Find out the actual instruction given in binary

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Answer 1

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Write a function using a loop to approximate the value of PI using the formula given including terms up through 1/99, 1/999 and 1/9999. As the number of iterations increase, the estimate gets closer to the value of PI. The function should accept the number of iterations and return the estimate of PI.

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Answer:

Following are the code to the given question:

#include <stdio.h>//header file

double estPi(int precision)//defining a method estPi that accepts value in parameter  

{

   double pi = 0, sign = 1, n = 1;//defining a double variable

   while (n <= precision) //use while loop that checks n value less than equal to precision

   {

       pi += sign / n;//defining pi variable that holds quotient value

       sign *= -1;//holding value in sign value

       n += 2;//increment value in n

   }

   return 4 * pi;//return value

}

int main() //main method

{

   int n;//defining an integer variable

   printf("Enter number of iterations: ");//print message

   scanf("%d", &n);//input value

   printf("Estimated PI is %lf\n", estPi(n));//print method that calls method

   return 0;

}

Output:

Please find the attached file.

Explanation:

In the given code a method "estPi" is declared that holds an integer variable "precision" is declared inside the method multiple double variable is declared inside the loop it calculate the value and return its values.

Inside the main method an integer variable "n" is declared that use print method to input the value and accepting value from the user-end and passing value in the method and print its values.

Answer:

Following are the code to the given question:

#include <stdio.h>//header file

double estPi(int precision)//defining a method estPi that accepts value in parameter  

{

  double pi = 0, sign = 1, n = 1;//defining a double variable

  while (n <= precision) //use while loop that checks n value less than equal to precision

  {

      pi += sign / n;//defining pi variable that holds quotient value

      sign *= -1;//holding value in sign value

     n += 2;//increment value in n

}

  return 4 * pi;//return value

}

int main() //main method

{

  int n;//defining an integer variable

  printf("Enter number of iterations: ");//print message

  scanf("%d", &n);//input value

  printf("Estimated PI is %lf\n", estPi(n));//print method that calls method

  return 0;

}

Output:

Please find the attached file.

In the given code a method "estPi" is declared that holds an integer variable "precision" is declared inside the method multiple double variable is declared inside the loop it calculate the value and return its values.

Inside the main method an integer variable "n" is declared that use print method to input the value and accepting value from the user-end and passing value in the method and print its values.

Answer: Following are the code to the given question: #include - 1

Explanation:

what is software? what are two types of software?​

Answers

Software is the programs and other operating information used by a computer. Two types of software are system software and Application software. Hope this helps :)

Answer:

Software is the collection of programs which makes computer work. The two types of software are 1)Application software

2)System software

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