Raw iron will rust more quickly in salt water when we add it to the first two test tubes, which will be filled with fresh and salt water, respectively.
The iron in the third and fourth test tubes will rust more quickly if oxygen or water are removed from them, respectively. Iron is susceptible to rusting, a form of corrosion. When iron is exposed to oxygen and water, rusting happens because hydrated iron(III) oxide is created. This means that any action we take to keep iron away from oxygen or water will delay the rusting process. When iron is exposed to salts or a low pH, the rusting process is also sped up. There is no water in a tube with simply air, but the nail is exposed to the air. Since air contains some water vapour, water will eventually find its way inside the tube. In tap water, there is always a little amount of dissolved oxygen gas. This indicates that the tube already contains water and oxygen.
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Select the true statement.
A. Refractive index is directly proportional to temperature.
B. Refractive index is directly proportional to wavelength.
C. Refractive index is inversely proportional to temperature.
D. Refractive index is inversely proportional to wavelength.
E. Both C and D
Option D-Refractive index is inversely proportional to wavelength.
Refractive index, often known as the index of refraction, is a measurement of the way a light beam bends when it travels through different media. The refractive index n is determined by dividing the sine of the angle of incidence by the sine of the angle of refraction, i.e., n = sin I / sin r, assuming that I is the angle of incidence of a ray in vacuum (angle between the incoming ray and the normal, which is perpendicular to the surface of a medium). Additionally, the refractive index is determined by dividing the speed of a specific wavelength of light in vacuum, c, by that same wavelength's speed, v.
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a simple harmonic oscillator consisting of a spring and a block oscillates on the horizontal plane at amplitude aa. at which of the following positions is the net force on the block at its maximum magnitude and pointing in the positive xx direction?
The net force on the block is at its maximum magnitude and pointing in the positive x direction when the block is at the extreme right end of its oscillation, where the displacement of the block is equal to the amplitude a.
What is oscillation?Oscillation is a repeating motion between two or more points. It can refer to the motion of a physical object, a sound wave, an electromagnetic wave, or any other type of wave. Oscillation is a fundamental concept in many branches of physics, such as mechanical, electrical, and acoustics. Examples of oscillation include a swinging pendulum, a vibrating guitar string, the sound of a siren, and the regular vibrations of an AC electrical current.
At this point, the spring is stretched to its maximum and is exerting a force in the positive x direction on the block. This is the only position at which the net force on the block is at its maximum magnitude and pointing in the positive x direction.
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A truck moving with an initial speed v collides with a car that is one-third as massive as the incident truck and is initially at rest. After the collision, the truck moves off in the same direction as before the collision with a speed v/2. Determine the following.
(a) the final speed of the car in terms of the initial speed v of the truck
The final speed of the car in terms of the initial speed v of the truck is 3v/2.
What is the final speed of the car?
The final speed of the car in terms of the initial speed v of the truck is calculated as follows;
Apply the principle of conservation of linear momentum as follows;
m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂
where;
m₁ is the mass of the truck u₁ is the initial speed of the truckm₂ is the mass of the caru₂ is the initial speed of the carv₁ is the final speed of the truckv₂ is the final speed of the carlet the mass of the truck = m
then, mass of the car = m/3
let the final speed of the truck, v₁ = v/2
The final speed of the car is calculated as follows
m(v) + (m/3)(0) = (m)(v/2) + (m/3)(v₂)
mv = (mv)/2 + (mv₂)/3
6mv = 3mv + 2mv₂
6mv - 3mv = 2mv₂
3mv = 2mv₂
v₂ = 3mv / 2m
v₂ = 3v / 2
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two compounds with partition coefficients of 0.15 and 0.18 are to be separated on a column with vm/vs. Calculate the number of theoretical plates needed to produce a resolution of 1.5?
The number of theoretical plates are 1757.
What is partition coefficients ?
The ratio of a compound's equilibrium concentrations in a combination of two immiscible liquids is known as a partition coefficient (P) or distribution coefficient (D). This ratio so compares the solubilities of the solute in these two liquids.
What is resolution ?
Resolution of the vector is the process of dissolving a vector into its parts. The components will result in the same vector when combined together vectorially. In general, we divide a vector into three parts: the x-component, the y-component, and the z-component. y-component is the name given to a component that runs along the y-axis.
The ratio of the partition coefficients of the two components ( ∝)
K ₂/ K₁ = 0.18/ 0.15= 1.2
The relationship between no. of plates and resolution is ask follows
R= [tex]\sqrt{N}[/tex]/ 4 (∝- 1/∝) (K₂/K₂+1)
Calculate K₂ by using K₂ and Vsm as follows
K₂= K₂ ( Vs/ Vm )
18*1/3= 6
calculate the number of plates ( N) as follows
R= [tex]\sqrt{N}[/tex]/4 (∝- 1/∝) (K₂/K₂+1)
[tex]\sqrt{N}[/tex]= R*4/(∝- 1/∝) (K₂/K₂+1)
N = ( r*4/ (∝- 1/∝) (K₂/K₂+1))²= [1.5*4/ ( 1.2-1/ 1.2) ( 6/ 6+1)]²= [6/(0.167) (0.857)]² = 1757
Therefore, number of theoretical plates are 1757.
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Two balls of clay known masses hang from the ceiling on masslessstrings of equal length. They barely touch when both hang atrest. One ball is pulled back until its string is45o, the released. It swings down, collides withthe second ball, and they stick together. To determine theangle to which the balls wing to the opposite side, you need toinvoke:
A. Conservation of momentum
B. Conservation of mechanicalenergy
C. Both conservation of momentum andconservation of mechanical energy
D. Either, but not both.
E. These principles alone are not sufficientto find the angle
The combination of momentum conservation and mechanical energy conservation yields the letter C.
You need:
1.Conservation of energy to calculate the velocity of the firstball of clay by the time it descends:
mgh=1/2mu2
[calculate h by using h=L(1-cos45)]
2.Conservation of momentum to find out the final velocity of theballs of clay using:
m1u1+m2u2=(m1+m2)v ---note:u2=0
3.Conservation of energy to calculate the max height the balls ofclay will go by using:
1/2(m1+m2)v2=mgh
Once you have h,
h=L(1-cosθ), solve for θ
In Newtonian physics, an object's mass and velocity are combined to form momentum, more precisely linear momentum or translational momentum. It has both a magnitude and a direction, making it a vector quantity. If an item has mass (m) and velocity (v), both of which are vector quantities, then it has momentum (p).
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Calculate the mass for an object with 5,000J of PE on top of a 200m tall building.
Answer:
2.5 [kg].
Explanation:
1. initial formula is:
E=m*g*h, where E - energy described in the condition, m - required mass, h - height and g≈10 [N/kg];
2. according to the formula above:
[tex]m=\frac{E}{gh}; \ = > \ m=\frac{5000}{200*10}=2.5[kg].[/tex]
the figure(figure 1) shows a particle of mass m at distance x along the axis of a very thin ring of mass m and radius r. calculate the gravitational potential energy of these two masses. use what you know about the relationship between force and potential energy to find the magnitude of the gravitational force on m when it is at position x>0 .
The magnitude of the gravitational force on mass m at distance x along the axis of a very thin ring when it is at position x>0 is 4GMm/4x^2-L^2.
Every body in the universe attracts every other body with a gravitational force that decreases with distance as 1/r2. if two bodies of different masses have the same acceleration they must be feeling forces in the same ratio as their masses (so a body twice as massive feels twice the gravitational force), that is, the gravitational force of attraction a body feels must be proportional to its mass.
The gravitational field at any point P in space is defined as the gravitational force felt by a tiny unit mass placed at P.
This relation can be find out by using the formula of gravitational potential = GMm/r and further integrating on small dx length at x from the origin of the rod, we get,
U = GMm/L㏑2x-2/2x+2.
now differentiating with respect to dx, we get
F = 4GMm/4x^2-L^2.
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which of the following seas was formed by glacier scouring of a river valley during the last ice age? quizleet
Answer: I think it's The Baltic Sea and The Black Sea
A loudspeaker at the origin emits a 110 Hz tone on a day when the speed of sound is 340 m/s. The phase difference between two points on the xxx-axis is 6.0 rad .
What is the distance between these two points? Express your answer with the appropriate units.
The distance between the two points on a loudspeaker that initially emits a 110 Hz tone with a sound speed of 340 m/s = 18.54 m.
Traveling and stationary wavesTraveling waves are waves that have a fixed amplitude. Meanwhile, a stationary wave is a wave whose amplitude changes at every point.
The phase difference is the difference in the phases of the waves or stages of the waves. Mathematically, the phase difference is formulated as follows:
Δφ = Δx/λ
We have,
The frequency = (110 Hz) ⇒ f
The speed of sound = 340 m/s ⇒ v
The phase difference between two points = 6.0 rad ⇒ Δφ
Determine the wavelength first,
λ = v/f
= 340/110
= 3.09 m
So, the distance between these two points:
Δφ = Δx/λ
(6.0) = Δx/3.09
Δx = 18.54 m
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Mitch Trubisky throws a football straight up into the air where it stays for 5.18 seconds
before he catches it. If the height that he releases the ball and catches the ball is the same,
and assuming that point is the origin, what is the maximum height the ball the ball will reach?
The acceleration due to gravity is 9.8m/s/s downward. Answer to two decimal places and do
not include units.
Answer:
32.93 ( m )
Explanation:
The ball travels up for half the time 1/2 * 5.18 = 2.59 s
( the other 2.59 s is coming down time)
When it reaches max height , vf = 0
vf = vo - 9.8 (t)
0 = vo - 9.81(2.59)
so vo = 25.4079 m/s
d = max height = vo t + 1/2 a t^2
= 25.4079 ( 2.59) + 1/2 ( - 9.8) (2.59^2) = ~ 32.93 m (Pretty high!!!)
an inclined ramp is set up on your table. from the top of the ramp, you release a disk, hoop, and solid sphere at the same time. all objects are well manufactured with exactly the same mass. they are completely uniform and roll without slipping. which object reaches the bottom of the ramp first, second and third? select from the following, which are listed in order of first, second, third.
Sphere, disk, hoop due to Torque.
Torque = I α if a man and radius is same α will be more for lesser moment of theta.
Is = 2/5 MR², Iloop = MR², Id = 1/2MR²
The order is
Is < Id< Ih
Sphere, disk, hoop.
rFsin() is the definition of torque. Or, to put it another way, torque is the cross product of the distance vector (the distance between the pivot point and the point at which force is applied) and the force vector, where 'a' is the angle between r and F. The torque is a pseudovector in three dimensions and is determined for point particles by the cross product of the force vector and the position vector (also known as the distance vector). The force applied, the lever arm vector[2] connecting the torque measurement point to the force application point, and the angle between the force and lever arm vectors all play a role in determining how much torque a rigid body can generate.
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two small speakers a and b are driven in step at 725 hz by the same audio oscillator. these speakers both start out 4.50 m from the listener, but speaker a is slowly moved away. (see (figure 1)).
The speakers produce the second destructive interference at the distance of 0.704 m.
Let us take the speed of sound v as 340 m/s.
The frequency f of sound is given as 725 Hz.
The wavelength is calculated to be,
λ = v / f = 340/ 725 = 0.469 m
For destructive interference, distance is given as,
d = (2k - 1) * λ/2
For second destructive interference, put K = 2 in the above formula,
d = (4 - 1) * 0.469/2 = 0.704 m
Thus, the speakers produce the second interference at the distance of 0.704 m.
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a single loop of wire with an area of 0.0940 m2 is in a uniform magnetic field that has an initial value of 3.80 t, is perpendicular to the plane of the loop, and is decreasing at a constant rate of 0.190 t/s . for related problem-solving tips and strategies, you may want to view a video tutor solution of emf and current induced in a loop.
The EMF induced in a single wire loop with an area of 0.0940 m² is in a uniform magnetic field which has an initial value of 3.80 T, is perpendicular to the plane of the loop, and decreases at a constant rate of 0.190 T = 0.34 V. And the current induced in the loop = 0.57 A.
The EMF inducedInduced electromotive force or induced emf is the potential difference at the ends of the coil which will produce an induced electric current.
An induced electric current appears as long as there is a change in magnetic flux.
The equation is:
ε = d∅/dt
We have,
The area of the loop = 0.0940m²
The change in magnetic field with time = (3.80 T - 0.190 T) = 3.61 T
So, the EMF induced:
ε = d∅/dt
= {(0.0940m²) (3.61)} / 1
= 0.34 V
And the current induced in the loop =
I = ε/R
= 0.34 V / 0.600 Ω
= 0.57 A
The question is incomplete, it should be:
A single loop of wire with an area of 0.0900m2 is in a uniform magnetic field that has an initial value of 3.8 T, is perpendicular to the plane of the loop, and is decreasing at a constant rate of 0.190 T/s.
(a) What emf is induced in this loop?
(b) If the loop has a resistance of 0.600O, find the current induced in the loop.
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Based on the solar atmosphere and outer layers of the sun, select all of the correct statements from the following list.
Spicules and filaments are found in the solar corona.
The temperature of the corona is millions of degrees.
The solar wind is ionized gas streaming away from the sun.
The photosphere is the outermost layer of the sun.
Helioseismology is the study of "sunquakes."
The chromosphere is the visible surface of the sun.
Granulation is caused by convection.
The deepest portion of the Sun that we may directly witness is the photosphere. It extends roughly 250 miles (400 km) above the solar disk's visible surface at its core.
The distances from the inner layers, which are measured in terms of distance from the sun's core, and the outer layers, which are measured in terms of distance from the sun's surface, are shown on this diagram as approximations for each layer. The Core, Radiative Zone, and Convection Zone are the inner layers. The Photosphere, Chromosphere, Transition Region, and Corona make up the outer layers.
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if you stand on a bathroom scale, the spring inside the scale compresses 0.60 mm , and it tells you your weight is 700 n .
The Kinematics of Spring Motion is 73730 N
Kinematics of Spring Motion:
An elastic spring abides by Hooke's law, which states that the force needed to stretch or compress a spring is inversely proportional to the length of the spring in question. Simple harmonic motion is performed by a mass that is connected to a spring.
According to Hooke's law, compression in spring is related to applied force as following.
F applied = -kx
Where,
k = force constant
x = compression in spring
Step 1)First, we will determine force constant of spring
k = 730/ (0.40*10-3)
k = 1825000 N/m
Step 2)We will determine compression in bathroom scale when man jumps on the scale.
m g (H+x) = 0.5 k x2
730 * (2.0 + x) = 0.5 * 1825000 * x2
0.0008 * (2.0 + x) = x2
x2 - 0.0008 x - 0.0016 = 0
x = 0.04040 m, -0.03(rejected since negative)
Hence,
F = k x = 1825000 * 0.04040 = 73730 N
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a television camera at ground level is filming the lift-off of a rocket at a point 800 meters from the launch pad. let be the angle of elevation of the rocket and let s be the distance between the camera and the rocket (see figure). write as a function of s for t
The function of θ in term of s is θ = arctan(s/75).
The value of θ is s is 900 and 1500 are 85,24 degrees and 87.14 degrees respectively.
Find the diagram attached. From the diagram, we are given the following:
Opposite = s
Adjacent = 75
According to SOH CAH TOA identity;
tanθ = opp/adj
tanθ = s/75
θ = arctan(s/75)
Hence the function of θ in term of s is θ = arctan(s/75)
b) If s=900meters
θ = arctan(900/75)
θ = 85,24 degrees
If s = 1500
θ = arctan(1500/75)
θ = 87.14 degres
Hence the value of θ is s is 900 and 1500 are 85,24 degrees and 87.14 degrees respectively.
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stunt motorcyclist biker sally rides her bike inside a futuristic rotating space station-a giant rotating donut-shaped structure in space. the normal support force feels like weight to her
As he rides in the same direction of rotation of station, the normal force increases and as he rides in opposite direction of motion, normal force decreases.
The gravitational force has not disappeared in space station, but astronauts feel weightlessness. This is because of microgravity. It happens when an object is falling freely.
Both the astronauts and the ISS are orbiting around the Earth. This means, they are in a state of freefall towards the Earth.
On the ISS therefore, the acceleration due to gravity is not zero. In fact the gravitational field inside the ISS is almost as large as that they are exposed to on the Earth.
As there is presence of gravity, there is also presence of opposite normal force. This force increases when rotation along with earth in same direction and it decreases when rotating in opposite direction.
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the magnetic field perpendicular to a circular wire loop 9.0 cm in diameter is changed from 0.48 t to -0.69 t in 200 ms , where means the field points away from an observer and - toward the observer.
The induced emf is equal to 0.025v. If the outward magnetic flux rises, the current must go counterclockwise. When the flux coupling with a conductor or coil changes, an electromotive force, or EMF.
There are two approaches to get this change in flux: by statically or dynamically inducing emf across a certain area. For instance, the magnetic flux density is lower if fewer magnetic lines cover a large region of cross section. Knowing the magnetic flux also enables us to make an educated guess about the magnitude of the magnetic field in a particular area. The surface integral of the normal component of the magnetic field is used to define the magnetic flux across a surface (B)
e = Pi*r^2(B2 - B1)/t
e = pi*81/4*0.50/130 *10
e = 0.025v
current must be clock wise
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the lorenz curve: group of answer choices is located farther from the diagonal when income is defined to include the value of noncash transfers. is located closer to the diagonal today than it was in 1975. plots graphically the distribution of income. plots graphically the poverty rate over time
Lorenz curve is the curve that plots graphically the distribution of income. Therefore, the correct statement is statement 3.
The Lorenz curve depicts the distribution of income (or wealth) within an economy. Max O. Lorenz created it in 1905 to symbolize the distribution of income. The Lorenz curve displays the total percentage of income earned by various demographic groups.
The graph shows cumulative income or wealth on the vertical axis and percentiles of the population according to income or wealth on the horizontal axis. Lorenz curves and the statistics derived from them are frequently utilized to assess inequality within a population.
An empirical measurement of the wealth or income distribution within a population, based on information from tax returns, which detail income for a significant section of the people, is the common starting point for a Lorenz curve.
Therefore, statement 3 is correct.
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you have a horizontal grindstone (a disk) that is 85 kg, has a 0.31 m radius, is turning at 91 rpm (in the positive direction), and you press a steel axe against the edge with a force of 21 n in the radial direction.
Angular speed , wi = 91 rpm
wi = 91 * 2pi/60 rad/s
wi = 9.11 rad/s
Frictional force , f = 0.20 * 16 = 3.2 N
part a) let the angular acceleration is a
Using the second law of motion
0.50 * 85 * 0.31^2 * a = 3.2 * 0.31
solving for a
a = 0.242 rad/s^2
The angular acceleration is 0.242 rad/s^2
b) Let the angle is theta
theta = 9.11^2/(2 * 0.242)
theta = 170 radian = 27.2 turns
The number of turns is 27.2
Angular velocity is the speed of an object in rotational motion. The distance traveled is denoted by θ and is measured in radians. Duration is measured in seconds. Angular velocity is therefore expressed in radians/second, or rad/s. Angular velocity is measured in radians per unit of time because it is the rate at which the central angle swept by an object changes as it moves around a circle.
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in the speed of particles is doubled by what factors of momentum change.? and what factors kinetic energy changes
If the speed of a particle is doubled, its momentum will also be doubled, because momentum is directly proportional to the speed of the particle. In other words, the momentum of a particle is equal to its mass times its velocity, so if the velocity is doubled, the momentum will also be doubled.
The kinetic energy of a particle is also directly proportional to the square of its speed, so if the speed is doubled, the kinetic energy will increase by a factor of four. This can be expressed mathematically as:
Kinetic energy = (1/2) * mass * velocity^2
If the velocity of a particle is doubled, the kinetic energy will increase by a factor of four, because velocity^2 will increase by a factor of four.
So to summarize, if the speed of a particle is doubled, its momentum will be doubled, and its kinetic energy will increase by a factor of four.
Find 5 Galaxies With Redshifts Less Than 0.001 And 10 Galaxies With Redshifts Greater Than 0.001. Record The Redshift And Distance And Calculate The Radial Velocity (Using The Method From Question 3) For Each Of These Galaxies. Make Sure You're Recoding The Distance In Mpc, If The Distance Is Given In Kpc Rather Than Mpc You Can Convert It Into Mpc Using TheThis question hasn't been solved yetAsk an expertFind 5 galaxies with redshifts less than 0.001 and 10 galaxies with redshifts greater than 0.001. Record the redshift and distance and calculate the radial velocity (using the method from Question 3) for each of these galaxies. Make sure you're recoding the distance in Mpc, if the distance is given in kpc rather than Mpc you can convert it into Mpc using the converstion 1000 kpc = 1 Mpc. You can use the tables on the second page of the lab for this if you want, but you can use normal paper as well, just make sure you don't reuse galaxies on accident.Graph all the galaxies with positive redshifts (don't use galaxies with negative redshifts) in excel or a similar spread sheet program with distance in Mpc on the x-axis and radial velocity in km/s on the y-axis (make sure you label the axis as such). Create a line of best fit for this graph and display the equation on the graph. If you're not sure how to do this, see the Excel Tutorial video.
The 5 galaxies with redshifts less than 0.001 are Ages, cosmos , hypernova , Gama , VVDS and greater than 0.001 are Devils, achne, simar , vipers, MGC, 2SLAQ,QCD, SAPM,AARS and ESP.
A more tricky task is determining the distance to the galaxy. For nearby galaxies, standard candlesticks such as Cepheid variables and Type I supernovae can be used. But in very distant galaxies, we have to resort to more indirect methods. The main assumption of this lab is that similar Hubble-type galaxies are actually similar true sizes no matter how far apart they are. This is known for adopting the "standard ruler". First, we need to adjust the actual size using a galaxy whose actual distance is known. Find the galaxies in the sample that are Sb galaxies to calibrate the distance using the nearby Sb galaxy M31, the Andromeda galaxy. The distance to the Andromeda Galaxy is known from observations of Cepheid variable stars. Then, to determine the distances to more distant similar galaxies, we only need to measure their apparent (angular) magnitudes and use the small-angle approximation: a=s/dTo study more about Andromeda galaxy -
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Beta-carotene is an organic compound with an orange color. The diagram above shows the ultraviolet spectrum of beta-carotene. Which of the following statements is true about the absorption bands in the spectrum?
The two main absorption bands are associated with transitions in electronic energy levels. The band in the region corresponding to shorter wavelengths shows a lower absorbance than the band in the region corresponding to longer wavelengths.
The two primary absorption bands are connected to changes in the energy levels of electrons. In comparison to the band in the region corresponding to longer wavelengths, the band in the shorter wavelength region has a lower absorption.
What is Beta-carotene?Plants have a pigment called beta-carotene that gives them colour. The Latin term for carrot is source of the name beta-carotene. Fruits and vegetables that are yellow or orange derive vibrant colors from it. Additionally, the foods like margarine are colored with beta-carotene.
Beta-carotene transforms into vitamin A in the body (retinol). For clear eyesight and healthy eyes, a robust immune system, and healthy skin and mucous membranes, we require vitamin A. Vitamin A in large levels can be poisonous, but your body only makes as much of the vitamin from beta-carotene as is required. In light of this, beta-carotene is regarded as a secure source of vitamin A.
For smokers, meanwhile, consuming too much beta-carotene can be harmful. It is safe to consume large doses of vitamin A or beta-carotene through food rather than supplements.
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If a monkey floating in outer space throws his hat away, the hat and the monkey will both
move away from each other, but at different speeds
If a monkey floating in outer space throws his hat away, the hat and the monkey will both move away from each other, but at different speeds.
Assuming that the floating monkey is in deep space away from any celestial bodies with a strong gravitational force and the hat is outside of the spacesuit and less massive than the monkey, then the hat and the monkey both will move away from each other, but at different speeds. On the basis of law of attraction, when the monkey threw the hat forward, the hat would push the monkey back.
As the monkey is heavier compared to the hat, its acceleration would be smaller than that of a hat which is less massive.
Due to this, the monkey moves back slower compared to that of a hat which moves forward at a greater speed.
They cannot move away from each other at the same speeds unless the mass of both the bodies is same. There is no friction in space so, there is nothing that would slow down their motion or let them stop unless they collide with other bodies in space.
The question is incomplete. The missing options are A) move away from each other, but at different speeds B) move away from each other at same speed C) move a short distance and then slow down D) move a short distance and then go faster E) come to a stop after few minutes
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NEED HELP PLS If you weigh 982 N on Earth, what would your weight be on the surface of Jupiter?
g = 9.8 m/s^2 on Earth's surface
g = 26.0 m/s^2 on Jupiter's surface
mass of the Earth is 6 x 1024 kg
mass of Jupiter is 1.9 x 1027 kg
radius of Earth is 6.4 x 106 m
radius of Jupiter is 7 x 107 m
Round your answer to the nearest whole number.
(ANSWER IS 2605 BUT I NEED TO KNOW HOW TO GET THE ANSWER)
The magnitude of your weight on the surface of Jupiter is 2,605.2 N.
What is your mass?
The magnitude of your mass which does not change on both Earth and Jupiter is calculated from your weight on Earth by applying Newton's second law of motion as follows;
W = mg
where;
m is your massg is acceleration due to gravity on Earthm = W / g
m = 982 N / ( 9.8 m/s²)
m = 100.2 kg
The magnitude of your weight on the surface of Jupiter is calculated as follows;
W = mg
where;
m is your massg is acceleration due to gravity on JupiterW = 100.2 kg x 26 m/s²
W = 2,605.2 N
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Question 20 (1 point) What is the maximum theoretical efficiency possible for a heat engine operating between a reservoir in which ice and water coexist, and a reservoir in which water and steam coexist? The pressure is constant at 1.0 atm for both reservoirs. 100% 27% 45% 17% 73%
The maximum theoretical efficiency possible for a heat engine operating between a reservoir in which ice and water coexist is 27 %.
Heat engines often operate at around 30% to 50% efficiency, due to practical limitations. It is impossible for heat engines to achieve 100% thermal efficiency, according to the Second law of thermodynamics.
The Carnot cycle is a theoretical power cycle and is used for showing the theoretical maximum of a heat engine.
The energy consumption, theoretical value is the value when computers operate following the power saving settings on individual computers and the sample settings.
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4.00 mol of the helium is confined to a 4.00-L container at a pressure of 14.0 atm. The atomic mass of helium is 4.00 u, and the conversion between u and kg is 1 u = 1.661 ××10?27 kg.
Calculate vrms. (Express your answer to three significant figures.)
Since 1 u = 1.661 10 kg, what is the atomic mass of helium, which is 4.00 u, in u? 27 kg equals 1031.46 m/s.
Vrms = [tex]\sqrt{3RT/m}[/tex]
PV = nRT
RT = PV/n
RT = 14 × 101325 × 4 × [tex]10^{-3}[/tex]/4
RT = 1418.55
Vrms = √1418.55 × 3/4 × [tex]10^{-3}[/tex]
Vrms = 1031.46m/s
The atomic mass ma of an isotope is divided by the atomic mass constant mu to produce a dimensionless value, which is the relative isotopic mass (see section below). As a result, while a carbon-12 atom's relative isotopic mass is simply 12, its atomic mass is defined as 12 Da. The total of all the atoms' respective isotopic masses makes up the relative molecular mass.
A unique isotope of an element is indicated by its relative isotopic mass and atomic mass. It is practical to use the elemental atomic mass, which is the average (mean) atomic mass of an element, weighted by the abundance of the isotopes, because most things are not isotopically pure.
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You are designing a hydraulic lift for an automobile garage. It will consist of two oil-filled cylindrical pipes of different diameters. A worker pushes down on a piston (with a diameter of 25 cm) at one end, raising the car on a platform at the other end. To handle a full range of jobs, you must be able to lift cars up to 3,471 kg, plus the 451 kg platform on which they are parked. To avoid injury to your workers, the maximum amount of force a worker should need to exert is 106 N. What should be the diameter of the pipe under the platform if the diameter? Use g = 9.8 ™. Express answers in meters (m).
The maximum weight that has to be lifted is 3922 N. and the diameter of the pipe under the platform if the diameter is 37.
What is platform?Platform is defined as a collection of technologies that serve as the foundation for the development of new applications, procedures, or technologies. By facilitating transactions, a platform eventually makes this wealth generation possible.
A maximum weight of (3,471 + 451) g = 3922 N must be lifted. The other piston cannot be subjected to more than 100 N of force. The ratio of the two pistons' diameters needs to be sqrt (3922 / 106) = 37.
Thus, the maximum weight that has to be lifted is 3922 N. and the diameter of the pipe under the platform if the diameter is 37.
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Which of the following characteristics of an astronomical telescope is the most important for determining the angular resolution?
The diameter of the objective lens or mirror characteristics of an astronomical telescope is the most important for determining the angular resolution .
The aperture of a telescope, also known as the objective or light-gathering lens or mirror, is its most crucial feature. The telescope's specifications can be found on the box, at the front of the tube, or close to the focuser.
In order to acquire a clearer view of the planets, stars, and galaxies that we are researching, we launch telescopes into space in order to avoid the Earth's atmosphere. Our atmosphere functions as a shield, allowing some light to pass through but blocking others.
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An object is thrown horizontally off a cliff with an initial velocity of 5.0 meters per second. The object strikes the ground 3.0 seconds later. (i) What is the vertical speed of the object as it reaches the ground? a) – 29.4 m/s b) zero. c) 15 m/s.
d) 29.4 m/s
(ii) How far from the base of the cliff will the object strike the ground? a) – 44.1 m/s b) zero. c) 15 m/s. d) 29.4 m/s
Answer:
Below
Explanation:
Vertical speed = at = 9.81 m/s * 3 = 29.4 m/s
For 3 seconds it travels 5 m/s horizontally = 15 meters (NOT m/s)