Answers
Answer:
To the right
Explanation:
Metals are to the left, nonmetals are to the right. There's a border I drew that separates nonmetals and metals
Related Questions
What happens to balls dropped on opposite sides of earth
Answers
Answer:
It reaches its top speed at the very center of the globe and continues rocketing toward the other side
Explanation:
So what happens? Well, as the ball drops through the hole it picks up speed - that's the acceleration due to gravity. It reaches its top speed at the very center of the globe and continues rocketing toward the other side.
A fisherman in a stream 30 cm deep looks downward into the water and sees a rock on the stream bed. How deep does the stream appear to the fisherman? Let the index of refraction of the water equal 1.33O 26cmO 40cmO 34cmO 23cm
Answers
Given:
The depth of the stream, d=30 cm
The refractive index of water, n=1.33
To find:
The apparent depth of the stream.
Explanation:
Let the eye of the fisherman is at a large height from the surface of the water.
Thus,
[tex]\sin(i)=\frac{x}{d}[/tex]Where i is the angle of incidence and r is the opposite side of the angle of incidence.
And,
[tex]\sin(r)=\frac{x}{h}[/tex]Where r is the angle of refraction and h is the apparent depth of the stream.
The refractive index of the air is n_a=1.
From snell's law,
[tex]n_a\sin r=n\sin i[/tex]On substituting the known values,
[tex]\begin{gathered} 1\times\frac{x}{h}=1.33\times\frac{x}{d} \\ \implies h=\frac{d}{1.33} \\ =\frac{30}{1.33} \\ =23\text{ cn} \end{gathered}[/tex]Final answer:
The correct answer is option d.
Which of the following methods can demonstrate cause and effect?
correlational
experimental
naturalistic observation
survey method
Answers
Where do you find valence electrons?
Answers
Answer:Valence electrons are the electrons in the outermost shell, or energy level, of an atom. For example, oxygen has six valence electrons, two in the 2s subshell and four in the 2p subshell.
Explanation:
A car is driving away from you at a constant speed for a while, and then it
gradually slows to a stop. Imagine a speed-versus-time graph showing the
car’s motion. Describe the line on the graph.
Answers
The line on the speed-time graph will slant from up to down showing a state of coming to rest.
What is speed - versus - time graph?
A speed versus-time-graph is a type of graph that shows the relationship between the speed of an object and the time of motion of the object.
For upward acceleration of an object when the object is speeding up, the line on the graph for such motion increases upward in a direct relationship with time of motion.
For a downward motion in which the object in motion slows down, the line on the graph for such motion will slant downward showing a gradual decrease in the speed of the object.
Thus, for a car that is driving away from you at a constant speed for a while, and then it gradually slows to a stop, the line on the speed-time graph will slant from up to down showing a state of coming to rest.
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In laser eye surgery, the average laser pulse power is 74 kW, and contains 1 mJ of light energy. Each laser pulse lasts
nanosecond.
Answers
If an average laser pulse power is 74 kW, and contains 1 mJ of light energy, each laser pulse lasts for a time period of 0.074 ns
E = P t
E = Light energy
P = Pulse power
t = Time
E = 74 KW = 74 * 10³ W
P = 1 * [tex]10^{-3}[/tex] J
t = E / P
t = 74 * 10³ / 1 * [tex]10^{-3}[/tex]
t = 74 * [tex]10^{6}[/tex] s
t = 0.074 ns
Power is the rate of work done. It can also be called as rate at which energy is used. This can be used to all forms of work and all types of energy.
Therefore, each laser pulse lasts 0.074 nanosecond.
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A storage tank 20 m high is filled with pure water. (Assume the tank is open and exposed to the atmosphere at the top.)
(a) Find the gauge pressure at the bottom of the tank.
(b) Calculate the magnitude of the net force that acts on a square access hatch at the bottom of the tank that measures 0.6 m by 0.6 m.
PLEASE HELP!!!
Answers
The gauge pressure at the bottom of the tank is 297500 N/m².
The magnitude of the net force that acts on a square access hatch at the bottom of the tank is 107100 N.
What is the pressure at the bottom of the tank?The pressure at the bottom of the tank is the pressure due to the weight of the fluid above it and the atmospheric pressure.
The pressure due to the atmosphere = 101300 N/m²
The pressure due to the water above the tank is calculated with the formula below:
Pressure = height * density * g
height of tank = 20 m
the density of water = 1 * 10³ kg/m³
g = 9.81 m/s²
Pressure due to water = 20 * 1 * 10³ kg/m³ * 9.81
Pressure due to water = 192000 N/m²
Total pressure = 192000 + 101300 N/m²
Total pressure = 297500 N/m²
B. Force = pressure * area
area of the hatch = 0.6 * 0.6 = 0.36 m²
Force = 297500 N/m² * 0.36 m²
Force = 107100 N
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A ball with a mass of 1.50 kg traveling +2.00 m/s collides with a stationery ball with a mass of 1.00 kg. After the collision, the velocity of the 1.50-kg ball is +0.40 m/s. What is the velocity of the 1.00-kg ball after the collision?
Answers
The velocity of the 1.00-Kg ball after the collision with the 1.50 Kg ball is 2.4m/s.
The mass M₁ of first ball is 1.5 Kg. The initial velocity U₁ of the first ball is 2m/s.
The mass M₂ of the second ball is 1 Kg. The initial velocity U₂ if the second ball is 0m/s.
After collision, the final velocity V₁ of the first ball is +0.40m/s.
Let us say that the final velocity of the second ball after collision is V₂.
As there is no external force,
We can apply the concept of conservation of linear momentum,
According to which, in a system when no external force is in effect, the total linear momentum of the system is conserved.
We can assume both balls to be a single system,
Initial momentum = Final momentum
M₁U₁+M₂U₂ = M₁V₁+M₂V₂
Putting all the values,
(1.5x2)+(1x0) = (1.5x0.4)+(1V₂)
V₂ = 1.5(2-0.4)
V₂ = 2.4m/s.
So, the final velocity of the 1.00kg ball is 2.4m.s.
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draw a sample displacement verses time graph for a car that drives away at a constant speed from a point and has no initial speed. Label any known values.
Answers
On a graph of distance vs time, a straight line indicates that a car speed is constant.
Velocity is the pace and direction of an object's movement, whereas speed is the time rate at which an object is travelling along a path. In other words, velocity is a vector, whereas speed is a scalar value.On a speed-time graph, a horizontal line denotes a constant speed. On a speed-time graph, an inclining line denotes an acceleration. The sloping line indicates that the object's speed is varying. Either the item is accelerating or decelerating. Distance and displacement appear to have the same meaning, they actually have very different definitions and implications. Displacement is the measurement of how far an object is out of place, whereas distance refers to ,how much ground an object has covered during its motion.Therefore, when a car moves with constant speed the the distance time graph is in straight line.
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A 100-kg box is sliding down a frictional surface with an acceleration of -2.0m/s².
Determine the magnitude of the friction force on the object.
Answers
Answer: 1180 N
Explanation:
F - Fs = ma
⇒ (100 × 9.8) - Fs = 100 × (-2)
⇒ Fs = 1180 N
What effect would that have on the force resulting in accordance to Newton's Third law ?
Answers
According to the Newton's Third law, the force sent back with equal and opposite in the reaction.
What is meant by Newton's Third law?According to Newton's third law, two objects exert a force of equal magnitude and opposite direction. This law represents a certain symmetry in nature: forces always occur in pairs, and one body cannot exert a force on another without experiencing a force on it. Newton's 3rd law of motion states that action and reaction are always equal but opposite in direction. Newton's third law that for every action in nature there is an equal and opposite reaction. If object A exerts a force on object B, object B also uses an alike and across-form force on object A.
So we can conclude that the force is in equal in magnitude but in opposite direction according to Newton's Third law.
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...as shall be thought most meet and convenient for the general good of the colony, unto which we promise all due submission and obedience.
This quote from the Mayflower Compact may have influenced the colonists to believe that (1 point)
a
they needed to expand to created additional colonies
b
all citizens would have to abide by the new laws created
c
they needed to create a list of laws for all citizens to follow
d
each person in the colony must be obedient to the laws of the king
Answers
Mayflower Compact influenced the colonists to believe that all citizens would have to abide by the new laws created
The colonists who sailed for the New World created a set of self-government laws known as the Mayflower Compact. The Pilgrims and other immigrants hoped to settle in northern Virginia as soon as they arrived in America. The immigrants' ship was forced off track by perilous shoals and storms and instead came ashore in Massachusetts, close to Cape Cod, outside of Virginia's authority.
The colonial authorities knew that life without laws may be devastating, so they created the Mayflower Compact to assure that a workable social structure would prevail. It preserved the idea of a law enacted by the people. This is the essential tenet of democracy. The Declaration of Independence was influenced by the notion that all citizens, not just a small group of elites, should have their interests represented by the government.
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Calculate the force which will produce an extension of 0.30mm in a steel wire with a length of 4.0m and a cross section area of 2.0 x 10^(-6) m^2Youngs modulus of steel is 2.1 x 10 ^11 Pa
Answers
Given data:
* The extension of the steel wire is 0.3 mm.
* The length of the wire is 4 m.
* The area of cross section of wire is,
[tex]A=2\times10^{-6}m^2[/tex]* The young modulus of the steel is,
[tex]Y=2.1\times10^{11}\text{ Pa}[/tex]Solution:
The young modulus of the steel in terms of the force and extension is,
[tex]Y=\frac{F\times l}{A\times dl}[/tex]where F is the force acting on the steel wire,, l is the original length of the wire, dl is the extension of the wire, and A is the area,
Substituting the known values,
[tex]\begin{gathered} 2.1\times10^{11}=\frac{F\times4}{2\times10^{-6}\times0.3\times10^{-3}} \\ F=0.315\times10^2\text{ N} \\ F=31.5\text{ N} \end{gathered}[/tex]Thus, the force which produce the extension of 0.3 mm of the steel wire is 31.5 N.
A ballerina begins a tour jeté (Fig. 11-20a) with angular speed w; and a rotational inertia consisting of two parts:
Ileg = 1.44 kg m² for her leg extended outward at angle
0 = 90.0° to her body and Itrunk = 0.660 kg m² for the rest of
her body (primarily her trunk). Near her maximum height
she holds both legs at angle 0 = 30.0° to her body and has angular speed wf (Fig. 11-20b). Assuming that trunk has not
changed, what is the ratio wf/w?
Answers
The term "moment of inertia" refers to the quantity that describes how a body resists angular acceleration. It is calculated by multiplying each particle's mass by its square of the distance from the axis of rotation.
A rigid body's moment of inertia—also referred to as its mass moment of inertia, angular mass, second moment of mass, or—most precisely—rotational inertia—determines the torque.
"I = L / W"
Let Ja be the moment of inertia of the legs.
When leg at 90 degrees,
Ja1 = 1.44 kgm² = m*1²...m = 1.44/1 = 1.44
When both legs at 26.5°
sin 26.5°= 0.45
Ja2 = 2*m*(sen26.5)² = 2.88*.45² = 0.58 kgm²
Jt1 = Ja1 + Jt = 1.44 + 0.76 = 2.15 kgm²
Jt2 = Ja2+Jt = 0.58+0.706 = 1.29 kgm²
wf/w = Jt1/Jt2 = 2.15/1.29 = 1.67
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7. Which wave property increases as the energy of a wave increases? *O periodfrequencywavelengthamplitude
Answers
Energy is directly proportional to the amplitude.
Thus, the amplitude of the wave increases as the energy of the wave increases.
please help!!
What is the name of the current theory that astronomers have developed that is used to describe the possible formation of the solar system?
Answers
Answer:
The answer of the question is nebular theory
A penny, starting from rest at Position 1, rolls down and then up a curved track towards Position 5. When it reaches Position 5, it rolls back down the track. Which description below is most consistent with what you can expect from the penny's motion?
A. The penny will roll as high as Position 3 since that position has the least potential energy.
B. The penny will roll past Position 1 since energy cannot be created or destroyed.
C. The penny will roll as high as Position 2 since some of the energy will be transformed to heat.
D. The penny will roll as high as Position 1 since energy cannot be created or destroyed
Answers
The penny will roll past Position 1 since energy cannot be created or destroyed, therefore the correct answer is option B.
What is mechanical energy?The sum of all the energy in motion (total kinetic energy) and all the energy that is stored in the system (total potential energy) is known as mechanical energy.
ME= PE + KE
As given in the problem if a penny, starting from rest at Position 1, rolls down and then up a curved track towards Position 5.
When it reaches Position 5, it rolls back down the track, then we have to find out Which description below is most consistent with what you can expect from the penny's motion,
Thus, the penny will roll past Position 1 since energy cannot be created or destroyed, therefore the correct answer is option B.
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A 32.3 kg mass ( ) is suspended by the cable assembly as shown in the figure. The cables have no mass of their own. The cable to the left ( 1 ) of the mass makes an angle of 0.00∘ with the horizontal, and the cable to the right ( 2 ) makes an angle ( 2 ) of 38.5∘ . If the mass is at rest, what is the tension in each of the cables, 1 and 2 ? The acceleration due to gravity is =9.81 m/s2 .
Answers
The tension in each of the wires, number 1 and number 2, respectively
T_1=398.35
This is further explained below.
What is tension ?Generally, At equilibrium, in direction [tex]$\Sigma F_y=0$[/tex]
[tex]\Rightarrow T_2 \sin \theta_2-m g=0 \text {. }[/tex]
[tex]$\Rightarrow \quad T_2 \sin \theta_2=m g$[/tex]
tension, [tex]$T_2=\frac{m g}{\sin \theta_2}$[/tex]
[tex]T_2=\frac{32.3 \times 9.81}{\sin (38.5}^{\circ})} \\\\T_2= {509.00} \mathrm{~N}$.[/tex]
[tex]In x-dirn; $\quad \Sigma F_x=0 \Rightarrow T_2 \cos \theta_2-T_1=0$.[/tex]
[tex]\Rightarrow T_1 &=T_2 \cos \theta_2 \\[/tex]
[tex]T_1 &=509.00\times \cos (38.5^{\circ}\right) \\\\[/tex]
T_1=398.35
In conclusion, the tension in each of the cables, 1 and 2
T_1=398.35
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Create a Graph : Include numbers, axes, and order pairs
Answers
a) Peak value = 20
b) Average value = 9.0
c) RMS value = 14.15
Explanation:The peak-to-peak value = 40
[tex]v_{p-p}=40[/tex][tex]\begin{gathered} v_{p-p}=2v_p \\ \\ 40=2v_p \\ \\ v_p=\frac{40}{2} \\ \\ v_p=20 \end{gathered}[/tex]c) The rms value
[tex]\begin{gathered} v_{rms}=\frac{v_p}{\sqrt{2}} \\ \\ v_{rms}=\frac{20}{\sqrt{2}} \\ \\ v_{rms}=14.14 \end{gathered}[/tex]b) Average value over alternation of the sine wave
[tex]\begin{gathered} v_{avg}=0.637v_p \\ \\ v_{avg}=0.637\times14.14 \\ \\ v_{avg}=9.0 \end{gathered}[/tex]Using m1v1i + m2v2i = m1v1f + m2v2f how does one describe the concept of left or right mathematically?
Answers
The concept of left or right can be described mathematically by using ( m₁*v₁)initial + (m₂*v₂)initial = (m₁*v₁)final + (m₂*v₂)final because as per the conservation of the momentum the, momentum before and after the collision will remain conserved.
What is momentum?It can be defined as the product of the mass and the speed of the particle, it represents the combined effect of mass and the speed of any particle,
P = mv
As given in the problem we have described the concept of left or right mathematically by using( m₁*v₁)initial + (m₂*v₂)initial = (m₁*v₁)final + (m₂*v₂)final
The total momentum of the object before the collision would be equal to the total momentum of the objects after the collision.
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What will happen to the velocity of light ray when it passes from glass to air?
Answers
Answer:
So, when light passes from air to glass, its speed decreases. Q.
Explanation:
ray from the ghostbusters
ASAPPPPPPPPPPPPPPPPPPPPPPPP!!!!!!
Answers
Answer:
its A
Explanation:
Answer:
it A bc it makes the most sense
Explanation:
How is Newton's Third Law of Motion used in the sport Jokgu?
Answers
Newton's third law of motion states that every force has an equal and opposite reaction force. That is when two bodies interact with each other, they apply a force on each other which are equal in magnitude and opposite in direction.
In Jokgu, when you hit the ball it applies an equal force on the leg. And when a player presses his leg against the ground, the ground exerts an equal force on the player which helps him to move around.
The Big Dipper is an example of an observed pattern of stars called a ___________.
Answers
Answer:
The answer is the asterism.
Explanation:
An asterism is recognizable pattern of stars . some other commonly recognized asterisms are the little dipper ,orion's belt , and the teapot
Question 2 of 25Which of the following is an effect of increasing the wavelength of anelectromagnetic wave?O A. Energy decreases.O B. Speed decreases.O C. Speed increases.O D. Energy increases.SUBMIT
Answers
Thesppeed of electromagnetic waves remains the same an is eqal to the speed of light. The wavelength is rearlated tothe energy bty the following ormula:
[tex]\lambda=\frac{c}{f}[/tex]Wher:
[tex]\begin{gathered} \lambda=\text{ wavelength} \\ c=\text{ speed of light} \\ f=\text{ frequency} \end{gathered}[/tex]Therefore, if the wavelength increases the frequency must decrease.-
Since the energy is proportiona to the frequency if the dfrequency decreases the energy decreases. Therefore, the right answer is A.
Answer:
energy decreases
Explanation:
hope this helps!
Describe the relationship between the state of matter of a pure substance (gas, liquid, solid) and the motion of the particles.
I will brainliest you!
Answers
Answer:
Gas is one of the state of pure substance and it have no shape and also it is non comprsable
Liquid is state of pure substance and it occupies the shape of its body and its slightly comrisable
Solid is the other physical state and it have definite volume and shape and also it is highly comrisable
3. A uniform light beam is pivoted halfway along its length. At one end it supports a load of 5 kN while the other end is tethered to a fixed point by a rope inclined at 45° to the horizontal. If the beam is in equilibrium, what is the tension in the rope?
Answers
Answer:
Approximately [tex]7.1\; {\rm kN}[/tex] ([tex]5 \sqrt{2}\; {\rm kN}[/tex].)
Explanation:
Let [tex]F_{1}[/tex] and [tex]F_{2}[/tex] denote the two forces that act on this beam. Let [tex]s_{1}[/tex], [tex]s_{2}[/tex], [tex]\theta_{1}[/tex], and [tex]\theta_{2}[/tex] denote the distance from pivot and angle relative to the beam of the two forces, respectively. The magnitude of the torques that the two forces exert on this beam will be [tex]F_{1}\, s_{1}\, \sin(\theta_{1})[/tex] and [tex]F_{2}\, s_{2}\, \sin(\theta_{2})[/tex], respectively.
The two forces in this question act on the beam from opposite sides of the pivot. Hence, for the beam to be in equilibrium, the torque from the two forces need to be equal in magnitude. In other words:
[tex]F_{1}\, s_{1}\, \sin(\theta_{1}) = F_{2}\, s_{2}\, \sin(\theta_{2})[/tex].
Let [tex]F_{1}[/tex] denote the [tex]5\; {\rm kN}[/tex] force that the load exerts on this beam; [tex]\theta = 90^{\circ}[/tex] since this load is placed directly on the beam. The normal force from the load will be perpendicular to the beam.
Let [tex]F_{2}[/tex] denote the force that the rope exerts on this beam; [tex]\theta = 45^{\circ}[/tex].
Note that [tex]s_{1} = s_{2}[/tex] since the pivot is exactly halfway between the two forces.
Rearrange the equation [tex]F_{1}\, s_{1}\, \sin(\theta_{1}) = F_{2}\, s_{2}\, \sin(\theta_{2})[/tex] to find the unknown [tex]F_{2}[/tex]:
[tex]\begin{aligned}F_{2} &= \frac{F_{1}\, s_{1}\, \sin(\theta_{1})}{s_{2}\, \sin(\theta_{2})} \\ &= \frac{F_{1}\, \sin(\theta_{1})}{\sin(\theta_{2})} && (\text{since $s_{1} = s_{2}$}) \\ &= \frac{5\; {\rm kN}\, \sin(90^{\circ})}{\sin(45^{\circ})} \\ &= \frac{5\; {\rm kN}}{(1 / \sqrt{2})} \\ &= 5 \sqrt{2}\; {\rm kN} \\ &\approx 7.1\; {\rm kN} \end{aligned}[/tex].
The tension in the rope will be equal in magnitude to the force exerted on the beam: approximately [tex]7.1\; {\rm kN}[/tex] ([tex]5 \sqrt{2}\; {\rm kN}[/tex].)
What is the index of refraction of a refractive medium if the angle of incidence in air (n=1.0003) is 87 degrees and the angle of refraction is 10 degrees?
Answers
Given:
The refractive index of the air, n₁=1.0003
The angle of incidence, θ₁=87°
The angle of refraction, θ₂=10°
To find:
The refractive index of the medium.
Explanation:
From the snell's law,
[tex]n_1\sin\theta_1=n_2\sin\theta_2[/tex]Where n₂ is the refractive index of the medium.
On substituting the known values,
[tex]\begin{gathered} 1.0003\sin87\degree=n_2\sin10\degree \\ \implies n_2=\frac{1.0003\times\sin87\degree}{\sin10\degree} \\ =5.75 \end{gathered}[/tex]Final answer:
Thus the refractive index of the medium is 5.75
I need help with the answer
Answers
Answer:
Yes, of course
Explanation:
Ask the questionI'll answer itSituation: A .71-kg billiard ball moving at 2.5 m/s in the x-direction strikes a stationary ball of the same mass. After the collision, the first ball moves at 2.17 m/s, at an angle of 30.0° with respect to the original line of motion. Assuming an elastic collision (and ignoring friction and rotational motion), answer the following questions to find the struck ball's momentum after the collision.1. Calculate the x-component of the first ball's final momentum after the collision in kg*m/s.2. Using the conservation of momentum in the x-direction, find the struck ball's x-component of momentum.3. Calculate the y-component of the first ball's final momentum after the collision in kg*m/s.4. Using the conservation of momentum in the y-direction, find the struck ball's y-component of momentum.
Answers
We are given the following situation:
Ball 1 strikes ball 2 and after the collision forms an angle of 30 degrees. To determine the x-component of the final momentum of the first ball we use the following formula:
[tex]P_{1fx}=m_1v_{1f}\cos\theta_1[/tex]Where:
[tex]\begin{gathered} P_{1fx}=final\text{ x-component of the momentum of ball 1} \\ m_1=\text{ mass of ball 1} \\ v_{1f}=\text{ final velocity of ball 1} \\ \theta_1=\text{ angle of ball 1} \end{gathered}[/tex]Now, we substitute the values:
[tex]P_{1fx}=(0.71kg)(2.17\frac{m}{s})\cos(30)[/tex]Solving the operations we get:
[tex]P_{1fx}=1.33kg\frac{m}{s}[/tex]Therefore, the x-components of the momentum of the first ball is 1.33 kgm/s.
Part 2. To determine the x-component of the second ball we will do a balance of momentum in the x-direction:
[tex]P_{10x}+P_{20x}=P_{1fx}+P_{2fx}[/tex]Where:
[tex]\begin{gathered} P_{10x},P_{20x}=\text{ initial momentum in the x-direction of ball 1 and 2} \\ P_{2fx},P_{20x}=\text{ final momentum in the x-direction of ball 1 and 2} \end{gathered}[/tex]Since the second ball starts from rest we have that its initial momentum is zero, therefore:
[tex]P_{10x}=P_{1fx}+P_{2fx}[/tex]Now, we solve for the x-component of the momentum of the second ball:
[tex]P_{10x}-P_{1fx}=P_{2fx}[/tex]The initial momentum of the first ball is the product of its mass and velocity:
[tex]m_1v_{01}-P_{1fx}=P_{2fx}[/tex]Now, we plug in the values:
[tex](0.71kg)(2.5\frac{m}{s})-1.33kg\frac{m}{s}=P_{2fx}[/tex]Solving the operations:
[tex]0.44kg\frac{m}{s}=P_{2fx}[/tex]Part 3. To calculate the y-component of the first ball after the collision we will use the following formula:
[tex]P_{1fy}=m_1v_{1f}\sin\theta[/tex]Now, we plug in the values:
[tex]P_{1fy}=(0.71kg)(2.17\frac{m}{s})\sin(30)[/tex]Solving the operations we get:
[tex]P_{1fy}=0.77kg\frac{m}{s}[/tex]Therefore, the y-component of the momentum of the first ball is 0.77 kgm/s.
Part 4. To determine the y-component of the second ball we use a balance of momentum of the y-components of the balls:
[tex]P_{10y}+P_{20y}=P_{1fy}+P_{2fy}[/tex]Since the first ball is not moving in the y-direction this means that its y-component of the momentum is 0. Since ball 2 is not moving initially this means that its momentum in the y-direction is zero.
[tex]0=P_{1fy}+P_{2fy}[/tex]Now we solve for the y-component of the second ball, and we get:
[tex]-P_{1fy}=P_{2fy}[/tex]Therefore, the y-component of the second ball is:
[tex]-0.77kg\frac{m}{s}=P_{2fy}[/tex]Therefore, the y-component of the second ball is -0.77 kgm/s.