The critical values for the following sample are ±2.0064.
Here it is given that α = 0.05,
To calculate the critical values we will use the t-statistic.
Here n₁ = 25 and n₂ = 30
Hence, the degrees of freedom
d.f = n₁ + n₂ - 2 [Since it's a 2-sample test]
= 25 + 30 - 2
= 53
Now our significance level is α = 0.05,
To know the critical value we will make use of a t-distribution table and look up the value corresponding to a 0.05 significance level and 53 degrees of freedom.
Here we will get the critical values ±2.0064
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*for the `babies` (**usingr**) data set, the variable `age` contains the recorded mom's age and `dage` contains the dad's age for several cases in the sample. do a significance test of the null hypothesis of equal ages against a one-sided alternative that the dads are older in the sampled population\.\*
On solving the provided question we can say that - mean of x mean of y
27.37136 30.73706
what is alternative hypothesis?
In statistical inference studies, an alternative hypothesis is a statement. This is represented by Ha or H1, which conflicts with the null hypothesis. It only serves as a zero replacement. The claims that researchers are investigating in hypothesis testing are alternative theories.
[tex]t = -11.067, \\df = 2301.5, \\p-value < 2.2e-16[/tex]
alternative hypothesis: true difference in means is less than 0
95 percent confidence interval:
[tex]-Inf -2.865266[/tex]
sample estimates:
mean of x mean of y
27.37136 30.73706
Conclusion:-
Here   p-value = 2.2e-16 < 0.05(Level of significance)
Therefore we reject at 5% Loss
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In order to understand the relation between smoking and hypertension (HT), a tea of researchers designed a study that looks at the numbers of smokers and nonsmokers with no HT, pre-HT, stage 1 HT, and stage 2 HT. Which one of the following statements is correct? a. A chi-square test of independence should be run for the study, because the outcome smoker vs. nonsmoker-is a continuous variable, and the grouping variable-no HT, pre-HT stage 1 HT, and stage 2 HT-categorizes the sample into four independent groups. b. A chi-square test of independence should be run for the study, because the outcome smoker vs. nonsmoker-is a dichotomous variable, and the grouping variable-no HT, pre-H stage 1 HT, and stage 2 HT-categorizes the sample into four independent groups. c. An independent samples t test should be run for the study, because the outcome-smoker vs. nonsmoker-is a categorical variable, and the grouping variable no HT, pre-HT, stage 1 HT, and stage 2 HT-categorizes the sample into four independent groups. d. An independent samples t test should be run for the study, because the outcome-smoker vs. nonsmoker-is a continuous variable, and the grouping variable no HT, pre-HT, stage 1 HT, and stage 2 HT-categorizes the sample into matched (or dependent) groups.
Correct option is C
In order to understand the relation between smoking and hypertension (HT) a tea of researchers designed a study that looks at the numbers of smokers and nonsmokers with no HT, pre-HT, stage 1 HT, and stage 2 HT.
An independent samples t test should be run for the study because the outcome smoker vs nonsmoker is a categorical variable and the grouping variable no HT, pre-HT, stage 1 HT, and stage 2 HT-categorizes the sample into four independent groups.
Variables
In Maths, a variable is an alphabet or term that represents an unknown number or unknown value or unknown quantity. The variables are specially used in the case of algebraic expression or algebra. For example, x+9=4 is a linear equation where x is a variable, where 9 and 4 are constants.
Probability
Probability is simply likely something is to happen. Whenever unsure about the outcome of an event, we can talk about the probabilities of certain outcome. The analysis of events governed by probability is called statistics.
Correct option is C
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the scientist creates an equation that models her data for each tree so that she can predict the diameter in the future. complete a linear equations that fits the data for tree 1, where x is the year and y is the trunk diameter, in inches. click on the variables and number you want to select and drag them into the boxes.
The linear equation obtained is y = 0.3X + 18.3
What is linear equation?A linear equation is an equation that can be written in the form ax + b = 0, where a and b are real numbers and x represents an unknown variable. The solutions of linear equations are often graphed on a coordinate plane, forming a straight line. Linear equations can be used to model many real-world situations, such as population growth, the rate of change of a physical quantity, or the total cost of an item. Linear equations can also be used to solve systems of equations, where several equations must be solved simultaneously.
Given that data :
x = year ;
y = trunk diameter, in inches
Year ________trunk diameter
1 __ 18.6
3 __ 19.2
5 __ 19.8
7 __ 20.4
9 ___21.0
11 __ 21.6
13 __ 22.2
Using the linear regression calculator :
The linear equation obtained is :
y = 0.3X + 18.3
Where ;
Slope = 0.3 ; intercept, c = 18.3
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Find the area of this triangle. Round to the nearest tenth. PLEASE HELP
Answer:
74.8 m²
Step-by-step explanation:
[tex]\boxed{\begin{minipage}{7.6 cm}\underline{Area of a triangle} \\\\$A=\dfrac{1}{2}ab \sin C$\\\\where:\\ \phantom{ww}$\bullet$ $C$ is the angle. \\ \phantom{ww}$\bullet$ $a$ and $b$ are the sides enclosing the angle. \\\end{minipage}}[/tex]
From inspection of the given triangle:
C = 115°a = 11 mb = 15 mSubstitute the values into the formula and solve for area:
[tex]\implies A=\dfrac{1}{2} \cdot 11 \cdot 15 \cdot \sin 115^{\circ}[/tex]
[tex]\implies A=\dfrac{165}{2} \sin 115^{\circ}[/tex]
[tex]\implies A=74.77039243[/tex]
[tex]\implies A=74.8\; \sf m^2\;(nearest\;tenth)[/tex]
Therefore, the area of the triangle is 74.8 m² rounded to the nearest tenth.
form differential equations for all circles in the xy plane
The differential equation that can represent all circles in the xy plane is given as follows:
[tex]\frac{dy}{dx} = -\frac{x - h}{\sqrt{r^2 - (x - h)^2}}[/tex]
How to obtain the differential equations for a circle?The equation of a circle of center (h,k) and radius r is given as follows:
(x - h)² + (y - k)² = r².
The equation can be arranged to isolate the variable y as follows:
(y - k)² = r² - (x - h)²
y - k = square root (r² - (x - h)²)
y = square root (r² - (x - h)²) + k
To obtain the differential equation, then this equation must be differentiated towards variable x as follows:
[tex]\frac{dy}{dx} = \frac{d}{dx}(\sqrt{r^2 - (x - h)^2} + k)[/tex]
Applying the chain rule, along with the derivative for the square root, we have that:
[tex]\frac{d}{dx}(\sqrt{r^2 - (x - h)^2} + k) = -\frac{x - h}{\sqrt{r^2 - (x - h)^2}}[/tex]
Meaning that the differential equation is given as follows:
[tex]\frac{dy}{dx} = -\frac{x - h}{\sqrt{r^2 - (x - h)^2}}[/tex]
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A. You need to buy 3eggs cost 8.00, 2 hotdogs cost 10.00 and 3bread cost 5.00 each. How much money you will need to take to the sari-sari store B. Evaluate the following polynomial 4x² + 2x - 3
(i need a reaal math genius please solve it with the right answer and right solving please i'm begging you
when:
1.) x=1
2.) x=2
3.) x=3
4.) x=5
5.) x=6
Amount of money needed to carry to the sari sari store is 59.
a) According to question
Amount of eggs to buy = 3
Rate of eggs = 8
Total amount for eggs = 3x8=24
Amount of hotdogs to buy = 2
Rate of hotdogs = 10
Total amount to pay for hotdogs = 2x10=20
Amount of bread to buy = 3
Rate of bread = 5
Total amount to pay for bread=3x5=15
So money needed to take to the sari sari store=24+20+15=59
b) Polynomial is 4x²+2x-3
1) x=1
4(1)²+2(1)-3
4+2-3
3
2) x=2
4(2)²+2(2)-3
4(4)+4-3
16+4-3
17
3) x=3
4(3)²+2(3)-3
4(9)+6-3
36+6-3
39
4) x=5
4(5)²+2(5)-3
4(25)+10-3
100+10-3
107
5) x=6
4(6)²+2(6)-3
4(36)+12-3
144+12-3
153
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What are the vertex and range of y = |2x + 6| + 2? 1 (0, 2); 2 < y < ∞ 2 (0, 2); −∞ ≤ y < ∞ 3 (−3, 2); 2 < y < ∞ 4 (−3, 2); −∞ ≤ y < ∞
Answer:
(−3, 2); 2 < y < ∞
Step-by-step explanation:
It's either (−3, 2); 2 < y < ∞ or (−3, 2); −∞ ≤ y < ∞ but I'm pretty sure its (−3, 2); 2 < y < ∞
enter the number to complete the linear combination.after substitution:gcd(85, 51) yields sequence: 85 51 34 17 0
The Greatest Common Divisor (GCD) of 85 and 51 is 17.
Greatest Common Divisor(GCD)The greatest common factor that divides two or more numbers is known as the greatest common divisor (GCD). The highest common factor is another name for it (HCF).
Explanation
Step 1: Divide 85 by 51. The quotient is 1 and the remainder is 34.
Step 2: Divide 51 by 34. The quotient is 1 and the remainder is 17.
Step 3: Divide 34 by 17. The quotient is 2 and the remainder is 0.
Step 4: Since the remainder is 0, the Greatest Common Divisor (GCD) of 85 and 51 is 17.
The GCD of 85 and 51 is 17.
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a survey was conducted with a large group of teenagers from 6 different states and it asked them for their favourite sport out of a large list of sports. the study aims to look at whether a teenager's state of residence is associated with their sporting preferences. assume that p is the proportion of teenagers who selected the sport most preferred in their state of residence, such that p1 is that for state 1, p2 is that for state 2 and so on. select from the following all statements that are true as well as the hypothesis that corresponds to this study:
The true statements are as follows
This is a chi-square test for association
The null and alternative hypothesis is
The null hypothesis is that here is no association between state and sporting preference.
The alternative hypothesis is that there is an association between state and sporting preference.
as given in the question
a survey was conducted with large group of teenagers from
6 different states.
let the portion of teenagers who selected the sports most preferred as (p)
(p1) as the the teenagers that for state 1
(p2) as for the teenagers that for state 2
(p3) as for the teenagers that for state 3
(p4) as for the teenagers that for state 4
(p5) as for the teenagers that for state 5
(p6) as for the teenagers that for stage 6
the formula of chi-square test is
[tex]\chi^2=\sum\frac{(O_i-E_i)^2}{E_i}[/tex]
where
[tex]O_i[/tex] is the observed value
[tex]E_i[/tex] is the expected value
[tex]\chi^2[/tex] is chi squared value
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Note:
The full question is
A survey was conducted with a large group of teenagers from 6 different states and it asked them for their favorite sport out of a large list of sports. The study aims to look at whether a teenager's state of residence is associated with their sporting preferences.
Assume that p is the proportion of teenagers who selected the sport most preferred in their state of residence, such that p1 is that for State 1 , p2 is that for State 2 and so on.
Select from the following all statements that are true as well as the hypothesis that corresponds to this study:
[tex]This\ is\ a\ chi-square test for association.& \mathrm{H}_0: \mathrm{p}_1 \neq \mathrm{p}_2 \neq \ldots \neq \mathrm{p}_6 \\& \mathrm{H}_{\mathrm{a}}: \mathrm{p}_1 \neq \mathrm{p}_2 \neq \ldots \neq \mathrm{p}_6 \\& \mathrm{H}_0: \mathrm{p}_1=\mathrm{p}_2=\ldots=\mathrm{p}_6$\mathrm{H}_0$ : There is no association between state and sporting preference. $\mathrm{H}_{\mathrm{a}}$ : There is an association between state and sporting preference. This is a one-way ANOVA test for equality of means.[/tex]
[tex]$\mathrm{H}_0$ : There is an association between state and sporting preference.$\mathrm{H}_{\mathrm{a}}: \mathrm{p}_1=\mathrm{p}_2=\ldots=\mathrm{p}_6$$\mathrm{H}_{\mathrm{a}}$ : There is no association between state and sporting preference.[/tex]
this isn’t mine but can someone correct this if it’s wrong right quick?
Answer:
That looks correct to me!
decide, without calculation, if each of the integrals below are positive, negative, or zero. let d be the region inside the unit circle centered at the origin. let t, b, r, and l denote the regions enclosed by the top half, the bottom half, the right half, and the left half of unit circle, respectively. positive 1. positive 2. negative 3. negative 4. zero 5.
The region inside the unit circle centered at the origin is 1. positive 2. positive 3. positive 4. positive 5. negative
Without calculation we need to state if the each of the integrals below are positive, negative, or zero. let d be the region inside the unit circle centered at the origin
xeˣ is positive for positive , and negative for negative , but the exponential factor makes the positive part dominating, so that the integral over D is positive overall.
The integrals over B and T are identical by symmetry, and both are equal to half the value of the integral over D, so they are both positive as well.
The integral over L is negative because it takes strictly non-positive values of x .
Similarly, the integral over R is positive because it considers non-negative values of x.
Therefore, the region inside the unit circle centered at the origin is 1. positive 2. positive 3. positive 4. positive 5. negative
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Why is [sin(2x)] / sin(x) = 2cos(x)?
Given m = 2 and the point (6, 8), what is the point-slope form of the equation?
Answer:
y - 8 = 2 (x - 6)
Step-by-step explanation:
The point-slope equation is ...
y - y1 = m ( x - x1 )
In the coordinate (6,8)
x = 6 and y = 8
m = 2
Plug in values to find the point-slope form
y - 8 = 2 (x - 6)
We are done!
To kick off the summer, Leah is planning a "School's Out!" party for all her friends. She and
her mom pick up a giant sub and a vat of root beer from Subs & Suds. When they get to the
park, they cut the sub into 18 equal sections. Each section is 1/3
of a foot long.
Which equation can you use to find the length g of the giant sub?
Answer:
g = 18(1/3)
Step-by-step explanation:
The sub is made of 18 sections of 1/3, so it is 18(1/3) feet long (or 6ft when simplified)
2, 7, 4, 2, 3, 6, 11
MEAN:
MEDIAN:
MODE:
RANGE:
answer: Mean:5
median:4
range: 9
mode: 2
Step-by-step explanation:
After I ate some pizza, there was 5/8 of the original pizza still left. My son at 1/3 of that. What fraction of the original pizza did he eat?
Answer:1/4 (I think)
pecan theatre inc. owns and operates movie theaters throughout florida and georgia. pecan theatre has declared the following annual dividends over a six-year period: year 1, $80,000; year 2, $90,000; year 3, $150,000; year 4, $150,000; year 5, $160,000; and year 6, $180,000. during the entire period ended december 31 of each year, the outstanding stock of the company was composed of 250,000 shares of cumulative, preferred 2% stock, $20 par, and 500,000 shares of common stock, $15 par
Preferred shares = 0.40/25.00 = 1.60%
Common shares = 0.07/17.50 = 0.40%
What is stock market?
The phrase "stock market" describes a number of marketplaces where shares of publicly traded firms can be purchased and sold. Such financial transactions take place on official exchanges and in over-the-counter (OTC) markets that adhere to a predetermined set of rules.
Year Total Preference Common Dividend per
dividend dividend dividend common share
1 80000 80000 0 0.32 0.00
2 90000 90000 0 0.36 0.00
3 150000 130000 20000 0.52 0.04
4 150000 100000 50000 0.40 0.10
5 160000 100000 60000 0.40 0.12
6 180000 100000 80000 0.40 0.16
Note: 2.40 0.42
Preference dividend per year = 250000*$20*2%= 100000
Preference dividend for the 3rd year includes arrear dividend of $20000 for the 1st year
and $10000 for the second year, in addition to the $100000 dividend of that year.
Average annual dividend per share:
Preferred shares = 2.40/6 = $0.40
Common shares = 0.42/6 = $0.07
Average annual percentage return:
Preferred shares = 0.40/25.00 = 1.60%
Common shares = 0.07/17.50 = 0.40%
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a survey of 800 randomly selected adults in a certain country found that 82% believed that protecting the right of those with unpopular views is a very important component of a strong democracy. verify the central limit theorem conditions
On solving the question - At α = 0.05, two tailed critical value, Lower Bound =[tex]0.757[/tex], Upper Bound = 0.803, (0.757, 0.803)
What is 95% Confidence interval?An estimation range for an unknowable parameter is referred to as a confidence interval in frequentist statistics. The most popular confidence level is 95%, however other levels, such 90% or 99%, are occasionally used for computing confidence intervals. A constant that indicates the intended degree of significance based on the normal distribution is multiplied by the standard error once it has been calculated to get the confidence interval. Intervals with 95% certainty have a constant value of 1.96.
The number of people in the sample that felt protecting the rights of those with unpopular views is a very important component of a strong democracy is 1200*.78 = 936
Yes, the sample size is large enough, since the expected number of successes is 936, and the expected number of failures is 1200-936= 264, both of which are greater than or equal to 10.
95% Confidence interval :
At α = 0.05, two tailed critical value
Lower Bound =[tex]0.757[/tex]
Upper Bound = 0.803
(0.757, 0.803)
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Messages arrive to a computer server according to a Poisson distributionwith a mean rate of 17 per hour. Determine the length of an interval oftime such that the probability that no messages arrive during this intervalis 0.94.
The length of an interval of time such that the probability that no messages arrive during this interval is 0.94 is 56.88 seconds.
We have to find the length of the time interval that the probability of no messages arrive during this interval is 0.94
Let X be the no.of messages arrive to the server
X follows the poisson distribution with mean λ = 17
Let t be the time interval
The probability of no messages arrive during this interval is 0.94
Then P(0) = 0.94
e⁻⁽λt⁾ = 0.94
λt = ln0.94
17 t = ln(0.94)
t = ln(0.94)/17
t = 0.026872 / 17 hrs
t = 0.0158
Convert 0.0158 hours to seconds
That is t=0.0158(60)(60)
=56.88seconds
Hence in 56.88 seconds the time interval that the probability of no messages arrive during this interval is 0.94 .
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[tex]2 \frac{3}{5} \div 5\frac{3}{8} [/tex]
in its simplest form:?
The expression 2 3/5 ÷ 5 3/8 given is written in simplest form as 104/215
How to write the expression in simplest formThe problem is a division problem in mixed numbers
converting to improper fractions we have
= 2 3/5 ÷ 5 3/8
= 13/5 ÷ 43/8
inverting the divisor to change to multiplication
= 13/5 ÷ 43/8
= 13/5 * 8/43
= 104/215
The division problem is simplest form give 104/215
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Find the solution to the system by elimination:
3x - 5y = 8
2x+ 3y = -1
Answer: x = 1, y = -1
Step-by-step explanation:
To solve this system by elimination, we will set it up so both of the y, or x, variables have opposite coefficients.
3x - 5y = 8
2x+ 3y = -1
3(3x - 5y = 8)
5(2x+ 3y = -1)
9x - 15y = 24
10x + 15y = -5
The 15y and -15y cancel each other out, so we're left with 9x + 10x on the left side and 24 - 5 on the right side of the equation.
19x = 19
x = 19/19
x = 1
Now, we will plug this back into one of the equations to solve for y.
3x - 5y = 8
3(1) - 5y = 8
3 - 5y = 8
-5y = 5
y = -1
What do I have to fill out in the blanks?
Opposite sides of a parallelogram are equal.
Opposite sides of a parallelogram are equal in the second case
RT is congruent to RT is obvious.
ΔRST and ΔRUT are congruent because a diagonal of a parallelogram divides it into two congruent triangles.
We know pair of interior alternate angles are equal.
What is congruency?We know two similar planer figures are congruent when we have sides or angles or both that are the same as the corresponding sides or angles or both.
Given, Line segment TU is congruent to line segment RS because in a parallelogram opposite are equal same reason for line segment RU and ST.
We also know that the diagonal of a parallelogram divides the parallelogram into two equal triangles hence ΔRST and ΔRUT are congruent.
We also know that the pair of alternating angles are equal hence,
∠RST and ∠TRU are congruent.
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8.) Graph f(x)=-x-3
a.) Evaluate f(-4).
b.) Evaluate f(5).
c.) Evaluate f(0).
d.) Circle any ordered pairs that are included in the function:
(-3,0) (-10,7) (13,10)
From the the graph f(x) = -x-3
Part a
The value of f(-4) = 1
Part b
The value of f(5) = -8
Part c
The value of f(0) = -3
The function is given that
f(x) = -x-3
The function is the mathematical statement that shows the relationship between the independent variable and dependent variable. The function consist of the different variables, numbers and mathematical operator.
The function is
f(x) = -x - 3
Part a
The value of f(-4)
Substitute the value of x in the function
f(-4) = - (-4) - 3
= 4 - 3
= 1
Part b
The value of f(5)
f(5) = -5 - 3
= -8
Part c
The value of f(0)
f(0) = -0 - 3
= -3
Therefore, the value of f(-4), f(5) and f(0) are 1, -8 and -3 respectively
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5. Identify the construction that the figure represents.
congruent segments
perpendicular bisector
congruent angles
angle bisector
The construction that the figure represents is perpendicular bisector
What is perpendicular bisector?A perpendicular bisector is a line that cuts through the intersection of two other line segments at a right angle.
So, a perpendicular bisector always splits a line segment through its middle, as we can see. By definition, the word "bisect" denotes an even or uniform division.
Perpendicular Bisector Properties for AB in the figure
It cuts AB in half, or into two equal halves.
It is perpendicular to AB or at right angles to it.
The distance between each point along the perpendicular bisector from points A and B is equal.
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Solve the equation. *Will give Branliest!*
-1/6x-5=2/3x
Answer:
[tex]x=-6[/tex]
Step-by-step explanation:
Solve for x.
Combine [tex]x[/tex] and [tex]\frac{1}{6}[/tex].
Combine [tex]x[/tex] and [tex]\frac{2}{3}[/tex].
[tex]-\frac{x}{6} -5=\frac{2x}{3}[/tex]
Move all terms containing x to the left side of the equation.
Subtract [tex]\frac{2x}{3}[/tex] from both sides of the equation.
[tex]-\frac{x}{6} -5-\frac{2x}{3}=0[/tex]
To write [tex]-\frac{2x}{3}[/tex] as a fraction with a common denominator, multiply by [tex]\frac{2}{2}[/tex].
[tex]-\frac{x}{6}-\frac{2x}{3}*\frac{2}{2}-5 =0[/tex]
Write each expression with a common denominator of 6, by multiplying each by an appropriate factor of 1.
[tex]-\frac{x}{6}-\frac{2x*2}{6}-5 =0[/tex]
Combine the numerators over the common denominator.
[tex]\frac{-x-2x*2}{6}-5 =0[/tex]
Simplify the numerator.
Factor [tex]x[/tex] out of [tex]-x-2x*2[/tex].
[tex]\frac{x(-1-2*2)}{6}-5 =0[/tex]
[tex]\frac{x(-1-4)}{6}-5 =0[/tex]
[tex]\frac{x*-5}{6}-5 =0[/tex]
Move the negative in front of the fraction.
[tex]-\frac{5x}{6} -5=0[/tex]
Add 5 to both sides of the equation.
[tex]-\frac{5x}{6}=5[/tex]
Multiply both sides of the equation by [tex]-\frac{6}{5}[/tex].
[tex]-\frac{6}{5}(-\frac{5x}{6})=-\frac{6}{5}*5[/tex]
Simplify the left side by cancelling the common factors of 5 and 6.
[tex]x=-\frac{6}{5} *5[/tex]
Move the leading negative in [tex]-\frac{6}{5}[/tex] into the numerator.
[tex]x=\frac{-6}{5} *5[/tex]
Cancel the common factor of 5.
[tex]x=-6[/tex]
A rating/review would be much appreciated. Wish you a happy holiday season!
Answer:
x = - 6---------------------------------
Given equation:
-1/6x - 5 = 2/3xFist, multiply both sides by 6 to clear the fraction:
6(-1/6)x - 6(5) = 6(2/3)x- x - 30 = 4xCollect the terms with the variable and solve for x:
4x + x = - 305x = - 30x = - 30/5x = - 6brainliest for first right answer in minutes 40 points I swear
The value of the missing angle of the triangle is; x = 31°
What is the missing angle of the triangle?Alternate angle theorem states that when two parallel lines are cut by a transversal, then the resulting alternate interior angles or alternate exterior angles are congruent.
Now, from the diagram, we can tell that ∠GAB is congruent to ∠CBA by alternate angles theorem.
Thus, ∠GAB = 28°
Similarly, sum of angles on a straight line = 180°. Thus;
∠EDA = 180 - (4x + x)
∠EDA = 180 - 5x
Also, sum of angles in a triangle is 180 degrees. Thus;
∠CAB = 180 - (90 + 28)
∠CAB = 62°
Thus;
62 + 3x + 180 - 5x = 180
62 - 2x = 0
2x = 62
x = 62/2
x = 31°
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Consider the experiment of rolling a pair of fair dice until a sum of 7 is obtained. Let X denote the number of trials needed to obtain a sum of 7.
a) Notice that X is discrete. What is the distribution of X?
b)What is the theoretical average value (mu) of X?
c)What is the theoretical variance of X?
d) Consider the random variable Y, the average number of trials needed to roll a sum of 7 based on 25 trials. What is E[Y] and Var (Y)?
a) The distribution of X is a discrete geometric distribution with pmf p(x) = (5/36)(1/6)^(x-1).b) The theoretical mean (mu) of X is 6.c) The theoretical variance of X is 35.d) The expected value of Y is 6 and the variance of Y is 3.875.
The distribution of X is a discrete geometric distribution, which means that the probability of X taking on any particular value is given by the formula p(x) = (5/36)(1/6)^(x-1). The theoretical mean (mu) of X is 6, which means that on average it should take 6 trials to obtain a sum of 7. The theoretical variance of X is 35, which means that there is a considerable amount of variability in the number of trials needed to obtain a sum of 7. If we consider the random variable Y, the average number of trials needed to roll a sum of 7 based on 25 trials, then the expected value of Y is 6 and the variance of Y is 3.875. This indicates that the average number of trials needed to obtain a sum of 7 is 6 and that the variability decreases as more trials are taken.
a) p(x) = (5/36)(1/6)^(x-1)
b) theoretical mean (mu) of X mu = 6
c) Var(X) = (5/36)*∑x=1∞(1/6)^(x-1)^2 - mu^2
= (5/36)*(1-1/36^2) - 6^2
= 35
d) The expected value of Y , E(Y) = 6
Var(Y) = Var(X/6)
= Var(X)/6^2
= 35/6^2
= 3.875
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Given that lines PQ and RS are parallel and t is a transversal, use a two column proof to prove <4=<6.
∠4=∠6 because each pair of alternate interior angles is equal ( The two column proof is attached ).
what is the two-column proof?Every two-column proof has exactly two columns. One column represents our statements or conclusions and the other lists our reasons. In other words, the left-hand side represents our “if-then” statements, and the right-hand side explains why we know what we know.
We can clearly observe here that ∠1=∠5 , ∠2=6, ∠3=∠7, ∠4=∠8 as Corresponding angles are equal.
∠4 + ∠3 = 180°……..(1) PQ is the straight line
∠6 + ∠7 = 180°……..(2) t is the straight line
therefore from the two equations we get
∠4 =∠6
Hence, ∠4 ≅∠6 ( The two column proof is attached )
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ASAP HELP QUICK GIVING BRANLIEST!! So confused, solve the inequality and graph the solution -0.7m + 5.6 < 8.4
let x be a continuous random variable. we know that it takes values between 0 and 3, but we do not know its distribution or its mean and variance. we are interested in estimating the mean of x, which we denote by h. we will use 1.5 as a conservative value (upper bound) for the standard deviation of x. to estimate h, we take n i.i.d. samples x1,x2,...,xn, which all have the same distribution as x, and compute the sample mean
The randomized variable's sample distribution would be as follows: H+/- 1.96 * √3)/√n
A random variable in mathematics would be a variable for whom the value is the numerical result of an unpredictable event and a random number generator X on a sample space. S denotes the rule that gives each of the outcomes S in a collection a numerical value.
In this case, we have assumed that x is a constant random variable with values ranging from 0 to 3, but we are unsure of its distribution, mean, or variance.
The mean of x, which we designate by the letter h, is what we're now interested in estimating. To provide a conservative estimate (upper bound), we'll choose 1.5 for the standard deviation of x.
In this case, we must estimate h. To do this, we select the sample size n, the samples x1, x2,.., xn, all of which share the same dissemination as x, and accurately measure the sample mean.
Therefore, we have used a normal distribution to determine the variation of x as (0,6),
And it equals to 3, then apply CLT resulting in
=> H+/- 1.96 * √3)/√n
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