10000 + 80000)) / (-2)

x = (-100 ± √90000) / (-2)

x = (-100 ± 300) / (-2)

x = (200 or -100) / 2

Since negative values are not meaningful in this context, we take the positive value, which is x = 100. Therefore, the horizontal distance between the fighter jet and the point of impact of the missile is 100 units.

To graph the equation, we plot the points on a coordinate system. The equation -x² + 100x + 20000 represents a downward-opening parabola. The highest point of the parabola is at (50, 22500) because the x-coordinate represents the midpoint of the parabolic path, and the maximum height is reached when x = 50. The two ends of the parabolic path are located at the x-intercepts we calculated earlier, which are (100, 0) and (0, 0).

The graph of the equation would show a downward-opening parabola passing through the points (50, 22500), (100, 0), and (0, 0).

The instantaneous rate of change represents the derivative of the equation with respect to x at a given point. To find the instantaneous rate of change when the missile has half of the horizontal journey left, we need to find the derivative of the equation and evaluate it at that point.

Taking the derivative of -x² + 100x + 20000 with respect to x, we get -2x + 100. Evaluating this derivative at x = 50 (when the missile has half of the horizontal journey left), we have:

-2(50) + 100 = -100 + 100 = 0

Therefore, the instantaneous rate of change when the missile has half of the horizontal journey left is 0. This indicates that at that point, the height of the missile is not changing with respect to the horizontal distance.

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(a) To show that v(x, y) is an ideal flow, we need to verify that it satisfies the conditions of being both irrotational and incompressible.

For irrotationality, we compute the curl of v(x, y):

curl(v) = ∂v_y/∂x - ∂v_x/∂y = 0 - 0 = 0

Since the curl is zero, v(x, y) is irrotational.

For incompressibility, we compute the divergence of v(x, y):

div(v) = ∂v_x/∂x + ∂v_y/∂y = 2 - 0 = 2

Since the divergence is not zero, v(x, y) is not incompressible. Therefore, v(x, y) is an irrotational flow but not an ideal flow.

(b) For the complex potential Φ for v(x, y), we can integrate the components of v(x, y) with respect to z = x + iy.

Φ = ∫ (2) dz = 2z = 2(x + iy) = 2x + 2iy

The complex potential Φ is given by Φ = 2x + 2iy.

(c) we need to solve for the points where both components of v are zero simultaneously:

v_x = 2x = 0

v_y = 0

From the first equation, x = 0. Substituting x = 0 into the second equation, we get v_y = 0, which holds for all values of y. Therefore, the stagnation point(s) of v(x, y) is at x = 0, y = y.

(d) For the streamlines (trajectories) of v, we can solve the differential equation given by dw/dz = Su_x - iu_y, where w is the complex potential Φ.

dw/dz = ∂Φ/∂x - i∂Φ/∂y = 2 - 2i

Integrating the above expression with respect to z, we get:

w = 2z - 2iz = 2(x + iy) - 2i(x + iy) = 2x + 2iy - 2ix - 2y = 2(x - y) + 2i(y - x)

The streamlines are given by the equation w = 2(x - y) + 2i(y - x), which shows that v(x, y) is a tangent vector to the streamline at z = x + iy (excluding the stagnation point(s)).

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Step-by-step explanation:

-√81=-√(9)²=-9

A number inside a Square root cannot ne negative. So, the second one is not a real no.

Answer:

[tex] - \sqrt{81} = - 9 \\ \sqrt{ - 25 = - 5} [/tex]

Step-by-step explanation:

-81/9 9+9+9+9+9+9+9+9+9(81)

-9

-25/5 (5+5+5+5+5(25)

-5

Answer:

n=1/8N^2

Step-by-step explanation:

n^2-8n=0

-8n=-N^2

n=1/8N^2

Answer:

It would be in thE 20.75

Step-by-step explanation:

Just keep adding change by 9 6 times

Given that a function is defined by `f(x) = x² + 2`, and the region R is enclosed by `y = f(x)`, the `y-axis` line `y = 4`. We need to find the exact volume generated when the region R is rotated through `27 radians` about the `y-axis`.

Explanation: The formula for finding the volume generated by rotating the region R about the `y-axis` is given by: `V = ∫ [from a to b] 2πxf(x) dx`. Here, the value of `a` is `0` because it's given that `f(x) = x² + 2`, and `f(x)` is greater than or equal to `0`. Also, the line `y = 4` intersects `f(x)` at `x = 2`. So, the value of `b` is `2`.

Therefore, the volume generated is given by: V = ∫ [from 0 to 2] 2πx (x² + 2) dx`=`2π ∫ [from 0 to 2] (x³ + 2x) dx`=`2π [(x⁴/4) + x²] {from 0 to 2}`=`2π [(2⁴/4) + 2²] - 0`=`2π [4 + 4]`=`16π` cubic units.

So, the exact volume generated when the region R is rotated through `27 radians` about the `y-axis` is `16π` cubic units.

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No, the set of all real-valued functions f(x) such that f(2) = 0 is not a subspace of the vector space consisting of all real-valued functions. The solution set of a nonhomogeneous linear system Ax = b, with b ≠ 0, is also not a subspace of R.

To determine if a set is a subspace, it must satisfy three conditions: closure under addition, closure under scalar multiplication, and contain the zero vector. In the case of the set of real-valued functions f(x) such that f(2) = 0, it fails to satisfy closure under scalar multiplication. If we take a scalar k and multiply it with a function f(x) in the set, the resulting function kf(x) will not necessarily have f(2) = 0. Therefore, the set does not form a subspace.

For the solution set of a nonhomogeneous linear system Ax = b, where b ≠ 0, it also fails to be a subspace of R. A subspace must contain the zero vector, which corresponds to the homogeneous solution of the linear system. However, in a nonhomogeneous system, the zero vector is not a valid solution since Ax ≠ b. Therefore, the set of solutions does not contain the zero vector and cannot be considered a subspace.

In conclusion, neither the set of real-valued functions with f(2) = 0 nor the solution set of a nonhomogeneous linear system with b ≠ 0 form subspaces in their respective vector spaces.

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Answer:

What is it, you need help with?

Step-by-step explanation:

:)

a) The derivative of g(x) at x=2 is g'(2) = 2.

b) The second derivative of k(x) at x=1 is k"(1) = -30.

c) The derivative of n(x) at x=0 is n'(0) = -18.

a) To find g'(x), we need to take the derivative of g(x) with respect to x. Let's differentiate each term separately:

g(x) = 3x³ - 8x² - 2x + 35

The derivative of 3x³ is obtained by applying the power rule, which states that if we have a term of the form [tex]ax^n[/tex], the derivative is given by [tex]nax^{(n-1)[/tex]. In this case, the derivative of 3x³ is 3 * 3x², which simplifies to 9x².

The derivative of -8x² is obtained in a similar manner, resulting in -16x.

The derivative of -2x is -2.

Since 35 is a constant term, its derivative is zero.

Now, let's combine these derivatives to find g'(x):

g'(x) = 9x² - 16x - 2

To find g'(2), we substitute x = 2 into the derivative:

g'(2) = 9(2)² - 16(2) - 2

= 9(4) - 32 - 2

= 36 - 32 - 2

= 2

Therefore, g'(2) = 2.

b) To find k"(x), we need to take the second derivative of k(x) with respect to x. Let's differentiate each term:

k(x) = 1 / [tex]x^5[/tex]

The derivative of 1/[tex]x^5[/tex] can be found using the power rule and the chain rule. The power rule states that the derivative of [tex]x^n[/tex] is n[tex]x^{(n-1)[/tex], and the chain rule applies when we have a function within another function. In this case, the derivative of 1/[tex]x^5[/tex] is -5/[tex]x^6[/tex].

Taking the derivative of -5/[tex]x^6[/tex], we apply the power rule again, resulting in 30/[tex]x^7[/tex].

Now, let's find k"(x) by differentiating -5/[tex]x^6[/tex] again:

k"(x) = -30/[tex]x^7[/tex]

To find k"(1), we substitute x = 1 into the second derivative:

k"(1) = -30/([tex]1^7[/tex])

= -30/1

= -30

Therefore, k"(1) = -30.

c) To find n'(x), we need to take the derivative of n(x) with respect to x. We can apply the product rule to differentiate the two factors of n(x):

n(x) = (-4x + 2)(3x² - 5x + 2)

Using the product rule, the derivative of n(x) is given by:

n'(x) = (-4x + 2)(d/dx)(3x² - 5x + 2) + (3x² - 5x + 2)(d/dx)(-4x + 2)

To differentiate each term, we use the power rule:

(d/dx)(3x² - 5x + 2) = 6x - 5

(d/dx)(-4x + 2) = -4

Substituting these derivatives back into n'(x), we get:

n'(x) = (-4x + 2)(6x - 5) + (3x² - 5x + 2)(-4)

Now, let's find n'(0) by substituting x = 0 into the derivative:

n'(0) = (-4(0) + 2)(6(0) - 5) + (3(0)² - 5(0) + 2)(-4)

= (2)(0 - 5) + (0 - 0 + 2)(-4)

= (2)(-5) + (2)(-4)

= -10 - 8

= -18

Therefore, n'(0) = -18.

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The solution of the initial value problem is:[tex]Y(t) = e^(3t) + e^(-t) - 3tet[/tex]

To solve the initial value problem Y" – 2y – 3y = 15tet, y(0) = 2, y'(0) = 0, we can use the method of undetermined coefficients.

First, we find the general solution of the homogeneous equation Y" – 2y – 3y = 0.

The characteristic equation is:

[tex]r^2 - 2r - 3 = 0[/tex]

Factoring the quadratic equation, we have:

(r - 3)(r + 1) = 0

This gives us two distinct roots: r = 3 and r = -1.

Therefore, the general solution of the homogeneous equation is:

[tex]Yh(t) = C1e^(3t) + C2e^(-t)[/tex]

To find a particular solution Yp(t) for the non-homogeneous equation, we assume a solution of the form Yp(t) = Atet, where A is a constant to be determined.

Taking the first and second derivatives of Yp(t), we have:

[tex]Yp'(t) = Ate^t + Aet[/tex]

[tex]Yp"(t) = Ate^t + 2Aet[/tex]

Substituting these derivatives into the non-homogeneous equation, we get:

[tex](Ate^t + 2Aet) - 2(Atet) - 3(Atet) = 15tet[/tex]

Simplifying the equation, we have:

[tex]Ate^t + 2Aet - 2Ate^t - 3Ate^t = 15tet[/tex]

Combining like terms, we get:

[tex](-4A + 2A - 3A)te^t = 15tet[/tex]

Simplifying further, we have:

[tex]-5Ate^t = 15tet[/tex]

Cancelling out the common terms, we get:

-5A = 15

Solving for A, we find:

A = -3

Now, we have the particular solution Yp(t) = -3tet.

The general solution of the non-homogeneous equation is the sum of the general solution of the homogeneous equation and the particular solution:

Y(t) = Yh(t) + Yp(t)

[tex]Y(t) = C1e^(3t) + C2e^(-t) - 3tet[/tex]

Using the initial conditions y(0) = 2 and y'(0) = 0, we can solve for the values of C1 and C2.

When t = 0:

[tex]Y(0) = C1e^(3(0)) + C2e^(-0) - 3(0)e^(0)[/tex]

2 = C1 + C2

Taking the derivative of Y(t) with respect to t and evaluating it at t = 0:

[tex]Y'(t) = 3C1e^(3t) - C2e^(-t) - 3te^(3t)Y'(0) = 3C1e^(3(0)) - C2e^(-0) - 3(0)e^(3(0))[/tex]

0 = 3C1 - C2

Solving these equations simultaneously, we find C1 = 1 and C2 = 1.

Therefore, the solution of the initial value problem is:

[tex]Y(t) = e^(3t) + e^(-t) - 3tet[/tex]

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Answer:

Part A

The two figures, ΔABC and ΔPQR are congruent by the SSS rule of congruency

Part B

The rigid motion that maps ΔABC to ΔPQR are a 180° clockwise rotation about the origin, followed by a horizontal shift of 1 unit to the right

Step-by-step explanation:

Part A

The given coordinates of the vertices of triangle ABC are;

A(-8, -2), B(-3, -6), C(-2, -2)

The length of side AB = √((-6 - (-2))² + (-3 - (-8))²) = √41

The length of side AC = √((-2 - (-2))² + (-2 - (-8))²) = 6

The length of side BC = √((-6 - (-2))² + (-3 - (-2))²) = √17

The given coordinates of the vertices of triangle PQR are;

P(9, 2), Q(4, 6), R(3, 2)

The length of side PQ = √((6 - 2)² + (4 - 9)²) = √41

The length of side PR = √((2 - 2)² + (3 - 9)²) = 6

The length of side RQ = √((6 - 2)² + (4 - 3)²) = √17

Given that the length of the three sides of triangle ABC are equal to the lengths of the three sides of triangle PQR, we have;

ΔABC ≅ ΔPQR by Side Side Side rule of congruency

Part B

Whereby AB and PQ, and BC and RQ are pair of corresponding sides, the rigid motion that maps ΔABC to ΔPQR are;

1) A 180° clockwise (or counterclockwise) rotation about the origin followed by

2) A shift of 1 unit to the right.