Find the area of the region that is bounded above by the curve f(x)=(x+3)2 and the line g(x)=−x−1 and bounded below by the x-axis.
Answers
By definite integrals, we find that the area of the region bounded by the functions f(x) and g(x) described in the statement is equal to 4.5 units.
How to determine the area of the region bounded by two curvesIn this problem we must determine the area between two functions, a quadratic equation f(x) and a linear equation g(x).
First, we need to determine the limits of the interval of x-values with the help of a graphing tool, represented by the points of intersection of the two functions.
The points of intersection of the two functions are (x₁, y₁) = (- 5, 4) and (x₂, y₂) = (- 2, 1), respectively. Then, the area is defined by the following definite integral:
[tex]I = \int\limits^{-2}_{-5} {[g(x) - f(x)]} \, dx[/tex]
[tex]I = \int\limits^{-2}_{- 5} {[(- x - 1) - (x + 3)^{2}]} \, dx[/tex]
[tex]I = - \frac{1}{2} \cdot [(- 2)^{2} - (- 5)^{2}] - [(- 2) - (- 5)] - (1 / 3) \cdot [(- 2 + 3)^{3} - (- 5 + 3)^{3}][/tex]
I = - (1 / 2) · (4 - 25) - 3 - (1 / 3) · (1 + 8)
I = - (1 / 2) · (- 21) - 3 - (1 / 3) · 9
I = 21 / 2 - 3 - 3
I = 21 / 2 - 6
I = 21 / 2 - 12 / 2
I = 9 / 2
I = 4.5
The area of the region represented by the definite integral introduced above is equal to 4.5 units.
RemarkThe statement leads to a contradiction. Correct form is presented below:
Find the area of the region that is bounded above by the curve f(x) = (x + 3)² and the line g(x) = - x - 1 and bound above the x-axis.
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Related Questions
help pls!! In the figure below, N is between M and O, and O is between N and P. If NO=2, NP = 8, and MP=15, find MO.
Answers
The distance between MO is 9.
How to find MO ?From the question MP is straight line and O & N is points between M & P.
No is 2NP is 8MP is 15so the total length of line is 15
Need to find MO , To find MO = MP - (NP - NO)
= 15 - (8 -2)
= 15 - 6 = 9
The MO is 9.
To find points in graph :
To find a line that's parallel to a line and goes through a particular point, use the point's coordinates for (x1, y1) in point slope form: y - y1 = m (x - x1).The slope intercept formula y = mx + b is used when you know the slope of the line to be examined.Use the slope and one of the points to solve for the y-intercept.One of your points can replace the x and y, and the slope you just calculated replaces the m of your equation y = mx + b. Then b is the only variable left. Use the tools you know for solving for a variable to solve for b.To learn more about finding distance refer :
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In an experiment, college students were given either four quarters or a $1 bill and they could either keep the money or
spend it on gum. The results are summarized in the table. Complete parts (a) through (c) below.
Answers
Using the probability concept, we have that:
a) The probability is of 0.244.
b) The probability is of 0.756.
c) A student given a $1 bill is more likely to have kept the money.
What is a probability?A probability is calculated as the number of desired outcomes in the experiment divided by the number of total outcomes in the experiment.
For item a, we have that out of 11 + 34 = 45 students who were given a $1 bill, 11 spent the money, hence the probability is given as follows:
p = 11/45 = 0.244.
For item b, we have that out of 11 + 34 = 45 students who were given a $1 bill, 34 kept the money, hence the probability is given as follows:
p = 34/45 = 0.756.
For item c, we have that a student given a $1 bill is more likely to have kept the money, as 0.756(kept) > 0.244(spent), which are the two probabilities we found in the previous items.
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Help find X-coordinate
Answers
The value of x coordinate be 0 or -2.
Given,
Vertex of the graph, f(x) = x² + 2x + 2
We have to find the x coordinate.
Here,
f(x) = x² + 2x + 2 is in the form of quadratic equation.
So, we can find x coordinate by using quadratic formula.
Quadratic formula: [tex]\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a}[/tex]
Here,
a = 1, b = 2 and c = 2
So,
[tex]\frac{-b(+-)\sqrt{b^{2}-4ac } }{2a}[/tex]
= [tex]\frac{-2(+-)\sqrt{2^{2}-4(1)(2) } }{2(1)}[/tex]
= [tex]\frac{-2(+-)\sqrt{4-8} }{2}[/tex]
= (-2±(-√4)) ÷ 2
= (-2±(-2)) ÷ 2
Solve for.
-2 + (-2) / 2 = -2 -2 / 2 = -4/2 = -2
Solve for,
-2 - (-2) / 2 = -2 + 2 / 2 = 0
That is,
The value of x coordinate be 0 or -2.
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Solve all
1. (25+5) x3-13
2. 19+12x2-4
3. 42+32+4
4. 12+34x2÷2
5. (4+3) x (2+5)
6. 2+14x5-5
7. 22+4x5-13
8. 13-42+7+2
9. 15+2-14÷7
10. (18-7)x2
Answers
2. 39
3. 78
4. 46
5. 49
6. 67
7. 29
8. -20
9. 15
10. 22
Given mn, find the value of x.
t
(7x-1)⁰
(5X-23)°
Answers
[tex](5x - 23) + (7x - 1) = 180 \\ 5x + 7x - 23 - 1 = 180 \\ 12x - 24 = 180 \\ 12x = 180 + 24 \\ 12x = 204 \\ \frac{12x}{12} = \frac{204}{12} \\ x = 17[/tex]
x=17°
I used the reasons CORRESPONDING ANGLES AND ANGLES ON A STRAIGHT LINE.round to 1,600 to the nearest hundred
Answers
Answer:1,600
Step-by-step explanation:C) If the last two digits are 00, then we do not have to do any rounding, because it is already to the hundred.
you already have the answer :)
find x if AC=15 , AB=x+14 , and BC= x+13
Answers
Given the information, we have the following:
Now, since AC=15, we have the following expression:
[tex]\begin{gathered} AB+BC=AC \\ \Rightarrow(x+14)+(x+13)=15 \end{gathered}[/tex]Solving for x we get:
[tex]\begin{gathered} (x+14)+(x+13)=15 \\ \Rightarrow2x=15-14-13=-12 \\ \Rightarrow2x=-12 \\ \Rightarrow x=\frac{-12}{2}=-6 \\ x=-6 \end{gathered}[/tex]Therefore, x=-6
calculate the complement of a 26° angle.
Answers
In this case, we'll have to carry out several steps to find the solution.
Step 01:
Data
angle = 26 degress
complement angle = ?
Step 02:
26 + x = 90
x = 90 - 26
x = 64
The answer is:
The complement angle is 64 degrees
Write a situation in which positive and negative numbers are used to describe values that have opposite meaning. What does 0 represent in this situation you created? (10 points)
Answers
A situation in which positive and negative numbers are used to describe values that have opposite meaning is that John is on top of a mountain that is 2000 above sea level and his friend is diving and is below 2000 feet.
The thing that 0 represents is the addition in the sea level.
How to illustrate the information?Based on the information illustrated, the situation will be that John is on top of a mountain that is 2000 above sea level and his friend is diving and is below 2000 feet.
Therefore, the addition will be:
= 2000 + (-2000)
= 2000 - 2000
= 0
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1 3/4 x 4 2/6 nnnnnnnnnnn
Answers
The result of the multiplication operation yields 7 7/12
Multiplication of numbersFrom the question, we are to multiply the given fractions. The given fractions are
1 3/4 and 4 2/6
First, we will convert the fractions to improper fractions
Converting 1 3/4 to an improper fraction
1 3/4 = 7/4
Converting 4 2/6 to an improper fraction
4 2/6 = 26/6
Thus,
The multiplication operation becomes
7/4 × 26/6
= 7/4 × 13/3
= 91/12
= 7 7/12
Hence, the product of the given numbers is 7 1/12
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Find the slope of a line containing
P1(3, 7)
and
P2(6, 9).
Answers
The slope of a line containing P1(3, 7) and P2(6, 9) is 2/3.
Slope, also called as gradient of a line is a value or number that describes both of the directions x and y. It basically tells the steepness of the line.
To find the slope of line, formula given below is used
[tex]\frac{y_{2} - y_{1} }{x_{2} -x_{1} }[/tex] = slope
Here, y2 = 9
y1 = 7
x2 = 6
x1 = 3
Thus, 9 - 7/6 - 3
= 2/3
Therefore, we can conclude that the slope of a line containing P1(3, 7) and P2(6, 9) is 2/3.
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write 7843 to nearest thousand with explanations
Answers
Step-by-step explanation:
Because if you round to the nearest thousand 8 is above 5 so you round up making it 8000
8. [-/1 Points]
SPRECALC7 1.7.071.
A pilot flew a jet from City A to City B, a distance of 1600 ml. On the return trip, the average speed was 20% faster than the outbound speed. The round-trip took 8 h 20 min. What was the speed from
City A to City B?
mi/h
DETAILS
MY NOTES
ASK YOUR TEACHER
PRACTICE ANOTHER
Answers
The speed from City A to City B is 352 miles/hour.
What is the relationship between speed, distance, and time?By dividing the distance traveled by the time required to travel it, speed is calculated.Speed is inversely correlated with time and directly correlated with distance. Thus, distance equals speed times time.Distance divided by speed equals time; as speed rises, time goes down, and vice versa.Given:
Distance for trip = 1600 miles
Distance for return trip = 1600 miles
The round-trip took 8 h 20 min.
Total time taken for both trips = 8 hours 20 minutes = 8 + (1/3) hours = 25/3 hours
It is mentioned that on the return trip, the average speed was 20% faster than the outbound speed.
Let's assume x is the speed for an outbound trip.
So, x + 20% of x is the average speed of the return trip
x + 20% of x = x + 0.2x = 1.2x
Speed for the return trip = 1.2x
Total time = (distance/speed of outbound trip) + (distance/speed of return trip)
⇒ [tex]\frac{25}{3} =\frac{1600}{x} +\frac{1600}{1.2x}[/tex]
⇒ [tex]\frac{25x}{3} =\frac{1600*1.2 +1600}{1.2}[/tex]
⇒ [tex]10x = 3520[/tex]
⇒ [tex]x = 352[/tex]
Therefore, the speed from City A to City B is 352 miles/hour.
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Solve I =prt for p when I =5,480,r =.04, and t=7. Round your answers to two decimal pla
Answers
We are asked to find the simple interest associated with a principal of 5480 , an annual rate of 0.04 (4%) and at the end of 7 years:
We use the simple interest formula:
I = P r t
in our case: I = (5480) (0.04) (7) = 1534.4
So the interest is: 1534.40
We answer using two decimal places because this is refering to cents of a dollar.
3. John and Savanah are saving money to go on a trip to Mexico. They need at least $2,545 in order to go. John tutors English and Savanah works as a babysitter to raise money. John charges $15 per hour and Savanah charges $20 per hour. The number of hours that Savanah has scheduled is no more than five times the number of hours John has scheduled. Savanah will babysit at least 40 hours.. Write a set of constraints to model the problem, with x representing the number of hours John tutors and y representing the number of hours Savanah babysits. Answer:
Answers
The group of restrictions used to simulate the issue includes
y<5x andy [tex]\geq[/tex] 40hours How to construct a set of restrictions to represent the issue:The issue includes the following information.
They need a minimum of $2,545 divided by the hours John instructs and the hours Savanah watches children.There is a maximum of a five-fold difference between the number of hours Savanah has booked and that John has.At least 40 hours will be spent watching the children by Savanah.The following are the restrictions for modeling the issue: There is a maximum of a five-fold difference between the number of hours Savanah has booked and that John has.
Savanah will provide childcare for at least 40 hours, with no more than meaning it is not larger than that which suggests it is less than, Hence, y<5x
Meaning "at least 40 hours" is "at least 40 hours." 40 hours or more may be expressed as
y ≥ 40 hours
The two necessary restrictions are represented as y< 5x and y=> 40 hours in an inequality model.
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-8>-3t-10 can someone help
Answers
Answer:
t > -2/3
Step-by-step explanation:
−8>−3t−10
Step 1: Flip the equation.
−3t−10<−8
Step 2: Add 10 to both sides.
−3t−10+10<−8+10
−3t<2
Step 3: Divide both sides by -3.
−3t/−3 < 2/−3
t > −2/3
Write an equation for a parabola with x-intercepts (-3,0) and (4,0) which passes through the point (2,-40)
Answers
The parabolic equation that passes through the points is y = 29/7x^2 + -27/7x - 342/7
What are parabolic equations?Parabolic equations are second-order polynomial equations and they have the form y = ax^2 + bx + c or y = a(x - h)^2 + k
How to determine the equation of the parabola?The given parameters are
x-intercepts (-3,0) and (4,0)
Point = (2,-40)
From the definition above, we have the form to be
y = ax^2 + bx + c
Substitute (-3,0) and (4,0) in the above equation
So, we have
0 = a(-3)^2 + b(-3) + c
0 = a(4)^2 + b(4) + c
This gives
9a -3b + c = 0
16a + 4b + c = 0
Substitute (2,-40) in the above equation y = ax^2 + bx + c
a(2)^2 + b(2) + c = -40
So, we have
4a + 2b + c = -40
The equations become
9a -3b + c = 0
16a + 4b + c = 0
4a + 2b + c = -40
Using a graphing tool, we have
a = 29/7, b = -27/7 and c = -342/7
So, we have
y = ax^2 + bx + c
This gives
y = 29/7x^2 + -27/7x - 342/7
Hence, the equation is y = 29/7x^2 + -27/7x - 342/7
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Find the center, transverse axis, vertices, foci, and asymptotes. Graph the equation.y² -x² =25
What are the asymptotes?
The asymptote with positive slope is, and the asymptote with negative slope is.
Answers
The values are as follows:
center: y²/25-x²/25 = 1
transverse axis : b = 5
Vertices: (0,5) and (0,-5)
Foci: (0,5√2) and (0,-5√2)
Asymptotes: y = x and y = -x
An asymptote is a line being approached by a curve but never touching the curve. i.e., an asymptote is a line to which the graph of a function converges. We usually do not need to draw asymptotes while graphing functions.
Types of Asymptotes:
1) Horizontal asymptote (HA) - It is a horizontal line and hence its equation is of the form y = k.
2) Vertical asymptote (VA) - It is a vertical line and hence its equation is of the form x = k.
3) Slanting asymptote (Oblique asymptote) - It is a slanting line and hence its equation is of the form y = mx + b.
y² -x² =25 up down hyperbola with (h,k) = (0,0) a = 5 and b = 5
(y-k)²/a²-(x-h)²/b² = 1 is the standard equation of up-down hyperbola.
With semi-axis is a and semi-conjugate axis is b.
and centre (h,k).
Center = (y-0)²/5²-(y-0)²/5² = 1
= y²/25-x²/25 = 1
The axes are a = 5 and b = 5
transverse axis is b = 5
The foci are given by (h, k+c) and (h, k-c), where c = √a²+b²
c = √5²+5² = 5√2
therefore, the foci are (0,5√2) and (0,-5√2).
The vertices are (h, k+a) and (h, k-a)
(h,k) = (0,0) and a = 5 and b = 5
vertices are (0,5) and (0,-5)
Asymptotes are y = x and y = -x.
Therefore, the summary is as follows:
center: y²/25-x²/25 = 1
transverse axis : b = 5
Vertices: (0,5) and (0,-5)
Foci: (0,5√2) and (0,-5√2)
Asymptotes: y = x and y = -x
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A kidney stone treatment study found that treatment A had 81 out of 87 successful trials in small stone treatments and 234 out of 270 successful trials in large stone treatments. Treatment B had 234 out of 270 successful trials in small stone treatments and 55 out of 80 trials successful in large stone treatments. Overall which treatment had a better success rate and why? 150 words no copy internet
Answers
Using proportions, it is found that due to the higher proportion of successful trials, Treatment A had the better success rate
What is a proportion?A proportion is a fraction of a total amount, and hence it is represented by the sum of the desired amounts divided by the sum of the total amounts.
For Treatment A, we have that:
There was a total of 87 + 270 = 357 trials.Of those, 81 + 234 = 315 trials were successful.Hence the proportion of successful trials for Treatment A is given by:
315/357 = 0.8824.
For Treatment B, we have that:
There was a total of 80 + 270 = 350 trials.Of those, 55 + 234 = 289 trials were successful.Hence the proportion of successful trials for Treatment B is given by:
289/350 = 0.8257.
The proportion for Treatment A is higher, as 0.8824 > 0.8257, hence it had the better success rate.
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For the function f(x)=4x+4,
find (a) f(x+h),
(b) f(x+h)−f(x), and
(c) f(x+h)−f(x) h.
(a) f(x+h)=?
Answers
Step-by-step explanation:
a)
[tex]f(x+h) = 4(x+h)+4[/tex]
[tex]f(x+h)=4x+4h+4[/tex]
b)
[tex]f(x+h)-f(x)=4x+4h+4-(4x+4)[/tex]
[tex]f(x+h)-f(x)=4x+4h+4-4x-4[/tex]
[tex]f(x+h)-f(x)=4h[/tex]
c)
[tex]f(x+h)-f(x)h=4x+4h+4-h(4x+4)[/tex]
[tex]f(x+h)-f(x)h=4x+4h+4-4hx+4h[/tex]
[tex]f(x+h)-f(x)h=-4hx+8h+4x+4[/tex]
Katie wants to save at least $280 to go on the math team field trip. He currently has $112 saved.
If he has 8 weeks left to save, which inequality and graph represent the amount of money per week he needs to save to meet the goal?
Answers
He must save 21 dollars per week to meet the goal.
How to find the amount to be saved?Given,
Katie wants to save at least $280
He currently has $112 saved.
If he has 8 weeks left to save.
Solution:
The amount to be saved is $280 - $112 = $168
If he has 8 weeks left to save,
Per week he must save = $168/8
= $21
He must save 21 dollars per week to meet the goal.
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Provide the correct reason for the statement in line 4. (please help)
Answers
Answer:
d) division property of =
Step-by-step explanation:
by step 3, the variable x is still being multiplied by 3. In order to isolate x, you must divide by 3 on both sides.
Write the following using algebraic notation, using the letter x for any
unknown numbers:
think of a number, double it, then add fifteen.
Answers
[tex] = x \times 2 + 15 \\ = 2x + 15[/tex]
DOUBLING IT MEANS MULTIPLYING IT BY 2
THEN ADD 15 AS SHOWN ABOVE.
HOPE THIS HELPS
There are 28 students in a class.
16 of the students are girls.
What proportion are boys?
Write your answer in two ways.
Answers
Answer:
3:7
Step-by-step explanation:
Given:
There are 28 students in a class16 of the students are girls.To Find:
What proportion of the students are boys.Formula used:
No. of boys = Total students - No. of girlsUsing the formula, we have
No. of boys = 28 - 16 = 12
Proportion of boys = 12/28 = 3/7
So, proportion of boys = 3:7.
Find the x-intercept of the function g(x)=8x²-10x-3
Answers
To find the x-intercepts of the function g(x), we must set it equal to 0 and solve for x.
We have the following:
[tex]\begin{gathered} g(x)=8x^2-10x-3 \\ if\text{ g(x)=0} \\ \Rightarrow8x^2-10x-3=0 \end{gathered}[/tex]we can use the quadratic formula to get the roots of the polynomial:
[tex]\begin{gathered} a=8 \\ b=-10 \\ c=-3 \\ x_{1,2}=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a} \\ \Rightarrow x_{1,2}=\frac{-(-10)\pm\sqrt[]{(-10)^2-4(8)(-3)}}{2(8)}=\frac{10\pm\sqrt[]{196}}{16} \\ \Rightarrow x_{1.2}=\frac{10\pm14}{16} \\ \Rightarrow x_1=\frac{10+14}{16}=\frac{24}{16}=\frac{3}{4} \\ \Rightarrow x_2=\frac{10-14}{16}=\frac{-4}{16}=-\frac{1}{4} \end{gathered}[/tex]therefore, the x-intercepts of the function g(x) are the points (3/4,0) and (-1/4,0)
If a nonlinear system of equations contains one linear function that touches the quadratic function at its minimum, then the system has which of the following?
A. No solution
B. Infinitely many solutions
C. One solution
D. Two solutions
Answers
Answer:
C. One solution
Step-by-step explanation:
You want to know the number of solutions of a system of equation such that the graph of the linear function touches the graph of the quadratic function at its minimum.
SolutionsThe number of real solutions of the system of equations is equal to the number of points of intersection of their graphs. The problem statement tells you the graphs intersect at one point, so there is one solution.
__
Additional comment
The linear function can only touch the minimum of a quadratic if its graph is a horizontal line.
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By drawing two circles, John got a figure, which consists of three regions(basically a venn diagram). At most how many regions could John get by drawing two squares?
Answers
See explanation:
List the angles of the triangle in order from largest to smallest.Question options:A) ∠A, ∠C, ∠BB) ∠C, ∠B, ∠AC) ∠B, ∠C, ∠AD) ∠A, ∠B, ∠C
Answers
Angles opposite to shorter sides are shorter. Then, the shortest angle is opposed to the shortest side.
Since the shortest side has a length 2.8 and is opposed to the angle A, then the shortes angle is A.
The next shortest side is that opposite to B, which has a length of 3.4.
And finally, the largest side has a length of 4.7 and it's opposite to the angle C.
Therefore, the list of angles from largest to smallest, is:
[tex]\angle C,\angle B,\angle A[/tex]Find the direction angle of v for the following vector.v=−6i−2jWhat is the direction angle of v?
Answers
Given:
v is the given vector.
[tex]v=-6i-2j[/tex]To find:
Find the direction angle of v.
Formula to find the direction:
[tex]\tan \theta=\frac{y}{x}[/tex]From the given vector x and y are:
[tex]x=-6\text{ \& y=-2}[/tex][tex]\begin{gathered} \tan \theta=\frac{-2}{-6} \\ \theta=\tan ^{-1}(\frac{1}{3}) \\ \theta=18.4\degree \end{gathered}[/tex]An actor bought a pearl, diamond, and ruby necklace for his famous wife for $54,000. In 2011 this necklace was auctioned for $11,379,600. The auction price was what percent of the original purchase price?
Answers
This necklace sold at auction for $11,379,600 in 2011. The percentage of the initial purchase price was represented by the auction price is 2.1%.
Given that,
For $54,000, an actor purchased a pearl, diamond, and ruby necklace for his well-known wife. This necklace sold at auction for $11,379,600 in 2011.
We have to find what percentage of the initial purchase price was represented by the auction price.
Let us take the percentage as x%.
Necklace sold at auction=the percentage multiplied by the actual price
We get,
$11,379,600 =x%($54,000)
x%=$11,379,600/$54,000
x%=2.1%
Therefore, the percentage of the initial purchase price was represented by the auction price is 2.1%.
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