Explain a situation in which a lighter object would take more work to move than a heavier object

Answer:

F = 5.9 N

Explanation:

Given that,

Mass of water, m₁ = 1000 kg

Mass of the Sun, [tex]m_2=1.99\times 10^{30}\ kg[/tex]

Distance between two bodies, [tex]r=1.5\times 10^{11}\ m[/tex]

We need to find the force of gravity between water and the Sun. The formula for the gravitational force between two bodies is given by :

[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1000\times 1.99\times 10^{30}}{(1.5\times 10^{11})^2}\\\\F=5.89\ N[/tex]

or

F = 5.9 N

Hence, the correct option is (b).

Answer:

37.5 N*m

Explanation:

w=fd

w=?

f=25 N

d=1.5 m

w=25N*1.5m=37.5 N*m

Answer:

5m/s²

Explanation:

Given parameters:

Mass of wagon  = 10kg

Force of pull  = 70N

Frictional force = 20N

Unknown:

Acceleration of the wagon = ?

Solution:

Frictional force is a force that opposes motion.

The net force is given as:

   Net force  = mass x acceleration

 Force of pull  - Frictional force = mass x acceleration

 Insert the parameters and solve;

     70 - 20  = 10 x acceleration

       50  = 10 x acceleration

      Acceleration  = 5m/s²

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Answer:

The answer is "[tex]\boxed{\boxed{\omega = \sqrt{\frac{2fd}{kmr^2}}}}[/tex]"

Explanation:

[tex]\to d= r \theta \\\\ \to \theta =\frac{d}{r}\\\\\to \omega^{r} - \omega_{0}^{r} = 2 \alpha \theta\\\\\to \omega^{r} = 2 \alpha \theta - \omega_{0}^{r} \\\\\to \omega^{r} = 2 (\frac{F}{Kmr}) \frac{d}{r}\\\\\to \omega = \sqrt{\frac{2fd}{kmr^2}}[/tex]

The angular velocity of the wheel is  [tex]\omega=\sqrt{\frac{Fd}{mkr^2} }[/tex]

Given that the force applied is F, and the displacement of the string is d.

If the radius of the wheel is r and the wheel has an angular displacement of θ, then:

d = rθ

θ = d/r

now, the angular acceleration is given by:

α = F/mkr

The initial angular velocity will be zero and let the final angular velocity is ω.

According to the third equation of motion:

ω² = 0 + 2αθ

ω² = 2(F/mkr)(d/r)

[tex]\omega=\sqrt{\frac{Fd}{mkr^2} }[/tex]

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Answer:

27000 J

Explanation:

Answer:

d

Explanation:

it is never stated in science

Objects of the same size will accelerate equally if they have different forces applied to them. This statement (D) does NOT apply to Newton’s second Law of Motion.

Newton’s second law of motion states that “Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.

As momentum is product of mass and velocity, the more mass something has, the more force it would take to accelerate it.  So option (A) is correct.

As rate of change of momentum of a body refers product of mass and acceleration of a body,  the more force applied to an object’s mass, the more it will accelerate and the force required to accelerate an object equals the objects mass times it’s acceleration. So, option (B) and (C) is correct.

But  force has no direct elation with size of the body. So, option (D) is not correct.

Learn more about Newton's second law of motion here:

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Answer:

nitric acid

Explanation:

because it is a solvent

Answer:

acetic acid

Explanation:

Not sure but I think so :) hope its right and helps

Answer:

C

Explanation:

Answer:

A

because volcano can produce sediment and

erodus rock

Answer:

C Iqaluq's observation belies a wider phenomenon. In summer 2020, due to intense summer heat, sea ice in the Arctic melted to its second-lowest extent on record.

Explanation:

Logic refers to the use of evidence to support one's argument. Statistics, facts, and data are used to back up the writer's argument. In the third option, the writer uses facts and figures to support his argument. He cited data on the Arctic melting in the summer of 2020.

The importance of logical reasoning is that the reader can reach a conclusion through the premises cited by the author. It is even more beneficial if the premises are data that can be verified.

Answer:

It is d

Explanation:

Answer:

D !!!!!

Explanation:

Electromagnetic powers versus Molecules:  

Electrons are kept in the circle around the core by the electromagnetic power, in light of the fact that the core in the focal point of the particle is decidedly charged and pulls in the contrarily charged electrons.  

Solid Nuclear power versus Molecules:  

The solid atomic power holds most standard issue together on the grounds that it limits quarks into hadron particles, for example, the proton and neutron.  

Feeble power versus Molecules:  

In atomic material science and molecule physical science, the frail cooperation, which is additionally frequently called the powerless power or feeble atomic power, is the instrument of communication between subatomic particles that is liable for the radioactive rot of iotas.  

Gravity Vs. Particles:  

Gravity influences molecules a similar way it influences all other issue. Each iota makes its own gravitational field which draws in all other issue known to man.

Answer:

D. A difference in resistance

The answer is infrared.

Answer:it’s the graph starts on the origin but is going down

Explanation: khan academy

Answer:

k nishant

Explanation:

the answer is option B

Answer:

Explanation:

The mass of the car can be found by using the formula

[tex]m = \frac{2k}{ {v}^{2} } \\ [/tex]

From the question we have

[tex]m = \frac{2 \times 300000}{ {20}^{2} } = \frac{600000}{400} = \frac{6000}{4} \\ [/tex]

We have the final answer as

Hope this helps you

Answer: it eventually cracks the rock and breaks pieces of the rock off

Explanation:

Answer:

Abiotic referfers to non-living and biotic factors are living or once living

Explanation:

Answer:

Explanation:

(b) The initial velocity is added to that due to acceleration by gravity. The velocity is increased linearly by gravity at the rate of 9.8 m/s². The average velocity of the pebble will be its velocity halfway through the 2-second time period.* That is, it will be ...

  4 m/s + (9.8 m/s²)(2 s)/2 = 13.8 m/s . . . . average velocity

__

(a) The distance covered in 2 seconds at an average velocity of 13.8 m/s is ...

  d = vt

  d = (13.8 m/s)(2 s) = 27.6 m

The water is about 27.6 m below ground.

_____

* We have chosen to make use of the fact that the velocity curve is linear, so the average velocity is half the sum of initial and final velocities:

  vAvg = (vInit + vFinal)/2 = (vInit + (vInit +at))/2 = vInit +at/2

__

If you work this in a straightforward way, you would find distance as the integral of velocity, then find average velocity from the distance and time.

  [tex]\displaystyle d=\int_0^t{(v_0+at)}\,dt=v_0t+\dfrac{1}{2}at^2=t\left(v_0+a\dfrac{t}{2}\right)\\\\v_{avg}=\dfrac{d}{t}=v_0+a\dfrac{t}{2}\qquad\text{the formula we started with}[/tex]

Answer:

Explanation:

To find the amplitude of the sound, we must first determine the wavelength and the phase difference between the two speakers.

For the wavelength;

Recall that, the separation between two successive max. and min. intensity points are [tex]\dfrac{\lambda}{2}[/tex]

Thus; for both speakers; the wavelength of the sound is:

[tex]\dfrac{\lambda}{2} = (10+30) cm[/tex]

[tex]\dfrac{\lambda}{2} = (40) cm[/tex]

λ = 80 cm

The relation between the path difference(Δx) and the phase difference(Δ∅) is:

[tex]\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o[/tex]

where;

Δx = 10 cm

λ = 80 cm

Δ∅ = π rad

∴

[tex]\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o[/tex]

[tex]\pi \ rad = \dfrac{2 \pi}{80 \ cm}(10 \ cm) + \Delta \phi_o[/tex]

[tex]\pi \ rad = \dfrac{2 \pi}{8}+ \Delta \phi_o[/tex]

[tex]\pi \ rad = \dfrac{ \pi}{4}+ \Delta \phi_o[/tex]

[tex]\Delta \phi_o = \pi -\dfrac{ \pi}{4}[/tex]

[tex]\Delta \phi_o = \dfrac{ 4\pi - \pi}{4}[/tex]

[tex]\Delta \phi_o = \dfrac{ 3\pi}{4} \ rad[/tex]

Suppose both speakers are placed side-by-side, then the path difference between the two speakers is: Δx = 0 cm

Thus, we have:

[tex]\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o[/tex]

[tex]\Delta \phi = \dfrac{2 \pi}{\lambda}(0 \ cm ) + \dfrac{3 \pi}{4} \ rad[/tex]

[tex]\Delta \phi = \dfrac{3 \pi}{4} \ rad[/tex]

∴

The amplitude of the sound wave if the two speakers are placed side-by-side is:

[tex]A = 2a \ cos \bigg (\dfrac{\Delta \phi }{2} \bigg)[/tex]

[tex]A = 2a \ cos \bigg (\dfrac{\dfrac{3 \pi}{4} }{2} \bigg)[/tex]

[tex]A = 2a \ cos \bigg ({\dfrac{3 \pi}{8} } \bigg)[/tex]

A = 0.765a

The expressions for sound interference allows to find the amplitude for the wave when the two speakers are together is:

Given parameters

To find

The interference phenomenon occurs when two coherent waves have paths of different lengths to reach a point, we have two extreme cases:

                        Δr = [tex]2n \ \frac{\lambda}{2}[/tex]  

                        Δr = [tex](2n+1) \ \frac{\lambda}{2}[/tex]  

Where Δr₁ and Δr₂ are the path difference, λ is the wavelength and n is an integer.

Let's start by looking for the wavelength that the speakers emit, see attached.

Destructive Interference       Δr₂ = (2n + 1) la / 2

Constructive interference    Δr₁ = 2n lam / s

Let's solve the system.

               Δr₂ - Δr₁ = [tex]\frac{\lambda}{2}[/tex]  

Let's calculate

              30 - (-10) = [tex]\frac{\lambda}{2}[/tex]  

              λ = 80 cm

Now we can use the general relation for the path change and the phase.

             [tex]\frac{\delta r}{\lambda } = \frac{\phi - \phi_o}{2\pi }[/tex]

             [tex]\phi = \frac{\Delta r \ 2\pi }{\lambda } + \phi_o[/tex]fi = Dr 2pi / lam + fio

Where [tex]\phi[/tex] is the possible initial phase difference between the speakers.

Let's find the initial phase difference emitted by the two speakers, let's use destructive interference, for which the phase difference is:

             [tex]\phi = \pi \ rad[/tex]  

Let's calculate

             [tex]\pi = \frac{2\pi }{80} \ 10 + \phi_o \\\phi_o = \pi - \frac{\pi}{4}[/tex]

              [tex]\phi_o[/tex]  = ¾ [tex]\pi[/tex] rad

This value is kept constant, let's find the phase angle for when the speakers are together, so the path difference is zero Δr = 0      

            [tex]0= \frac{\phi - \phi_o}{2\pi }\\\phi = \phi_o[/tex]

            [tex]\phi[/tex] = ¾ pi

The amplitude of the sound wave is

            A = 2a cos [tex]\frac{\phi}{2}[/tex]  

            A = 2a cos ⅜ π

           A = 0.765 a

In conclusion using the expression for sound interference we can find the amplitude for the wave when the two speakers are together is:

           A = 0.765a

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Answer:

π/2 radians.

Explanation:

Angular Displacement

It's the angle expressed in radians, degrees, revolutions, etc. through which a point revolves around a point called the center.

To find the angular displacement, we must recall a full revolution, or turn around the center measures 360 degrees, or 2π radians.

The Earth completes a turn every 24 hours. This means that in 6 hours, it has given 6/24 = 1/4 of a turn.

This means that, measured in radians, the angular displacement of a person during 6 hours is:

1/4*2π radians

Simplifying:

π/2 radians.

Answer:The answer is circular orbits I hope this helps

Explanation:

Answer:

Oppenheimer suggested that the bomb laboratory operate secretly in an isolated area but allow free exchange of ideas among the scientists on the staff.

Explanation:

Answer:

1 white blood cells

2 thyroid

3 bones

4 smooth, cardiac, skelatal