y = 3x
x y
-2 -6
-1 -3
0 0
1 3
y = -2x +11
x. y
-1. 13
0 11
1. 9
2. 7
Can you help please I am struggling thank you
Answer:
m<ADC = 107
Step-by-step explanation:
You need to know three things to solve this problem.
1) Opposite angles of an inscribed quadrilateral are supplementary.
2) The measure of an inscribed angle is half the measure of its subtended arc.
3) The sum of the measures of all the arcs of a circle is 360 deg.
From 1) we get:
m<A + m<C = 180
72 + m<C = 180
m<C = 108
From 2) we get:
m<C = (1/2)m(arc)BAD
108 = (1/2)[m(arc)AB + m(arc)AD]
216 = m(arc)AB + 122
m(arc)AB = 94
From 3) we get:
m(arc)AB + m(arc)BC + m(arc)CD + m(arc)DA = 360
94 + 120 + m(arc)CD + 122 = 360
m(arc)CD = 24
From 2) we get:
m<ADC = (1/2)m(arc)ABC
m<ADC = (1/2)[m(arc)AB + m(arc)BC]
m<ADC = (1/2)[94 + 120]
m<ADC = 107
CAN SOMEONE PLEASE FIND THE VOLUME AND SURFACE AREA OF THIS FIGURE.
and round to the nearest hundredth
Answer:
Volume = 1659.84Surface area = 1205.36Step-by-step explanation:
Volume for triangular prism = 1/2 * b * l * h
we are given the length and the height but not the base.
since it is a right triangle we can use the Pythagorean theorem a^2 + b^2 = c^2
13.3^2 + b^2 = 20.5^2
176.89 + b^2 = 420.25
b^2 = 243.36
b = [tex]\sqrt{243.36}[/tex] = 15.6
1/2 (15.6)(13.3)(16) = 1659.84
Front: 15.6 x 13.3 = 207.48
Back: 15.6 x 13.3 = 207.48
Left: 15.6 x 16 = 249.6
Right: 13.3 x 16 = 212.8
Bottom: 20.5 x 16 = 328
207.48 + 207.48 + 249.6 + 212.8 + 328 = 1205.36
Three-fifths of the students in a room are girls. One-third of the girls have blond hair. One-half of the boys have brown hair. What fraction of all the students are girls with blond hair?
Answer:
1/5
*I'm sorry if I got it wrong, but if not I hope this helps!*
Step-by-step explanation:
since 3/5 of the students are girls, and 1/3 of the girls have blonde hair, to find what fraction of all the girls have blond hair, we would multiply 3/5(1/3)
3/5(1/3)=3/15=1/5
therefore, 1/5 of all the students are girls with blond hair
Mr. Snyder begins traveling east on Interstate 90 from Spokane with a full tank of gasoline. His car has a 15-gallon gas tank and gets 30 miles per gallon during highway travel. Let m = the number of miles Mr. Snyder has driven Let g = the number of gallons of gas remaining in his tank Select in the letter of the equation that describes the relationship between the number of miles Mr. Snyder has traveled and the number of gallons remaining in his gas tank.
Answer:
[tex]g = 15 - \frac{1}{30}m[/tex]
Step-by-step explanation:
Given
[tex]Initial = 15[/tex]
[tex]mpg = 30[/tex] --- miles per gallon
Required
Determine an equation for this trip
First we have to get the number of gallons per mile from [tex]mpg = 30[/tex]
[tex]\frac{miles}{gallon}=30[/tex]
Inverse the equation
[tex]\frac{gallon}{miles}=\frac{1}{30}[/tex]
This represents the rate in gallons/mile
So, the equation is:
[tex]g= Initial - Rate * m[/tex]
[tex]g= 15 - \frac{1}{30} * m[/tex]
[tex]g= 15 - \frac{1}{30}m[/tex]
Find the solution set for this equation.
y2 + 2y = 0
comma.
Separate the two values with a comma.
Karla has spent $39 on food. She bought milk, cheese, and meat. The milk cost half as much as the cheese and the meat cost four times as much as the cheese. Which equation would help you find the cost of the cheese?
Let c = the amount spent on cheese
Click on the correct answer:
1)C+ 4c/5c=39
2)C+2c + 4c = 39
3)C+.5c + 4c = 39
4)C(.5c+ 4c) = 39
This is part of "Using Linear Equations to Solve Problems:Application" on Edmentum.
Answer:
i think the answer is 3)C+.5c + 4c = 39
Step-by-step explanation:
help me with this geometey question !! thanks!
Answer:
A=542
Step-by-step explanation:
none, sorry
Answer: 542 ft.^2
Steps:
2(l*w) + 2(l*h) + 2(w*h)
2(13*7) + 2(13*9) + 2(7*9)
2(91) + 2(117) + 2(63)
182 + 234 + 126
=542
Determine if this table is a linear function. If so, what is the slope?
Answer:
No, it is not linear
Step-by-step explanation:
It does not steadily increase the same interval every time.
Hope this helps (:
PLEASE ANSWER ALL BIG REWARD
Dilations involve ________ the scale factor and the pre–image ordered pair(s)? *
adding
dividing
subtracting
multiplying
All dilations produce _______. *
similar figures
vertical figures
congruent figures
supplementary figures
The rule to describe a dilation is written in _________. *
a list
scale factor
arrow notation
slope-intercept form
Which of the rules below would create a reduction/compression? *
(x, y) (–3x, –3y)
(x, y) (3.2x, 3.2y)
(x, y) (x + 9, y + 9)
(x, y) (0.23x, 0.23y)
Which of the following rules below do NOT represent a dilation? *
(x, y) --> (2x, 4y)
(x, y) --> (–8x, –8y)
(x, y) --> (1/2x, 1/2y)
(x, y) --> (3x, 3y)
(x, y) --> (1.2x, 1.2y)
In the diagram below, triangle ABC will be dilated with the origin as the center of dilation by a scale factor of 1/2. What will be the coordinates of A'? *
Captionless Image
(0, 3/2)
(12, 6)
(3, – 3/2)
(–1, –5/2)
A line segment with endpoints D (–6, –5) and E (3, –4) is dilated by a scale factor of 2. Which statement below is true? *
The line segment has become longer with endpoints D' (-12, -10) and E' (6 -8).
The line segment has become shorter with endpoints D' (-12, -10) and E' (6 -8).
The line segment has become longer with endpoints D' (-3, -5/2) and E' (3/2, -2).
The line segment stays the same length with endpoints D' (-3, -5/2) and E' (3/2, -2).
Write a rule to describe the dilation below. *
Captionless Image
(x, y)→ (1/2x, 1/2y)
(x, y)→ (1/3x, 1/3y)
(x, y)→ (3x, 3y)
(x, y)→ (2x, 2y)
If the scale factor k = 1/9 the resulting dilation will be a/an *
enlargement
reduction
If the scale factor k = 3 the resulting dilation will be a/an *
enlargement
reduction
Answer:
multiplying similar figures scale factor (x, y) (–3x, –3y) and (x, y) (0.23x, 0.23y) (x, y) --> (2x, 4y) Need diagramA. The line segment has become longer with endpoints D' (-12, -10) and E' (6 -8).Need imageReductionEnlargementgood luck, i hope this helps :)
can i get some help!!
yes u can get help what is it?
Answer:
Yeah i can help you ,but the picture u have uploaded is blank.
pls upload again.
Step-by-step explanation:
Pls mark BRAINLIEST
When two rays have a common _________, they form a(n) _________.
A
vertex, angle
B
angle, vertex
C
angle, line segment
D
vertex, line segment
(this is for 7th grade by the way)
In a school, 30% of the students arrived by private car, 15 travel by taxi and the remainder walk to school. If the school has a population of 230, how many more students walk to school than arrives by car?
Answer:
57.5 students
Step-by-step explanation:
Given that
The 30% students would be arrived by private car
So 15% would be travelled by taxi
And, the remaining i.e. 55% would be walk to school
Since the population of the school is 230
So by car, the students would be
= 230 × 0.30
= 69
By walk, the students would be
= 230 × 0.55
= 126.50
Now the more students would be
= 126.50 - 69
= 57.5 students
Will someone help me
Answer:
1.one solution
2.no solution
3.ifinitly many
Step-by-step explanation:
Answer:
1, one solution
2, no solution
3, infinitely many solution
A local boutique marks up all merchandise by 45%. If she purchases a dress wholesale for $28, what will be the sale price at her boutique? Help please
Answer:
45+28
Step-by-step explanation:
the
I NEED ANSWERS ASAP!!! PLEASE
Answer:
10 in by 48 in
Step-by-step explanation:
The volume (V) of a rectangular solid is calculated as
V = Ah ( A is the area of the base and h the height )
Here h = 3 and V = 1440 , then
3A = 1440 ( divide both sides by 3 )
A = 480 in²
The area of a rectangle = length × breadth
From the give options
10 × 48 = 480 ← is the only option
Please select the best answer from the choices provided ASAP
Answer:
c
Step-by-step explanation:
question 9 working out plzzz
Answer:
Here is the answer key!
https://2fv5d843v9w22sxtto1ibxtu-wpengine.netdna-ssl.com/wp-content/uploads/2015/12/Ratio-H-Speed-Distance-Time-Rates-of-Change-v2-SOLUTIONS.pdf
Step-by-step explanation:
Please help! It's due today!
Expand (3a-2b^3)^2
Answer:
9a²-12ab³+4b⁶
Step-by-step explanation:
use FOIL to solve
f-first
o-outer
i-inner
l-last
Answer: 4b^6 - 12ab^3 + 9a^2
yw
HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
A population of 470 animals decreases at an annual rate of 12%.
a.f(x)=470(1.88)x
b.f(x)=470(0.12)x
c.f(x)=470(0.88)x
d.f(x)=470(1.12)x
Answer:
C. f(x) = 470(0.88)ˣStep-by-step explanation:
Initial number = 470Decrease rate = 12% ⇒ 100% - 12% = 88% ⇒ 0.88 timesRequired equation:
f(x) = 470(0.88)ˣCorrect choice is C
Please Help
Which of the following is a continuous random variable?
A. X= number of incoming flights at the local airport
B. T=winning time in the man's 100 meter dash at the 2016 Olympics
C. P=number of points scored by Stephen curry in a game
D.H=The number of hats sold on Tuesday
Answer:
option A
Step-by-step explanation:
because it is not limited to anything while option b is limited to the men's hundred meter dash and 2016, and to the Olympics
C is limited to one game and stephen curry
D is limited to tuesday
since option a isn't confined to one day, person, or specific event there can be endless numbers assigned to the variable
Beth is buying 2.6 pounds of coffee beans. If the coffee costs 6.79 per pound, how much will she pay? Round to the nearest cent..
Answer:
$17.65
Step-by-step explanation:
hope this helped!!
Find the mean of the set of data.
6, 8, 6, 6, 8, 6, 3, 8, 3, 8.
Answer:
Hellothe mean of the data =
= 6+8+6+6+8+6+3+8++3+8
10
= 62
10
= 6.2
Step-by-step explanation:
thanks pls mark as brainliest
Solve the system of equations -x+6y=2 and -3x+y=-11 by combining the equations.
Answer this question( need less then 5 minutes) 15 = t - 25 t=
Answer: t=40
Step-by-step explanation:
To work out t on its own you have to do the inverse of takeaway which is add so it is 15+25=40.
Please help with this
Answer:
What is your question?
______________________________
Please rate my answer and say thanks!
Sophia bought snacks for her team's practice. She bought a bag of popcorn for $1.98
and a 10-pack of juice bottles. The total cost before tax was $12.48. Write and solve
an equation which can be used to determine j, how much each bottle of juice costs?
Answer:
j = $1.05
Step-by-step explanation:
($12.48 - $1.98) / 10 = j
(Total cost - popcorn cost) / number of juice boxes = cost of one juice box
Answer:
10j+1.98=12.48
j= 1.05
Step-by-step explanation:
A student is standing next to a vertical flagpole. The top of the student's shadow
coincides with the top of the flagpole's shadow as shown.
not to scale
The student is 62 inches tall. The student estimates that the distance from the flagpole
to the point where the student is standing is between 21 and 22 feet. The student also
estimates that the length of the student's shadow is between 7 and 7 feet.
Based on the given information, what are the least and greatest possible heights, in
feet, of the flagpole? Explain how you arrived at your answers.
Answer:
The least possible height of the flagpole is 227.33 inches and the greatest possible height is 248 inches
Step-by-step explanation:
Given
See attachment for the system
Required
Determine the least and greatest heights of the flagpole
From the question, we have:
[tex]AB = 7\ to\ 7\frac{1}{2} ft[/tex]
[tex]BE =62in[/tex]
[tex]BC = 20\ to\ 21ft[/tex]
Convert AB and BC to feet (multiply by 12)
[tex]AB = 84in\ to\ 90in[/tex]
[tex]BC = 240in\ to\ 252in[/tex]
The height of the flagpole is represented as: CD
To calculate CD, we make use of the following equivalent ratios:
[tex]CD : AC = BE : AB[/tex]
Express as fraction
[tex]\frac{CD }{ AC } = \frac{BE }{ AB}[/tex]
Make CD the subject
[tex]CD = \frac{BE }{ AB} * AC[/tex]
From the attachment:
[tex]AC = AB + BC[/tex]
Where:
[tex]AB = 84in\ to\ 90in[/tex]
[tex]BC = 240in\ to\ 252in[/tex]
The possible values of AC are:
[tex]AC = 84 + 240 =324in[/tex]
[tex]AC = 84 + 252 =336in[/tex]
[tex]BC = 90 + 240 = 330in[/tex]
[tex]AC = 90 + 252 =342in[/tex]
So:
[tex]CD = \frac{BE }{ AB} * AC[/tex]
[tex]BE =62in[/tex]
When AC = 324 ; AB = 84
[tex]CD = \frac{62}{84} * 324[/tex]
[tex]CD = \frac{62* 324}{84}[/tex]
[tex]CD = \frac{20088}{84}[/tex]
[tex]CD = 239.14in[/tex]
When AC = 336 ; AB = 84
[tex]CD = \frac{62}{84} * 336[/tex]
[tex]CD = \frac{62* 336}{84}[/tex]
[tex]CD = \frac{20832}{84}[/tex]
[tex]CD = 248in[/tex]
When AC = 330 ; AB = 90
[tex]CD = \frac{62}{90} * 330[/tex]
[tex]CD = \frac{62 * 330}{90}[/tex]
[tex]CD = \frac{20460}{90}[/tex]
[tex]CD = 227.33in[/tex]
When AC = 342 ; AB = 90
[tex]CD = \frac{62}{90} * 342[/tex]
[tex]CD = \frac{62* 342}{90}[/tex]
[tex]CD = \frac{21204}{90}[/tex]
[tex]CD = 235.6in[/tex]
So, we have:
[tex]CD = 239.14in[/tex]
[tex]CD = 248in[/tex]
[tex]CD = 227.33in[/tex]
[tex]CD = 235.6in[/tex]
The least possible height of the flagpole is 227.33 inches and the greatest possible height is 248 inches
The given range of the length of the shadow and distance of the student
from the tree of between 7 and [tex]7\frac{1}{2}[/tex] feet and 21 and 22 feet gives;
The greatest possible height of the flagpole in feet ≈ 21.8 feet
The least possible height of the flagpole in feet = 19.3 feet
How can the height of the tree be calculated?Height of the student = 62 inches = [tex]5\frac{1}{6}[/tex] feet
Distance of the flagpole to the student = 21 to 22 feet = 252 to 264 inches
Length of the student's shadow = Between 7 and [tex]\mathbf{7\frac{1}{2}}[/tex] feet = Between 84 and 90 inches
Required:
The least and greatest height of the flagpole.
Solution;
By using similar triangles formed by the student and the flagpole, we
have;
[tex]\dfrac{Height \ of \ the \ student}{Length\ of \ the \ student's \ shadow} = \mathbf{\dfrac{Height \ of \ the \ flagpole}{Length\ of \ the \ flagpole's \ shadow}}[/tex]
Which gives;
[tex]\dfrac{62}{84 \ or \ 90} =\mathbf{ \dfrac{h}{252+(84 \ or \ 90) \ or \ 264 + (84 \ or \ 90)}}[/tex]
Based on the method of cross multiplication, h will be the greatest
possible value, when we have, the largest possible value for the
denominator on the right hand side and the least possible value for the
denominator on the left hand side of the equation, and vice versa.
Which gives;
[tex]\dfrac{62}{90} = \mathbf{\dfrac{h_{min}}{252 + 84}}[/tex]
[tex]h_{min} \ in \ feet = \mathbf{\dfrac{\dfrac{62}{90} \times (252 + 84)}{12}} \approx 19.3[/tex]
The least possible height of the flagpole in feet, [tex]h_{min}[/tex] ≈ 19.3 feet
Similarly. we have;
[tex]\dfrac{62}{84} = \mathbf{\dfrac{h_{max}}{264 + 90}}[/tex]
Which gives;
[tex]h_{max} = \dfrac{62}{84} \times (264 + 90) \approx 261.3[/tex]
[tex]h_{max} \ in \ feet \approx \dfrac{261.3}{12} \approx\mathbf{ 21.8}[/tex]
The greatest possible height of the flagpole in feet, [tex]h_{max}[/tex] ≈ 21.8 feet
Learn more about the characteristics of similar triangles here:
https://brainly.com/question/10703692
Plz help me with this
Find The Product of:
[tex] \sqrt[3]{2} \times \sqrt[6]{5} [/tex]
Answer:
Step-by-step explanation:
You can find the cube root of 2 and multiply it by the 6th root of 5.
cube root(2) = 2^(1/3) = 1.2599
6th root of (5) = 0.7418
Product = 1.2599 * 0.7418 = .9346
You need a key that will do fractional powers. Look around on your calculator for ^ that key y^x or x^y.
Using one of those keys, you would put in 2 ^ 0.33333333 =
If your calculator does not have this key (I recommend you buy one that does. They are less than 10 dollars), then you can use the calculator on windows.
What is the correct answer?
Answer:
F
Step-by-step explanation:
Please answer correctly !!!!!!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!
Add the ratios together:
5 + 2 + 1 = 8
Divide the length of NQ by that:
24/8 = 3
Multiply the ratio of NO by that/l
The ratio of NO is 5, 5 x 3 = 15
NO = 15