Find the Pythagorean Triple (a,b,c) using the terms (x²-y², 2xy, x²+y²) for x > y > 0 when x = 8 and y = 5.

Answer:

(39,80,89)

Step-by-step explanation:

A Pythagorean triple is one that consists of three positive integers a, b and c such that;

a² + b² = c²

In this case;

The terms are: (x²-y², 2xy, x²+y²) where x > y > 0  where x=8 and y=5

The terms are : x²-y² = 8²-5² = 64-25 = 39

                       : 2xy = 2*8*5 =16*5 = 80

                       : x²+y²= 8²+5²=64+25 = 89

Applying the Pythagorean triple;

a² + b² = c²

39² + 80² = 89²

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