Explain step by step how
to estimate the square root
of 13 and show your work

Answer:

15%

Step-by-step explanation:

Percent increase in the original price of jacket = 15%

Percentage is defined as a given part or amount in every hundred. It is a fraction with 100 as the denominator and is represented by the symbol "%".

Given,

Original price of jacket = $110

Increased price of jacket = $126.5

Increased amount = $126.5 - $110

                               = $16.5

Increased amount in percentage = ($16.5/$110) × 100

                                                       = 0.15 × 100

                                                       = 15%

Hence, 15% is increase in the original price of jacket.

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Answer:

see attached image

Step-by-step explanation:

To write 28 + 24 as a product of two factors, we need to determine the HCF of the addends (28 and 24). This can be done by listing the factors of the addends. The greatest factor that is common in 28 and 24 is the HCF.

If the number is in bolded text, the number is a common factor.

Since 4 > 2 > 1, the HCF is 4.

Now, let us put the provided expression between parentheses.

Finally, factor four out of the expression, as it is the GCF of 28 and 24.

Therefore, 28 + 24 as a product of two factors is 4(7 + 6).

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Answer:

12 is johns age

Step-by-step explanation:

all you have to do is multiply johns age times 3 then you get your anser

Answer:

the distance between the CD points is 5

Step-by-step explanation:

(-4,-6) (1,6)

it takes 4 to get from -4 to 0 plus 1 to get to 1

so 4+1=5

Answer:

D) (f o g)(x) = 10x² - 60x + 93

Step-by-step explanation:

f(x) = 10x² + 3

g(x) = x - 3

⇒ (f o g)(x)

⇒ f(x - 3)

⇒ f(x - 3) = 10(x - 3)² + 3

⇒ f(x - 3) = 10(x² - 6x + 9) + 3

⇒ f(x - 3) = 10x² - 60x + 90 + 3

⇒ (f o g)(x) = 10x² - 60x + 93

Answer:

[tex]\textsf{D)} \quad (f \circ g)(x)=10x^2-60x+93[/tex]

Step-by-step explanation:

[tex]\textsf{If }\:f(x)=10x^2+3\:\textsf{ and }\:g(x)=x-3\:\textsf{ then}:[/tex]

[tex]\begin{aligned}(f \circ g)(x) & = f[g(x)]\\ & = f(x-3)\\& = 10(x-3)^2+3\\& = 10(x^2-6x+9)+3\\& = 10x^2-60x+90+3\\& = 10x^2-60x+93\\\end{aligned}[/tex]

Answer:

Step-by-step explanation:

Area of a triangle is a*b divided by 2

Lets assume a = 8 and b= 9

8 *

9=72

72/2=36

Answer:

P = 0.5Q - 20

Step-by-step explanation:

P = kQ + c

substitute Q = 60 , P = 10 into the equation

10 = 60k + c → (1)

substitute Q = 240, P = 100 into the equation

100 = 240k + c → (2)

subtract (1) from (2) term by term to eliminate c

90 = 180k ( divide both sides by 180 )

[tex]\frac{90}{180}[/tex] = [tex]\frac{1}{2}[/tex] = 0.5 = k

substitute k = 0.5 into (1) and solve for c

10 = 60(0.5) + c

10 = 30 + c ( subtract 30 from both sides )

- 20 = c

then

P = 0.5Q - 20

Answer:

3052.08

Step-by-step explanation:

Answer:

Step-by-step explanation:

1[tex]\frac{1}{2}[/tex]=1×[tex]\frac{2}{2}[/tex], +[tex]\frac{1}{2}[/tex]

(-[tex]\frac{3}{2}[/tex])÷[tex]\frac{3}{4}[/tex]×(-[tex]\frac{2}{3}[/tex])

[tex]\frac{3}{2}[/tex]×[tex]\frac{4}{3}[/tex]×[tex]\frac{2}{3}[/tex]

[tex]\frac{1}{2}[/tex]×4×[tex]\frac{1}{3}[/tex]

4×[tex]\frac{1}{3}[/tex]=[tex]\frac{1}{3}[/tex]+[tex]\frac{1}{3}[/tex]+[tex]\frac{1}{3}[/tex]+[tex]\frac{1}{3}[/tex]

=[tex]\frac{4}{3}[/tex]

The names of this polygon include:

The polygon given has three sides which means that it is a triangle. It is an acute triangle because the angles are all less than 90°.

It is also a scalene triangle because all the sides have different lengths from each other.

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Answer:

Step-by-step explanation:

I: acute triangle

L: Isosceles triange

(sorry if im wrong i have not done this in a good few years lol)

The volume of the given cylinder.

First, we'll have to find the raduis.

[tex]d = 2r [/tex]

[tex]r = \frac{12}{2} [/tex]

[tex]r = 6 \: in [/tex]

Now, we can work out the volume.

[tex]V = \pi {r}^{2} h[/tex]

[tex]V = \pi \times {6}^{2} \times 13[/tex]

[tex]V = 1470.26536 \: {in}^{3} [/tex]

[tex]\large\boxed{\sf{V = 1470.3 \: {in}^{3}}}[/tex]

Hence, the volume of the given cylinder is 1470.3 cubic inches.

Answer:

4 days

Step-by-step explanation:

Answer:

D)

Step-by-step explanation:

Kevin starts with 0 poems but increases 3 each day

Let kevin = x

y = 3x

Anita has 4 poems to start with but increases 2 each day

Let anita = y

y = 2x + 4

As seen on this graph:

The point of intersection is (4,12)

The x axis being the number of days.

Thus the answer is D)

Answer: 3

Step-by-step explanation: This equation can be written as 4x+3x-4=17

We can now solve.

Moving the 4 to the other side (adding) and we get 21.

Now we have 4x+3x. Adding like terms, we get 7x = 21. Now we divide by 7.

X = 3.

Answer:

8 and 48

Step-by-step explanation:

Here is how to find it mathematically

x = one number     6x = other number    ( because 3x is 1/2 of x)

(x + 6x) /2 = 28

7x = 56

x = 8     then 6x = 48

The radius of the yaw mark to the nearest tenth of a foot is 11.2 ft

The minimum speed  11.1634 miles per hour.

Yaw marks are always curved. They are, initiated by a steering input. They're what's left from a tire that is still rolling but is simultaneously sliding laterally.

The formula for determining radius from a chord and middle ordinate is

[tex]r^{2}= \frac{c^{2}}{8m}+\frac{m}{2}[/tex]

To find the radius of the yaw mark, we have to use the formula

[tex]r^{2}= \frac{c^{2}}{8m}+\frac{m}{2}[/tex]

where c is the length of the chord and m is the middle ordinate

As the tires leave a yaw mark with a 31 foot chord and a middle ordinate of 3 feet.

So,

[tex]r^{2}= \frac{31^{2}}{8*3}+\frac{3}{2}[/tex]

[tex]r^{2}= 40.041 +1.5\\r^{2}=41.541[/tex]

Now to find the minimum speed, we are going to use the formula: [tex]s=\sqrt{15fr}[/tex]

where 'f' is drag factor and 'r' is the radius

drag factor is 0.2, f=0.2

and r= 41.541 ft

So, [tex]s=\sqrt{15* 0.2*41.541}\\s=\sqrt{124.623}\\s= 11.1634 mph[/tex]

The minimum speed before the brakes are applied was 11.1634 miles per hour.

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Answer:

  96 ft³

Step-by-step explanation:

A graphing calculator conveniently graphs this function. It shows the maximum volume is about 96 ft³.

Done

[tex] \pink{\underline{\boxed{8a²+a-7}}}[/tex]

Solution :-

[tex]\Longrightarrow\sf{(3a ^2 + 2a) + (5a^2 -a-7)}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\Longrightarrow\sf{3a^2+ 2a + 5a^2-a-7}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\Longrightarrow\sf{8a^2+2a-a-7}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex] \Longrightarrow\sf{8a^2+1a-7}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: [/tex]

[tex]\Longrightarrow\sf{8a^2+a-7}[/tex]

[tex]\red{━━━━━━━━━━━━━━━━━━━━━━}[/tex]

Answer:

I would edit this answer and tell you what I hope would be the correct answer if you give me the problem you are confused with

Step-by-step explanation:

I can't help you otherwise

Sorry

Answer:

[tex]0 \leqslant x \leqslant 20[/tex]

The expression that can be use to find the difference between the fraction of money Amar put in the bank and the fraction he spent on the book is 4 / 7 x - 1 / 3 x

Amar put 4/7 of the money he earned raking leaves in the bank. Therefore,

let the money she earned = x

Hence,

amount put in bank = 4 / 7 x

She spent 1 / 3 of the money on books. Therefore,

money spent on books = 1 / 3 x

Therefore, the expression that can be use to find the difference between the fraction of money Amar put in the bank and the fraction he spent on the book is as follow:

4 / 7 x - 1 / 3 x

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Answer:

if each was used only once, the answer would be 52080

Step-by-step explanation:

Answer:

Graph D

Step-by-step explanation:

Graph D is the graph of -2x + y < 5

Answer:

22.5¢ per oz

Step-by-step explanation:

24 oz cost = $5.30

1 oz cost = $5.40/24 = 22.5¢ per oz

Answer:

0.22.5

Step-by-step explanation:

Answer:

y = 5x-17

Step-by-step explanation:

point slope form would be

y- -2   =  5(x-3)        or  re-arrange to:    y = 5x -17

The function h(x) is a translation of the exponential function [tex]g(x) = 2(3)^{x - 4}[/tex] , is  [tex]h(x) = 4(3)^{x + 7} - 9[/tex]

When the expression of function is such that it involves the input to be present as an exponent (power) of some constant, then such function is called exponential function.

There usual form is specified below. They are written in several such equivalent forms.

The function h(x) is a translation of the exponential function given as

[tex]g(x) = 2(3)^{x - 4}[/tex]

We have to determine, the h(x) if the translation is a vertical stretch by a factor of 2, a vertical shift upward of 9 units, and a horizontal shift to the right 7 units.

The function h(x) is vertically stretched by 2.

  [tex]h(x) = 2 (2(3)^{x - 4})\\\\h(x) = 4((3)^{x - 4})[/tex]      

Vertically shift upward by 9,

[tex]h(x) = 4((3)^{x - 4})\\\\h(x) = 4((3)^{x - 4})- 9[/tex]                    

And a horizontal shift to the right 7 units,

[tex]h(x) = 4((3)^{x - 7})- 9[/tex]                    

The function h(x) is a translation of the exponential function [tex]g(x) = 2(3)^{x - 4}[/tex] , is  [tex]h(x) = 4(3)^{x + 7} - 9[/tex]

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