EXPERIMENT: COMPARING HARDNESS AND DENSITY OF SOLIDS 100 POINTS I NEED THIS DONE
In this activity, you will identify several minerals, then you will compare the minerals to determine if there is a relationship between the hardness of a sample and its density. You should consider the factors that determine the density and the hardness of a material and then form a hypothesis as to whether you believe these two properties will show a correlation. If they show a correlation, it may indicate that one property depends on or is in some way related to the other property. You should consider this in making your hypothesis. If two properties have a positive correlation, then the graph of their values will be a straight line. You will use this fact to test the accuracy of your hypothesis.
OBJECTIVES
Use several tests, including hardness to identify 6 minerals.
Using hardness and density data, creating a graph.
Explain how to interpret a positive or negative correlation between graphed values.
Answers
Answer:
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Answer: My hypothesis was that the future results of the experiment would show a correlation. According to my data, my hypothesis was correct. The file uploaded to this assignment shows that the graph is a correlation but not a 100% positive correlation because if you imagined there was a straight line there, the points would be completely aligned. The correlation is simply a “positive correlation”. Some of the difficulties I had when performing the experiment was distinguishing which type of luster was for each mineral because the light almost looked the same with other minerals. You might change the procedure to avoid this problem in the way of getting all the rest of the results for that specific mineral and then look at which of the graph with the answers was most alike and then you can see why the luster is that certain result in that data which is the correct one. A graphical analysis can be used to explore the relationship between any two scientific variables by changing the numerical data of the experiment into a graph, which is a much more effective and easier way of interpreting the gathered results. It's easier to visualize a graph data than read all the tables with numbers.
The graph is in the attachment below and the 6 minerals also with their names, their density, and their hardness
Related Questions
Calculate the force of attraction between Mars and one of its moon named Phobos given that the mass of Phobos is 10.6 x 1015 kg and the distance from Mars is 9,376 km (convert to m). Mars has a mass 10.7% that of Earth (approx. 1/10th the mass of Earth).
Answers
The force of attraction between Mars and one of its moon; F= 5.16*10²¹
What does gravity mean?The gravitational force is the force that the earth exerts on a body to attract it. Examples of motion caused by gravitational force include the downward motion of water in rivers and streams, the upward motion of thrown objects such as balls, and the downward motion of the leaves and fruits of trees as they fall to the earth.
What is a phobos?"The bigger of Mars' two moons, Phobos, measures 17 x 14 x 11 miles (27 x 22 x 18 kilometers) in diameter. It makes three daily circuits around Mars and is so near the planet's surface that it cannot always be seen there."
according to data:The product of mass and mass is directly proportional to the gravitational force between two large objects. The gravitational attraction between Mars and Phobos is.
Newton's law of universal gravitation: Fg = Gm1m2/r2
Where,
F = Force =
G = Gravitational constant = 6.6743 × 10-11 N.m²/kg²
m2 = Mass of Mars = 6.42 x 10²³ (approx 10.7 % of Earth)
m2 = Mass of Phobos = 10.6 x 1015 r = Distance between centers of the masses= 9,376 km
Put the values in the formula,
F = 6.6743 * 10-11 * [tex]\frac{6.42 x 10^2^3 * 10.6 x 10^1^5}{ 9,376^2}[/tex] F= 5.16*10²¹
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Calculate the energy needed to raise the temperature of 1 kg of lead (specific heat capacity of 130 J/kg °C) from 40.0 °C to 60.0 °C
Answers
The energy needed to raise the temperature of 1 kg of lead from 40 °C to 60°C will be 2600 Joules.
We can calculate the energy of a substance by using the given formula:
Q = mc∆T
where;
Q = quantity of heat absorbed or released
m = mass of the substance
c = specific heat capacity
∆T = change in temperature(°C)
Now, according to the given question, 1 kg of lead has to be raised from 40°C to 60°C and we also have the specific heat capacity(c) of lead that is 130J/kg°C.
We can calculate the energy by putting the given values in the above equation:
Q = mc∆T
= 1 × 130 × (60-40)
= 20 × 130
Q = 2600J
Therefore, the amount of energy required to raise the temperature of 1 kg of lead from 40°C to 60°C is 2600J.
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Help number five physics In the three diagrams, the circles represent small balls that carry electric charges. In Diagram A, ball 1 carries a negative charge, and ball 2 is repelled byball 1. In Diagram B, we see that ball 2 now repels ball 3. In Diagram C, we see that ball 3 now attracts ball 4. Based on these diagrams, what is theelectric charge on ball 4?
Answers
Question 5
Given:
Ball 1 has negative charge.
Ball 2 is repelled by ball 1.
Ball 2 repels ball 3.
Ball 3 attracts ball 4.
To find the electric charge on ball 4.
Explanation:
Like charges repel each other.
Example - Positive and positive charge repel each other.
Also, negative and negative charge repel each other.
Unlike charges attract each other.
Positive and negative charge attract each other.
In the first diagram, ball 1 and ball 2 repel each other which means ball 2 has negative charge.
In the second diagram, ball 2 and ball 3 repel each other which means ball 3 has negative charge.
Now, in the diagram 3, ball 3 and ball 4 attract each other which means ball 4 has positive charge.
Thus, ball 4 has positive charge.
Module 1 question 12
Assume that an MX missile goes from rest to a suborbital velocity of 3.50 km/s in 40.0 s (the actual speed and time are classified). What is its average acceleration in m/s2?
m/s2
What is its average acceleration in multiples of g?
g
Answers
The average acceleration of the MX missile is 87.5 m/s^2. The average acceleration in multiples of g is 8.9g.
The rate at which the velocity changes is known to as average acceleration. To determine the average acceleration of an object, we divide the change in velocity by the amount of time that has passed. The formula of acceleration is,
a = (v_f - v_i)/t
Where a = acceleration, v_f = final velocity, v_i = initial velocity and t = time.
Here, the initial velocity is zero, final velocity is 3.5 km/s and time is 40.0 seconds. The acceleration will be
a = (3.50*1000 - 0)/40.0
a = 3500/40
a = 87.5 m/s^2
The value of acceleration due to gravity (g) is 9.8 m/s^2. The acceleration of the MS missile in multiples of g is,
a = 87.5/9.8
a = 8.9g
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A 55.0-kg person steps on a scale which is on a horizontal floor. What is the normal force acting on the individual by the scale?
Answers
ANSWER:
-539 N
STEP-BY-STEP EXPLANATION:
We know that the normal force is the force opposite to the force exerted by the weight, therefore, we can calculate the normal force as follows:
[tex]\begin{gathered} F_N=-W \\ W=m\cdot g \\ F_N=-m\cdot g \\ \text{ replacing:} \\ F_N=-55\cdot9.8 \\ F_N=-539\text{ N} \end{gathered}[/tex]The normal force is -539 N
Mario drives his Kart at an average speed of 42 miles per hour for 1.7 minutes. How far does he drive? Include units in your answer. More information.Note: For this question and all questions on subsequent WebAssignments, answers to problems should have three significant digits and should include proper units.
Answers
Given:
The speed of Mario's kart is
[tex]v=42\text{ miles/h}[/tex]To find:
How far does he drive in 1.7 minutes?
Explanation:
The speed is,
[tex]\begin{gathered} v=42\text{ miles/h} \\ =42\times1.6\text{ km/h} \end{gathered}[/tex]The distance Mario drives is,
[tex]\begin{gathered} d=vt \\ =42\times1.6\times\frac{1.7}{60}\text{ km} \\ =1.90\text{ km} \end{gathered}[/tex]Hence, the required distance is 1.90 km.
module 2 question 11
A knife is dropped from the top of a 15.0 m high mast on a ship moving at 1.73 m/s due south.
(a) Calculate the velocity of the knife relative to the ship when it hits the deck of the ship.
m/s (down)
(b) Calculate the velocity of the knife relative to a stationary observer on shore.
m/s
° (below the horizontal to the south)
(c) Discuss how the answers give a consistent result for the position at which the knife hits the deck.
Answers
If a knife is dropped from 15.0 m high on a ship moving at 1.73 m / s
The velocity of the knife relative to the ship on the deck = -17.15 m/sThe velocity of the knife relative to a stationary observer = 17.24 m/sFor an observer on the ship, it will appear as the knife is falling straight down. So, for an observer on the ship, the knife will not have a horizontal component.
u = 0
a = - 9.8 m / s²
s = - 15 m
v² = u² + 2 a s
v² = 0 + ( 2 * - 9.8 * - 15 )
v² = 294
v = ± 17.15 m / s
[tex]v_{y}[/tex] = - 17.15 m / s ( Since it is moving downwards )
For an stationary observer on the shore, it will appear as the knife moves a certain distance along with the ship in x direction along with its y displacement. So, for an observer on the shore, the knife will have both horizontal and vertical components.
[tex]v_{i}_{x}[/tex] = - 1.73 m / s
[tex]a_{x}[/tex] = 0
[tex]v_{x}[/tex] = - 1.73 m / s
R = √ [tex]v_{x}[/tex]² + [tex]v_{y}[/tex]²
R = √ ( - 1.73 )² + ( - 17.15 )²
R = √ 2.99 + 294.12
R = √ 297.11
R = 17.24 m / s
For an observer on the ship, the knife and the ship doesn't have any x component. So the position the knife lands is straight below the point it was dropped. For an observer on the shore, it seems that both the knife and ship have an equal amount of x-component. From the point of view also, the position the knife lands is straight below the point it was dropped.
Therefore,
The velocity of the knife relative to the ship = - 17.15 m / sThe velocity of the knife relative to a stationary observer = 17.24 m / sTo know more about relative velocity
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Calculate the percentage error in a steel tape used for measurement on a cold day when the temperature is -5 ℃ if it was calibrated at 20 ℃. [αsteel=1.1×10-5 ℃-1]
Answers
The percentage error in a steel tape used for measurement on a cold day when the temperature is -5 ℃ is - 0.028
Coefficient of linear thermal expansion for steel, α = 1.1 * [tex]10^{-5}[/tex] / C
Let the length of the tape at 20 ℃ be L.
New length of the steel tape after cooling, L' = L ( 1 + α ΔT )
ΔL = L' - L
ΔL = L ( 1 + α ΔT ) - L
ΔL = L ( 1 + α ΔT - 1 )
ΔL = L α ΔT
ΔT = T - [tex]T_{0}[/tex]
T = Final temperature
[tex]T_{0}[/tex] = Initial temperature
ΔT = - 5 - 20
ΔT = - 25 ℃
ΔL = L * 1.1 * [tex]10^{-5}[/tex] * ( - 25 )
ΔL = - 27.5 * [tex]10^{-5}[/tex] * L
Percentage error = ΔL / L * 100
Percentage error = - 27.5 * [tex]10^{-5}[/tex] * L / L * 100
Percentage error = - 0.028
Therefore, the percentage error in the steel tape is - 0.028
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A restaurant owner attaches a sign to the side of his building as shown in the image. A beam is bolted to the building to support the cable, and the cable is anchored to the end of the beam and tensioned such that it bears the full weight of the sign. The beam is exactly horizontal with respect to the earth, the upper portion of cable makes a 30.0o angle with the beam, and the mass of the sign is 10.0 kg.
Determine the magnitude of the tension in the cable
Answers
The magnitude of the tension in the cable is determined as 49 N.
What is tension force?
Force of tension is defined as the force transmitted through a rope, string or wire when pulled by forces acting from opposite sides.
The upward tension of the cable is equal to the downward weight of the beam.
Mathematically, the formula for calculating the tension in the cable is calculated as follows;
T = W sinθ
where;
W is the weight of the beam due to force of gravity pulling it downwardsθ is the angle of inclination of the cable above the horizontalT = mg sinθ
Substitute the given parameters and solve for the tension,
T = (10 kg x 9.8 m/s²) x sin(30⁰)
T = 49 N
Thus, we can conclude that the tension in the cable as it bears the full weight of the beam is 49 N.
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a skier has just begun descending a 20 degrees slope. assuming that the coeffecient of the friction 0.10 calculate
acceleration of the skier
the final velocity of the skier after 8.0 s
Answers
A skier has just begun descending a 20° slope, so the Acceleration of the skier will be -4.7 m/s².
What is average velocity?Average velocity is a vector quantity. The change in position or displacement divided by the periods during which the displacement happens is known as average velocity. Depending on how the displacement is displaced, the average velocity may be positive or negative. Meters per second (m/s), the SI unit of average velocity, is used.
Average Velocity= [tex]Total\ Displacement/ Total\ Time[/tex]
According to the question,
Skier is on a 20° down slope.
Portion of weight parallel to and down slope.
f₁ = (sin20°)mg = 0.3 × mg
The friction force resists motion parallel to the slope, therefore its sign is opposite that of f1, and it is equal to the kinetic coefficient of friction times the weight's surface normal component.
f₂ = -μ(cos30°)mg = -0.9*0.8660 × mg
f₂ = -0.7794 × mg
The net force on the skier parallel to and down the slope
F = f₁ + f₂ = (0.3 -0.7794)mg
F = -0.4794 × mg
By Newton’s second law, net acceleration parallel to and down slope.
a = F/m = -0.4794 × g
For g = 9.807 m/s²,
a = -0.4794 × 9.807 = -4.7 m/s².
So, the acceleration of the skier will be -4.7 m/s².
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Leah was pulling on a wagon with a force of 156N at an angle of 38 degrees. if she moves the wagon 45.5m how much work has she done
Answers
Answer:
W = 5593.3 J
Explanation:
The work can be calculated as
W = Fdcosθ
Where F is the force, d is the distance and θ is the angle.
So, replacing F = 156N, d = 45.5 m and θ = 38, we get:
W = (156N)(45.5m)(cos38)
W = (156N)(45.5m)(0.788)
W = 5593.3 J
What forward force must the ground apply to the foot of a 60.0kg person to result in an acceleration of 1.00 m/s^2?
Answers
Answer:
F=ma
=60×1
=60N
Explanation:
straightforward formula
50 POINTS!!!!!
A skier traveling at 31.3 m/s encounters a 20 degree slope. If you could ignore friction, to the nearest meter, how far up the hill does he go?
Answers
121 m far up the hill does he go.
Vo = 31.3 m/s
Angle [tex]\theta[/tex] = [tex]20^o[/tex]
Yo = 31.3*sin20
= 28.57 m/s.
[tex]Y^2 = Yo^2 + 2g*h = 0.[/tex]
[tex]28.57^2 - 19.6h = 0 \\19.6h = 816.4\\ h = 41.6 m.[/tex]
[tex]d*sin20 = 41.6\\ d = 121 m. -- > up \ hill.[/tex]
What is friction?Friction is a force that opposes the relative motion of solid surfaces, fluid layers and material elements that slide against each other.
There are four types of friction and they are classified as follows:
Static friction Sliding friction Rolling friction Fluid frictionApplications of friction
Friction is used when matches burn. The movement of the pistons in the cylinder is due to friction. It is possible to write on books and blackboards because there is friction between the pen and the blackboard.To learn more about friction, refer;
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a 10 kg block of ice slide down the ramp 20 m long. inclined at 10 degrees to the horizontal.
if the ramp is frictionless what is the acceleration of the block of ice
if the coefficient of friction is 0.10 how long will it take the block to slide down the ramp if it starts from rest
Answers
At the given coefficient of friction of the ramp, the acceleration is 0.97 m/s².
The time taken for the block to travel down the ramp is 6.42 s.
What is the acceleration of the block?The acceleration of the block is calculated as follows;
Apply Newton's second law of motion to determine the acceleration of the block.
μmgcos(θ) = ma
μgcos(θ) = a
where;
μ is coefficient of frictiong is acceleration due to gravityθ is the angle of inclination of the planea = (0.1)(9.8) cos(10)
a = 0.97 m/s²
The time taken for the block to travel down the inclined plane is calculated as follows;
s = vt + ¹/₂at²
where;
v is the initial velocity = 0s is the length of the ramp20 = 0 + ¹/₂(0.97)t²
40 = 0.97t²
t² = 40/0.97
t² = 41.24
t = √41.24
t = 6.42 seconds
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PLS HELP
What group and period would this element be in from the picture below?
Describe how you determined it’s place.
What family does it belong to?
PLSSSS HELP
Answers
Based on the structure of the element shown, the element belongs to group 2A of the periodic table.
What are families in the periodic element?Families of elements in the periodic table refer to the elements that are found in the same vertical column in the periodic table.
The families of elements in the periodic table are also called groups.
Elements belonging to the same family in the periodic table have similarities in their properties, both physical and chemical.
The group or family to which an element belongs to depends on the number of electrons found in the valence shell of the element.
Elements in the same group have the same number of electrons in their valence shells. For example, elements in group 1A of the periodic table have one valence electron in their valence shell.
Considering the given element;
The element has three electron shells.
In the valence or outermost shell, there are 2 electrons in the atom of the element. This means that the element would belong to the family of elements that have two valence electrons, group 2A.
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PLEASE HELP ME I NEED THIS ASAP
Investigating Energy Systems
Harnessing Human Energy Chapter 1 Lesson 1.2
Reasoning Tool
Possible subclaims:
The Battery System does have energy.
or
The Battery System does not have energy.
The Hand-Crank Generator System does have energy.
or
The Hand-Crank Generator System does not have energy.
The Solar Cell System does have energy.
or
The Solar Cell System does not have energy.
Evidence
(observations about whether the system does or does not have energy)
This matters because . . .
(How does this evidence support the subclaim?)
Therefore, . . .
(subclaim)
Answers
Considering the energy systems:
The Battery System does have energy because it can be used to light a bulb for example.The Hand-Crank Generator System does have energy because turning the lever generates electrical energy.The Solar Cell System does have energy because it can light a bulb.What is energy?Energy is the ability to do work.
There are several forms of energy such as:
chemical energy - energy stored in chemical bondsSolar energy - energy from the radiation of the sunLight energy - energy from the sensation of lightSound energy -Mechanical energy - there are two forms; kinetic energy and potential energyElectrical energy is the energy due to the movement of electrons.Generally, all matter possesses energy that can be used to do work.
The various forms of energy can be interconverted.
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Explain the difference
between the 4 states of
matter in terms of shape,
volume, forces, molecular
movement
Answers
In states of matter, Solid has definite shape and volume, liquid has no shape but have definite volume, gas and plasma has no shape as well as no volume.
What are the difference between different states of matter?A solid has a definite shape and volume, liquid has a definite volume, but has no specific shape. A gas has no defined shape or has no volume. Plasma is similar to a gas but a gas is neutral whereas plasma has a charge. Solids and liquids have a definite volume. Gases and plasma have no definite volume. The force of attraction between the molecules of solid is maximum, less in liquid, least in gases and very less in plasma. Gas vibrate and move freely at very high speeds. liquid vibrate and slide past each other. Solid vibrate but do not move from place to place.
So we can conclude that solid has shape and volume, liquid has volume but no shape, gas and plasma has no shape and no volume.
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3.-A projectile has an initial horizontal velocity of
5 m/s and an initial vertical velocity of 3 m/s second upward. At what angle was the projectile
fired?
Answers
Answer:
Explanation:
tg α = V₂ / V₁ = 3 / 5 = 0.6
α ≈ 31°
When a car brakes hard and skids, the maximum deceleration is 3.1m/s^2. The coefficient of friction between the tires and the road is ___.
Answers
When a car brakes hard and skids, the maximum deceleration is 3.1m/s^2. The coefficient of friction between the tires and the road is [tex]\mu=0.61[/tex].
This is further explained below.
What is the coefficient of friction?Let us assume that the mass of the vehicle is m, and that the coefficient of friction between the tires and the road is mu.
We have determined this by using Newton's second rule of motion.
f=m a
[tex]\mu[/tex]m g=m a
[tex]&\mu=\frac{a}{g}[/tex]
[tex]&a=6 \mathrm{~m} / \mathrm{s}^2 \\\\&g=9.8 \mathrm{~m} / \mathrm{s}^2 \\[/tex]
Therefore
[tex]\mu=\frac{6}{9.8}[/tex]
[tex]\mu=0.61[/tex]
In conclusion,0.61 is the value of the coefficient of friction that exists between the tires and the vehicle.
[tex]\mu=0.61[/tex]
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To measure the capacitance C of a capacitor, you attach the capacitor to a battery and wait until it is fully charged. You then disconnect the capacitor from the battery and let it discharge through a resistor of resistance R. You measure the time T1/2 that it takes the voltage across the resistor to decrease to half its initial value at the instant that the connection to the capacitor is first completed. You repeat this for several different resistors. You plot the data as T1/2 versus R and find that they lie close to a straight line that has slope 7.50 μF.
What is the capacitance C of the capacitor?
Answers
The RC circuit, which is utilized in this experiment, is one of the most basic circuits that make use of a capacitor. When two conductors are linked to a charging device, the charge is passed from one conductor to the other.
When two conductors are connected to a charging device (such as a battery), the charge is transferred from one conductor to the other until the potential difference between the terminals of the charging device and the potential difference between the conductors are equal.
Capacitors are objects that have the capacity to hold electrical charge and energy. Capacitors have a wide range of uses, such as filters in DC power supplies and energy banks for pulsed lasers. Since capacitors only pass AC current and not DC current, they are used to block the DC component of a signal so that the AC component of the signal may be detected.
Plasma physics makes use of the energy-storage capabilities of capacitors. In plasma physics, short energy bursts with extremely high voltages and currents are frequently needed. A capacitor can be softly charged to the necessary voltage and then quickly discharged to yield the necessary energy.
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What is the voltage across a 100 Ω resistor with a current of 4.5 amps?
Answers
We can use the following equation to solve for V, voltage:
V = IR, where
I: current, and R: resistance
Let's plug in our known variables, current and resistance:
V = 4.5*100
Then solve for V:
V = 450V
Two 5.0-cm-diameter metal disks separated by a 0.68-mm-thick piece of Pyrex glass are charged to a potential difference of 1800 V.
a) What is the surface charge density on the disk?
b) What is the surface charge density on the glass?
Answers
The surface charge density on the disk is 1.73 x 10⁻⁸ C/m².
The surface charge density of the glass is 9.36 x 10⁻⁵ C/m²
What is the magnitude of the charge?The magnitude of the charge is calculated as follows;
V = kQ/r
where;
V is the potential differencek is Coulomb's constantq is magnitude of the charger is the distance of separationkQ = Vr
Q = Vr/k
Q = (1800 x 0.68 x 10⁻³) / (9 x 10⁹)
Q = 1.36 x 10⁻¹⁰ C
The surface charge density of the disk is calculated as follows;
σ = Q/A
σ = Q/(4πr²)
where;
r is the radius of the disk = 5 cm / 2 = 2.5 cm = 0.025 mσ = Q/(4πr²)
σ = (1.36 x 10⁻¹⁰ )/(4π x 0.025²)
σ = 1.73 x 10⁻⁸ C/m²
The surface charge density of the glass is calculated as follows;
σ = Q/A
σ = Q/(4πr²)
where;
r is the radius of the glass = 0.68 mm / 2 = 0.34 mm = 0.00034 mσ = Q/(4πr²)
σ = (1.36 x 10⁻¹⁰ )/(4π x 0.00034²)
σ = 9.36 x 10⁻⁵ C/m²
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Assume that when we go to Mars, we discover that there is a previously unknown planet between Mars and Jupiter. The newly found planet is 2.5 Astronomic Units (A.U.) from the Sun.
What is the period around the Sun of the new Planet?
Answers
The period of the revolution as obtained from the question is 3.95 years.
What is the solar system?We know that the solar system is composed of the sun and the planets. The sun is at the center of the solar system and the sun is surrounded by the planets which tend to form concentric circles.
From the Kepler's laws, we can see that the square of the period is directly proportional to the cube of the radius of the planet;
Hence;
T^2 α r^3
T = period
r = distance
T = r^3/3
T = (2.5)^3/2
T = 3.95 years
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A ball of mass 1.2 kg is suspended by two wires from a horizontal arm, which is attached to a vertical shaft, as shown in the figure. The rate of rotation of the shaft and ball is such that the tensions in the two wires are equal. What is the radial acceleration of the ball?
Answers
The radial acceleration of the ball of mass 1.2 kg that is suspended by two wires from a horizontal arm, which is attached to a vertical shaft is 4.9 m / s²
Since the wires form a right angled triangle with the horizontal arm,
tan θ = Opposite side / Adjacent side
tan θ = 0.6 / 0.8
θ = [tex]tan^{-1}[/tex] ( 0.75 )
θ = 36.9°
m = 1.2 kg
W = m g
W = 1.2 * 9.8
W = 11.76 N
T1 = T2 = T
∑ [tex]F_{y}[/tex] = 0
T1 + T2 sin θ - W = 0
T + T sin 36.9° - 11.76 = 0
T + 0.6 T = 11.76
T = 11.76 / 1.6
T = 7.35 N
[tex]F_{c}[/tex] = m v² / r
[tex]F_{c}[/tex] = Centripetal force
∑ [tex]F_{x}[/tex] = m v² / r
T cos 36.9° = m * [tex]a_{r}[/tex]
[tex]a_{r}[/tex] = 7.35 * 0.8 / 1.2
[tex]a_{r}[/tex] = 4.9 m / s²
Therefore, the radial acceleration of the ball = 4.9 m / s²
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Indiana Jones is running from his enemies. How fast is he running if he jumps
from a 9.0m high cliff and lands at the edge of a ledge that is 1.75 m from the cliff?
Answers
The speed of Indiana Jones if he jumps from a 9.0 m high cliff and lands at the edge of a ledge that is 1.75 m from the cliff is 1.29 m / s
From the equations of motion,
s = ut + 1 / 2 at²
In vertical motion,
s = 9 m
u = 0
a = 9.8 m / s²
9 = 0 + ( 1 / 2 * 9.8 * t² )
t² = 1.84
t = 1.36 s
In horizontal motion,
a = 0
s = 1.75 m
1.75 = ( u * 1.36 ) + 0
u = 1.75 / 1.36
u = 1.29 m / s
Therefore, Indiana jones is running at a speed of 1.29 m / s
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3. What stroke of an engine moves the piston down into the engine and causes the top of
cylinder to open and mix air and fuel?
Answers
Answer:
See below
Explanation:
INTAKE - compression - power - exhaust for a 4 stroke engine
Answer: intake
Explanation:
I took the quiz.
Which of the following is NOT a way to change a rhythm?
A. Adding syncopation
B. Adding sixteenth notes
C. Adding an ostinato
D. Adding a dotted rhythm
Answers
Syncopation in music is the off-beating of all or a portion of a tune or piece of music by combining different rhythms. Adding syncopation is NOT a way to change a rhythm.
What is meant by syncopation?Syncopation in music is the off-beating of all or a portion of a tune or piece of music by combining different rhythms. Syncopation can be defined more simply as "a disruption or interruption of the regular flow of rhythm" or "the placement of rhythmic stresses or accents where they wouldn't normally occur."
By challenging our perceptions of where the beat should be, syncopation adds excitement to the music. When every note falls on the anticipated beat, this groove-inducing technique departs from the straight feel. Syncopation also draws the listener's attention. Syncopation is NOT a method of altering rhythm.
Therefore, the correct answer is option A. Adding syncopation.
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what does a closed circuit need to work?
Answers
Answer:
Explanation what does a closed circuit need to work?
Closed Circuit: In a closed circuit, the connected source and load form a closed-loop path. We need a switch to make (ON) and break (OFF) the circuit for the electrical and electronic circuits to work (open circuit and closed circuit).
During the experiment, the angular velocity will be allowed to vary. If the mass of the rotating object is 5 kg and the radius of rotation is 0.2 m, what will be the angular velocity, ω, when the force sensor reads 3.4 N?
Answers
Answer: w=1.84 rad/s
Explanation:
During the experiment, the angular velocity will be allowed to vary. If the mass of the rotating object is 5 kg and the radius of rotation is 0.2 m, what will be the angular velocity, ω, when the force sensor reads 3.4 N?
first we set 3.4N = to the equation [tex]5kg(w)^{2}* .20[/tex]
solving for w [tex]w^2=17/5[/tex]
[tex]w=(\sqrt{85})/5 \\[/tex]
[tex]w=1.84391[/tex]
w=1.84 rad/s
What is the relationship of the force on the spring and stretch of the spring? (I have a picture of a spring that weights can be added to) as seen
Answers
Given data:
The mass of the first weight is
[tex]m_1=250\text{ g}[/tex]second
[tex]m_2=100\text{ g}[/tex]The mass of the third weight is
[tex]m_3=100\text{ g}[/tex]The mass of the fourth weight is
[tex]m_4=50\text{ g}[/tex]The force on the spring can be expressed as,
[tex]F=mg[/tex]Here, g is the acceleration due to gravity which is considered as a constant value.
The force on the spring depends on the mass of each weight. Higher is the weight then more will be the force on each spring.
,
The mass relation for each weight can be given as:
The relationship between the forces acts on the spring can be given as,
[tex]F1>F_2=F_3>F_4[/tex]Here, suffixes (1,2,3, and 4) numbers related to the first, second, third, and fourth weights.Thus, the relationship of the force on the spring is
[tex]F_1>F_2=F_3>F_4[/tex][tex]\begin{gathered} F=kx \\ x=\frac{F}{k} \end{gathered}[/tex]Here, x is the stretch of the spring and k is the spring constant.
The stretch of the spring depends on the force of the spring.
The stretch of the spring relationship for the given weights can be given as:
[tex]x_1>x_2=x_3>x_4[/tex]Thus, the relationship of the stretch of the spring is
[tex]x_1>x_2=x_3>x_4[/tex]