Find the equation of line b described below, in slope-intercept form

Line a is perpendicular to line b
Line a passes through the points (1,-8) and (9,-12)
Line b passes through the point (-8, -16)
The equation of line b is y= ______

Given:

Line a is perpendicular to line b .

Line a passes through the points (1,-8) and (9,-12) .

Line b passes through the point (-8, -16).

To find:

The equation of b.

Solution:

Line a passes through the points (1,-8) and (9,-12) . So, slope of line a is

[tex]m=\dfrac{y_2-y_1}{x_2-x_1}[/tex]

[tex]m_a=\dfrac{-12-(-8)}{9-1}[/tex]

[tex]m_a=\dfrac{-12+8}{8}[/tex]

[tex]m_a=\dfrac{-4}{8}[/tex]

[tex]m_a=-\dfrac{1}{2}[/tex]

Product of slopes of two perpendicular lines is -1.

[tex]m_a\times a_b=-1[/tex]

[tex]-\dfrac{1}{2}\times a_b=-1[/tex]

[tex]b=2[/tex]

Slope of line b is 2.

If a line passing through a point [tex](x_1,y_1)[/tex] with slope m, then equation of line is

[tex]y-y_1=m(x-x_1)[/tex]

Line b passing through (-8,-16) with slope 2. So, equation of line b is

[tex]y-(-16)=2(x-(-8))[/tex]

[tex]y+16=2(x+8)[/tex]

[tex]y+16=2x+16[/tex]

Subtract 16  from both sides.

[tex]y=2x[/tex]

Therefore, the equation of line b is [tex]y=2x[/tex].

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