Energy released by the electron transport chain is used to pump h+ ions into which location.

In such a motion, the rigid body rotates along a fixed axis that is parallel to a fixed plane.

In other words, with respect to an inertial frame of reference, the axis is stationary and does not move or change direction. I=jmjr2j, where mj is the mass of the point particle and rj is its distance from the rotation axis, is the moment of inertia for a system of point particles revolving about a fixed axis. The angle of rotation is the angle at which an object revolves (turns) around a given point. Constant angular speed rotation is the most basic type of rotation around a fixed axis. The total torque then becomes zero.

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The centripetal acceleration for radius 2.0 m = 50 m/s²

The centripetal acceleration for radius 4.0 m = 25 m/s²

The centripetal acceleration for radius 6.0 m = 16.67 m/s²

The centripetal acceleration for radius 8.0 m = 12.5 m/s²

The centripetal acceleration for radius 10.0 m = 10 m/s²

An object that moving in a circle and has an acceleration vector pointing towards the center of the circle is called centripetal acceleration.

a₀ = v²/r

Where, a₀ = Centripetal acceleration

v = velocity of the object

r = radius of circular path

Given,

m = 1 kg

v = 10 m/s

r = 2.0 m, 4.0 m, 6.0 m, 8.0 m, 10.0 m

Now,

a₀₁ = 10²/2

a₀₁ = 50 m/s²

a₀₂ = 10²/4

a₀₂ = 25 m/s²

a₀₃ = 10²/6

a₀₃ = 16.67 m/s²

a₀₄ = 10²/8

a₀₄ = 12.5 m/s²

a₀₅ = 10²/10

a₀₅ = 10 m/s²

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The complete question is as follows:

"Keeping the mass at 1.0 kg and the velocity at 10.0 m/s, record the magnitude of centripetal acceleration for each given radius value. Include units. Radius: 2.0 m 4.0 m 6.0 m 8.0 m 10.0 m Acceleration: Radius factor: Acceleration factor:"

In order to lift a bucket of concrete, you must pull up harder on the bucket than it pulls down on you is referred to as a false statement.

This is referred to as an external agent which is capable of influencing the motion of an object or body. It is also capable of changing the state of rest of a body and the unit in Newton.

When lifting the bucket, the total opposite forces and not only the weight which is what pulls it down must be overcome in other to lift the object or body successfully which is why false was chosen.

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The angle at which a ray of light strikes a pane of window glass is smaller than the angle at which it passes out the other side.

When light go through window glass it will experience refraction due to change of light speed. The relation between angle of incidence and angle of refraction is given by the Snell's law:

n₁ sin∅₁ =  n₂ sin∅₂

Where:

n₁ = incident index (refractive index of medium 1)

n₂ = refraction index ((refractive index of medium 2)

∅₁ = incident angle

∅₂ = refraction angle

Typical refractive index for glass is around 1.5 while refractive index for air is 1.000273.

In the given case, the ray of light is from the window glass and pass out the other side. Hence,

n₂ = air

n₁ = glass

Since  n₁ > n₂ , the velocity in the air is greater than the velocity in the window glass. Hence, ∅₁ < ∅₂  or the incident angle is smaller than the refracted angle.

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Using the Time period formula for a Satellite,

the radius of orbit from earth center is 6.7590.

Time period : The satellite period is the time it takes for a satellite to make one orbit around the Earth, denoted by T. Therefore, T = distance traveled in 1 revolution/orbital velocity = 2πr/V.

We have the following information,

the Satellite revolves the earth twice in a day .

As we know,

mass of the earth(M) is 5.97 × 1024 kg

Gravitational constant (G)= 6.67 × 10-11 Nm²/kg²

The time taken to complete two rounds is a day. Time taken by the satellite in one alone will be cost to one by the day i.e., T = 24 hours

The time period of the satellite must be equal to

2T = 2×24×60×60 sec = 172800 sec.

According to Kepler's 3Rd law ,

T² = ( 4π²/GM )r³---(1)

where, T ---> time period

M --> mass of earth

G--> gravtional constant

r --> radius of orbit

putting all the values in above formula

(172800)² = ( 4×(3.14)²/(6.67 × 10-11 Nm²/kg²× 5.97 × 1024 kg))r³

=> r³ = (172800)²/96,720,640.93= 308.722

=> r = 6.75890 ~ 7

Hence, the radius of orbit is 6.75890

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Answer:

See below

Explanation:

The energy is her Potential Energy acquired by her doing work against gravity to climb up the rope ladder to the height of the zip line start.

Answer:

F = q V X B = I L X B     are descriptions of the force on a moving charge

Suppose that a battery terminal is + on the left connected by a wire to    a - charge on the right, the X indicates a cross product so the force on the moving charge is perpendicular to both the magnetic field and the moving charge.

If one wraps the hand around the wire with the thumb pointing in the direction of the "conventional" current, the induced field will be in the direction of the fingers - V X B is the cross product of the moving charge and the magnetic field;
Note q V = q L / t = (q / t) * L = I L

The magnitude of the sum of these two vectors is 23.95 m.

The sum of the vectors is the resultant vector obtained by resolving the vectors into x and y component.

the horizontal component of the vector (x)  = v cosθ

the vertical component of the vector  (y) = v sinθ

where;

For the first vector;

x = 16.3 m x cos(27.8) = 14.42 m

y = 16.3 m x sin(27.8) = 7.6 m

For the second vector;

x = 7.7 m  x   cos(20) = 7.24 m

y = 7.7 m  x  sin(20) = 2.63  m

Net horizontal and vertical vector;

∑x = 14.42 m  +   7.24 m   = 21.66 m

∑y = 7.6 m + 2.63 m = 10.23 m

The magnitude of the sum of these two vectors is calculated as;

v = √(∑x² + ∑y²)

v = √(21.66²   +    10.23²)

v  = 23.95 m

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50.0 g of water will require 3135  Joules energy is needed to change temperature by 15.0 C .

mass is 50 g

temperature is 15

Q=mC8ΔT

where,

m is mass of substance

C8=4.18 jouls /g

Q=50*4.18*15

Q=3135 J

The temperature is a numerical indicator of how cold or hot something is. One can measure temperature by using a thermometer. The calibration of thermometers involves using various temperature scales, which historically defined them using various reference points and thermometric materials. Several scales, including Fahrenheit and Celsius, can be used to express temperature, which is a unit of measurement. A hotter body (one with a higher temperature) will spontaneously move heat energy in the opposite direction to a cold body, as shown by temperature. the level of heat or cold in a body or environment the sensation of coldness or heat.

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The box's acceleration is 2.75m/s².

It is said that an equilibrium is stable when small, externally induced displacements from it result in forces that have a tendency to oppose the displacement and bring the body or particle back to the equilibrium state. A brick placed flat on the ground or a weight suspended by a spring are two examples.

Given,

F = 185 N is the amount of force that the student applied

Horizontal is at an angle of θ = 25°

Mass of box = 35kg

Between the box and the floor, there is a kinetic friction coefficient of

µ = 0.27

The equilibrium of forces is the foundation for the presented issue. We also need to find the equation of motion for the force's horizontal and vertical components in order to solve the problem. So,

Across the horizontal axis,

Tcosθ - µN = ma  (1)

The forces acting in the vertical direction are,

N + Tsinθ = mg

N = mg - Tsinθ  (2)

Replace (1) with the value of equation (2) as,

Tcosθ - µ( mg - Tsinθ) = ma

a = Tcosθ - µ( mg - Tsinθ)/m

The applied force, T = F = 185 N, causes the tension force on the rope.

fixing as,

a = 185×cos25× -(0.25)×35×9.8+((185)sin25)/35

a = 2.75m/s².

Consequently, we can say that the box's acceleration is a = 2.75m/s².

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The force P on the cable if the spring is compressed 0.5 in with a stiffness of k = 800 lb/ft is 46.91 lb

k = Fe / δ

k = Stiffness of spring

Fe = Force on spring

k = 800 lb / ft = 6.67 lb / in

δ = 0.5 in

Fe = k δ

Fe = 6.67 * 0.5

Fe = 33.33 lb

At joint A,

∑ MA = 0

( - Bx * 6 ) + ( - By * 6 ) + ( 33.33 * 30 ) = 0

Bx + By = 166.67  → ( 1 )

At joint D,

∑ MD = 0

( - By * 6 ) + ( P * 4 ) = 0

By = 0.067 P  → ( 2 )

∑ Fx = 0

- Bx + FCD cos 30° = 0  → ( 3 )

At joint B,

∑ MB = 0

( - FCD sin 30° * 6 ) + ( P * 10 ) = 0

FCD = 3.33 P

Sub FCD in ( 3 ),

- Bx + 3.33 P cos 30° = 0

Bx = 2.8867 P

Sub Bx and By in ( 1 ),

2.8867 P + 0.667 P = 166.67

P = 46.91 lb

Therefore, the force P on the cable if the spring is 46.91 lb

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Jupiter can never be farther from the sun than Saturn if the mass of the sun is 1991030 kg, the orbital radius of Jupiter is 7781011 m, and the orbital radius of Saturn is 1431012 m.

Fc = m v² / r

Fg = G M m / r²

Fc = Centripetal force

Fg = Gravitational force

m = Mass of planet

v = Linear Velocity of planet

r = Orbit radius

G = Gravitational constant

M = Mass of sun

Fc = Fg

G M m / r² = m v² / r

v² = G M / r

M = 1991030 kg

G = 6.67 * [tex]10^{-11}[/tex] N m² / kg²

v² = G M / r

For Jupiter,

r = 7781011 m

vj² = 6.67 * [tex]10^{-11}[/tex] * 1991030 / 7781011

vj² = 1.17 * [tex]10^{-11}[/tex]

vj = 3.42 * [tex]10^{-6}[/tex] m / s

For Saturn,

r = 1431012 m

vs² = 6.67 * [tex]10^{-11}[/tex] * 1991030 / 1431012

vs² = 9.28 * [tex]10^{-11}[/tex]

vs = 9.63 * [tex]10^{-6}[/tex] m / s

vs > vj

Therefore, Jupiter can never be farther from the sun than Saturn

The given question is incomplete. The complete question is :

Suppose the sun's gravity were switched off. the planets would leave their orbits and fly away in straight lines as described by newton's first law. (assume the mass of the sun is 1991030 kg, the orbital radius of Jupiter is 7781011 m, and the orbital radius of Saturn is 1431012 m. Would Jupiter ever be farther from the Sun than Saturn?

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Answer:

Yes. Producers are the basis of all food webs, for if there weren't any producers, there wouldn't be any food web whatsoever. The role of producers is the building block of food webs. They start out as not needing any other organism to be dependent of, then get consumed to form such a food web, whether it's in the ocean, in a jungle, or in the Arctic.

Explanation:

Answer:  The producers play the main role in the food web .  

Explanation:

Only producers have the ability to make food by trapping sunlight. Consumers require this energy because they cannot make it on their own. This energy is passed own throughout the individual food chains which make up the food webs. All these organisms provide energy for all other trophic levels ( organisms called consumers that consume (eat) other organisms for energy). that come above them. So there producers are considered as the basis of all food webs

Answer:

windmill, device for tapping the energy of the wind by means of sails mounted on a rotating shaft. The sails are mounted at an angle or are given a slight twist so that the force of wind against them is divided into two components, one of which, in the plane of the sails, imparts rotation.

Explanation:

The use of windmills was increasingly widespread in Europe from the 12th century until the early 19th century. Their slow decline, because of the development of steam power, lasted for a further 100 years. Their rapid demise began following World War I with the development of the internal-combustion engine and the spread of electric power; from that time on, however, electrical generation by wind power has served as the subject of more and more experiments

To work efficiently, the sails of a windmill must face squarely into the wind, and in the early mills the turning of the post-mill body, or the tower-mill cap, was done by hand by means of a long tailpole stretching down to the ground. In 1745 Edmund Lee in England invented the automatic fantail. This consists of a set of five to eight smaller vanes mounted on the tailpole or the ladder of a post mill at right angles to the sails and connected by gearing to wheels running on a track around the mill

The most important use of the windmill was for grinding grain. In certain areas its uses in land drainage and water pumping were equally important. The windmill has been used as a source of electrical power since P. La Cour’s mill, built in Denmark in 1890 with patent sails and twin fantails on a steel tower. Interest in the use of windmills for the generation of electric power, on both single-user and commercial scales, revived in the 1970s.

Answer:

100 m/s^{2}

Explanation:

the given information we have is:
vi = 30m/s

vf = 20m/s

t = 0.10s

we need to find a so we will use the following kinematics equation

[tex]vf=vi+at[/tex]

we can rearrange the equation so it will give us our desired answer like so:

[tex]a = \frac{vf-vi}{t}[/tex]

now we can plug in our given numbers

[tex]a = \frac{20 m/s - 30 m/s}{0.10s}[/tex]

which will equal

[tex]100 m/s^{2}[/tex]

He is going at the velocity of 40m/s even though he started at rest.

What is acceleration?

Acceleration is the rate at which velocity changes with respect to both speed as well as distance. If an object speeds up or down and is moving in a straight line, then the object is said to be accelerated. In a circular motion, the speed remains constant but the body is accelerated as the direction keeps on changing. The SI Unit is meter per second m/s2

Acceleration= 10m/s2

Initial velocity= 0m/s as the body started at rest.

Distance = 80 m

v2= u2+ 2aS

  = 02+ 2 10 80

  = 1600

v= 40m/s

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-400 N/m  spring constant has the shortest period when attached to a 100 g mass

F=800 N

x=2 m

F=kx

k=F/x

k=800 N/2 m

k=-400 N/m

The spring constant is the amount of force required to restore a spring to its initial shape after each unit of extension. This indicates that if we know the spring constant, we can easily calculate the amount of force needed to bend the spring. The reason is because if we exert more force on the spring than it can withstand, SHM will no longer be possible. N/m is its unit (Newton per meter). As a spring's length grows, less power is required to bring it to equilibrium, and vice versa.

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The glass & lead ball will both fall to the ground simultaneously. Galileo lowered two walls from the roof of Pisa. Whichever one lands on the ground first must be determined.

To shape metal, fill forming bags or use them as counterbalance. A minimum of 97% of the material is pure lead. All of these balls have precisely made for a flawless finish. They are additionally called lead shot.

Lead balls are frequently used in radiation protection for fill and melt into cracks and holes in lead shields in which other lead products, such as lead sheet or lead bricks, are inaccessible. The substance has a low point of melting and thus is simple to work with and quick to form a uniform barrier layer.

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The relationship between the linear speeds of the top point of the object, the center of the object, and the bottom point where the object contacts the ground

                                                      v_CM = ωR

What do you understand by rolling motion?

In order for two objects to come into touch with one another without sliding, optimal conditions must exist. This is where rolling comes into play. Rolling is a sort of motion that combines rotation and translation of the object with regard to a surface. Pure rolling is referred to as rolling without sliding.

As the wheel rolls on the ground, let's assume that the entire wheel is moving, and the wheel's centre of mass is moving at a certain speed, v_CM.

Each point along the wheel's edge will have a velocity v determined by the formula:

v = v_rot + v_CM

in the frame of reference of the ground.

The point is currently at rest in relation to the ground if the wheel is not slipping with regard to it.

The v_rot and v_CM vectors are anti-parallel, horizontal, and have a sum of zero at the point in touch with the ground.

v = v_rot + v_CM

0=v_rot + v_CM

v_rot = v_CM

Relationship between the centre of mass's speed and angular velocity for rolling without slipping:

                                         v_CM = ωR

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The time taken to travel from one edge of our galaxy to the opposite side for a photon of light is 36.5 * [tex]10^{6}[/tex] days

v = d / t

v = Velocity

d = Distance

t = Time

Distance from one edge of our galaxy to the opposite side = 100,000 light years

1 light year = 9.46 * [tex]10^{12}[/tex] km

100,000 light years = 9.46 * [tex]10^{17}[/tex] km

Speed of light = 300,000 km / s

t = d / v

t = 9.46 * [tex]10^{17}[/tex] / 300,000

t = 3.15 * [tex]10^{12}[/tex] s

t = 8.76 * [tex]10^{8}[/tex] hr

t = 36.5 * [tex]10^{6}[/tex] days

Therefore, the time taken to travel from one edge of our galaxy to the opposite side is 36.5 * [tex]10^{6}[/tex] days

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The distance is 7m while the displacement is 1m. Option A

We know that the displacement is defined as the distance that is covered in a specified direction. We must note that there are two kinds of quantities that we have in physics and these are the vectors and the scalars. The vectors are the quantities that have both magnitude and direction while the scalars are the quantities that have magnitude but do not have direction.

Now we know that when we are dealing with the vectors that we must be able to consider the direction of the vector in question. This is not important when we are dealing with a scalar.

Now, distance is a vector and displacement is a scalar hence we must be able to consider the direction as we deal with the displacement of the ball.

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Option B. the stored electric field energy can be greater than the stored magnetic field energy. An inductor is connected in series to a fully charged capacitor.

An inductor, additionally known as a coil, choke, or reactor, is a passive-terminal electric issue that stores electricity in a magnetic field whilst electric modern flows through it. An inductor normally includes an insulated twine wound into a coil.

An inductor is a passive digital element that's able to store electrical power in the form of magnetic electricity. basically, it uses a conductor this is wound into a coil, and while power flows into the coil from the left to the proper, this will generate a magnetic subject in the clockwise direction.

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16 m/s² is the acceleration when a roller coasters accelerates from an initial velocity of of 6.0 m/s to a final velocity of 70 m/s over 4 seconds.

a=(v-u)/t

a=acceleration=?

v= final velocity = 70m/s

u=initial velocity = 6m/s

t=time= 4 second

a=(v-u)/t

a=(70-6)/4

a=16 m/s²

The rate at which an item changes its velocity is known as acceleration, a vector variable. If an object's velocity is changing, it is accelerating. A moving object can occasionally alter its velocity by the same amount every second. a moving object that changes its speed by 10 m/s per second. Since the velocity is changing by a fixed amount every second, this is known as a constant acceleration. It is important to distinguish between an item with a constant acceleration and one with a constant velocity. Be not deceived! An object is accelerating if its velocity is changing, whether by a fixed amount or a variable quantity. Additionally, a moving item with a constant speed is not accelerating.

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The heat produced by a resistor is  1.134 × 10⁹ Calorie.

A resistor is an electrical component that controls or restricts how much electrical current can pass across a circuit in an electronic device. A specified voltage can be supplied via resistors to an active device like a transistor.

Given parameters:

Resistance of the resistor; R = 25 Ω.

Current; I = 5 amp.

Voltage; V = 125 V.

Time; t = 5 days = 5×24×60×60 second =432000 second.

We have to find; the heat generated by a resistor; q = ?

We know that, the heat generated by a resistor; q = I²Rt Joule.

= 5² × 25 × 432000 Joule.

= 2.7 × 10⁸ Joule.

= 4.2 ×  2.7 × 10⁸ Calorie.

=  1.134 × 10⁹ Calorie.

Hence,  heat generated by a resistor is  1.134 × 10⁹ Calorie.

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A) The initial kinetic energy of the bullet is 722J

B) Kinetic energy of the bullet and pendulum immediately after the bullet becomes embedded in the pendulum  0.68J

C)  The vertical height through which the pendulum rises  0.69cm

The following data-

Mass of the bullet - 10.0g

speed - 380m/s

mass of the pendulum - 10.0kg

length of cord - 70.0cm

To find the initial kinetic energy of the bullet -

KE=1/2mv^2

KE = 1/2 x 0.010 x 380^2

KE= 722J

initial kinetic energy = 722 J

To find the Kinetic energy of the bullet and pendulum immediately after the bullet becomes embedded in the pendulum, we need to first find the final velocity and vertical height through which pendulum rises-

we will find final velocity by applying the law of conservation of momentum

We know, Momentum of bullet is equal to the sum of the momentum of bullet and pendulum.

MbVb= (Mb+Mp)V

where,

Mb= mass of bullet

Mp = mass of pendulum

Vb = velocity of bullet

V = Final velocity

0.010 x 380 = ( 0.010 + 10)V

3.8 = 10.01V

V = 3.8/10.01

v = 0.37m/s

The final velocity = 0.37m/s

now, to find the vertical height

height = V^2/2g

= 0.37^2/2 x 9.8

= 0.136/19.6

= 0.00693m

converting to cm

0.00693 x 100 = 0.69 cm

To find the kinetic energy of the bullet and pendulum immediately after the bullet becomes embedded in the pendulum -

KE = 1/2 (Mb + Mp)V^2

KE = 1/2 ( 0.010 + 10) x 0.37 ^2

KE = 1/2 ( 10.01) x 0.1369

KE = 0.68J

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A force of 80 newtons is applied to the combined masses.acceleration of the system is =40/3 or 13.33 metre/sec².

acceleration, rate at which velocity changes with time, in terms of both speed and direction. A point or an object moving in a straight line is accelerated if it speeds up or slows down. Motion on a circle is accelerated even if the speed is constant, because the direction is continually changing.

acceleration of object A= FORCE APPLIED ÷ MASS OF A

                                                               =80÷ mass of A

                       mass of A = 80÷ acc of object A

                        mass of A= 80÷20=4kg

                         mass of A = 4kg

acc of object B = force applied ÷ mass of B

 mass of object B =force applied ÷ acc of object B

 mass of object B=80÷40=2kg

mass of object B =2Kg

when same force is applied to the combined system of 4kg and 2kg then acceleration of the combined mass is = force applied ÷ total mass

=80÷[4+2]

=80÷6

=40÷3

=13.333 metre/sec²  

acc of the combined system is 13.333 metre/sec²

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The magnitude of the net force on particle Q₂ is  6.487 x 10⁶ N.

The net force on particle Q₂ is obtained by applying Coulomb's law of electrostatic force.

Force between Q₁ and Q₂;

F₁₂ = kq₁q₂/r²

where;

F₁₂ = (9 x 10⁹ x 20.5 x 10⁻³ x 9.3 x 10⁻³)/(0.98)²

F₁₂ = 1.787 x 10⁶ N

Force between Q₂ and Q₃;

F₂₃ = kq₂q₃/r²

F₂₃ = (9 x 10⁹ x 9.3 x 10⁻³ x 31.6 x 10⁻³)/(0.75)²

F₂₃ = 4.7 x 10⁶ N

The net force on particle Q₂;

F(net) = F₁₂ + F₂₃

F(net) = 1.787 x 10⁶ N +  4.7 x 10⁶ N

F(net) =  6.487 x 10⁶ N

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