To Find :
The horizontal range of a projectile launched at 15 degrees to the horizontal with speed of 40 m/s.
Solution :
The horizontal range of a projectile is given by :
[tex]R = \dfrac{u^2 sin 2\theta}{g}[/tex] ( Here, g is acceleration due to gravity = 10 m/s² )
Putting all value in above equation :
[tex]R = \dfrac{40^2 \times sin (2 \times 15)}{10} \ m\\\\R = \dfrac{1600 \times 1}{2\times 10} \ m\\\\R = 80 \ m[/tex]
Therefore, the horizontal range of projectile is 80 m.
If 23.6 mL of 0.200 M NaOH is required to neutralize 10.00 mL of a H3PO4 solution , what is the concentration of the phosphoric acid solution
Answer:
The correct answer is 0.157 M.
Explanation:
The chemical equation of the mentioned reaction is, 3NaOH + H₃PO₄ ⇄ Na₃PO₄ + 3H₂O The molarity of NaOH given is 0.2 M, the volume of NaOH given is 23.6 ml or 23.6 × 10⁻³ L. The moles of NaOH can be determined by using the formula, Moles of NaOH = Volume of NaOH × Molarity Moles of NaOH = 23.66 × 10⁻³ L × 0.2 M = 0.00472 moles Based on the reaction, 3 moles of NaOH needs 1 mole of H₃PO₄. So, 0.00472 moles of NaOH will require, 0.00472/3 = 0.0015733 moles.
The concentration or molarity of the H₃PO₄ will be, [H₃PO₄] = Moles of H3PO4/Volume of H₃PO₄ in liters (Volume of H₃PO₄ given is 10 ml of 10 × 10⁻³L) = 0.0015733 moles/ (10 × 10⁻³ L) = 0.157 M
Limitations of Pearson rule
You need 520. mL of a 10. % (m/v) glucose solution. If you have a 25% (m/v) glucose solution on hand, how many milliliters do you need
Answer:
The answer is "208 mL".
Explanation:
[tex]C_1 = 25\% \ \frac{m}{v}\\\\C2 = 10\% \ \frac{m}{v}\\ \\V_1= 520\ \ mL\\\\V_2=?[/tex]
In dilutions of different concentration, its initial volume for glucose solution V1 can be obtained by using the following formula, i.e.
[tex]\to C_1V_1 = C_2V_2\\\\\to V_1 = \frac{C_2V_2}{C_1} \\\\= \frac{10 \times 520 }{ 25}\\\\ = 208 \ mL[/tex]
The solution of 520 mL [tex]10\%\ \ (\frac{m}{v})[/tex] final glucose solution thus requires 208 mL of glucose solution of [tex]25\%\ \ (\frac{m}{v})[/tex].
If an atomic number of an element is 24, the number of protons the Atom has is
A. 24
B. 12
C. 189
D.51.996
Explanation:
i think the answer is A ........ hope this helps
(1.21 x 10^-3 + 1.3 x 10^-3) x 6.453 x 10^2 =
Answer:
1.61
Explanation:
Please help, any and all is very much appreciated!
Each of the following models represents particles present before and after a
chemical reaction which correctly shows conservation of mass during a
reaction?
Answer:
D
Explanation:
According to the law of conservation of mass, matter can neither be created nor destroyed. The implication of this is that the total mass of reactants should be equal to the total mass of products.
There should be equal masses of reactants and products on both sides of the reaction equation. This most important condition is only satisfied by option D.
Convert 2.0 micrometer to centimeters and to inches
Answer:
2x10⁻⁴cm and 7.9x10⁻⁵ inches
Explanation:
Micrometer, μm, is an unit of length. Could be related with another units of lenght as, for example:
1.0μm = 1x10⁻⁴cm
1.0μm = 3.93701x10⁻⁵ inches
That means, 2.0μm are:
2.0μm * (1x10⁻⁴cm / 1μm) = 2x10⁻⁴cm
And:
2.0μm * (3.93701x10⁻⁵ inches / 1μm) = 7.9x10⁻⁵ inches
Measure the initial temperature of the water to the nearest 0.1°C. Record in the data table.
Initial Temp. of Metal
Initial Temp. of water
Initial Temp. of Both
Subtract to find the temperature changes for the water and the metal
Water
Metal
The heat capacity of the metal is calculated using the formula:
Heat capacity = quantity of heat/(mass * temperature difference)What is temperature?
The temperature of a substance is the degree of hotness or coldness of that substance.
Temperature difference between substances enables heat flow.
Heat flows from hot to cold bodies.
In the given experiment, to determine the heat capacity of a metal, the temperature difference is obtained by substracting the initial and final temperatures.
The heat capacity of the metal is then calculated using the formula:
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Explain why the coefficients on the left side of the equation don’t necessarily equal the coefficients on the right side of the equation. Is this possible if mass is being conserved?
Answer:
Explanation:
Short answer: Yes.
The coefficients may not be conserved, but mass always has to be. Take this equation as an example
2 Mg3P2 ===> 6Mg + P4
There is a 2 on the left side and 6 and 1 on the right. I hope you mean that the coefficient 2 is not equal to 7.
But let's look a little closer. You have to look at the molecular structure of the left and right side.
2Mg3P2 has 6 Mgs and 4 Ps on the left side.
6Mg is on the right. They are free standing.
P4 has 1 molecule consisting of 4 Ps.
Everything balances.
This is a terrific question to be asking. You need to understand the internal balance numbers vs the molecular ones on the out side.
That sounds like a bit of gobbledygook and it takes a bit of study.
2 Mg3P2 means that Mg3P2 is written twice.
Mg3P2 ==> "3 Mg2+ + 2P3+ and there is another one written the same way.
Mg3P2 ==> "3 Mg2+ + 2P3+
How many moles of zinc are in 0.535 g ?*
Answer:
0.00818 moles
Explanation:
Why is carbon used to date things that were once living?
A. Carbon is not toxic to living things.
B. The half-life of carbon depends on age.
C. The amount of carbon is easy to measure.
D. Living things take in carbon from food.
Answer:
a - carbon is not toxic to living things
Explanation:
The reason carbon dating works is that the fresh carbon-14 gets mixed in with the rest of the carbon in the atmosphere and, since it's chemically identical to regular carbon, gets worked into whatever is presently absorbing atmospheric carbon
what does litmus do when it is put into sodium hydroxide?
PLEASE ANSWER ME FAST PLEASE
Answer:
The red litmus turns to blue
Explanation:
Hope it helps
) Dinitrogen Tetroxide partially decomposes according to the following equilibrium: N2O4 (g) 2NO2 (g) A 1.00-L flask is charged with 0.400 mol of N2O4. At equilibrium at 373 K, 0.0055 mol of N2O4 remains. Keq for this reaction is __________.
Answer: The value of [tex]K_{eq}[/tex] for this reaction is 1.578.
Explanation:
Given: Initial moles of [tex]N_{2}O_{4}[/tex] = 0.4 mol
Volume = 1.00 L
Therefore, initial concentration of [tex]N_{2}O_{4}[/tex] is calculated as follows.
[tex]Concentration = \frac{moles}{volume}\\= \frac{0.4}{1.0 L} mol\\= 0.4 M[/tex]
Now, ICE table for the given reaction equation is as follows.
[tex]N_{2}O_{4}(g) \rightleftharpoons 2NO_{2}[/tex]
Initial: 0.4 0
Change: -x +2x
Equib: 0.4 - x = 0.0055 2x
Hence, the value of x is calculated as follows.
0.4 - x = 0.0055
x = 0.4 - 0.0055
= 0.3945
Now, the [tex][NO_{2}][/tex] is calculated as follows.
2x = [tex][NO_{2}][/tex] = [tex]2 \times 0.3945 = 0.789[/tex]
Therefore, [tex]K_{eq}[/tex] for the given reaction is calculated as follows.
[tex]K_{eq} = \frac{[NO_{2}]^{2}}{[N_{2}O_{4}]}\\= \frac{(0.789)^{2}}{(0.3945)}\\= 1.578[/tex]
Thus, we can conclude that [tex]K_{eq}[/tex] for this reaction is 1.578.
What is the colour change when universal indicator is added to a solution containing potassium
in water?
Answer:. Dark purple
(b). Orange yellow
(c). Red
Explanation:
an organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classified as:
a. alkane
b. alkene
c. alkyne
d. arene
Answer:
c. alkyne.
Explanation:
Hello there!
In this case, according to the attached file, it turns out possible for us to say that alkanes have only single-bonded carbon atoms, alkenes have two double-bonded carbon atoms and alkynes have two triple-bonded carbon atoms.
In such a way, according to the aforementioned definition, we infer that that an organic compound that contains only carbon and hydrogen and a triple bond (all the other bonds are single bonds) is classified as c. alkyne.
Regards!
In Atom, what is a heavier sub-atomic particle than the others and explain why
The nucleons are havier in sub atomic particle like neutrons and protons.
fun fact i read in a book even 1cm³ of nucleons are around 2 million Kg which you can't pick up by hand even by machines like buldozer.
if you were conducting an experiment with pepsin which has an optimal enzymatic actigity at ph 2.3, wat buffer would be the best choice
Answer: One with a pKa of 1.9
Hope this helps <3
P.S Fun Fact~~
There are only two words in the English language that have all five vowels in order: "abstemious" and "facetious."!
Answer:
Explanation: Is there choises? H3PO4 / NaH2PO4 buffer with equal concentrations would form a buffer solution pH = 2.15
Which area of chemistry best links the use of titanium and plastics in artificial bone and joint replacements?
A) environmental chemistry
B) materials chemistry
C) agricultural chemistry
D) physical chemistry
Answer:I think it’s material chemistry
Explanation:
Answer:
Material chemistry.
Explanation:
Artificial bone and joint replacements is not environmental, it does not have anything to do with farming or such things, and physical chemistry has to do with chemical reactions which is not going on. This leaves materials chemistry.
Draw the major organic product(s) for the reaction. The starting material is a benzene ring with one substituent. The substituent is a nitrogen bonded to a hydrogen and a carbonyl that is bonded to a methyl group. THis reacts with tert butyl bromide and A l b r 3 to give the product.
Answer:
See Explanation
Explanation:
In electrophilic aromatic substitution, the benzene ring undergoes substitution when it is reacted with suitable electrophiles.
The products of electrophilic aromatic substitution depends on the substituents already present on the benzene ring. Some substituents activate the ring towards electrophilic substitution and direct the incoming electrophile to the ortho and para positions on the ring while some substituents deactivate the benzene ring towards electrophilic substitution and direct the incoming electrophlle to the meta position on the ring.
The amide substituent is moderately activating and is an ortho, para director hence the products shown in the mage attached to this answer.
2) A 0.77 mg sample of nitrogen gas reacts with chlorine gas to form 6.61 mg of a nitrogen
chloride compound. What is the empirical formula of the nitrogen chloride compound?
Answer:
NCl₃
Explanation:
From the question given above, the following data were obtained:
Mass of nitrogen (N) = 0.77 mg
Mass of chlorine (Cl) = 6.61 mg
Empirical formula =?
The empirical formula of the compound can be obtained as follow:
N = 0.77 mg
Cl = 6.61 mg
Divide by their molar mass
N = 0.77 / 14 = 0.055
Cl = 6.61 / 35.5 = 0.186
Divide by the smallest
N = 0.055 / 0.055 = 1
Cl = 0.186 /0.055 = 3
Therefore, the empirical formula of the compound is NCl₃
Which is a fossil fuel?
O A. Coal
O B. Biomass
O C. Geothermal
O D. Nuclear
Answer:
coal
Explanation:
fossil fuels are formed by natural process.
Coal is the fossil fuel. A is correct.
Fossil fuels are non renewable source of energy that means once they get finished we will not be able to use them. Hence it is very important for us to find an alternate like a renewable source of energy like sunlight so that we will not have to depend on these fossil fuels and will not have to tolerate the pollution happening by them as well.
Given options are-
A. Coal
B. Biomass
C. Geothermal
D. Nuclear
Therefore, Coal is the fossil fuel. A is correct.
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HELP PLS HELP i rlly need help omg
It took 10.40 mL of a NaOH solution to neutralize 0.307 g of KHP. What is the molarity of the NaOH solution
Answer:
0.144 M
Explanation:
First we convert 0.307 g of KHP (potassium hydrogen phthalate, KHC₈H₄O₄) into moles, using its molar mass:
0.307 g ÷ 204.22 g/mol = 0.0015 mol KHP1 mol of KHP reacts with 1 mol of NaOH, that means that in 10.40 mL of the NaOH solution there were 0.0015 moles of NaOH.
Now we calculate the molarity of the NaOH solution:
10.40 mL / 1000 = 0.0104 LMolarity = 0.0015 mol / 0.0104 L = 0.144 M1. How did the change of stress (adding or removing reactants or products) cause a shift in the equilibrium system of your solutions? Use data to support your answer. Make sure you discuss all four stress changes: a. Adding a reactant b. Adding a product c. Removing a reactant d. Removing a product
Answer:
If reactant or product is removed, the equilibrium shifts to make more reactant or product, respectively, to make up for the loss.
If the reactant or product is removed, the equilibrium shifts to make more reactant or product, to make up for the loss.
Consider four different samples: aqueous LiBr, molten LiBr, aqueous LiF, and molten LiF. Current run through each sample produces one of the following products at the anode: liquid bromine, fluorine gas, or oxygen gas. Match each sample to its anodic product from aqueous LiBr, Molten LiBr, aqueous LiF, and molten LiFA. Liquid bromine,
B. Fluorine gas,
C. oxygen gas
Answer:
Following are the solution to the given question:
Explanation:
Please find the matching in attached file.
During the electrolysis of Molten LiBr : Li is reduced and Br are oxidized .
Lithium Metal is produced at the Cathod during the electrolysis of Molten LiBR .
In the aquous LiBr : In aquous LiBr potential of Li is greater than the of water then Li is reduced to produce solid Li ion. As well As aqueous LiF ( electrolysis)and Molten LiF electrolysis produce the gas.
aqueous LiF: Oxygen gas.
Molten LiF : Flourine gas.
How much energy is required to vaporize 2 kg of copper? Use the table below
and this equation: Q = mLvapor-
Answer:
9460 kj
Explanation:
just did it
Pea plants have green seeds only if a plant receives an allele for green seeds from each of its parents. What kind of allele produces green seeds in pea plants?
Your answer:
Hybrid
Dominant
Recessive
Mutated
Answer:If two heterozygous parents with a genotype of Yy are crossed, the possible combination of genotypes in their offspring would be YY, Yy, Yy, and yy. Therefore, the genotypic ratio of the offspring produced is 1:2:1.
Explanation:If two heterozygous parents with a genotype of Yy are crossed, the possible combination of genotypes in their offspring would be YY, Yy, Yy, and yy. Therefore, the genotypic ratio of the offspring produced is 1:2:1.
If only 0.225 g of Ca(OH)2 dissolves in enough water to give 0.100 L of aqueous solution at a given temperature, what is the Ksp value for calcium hydroxide at this temperature
Answer: The [tex]K_{sp}[/tex] value for calcium hydroxide at this temperature is [tex]1.08 \times 10^{-4}[/tex].
Explanation:
Given: Mass of [tex]Ca(OH)_{2}[/tex] = 0.225 g
Volume = 0.100 L
As moles is the mass of substance divided by its molar mass.
So, moles of [tex]Ca(OH)_{2}[/tex] (molar mass = 74 g/mol) is calculated as follows.
[tex]Moles = \frac{mass}{molar mass}\\= \frac{0.225 g}{74 g/mol}\\= 0.003 mol[/tex]
Molarity is the number of moles of substance present in a liter of solution.
Hence, molarity of given solution will be as follows.
[tex]Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.003 mol}{0.1 L}\\= 0.03 M[/tex]
The equation for dissociation of [tex]Ca(OH)_{2}[/tex] is as follows.
[tex]Ca(OH)_{2} \rightarrow Ca^{2+} + 2OH^{-}[/tex]
This means that [tex][Ca^{2+}] = 0.03[/tex] and [tex][OH^{-}] = 2 \times 0.03 = 0.06[/tex]. Hence, [tex]K_{sp}[/tex] value for this reaction is calculated as follows.
[tex]K_{sp} = [Ca^{2+}][OH^{-}]^{2}\\= (0.03) \times (0.06)^{2}\\= 1.08 \times 10^{-4}[/tex]
Thus, we can conclude that the [tex]K_{sp}[/tex] value for calcium hydroxide at this temperature is [tex]1.08 \times 10^{-4}[/tex].
What caused carbon dioxide to decrease in the air (abiotic matter) of the biodome?
Answer:
As organisms release energy during cellular respiration, carbon dioxide is produced from the carbon in energy storage molecules. ... Carbon dioxide in the biodome decreased because decomposers decreased which means there was a decrease in cellular respiration overall.
Explanation:
Carbon dioxide is "a colorless, odorless gas that is present in the atmosphere and is formed when any fuel containing carbon is burned".
What is atmosphere?Atmosphere is "a mixture of gases that includes about 78% nitrogen and 21% oxygen at Earth's surface".
What is fuel?Fuel is "a substance which upon combustion produces a usable amount of energy".
When the population of decomposer decreased, the amount of carbon dioxide in the biodome decreased drastically. The carbon dioxide that used to be in the air (abiotic matter) is now in another part of the ecosystem and the carbon remained constant.
Hence, Carbon dioxide decreased in the air (abiotic matter) of the biodome.
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