EASY MATH
Find all the zeros of f(x)= x^3 − 6x^2 + 13x − 20 given that 1−2i is a zero.
x=

Answer:

f

f

v

Step-by-step explanation:

False. Data mining can automatically find beneficial patterns for a business by utilizing various techniques and algorithms to extract valuable insights and uncover hidden patterns from large datasets.

Data mining refers to the process of discovering patterns, relationships, and insights from large datasets. It involves using various techniques and algorithms to extract valuable information and knowledge from data. One of the primary goals of data mining is to uncover patterns that can be beneficial for businesses, such as identifying customer preferences, market trends, or predicting future outcomes.

Through automated analysis and pattern recognition, data mining can uncover hidden patterns and relationships that may not be apparent through traditional manual analysis. Therefore, data mining has the potential to automatically find beneficial patterns for businesses, making the statement "Data Mining cannot automatically find beneficial patterns for a business" false.

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Answer:

i just did this one it is YES

Step-by-step explanation:

Answer:

7

Step-by-step explanation:

Answer:

so one the MAD is wrong its actually 1 for both and

The multiple would be 4 and 10.

Step-by-step explanation:

4x1=4

10x1=10

Answer:

71.3 * 10² that's the answer to your question

Step-by-step explanation:

The answer is 713 X 10^4

I hope it helps

Answer:

D Length of  F I S H

Step-by-step explanation:

I chose the bowling one and got it wrong, but you can have the right answer

Answer: length of a fish

Step-by-step explanation: quizzzz

Answer:

600ft^2

Step-by-step explanation:

Step One: There are two identical faces of each, which means we can multiply each face times two to make it faster. The first face will be 2(4*12)=96. I muliplied by two, because, once again, there are two faces of each.

Step Two: The next is 2(18*12)=432 and lastly, 2(4*18)= 72

Step Three: We just have to add it all up: 72+96+432= 600ft^2

The 95% confidence interval estimate of the overall difference in the percentages of Democrats and Republicans that prioritize protecting the environment is approximately 37.0% ± 5.0%.

Calculate the proportions for Democrats and Republicans:

Proportion of Democrats prioritizing environment = 731/850 ≈ 0.860

Proportion of Republicans prioritizing environment = 466/950 ≈ 0.490

Next, calculate the standard error (SE) of the difference between the proportions:

SE = √[(p1(1 - p1))/n1 + (p2(1 - p2))/n2]

= √[(0.860(1 - 0.860))/850 + (0.490(1 - 0.490))/950]

≈ √(0.000407 + 0.000245)

≈ √0.000652

≈ 0.0255

Now, calculate the margin of error (ME) using the critical value for a 95% confidence level (z-value):

ME = z × SE

≈ 1.96 × 0.0255

≈ 0.04998

Finally, construct the confidence interval:

Difference in proportions ± Margin of error

(0.860 - 0.490) ± 0.04998

0.370 ± 0.04998

The 95% confidence interval is approximately 37.0% ± 5.0%.

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The function f(x) = e⁻ˣ² has critical points at x = 0 and inflection points at x = √(1/2) and x = -√(1/2). function does not have any local maximum or minimum points

The given function is f(x) = e⁻ˣ².

a) The derivative of the function f(x) can be found using the chain rule. Let's calculate it:

f'(x) = d/dx(e⁻ˣ²)

f'(x) = -2x × e⁻ˣ²)

b) The second derivative of the function f(x) can be found by differentiating f'(x) with respect to x:

f''(x) = d/dx(-2x × e⁻ˣ²)

= -2 × e⁻ˣ² + (-2x) × (-2x) × e⁻ˣ²)

= -2 × e⁻ˣ² + 4x² × e⁻ˣ²)

= e⁻ˣ²(-2 + 4x²)

c) To find the critical points of the function f(x), we need to solve the equation f'(x) = 0

-2x × e⁻ˣ² = 0

Setting -2x = 0, we get x = 0.

d) To determine the intervals where the function is increasing or decreasing, we can analyze the sign of the first derivative. Recall that

f'(x) = -2x × e⁻ˣ².

When x < 0, e⁻ˣ² is positive, and -2x is negative. Therefore, f'(x) < 0 for x < 0, indicating that the function is decreasing in this interval.

When x > 0, e⁻ˣ² is positive, and -2x is positive. Therefore, f'(x) > 0 for x > 0, indicating that the function is increasing in this interval.

e) To find the inflection points of the function, we need to solve the equation f''(x) = 0

e⁻ˣ²(-2 + 4x²) = 0

Setting -2 + 4x² = 0, we get x² = 1/2, which leads to

x = ±√(1/2)

x = ±(1/√2)

x = ±(√2/2).

Therefore, the function f(x) = e⁻ˣ² has critical points at x = 0 and inflection points at x = √(1/2) and x = -√(1/2). function does not have any local maximum or minimum points

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Answer:

8/3 gram

Step-by-step explanation:

Since the hanger is said to be in balance, then the weight on the right balances the weight on the left ;

Right hand side = Left hand side

12 = 4 + x + x + x

12 = 4 + 3x

12 - 4 = 3x

8 = 3x

8/3 = 3x / 3

x = 8/3 gram

The solution to the initial value problem using the method of separation of variables is y = (x³/3) - (1/2)x + 4/3.

To solve the initial value problem y' = x² - 1/2 with the initial condition y(2) = 3, we can use the method of separation of variables. Here are the steps:

Step 1: Separate the variables

Write the given differential equation in the form:

dy/dx = x² - 1/2

Step 2: Integrate both sides

Integrate both sides of the equation with respect to x:

∫dy = ∫(x² - 1/2) dx

Integration yields:

y = (x³/3) - (1/2)x + C

Step 3: Apply the initial condition

To find the constant C, substitute the initial condition y(2) = 3 into the equation obtained in Step 2:

3 = (2³/3) - (1/2)(2) + C

Simplifying the equation:

3 = 8/3 - 1 + C

3 = 8/3 - 3/3 + C

3 = 5/3 + C

Therefore, C = 3 - 5/3 = 9/3 - 5/3 = 4/3.

Step 4: Write the final solution

Substitute the value of C back into the equation obtained in Step 2:

y = (x³/3) - (1/2)x + 4/3

So, the solution to the initial value problem y' = x² - 1/2, y(2) = 3 is y = (x³/3) - (1/2)x + 4/3.

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The code could be the number "181*2" since the sum of the digits in even positions (8+2) is equal to the sum of the digits in odd positions (1+1).(option A)

To determine if a number could be the code, we need to check if the sum of the digits in even positions is equal to the sum of the digits in odd positions.

Let's analyze the options:

A) 12*9*8: The sum of the digits in even positions is 1+9 = 10, while the sum of the digits in odd positions is 2+8 = 10. Therefore, this number could be the code.

B) 181*2: The sum of the digits in even positions is 8+2 = 10, and the sum of the digits in odd positions is 1+1 = 2. These sums are not equal, so this number cannot be the code.

Based on the given information, only option A (1298) satisfies the condition where the sums of the digits in even and odd positions are equal.

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The linear transformation T: R³ → R³ that projects u onto v has Rank(T) = 1 and the basis for the kernel of T is {a}.

To find the rank and nullity of the linear transformation T: R³→ R³, we need to determine the dimensions of the image space (range) and the kernel (null space) of T.

(a) Rank of T:

The rank of T is equal to the dimension of the image space. Since T projects u onto v, the image of T is the span of the vector v. Therefore, the rank of T is 1.

Rank(T) = 1

(b) Basis for the kernel of T:

The kernel of T consists of all vectors u in R³ that are mapped to the zero vector in R³. In other words, it consists of all vectors u perpendicular to the vector v.

To find a basis for the kernel, we need to solve the equation T(u) = 0. Since T projects u onto v, we can express this as u - proj_v(u) = 0.

For any vector u in R³, the projection of u onto v can be computed as:

proj_v(u) = (u · v) / (||v||²) * v

where u · v represents the dot product of u and v, and ||v|| is the norm (length) of v.

In this case, v = (a), so we can rewrite the projection formula as:

proj_v(u) = (u · (a)) / (||a||²) * (a)

Since T(u) = u - proj_v(u) = 0, we have:

u - (u · (a)) / (||a||²) * (a) = 0

This equation can be rearranged as:

u = (u · (a)) / (||a||²) * (a)

Now we can find a basis for the kernel by setting u to be a free variable and expressing it in terms of (a).

Let's denote the scalar (u · (a)) / (||a||²) as k:

u = k * a

Therefore, any vector in the kernel of T can be written as k * a, where k is a scalar.

A basis for the kernel of T is {a}.

So, the basis for the kernel of T is {a}.

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Answer:

2/3πx³

Step-by-step explanation:

Volume of a cone is expressed as;

V = 1/3πx²h ... 1

x is the radius

h is the height of the cone

If the height of a cone is twice the radius of its base, then;

h = 2x ... 2

Substitute equation 2 into 1

Recall that V =  1/3πx²h

V = 1/3πx²(2x)

V = 2/3πx³

Hence the expression that represents the volume of the cone is 2/3πx³ cubic units

Taking the given data into consideration we reach the conclusion that the IQ score ranging the bottom 15% from the top 85% is approximately 79.2, under the standard deviation 20.

Let us assume that adults have IQ scores that are normally expressed  with a mean of 100 and a standard deviation of 20, we need to calculate the IQ score ranging the bottom 15% from the top 85%, which is denoted as [tex]P_{15}[/tex]
To find the answer for this problem, we need to evaluate the z-score that corresponds to the 15th percentile. We can utilise a standard normal distribution table to  evaluate this value.
Implementing a standard normal distribution table, we could evaluate that the z-score corresponding to the 15th percentile is approximately -1.04.
[tex]z = (P_{15} - mean) /standard deviation[/tex]
[tex]-1.04 =( P_{15} - 100) /20[/tex]
[tex]- 20.8 = P_{15} - 100[/tex]
[tex]P_{15} = 79.2[/tex]
Hence, the IQ score separating the bottom 15% from the top 85% is approximately 79.2.
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The evidence and data support Evan's argument that plants predominantly acquire the materials they need to grow from air and water .

Evan's statement is supported by evidence and data that demonstrate how plants obtain the majority of the materials they need to grow from air and water. Here are some key points to support his argument:

Carbon Dioxide (CO2) from the air: Through the process of photosynthesis, plants take in carbon dioxide from the air. They use the carbon dioxide along with water and sunlight to produce glucose and oxygen. This glucose serves as an essential energy source for plant growth and development.

Water: Plants absorb water from the soil through their root systems. Water plays a critical role in various plant processes, including nutrient uptake, transportation, and the maintenance of cell turgidity. It is a primary component of plant cells and is necessary for photosynthesis to occur.

Essential nutrients from the soil: While air and water provide the primary materials for plant growth, plants also require certain nutrients to thrive. These essential nutrients, such as nitrogen, phosphorus, and potassium, are typically obtained from the soil. However, it's important to note that these nutrients are often dissolved in water and taken up by plant roots.

Experimentation and research: Numerous scientific experiments and studies have been conducted to investigate plant nutrient uptake. These experiments have confirmed that plants can grow and develop using only air, water, and the necessary nutrients found in these sources.

The evidence and data support Evan's argument that plants predominantly acquire the materials they need to grow from air and water. While nutrients from the soil are essential, the primary sources of plant growth materials are carbon dioxide from the air and water, which are crucial for photosynthesis and various physiological processes in plants.

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A graphical interpretation of the 2-point backward difference formula for approximating f'(x) is the slope of the line joining the points of abscissas xo - h and X, with h > 0 is False

The 2-point backward difference formula for approximating f'(x) is given by:

f'(x) ≈ (f(x) - f(x - h)) / h

In this formula, the slope is calculated using the values of f(x) and f(x - h) at two points: x and x - h. The graphical interpretation of this formula involves finding the slope of the line passing through these two points.

However, the given statement states that the line is joining the points of abscissas xo - h and X, with h > 0. This implies that the line is connecting a fixed point xo - h to a variable point X. This interpretation does not align with the 2-point backward difference formula.

Therefore, the statement is false.

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Answer:

11 maybe???

Step-by-step explanation:

After considering the given data we conclude that it is proven that [tex]limnan = a (and) a + 0[/tex], and there exists a positive number k and a positive integer m such that Jan> k, whenever n > m.

To prove that if [tex]limnan = a (and) a + 0[/tex], then there exists a positive number k and a positive integer m such that Jan> k, whenever n > m, we can apply the definition of a limit.
Definition of a limit: Let assume (an) be a sequence of real numbers. We interpret that the limit of (an) as n approaches infinity is a,
denoted limnan = a, if for every ε > 0, there exists a positive integer N such that [tex]\{|an - a| < \epsilon\} whenever}\{ n > N\}[/tex].
Then lets proceed with the proof
Consider that [tex]limnan = a (and) a + 0.[/tex]
Let [tex]\epsilon = a/2[/tex]. Since a + 0, we know that a > 0, so [tex]\epsilon[/tex] > 0.
Applying the definition of a limit, there exists a positive integer [tex]N_1[/tex] such that [tex]|an - a| < \epsilon (whenever) n > N_1.[/tex]
Then [tex]k = a/\epsilon = 2[/tex]. Since [tex]\epsilon = a/2, (we have) k = 2.[/tex]
Then  [tex]m = max\{N1, k\}[/tex] Hence, for n > m, we have:
[tex]n > N_1, (since) m \geq N_1[/tex].
[tex]n > k,( since) m \geq k.[/tex]
Therefore, we have:
[tex]|an - a| < \epsilon , (by the description) of N_1[/tex].
[tex]\epsilon = a/2 < a/k, (since) k = 2.[/tex]
[tex]|an - a| < a/k,[/tex] by applying substitution.
[tex]an - a < a/k[/tex], since |an - a| is positive.
[tex]an < a(1 + 1/k)[/tex], by adding a to both sides.
[tex]an < a(1 + 1/2) = 3a/2.[/tex]
Hence , we have shown that there exists a positive number k = 2 and a positive integer [tex]m = max\{N1, k\}[/tex] such that Jan> k, whenever n > m.
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Answer:

B and E

Step-by-step explanation:

The indicated IQ score, corresponding to the shaded area under the curve of 0.5675 in a normal distribution with a mean of 100 and a standard deviation of 15, is approximately 102.55.

To find the indicated IQ score, we need to determine the corresponding z-score using the given information about the normal distribution. Here's how we can calculate it step by step:

Step 1: Identify the shaded area under the curve.

The shaded area under the curve represents the cumulative probability of the IQ scores. In this case, the shaded area is 0.5675 or 56.75%.

Step 2: Convert the cumulative probability to a z-score.

To find the z-score corresponding to the shaded area, we need to find the z-score that gives us a cumulative probability of 56.75%. We can use a standard normal distribution table or a statistical calculator to find the z-score.

Step 3: Find the z-score.

Using a standard normal distribution table, we can search for the closest cumulative probability to 0.5675. The closest cumulative probability we can find in the table is 0.5681, which corresponds to a z-score of approximately 0.17.

Step 4: Convert the z-score to an IQ score.

Now that we have the z-score of 0.17, we can use the formula for transforming z-scores to raw scores:

IQ score = (z-score × standard deviation) + mean

Given that the mean is 100 and the standard deviation is 15, we can calculate the IQ score:

IQ score = (0.17 × 15) + 100

IQ score = 2.55 + 100

IQ score ≈ 102.55

Therefore, the indicated IQ score is approximately 102.55.

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Answer:

A) A function is a rule that assigns one input into one output.

The general function is f(x) = y

Where we have one input, x, and one output, y.

But this is a really simple type of function, for example, you could define a function that calculates the volume of a box of length L, width W, and height H as:

V = f(L, W, H) = L*W*H

Then we have "3 inputs" and one output, right?

Well, not exactly, here the set (L, W, H) is called the input, so here we have a single input consisting of 3 variables.

Also we can have functions with a single input into vector-like outputs

For example:

(y, z) = f(x)

So for the input x, we got two values in the output y and z, but this is a single output defined as (y, z), then we always have a single output.

B) The graph of a function is a set of points consisting of one input and the corresponding output.

C) You can determine if a graph represents a function by using the vertical line proof.

A rule that assigns inputs into outputs is only a function if each input is assigned into only one output.

Then if we draw a vertical line that intersects our graph, it should intersect it only one time for functions.

If the line intersects the line two times this means that a single input has more than one output, then this is not a function.

Answer:

A: exactly one, each

B: ordered pairs

C: vertical line test

Step-by-step explanation:

Answer:

27

Step-by-step explanation:

You do 3159 ÷ 27

Comes out to 27

I found 27 by just plugging in numbers.

Hope this helps

Answer:

There are 27 students in the class.

Step-by-step explanation:

Since the total weight is 3,159 and the average weight is 117lb, you can just divide 3,159 by 117, which will give you 27.

Answer:

402 in^3

Step-by-step explanation:

We know that the volume of a sphere = 4 /3 πr^3

Variables:

r = 2in

Solve for 1 toy:

4 /3 πr^3

4/3 π (2in)^3

= 33.51 cubic inches for 1 toy

For 12 toys:

33.51 in^3 * 12 toys = 402.12 in^3 of water for all the toys

Round:

402.12 in^3 ≈ 402 in^3 of water

Please mark brainliest if this helped!

Please mark brainliest if this helped!

Answer:

Fraction: 17/20

Percent: 85%

Ratio: 85 out of 100

Step-by-step explanation:

Step-by-step explanation:

Fraction = 85/100 = 17 / 20

Percent = 17 / 20 × 100 = 85%

Ratio = 17 : 20

The y-coordinate of the position vector at time t=3 is approximately 1.446.

For the y-coordinate of the position vector at time t=3, we first need to integrate the given velocity components with respect to time to obtain the position components:

x(t) = ∫(dx/dt) dt = ∫sin(t²) dt

= (1/2)∫sin(u)/√(u) du

(where u = t²)

y(t) = ∫(dy/dt) dt

= ∫[tex]e^{cos t}[/tex] dt = [tex]e^{cos t}[/tex] + C

We can then use the given initial condition at time t=4 to determine the constant value C for the y-component:

x(4) = 2, y(4) = 1

Plugging in t=4 to the position equations, we get:

x(4) = (1/2)∫sin(u)/√(u) du = 2

y(4) = [tex]e^{cos 4}[/tex] + C = 1

Solving for C, we get:

C = 1 -  [tex]e^{cos 4}[/tex]

Now we can plug in t=3 to find the y-coordinate of the position vector:

y(3) =  [tex]e^{cos 3}[/tex] + C

y(3) =  [tex]e^{cos 3}[/tex] + 1 -  [tex]e^{cos 4}[/tex]

y(3) ≈ 1.446 (rounded to three decimal places)

Therefore, the y-coordinate of the position vector at time t=3 is , 1.446.

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Answer: 5.4

Step-by-step explanation:

Pretty Simple 5 squared plus 2 squared is 29.Just find the square root of that and it is the third side.:)

Answer:

5^2 + 2^2 = 29

sqr root of 29 is 5.385

Step-by-step explanation: