Answer:
False
Explanation:
I got it wrong picking true
A 90-hp (shaft output) electric car is powered by an electric motor mounted in the engine compartment. If the motor has an average efficiency of 91 percent, determine the rate of heat supply by the motor to the engine compartment at full load.
Answer:
The rate of heat supply is 8.901 horse-power.
Explanation:
From Thermodynamics energy efficiency of the electric car ([tex]\eta[/tex]), no unit, is the ratio of translational mechanical power ([tex]\dot E_{out}[/tex]), measured in horse power, to electric power ([tex]\dot E_{in}[/tex]), measured in horse-power. The rate of heat supply ([tex]\dot E_{l}[/tex]), measured in horse-power, by the motor to the engine compartment at full load is difference between electric energy and translational mechanical energy. That is:
[tex]\eta = \frac{\dot E_{out}}{\dot E_{in}}[/tex] (1)
[tex]\dot E_{l} = \dot E_{in}-\dot E_{out}[/tex] (2)
[tex]\dot E_{l} = \left(\frac{1}{\eta}-1\right)\cdot \dot E_{out}[/tex] (3)
If we know that [tex]\eta = 0.91[/tex] and [tex]\dot E_{out} = 90\,hp[/tex], then rate of heat supply is:
[tex]\dot E_{l} = \left(\frac{1}{0.91}-1 \right)\cdot (90\,hp)[/tex]
[tex]\dot E_{l} = 8.901\,hp[/tex]
The rate of heat supply is 8.901 horse-power.
Technician A says that reinforcements may be made of plastic,
Technician B says that reinforcements may be made of nylon.
Who is right?
O A only
B only
Both A and B
of Contents
Neither Anor B
Answer:
A Only
Explanation:
Reinforcements, as the name suggests, are used to enhance the mechanical properties of a plastic. Finely divided silica, carbon black, talc, mica, and calcium carbonate, as well as short fibres of a variety of materials, can be incorporated as particulate fillers.
Which option distinguishes the stage in the product development life cycle described in the following scenario?
A design team generates a list of product features to include in the design of a watch Internet interface.
A. detailed product design
B. product systems design
C. concept development
D. product planning
Select the correct answer from each drop-down menu. Choose the correct words.To complete the statements about career planning. Throughout your job search, you'll find that is closely related to the career of your choosing. It's important to take the time to find out what to expect now, so you can start developing the you need to excel in that career. Reset Next
Complete Question:
Throughout your job search, you’ll find that _____(the economy/education/salary) is closely related to the career of your choosing. It’s important to take the time to find out what to expect now, so you can start developing the ____ (task/communication/skill) that you need to excel in that career.
Answer:
Education; skills.
Explanation:
Throughout your job search, you'll find that education is closely related to the career of your choosing. It's important to take the time to find out what to expect now, so you can start developing the skills you need to excel in that career.
This ultimately implies that, all job openings that are being advertised by various organizations usually have a minimum requirement such as academic experience or level i.e the prospective candidate must have attained a level of education. Also, it is very important for undergraduates and potential employees to ensure that they are being proactive, as well as developing the requisite skills needed to excel in their career.
Answer:
both are c
Explanation:
Conduction is thermal energy transfer by:_______.
a. molecular interactions.
b. bulk (macroscopic) particle motion.
c. electromagnetic waves inside the solid.
d. a combination of molecular interactions and macroscopic particle motion.
Answer:
a. molecular interactions.
Explanation:
Conduction is thermal energy transfer by molecular interactions. Therefore, conduction involves the transfer of electric charge or thermal energy due to the movement of particles. When the conduction relates to electric charge, it is known as electrical conduction while when it relates to thermal energy, it is known as heat conduction.
In the process of heat conduction, thermal energy is usually transferred from fast moving particles to slow moving particles during the collision of these particles. Also, thermal energy is typically transferred between objects that has different degrees of temperature and materials (particles) that are directly in contact with each other but differ in their ability to accept or give up electrons.
Some examples of conductors include metal, steel, aluminum, copper, graphite, etc.
Hence, conduction is thermal energy transfer as a result of the movement of electrons and collision between the molecules of an object.
Which option demonstrates when most vehicles lose their efficiency?
as they refuel
during starts and stops
during the testing phase
as they brake
Hey there ..
I think the answer is as they put brake ..
I am not sure .. just check the image also provided above .. ..
If u think this helped u ..plz mark me as brainliest ..
And follow me
Answer:
During starts and stops
Explanation:
"Many of the energy inefficiencies in vehicles occur during starts and stops."
found it in the text.
The values of four out of a sample of five deviations are: -5, +2, +4, -2. What is The value of the fifth deviation?
Answer:
The fifth deviation is +1
Explanation:
Given
[tex]Deviations = -5, +2, +4,-2[/tex]
Required
Determine the fifth deviation
Represent the fifth deviation with x.
As a theorem, the sum of deviations from mean is always 0.
So, we have:
[tex]-5 +2 +4-2+x = 0[/tex]
[tex]-1+x = 0[/tex]
Add 1 to both sides
[tex]1 -1+x = 0 +1[/tex]
[tex]x = 0 +1[/tex]
[tex]x= +\ 1[/tex]
Hence, the fifth deviation is +1
2.) Technician A says that milky colored ATF could indicate a leaking transmission cooler in the radiator.
Technician B says that milky colored ATF could indicate the presence of leak detection dye.
Who is right?
OA. A only
OB. B only
OC. Both A and B
OD. Neither A nor B
Determine the voltage drop from the top terminal to the bottom terminal, vab, in the right hand branch and, vcd, in the left hand branch of the circuit. Determine each voltage drop based on the elements in the corresponding branch.
Answer:
Hello your question is incomplete attached below is the missing part of the question
answer ;
voltage drop in the Vcd branch = 30 V
Voltage drop in the middle branch = 40v - 30v = 10 volts
voltage drop in AB = 60 + ( -600 * 0.05 ) = 60 - 30 = 30 volts
Explanation:
Determine voltage drop from top terminal to bottom terminal ( Vab ) in the right hand branch and Vcd in left hand branch
40v and 50mA are in series hence; Ix = 50mA
also Vcd = 30V
CD is parallel to AB hence; Vcd = Vab = 30 V
Vab = ∝*Ix + 60 v
30v = ∝ ( 50mA ) + 60
therefore ∝ = -600
voltage drop in the Vcd branch = 30 V
Voltage drop in the middle branch = 40v - 30v = 10 volts
voltage drop in AB = 60 + ( -600 * 0.05 ) = 60 - 30 = 30 volts
A brass alloy rod having a cross sectional area of 100 mm2 and a modulus of 110 GPa is subjected to a tensile load. Plastic deformation was observed to begin at a load of 39872 N. a. Determine the maximum stress that can be applied without plastic deformation. b. If the maximum length to which a specimen may be stretched without causing plastic deformation is 67.21 mm, what is the original specimen length
Answer:
a) the maximum stress that can be applied without plastic deformation is 398.72 N/mm²
b) length of the specimen is 66.97 mm
Explanation:
Given the data in the question;
a) Determine the maximum stress that can be applied without plastic deformation
when know that; maximum stress σ[tex]_{max}[/tex] = F / A
where F is the force in the rod ( 39872 N )
A is the cross-sectional area of the rod ( 100 mm² )
so we substitute;
σ[tex]_{max}[/tex] = 39872 N / 100 mm²
σ[tex]_{max}[/tex] = 398.72 N/mm²
Therefore, the maximum stress that can be applied without plastic deformation is 398.72 N/mm²
b)
strain in the members can be calculated using the expression
ε = σ / E
where σ is the stress in the rod
E is the module of elasticity ( 110 GPa = 110000 N/mm² )
(Sl-L) / L = σ/E
where Sl-L is the change in length of the member
L is the original length of the specimen
so we substitute
(67.21 - L) / L = 398.72 / 110000
110000( 67.21 - L) = 398.72L
7393100 - 110000L = 398.72L
7393100 = 398.72L+ 110000L
7393100 = 110398.72L
L = 7393100 / 110398.72
L = 66.97 mm
Therefore; length of the specimen is 66.97 mm
A horizontal curve of a two-lane undivided highway (12-foot lanes) has a radius of 678 feet to the center line of the roadway. An old building (sight obstruction) is located 30 feet from the edge of the innermost lane. The road is level and the superelevation is 0.06. Please determine the maximum speed for safe vehicle operation on this horizontal curve.
Answer:
maximum speed for safe vehicle operation = 55mph
Explanation:
Given data :
radius ( R ) = 678 ft
old building located ( m )= 30 ft
super elevation = 0.06
Determine the maximum speed for safe vehicle operation
firstly calculate the stopping sight distance
m = R ( 1 - cos [tex]\frac{28.655*S}{R}[/tex] ) ---- ( 1 )
R = 678
m ( horizontal sightline ) = 30 ft
back to equation 1
30 = 678 ( 1 - cos (28.655 *s / 678 ) )
( 1 - cos (28.655 *s / 678 ) ) = 30 / 678 = 0.044
cos [tex]\frac{28.65 *s }{678}[/tex] = 1.044
hence ; 28.65 * s = 678 * 0.2956
s = 6.99 ≈ 7 ft
next we will calculate the design speed ( u ) using the formula below
S = 1.47 ut + [tex]\frac{u^2}{30(\frac{a}{3.2} )-G1}[/tex] ---- ( 2 )
t = reaction time, a = vehicle acceleration, G1 = grade percentage
assuming ; t = 2.5 sec , a = 11.2 ft/sec^2, G1 = 0
back to equation 2
6.99 = 1.47 * u * 2.5 + [tex]\frac{u^2}{30[(11.2/32.2)-0 ]}[/tex]
3.675 u + 0.0958 u^2 - 6.99 = 0
u ( 3.675 + 0.0958 u ) = 6.99
QUESTÃO 13. Explique o uso das aspas no trecho "Darei a cada uma de vocês
semente. Aquela que dentro de seis meses me trouxer a mais bela flor será escolhida ma
esposa e a futura imperatriz da China.".
QUESTÃO 14. A serva do palácio considerou a ideia de a filha comparecer à celeb
rganizada pelo príncipe da região, uma ideia insensata, uma loucura. Isso é uma OP
Você concorda com essa opinião da personagem? Justifique a sua resposta.
Answer: speaks Portuguese
Eu disse a todos a tradução para que possam te ajudar
Explanation: Y’all can help I have no idea
QUESTION 13. Explain the use of quotation marks in the excerpt "I will give each of you
seed. The one who will bring me the most beautiful flower within six months will be chosen but
wife and the future empress of China. ".
QUESTION 14. The palace servant considered the idea of her daughter attending the celeb
organized by the prince of the region, a foolish idea, a madness. This is an OP
Do you agree with this opinion of the character? Justify your answer.
The input and output signals of a system is related by the following equation: fraction numerator d squared y over denominator d t squared end fraction plus sin (3 y )fraction numerator d y over denominator d t end fraction plus y equals t fraction numerator d f over denominator d t end fraction plus f. Then, the system is:
Answer:
Explanation:
The given equation is :
[tex]\frac{d^{2}y }{dx^{2} } + sin(3y) \frac{dy}{dt} + y = t\frac{df}{dt} + f[/tex]
Question 5
1 pts
Lumber which has been put through a planer is known as surfaced or
]
Answer:
what does that mean welp I have no idea sorry for answering
2.14 LAB: Using math functions
Given three floating-point numbers x, y, and z, output the square root of x, the absolute value of (y minus z) , and the factorial of (the ceiling of z).
Output each floating-point value with two digits after the decimal point, which can be achieved as follows:
print('%0.2f %0.2f %0.2f' % (your_value1, your_value2, your_value3))
Ex: If the input is:
5.0
6.5
3.2
Then the output is:
2.24 3.30 24.00
Answer:
In Java:
import java.util.Scanner;
import java.lang.Math;
public class MyClass {
public static void main(String args[]) {
Scanner input = new Scanner(System.in);
float x, y, z;
System.out.print("Enter three numbers: ");
x = input.nextFloat(); y = input.nextFloat(); z = input.nextFloat();
System.out.print("Square root of x: ");
System.out.printf("%.2f",Math.sqrt(x));
System.out.println();
System.out.print("Absolute of y - z: ");
System.out.printf("%.2f",Math.abs(y - z));
System.out.println();
int fact = 1;
for(int i = 1;i<=(int)Math.ceil(z);i++){
fact*=i;
}
System.out.print("Factorial of z: "+fact);
}
}
Explanation:
This line declares x, y and z as float
float x, y, z;
This line prompts user for three numbers
System.out.print("Enter three numbers: ");
The next line get input for x, y and z
x = input.nextFloat(); y = input.nextFloat(); z = input.nextFloat();
The italicized prints the square root of x rounded to 2 decimal places
System.out.print("Square root of x: ");
System.out.printf("%.2f",Math.sqrt(x));
System.out.println();
The italicized prints the absolute of y - z to 2 decimal places
System.out.print("Absolute of y - z: ");
System.out.printf("%.2f",Math.abs(y - z));
System.out.println();
This initializes fact to 1
int fact = 1;
The following iteration calculates the factorial of ceil z
for(int i = 1;i<=(int)Math.ceil(z);i++){
fact*=i;
}
This prints the calculated factorial
System.out.print("Factorial of z: "+fact);
}
}
A front wheel drive vehicle with four wheel disc brakes is pulling to the left. Tech A says an external kink or internal restriction in the LF brake line will result in this condition. Tech B says to use a compression fitting to repair a section of brake line. Who is correct? Tech A Tech A Tech B Tech B Both Both Neither
Answer:
Tech A is correct.
Explanation:
A front-wheel-drive pulling to the left can result from several factors. One of them is definitely a faulty break.
A correct diagnosis linking the problem to the brakes is when there is an internal restriction and the pull is constant to one side and gets worse when the brakes are applied.
To confirm this, one would need to lift the vehicle and rotate each wheel by hand to check for excessive friction.
So the restriction may be caused by:
brake calipers that are sticky to the drumtoo much brake fluid in the brake master cylinder - this prevents the caliper pistons from retracting when the brakes are released misadjusted drum brakes and or parking brakes.Cheers
64A geothermal pump is used to pump brine whose density is 1050 kg/m3at a rate of 0.3 m3/s from a depth of 200 m. For a pump efficiency of 74 percent, determine the required power input to the pump. Disregard frictional losses in the pipes, and assume the geothermal water at 200m depth to be exposed to the atmosphere.
Answer:
835,175.68W
Explanation:
Calculation to determine the required power input to the pump
First step is to calculate the power needed
Using this formula
P=V*p*g*h
Where,
P represent power
V represent Volume flow rate =0.3 m³/s
p represent brine density=1050 kg/m³
g represent gravity=9.81m/s²
h represent height=200m
Let plug in the formula
P=0.3 m³/s *1050 kg/m³*9.81m/s² *200m
P=618,030 W
Now let calculate the required power input to the pump
Using this formula
Required power input=P/μ
Where,
P represent power=618,030 W
μ represent pump efficiency=74%
Let plug in the formula
Required power input=618,030W/0.74
Required power input=835,175.68W
Therefore the required power input to the pump will be 835,175.68W
describe the historical development of building material being used in the construction indsury
Answer:
Construction, the techniques and industry involved in the assembly and ... Early building materials were perishable, such as leaves, branches, and animal hides. ... The well-developed masonry technology of Mesopotamia was used to build large ... although its precise description is unknown; the concealed faces of stones
Explanation:
Select four types of engineers who might be involved in the development of a product such as an iPhone.
(select four)
-hydraulic engineers
-geodetic engineers
-chemical engineers
-electrical engineers
-computer engineers
-manufacturing engineers
-mechanical engineers
-civil engineers
Answer:
electrical
computer
mechanical
and manufacturing .... I think
The answer is electrical, manufacture, computer, and chemical
The following are the results of a sieve analysis. U.S. sieve no. Mass of soil retained (g) 4 0 10 18.5 20 53.2 40 90.5 60 81.8 100 92.2 200 58.5 Pan 26.5 a. Determine the percent ner than each sieve and plot a grain-size distribution curve. b. Determine D10, D30, and D60 for each soil. c. Calculate the uniformity coefcient Cu. d. Calculate the coefcient of gradation Cc
Answer:
a.)
US Sieve no. % finer (C₅ )
4 100
10 95.61
20 82.98
40 61.50
60 42.08
100 20.19
200 6.3
Pan 0
b.) D10 = 0.12, D30 = 0.22, and D60 = 0.4
c.) Cu = 3.33
d.) Cc = 1
Explanation:
As given ,
US Sieve no. Mass of soil retained (C₂ )
4 0
10 18.5
20 53.2
40 90.5
60 81.8
100 92.2
200 58.5
Pan 26.5
Now,
Total weight of the soil = w = 0 + 18.5 + 53.2 + 90.5 + 81.8 + 92.2 + 58.5 + 26.5 = 421.2 g
⇒ w = 421.2 g
As we know that ,
% Retained = C₃ = C₂×[tex]\frac{100}{w}[/tex]
∴ we get
US Sieve no. % retained (C₃ ) Cummulative % retained (C₄)
4 0 0
10 4.39 4.39
20 12.63 17.02
40 21.48 38.50
60 19.42 57.92
100 21.89 79.81
200 13.89 93.70
Pan 6.30 100
Now,
% finer = C₅ = 100 - C₄
∴ we get
US Sieve no. Cummulative % retained (C₄) % finer (C₅ )
4 0 100
10 4.39 95.61
20 17.02 82.98
40 38.50 61.50
60 57.92 42.08
100 79.81 20.19
200 93.70 6.3
Pan 100 0
The grain-size distribution is :
b.)
From the diagram , we can see that
D10 = 0.12
D30 = 0.22
D60 = 0.12
c.)
Uniformity Coefficient = Cu = [tex]\frac{D60}{D10}[/tex]
⇒ Cu = [tex]\frac{0.4}{0.12} = 3.33[/tex]
d.)
Coefficient of Graduation = Cc = [tex]\frac{D30^{2}}{D10 . D60}[/tex]
⇒ Cc = [tex]\frac{0.22^{2}}{(0.4) . (0.12)}[/tex] = 1
3.) Technician A says that a scan tool can be used to verify engine operating temperature,
Technician B says that a refractometer can be used to verify engine operating temperature.
Who is right?
OA. A only
OB. B only
OC. Both A and B
OD. Neither A nor B
A Russian rocket engine (RD-110 with LOX-kerosene) consists of four thrust chambers supplied by a single turbopump. The exhaust from the turbine of the turbopump then is ducted to four vernier nozzles (which can be rotated to provide some control of the flight path). Using the information below, determine the thrust and mass flow rate of the four vernier gas nozzles. For individual thrust chambers (vacuum): F= 73.14 kN, c = 3279 m/sec Overall engine with verniers (vacuum): F= 297.93 kN, c = 3197 m/sec.
Answer:
- Vernier thrust is 5.37 kN
- mass flow rate of the four Vernier gas nozzles is 0.4048 kg/s
Explanation:
Given that;
For individual thrust chambers (vacuum);
Fc = 73.14 kN , Cc = 3279 m/sec
For Overall engine with Vernier (vacuum);
Foa = 297.93 kN = , Coa = 3197 m/sec.
- determine the Vernier thrust
Vernier thrust Fv = Foa - ( 4 × Fc )
Vernier thrust Fv = 297.93 - ( 4 × 73.14)
Vernier thrust Fv = 297.93 - 292.56
Vernier thrust Fv = 5.37 kN
Therefore, Vernier thrust is 5.37 kN
-
Vernier mass flow rate;
we know that
[tex]Co_{a}[/tex] = Fc + Fv / mc + mv
mv = Foa/Coa - Fc/Cc
we convert kilonewton to kilograms
1 kn = 102 kg
Fc = 73.14 kN = 73.14 × 102 = 7460.28 kg
Foa = 297.93 kN = 297.93 × 102 = 30388.86 kg
we substitute
mv = (30388.86 / 3197) - (( 4 × 7460.28) / 3279)
mv = 9.5054 - 9.1006
mv = 0.4048 kg/s
Therefore, mass flow rate of the four Vernier gas nozzles is 0.4048 kg/s
Please Help will give 50 points and brainliest!!!
In a short outline, describe five important attributes, skills, talents, learning areas, or work activities of someone in a “considerable” or “extensive preparation” career (Job Zone Four or Five) in the Architecture and Construction career cluster.
Answer:
They have to make sure that the building is safe, appropriate for city conditions, they are very creative, they can build really well, and can be very focused.
A site is underlain by two layers of normally consolidated clayey sand. The unit weights of the top layer are 19 and 21 kN/m2 and the layer is 6 meters thick. The unit weights of the bottom layer are 20 and 22 kN/m, and the layer is 8 meters thick. Below the bottom layer lies bedrock. The water table is located 2 meters below the ground surface. The top layer soil has a friction angle of 38 degrees, a cohesion intercept of 20 kPa, and an undrained strength of 160 kPa. The bottom layer soil has a friction angle of 33 degrees, a cohesion intercept of 10 kPa, and an undrained strength of 120 kPa. Point A is located 9 meters underground. All layers have a lateral stress ratio of 0.5.
Required:
a. Draw the profile neatly, add dimensions, and draw a tree on the ground surface.
b. Determine the geostatic vertical effective stress and the geostatic horizontal effective stress at point A.
c. Draw the Mohr Circle to determine the effective stress that acts at point A on a plane inclined 10 degrees counter-clockwise from the horizontal plane. Make sure the Mohr Circle is a well-drawn circle
Answer:
A) attached below
B) Geostatic vertical effective stress ( бv )
= 119.33 KN/m^2
Geostatic horizontal effective stress ( бn )
= 59.66 KN/m^2
C) attached below
Explanation:
attached below is a detailed solution
A) attached below
B) Determine the geostatic vertical effective stress and the geostatic horizontal effective stress at point A
Geostatic vertical effective stress ( бv )
= 119.33 KN/m^2
Geostatic horizontal effective stress ( бn )
= 59.66 KN/m^2
C) attached below
A consolidated-drained triaxial test is carried out on a sand specimen that is subjected to 80 kN/m2 confining pressure. The vertical deviator stress was increased slowly such that there is no built-up of pore water pressure within the specimen. The specimen failed when the addition axial stress reached 240 kN/m2. Find the friction angle of the sand. If another identical sand specimen was subjected to 150 kN/m2 confining pressure, what would be the deviator stress at failure.
Answer:
a) the friction angle of the sand is 36.87°
b) the deviator stress at failure is 450 kN/m³
Explanation:
Given the data in the question;
For a consolidated drained test
The effective major principle stresses
σ₃ = σ₃' = 80 kN/m²
and
σ₁' = σ₃' + (Δσ[tex]_{d}[/tex])[tex]_{f}[/tex] = 80 kN/m² + 240 kN/m² = 320 kN/m²
now
a) friction angle of the sand
σ₁' = σ₃'tan²( 45° + Ф/2' ) + 2c' tan( 45° + Ф/2 )
for sand; c' = 0
so
σ₁' = σ₃'tan²( 45° + Ф/2' )
we substitute
320 = 80 tan²( 45° + Ф/2' )
Ф' = 2 × [ tan⁻¹ (√[tex]\frac{320}{80}[/tex]) - 45° ]
Ф' = 2 × [ 63.4349° - 45° ]
Ф' = 2 × 18.4349
Ф' = 36.87°
Therefore, the friction angle of the sand is 36.87°
b) deviator stress
σ₁' = σ₃'tan²( 45° + Ф/2' )
σ₁' = σ₃' + (Δσ[tex]_{d}[/tex])[tex]_{f}[/tex] = σ₃'tan²( 45° + Ф/2' )
σ₃' + (Δσ[tex]_{d}[/tex])[tex]_{f}[/tex] = σ₃'tan²( 45° + Ф/2' ) 3.597
150 + (Δσ[tex]_{d}[/tex])[tex]_{f}[/tex] = 150tan²( 45° + 36.87°/2 )
150 + (Δσ[tex]_{d}[/tex])[tex]_{f}[/tex] = 600
(Δσ[tex]_{d}[/tex])[tex]_{f}[/tex] = 600 - 150
(Δσ[tex]_{d}[/tex])[tex]_{f}[/tex] = 450 kN/m³
Therefore, the deviator stress at failure is 450 kN/m³
identify which country has an absolute advantage in production of cookies and which has the absolute advantage in production of milk
a) Question Completion:
INPUT HOURS OF LABOR
Country Cookies Milk
Atlantis 2 hours 1 hour
Neverland 4 hours 1 hour
Answer:
1. Atlantis has the absolute advantage in the production of cookies.
2. No country has the absolute advantage in the production of milk.
Explanation:
Absolute advantage refers to superior production capability. It is determined when a country, for example, has the ability to produce a particular good or service at lower cost or more efficiently (i.e. with less resources) than the other country. In the scenario above, Atlantis has an absolute advantage in the production of cookies because it can produce the same quantity of cookies using 2 labor hours that Neverland can produce using 4 labor hours. But for the production of milk, Atlantis and Neverland share the same comparative advantage less they can use less labor hours to produce milk than they can produce cookies.
Sealer come in two general varieties
Answer:
red RTV is sealant for areas that get hot black RTV is for oily surfaces like oil pans and head covers
Explanation:
The accompanying specific gravity values describe various wood types used in construction. 0.320.350.360.360.370.380.400.400.40 0.410.410.420.420.420.420.420.430.44 0.450.460.460.470.480.480.490.510.54 0.540.550.580.630.660.660.670.680.78 Construct a stem-and-leaf display using repeated stems. (Enter numbers from smallest to largest separated by spaces. Enter NONE for stems with no values.)
Answer:
[tex]\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \\ \\{0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \\ \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \\ \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \\ \ \\ {0.7} & {\vert} & {8} \ \ \end{array}[/tex]
Explanation:
Given
[tex]0.32,\ 0.35,\ 0.36,\ 0.36,\ 0.37,\ 0.38,\ 0.40,\ 0.40,\ 0.40,\ 0.41,[/tex]
[tex]0.41,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.43,\ 0.44,\ 0.45,\ 0.46,[/tex]
[tex]0.46,\ 0.47,\ 0.48,\ 0.48,\ 0.49,\ 0.51,\ 0.54,\ 0.54,\ 0.55,[/tex]
[tex]0.58,\ 0.63,\ 0.66,\ 0.66,\ 0.67,\ 0.68,\ 0.78.[/tex]
Required
Plot a steam and leaf display for the given data
Start by categorizing the data by their tenth values:
[tex]0.32,\ 0.35,\ 0.36,\ 0.36,\ 0.37,\ 0.38.[/tex]
[tex]0.40,\ 0.40,\ 0.40,\ 0.41,\ 0.41,\ 0.42,\ 0.42,\ 0.42,\ 0.42,\ 0.42,[/tex]
[tex]0.43,\ 0.44,\ 0.45,\ 0.46,\ 0.46,\ 0.47,\ 0.48,\ 0.48,\ 0.49.[/tex]
[tex]0.51,\ 0.54,\ 0.54,\ 0.55,\ 0.58.[/tex]
[tex]0.63,\ 0.66,\ 0.66,\ 0.67,\ 0.68.[/tex]
[tex]0.78.[/tex]
The 0.3's is will be plotted as thus:
[tex]\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \ \end{array}[/tex]
The 0.4's is as follows:
[tex]\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \ \end{array}[/tex]
The 0.5's is as follows:
[tex]\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \ \end{array}[/tex]
The 0.6's is as thus:
[tex]\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \ \end{array}[/tex]
Lastly, the 0.7's is as thus:
[tex]\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ {0.7} & {\vert} & {8} \ \ \end{array}[/tex]
The combined steam and leaf plot is:
[tex]\begin{array}{ccc}{Steam} & {\vert} & {Leaf} \ \\ \\ {0.3} & {\vert} & {2\ 5\ 6\ 6\ 7\ 8} \ \\ \\{0.4} & {\vert} & {0\ 0\ 0\ 1\ 1\ 2\ 2\ 2\ 2\ 2\ 3\ 4\ 5\ 6\ 6\ 7\ 8\ 8\ 9} \ \\ \ \\ {0.5} & {\vert} & {1\ 4\ 4\ 5\ 8} \ \\ \ \\ {0.6} & {\vert} & {3\ 6\ 6\ 7\ 8} \ \\ \ \\ {0.7} & {\vert} & {8} \ \ \end{array}[/tex]
Consider a Rankine cycle with reheat using water (steam) as the working fluid. Saturated liquid at 100C exits the condenser. The fluid exits the boiler at 6500C, 20000 kPa. The cycle uses a single reheater with operating pressure 200 kPa and exit temperature 5000C. The mass flow rate of water (steam) in the cycle is 40 kg/s. The operation of the turbines and pump are adiabatic and have isentropic efficiency 0.90. As usual, neglect pressure losses in piping, boiler, reheater, and condenser. Compute: quality at the exit of the high-pressure turbine.
Technician A says that reinforcements may be made of plastic.
Technician B says that reinforcements may be made of nylon.
Who is right?
Answer:
Technician A Is right
Explanation:
Reinforcements, as the name suggests, are used to enhance the mechanical properties of a plastic. Finely divided silica, carbon black, talc, mica, and calcium carbonate, as well as short fibres of a variety of materials, can be incorporated as particulate fillers.