The moment of inertia of the point is from to be 0.0045 Kg-m².
The moment of inertia of any mass that is situated away from the axis of the rotation is given by other relation,
I = MR²
Where,
M is the mass of the body and R is the distance of the body from the axis rotation.
It is given to as that the mass of the body is 0.05 grams and it is situated perpendicularly at a distance of 3 m from the axis of rotation.
Now, putting all the values to find the value of the moment of inertia,
I = 0.0005×9
I = 0.0045 Kg-m²
So, the moment of inertia the point is found to be 0.0045 Kg-m².
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suppose earth orbited the sun in 6 months rather than 1 year but had the same rotational period how much longer would a solar day be than sidereal day
A solar day is 0.50001917 times longer than a sidereal day if the earth's orbital period is shortened to six months.
Earth, what is it?Earth is just a rocky, earthy planet and is home to us. There are mountains, valleys, canyons, plains, and much more on its stable and dynamic surface. Being an ocean planet, Earth is unique. The Earth's surface is 70% covered by water.
Briefing:1 Sidereal year = 365.256 days
1 Solar year (1 tropical year) = 365.242 days
The length of time inside a sidereal year is equal to 365.256/2 days, or 182.628 days, if the earth's orbital period is six months.
1 Solar day = 182.256/365.242 sidereal days
1 Solar day = 0.50001917 sidereal day
A solar day is 0.50001917 times longer than a sidereal day if the earth's orbital period is shortened to six months.
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The complete question is-
Solar and Sidereal Days. Suppose Earth orbited the Sun in 6 months rather than 1 year but had the same rotation period. How much longer would a solar day be than a sidereal day? Explain.
if the pendulum is modeled as a simple pendulum, how long must it be for the ticks to occur once a second?
A pendulum requiring exactly one second for each swing in either direction or two seconds for a complete vibration and having a length between centers of suspension and oscillation of 99.353 centimetres at sea level in latitude 45 degrees.
the orion nebula, m-42, is a hot, thin cloud of glowing gas, so its spectrum is
The orion nebula, m-42, is a hot, thin cloud of glowing gas, so its spectrum is (d) a few bright lines against a dark background.
The Orion Nebula is it a cloud of gas?
One of the best-known celestial features is the Orion Nebula, often known as M42. This cloud of gas and dust, the middle "star" in Orion's dagger hanging below his belt, is so dazzling that it can be seen with the unaided eye even from a distance of more than 13 quadrillion kilometers (8 thousand trillion miles).
Why is Orion so crucial?
One of the starry sky's most intriguing and significant constellations is Orion. One reason why astronomers are drawn to it is that it contains one of the Milky Way Galaxy's closest and most active star nurseries (the Orion Nebula).
The Orion Nebula's gas glows for what reason?
The Trapezium and Nebula are located in front of a cold, dusty "giant molecular cloud" that contains regions of active star formation, around 1500 light years away. A blister on the molecular cloud's front edge gets electrified by the stars of the Trapezium, making it glow.
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the predominant wavelength emitted by an ultraviolet lamp is 370 nm a) what is a frequency of this light? b) what is the energy (in joules) of a single photon of this light? c) if the total power emitted at this wavelength is 45.0 w, how many photons are emitted per second? socratic.org
8.1 * [tex]10^{5}[/tex] Hz is a frequency of this light when predominant wavelength emitted by an ultraviolet lamp is 370 nm .
fλ = c
where f- Frequency
λ - Wavelength
c- speed of light
f= c/ λ
= 3 * [tex]10^{8}[/tex]/ 370
= 8.1 * [tex]10^{5}[/tex] Hz
A waveform signal that is carried in space or down a wire has a wavelength, which is the separation between two identical places (adjacent crests) in the consecutive cycles. This length is typically defined in wireless systems in meters (m), centimeters (cm), or millimeters (mm).
The wavelength, which will also apply to troughs, is the separation between two wave crests. The number of vibrations that span a particular area in a second is known as the frequency, which is measured in cycles per second (Hz) .
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is the electric field strength in the figure(figure 1) increasing, decreasing, or not changing?
Answer:
Decreasing
Explanation:
The electric field strength is decreasing in figure 1.
for a particular process q = –17 kj and w = 21 kj. which of the following statements is false?
The statement 'the system does work on surroundings' is false because the work done is a positive quantity.
This question can be answered using the first law of thermodynamics.
The First Law of Thermodynamics is a thermodynamic adaptation of the law of conservation of energy. "The overall energy in a system remains constant, even when it may be transformed from one form to another," says one basic expression. Another typical phrase is "energy cannot be generated or destroyed" (in a "closed system"). While there are other nuances and consequences that may be better conveyed in more sophisticated formulations, this is the fundamental premise of the First Law.
According to first law,
U= Q+W
U: internal energy of the system
Q: amount of heat
W: work done
Q= -17 kJ, W= 21 kJ
If Q is positive it means heat flows into the system. If Q is negative it means heat flows out of the system.
In the given question heat s negative which means heat flows into the system.
Work done is positive hence work is done on the system.
U= Q+W
U= -17+21= 4kJ
This is an exothermic process since Q is negative.
Complete question:
For a particular process q = –17 kj and w = 21 kj. Which of the following statements is false?
a) heat flows from the system to the surrounding
b) the system does works on the surrounding
c) U= +4kJ
d) the process is exothermic
e) none of the above is false
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FILL IN THE BLANK. when the cyclin‒cdk complex phosphorylates rb, the cell cycle progresses from _______ to _______.
The cell cycle advances from G1 phase to S phase when the cyclin–CDK complex phosphorylates RB.
The management of eukaryotic cell proliferation depends on the precise transition from G1 phase to S phase of the cell cycle, and its dysregulation encourages oncogenesis. Growth-dependent cyclin-dependent kinase (CDK) activity encourages DNA replication and starts the transition from G1 to S phase during G1 phase.
By causing alterations in transcription across the entire genome, CDK activation sets off a positive feedback loop that drives up CDK activity even more, committing the cell to division. G1-S transcripts produce proteins that control subsequent cell cycle processes. The intricate molecular mechanisms that regulate the temporal order of transcriptional activation and inactivation, identify distinctive functional subgroups of genes, and link cell cycle-dependent transcription are just now starting to come into focus as a result of recent research.
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an electrical circuit refers to the combination of various electrical components that are connected together. group of answer choices true false
An electrical circuit refers to the combination of various electrical components that are connected together. - True
An electrical circuit refers to the combination of various electrical components that are connected together in a closed loop, thereby allowing electrons to flow through the circuit. Electrical circuits are essential for the operation of most electronic devices and are made up of a variety of components such as resistors, capacitors, inductors, and transistors.
These components are connected together using conductive materials. The conductive material is generally the copper wire which is used to create the circuit. The flow of electrons through the circuit can be controlled and manipulated using various techniques, such as switching and modulation, to perform a wide range of functions.
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Which of the following pairs are similar?(A) work and power(B) momentum and energy(C) force and power(D) work and energy
The pair of work and energy is similar.
Among all the given pairs the pair of work and energy are similar because they have similar units.
According to the work energy theorem, the total work done on a body by all the forces combined is equal to the change in kinetic energy of the body.
W = ∆K
According to the principle of homogeneity,
If two quantities are equal then they must have similar units.
In the case of energy and work both of them has the unit Joule. Because there equal as per the work energy theorem.
Work and power, Momentum and energy, force and power all have different units so they are not similar pairs.
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determine the location of the resultant force of the water acting on the vertical end wall of the pool where the depth is 2.5m
The location of the resultant force of the water on the vertical end of the pool is 1.67 m from the top.
Given that, length of the swimming pool is 16 m
Width of the swimming pool is 6 m
Depth of the pool (h) is 2.5 m
Area of the pool (A) = 6* 2.5 = 15 m²
Moment of inertia (I) = bh³/12 = 6* 2.5³/12 = 7.82 m⁴
x = h/2 = 1.25 m
The expression for location of force is
H = x + I/(A*x) = 1.25 + 7.82/(15* 1.25) = 1.25 + 7.82/18.75 = 1.67 m
Thus, the location of the resultant force of the water on the vertical end of the pool is 1.67 m from the top.
The question is incomplete. A swimming pool is 16 m long and 6 m wide.
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3. An object rotates in a circular track with a uniform speed 10 ms¹ and it has a periodic time 4 s. what is the magnitude of the mean acceleration of the object when it moves from A to B where AB is a diameter? 1). 0 2).5 ms² 3). 15 ms 4). 20 ms-² 5). 10 ms-²
The magnitude of the mean acceleration of the object is 15 m/s^2 when it moves from A to B where AB is a diameter.
What is centripetal acceleration?Centripetal acceleration is a characteristic of an object's motion along a circular path. Centripetal acceleration applies to any item travelling in a circle with an acceleration vector pointing in the direction of the circle's center.
Given that: uniform speed of the object: v = 10 m/s.
Periodic time: T = 4 second.
Hence, the magnitude of the centripetal acceleration of the object = 2πv/T
= (2π × 10)/4
= 15 m/s^2.
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Answer: 5. 10 ms-²
Explanation:
Answer: 5. 10 ms-²
Explanation: The magnitude of the mean acceleration of the object when it moves from A to B is equal to the angular acceleration multiplied by the radius of the circular track.
Therefore, the angular acceleration = (2π/T) = (2π/4) = (π/2) rad/s²
The radius of the circular track = 10 m
Therefore, the magnitude of the mean acceleration of the object when it moves from A to B = (π/2) x 10 = 10 ms-²
Sherwin and Lia are playing bumper car at town fair. Sherwin and hi cart have a ma of 150 kg. Lia and her cart have a ma of 95 kg. Sherwin i topped when Lia, moving at a velocity of 12 m/, collide with him. If Lia come to a complete top after the colliion, then what i Sherwin' reulting velocity after the colliion?
Sherwin's resulting velocity after the collision is 18.94m/sec. if his initial velocity is 12m/sec and mass of 150kg.
It is given that Sherwin has initial velocity and Lia is going to start the bumper car. It means that initial velocity of Sherwin is 12m/sec and initial velocity of Lia is 0m/sec. Since, the collision is elastic, it means that energy will not lost during the collision and momentum will remain conserved.
So, applying the law of conservation of momentum which is
Initial momentum =Final momentum
=>Initial momentum of Sherwin is=mass × velocity
=>Initial momentum of Sherwin=150 × 12m/sec
Now, initial momentum of Lia is =mass × velocity
=>Initial momentum of Lia is =95×0=0m/sec
Now, final momentum of Sherwin=0m/sec since collision is elastic
Also, final momentum of Lia is =95×v
According to the formula, we get
=>150 × 12 +0 =0 + 95×v
=>95×v=150 × 12
=>v=(150 × 12)/95
=>v=1800/95
=>v=18.94m/sec
Hence, Sherwin velocity is 18.94m/sec.
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I need help this test is timed
A solid sphere has a radius of 5cm. It is hung from a spring with spring constant 80 N/m and stretches the spring 8cm from its equilibrium position. Find the density of the sphere
The density of the sphere given it stretches the spring 8 cm from it's equilibrium position is 1.25 g/cm³
How do I determine the density of the sphere?First, we shall obtain the mass of the sphere. Details below:
Spring constant (K) = 80 NExtension (e) = 8 cm = 8 / 100 = 0.08 mAcceleration due to gravity (g) = 9.8 m/s²Mass (m) = ?F = mg
F = Ke
Thus,
mg = Ke
Divide both sides by g
m = Ke / g
m = (80 × 0.08) / 9.8
m = 0.653 Kg
Multiply by 1000 to express in grams
m = 0.653 × 1000
m = 653 g
Finall, we shall determine the density of the sphere. Details below:
Radius (r) = 5 cm Pi (π) = 3.14Volume of sphere = 4/3πr³ = (4/3) × 3.14 × 5³ = 523 cm³Mass of sphere = 653 gDensity of sphere = ?Density = mass / volume
Density of sphere = 653 / 523
Density of sphere = 1.25 g/cm³
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a billiard ball is decelerating at a constant rate. its initial velocity is 8m/s. after 1.5 seconds it is travelling at 6m/s. find its acceleration.
1.33m/s^2 is the acceleration. when a billiard ball is decelerating at a constant rate. its initial velocity is 8m/s. after 1.5 seconds it is travelling at 6m/s.
What are two illustrations of acceleration?The rate at which a moving object's velocity changes is known as acceleration. It gauges the speed of velocity changes. Examples of acceleration include riding a carousel and traveling at a constant speed around a bend on a road.
The equation a = v/t denotes acceleration (a), which is the change in velocity (v) over the change in time (t).
a = (v_f - v_i) / Δt
a= 6m/s - 8m/s / 1.5 seconds
a=-1.33m/s^2
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Observations of young stars (as well as theory) tell us that when the Sun was young the solar wind
A) was weaker than it is today.
B) was stronger than it is today.
C) was about the same strength as it is today.
D) was nonexistent.
E) blew outward only along the Sun's poles.
Observations of young stars tell us that when the Sun was young the solar wind was stronger than it is today.
The proto-planetary disc's gas and dust would have been cleaned away by the young Sun's solar wind after three to ten million years, pushing it into interstellar space and putting an end to the planets' formation.
The solar nebular disc model, often known as the solar nebular model, is the most extensively used current variation of the nebular hypothesis.
The planets' almost circular and coplanar orbits, as well as their motion in the same plane as the Sun's spin, were all explained by this theory, along with a number of other features of the Solar System.
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Consider two children sitting on a merry-go-round, with one closer to the outer edge and one closer to the center. Which child has a greater angular speed?
PLEASE HELP!!
If the heat that is released is 450 J what is the heat absorbed if the efficiency of the engine is 55%?
-7.18 J
1000 J
-1000 J
8.18 J
If possible can you also explain how you got the answer?
The heat absorbed if the efficiency of the engine is 55% is determined as 1,000 J.
What is the heat absorbed by the system?The heat absorbed by the system is the positive heat gain by the system or the useful energy of the system.
From the fist law of thermodynamics, when heat is added to a system or absorbed by the system, the system gains heat.
Mathematically, the first law of thermodynamics is given as;
ΔU = q + w
where;
ΔU is the change in internal energy of the systemq is the heat added to the systemw is the work done on the systemThe heat absorbed by the system is calculated as follows;
q = ΔH / ( 1 - e )
where;
e is the efficiency of the system = 55 % = 0.55q = 450 J / ( 1 - 0.55 )
q = 450 J / 0.45
q = 1,000 J
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the fraction of light that is transmitted through a 100 mm panel of pmma is 0.97. neglecting reflection at both surfaces, what is the absorption coefficient b of pmma?
The absorption coefficient ,[tex]\beta[/tex] of PMMA is [tex]0.3\ m^{-1}[/tex] when 0.97 fraction of light is transmitted through 10 mm panel of PMMA.
The absorption coefficient determines how far light of a specific wavelength can penetrate before being absorbed. Light is only poorly absorbed in a material with a low absorption coefficient, and if the material is thin enough, it will appear transparent to that wavelength.
Given,
The fraction of light transmitted through PMMA panel = 0.97
Thickness of PMMA panel = 100 mm = 0.1 m
The absorption of coefficient, [tex]\beta[/tex]can be determined by the relation,
[tex]I=I_oe^{-\beta x}\\\\\frac{I}{I_o}=e^{-\beta x}\\\\[/tex]
applying natural log on both sides
[tex]ln(\frac{I}{I_o})=ln(e^{-\beta x})\\\\ln(\frac{I}{I_o})=-\beta x\\\\\beta = -\frac{1}{x}ln(\frac{I}{I_o})[/tex]
Here, x is the thickness of the PMMA panel; [tex]\frac{I}{I_o}[/tex] is the fraction of light transmitted; I is the initial intensity of light before transmitting through panel and [tex]I_o[/tex] is the final intensity of light after passing through the panel.
[tex]\beta = -\frac{1}{0.1}ln(0.97)\\\\\beta = -10*(-0.03)=0.3 m^{-1}[/tex]
Thus, the absorption coefficient is [tex]0.3\ m^{-1}[/tex]
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Find the standard matrices A and A' forT = T2 ∘ T1 and T' = T1 ∘ T2.T1: R2 → R2, T1(x, y) = (x − 3y, 3x + 5y)T2: R2 → R2, T2(x, y) = (y, 0)A=A'=
Upon calculation A=[tex]\left[\begin{array}{ccc}3&5\\0&0\\\end{array}\right][/tex] and A'= [tex]\left[\begin{array}{ccc}0&1\\0&3\\\end{array}\right][/tex]
This question can be solved using the concept of matrices.
A matrix is a rectangular array of integers divided into rows and columns. In mathematics, a matrix is an array of integers that is arranged in a rectangular pattern and split into rows and columns. They are often expressed by enclosing all of the numbers included between square braces.
According to the question given here
T₁(x,y)= (x-3y,3x+5y)
and
T₂(x,y)= (y,0)
Now it is clearly mentioned that T= T₁*T₂
T(x,y)= T₂[T, (x,y)]
T(x,y)= T₂(x-3y,3x+5y)
T(x,y)= (3x+5y,0)
T(1,0)= (3*1+5*0,0)= (3,0)
T(0,1)= (3*0+5*1,0)= (5,0)
which means A=[tex]\left[\begin{array}{ccc}3&5\\0&0\\\end{array}\right][/tex]
Now to find A'
T'= T₁*T₂
T'(x,y)= T₁[T₂(x,y)]
T'(x,y)= T₁(y,0)
T'(x,y)= (y-3*0,3y+5*0)
T'(x,y)= (y,3y)
T'(1,0)= (0,0)
T'(0,1)= (1,3)
which gives us A'= [tex]\left[\begin{array}{ccc}0&1\\0&3\\\end{array}\right][/tex]
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which of these correctly compares the masses of different objects in the universe?
A moon has more mass than the planet it circles and less mass than a star.
Do planets have a greater mass than stars?
By this definition, "stars" must be larger than planets in terms of mass. The size of a white dwarf would be comparable to that of a moon or small planet, but its mass would be approximately 200–1300 times that of Jupiter. Even more extreme are neutron stars, which are about the size of an asteroid but have a mass of several thousand Jupiters.
Why is the weight of the same object different on different planets Class 7?
The weight of an object is determined by its mass and the gravitational force that it experiences. The separation between two objects affects how strong gravity is. Because of this, an object weights differently on many planets.
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Make a table in which you list all possible outcomes of rolling two dice. Call the dice A and B.Part AWhat is the probability of rolling a 7.00? You can give the probabilities as fractions, such as 3/36.Part BWhat is the probability of any double?Part CWhat is the probability of rolling a 7.00 or an 8? You can give the probabilities as fractions, such as 3/36.
When two dice are rolled there are 36 possible outcomes. The sample for two diced named A and B can be written as follows:
S= {(1,1), (1,2), (1,3),(1,4),(1,5),(1,6), (2,1),(2,2),(2,3),(2,4), (2,5),(2,7),(3,1),(3,2),(3,3),(3,4),(3,5),(3,6),(4,1),(4,2),(4,3),(4,4),(4,5),(4,6),(5,1),(5,2),(5,3),(5,4),(5,5),(5,6),(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}
This question can be solved using concept of probability and sample space.
a) probability of rolling a 7
Possible outcomes: (6,1),(1,6),(2,5),(3,4),(4,3),(5,2)
Probability= 6/36=1/6
b) Probability of a double
possible outcomes: (1,1),(2,2),(3,3),(4,4),(5,5),(6,6)
probability= 6/36= 1/6
c) probability of rolling a 7 or 8
= probability of rolling 7+ probability of rolling 8
= [tex]\frac{6}{36} +\frac{5}{36}= \frac{11}{36}[/tex]
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a coil of wire contains of 20 turns, each with an area of 1.5 x 10-3 m2. a magnetic field is normal to the surface of each loop. initially, the magnitude of b is 0.050 t. during the period of time of 0.10 s, the magnitude of the field at the coil has increased to 0.060 t. what is the average emf induced in the coil during this time?
electromagnetic induction was discovered by a. hans christian oersted b. isaac newton c. michael faraday d. benjamin franklin e. albert einstein
Answer:
Electromagnetic induction was discovered by Micheal Faraday.
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why did you have to draw circles around each station in order to pinpoint the epicenter? why couldn't you just use the distance from each station to go directly to the epicenter in a straight line? explain.
The ratio of the three circles they draw is equal to the distances from the stations to the epicenter.
Scientists use triangulation to find the epicenter of an earthquake. If seismic data are collected from at least three different locations, their intersection can be used to determine the epicenter. Each earthquake is recorded by numerous seismometers placed in different directions.
The epicenter is the point on the surface directly above the earthquake. A seismic station uses seismometer recordings to detect earthquakes. Determining the epicenter of an earthquake requires records from three separate seismic stations. Triangulation is a method of uniquely identifying earthquakes using distance information determined from three seismic stations.
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1. a million kg asteroid is in the asteroid belt. a 50000 kg chunk of rock floats 400m away. what is the force of gravity between the two asteroids?
The force of gravity between the two asteroids will be 125 *10^6 n
From the data,
The mass of the first asteroid is = 1 million kg = 1000000 Kg.
The mass of the second asteroid is = 50000 Kg.
The distance between both the asteroids = 400 m
We know,
The force of gravity between two objects can be determined by using the relationship
[tex]F_g=\frac{M_1M_2}{d}[/tex]
So, for determining the value of the force of gravity we will put the value of m1, m2 and d in the above formula:
Thus we will get:
[tex]F_g=\frac{1000000\times 50000}{400}=125,000,000=125\times 10^6\:N[/tex]
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what was the effect of doubling the water mass on the temperature change, and why do you think this happened?
The effect of doubling the water mass on the temperature change, and why do you think this happened is doubling the mass will double the temperature change.
It lowers the temperature. Because the water temperature lowers as the bulk of the cylinder grows, it will result in a cooler year. Thermal expansion happens with heating. The mass stays constant. The loudness goes up. And as a result, the density drops. The average kinetic energy of an object's particles rises with increasing temperature. The object's thermal energy grows as the average kinetic energy of its particles rises. As a result, an object's thermal energy rises as its temperature does.
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water falls without splashing at a rate of 0.250 l/s from a height of 2.60 m into a 0.750-kg bucket on a scale. if the bucket is originally empty, what does the scale read in newtons 3.00 s after water
Water falls at a flow rate of 0.250 l/s into a 0.750-kg bucket on a scale. After 3 seconds, the weight shown on the scale is 14.7 N
The relation between the accumulated volume and the volume flow rate is given by:
V = Q x t
Where:
V = accumulated volume of water
Q = volume flow rate
t = time period
In the given problem:
Q = 0.25 l/s
t = 3 s
Hence,
V = Q x t = 0.25 x 3 = 0.75 liter
The density of the water is 1 kg per liter, therefore 0.75 liter of water is equal to 0.75 kg of water.
Total mass on the scale = mass of water + mass of bucket
= 0.75 + 0.75 = 1.5 kg
The scale will read the weight:
Weight = mg = 1.5 x 9.8 = 14.7 N
Your question is incomplete, but most probably your question was:
Water falls without splashing at a rate of 0.250 L/s from a height of 2.60 m into a 0.750 kg bucket on a scale. If the bucket is originally empty , what does the scale read 3 s after water starts to accumulate in it.
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Students build a circuit. The circuit has wires that connect a battery to a switch and a fan. Which energy transformations happen when the students close the circuit and the blades of the fan begin to spin?
When the students close the circuit and the fan blades start to spin, energy is transformed from electrical energy to mechanical energy.
What is electrical energy?Electrical energy is energy generated from the flow of electric charge through a conductor. This energy is utilized in virtually all modern-day appliances, from lightbulbs to cell phones to electric cars. It is created in power plants, harnessed through transmission lines, and distributed to consumers. Electrical energy can be converted into other forms of energy, such as heat or light, and can be used to power machines and equipment.
This is done by the battery supplying electrical energy to the switch and the fan, which then converts the energy into rotational energy. This is what causes the fan blades to spin and produces mechanical energy. The mechanical energy produced by the fan is then used to create air movement, which is another form of mechanical energy.
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a certain heat engine does 9.5 kj of work and 8.50 kj heat transfer occurs to the environment in a cyclical process. (a) what was the heat transfer (in kj) into this engine?
The heat transfer into this engine is 52.7%.
Solution:
9.5 + 8.5
Hi = 18KJ
n = w/Hi
= 9.5/18 x 100
= 52.7%
Heat transfer is the field of thermal engineering concerned with the production use conversion and exchange of thermal energy between physical systems. Heat transfer is classified into different mechanisms such as. Conduction convection radiation and energy transfer through a phase change.
There are three ways heat is transferred conduction convection and radiation. Heat transfer between states of matter occurs whenever there is a temperature difference, and heat transfer only occurs in the direction of decreasing temperature, that is, from a hot body to a cold body.
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Identify the stage in star life cycle in which hydrogen is the primary fuel for nuclear fusion?
Main sequence is the stage of the star's lifecycle in which hydrogen acts as the primary fuel for nuclear fusion.
Life Cycle of StarThese hydrogen and helium elements combine to increase the mass in the centre of the cloud as a result of gravity's contracting force. As mass increases, gravitational pull also expands. All of the molecules and particles in the environment are pulled in by gravity. As the molecules continue to descend into the cloud's core, the cloud's mass rises and the cloud's center begins to heat up. This heated center is known as a protostar.
Now, as additional molecules are drawn to this protostar, the protostar's temperature is rising. The temperature continues to climb until the time comes when the pressure exceeds the point when two hydrogen atoms start to fuse, releasing heat and radiation to create helium.
Nuclear fusion is the process of fusing two hydrogen atoms to create helium by releasing a large amount of energy.
The outward force produced by the radiation and heat emitted now balances the inward force exerted by gravity. The star is born when the force is balanced equally inward and outward.
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