Find the first six terms of the sequence defined by each of these recurrence relations and initial conditions.
a) an=6an-1, a0=2
b) an=a2n-1, a1=2
c) an=an-1+3an-2, a0=1 , a1=2
d) an=nan-1+n2 an-2 a0=1 ,a1=1
e) an= an-1+an-3 , a0=1, a1=2 , a2=0

Answers

Answer 1

Answer:

See explanation

Step-by-step explanation:

Solving (a):

[tex]a_n = 6a_{n-1}[/tex] where [tex]a_0 = 2[/tex]

n = 1

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_1 = 6a_{1-1}[/tex]

[tex]a_1 = 6a_{0}[/tex]

Substitute 2 for [tex]a_0[/tex]

[tex]a_1= 6 * 2[/tex]

[tex]a_1= 12[/tex]

n = 2

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_2 = 6a_{2-1}[/tex]

[tex]a_2 = 6a_{1}[/tex]

Substitute 12 for [tex]a_1[/tex]

[tex]a_2= 6 * 12[/tex]

[tex]a_2= 72[/tex]

n = 3

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_3 = 6a_{3-1}[/tex]

[tex]a_3 = 6a_2[/tex]

Substitute 72 for [tex]a_2[/tex]

[tex]a_3= 6 * 72[/tex]

[tex]a_3= 432[/tex]

n = 4

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_4 = 6a_{4-1}[/tex]

[tex]a_4 = 6a_{3}[/tex]

Substitute 432 for [tex]a_3[/tex]

[tex]a_4 = 6 * 432[/tex]

[tex]a_4 = 2592[/tex]

n = 5

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_5 = 6a_{5-1}[/tex]

[tex]a_5 = 6a_4[/tex]

Substitute 2592 for [tex]a_4[/tex]

[tex]a_5 = 6 * 2592[/tex]

[tex]a_5 = 15552[/tex]

n = 6

[tex]a_n = 6a_{n-1}[/tex]

[tex]a_6 = 6a_{6-1}[/tex]

[tex]a_6 = 6a_{5}[/tex]

Substitute 15552 for [tex]a_5[/tex]

[tex]a_6 = 6 * 15552[/tex]

[tex]a_6 = 93312[/tex]

[tex]a_1= 12[/tex]   [tex]a_2= 72[/tex]   [tex]a_3= 432[/tex]   [tex]a_4 = 2592[/tex]   [tex]a_5 = 15552[/tex]   [tex]a_6 = 93312[/tex]

Solving (b):

[tex]a_n = a^2_{n - 1[/tex] where [tex]a_1 = 2[/tex]

We have

[tex]a_1 = 2[/tex] which serves as the first term

n =2

[tex]a_n = a^2_{n - 1[/tex]

[tex]a_2 = a^2_{2-1}[/tex]

[tex]a_2 = a^2_{1}[/tex]

Substitute 2 for [tex]a_1[/tex]

[tex]a_2 = 2^2[/tex]

[tex]a_2 = 4[/tex]

n = 3

[tex]a_3 = a^2_{3-1}[/tex]

[tex]a_3 = a^2_{2}[/tex]

[tex]a_3 = 4^2[/tex]

[tex]a_3 = 16[/tex]

n = 4

[tex]a_4 = a^2_{4-1}[/tex]

[tex]a_4 = a^2_3[/tex]

[tex]a_4 = 16^2[/tex]

[tex]a_4 = 256[/tex]

n =5

[tex]a_5 = a^2_{5-1[/tex]

[tex]a_5 = a^2_4[/tex]

[tex]a_5 = 256^2[/tex]

[tex]a_5 = 65536[/tex]

n = 6

[tex]a_6 = a^2_{6-1[/tex]

[tex]a_6 = a^2_{5[/tex]

[tex]a_6 = 65536^2[/tex]

[tex]a_6 = 4294967296[/tex]

[tex]a_1 = 2[/tex]   [tex]a_2 = 4[/tex]   [tex]a_3 = 16[/tex]   [tex]a_4 = 256[/tex]   [tex]a_5 = 65536[/tex]   [tex]a_6 = 4294967296[/tex]

Solving (c):

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] [tex]a_0=1[/tex]  ; ;  [tex]a_1=2[/tex]

[tex]a_1=2[/tex] ---- First term

n = 2

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_2=a_{2-1}+3a_{2-2}[/tex]

[tex]a_2=a_1+3a_0[/tex]

Substitute values for a1 and a0

[tex]a_2=2+3 * 1[/tex]

[tex]a_2=2+3[/tex]

[tex]a_2=5[/tex]

n = 3

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_3=a_{3-1}+3a_{3-2}[/tex]

[tex]a_3=a_{2}+3a_{1}[/tex]

[tex]a_3=5+3 * 2[/tex]

[tex]a_3=5+6[/tex]

[tex]a_3=11[/tex]

n = 4

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_4=a_{4-1}+3a_{4-2}[/tex]

[tex]a_4=a_{3}+3a_{2}[/tex]

[tex]a_4=11+3 * 5[/tex]

[tex]a_4=11+15[/tex]

[tex]a_4=26[/tex]

n = 5

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_5=a_{5-1}+3a_{5-2};[/tex]

[tex]a_5=a_{4}+3a_3[/tex]

[tex]a_5=26+3 * 11[/tex]

[tex]a_5=26+33[/tex]

[tex]a_5=59[/tex]

n = 6

[tex]a_n=a_{n-1}+3a_{n-2};[/tex] becomes

[tex]a_6=a_{6-1}+3a_{6-2}[/tex]

[tex]a_6=a_{5}+3a_4[/tex]

[tex]a_6=59+3*26[/tex]

[tex]a_6=59+78[/tex]

[tex]a_6=137[/tex]

[tex]a_1=2[/tex]   [tex]a_2=5[/tex]   [tex]a_3=11[/tex]   [tex]a_4=26[/tex]   [tex]a_5=59[/tex]   [tex]a_6=137[/tex]

Solving (d):

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex];     [tex]a_0=1[/tex]; [tex]a_1=1[/tex]

[tex]a_1=1[/tex] --- First term

n = 2

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_2=2 * a_{2-1}+2^2a_{2-2}[/tex]

[tex]a_2=2 * a_1+4*a_0[/tex]

[tex]a_2=2 * 1+4*1[/tex]

[tex]a_2=2 +4[/tex]

[tex]a_2=6[/tex]

n = 3

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_3=3 * a_{3-1}+3^2 * a_{3-2}[/tex]

[tex]a_3=3 * a_{2}+9 * a_{1}[/tex]

[tex]a_3=3 * 6+9 * 1[/tex]

[tex]a_3=18+9[/tex]

[tex]a_3=27[/tex]

n = 4

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_4=4*a_{4-1}+4^2*a_{4-2}[/tex]

[tex]a_4=4*a_{3}+16*a_{2}[/tex]

[tex]a_4=4*27+16*6[/tex]

[tex]a_4=204[/tex]

n = 5

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_5=5 * a_{5-1}+5^2 * a_{5-2}[/tex]

[tex]a_5=5 * a_{4}+25 * a_{3}[/tex]

[tex]a_5=5 * 204+25 *27[/tex]

[tex]a_5=1695[/tex]

n = 6

[tex]a_n=na_{n-1}+n^2a_{n-2}[/tex] becomes

[tex]a_6=6 * a_{6-1}+6^2*a_{6-2}[/tex]

[tex]a_6=6 * a_{5}+36*a_{4}[/tex]

[tex]a_6=6 * 1695+36*204[/tex]

[tex]a_6=17514[/tex]

[tex]a_1=1[/tex]   [tex]a_2=6[/tex]   [tex]a_3=27[/tex]   [tex]a_4=204[/tex]   [tex]a_5=1695[/tex]   [tex]a_6=17514[/tex]

Solving (e):

[tex]a_n= a_{n-1}+a_{n-3};\ a_0=1; a_1=2; a_2=0[/tex]

First term: [tex]a_1=2[/tex]

Second Term: [tex]a_2=0[/tex]

n = 3

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_3= a_{3-1}+a_{3-3}[/tex]

[tex]a_3= a_{2}+a_0[/tex]

[tex]a_3= 0+1[/tex]

[tex]a_3= 1[/tex]

n = 4

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_4= a_{4-1}+a_{4-3}[/tex]

[tex]a_4= a_{3}+a_{1}[/tex]

[tex]a_4= 1+2[/tex]

[tex]a_4=3[/tex]

n = 5

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_5= a_{5-1}+a_{5-3}[/tex]

[tex]a_5= a_{4}+a_{2}[/tex]

[tex]a_5= 3 + 0[/tex]

[tex]a_5= 3[/tex]

n = 6

[tex]a_n= a_{n-1}+a_{n-3}[/tex] becomes

[tex]a_6= a_{6-1}+a_{6-3}[/tex]

[tex]a_6= a_{5}+a_{3}[/tex]

[tex]a_6= 3 + 1[/tex]

[tex]a_6= 4[/tex]

[tex]a_1=2[/tex]   [tex]a_2=0[/tex]   [tex]a_3= 1[/tex]   [tex]a_4=3[/tex]   [tex]a_5= 3[/tex]   [tex]a_6= 4[/tex]


Related Questions

Find the deposit required to accumulate $7700 after investing 3 years in an account that pays an APR of 5% compounded quarterly. How much is earned in interest?

Answers

Answer:

The deposit required is $6633.62   and the interest earned is $366.38

Step-by-step explanation:

Compound interest occurs when the interest earned is reinvested rather than paying it out. When it happens interest in the next period is then earned on the principal sum plus previously accumulated interest.

The formula is:

[tex]{\displaystyle A=P\left(1+{\frac {r}{n}}\right)^{nt}}[/tex]

Where:

A = final amount

P = initial principal balance

r = interest rate

n = number of times interest applied per time period

t = number of time periods elapsed

It's given the final amount A=$7700 after t=3 years of investment in an account that pays an APR of r=5%=0.05. Since the interests compound quarterly and there are 4 quarters in a year, then n=4.

To find the principal P, we solve the previous equation for P as follows:

[tex]{\displaystyle P=A\left(1+{\frac {r}{n}}\right)^{-nt}}[/tex]

Substituting:

[tex]{\displaystyle P=7700\left(1+{\frac {0.05}{4}}\right)^{-4\cdot 3}}[/tex]

[tex]{\displaystyle P=7700\left(1+0.0125}\right)^{-12}}[/tex]

P=$6633.62  

The interest earned is:

I = A - P = $7700 - $6633.62 = $366.38

The deposit required is $6633.62   and the interest earned is $366.38

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Answers

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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(group like terms)

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Answers

Answer:

The ratio of their volumes is not the same 4:1, but [tex](4:1)^3[/tex] = 64:1.

Step-by-step explanation:

Measurements in Similar Figures

In similar figures, if the ratio of any of these corresponding lengths is expressed as a:b then the ratio of the other corresponding lengths can also be expressed as a:b.

In similar figures, if the ratio of any of these corresponding lengths is expressed as a:b then the ratio of the areas can be expressed as (a:b)^2 and the ratio of the volumes can be expressed as (a:b)^3.

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Harry earns$12 20 per hour Monday to Friday if he works on a Sunday he owns 1.75 times hourly rate how much will Harry earn if he works for 8 hours on a Sunday

Answers

Answer:

he will make 170.80 that day

Step-by-step explanation:

12.20*1.75*8

Answer:

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Answers

Answer:

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Step-by-step explanation:

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Answers

Answer:

15,17,19

Step-by-step explanation:

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Answer:

Step-by-step explanation:

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Answers

Answer:

1.5

Step-by-step explanation:

i am not certain but this is how I got it

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Answers

Answer is less than or equal to -7 or -5greater than or equal to

PLEASE NEED HELP URGENTLY!


Raul tried to find the midpoint between 5 & 3i and 12 + 7i. Check his work below.

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=2+19i

so the midpoint is 1+ 19over2 i

What mistake did Raul make?


AHe subtracted the values instead of adding them.


BHe did not add the corresponding parts of the complex numbers.


CHe found the sum instead of the average because he forgot to divide by two.


DHe added the numbers in the wrong order.

Answers

Answer:

B.He did not add the corresponding parts of the complex numbers.

Step-by-step explanation:

A mid point is a point that is of equal distance to two reference points.

Given: Find the midpoint of 5+(-3)i and 12+7i.

These expressions have two parts: the value and complex number parts.

Thus the addition ought to have been;

 (5+(-3i)) + (12+7i) = (5 - 3i) + (12 + 7i)

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                            = 17 + 4i

The midpoint can be determined as:

                        [tex]\frac{(17 +4i)}{2}[/tex]

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Step-by-step explanation:

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Answers

Answer:

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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Answers

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Step-by-step explanation:

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Answers

Answer: b=6

Step-by-step explanation:

I hope this helps on edge

To make the system have an infinite number of solutions, the value of b can be any real number.

What is a solution?

Solutions are the values of an equation where the values are substituted in the variables of the equation and make the equality in the equation true.

We also find the solution in a system of equations using the substitution or elimination method.

Example:

2x + 4 = 8

The solution is x = 2.

We have,

For the system to have an infinite number of solutions, the two equations must be dependent, which means that one of the equations can be obtained by a linear combination of the other two equations.

So,

Let's rearrange the given equations into the slope-intercept form:

y = 6x - b _____(1)

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-3x + y = -3 ______(3)

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We can see that equation (1) is a multiple of equation (4) with a slope of 6/3 = 2.

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So,

2(3x - 3) - b = 6x - b

Simplifying this expression.

6x - b = 6x - b

Since this equation is true for any value of x and b, we have an infinite number of solutions.

Therefore,

To make the system have an infinite number of solutions, the value of b can be any real number.

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What is the equation of the line that passes through the points (3,6) and (-4,-8)

Answers

Hi

You have two points     A ( X;Y)  and B ( X ; Y)

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                     ( -8 - 6 ) / ( -4 - 3) =   -14 /-7 =  2

slope is   2  

now :  we have  :  2 ( 3) +...  = 6

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A company that makes​ hair-care products had 4,000 people try a new shampoo. Of the 4,000 ​people, 24 had a mild allergic reaction. What percent of the people had a mild allergic​ reaction?

Answers

The answer is 0.7%

Hope this helped!

Answer:

0.6%

Step-by-step explanation:

Percentage = 24/4000 *100

=0.6%

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Answers

Answer:

4

Step-by-step explanation:

Slope is [tex]\frac{rise}{run}[/tex]. Or, in other words the distance it travels in the y direction divided by the distance it travels in the x direction. Each time the y variable increments +4 and the x variable increments +1. Which means the line rises 4 units every time it runs 1 unit.

Slope=[tex]\frac{rise}{run}=\frac{4}{1}=4[/tex]

40 percent of the people in the club are new this year if there are 12 be people how many people are in the club

Answers

30? (so sorry if that’s wrong)

Answer:

The answer is 30

Step-by-step explanation:

12 ÷ 40% = 30

Mrs. Alonza ordered 4 x 10³ markers for her store. How many markers did she order?

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The answer is 4000 hope this helped

What is the area of the right triangle shown below?
1.5
2.5

Answers

Answer:

Hello! The answer is 1.5

The area of the given right-angle triangle will be 1.5 unit².

What is a triangle?

A triangle is a closed, 2-dimensional shape with 3 sides, 3 angles, and 3 vertices.

In a triangle, the sum of all three angles is 180°.

Triangle is a very common figure to deal with our daily life for example in our daily life to measure the height of any tower then there is a huge application of the right angle triangle.

Given the tringle with,

Base =1.5 unit

Hypotaneous = 2.5 unit

By Pythagoras theorem

Perpendicular² = (Hypo² - Base²)

Perpendicular² =  2.5² - 1.5²

Perpendicular = 2 units.

Now the area of the right-angle triangle is

⇒  (1/2) × base × height.

Area = (1/2) × 1.5 × 2 ⇒ 1.5 unit²

Hence the area of the given triangle will be 1.5 unit².

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Devra soled the
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Answers

Answer:

What’s the problem? If you could attach the problem we can help u out!

Step-by-step explanation:

Francesca obtains a loan of $18.965.00. The loan has a simple interest rate of 3%. How much interest will Francesca owe at the end of the first year?

Answers

Answer:

$568.95

Step-by-step explanation:

Given parameters:

Value of loan  = $18965

Interest rate  = 3%

Time  = 1year

Unknown:

Interest = ?

Solution:

The interest on a particular amount is given as:

        I  = [tex]\frac{PRT}{100}[/tex]  

I is the interest

P is the principal

R is the rate

T is the time

       I  = [tex]\frac{18965 x 3 x 1}{100}[/tex]   = $568.95

what is the 50th term of the sequence that begins -4,2,8,14,...?
A. 290
B. 294
C. 296
D. 300​

Answers

Answer:

B

Step-by-step explanation:

I am learning this now and I used the equation I'm learning and I got 294.

Answer:

d

Step-by-step explanation:

d because 50th term is 300....50×6=300 thats the answer

Can someone help me please?

Answers

Answer:

the first one and the last three

Step-by-step explanation:

that should be it.

A, e,d,f........................

the question is the picture​

Answers

Y=Mx+c
C=1
M=3/1
Y=3x+1

helppp me please i’m going to fail

Answers

Multiple the top equation by 2 and rearrange so that -7 is equal to the others.
-10x+2y=-14
-3x-2y=-12
——————-
-13x=-26
Divide both by -13
x=2

Express 8e^i16pie in rectangular, polar and trignometric form?

Answers

Euler's formula immediately gives

[tex]8e^{i\cdot16\pi}=8\cos(16\pi)+8i\sin(16\pi)=8[/tex]

and the equation above lists, from left to right, the polar, trigonometric, and rectangular forms.

Identify the critical t. An independent random sample is selected from an approximately normal population with unknown standard deviation. Find the degrees of freedom and the critical t value t∗t∗ for the given sample size and confidence level. Round critical t values to 3 decimal places.Sample size, n Confidence level Degree of Freedom Critical value, t∗t∗5 90 13 95 22 98 15 99

Answers

Answer and Step-by-step explanation: The critical value for a desired confidence level is the distance where you must go above and below the center of distribution to obtain an area of the desired level.

Each sample has a different degree of freedom and critical value.

To determine critical value:

1) Calculate degree of freedom: df = n - 1

2) Subtract the level per 100%;

3) Divide the result by 2 tails;

4) Use calculator or table to find the critical value t*;

For n = 5 Level = 90%:

df = 4

t = [tex]\frac{1-0.9}{2}[/tex] = 0.05

Using t-table:

t* = 2.132

n = 13 Level = 95%:

df = 12

t = [tex]\frac{1-0.95}{2}[/tex] = 0.025

Then:

t* = 2.160

n = 22 Level = 98%

df = 21

t = [tex]\frac{1-0.98}{2}[/tex] = 0.01

t* = 2.819

n = 15 Level = 99%

df = 14

t = [tex]\frac{1-0.99}{2}[/tex] = 0.005

t* = 2.977

The critical values and degree of freedom are:

sample size          level           df              critical value

     5                      90%           4                   2.132

   13                       95%            12                 2.160

   22                      98%            21                 2.819

   15                       99%            14                 2.977

Justin played video games for the following amount of time this past week 42 mins, 35 mins, 28 mins, 55 mins, and 57 mins what was the median amount of time justin played video games this past week

Answers

Answer:

42 minutes

Step-by-step explanation:

Put all numbers in order then cross out a number from each side until you reach the middle.

28, 35, 42, 55, 57

/ 35, 42, 55 /

/ / 42 / /

Answer:

3 hours and 37 minutes

Step-by-step explanation:

42+35+28+55+57=217

217/60=3.61666.....

217-60-60-60=37

Mr. Chavez has assets of $250,000 and liabilities of $18,000. He decides to finance the entire amount of the purchase of a car valued at $26,000. Which of the following is true? a. Mr. Chavez increased his assets. b. Mr. Chavez increased his net worth. c. Mr. Chavez increased both his assets and net worth. d. Mr. Chavez did not increase his assets or his net worth. Please select the best answer from the choices provided A B C D

Answers

Answer:

C.

Step-by-step explanation:

Answer: C. Mr Chavez increased both his assets and net worth

Step-by-step explanation: edgenu 2021

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