Answer:
The ping pong ball is hollow.
Explanation:
Since a ping pong ball, unlike the golf ball, is only filled with air, it is less dense. Air is notably LESS dense than solids, which is what comprises the inside of a golf ball.
A fireworks shell is accelerated from rest to a velocity of 68.0 m/s over a distance of 0.230 m.
A) Calculate the acceleration.
B) How long did the acceleration last?
Answer:
(A) 10052.2 m/s²
(B) 0.00678 seconds
Explanation:
From the question,
(A) Applying
V² = U²+2as..................... Equation 1
Where V = Final velocity, U = Initial velocity, a = acceleration due to gravity, s = distance.
make a the subject of the equation
a = (V²-U²)/2s........................ Equation 2
Given: U = 0 m/s( from rest), V = 68 m/s, s = 0.230 m
Substitute these values into equation 2
a = (68²-0²)/(2×0.230)
a = 10052.2 m/s²
(B) Using,
a = (V-U)/t......................... Equation 3
Where t= time.
make t the subject of the equation
t = (V-U)/a......................... Equation 4
Given: V = 68 m/s, U = 0 m/s, a = 10052.2
Substitute into equation 4
t = (68-0)/10052.2
t = 0.00678 seconds
What is the difference between a molecule ard
a compound ?
A car moves in a straight line at a speed of 55.4 km/h.
How long (in seconds) will it take the car to move 1.21 km at this speed?
55.4 km => 1hr (60 min) (60×60=120 sec)
1 km => 120 ÷ 55.4
1.21 km => (120 ÷ 55.4) × 1.21
= 2.6209 sec ( 5sf )
= 2.62 sec ( 3sf )
i hope you are able to understand my solution :))
Examine the resistor network. The answers to each of the questions can be either "none" or the numbers of one or more resistors. Which resistors are connected in parallel with resistor 2? Which resistors are connected in parallel with resistor 9? Which resistors are connected in parallel with resistor 11? Which resistors are not connected in parallel with any other resistors?
Answer:
parallel with 2: 1parallel with 9: 5, 6, 8parallel with 11: 4, 7not in a parallel branch: 3Explanation:
The attachments show the labeling of the network nodes. We found it convenient to do this so we could identify the specific nodes any given branch was attached to. Then the connections for each resistor were identified, and the list sorted to make it easier to see parallel connections.
Resistors 1 and 2 are in parallel
Resistors 5, 6, 8, 9 are in parallel
Resistors 4, 7, 11 are in parallel
No resistor has a parallel connection to resistor 3.
The earth is about 93,000,000 miles from the sun and traverses its orbit, which is nearly circular, every 365.25 days. What is the linear velocity of the earth in its orbit, in miles per hour? \
Answer:
10609.17miles per hr is the linear velocity
Explanation:
To arrive at Ans in miles per hr we first convert 365.25 days to hours
Which is 365.25 x24hrs per day= 8766hrs
So velocity= distance/time
So
93000000/8766= 10609.17miles per hr
009 10.0 points
A typical radio wave has a period of 1.5 microsecond
Express this period in seconds.
Answer in units of s.
1.5 microseconds means . . .
-- 1.5 millionths of a second
-- 1.5 x 10⁻⁶ second
-- 0.0000015 second
If an object accelerates at 40 m/s^2 in four minutes ("careful this is in minutes),
what will be the final velocity? (assume the object started from rest) *
Change in speed = (acceleration) x (time)
4 minutes = 240 seconds
Change in speed = (40 m/s²) x (240 seconds)
Change in speed = 9,600 m/s
What you're actually describing here is a car pulling 4 G's for 4 minutes, and ending up going 21,475 miles per hour.
The driver would definitely NOT get a speeding ticket, because nobody could catch him.
Also, his car would heat up and shoot flames from atmospheric friction.
(He could avoid this with some fancy steering, leave the atmosphere, and end up in low-Earth-orbit.)
Actually, I hope there's nobody in the car. His experience wouldn't be pretty.
A sled starts from rest,
and slides 10.0 m down a 28.0°
frictionless hill. What is its
acceleration?
(Unit = m/s2)
Answer:
The acceleration of the sled is [tex]4.6\ m/s^2[/tex].
Explanation:
It is given that,
Initial speed of sled is 0 because it was at rest.
It is placed at an angle of 28° on a frictionless hill.
We need to find the acceleration of the sled. It is placed at an incline. It means that the acceleration of the sled is given by :
[tex]a=g\sin\theta\\\\a=9.8\times \sin(28)\\\\a=4.6\ m/s^2[/tex]
So, the acceleration of the sled is [tex]4.6\ m/s^2[/tex].
Why do you think the temperature does not change much during a phase change? If possible, discuss your answer with your classmates and teacher.
Answer:
Explanation:
The fact is that there exists no temperature change until a phase change is complete. That is to say, during a phase change, the energy that will be supplied is used only to separate the molecules. There is no part of it is used to increase the kinetic energy of the molecules. So its temperature will not rise, not really, since the kinetic energy of the molecules remains the same. Also, it should be noted that the average kinetic energy of the molecules does not change at the moment that melting occurs, thus the temperature of the molecules does not change.
The average speed during any time interval is equal to the total distance of travel divided by the total time. Let d represent the distance between A and B. Let t1 be the time for which she has the higher speed of 5.15 m/s = d/t1. Let t2 represent the longer time for the return trip at 2.80 m/s =d/t2. Then the times are t1 = d/5.15 5.15 m/s and t2 = d/2.80 2.8 m/s. The average speed vavg is given by the following equation. vavg = Total distance/Total time = d + d/t1 + t2.
Answer:
Average speed = 3.63 m/s
Explanation:
The average speed during any time interval is equal to the total distance travelled divided by the total time.
That is,
Average speed = distance/ time
Let d represent the distance between A and B.
Let t1 be the time for which she has the higher speed of 5.15 m/s. Therefore,
5.15 = d/t1.
Make d the subject of formula
d = 5.15t1
Let t2 represent the longer time for the return trip at 2.80 m/s . That is,
2.80 = d/t2.
Then the times are t1 = d/5.15 5 and
t2 = d/2.80.
The average speed vavg is given by the following equation.
avg speed = Total distance/Total time
Avg speed = d + d/t1 + t2
Where
Total distance = 2d
Total time = t1 + t2
Total time = d/5.15 + d/2.80
Total time = (2.8d + 5.15d)/14.42
Total time = 7.95d/14.42
Total time = 0.55d
Substitute total distance and time into the formula above.
Avg speed = 2d / 0.55d
Avg Speed = 3.63 m/s
A parking lot is going to be 60 m wide and 240 m long. what dimensions could be used for a scale model of the lot?
Answer:
it is A or 20x80 cm
Explanation: DID IT ON APEX
WOO
The_____is the division of the atmosphere where the lapse rate decreases with altitude.
Answer:
Troposphere
Explanation:
The troposphere happens to be the lowest region amongst the atmosphere. It has a length that extends from the surface to a height of about 6–10 km. And that is the lower boundary of the stratosphere among the layers of the atmosphere
The troposphere in itself is bonded on the top by a layer of air tropopause. This layer is the one which separates the troposphere from the stratosphere, and on bottom by the surface of the Earth.
Given the displacement vector D = (2î − 6ĵ) m, find the displacement vector (in m) R so that D + R = −5Dĵ.
Answer:
R = (-2î − 6ĵ + 10k^)m
Explanation:
We are given;
D = (2î − 6ĵ)
Now, we want to find R such that,
D + R = −5Dĵ
Plugging in (2î − 6ĵ) for D in the R equation gives;
(2î − 6ĵ) + R = -5(2î − 6ĵ)j
(2î − 6ĵ) + R = -10k + 0
This is because in vector multiplication, i × j = k and j × j = 0
Thus;
(2î − 6ĵ) + R = -10k
Making R the subject gives;
R = -2î − 6ĵ + 10k^
Thus, the displacement vector R is;
R = (-2î − 6ĵ + 10k^)m
QUESTIONS
An ant walks eastward for 11.1 cm, then northward for 4,4 cm and finally westward for 11.1 cm. What is the magnitude of the displacement in cm Do
not include the units in your answer.
Answer:
4.4.
Explanation:
Hello,
In this considering the attached picture, we can see that the eastward movement is represented from O to A, the northward displacement from A to B and the westward displacement from B to C, which means that the resulting displacement is marked from O to C which includes the northwards movement since eastward and westward movement are the same.
In such a way, the magnitude of the displacement is simply 4.4 cm as no other dimension is taken into account due to the return to the same initial's x-axis position.
Regards-
A beam of light has a wavelength of 620 nm in vacuum.
a. What is the speed of this light in a liquid whose index of refraction at this wavelength is 1.56? (Use 3.00×108 m/s for the speed of light in a vacuum.)
b. What is the wavelength of these waves in the liquid?
Explanation:
It is given that,
Wavelength of a beam of light in vacuum, [tex]\lambda_o=620\ nm[/tex]
(a) Let v is the speed of light in a liquid whose index of refraction at this wavelength is 1.56.
We know that,
Refractive index,
[tex]n=\dfrac{c}{v}\\\\v=\dfrac{c}{n}\\\\v=\dfrac{3\times 10^8}{1.56}\\\\v=1.92\times 10^8\ m/s[/tex]
(b) The wavelength of light in material,
[tex]\lambda=\dfrac{\lambda_o}{n}[/tex]
Let [tex]\lambda_1[/tex] is the wavelength of these waves in the liquid. So,
[tex]\lambda_1=\dfrac{\lambda_o}{n}\\\\\lambda_1=\dfrac{620\times 10^{-9}}{1.56}\\\\\lambda_1=3.97\times 10^{-7}\ m[/tex]
Hence, this is the required solution.
How do you know if a boy like you?
Answer:
They cherish you
Explanation:
Answer:
They might mess with you. If you catch them looking at you they will look away quickly.
Explanation:
An object travels 7.5 m/s toward the west . Under the influence of a constant net force of 5.2 kN, it comes to rest in 3.2 s. What is its mass?
Answer:
m = 2218.67 kg
Explanation:
It is given that,
Initial velocity, u = 7.5 m/s
Final speed of an object, v = 0 (at rest)
Force, F = 5.2 kN
Time, t = 3.2 s
We need to find the mass of the object. Force acting on an object is given by :
F = ma
m is mass, a is acceleration
[tex]F=\dfrac{m(v-u)}{t}\\\\m=\dfrac{Ft}{v-u}\\\\m=\dfrac{5.2\times 10^3\times 3.2}{0-7.5}\\\\m=2218.67\ kg[/tex]
So, the mass of the object is 2218.67 kg
The force is always equal to the product of mass and acceleration. The mass of the object is 2218.7 Kg.
An object travels 7.5 m/s toward the west.
Under the influence of a constant net force of 5.2 kN, it comes to rest in 3.2 s.
Now,
The initial velocity of the object is 7.5 m/s.
The final velocity of the object is 0 m/s.
The object comes to the rest position in 3.2 seconds.
The formula for finding the acceleration of the object is mentioned below:
[tex]v=u+at\\0=7.5+a \times 3.2\\a= -2.34375\;\rm m/s^2[/tex]
The formula for finding the force is mentioned below:
[tex]F=ma\\-5.2 \times 10^3=m \times 2.34375\\m=2218.7 \ \;kg[/tex]
Hence, the mass of the object is 2218.7 Kg.
To know more about it, please refer to the link:
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A wooden cube of side 5cm float in water 2.0cm of its depth below the water surface and its sides are vertical calculate the density of the wood in gcm^-3. ( Density of water= 1gcm^-3)
Answer:
The density of the wooden cube is [tex]\delta= 0.4 \, \frac{g}{cm^3}[/tex]
Explanation:
Recall that the weight of the entire piece of wood that is floating must equal the weight of the displaced water in the case we have an object under flotation.
At the same time. we have a relationship between Volume (V), Weight (w) and density [tex](\delta)[/tex] given by the formula:
[tex]w=\delta\,*\,V[/tex]
Since both weights must be the same, we can write the following equation:
[tex]w_{wood} = w_{water}\\\delta *\,(5\,\,cm)^3= (\frac{1\,g}{cm^3} )\,(2\,*5^2) cm^3\\\delta= \frac{2}{5} \, \frac{g}{cm^3} \\\delta= 0.4 \, \frac{g}{cm^3}[/tex]
A pendulum built from a steel sphere with radius r cm 5 and density stl kg m S 3 7800 is attached to an aluminum bar with length l m 1 thickness t cm 0 8. and width w cm 4 and density . al kg m S 3 2820 a. Calculate the mass moment of inertia of the pendulum about its center of mass, . cm I b. Calculate the mass moment of inertia of the pendulum about its pivot point, o
Answer:
1) I_ pendulum = 2.3159 kg m² , 2) I_pendulum = 24.683 kg m²
Explanation:
In this exercise we are asked to calculate the moment of inertia of a physical pendulum, let's start by calculating the center of mass of each elements of the pendulum and then the center of mass of the pendulum
Sphere
They indicate the density of the sphere roh = 37800 kg / m³ and its radius
r = 5 cm = 0.05 m
we use the definition of density
ρ = M / V
M = ρ V
the volume of a sphere is
V = 4/3 π r³
we substitute
M = ρ 4/3 π r³
we calculate
M = 37800 4/3 π 0.05³
M = 19,792 kg
Bar
the density is ρ = 32800 kg / m³ and its dimensions are 1 m,
0.8 cm = 0.0008 m and 4cm = 0.04 m
The volume of the bar is
V = l w h
m = ρ l w h
we calculate
m = 32800 (1 0.008 0.04)
m = 10.496 kg
Now we can calculate the center of mass of the pendulum, we use that the center of mass of the sphere is its geometric center, that is, its center and the center of mass of the bar is where the diagonals intersect, in this case it is a very bar. long and narrow, whereby the center of mass is about half the length. It's mass scepter of the pendulum is
r_cm = 1 / M (M r_sphere + m r_bar)
M = 19,792 + 10,496 = 30,288 kg
r_cm = 1 / 30,288 (10,496 0.5 + 19.792 (1 + 0.05))
r_cm = 1 / 30,288 (5,248 + 20,7816)
r_cm = 0.859 m
This is the center of mass of the pendulum.
1) Now we can calculate the moment of inertia with respect to this center of mass, for this we can use the theorem of parallel axes and that the moments of inertia of the bodies are:
Sphere I = 2/5 M r2
Bar I = 1/12 m L2
parallel axes theorem
I = I_cm + m D²
where m is the mass of the body and D is the distance from the body to the axis of rotation
Sphere
m = 19,792 ka
the distance D is
D = 1.05 -0.85
D = 0.2 m
we calculate
I_sphere = 2/5 19.792 0.05 2 + 19.792 0.2 2 = 0.019792 +0.79168
I_sphere = 0.811472 kg m²
Bar
m = 10.496 kg
distance D
D = 0.85 - 0.5
D = 0.35 m
I_bar = 1/12 10.496 0.5 2 + 10.496 0.35 2 = 0.2186 + 1.28576
I_bar = 1.5044 kg m²
The moment of inertia is a scalar quantity whereby the moment of inertia of the body is the sum of the moment of the parts
I_pendulum = I_sphere + I_bar
I_pendulum = 0.811472 +1.5044
I_ pendulum = 2.3159 kg m²
this is the moment of inertia of the pendulum with respect to its center of mass located at r = 0.85 m
2) The moment is requested with respect to the pivot point at r = 0 m
Sphere
D = 1.05 m
I_sphere = 2/5 M r2 + M D2
I_sphere = 2/5 19.792 0.05 2 + 19.792 1.05 2 = 0.019792 +21.82
I_sphere = 21.84 kg m²
Bar
D = 0.5 m
I_bar = 1/12 10.496 0.5 2 + 10.496 0.5 2 = 0.21866 + 2.624
I_bar = 2,84266 kg m 2
The pendulum moment of inertia is
I_pendulum = 21.84 +2.843
I_pendulum = 24.683 kg m²
This moment of inertia is about the turning point at r = 0 m
which statement describes a characteristics of a question that can be answered through scientific inquiry?
Answer: it is constructed in such a way that possible answers can be tested
Explanation:
The statement that describes a characteristic of a question that can be answered through scientific inquiry is it can be answered through making observations. The correct option is B.
What is scientific inquiry?The goal of scientific inquiry is to establish answers for this phenomenon by a continuous and creative process of questioning, observing and inferring, experimentation, collecting and organising data, finding evidence, drawing conclusions, and repeating the experiment numerous times.
The following phrases define scientific inquiry:
Asking and responding to questions is the process of scientific research.Investigative work and data gathering are part of scientific inquiry.Similar procedures and techniques are used in a scientific investigation.Therefore, the correct option is B. It can be answered by making observations.
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The question is incomplete. Your most probably complete question is given below:
A. It can be answered by gathering opinions.
B. It can be answered through making observations
C. It must be asked by a person who is a working scientist.
D. It must have a simple “yes or “no” answer
To find Earth's equatorial rotation speed, we should divide the circumference of Earth by a 24 hours (1 day). To find the rotation speed at any other latitude, you need the following fact: The radial distance from Earth's axis at any latitude is equal to the equatorial radius times the cosine of the latitude. (Hint: When using the cosine (cos) function, be sure your calculator is set to recognize angles in degree mode, not in radian or gradient mode.) The radius of Earth is 6380 kilometers. Vi = 1370 km/hr
Find the rotation speed for a person at latitude 35°N.
Answer:
The value is [tex]v = 1370 km /hr [/tex]
Explanation:
From the question we are told that
The radius of the Earth is [tex]R = 6380 \ km[/tex]
The latitude is [tex]35^o N[/tex]
Generally the Earth's equatorial rotation speed is mathematically represented as
[tex]v_e = \frac{C}{t}[/tex]
Here C is the circumference which is mathematically represented as
[tex]C = 2 * \pi * R [/tex]
=> [tex]C = 2 * 3.142 * 6380 [/tex]
=> [tex]C = 40091.92 [/tex]
t is the time which is mathematically represented as
t = 24 h
So
[tex]v_e = \frac{40091.92}{24}[/tex]
=> [tex]v_e = 1670.5 \ km/h[/tex]
Generally the rotation speed for a person at latitude 35°N. is mathematically represented as
[tex]v = v_e cos (35)[/tex]
=> [tex]v = 1368 [/tex]
=> [tex] v \approx 1370 km/hr [/tex]
Calculate the total distance traveled (in m)
Answer:
Distance is 13m and Displacement is 9m
Explanation:
With all his gear, Neil Armstrong weighed 360 pounds on Earth. When he landed on the Moon, he weighed 60 pounds. Why?
Answer:C: The gravity on the moon is less than the gravity on Earth.
Explanation:
The fastest man alive can run the 100 meter dash in 9.58 seconds, calculate average speed in meters per second
Answer:
100 ÷ 9.58 = 10.44 (approximate answer)
What is the difiniton of absolute value in science
Answer: The absolute value of a number is symbolized by two vertical lines as 3 or -3
Please pick me as brainliest please
Answer: the magnetic of a real number without regard to its sign
Explanation: In mathematics, the absolute value or modulus of a real number x, denoted |x| or, is the non-negative value of x without regard to its sign. Namely, |x| = x if x is positive, and |x| = −x if x is negative, and |0| = 0. For example, the absolute value of 3 is 3, and the absolute value of −3 is also 3
How do very small objects behave?
a. like particles
b. like waves
c. like both waves and particles
d. like neither waves nor particles
Answer:
A) PARTICLES
Explanation:
VERY SMALL OBJECTS ARE BEHAVE LIKE A PARTICLES.
HOPE IT HELP.....❤❤A psychologist has to obtain a medical degree to diagnose and treat people with disorders.
Please select the best answer from the choices provided
T
F
Answer:
False
Explanation:
A psychologist is a person who deals with normal and abnormal mental states, emotional, and social processes and behavior of an individual in relation to one another and to their environments.
Individuals with a master's degree in psychology can work as industrial-organizational psychologists
A psychologist is not required to obtain a medical degree to diagnose and treat people with disorders.
So, the given statement is false.
Answer:
false
Explanation:
Convert 7 (gcm^2)/(min^2) into a value in standard S.I. units. Be sure to use scientific notation if necessary. You do not need to answer units.
The required value is required in SI units.
The required answer is [tex]1.94\times10^{-10}\ \text{kg m}^2/\text{s}^2[/tex]
SI unitsThe SI unit of mass, length and time is kg, m and s respectively.
In order to convert one unit into another it has to be multiplied or divided by the conversion factors.
A definite magnitude which has some quantity which is defined by convention or law is called a unit.
The conversion factors are
[tex]1\ \text{g}=10^{-3}\ \text{kg}[/tex]
[tex]1\ \text{cm}=10^{-2}\ \text{m}[/tex]
[tex]1\ \text{cm}^2=10^{-4}\ \text{m}^2[/tex]
1 min = 60 s
[tex]1\ \text{min}^2=60\times60\ \text{s}^2[/tex]
So,
[tex]7\ \text{g cm}^2/\text{min}^2=7\times \dfrac{10^{-3}\times 10^{-4}}{60\times 60}\\ =1.94\times10^{-10}\ \text{kg m}^2/\text{s}^2[/tex]
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What caused the formation of the East African Rift Zone?
Answer: divergent plate
Explanation: the East African Rift Valley (EAR) is a developing divergent plate boundary in East Africa. Here the eastern portion of Africa, the Somalian plate, is pulling away from the rest of the continent, which comprises the Nubian plate.
Answer:
Lake Victoria sits between these two branches. It is thought that these rifts are generally following old sutures between ancient continental masses that collided billions of years ago to form the African craton and that the split around the Lake Victoria region occurred due to the presence of a small core of ancient metamorphic rock, the Tanzania craton, that was too hard for the rift to tear through. Because the rift could not go straight through this area, it instead diverged around it leading to the two branches that can be seen today.
Explanation:
A velocity time graph shows how____ changes over time
Answer: A velocity-time graph shows how velocity changes over time
Explanation:
Answer:velocity
Explanation: