Find the lateral area and surface area of the regular square pyramid.
Round to nearest tenth.

Find The Lateral Area And Surface Area Of The Regular Square Pyramid.Round To Nearest Tenth.

Answers

Answer 1

Answer:

Step-by-step explanation:

lateral edge is an edge from the base to the vertex. As opposed to a base edge.

If the base edge is 6, the base diagonal is 6√2

Now draw a right triangle from the center of the base to the vertex, including one base corner.

(6√2/2)^2 + h^2 = (√34)^2

18 + h^2 = 34

h = 4

So, now we have height 4 and base edge 6, so the faces are triangles with

base = 6

height = √(3^2 + 4^2) = 5

lateral area is thus 4 * 1/2 (6)(5)

add the square base if desired.


Related Questions

A marble is 2 centimeters long. A rock is 75% longer than the marble. How long is the rock?

Answers

Answer:

3.5 centimeters

Step-by-step explanation:

75% of 2 cm = .75 x 2 = 1.5 cm

2 cm + 1.5 cm = 3.5 cm

In a triangle, an exterior angle formed by producing a side is half of a right angle. One of the two opposite interior angles is twice the Other; find the sizes of each interior angle of triangle.​

Answers

Step-by-step explanation:

let's explain this a bit.

when the exterior angle is a certain size, then the interior angle is 180 - that exterior angle.

in our case the exterior angle is half of a right angle, so it is 90/2 = 45°.

the corresponding interior angle is 180-45 = 135°.

the sum of all angles inside a triangle is always 180°.

so,

x + 2x + 135 = 180

3x = 45

x = 15°

2x = 30°

so, the 3 interior angles are

135°, 15°, 30°

P is the point (2, 7) and Q is the point (6, -3).
What is the gradient of PQ?

Answers

The Gradient of the line PQ is -5/2.

What is Gradient?

Gradient the basically the ratio between the change in vertical coordinate to change in horizontal coordinates.

Here, P (2, 7) and Q (6, -3)

Now, Gradient = [tex]\frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

           m = [tex]\frac{-3 -7}{6 - 2}[/tex]

           m = -10/4

         m = -5/2

Thus, the Gradient of the line PQ is -5/2.

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Julian’s friend James also has a tank in the shape of a triangular prism. The dimensions of James’ tank are each exactly 2 3/4 times the dimensions of Julian’s tank. If the area of the triangular base of Julian’s tank is approximately 400 square inches, what is the approximate area of the triangular base of James’ tank?

3,025 square inches
2,035 square inches
3,045 square inches
4,025 square inches

Answers

The approximate area of the triangular base of James’ tank is 3025 in²

To find the approximate area of the triangular base of James' tank, we need to know what scale is.

What is scale?

A scale is the ratio of two dimension. It is given by scale = New dimension/old dimension

Given that the dimensions of James’ tank are each exactly 2 3/4 times the dimensions of Julian’s tank.

The scale of the area of James' tank to the area of triangular base of Julian's tank is S = (2³/₄)²

= (11/4)²

= 121/16

Let

A = area of triangular base of James' tank, A' = area of triangular base of Julian's tank = 400 in²

So, scale, S = A/A'

The approximate area of the triangular base of James’ tank

So, making A subject of the formula, we have

A = SA'

A = 121/16 × 400 in²

A = 121 × 25 in²

A = 3025 in²

So, the approximate area of the triangular base of James’ tank is 3025 in²

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Find the sum or difference
(X-2)+(x+6)

Answers

The sum of the expression (x - 2) and (x+6) is 2x + 8

How to find sum of an expression?

The sum of numbers simply means to add up the numbers.

Therefore,

(x  -2) + (x + 6)

Hence,

(x - 2) + (x + 6)

open the brackets

Therefore,

x - 2 + x + 6

combine like terms

x + x + 2 + 6

add or subtract the like terms

2x + 8

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i need help with 7th grade math 30 points and brainleist ASAP

Answers

Answer:

The scale factor is 8. The model is scaled by 8 to get the sculpture.

If they want it in reverse, the answer is 1/8. The model is 1/8th of the sculpture's size.

Sculpture = scale factor * model

[we get this equation because the model must be turned into a sculpture so we want to find how much bigger the model is compared to sculpture]

Let's take the length of the sculpture and model to put in.

x

56 = scale factor * 7

56/7  = scale factor

8 = scale factor

Answer:

1/8

Step-by-step explanation:

Take the scale factor as a ratio between the model and the sculpture.

Take any of the listed dimensions (length, for example) and divide.

7/561/8


Rick recorded the information shown below. What type of graph would be the most appropriate for Rick to use

Answers

A Line graph

Sure hope this helps you

Draw a line representing “rise” and line representing the “run of the line state the slope of the line .state the slope of the line in the simplest form.

Answers

Answer:

  slope 4/5

Step-by-step explanation:

The attachment shows the rise in green (4 grid squares), and the run in red (5 grid squares). The slope is the ratio rise/run.

__

The slope is rise/run = 4/5.

Chords AB and CB intersect at E in circle O, as shown in the diagram below. Secant
PFA and tangent PD are drawn to circle O from external point and chord AC is drawn. The ratio of BF:FC:CA:AB = 3:3:4:8. Find the measures of FC,∠P,∠CEA, and ∠ABC.

Answers

Answer:

Step-by-step explanation:

What is the quotient of 9-x2/
3x
and
x2 +6x+9/
3x?

Answers

44 rem

Im sorry if its wrong

467532 rounded by 100 000

Answers

Answer:

Round off value = 500000

Step-by-step explanation:

467532  > 500

- Round up

⇒ 500,000

anyone understands this?

Answers

Answer:

See below

Step-by-step explanation:

Not sure what they are looking for here....unless there is more info

[tex]\sqrt[14]{y}[/tex]  =  [tex]y^{1/14}[/tex]     perhaps?

Find the product of



[tex]8(4\sqrt 7-\sqrt18)[/tex]

Answers

Answer:

[tex]32\sqrt{7}-24\sqrt{2}[/tex]

Step-by-step explanation:

[tex]8(4\sqrt{7}-\sqrt{18})\\\\8(4\sqrt{7}-3\sqrt{2})\\\\32\sqrt{7}-24\sqrt{2}[/tex]

When you use word processor functions such as spell check and thesaurus to write a second draft you are
A. Peer editing
B. Publishing
C. Revising
D. Prewriting

Answers

C. Revising because it should be your last stage in the writing process before you publish

When you use word processor functions such as spell check and thesaurus to write a second draft, you are "C. Revising."

What is word processor

Revising means making changes and improvements to a piece of writing to make it better. This includes making it easier to understand, organizing it well, and making sure it is good quality overall.

Using spell check helps you fix mistakes in your spelling, while using the thesaurus helps you find different words that mean the same thing and choose better words to make your writing clearer and more accurate.

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USING Pythagoras theorem find the formula of equilateral triangle.​

Answers

Answer:

Answer with explanation is below~

Step-by-step explanation:

We could easily obtain the formulae/formula of an equilateral triangle not only through Pythagoras Theorem, but also through Heron's formula.

INTRODUCTION:

What's equilateral triangle?

It's an triangle, whose all sides're of equal measurement.

What's Heron Formula?

It's just a formula actually,take an example:Let,a,b and c denotes the lengths of 3 sides of any triangle,then the area will be given as:

[tex] \boxed{\rm \: Area= \sqrt{s(s - a)(s - b)(s - c)} \: units ^{2}} [/tex]

Where,

s = (a+b+c)/2 {Half of the perimeter, basically}

What's Pythagoras' Theorem?

It's actually like a formula but a theorem introduced by Pythagoras.

SOLVING:

Let,ABC an equilateral triangle of sides a.

Now:Draw a perpendicular straight line AM to the side BC(Name each part of triangle)

So it's clear that ∆AMB is a right angled triangle at M, BM = (1/2)BC = a/2.

Please note AM here represents the height of ∆ ABC.

Let's use Pythagoras' theorem now.

[tex] \boxed{\rm \: AM = \sqrt{AB^2-BM^2}}[/tex]

AB = aBM = a/2

[tex] \rm \: AM = \sqrt{a {}^{2} - { \bigg( \cfrac{a}{2} \bigg) }^{2} } [/tex]

[tex] \rm \: AM = 3 \: \cfrac{a {}^{2} }{4} [/tex]

[tex] \rm \: AM = \cfrac{ \sqrt{3} }{2} \: a[/tex]

Now find the area of ∆ABC:

[tex] \rm \triangle \: ABC = \cfrac{1}{2} \times \: BC \times A [/tex]

[tex] \rm \: \triangle \: ABC = \cfrac{1}{2} \times a \times \cfrac{ \sqrt{3}}{4}a [/tex]

[tex] \boxed{\rm\triangle \: ABC = \cfrac{ \sqrt{3 } }{4} a {}^{2} \: units {}^{2}} [/tex]

Hence,the formulae of equilateral triangle using Pythagoras' theorem is {√(3)/4} a^2

[tex] \rule{225pt}{2pt}[/tex]

Extras:

Now let's find the area using Heron's Formula.

Solving:

Let each side of an equilateral triangle be a.

SO, then:

s = (3a/2)

We know that, (Heron's formula)

[tex] \rm \: A = \sqrt{s(s - a)(s - b)(s - c)} [/tex]

Now the area A :

[tex]\rm AR(A)= \sqrt{ \cfrac{ 3a } 2 \bigg(\cfrac{ 3a }{2} - a \bigg)\bigg(\cfrac{ 3a }{2} - a \bigg)\bigg(\cfrac{ 3a }{2} - a \bigg)} [/tex]

[tex]\rm AR(A)= \sqrt{ \cfrac{3a}{2} \bigg( \cfrac{a}{2} \bigg)\bigg( \cfrac{a}{2} \bigg)\bigg( \cfrac{a}{2} \bigg)}[/tex]

[tex]\rm \boxed{ \rm AR(A)= \cfrac{ \sqrt{ 3a}}{4} \: a {}^{2} \: \: units {}^{2}} [/tex]

And voila! we're done!

I hope this helps! :)

[Figure of Equilateral triangle is attached, it denotes the triangle we need to draw while finding the formulae through Pythagoras' theorem. ]

(Brainliest will be given :D) (Please help, with hints!) The floor plan of an office was drawn using a scale of 1 inch = 4 feet.

The reception area on the floor plan is 3 inches by 5 inches.

What are the dimensions of the reception area?

HINT: Write and solve a proportion comparing the scale of 1 inch = 4 feet to each of the dimensions of the reception area of the floor plan (one for 3 inches and one for 5 inches).

Answers

Using proportions, it is found that the dimensions of the reception area of of 12 feet by 20 feet.

What is a proportion?

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

In this problem, the scale factor is of 1 inch = 4 feet, meaning that each inch on the drawing represents a dimension of 4 feet.

The drawing is of 3 inches by 5 inches, hence the real dimensions are given by;

3 x 4 = 12 feet.5 x 4 = 20 feet.

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A store employee conducted a survey of 325 randomly selected customers. According to the survey, 212 of the customers often use the app to shop. Get app | Meijer How many people would you expect to use the app if all 2,000 people in the community visited the store?

Answers

The number of people out of 2000 expected to use the app will be 1300.

What is a survey?

A survey is a research method used for collecting data from a predefined group of respondents to gain information and insights into various topics.

It is given that:-

A store employee conducted a survey of 325 randomly selected customers. According to survey 212, customers often use the app to shop.

We need to find the data for 2000 people who visited the store.

So the percentage of the people who are using the app will be calculated as:-

[tex]= \dfrac{212}{3254}=65\%[/tex]

So the number of the people out of 2000 will be:-

[tex]N\ = 2000\times \dfrac{65}{100}=1300\ \[/tex]

Hence the number of people out of 2000 expected to use the app will be 1300.

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Jenny is putting 11 books in a row on her bookshelf. She will put one of the books, The Iliad, in the first spot. She will put another of the books, The Odyssey, in the last spot. In how many ways can she put the books on the shelf?

Answers

i believe the answer is there are
39,916,800 ways she can put the books on the shelf

2.2 Determine the general solution of 2.2.1 3 sin x = cos x
2.2.2 2 cos²x + 5 sin x = 4​

Answers

Step-by-step explanation:

try this solution, note, the answers are underlined with green colour.

Given that x = 2u + v, y = u/v and z = e^(xy) find dz/du and dz/dv using the chain rule.​

Answers

Answer:

[tex]\displaystyle \boxed{ \frac{dz}{du} = \frac{e^\big{\frac{u(2u + v)}{v}}}{v} \Bigg[ 4u + v \Bigg] }[/tex]

[tex]\displaystyle \boxed{ \frac{dz}{dv} = \frac{ue^\big{\frac{u(2u + v)}{v}}}{v} \Bigg[ 1 - \frac{2u + v}{v} \Bigg] }[/tex]

General Formulas and Concepts:

Calculus

Differentiation

DerivativesDerivative Notation

Derivative Property [Multiplied Constant]:
[tex]\displaystyle (cu)' = cu'[/tex]

Derivative Property [Addition/Subtraction]:
[tex]\displaystyle (u + v)' = u' + v'[/tex]

Derivative Rule [Basic Power Rule]:

f(x) = cxⁿf’(x) = c·nxⁿ⁻¹

Multivariable Calculus

Partial Derivatives

Partial Derivative Rule [Chain Rule]:
[tex]\displaystyle \frac{dw}{dt} = \frac{\partial w}{\partial x} \frac{\partial x}{\partial t} + \frac{\partial w}{\partial y} \frac{\partial y}{\partial t} + \frac{\partial w}{\partial z} \frac{\partial z}{\partial t}[/tex]

Step-by-step explanation:

Step 1: Define

Identify given.

[tex]\displaystyle x = 2u + v[/tex]

[tex]\displaystyle y = \frac{u}{v}[/tex]

[tex]\displaystyle z = e^{xy}[/tex]

Step 2: Find Derivatives

[tex]\displaystyle \frac{dz}{du}[/tex]:

[Derivative] Rewrite [Partial Derivative Rule - Chain Rule]:
[tex]\displaystyle \frac{dz}{du} = \frac{\partial z}{\partial x} \frac{\partial x}{\partial u} + \frac{\partial z}{\partial y} \frac{\partial y}{\partial u}[/tex]

We can find the partial derivatives by differentiating using basic differentiation rules found under "Calculus":

[tex]\displaystyle\begin{aligned}\frac{\partial z}{\partial x} & = ye^{xy} \\\frac{\partial x}{\partial u} & = 2 \\\frac{\partial z}{\partial y} & = xe^{xy} \\\frac{\partial y}{\partial u} & = \frac{1}{v} \\\end{aligned}[/tex]

Substituting in our partial derivatives and our variables x and y, we can obtain a final derivative:

[tex]\displaystyle\begin{aligned}\frac{dz}{du} & = 2ye^{xy} + \frac{xe^{xy}}{v} \\& = \frac{2ue^\big{\frac{u(2u + v)}{v}}}{v} + \frac{(2u + v)e^\big{\frac{u(2u + v)}{v}}}{v} \\& = \boxed{ \frac{e^\big{\frac{u(2u + v)}{v}}}{v} \Bigg[ 4u + v \Bigg] }\end{aligned}[/tex]

∴ we have found the derivative of z with respect to u.

[tex]\displaystyle \frac{dz}{dv}[/tex]:

[Derivative] Rewrite [Partial Derivative Rule - Chain Rule]:
[tex]\displaystyle \frac{dz}{dv} = \frac{\partial z}{\partial x} \frac{\partial x}{\partial v} + \frac{\partial z}{\partial y} \frac{\partial y}{\partial v}[/tex]

We can find the partial derivatives by using the same method(s):

[tex]\displaystyle\begin{aligned}\frac{\partial z}{\partial x} & = ye^{xy} \\\frac{\partial x}{\partial v} & = 1 \\ \frac{\partial z}{\partial y} & = xe^{xy} \\\frac{\partial x}{\partial v} & = \frac{-u}{v^2} \\ \end{aligned}[/tex]

Substituting in our partial derivatives and our variables x and y, we can obtain a final derivative:

[tex]\displaystyle\begin{aligned}\frac{dz}{dv} & = ye^{xy} + \frac{-uxe^{xy}}{v^2} \\& = \frac{ue^\big{\frac{u(2u + v)}{v}}}{v} + \frac{-u(2u + v)e^\big{\frac{u(2u + v)}{v}}}{v^2} \\& = \boxed{ \frac{ue^\big{\frac{u(2u + v)}{v}}}{v} \Bigg[ 1 - \frac{2u + v}{v} \Bigg] }\end{aligned}[/tex]

∴ we have found the derivative of z with respect to v.

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Topic: Multivariable Calculus

Unit: Partial Derivatives and Applications

A quadratic function has 2 distinct roots. Always never sometimes

Answers

Answer:

Always

Step-by-step explanation:

[tex]ax^{2} + bx + c = 0[/tex]

Area of circumstances of a circle with radius of 5

Answers

Circumference of a Circle = 2πr
2 π 5
approx 31.41

Area of a Circle πr^2

π5^2
Approx 78.53

. Carl bought one book for $3.95 and a second book for $4.95. What is his total cost? $9.90 $9.00 $8.90 $7.90

Answers

The Cost of Carl's first item is 3.95. The Cost of his second item is 4.95. To find the total amount we need to add these two numbers together.

3 plus 4 is 7

95 cents plus 95 cents is 1.90

7+1.90 is 8.90

The total cost is $8.90

Hope this helps!

Can somebody please help me with this please and thankyou!!

Answers

Answer:

a) x=loge3 ( log e base 3)

b)4=e^y

Answer:

A.) loge(x)=3

B.)  e^y =4

Step-by-step explanation:

A.) loge(x)=3

B.)  e^y =4

PLEASE HELP PLEASE PLEASE HELP

Answers

Answer:

2:3

Step-by-step explanation:

Simplica Los dos numeros

6 ÷ 3 = 2

9 ÷ 3 = 3

same here, i rlly need help

Answers

Answer:

Area = 50.125 cm^2

Perimeter = 26 + 15 = 41 cm

Step-by-step explanation:

Area Rectangle = 6 * 7 = 42 cm^2

Area Triangle = 1/2 * (9.5 - 7) * 6.5

Area Triangle = 1/2 * (2.5) * 6.5 = 8.125 cm^2

Total Area = 42 + 8.125 = 50.125 cm^2

Perimeter Rectangle = 6 + 7 + 6 + 7 = 26 cm

Perimeter or Triangle = 2.5 + 6.5 + 6 = 15 cm

Total Perimeter = 26 + 15 = 41 cm

Find the slope.
y= X/3 + 4
M= ?/?

Answers

Answer:

m=1/7

Step-by-step explanation:

The slope of y=x/3 + 4 is 1/7.

x/3+4 = x/7 so m = 1/7.

Answer:

m = 1/3

Step-by-step explanation:

The equation given is in slope-intercept form, which has the basic structure:

y = mx + b

In this equation, "m" is the slope and "b" is the y-intercept.

The value of "b" is 4.

The value of "m" is 1/3. This is because (x/3) is the same as (1/3 times x).

What do u know about Trigonometry in grade 11

Answers

Answer:

A lot

Step-by-step explanation:

So basically you learn a lot

Help plez . What is the mean absolute deviation of the data set?

8, 5, 12, 4, 5, 8, 7


1

2

5

7

Answers

Answer:

2

Step-by-step explanation:

first, add terms

8 + 5 + 12 + 4 + 5 + 8 + 7 = 49

seven terms, therefore we divide by 7

49/7 = 7

find distance

8-7= 1

7-5= 2

12-7=5

7-4=3

7-5=2

8-7=1

7-7=0

added together you get 14,

14/7 = 2

your answer is 2

hope this helps:)

$800 is deposited in an account
that pays 9% annual interest,
compounded annually. Find the
balance after four years.
$[ ? ]

Answers

Answer:

$1,129.27

Step-by-step explanation:

Compounded interest formula is

[tex]A=P(1+\frac{r}{n} )^{nt}[/tex]

Where [tex]A[/tex] is the final amount, [tex]P[/tex] is the principal, [tex]r[/tex] is the anual interest in decimal, [tex]n[/tex] is the numer of compounded periods in one year and [tex]t[/tex] is the time in years.

[tex]P= 800\\r= 0.09\\n= 1\\t= 4[/tex]

So then we plug our numbers...

[tex]A=800(1+\frac{0.09}{1})^{1(4)}=800(1.09)^{4}[/tex]

[tex]A=$1,129.27[/tex]

After 4 years the amount would be $1,129.27

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