Evaluate the expression when m = -4. M^2+6m+9

Answers

Answer 1
[tex]m^2\text{ + 6m + 9, where m = -4}[/tex][tex]\text{Replacing m by - 4, we have: -4}^2\text{ + 6 }\cdot\text{ -4 + 9}[/tex][tex]1\text{6 + 9 - 24 = 25 - 24 = 1}[/tex]

The answer is 1


Related Questions

Hello, just want to check my answers at Part B. Thanks!

Answers

SOLUTION

The given functions are:

[tex]f(x)=(x-2)(x-1)(x-1),g(x)=\sqrt[3]{x}-2[/tex]

Notice that when x=0

[tex]\begin{gathered} f(0)=(0-2)(0-1)(0-1) \\ f(0)=-2 \end{gathered}[/tex]

Also

[tex]\begin{gathered} g(0)=\sqrt[3]{0}-2 \\ g(0)=-2 \end{gathered}[/tex]

This shows that f(0)=g(0)

Hence there are no breakes in the domain of h(x)

A girl is pedaling her bicycle at a speed of 0.10 km/min. How far will she travel in three hours?

Answers

Answer:

18 km

Step-by-step explanation:

.1 km/min  *  60 min/hr  * 3 hr = 18 km

Answer: 18 km

Step-by-step explanation:

First, you know that 60 minutes equal one hour so to get a km/hr ratio you need to multiply the 0.10km by 60 and the minute (1) to get 6(km)/1(hr), then you multiply the 6km by 3 as well as the 1hr by 3 since we need to get to three hours. With this you get 18(km)/3(hr).

Maya is playing golf. On her first two holes she scored one under par then six over par. Find her score after the first two holes.

Answers

If Maya is playing golf in which on  her first two holes she has one under par then six over par. Her score after the first is 5 over  per.

Score after the first two holes

First is to analyze the given the information given

What she got on the first hole = one under par = -1

What she got on her second hole = six over par = 6

Now let find or determine her score

Score = -1 + 6

Score = 5 over par

Therefore we can conclude that her score is 5 over  per.

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What is the slope of a line perpendicular to the line whose equation is x+3y=-15. Fully simplify your answer.

Answers

ANSWER

The slope of the line perpendicular line of the equation is 3

STEP-BY-STEP EXPLANATION:

What to find? The slope of a line perpendicular to the line whose equation is x + 3y = -15

Given the equation

x + 3y = -15

The slope-intercept form of an equation is given as

[tex]y\text{ = mx + b}[/tex]

Where m = slope of the line

y = the intercept of the y-axis

The next step is to re-arrange the above equation in the slope-intercept format

[tex]\begin{gathered} \text{Given the equation of a straight line as} \\ x\text{ + 3y = -15} \\ \text{Isolate 3y by substracting x from both sides} \\ x\text{ - x + 3y = -15 - x} \\ 3y\text{ = -x - 15} \\ \text{Divide through by 3} \\ \frac{3y}{3}\text{ = }\frac{-1}{3}x\text{ -}\frac{15}{3} \\ y\text{ = }\frac{-1}{3}x\text{ - 5} \\ \text{Hence, the slope}-\text{intercept form of the above equation is given as} \\ y\text{ = }\frac{-1}{3}x\text{ - 5} \end{gathered}[/tex]

NB: That the two lines are perpendicular to each other

From y = mx + b

m = -1/3

The slope of the equation

[tex]\begin{gathered} \text{ For two perpendicular lines, we can calculate the slope as follows} \\ m_1\cdot m_2\text{ =- 1} \\ \text{where m}_1\text{ = }\frac{-1}{3} \\ \frac{-1}{3}\cdot m_2\text{ = -1} \\ \frac{-1\cdot m_2}{3}=\text{ -1} \\ \text{Cross multiply} \\ -m_2\text{ = -1 }\cdot\text{ 3} \\ -m_2\text{ = -3} \\ \text{Divide through by -1} \\ \frac{-m_2}{-1}\text{ = }\frac{-3}{-1} \\ m_2\text{ = }3 \\ \text{Hence, the slope of the perpendicular line to the equation is 3} \end{gathered}[/tex]

If 4–(x – 4) = 1 over 16 what is the value of x? (2 points)
–2
–6
6
2

Answers

Answer:    these are the answers that i got -2 for x =10 -6= 14 6=2 and 2= 6

Step-by-step explanation:

a man paddles his canoe at a rate of 12 kilometers per hour. write this rate as meters per minute

Answers

Answer

12 kilometers per hour = 200 meters per minute

Explanation

In order to convert 12 kilometers per hour into meters per minute, we need to note that

1 kilometer = 1000 meters

1 hour = 60 minutes

[tex]\begin{gathered} 12\frac{kilometers}{hour} \\ We\text{ ne}ed\text{ to note that } \\ \frac{1000\text{ meters}}{1\text{ kilometers}}=1 \\ \frac{1\text{ hour}}{60\text{ minutes}}=1 \\ 12\frac{\text{kilometers}}{\text{hour}}\times1\times1 \\ =12\frac{\text{kilometers}}{\text{hour}}\times\frac{1000\text{ meters}}{1\text{ kilometer}}\times\frac{1\text{ hour}}{60\text{ minutes}} \\ =\frac{12\times1000\times1}{1\times60}\frac{meters}{\min ute} \\ =200\frac{\text{meters}}{\text{minute}} \end{gathered}[/tex]

Hope this Helps!!!

xx yyy
121212 363636
181818 545454
252525 757575
Find the constant of proportionality (r)(r)left parenthesis, r, right parenthesis in the equation y=rxy=rxy, equals, r, x.

Answers

The constant of proportionality for the given set is 3.

Given,

The set;

x        y

12     36

18     54

25    75

We have to find the constant of proportionality;

Here,

y = x × r

Where r is the constant of proportionality.

Lets see;

Case 1; 12 and 36

36 = 12 × r

r = 36/12

r = 3

Case 2; 18 and 54

54 = 18 × r

r = 54/18

r = 3

Case 3; 25 and 75

75 = 25 × r

r = 75/25

r = 3

Therefore,

The constant of proportionality for the given set is 3.

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A local newspaper charges $13 for each of the first four lines of a classified ad, and $7.50 foreach additional line. Express the cost of a -line ad, c(x), as a piecewise function

Answers

The cost is the basic cost increased by the product of the number of extra lines and the price per additional line, then:

Let x be the number of additional lines

c(x)=13+7.50x

For the line y = 1 - 3x, create a table to show the values of x and y where x is from -2 to 2.​

Answers

For the line y = 1 - 3x the values of x and y are given below:

Given,

y = 1 - 3x

putting x = -2

y = 1 - 3x

y = 1 - 3(-2)

y = 7

Putting x = -1

y = 1 - 3(-1)

y = 4

putting x = 0

y = 1 - 3(0)

y = 1

Now putting x = 1

y = 1 - 3(1)

y = -2

putting x = 2

y = 1 - 3(2)

y = -5

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A map is drawn using a scale of 1 inch : 4 meters. If the length of a paved path on a map is 16 inches, then find the actual length of the paved path.

Answers

Nana, this is the solution to the exercise:

Scale 1 inch : 4 meters

For solving this exercise, we will use the Direct Rule of Three, as follows:

Length on the map (inches) - Actual length (meters)

______________________________________________

1 4

16 x

_______________________________________________

1 * x = 16 * 4

x = 64

The actual length of the paved path is 64 meters

What is the ones digit in the number 2 to the 2056 Power?Hint: start with smaller exponents to find the pattern

Answers

Follow the steps below to find the ones digit in the number:

[tex]\begin{gathered} 2^{2056} \\ \text{The base = 2} \\ \text{The power = 2056} \end{gathered}[/tex]

step 1: Identify the unit digit in the base - the unit digit is 2.

step 2:

If the power or exponent is exactly divisible by 4

case 1: The unit digit of the number is 6 if the unit digit in the base is any of 2, 4, 6, 8.

case 2: The unit digit of the number is 1 if the unit digit in the base is 3, 7, 9.

In this case, the power 2056 is exactly divisible by 4 and the unit digit in the base is 2.

Therefore, the ones digit is 6

What’s the correct answer answer asap i need help can somebody answer this question?
il give you brainlist

Answers

Answer:

Virtuosity on the piano

Answer: a

Step-by-step explanation:

When the engine falls out of Rhonda's old car, it's time to shop for something newer. She is hoping to keep her monthly payment at $140, and a loan will be 5% simple interest for 48 months with a $1000 down payment. Under these conditions, the most expensive car that Rhonda can afford is $6600.00. A salesman tries to convince Rhonda that she would be able to get a much better car if she raises the payment by just $30 per month.

Answers

The maximum value increase along with the down payment is $1200.

What is Down Payment?

A down payment, sometimes known as a deposit in British English, is an upfront partial payment made when purchasing expensive goods or services like a home or car. At the moment the transaction is completed, it is often paid in cash or an equivalent. The remainder of the payment must then be financed using some kind of loan.

We need to calculate the value by which the price increases if she does raise the payment by $30

So, the total payment made by her = $140 +$30 = $170

This payment is made for 48 months at 5% simple interest

Total payments made= $170 × 48 = $8160

Let P be the total car value

P + SI = 8160

P + PTR = 8160

P(1+TR) = 8160

P = 8160/ (1+0.05 × 48 /12)

P= $6800

The maximum price that can be done is $6800 + down payment

hence the maximum price is $7800

Hence, the maximum value increase =$7800 - $6600= $1200

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Question: When the engine falls out of Rhonda's old car, it's time to shop for something newer. She is hoping to keep her monthly payment at $140, and a loan will be 5% simple interest for 48 months with a $1000 down payment. Under these conditions, the most expensive car that Rhonda can afford is $6600.00. A salesman tries to convince Rhonda that she would be able to get a much better car if she raises the payment by just $30 per month. What is the maximum value increase along with the down payment?

Joe drinks 0.55 L of milk every day. How much milk does he drink in 5 days? Write your answer in milliliters.

Answers

Given that

Joe drinks 0.55 l of milk every day and we have to find the milk he can drink in 5 days.

Explanation -

Let the given condition be represented as

1 day = 0.55 L milk

So multiplying by 5 on both sides we have

1 x 5 days = 0.55 x 5 L milk

5 days = 2.75 L milk

And conversion is

1L = 1000 ml

So multiplying by 2.75 in the above equation we have

2.75L = 2.75 x 1000 ml = 2750 ml

So Joe will drink 2750 ml of milk in 5 days.

Hence the final answer is 2750 ml.

On a flight from Chicago, Illinois, to Denver, Colorado,
the typical cruising altitude of a passenger jet is approximately
38,000 feet. As the flight departs from O'Hare International Airport,
the jet begins to ascend. At 4.3 miles away from the airport, the jet
is at an altitude of 4200 feet. The jet reaches an altitude of 36,700
feet at 167.5 miles away from the airport.
Determine the slope of ascent of the flight given that 5280 feet = 1 mile.
Round your answer to the nearest thousandth.

Answers

The slope of ascent of the flight is 0.04

How to calculate the slope of ascent?

From the question, we have the following parameters that can be used in our computation:

Typical cruising altitude = 38,000 feetInitial point of ascend = 4.3 miles at 4,200 feetAnother point of ascend = 167.5 miles at 36,700 feet

The above parameters can be represented as

(x, y) = (4.3, 4200) and (167.5, 36,700)

The slope is then calculated as

Slope = (y₂ - y₁)/(x₂ - x₁)

Where x and y are defined above

So, we have

Slope = (36700 - 4200)/(167.5 - 4.3)

Evaluate

Slope = 199.14 feet per mile

Recall that 5280 feet = 1 mile.

So, we have

Slope = 199.14 feet/5280 feet

Evaluate

Slope = 0.04

Hence, the required slope is 0.04

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Find the percent change and tell whether it is a percent decrease orincrease.Original amount: 30End amount: 45

Answers

Step 1

Since the end amount is greater than the original amount, it is, therefore, percentage increase

Step 2

Calculate the percentage increase

The formula is given by

[tex]\begin{gathered} \text{Percentage increase =}\frac{Increase}{\text{Original}}\times100 \\ \text{Increase}=\text{ }45\text{ - 30 = 15} \\ \end{gathered}[/tex][tex]\text{Percentage increase =}\frac{15}{30}\times100=\text{ 50 percent}[/tex]

The answer is therefore 50%

I need help on question 10.The solution of the system below is:3x + 2y = 143x – 2y = 10

Answers

Given the system of equations:

[tex]\begin{cases}3x+2y=14 \\ 3x-2y=10\end{cases}[/tex]

We'll multiply the second equation by -1 and then add both equations up:

[tex]\begin{gathered} \begin{cases}3x+2y=14 \\ 3x-2y=10\end{cases}\rightarrow\begin{cases}3x+2y=14 \\ -3x+2y=-10\end{cases} \\ \\ \rightarrow4y=4 \end{gathered}[/tex]

Solving the resulting equation for y ,

[tex]\begin{gathered} 4y=4\rightarrow y=\frac{4}{4} \\ \\ \Rightarrow y=1 \end{gathered}[/tex]

We'll plug in this y-value in the first equation and solve for x ,

[tex]\begin{gathered} 3x+2y=14 \\ \rightarrow3x+2(1)=14 \\ \rightarrow3x+2=14\rightarrow3x=12\rightarrow x=\frac{12}{3} \\ \\ \Rightarrow x=4 \end{gathered}[/tex]

Therefore, we can conclude that the solution to our system is:

[tex]\begin{gathered} x=4 \\ y=1 \end{gathered}[/tex]

The price-demand and cost functions for the production of microwaves are given asP= 180 - q/50and C(q) = 72000 + 110g,where q is the number of microwaves that can be sold at a price of p dollars per unit and C(q) is the total cost (in dollars) of producing q units.(C) Find the marginal revenue function in terms of q.R'(q) =(D) Evaluate the marginal revenue function at q=1100.R'(1100) =(E) Find the profit function in terms of q.P(q)(F) Evaluate the marginal proft function at q = 1100.P'(1100)

Answers

Answer:

A)

[tex]\begin{equation*} C^{\prime}(q)=110 \end{equation*}[/tex]

B)

[tex]\begin{equation*} R(q)=180q-\frac{q^2}{50} \end{equation*}[/tex]

C)

[tex]\begin{equation*} R^{\prime}(q)=180-\frac{q}{25} \end{equation*}[/tex]

D)

[tex]\begin{equation*} R^{\prime}(1100)=136 \end{equation*}[/tex]

E)

[tex]\begin{equation*} P(q)=-\frac{q^2}{50}+70q-72000 \end{equation*}[/tex]

F)

[tex]\begin{equation*} P^{\prime}(1100)=26 \end{equation*}[/tex]

Explanation:

Given:

[tex]\begin{gathered} p=180-\frac{q}{50} \\ C(q)=72000+110q \end{gathered}[/tex]

where q = the number of microwaves that can be sold at a price of p dollars per unit

C(q) = the total cost (in dollars) of producing q units.

A) To find the marginal cost, C'(q), we'll go ahead and take the derivative of the total cost as seen below;

[tex]\begin{gathered} C(q)=72000+110q \\ C^{\prime}(q)=0+110 \\ \therefore C^{\prime}(q)=110 \end{gathered}[/tex]

So the marginal cost, C'(q) = 110

B) We'll go ahead and determine the revenue function, R(q), by multiplying the price, p, by the quantity, q, as seen below;

[tex]\begin{gathered} R(q)=p*q=(180-\frac{q}{50})q=180q-\frac{q^2}{50} \\ \therefore R(q)=180q-\frac{q^2}{50} \end{gathered}[/tex]

C) We'll go ahead and determine the marginal revenue function, R'(q), by taking the derivative of the revenue function, R(q);

[tex]\begin{gathered} \begin{equation*} R(q)=180q-\frac{q^2}{50} \end{equation*} \\ R^{\prime}(q)=180-\frac{2q^{2-1}}{50}=180-\frac{q}{25} \\ \therefore R^{\prime}(q)=180-\frac{q}{25} \end{gathered}[/tex]

D) To evaluate the marginal revenue function at q = 1100, all we need to do is substitute the q with 1100 in R'(q) and simplify;

[tex]\begin{gathered} \begin{equation*} R^{\prime}(q)=180-\frac{q}{25} \end{equation*} \\ R^{\prime}(1100)=180-\frac{1100}{25}=180-44=136 \\ \therefore R^{\prime}(1100)=136 \end{gathered}[/tex]

Therefore, R'(1100) is 136

E) To find the profit function, P(q), we have to subtract the total cost, C(q), from the revenue cost, R(q);

[tex]\begin{gathered} P(q)=R(q)-C(q) \\ =(180q-\frac{q^2}{50})-(72,000+110q) \\ =180q-\frac{q^2}{50}-72000-110q \\ =-\frac{q^2}{50}+180q-110q-72000 \\ =-\frac{q^2}{50}+70q-72000 \\ \therefore P(q)=-\frac{q^2}{50}+70q-72000 \end{gathered}[/tex]

F) To Evaluate the marginal profit function at q = 1100, we have to first determine the marginal profit, P'(q), by taking the derivative of the profit function, P(x);

[tex]\begin{gathered} \begin{equation*} P(q)=-\frac{q^2}{50}+70q-72000 \end{equation*} \\ P^{\prime}(q)=-\frac{2q^{2-1}}{50}+70(1*q^{1-1})-0=-2q^{50}+70q^0=-\frac{q}{25}+70 \\ \therefore P^{\prime}(q)=-\frac{q}{25}+70 \end{gathered}[/tex]

We can now go ahead and find P'(1100) as seen below;

[tex]\begin{gathered} P^{\prime}(1100)=-\frac{1100}{25}+70=-44+70=26 \\ \therefore P^{\prime}(1100)=26 \end{gathered}[/tex]

So P'(1100) = 26

To pass a course with a B grade a student must have an average of 80 or greater. The students grades on three test are 80, 81 and 70. Find what score the student must get on the next test to get a B average or better.

Answers

Given that the student's grades on three tests are 80, 81 and 70

Let the student's grade on the fourth test be X

In order to pass the course, the student must have an average of 80 or greater.

Hence,

[tex]\begin{gathered} \frac{80+81+70+X}{4}\ge80 \\ \frac{231+X}{4}\ge80 \\ 231+X\ge320 \\ X\ge320-231 \\ X\ge89 \end{gathered}[/tex]

The score the student must get on the next test to get a B average or better is greater than or equal to 89

how many many eighths are in 8/9

Answers

[tex]\frac{1}{8}\cdot\frac{8}{9}=\frac{1\cdot8}{8\cdot9}=\frac{8}{72}=\frac{1}{9}[/tex]

There are 1/9 eighths in 8/9

What is 75.6 divided by 4

Answers

Answer:

18.9

Step-by-step explanation:

Calculators, haha

18.9 Is the answer. I need this to be 20 characters long so don’t mind this

Colin just travelled across Ontario on a road trip. He bought some skis in Blue Mountain for
$879.95 plus tax, a boom box in Muskoka for $145.58 including taxes, a souvenir in Niagara Falls
for $99.97 plus tax, and some maple syrup in Toronto for $45.14 including tax. Overall, how
much HST did Colin pay on his trip? Answer should be rounded off to whole number.

Answers

The Harmonized Sales Tax paid by Colin is $152.

What is Harmonized Sales Tax?Almost all buyers of taxable supplies of goods and services must pay the GST/HST (other than zero-rated supplies). Indians, Indian bands, and entities with band authority, however, are occasionally exempt from having to pay the GST/HST on taxable supplies. In Ontario, the HST (Harmonized Sales Tax) is 13%. Ontario offers a point-of-sale rebate for the 8% provincial HST exemption on a selection of goods.

So, the amount of HST Colin pays:

The total amount of items brought:

Skis: $879.95Boom box: $145.58Souvenir: $99.97Maple syrup: $45.14

Total amount: $1,170.64

We know that HST is 13% of the amount, then:

$1,170.64/100 × 13 = 152.1832Rounding off: $152

Therefore, the Harmonized Sales Tax paid by Colin is $152.

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Which combination could the coach buy?Click on the correct answer.Remember, the coach1) needs to buy at least 4 bats and atleast 8 balls2) cannot spend more than $1206 bats, 10 balls12-3 bats, 10 balls84 bats, 9 balls-4-110T14812x24y2815x + 5y = 120

Answers

It is important to know that the yellow area represents all the possible solutions because there all the areas intercept. So, among the options, the correct one is 4 bats, 9 balls because it represents (3,10) which is inside the yellow region.

Hence, the answer is option 3.

1. Given d = 25,01 = 15°, and O2 = 40°. Find x and h. Show work. Round to 2 decimal places.0,

Answers

Let's check first this right triangle from the figure:

We have, using tangent on the angle:

[tex]\begin{gathered} \tan (15^o)=\frac{h}{25+x} \\ \Rightarrow h=0.268(25+x) \end{gathered}[/tex]

And then, looking at the other right triangle:

Doing the same as before, we have that:

[tex]\begin{gathered} \tan (40)\text{ = }\frac{h}{x} \\ \Rightarrow h=0.839x \end{gathered}[/tex]

Now, we can use both equations of h to solve for x:

[tex]\begin{gathered} 0.268(25+x)=0.839x \\ \Rightarrow6.7+0.268x=0.839x \\ \Rightarrow6.7=0.571x\Rightarrow x=\frac{6.7}{0.571}=11.73 \end{gathered}[/tex]

Which we can finally use to find h in any equation:

[tex]\begin{gathered} h=0.268(25+11.73)=9.843 \\ or \\ h=0.839\cdot11.73=9.841 \end{gathered}[/tex]

Please see attachment below Is the following an example of theoretical probability or empirical probability? A fisherman notes that eight out of ten times that he uses a certain lure to catch a fish within an hour. He concludes that the probability that the lure wil catch a fish on his next fishing trip is about 80%. Is it empirical or theoretical?

Answers

From the information provided, we know that the fisherman has already conducted some experiments and from these events he was able to conclude the probability of catching a fish on his next fishing trip. This is an example of EMPIRICAL PROBABILITY.

This is probability calculated after the event has occured.

ANSWER:

Empirical

Margaret drove to a business appointment at 70 mph. Her average speed on the return trip was 60 mph. The return took ⅓ hr longer because of heavy traffic. How far did she travel to the appointment ?

Answers

Let d and t be the distance and the time it takes for Margaret to get the place of the appointment.

d is the product of the speed when she was going to the appointment times the time (t):

[tex]d=70t[/tex]

d is also the product of the speed when she was going back home times t+1/3:

[tex]d=60(t+\frac{1}{3})[/tex]

Make both d equal and find the value of t:

[tex]\begin{gathered} 70t=60(t+\frac{1}{3}) \\ 70t=60t+20 \\ 10t=20 \\ t=\frac{20}{10} \\ t=2 \end{gathered}[/tex]

Use this value of t to find d:

[tex]\begin{gathered} d=70(2) \\ d=140 \end{gathered}[/tex]

According to this, she traveled 140 miles to the appointment.

Someone please help I don’t understand this at all would really appreciate some help !!!!

Answers

The results of the operations of functions evaluated at are listed below:

Addition - (f + g) (- 2) = 9Subtraction - (f - g) (- 2) = 3Multiplication - (f · g) (- 2) = 18Division - (f / g) (- 2) = 2 / 3

How to evaluate operations of functions

In this problem we four cases of operations between two functions, a quadratic equation f(x) and a linear equation g(x). There are four operations:

Addition - f (x) + g (x) = (f + g) (x)

Subtraction - f (x) - g(x) = (f - g) (x)

Multiplication - f (x) · g (x) = f · g (x)

Division - f (x) / g (x) = (f / g) (x)

If we know that f(x) = x² - x and g(x) = 3 · x + 9, then the compositions of functions evaluated at x = - 2 are, respectively:

(f + g) (- 2) = (- 2)² - (- 2) + 3 · (- 2) + 9

(f + g) (- 2) = 4 + 2 - 6 + 9

(f + g) (- 2) = 9

(f - g) (- 2) = (- 2)² - (- 2) - 3 · (- 2) - 9

(f - g) (- 2) = 4 + 2 + 6 - 9

(f - g) (- 2) = 3

(f · g) (- 2) = [(- 2)² - (- 2)] · [3 · (- 2) + 9]

(f · g) (- 2) = 6 · 3

(f · g) (- 2) = 18

(f / g) (- 2) = [(- 2)² - 2] / [3 · (- 2) + 9]

(f / g) (- 2) = 2 / 3

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The question is in the ss

Answers

An algebraic expression that is equivalent to the given expression

(2c³)⁵(4c⁴) / (8c⁶)² is equal to 2c⁷.

As given in the question,

Given algebraic expression is equal to :

(2c³)⁵(4c⁴) / (8c⁶)²

Law of indices:

mᵃ × mᵇ = mᵃ⁺ᵇ

mᵃ ÷ mᵇ = mᵃ⁻ᵇ

To get equivalent expression simplify the given expression

(2c³)⁵(4c⁴) / (8c⁶)² using law of indices:

(2c³)⁵(4c⁴) / (8c⁶)²

= ( 2⁵c¹⁵) ( 2²c⁴) / ( 2³c⁶)²

=( 2⁵c¹⁵) ( 2²c⁴) / ( 2⁶c¹²)

= 2⁵⁺²⁻⁶ c¹⁵⁺⁴⁻¹²

= 2c⁷

Therefore, an algebraic expression that is equivalent to the given expression (2c³)⁵(4c⁴) / (8c⁶)² is equal to 2c⁷.

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Determine the values of x in the equation x^2 = 81. Please help


x = −9

x = ±9

x = ±40.5

x = 40.5

Answers

The value of x in the quadratic equation is ±9.

As equation is [tex]X^{2}[/tex] = 81

Taking square root on both sides

⇒ [tex]\sqrt{x^{2} } = \sqrt{81}[/tex]

⇒ X = ± 9

∴ The value of X is  ± 9

The roots of the given quadratic equation are +9 and -9.

How to solve a quadratic equation?

An equation of degree 2 containing a single variable is known as the quadratic equation. . Its general form is [tex]Ax^{2}+ Bx^{} + C[/tex], where variables are x and constants are a, b, and c.

Examples are [tex]X^{2}[/tex] = ± 3, [tex]X^{2}[/tex] =  ±9, [tex]X^{2}[/tex]=4 or any real number.

Some other examples are [tex]x^{2} + 2X+2[/tex], etc.

To learn more about quadratic equations, refer to the following link.

https://brainly.com/question/1863222

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whats the average for 62,81,72,60,100,79

Answers

Answer:

75.66

Step-by-step explanation:

62, 81, 72, 60, 100, 79

To find the average, add all the numbers together then divide by how many numbers there are.

62 + 81 + 72 + 60 + 100 + 79 = 454

454 ÷ 6 = 75.66 or rounded 76

I hope this helps!

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