dy/dx=(x+y+1)2 {Linear Substitution}

The correct answer is option d) 9x² + 12xy + 4y². To simplify the expression (3x + 2y)² using the square of a binomial formula, we need to apply the formula (a + b)² = a² + 2ab + b². In this case, a = 3x and b = 2y.

Using the formula, we have:

(3x + 2y)² = (3x)² + 2(3x)(2y) + (2y)²

= 9x² + 12xy + 4y²

So the simplified form of (3x + 2y)² is 9x² + 12xy + 4y².

Now let's analyze the given options:

a) 9x² + 4y²: This option is incorrect because it is missing the term 12xy.

b) 9x² + 5xy + 4y²: This option is also incorrect because it contains an additional term, 5xy, which is not present in the simplified expression.

c) 9x² + 6xy + 4y²: This option is incorrect because it also contains an additional term, 6xy, which is not present in the simplified expression.

d) 9x² + 12xy + 4y²: This option is correct because it matches the simplified form we obtained using the square of a binomial formula.

Therefore, the correct answer is option d) 9x² + 12xy + 4y².

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Answer:

A rectangle

Step-by-step explanation:

A square can be a rectangle but a rectangle can't always be a square.

Answer:

69 minutes? i don't know haha

Step-by-step explanation:

Answer:

6a

Step-by-step explanation:

Answer:

6a

Step-by-step explanation:

3a+2a+a= 6a

6-4-2=0

6a+0=6a

Answer:

Q' = (1, -5)

R' = (3, 1)

S' = (0, 0)

T' = (-2, -3)

Step-by-step explanation:

Look at the numbers of the current vertices and then change the signs of the y-coordinates around. For example, the original Q-coordinate was (1,5) so I changed the 5 to a -5 to reflect across the axis. Changing the y-coordinate sign reflects across the x-axis, while changing the x-coordinate sign reflects across the y-axis.

Answer:

7 cm

Step-by-step explanation:

10 mm = 1cm

All you need to do is add 10mm + 6cm.

10mm = 1cm

So, 6cm + 1cm.

Therefore, it equals to 7cm.

Answer:

471.2 cm cubed

Step-by-step explanation:

The formula for the volume of a cylinder is:

π*radius squared*height

The diameter is the distance across the circle.

10 mm is the same as 1 cm

The radius is half of the diameter.

1/2=.5

Radius=.5 cm

Height=6 cm

Plug the numbers in.

.5 squared is .25

π*(.25)(6 cm)

Volume=4.71

Rounded to the nearest tenth:

Volume=4.7 cm cubed

Answer:

no picture

Step-by-step explanation:

Answer:

The answer and work are in the pdf

Step-by-step explanation:

Answer: A. The majority of the math scores are greater than the median of the science scores

Step-by-step explanation:

I took the test!

Answer:

5

Step-by-step explanation:

3x-7=8

x=5

Answer:

144

Step-by-step explanation:

24 books at 6 points each would be 24 x 6 which equals 144

Answer:

They'll have 144 points if they read 24 books.

Step-by-step explanation:

6 x 24 = 144

The symbolic argument ~p -> q is valid.

To determine the validity of the argument ~p -> q using a truth table, we need to consider all possible combinations of truth values for p and q and evaluate the truth value of the implication ~p -> q.

The symbolic form of the argument is ~p -> q, which can also be written as ¬p → q.

A truth table for this argument would have columns for p, ~p, q, and ~p -> q.

Let's construct the truth table:

|   p      |  ~p    |   q      |  ~p -> q |

| True  | False | True  |   True    |

| True  | False | False |   False   |

| False | True  | True  |   True    |

| False | True  | False |   True    |

In the truth table, we consider all possible combinations of true (T) and false (F) for p and q. For ~p, we negate the value of p.

For the implication ~p -> q, it is true (T) if either ~p is false (F) or q is true (T). In all other cases, it is false (F).

Looking at the truth table, we can see that in all rows where ~p -> q is true (T), the corresponding conclusion q is true (T). Therefore, the argument ~p -> q is valid because whenever ~p is true (F), the conclusion q is also true (T).

In summary, the symbolic argument ~p -> q is valid.

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Answer:

the answer is the cheese soup has a good change of being picked but not as good as the chicken soup there would so 3:2 to 2. so if they picked the cheese soup the first time then there is not a good change of the cheese souo to be picked again i hope that helps if not let me know

Answer:

(-2,2)

Step-by-step explanation:

Hi,

4x + 5y = 2

-2x + 2y = 8

To solve using elimination, we can multiply the second equation by 2 to try and get rid of the x. So...

4x + 5y = 2

-4x + 4y = 16

Now, add...

9y = 18

Divide by 9...

y = 2

Now, let's solve for x...

4x + 5(2) = 2

4x + 10 = 2

4x = -8

x = -2

Your solution is, (-2,2)

I hope this helps :)

Main Answer: The numerical value of y(2.0) rounded off to three figures is 1.279.

Supporting Explanation:

The student solved the initial-value problem and found that y(2.0) = 1.27977. The question asks to round off the value to three figures. Therefore, we have to keep only the first three digits after the decimal point, which are 279. The next digit after 9 is 7, which means we have to round up the last digit. Thus, the rounded off value of y(2.0) is 1.279.

The initial-value problem is a differential equation that has an initial condition given for a specific value of the independent variable. In this case, the initial condition is y(1) = 2. The solution of the initial-value problem gives the value of y for other values of x. Here, we are required to find the value of y for x = 2.0.

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Answer:

2.True

3. HGK

4. 17°

hope it helps

Answer:

Step-by-step explanation:

1 pound = 16 ounces

35 pounds = 560 ounces + 24 ounce = 584ounces

35 pounds,24ounces = 16 ounces

the number of choices in each case is:

a. With no restriction: 10,000 choices.

b. No digit is repeated: 5,040 choices.

c. No digit is repeated, 2 and 5 must be present: 56 choices.

Let's calculate the number of choices in each case:

a. With no restriction:

For each digit in a 4-digit pin code, we have 10 choices (0-9). Since there are 4 digits in total, the number of choices is 10⁴ = 10,000.

b. No digit is repeated:

For the first digit, we have 10 choices (0-9).

For the second digit, we have 9 choices (any digit except the one chosen for the first digit).

For the third digit, we have 8 choices (any digit except the two chosen for the first and second digits).

For the fourth digit, we have 7 choices (any digit except the three chosen for the first, second, and third digits).

The total number of choices is 10 * 9 * 8 * 7 = 5,040.

c. No digit is repeated, and 2 and 5 must be present:

We have two fixed digits (2 and 5) that must be present in the pin code.

For the first fixed digit (2), we have only 1 choice.

For the second fixed digit (5), we have only 1 choice.

For the remaining two digits, we have 8 choices each (any digit except 2 and 5).

The total number of choices is 1 * 1 * 8 * 7 = 56

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Answer:

D

Step-by-step explanation:

10 and -6                                  

.....................................................

The probability distribution of X is as follows:P(X = x) = 0 for x < 1P(X = x) = 0 for 1 ≤ x < 10.5P(X = x) = 1 for 10.5 ≤ x < 31P(X = x) = 0 for x ≥ 31.

Given function: f(x)={0x<10.51≤x<313≤xTo verify that the given function is a cumulative distribution function, we have to check the following conditions:1. f(x) is non-negative for all x.2. f(x) is continuous from the right for all x.3. f(x) is a non-decreasing function for all x.4. lim{x → -∞} f(x) = 0 and lim{x → ∞} f(x) = 1. Now, let's verify these conditions one by one.1. f(x) is non-negative for all x. This condition is satisfied, as the given function f(x) is defined only for x ≥ 1, and is non-negative for all x in this domain. Therefore, f(x) is non-negative for all x.2. f(x) is continuous from the right for all x. This condition is also satisfied, as the given function f(x) is defined piecewise as a continuous function for all x. Therefore, f(x) is continuous from the right for all x.3. f(x) is a non-decreasing function for all x. This condition is satisfied, as the given function f(x) is non-decreasing for all x in its domain.4. lim{x → -∞} f(x) = 0 and lim{x → ∞} f(x) = 1.

Using the definition of f(x) for x < 10, we have f(x) = 0 for x < 10. Therefore, lim{x → -∞} f(x) = 0. Using the definition of f(x) for x ≥ 31, we have f(x) = 1 for x ≥ 31. Therefore, lim{x → ∞} f(x) = 1. Hence, all four conditions are satisfied. Therefore, the given function is a cumulative distribution function. To find the probabilities of the intervals, we use the formula: P(a ≤ X ≤ b) = F(b) - F(a)where P(a ≤ X ≤ b) is the probability that X lies between a and b, and F(x) is the cumulative distribution function of X. Furthermore, the probability of the interval (a, b] is: P(a < X ≤ b) = F(b) - F(a)Therefore, the probabilities of the intervals are: P(1 < X ≤ 10.5) = F(10.5) - F(1) = 0 - 0 = 0P(10.5 < X ≤ 31) = F(31) - F(10.5) = 1 - 0 = 1P(X > 31) = F(∞) - F(31) = 1 - 1 = 0Therefore, we have: P(1 < X ≤ 10.5) = 0P(10.5 < X ≤ 31) = 1P(X > 31) = 0

Hence, the probability distribution of X is as follows: P(X = x) = 0 for x < 1P(X = x) = 0 for 1 ≤ x < 10.5P(X = x) = 1 for 10.5 ≤ x < 31P(X = x) = 0 for x ≥ 31. Therefore, the given function is a cumulative distribution function, and the probability distribution of X is as above.

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Answer:

8/10 or 4/5 as a fraction. the percentage is 80%

Step-by-step explanation:

For  the quadratic function f(x) = x^2 - 5x + 6, the values of the coefficients and constant are:

a = 1
b = -5
c = 6.

To identify the coefficients and constant in the quadratic function f(x) = x^2 - 5x + 6, let's examine the standard form of a quadratic equation:

f(x) = ax^2 + bx + c

Comparing this with the given quadratic function, we can determine the values of the coefficients and constant:

a = 1 (coefficient of x^2 term)
b = -5 (coefficient of x term)
c = 6 (constant term)

Therefore, for the quadratic function f(x) = x^2 - 5x + 6, the values of the coefficients and constant are:

a = 1
b = -5
c = 6.

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Answer:

B

Step-by-step explanation:

Its dominant because its brown hair.

The square root of -i that graphs in the second quadrant,

⇒ z = (1/2)((√(2))(cos(135°) + i sin(135°))

To find the square root of -i,

we can start by writing -i in polar form.

⇒ i = 1(cos(270°) + i sin(270°))

Now, we can find the square root by taking the square root of the magnitude and dividing the angle by 2.

⇒ √(-i) = √(1)  [cos(270°/2) + i sin(270°/2)]

⇒ [tex](1)^{(1/2)}[/tex]  [cos(135°) + i sin(135°)]

⇒ (1/2)(√(2)) [cos(135°) + i sin(135°)]

⇒ (1/2)(√(2)) (-√(2)/2 + i(√(2))/2)

⇒ -1/2 + ((√t(2)/2)i

Therefore,

The square root of -i that graphs in the second quadrant in the form of

z = r(cosθ + i sinθ)

Hence,

z = (1/2)((√(2))(cos(135°) + i sin(135°)).

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The solution of the differential equation is 1 = c₁v₁ + c₂v₂ and 5 = c₁v₁ + c₂v₂

We are given a system of two differential equations:

x₁' = – 5x₁ + 0x₂

x₂' = – 16x₁ + 3x₂

To solve this system, we can use several methods, such as substitution or matrix methods. In this explanation, we will use the substitution method.

We can write the given system of differential equations in matrix form as follows:

X' = AX

where X is the column vector [x₁, x₂], X' is the derivative of X, and A is the coefficient matrix:

A = [–5 0]

[–16 3]

To find the eigenvalues λ and eigenvectors v, we solve the characteristic equation:

|A - λI| = 0

where I is the identity matrix. Solving this equation will give us the eigenvalues and eigenvectors.

A - λI = [–5-λ 0]

[–16 3-λ]

Setting the determinant of A - λI to zero, we get:

(–5-λ)(3-λ) - (0)(–16) = 0

Simplifying, we have:

(λ + 5)(λ - 3) = 0

Solving this equation, we find two eigenvalues:

λ₁ = -5

λ₂ = 3

For each eigenvalue, we need to find its corresponding eigenvector. For λ₁ = -5, we solve the system of equations:

(A - (-5)I)v₁ = 0

Substituting the values of A and λ₁, we have:

[0 0] v₁ = 0

[–16 8]

Simplifying the equation, we get:

0v₁ + 0v₂ = 0

-16v₁ + 8v₂ = 0

From the first equation, we can see that v₁ can take any value. Let's choose v₁ = 1 for simplicity. Substituting this value into the second equation, we get:

-16(1) + 8v₂ = 0

-16 + 8v₂ = 0

8v₂ = 16

v₂ = 2

So, for λ₁ = -5, the corresponding eigenvector is v₁ = [1, 2].

Similarly, for λ₂ = 3, we solve the system of equations:

(A - 3I)v₂ = 0

Substituting the values of A and λ₂, we have:

[-8 0] v₂ = 0

[–16 0]

Simplifying the equation, we get:

-8v₁ + 0v₂ = 0

-16v₁ + 0v₂ = 0

From the first equation, we can see that v₁ can take any value. Let's choose v₁ = 1 for simplicity. Substituting this value into the second equation, we get:

-16(1) + 0v₂ = 0

-16 = 0

This equation has no solution. However, this means that v₂ can take any value. Let's choose v₂ = 1 for simplicity.

So, for λ₂ = 3, the corresponding eigenvector is v₂ = [1, 1].

The general solution of the system of differential equations can be expressed as:

X(t) = c₁e(λ₁t)v₁ + c₂e(λ₂t)v₂

where c₁ and c₂ are constants that need to be determined.

We are given the initial conditions x₁(0) = 1 and x₂(0) = 5. Substituting these values into the general solution, we get two equations:

x₁(0) = c₁e(λ₁(0))v₁ + c₂e(λ₂(0))v₂

x₂(0) = c₁e(λ₁(0))v₁ + c₂e(λ₂(0))v₂

Simplifying, we have:

1 = c₁v₁ + c₂v₂

5 = c₁v₁ + c₂v₂

Solving this system of equations, we can find the values of c₁ and c₂.

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The mass of the wire is given by the integral [tex]\int[0, R] k\sqrt{(1 + (-x/\sqrt{(9 - x^2}))^2}[/tex] dx, and the centre of mass is given by [tex]\int[0, R] x(k\sqrt{1 + (-x/\sqrt{9 - x^2})^2}[/tex] dx divided by the mass.

Find the mass and centre of mass of the wire?

To find the mass and center of mass of the wire, we need to integrate the linear density function along the curve of the wire.

The linear density function is given as a constant k, which means the mass per unit length is constant.

To find the mass of the wire, we integrate the linear density function over the length of the wire. The length of the semicircle can be found using the arc length formula:

[tex]s = \int[0, R] \sqrt{(1 + (dy/dx)^2} dx[/tex]

In this case, the equation of the semicircle is x² + y² = 9, so y = √(9 - x²). Taking the derivative with respect to x, we have dy/dx = -x/√(9 - x²).

Substituting this into the arc length formula, we have:

s = ∫[0, R] √(1 + (-x/√(9 - x²))²) dx

To find the centre of mass, we need to find the weighted average of the x-coordinate of the wire. The weight function is the linear density function, which is a constant k.

Therefore, the mass of the wire is given by the integral [tex]\int[0, R] k\sqrt{(1 + (-x/\sqrt{(9 - x^2}))^2}[/tex] dx, and the center of mass is given by [tex]\int[0, R] x(k\sqrt{1 + (-x/\sqrt{9 - x^2})^2}[/tex] dx divided by the mass.

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Answer:

√89

Step-by-step explanation:

√(x2 - x1)² + (y2 - y1)²

√(9 - 1)² + [-6 - (-1)]²

√(8)² + (-5)²

√64 + 25

√89