Draw and give the IUPAC names for the following organic molecules:

• Ascorbic Acid (Vitamin C)
• Fructose
• Glucose

You can use the molecular mass of Co with its percentage composition to discover the molar mass of cyanocobalamin is 59.903g.

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3.12 moles NaOH  are contained in 15.2l of a 0.205m NaOH solution

15.2 x 0.205 = 3.116 moles. By rearranging the equation, you must first determine how many moles are there in this solution. False. Molarity (M) x Volume (L) equals 15.2 x.205, or 3.12 moles.

Molarity (M), which is determined by dividing the solute's mass in moles by the volume of the NaOH  solution in liters, is the most often used unit to represent NaOH solution concentration: liters of solution/moles of solute equals M. One liter of a NaOH  solution with a 1.00 molar concentration (1.00 M) contains 1.00 moles of solute.

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The information in which molecular formula helps to provide is the number and kind of electrons present in a molecule.

The correct answer choice is option d.

A molecular formula is a formula which which helps to give information about the characteristic feature of an molecules as to the number and kind of electrons present in it.

A molecule is a substance which can normally exist alone and still retain the chemical properties of that substance.

In conclusion, we can now confirm from the explanation given above that molecular formula helps to to understand the constituent of a molecular substance.

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HOOCCH2CH2COOH + H2NCH2CH2NH2 ----> Polymer + H2O is the chemical equation for formation of a polymer via a condensation reaction from the monomers succinic acid (hoocch2ch2cooh) and ethylenediamine (h2nch2ch2nh2).

A condensation reaction is a chemical reaction in which two smaller molecules combine to form a larger molecule, releasing a small molecule such as water or methanol as a byproduct. Condensation reactions are often used to synthesize polymer, which are large molecules made up of repeating units called monomers.

To write a chemical equation for the formation of a polymer via a condensation reaction from the monomers succinic acid and ethylenediamine, we can start by representing the monomers as follows:

Succinic acid: HOOCCH2CH2COOH

Ethylenediamine: H2NCH2CH2NH2

In a condensation reaction, the monomers combine through a dehydration synthesis reaction, in which a molecule of water is released as a byproduct. The resulting polymer consists of repeating units of the monomers linked by a covalent bond.

The general chemical equation for a condensation reaction between two monomers can be written as follows:

Monomer 1 + Monomer 2 --> Polymer + byproduct

In this case, the polymer produced by the condensation reaction between succinic acid and ethylenediamine would be a polyamine with repeating units of the monomers linked by a covalent bond. The chemical equation for the formation of this polymer via a condensation reaction would be:

HOOCCH2CH2COOH + H2NCH2CH2NH2 -> Polymer + H2O

It is important to note that the actual structure of the polymer produced in this reaction will depend on the specific conditions of the reaction and the specific monomers involved. The chemical equation provided is a general representation of a condensation reaction between these monomers and does not represent the exact structure of the polymer that would be produced.

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The sucrose is actively transferred to the partner cells, and it diffuses from the companion cells to the sieve tube elements through the plasmodesmata.

As a result, the sucrose concentration in the sieve tube components rises. The same leaf vein receives water through osmosis from the neighboring xylem. The hydrostatic pressure on the sieve tube components rises as a result. Sucrose and other substances are forced through the sieve tube cells by hydrostatic pressure. Water is forced out of the sieve tube cells by osmosis, which reduces the hydrostatic pressure inside the cells. As a result of the entrance of sugars in sieve elements at the source and the elimination of sucrose, the pressure gradient is thus established.

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His E7 isn't a ligand for the porphyrin ring (Fe(II)) ion in oxymyoglobin.

In the porphyrin ring, four pyrrole nitrogens are bound to the a ferrous (Fe(II)) ion centre. The Fe(II) ion does have six coordination sites, four of which are inhabited by pyrrole nitrogen, one by proximal histidine, and the final site can form a reversible bond with an O2 molecule.

A porphyrin is a large ring molecule composed of four pyrroles, which are smaller rings with four carbons and one nitrogen. A series of single and double bonds connect these pyrrole molecules, causing the formation of a large ring. The technical term for four pyrroles linked together is tetrapyrrole. The ring is flat in space and has a fairly even electron distribution around in its circumference.

A porphyrin is thus categorized as an aromatic compound. This demonstrates how stable a porphyrin molecule is. Porphin is the general porphyrin model. This molecule appears as just an intermediate in nature only on rare occasions, but it serves as the foundation for all porphyrin molecules.

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I put the burning metal into a crucible and then collected the product.

The system gains heat and has work done on it by the surrounding, this condition would always result in an increase in the internal energy of a system. thus the option D is correct.

When a system is heated or has work done on it by its environment, the internal energy of the system is constantly raised. Energy is an immaterial substance that is concerned with performing work on an item. One of the fundamental conservation rules that holds true throughout the cosmos is the conservation of energy. A type of energy is internal energy. The total kinetic energy of each gas molecule can be considered to be the internal energy U of our system. In other words, when the gas's temperature T rises, its molecules move more quickly and its internal energy U rises.

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The number of protons in each isotopes is the same. Because both isotopes have the same amount of orbital electrons, the claims made about them are accurate.

An element is a basic thing that is difficult to divide into smaller parts. A material that cannot be broken down by non-nuclear processes is referred to as an element in chemistry and physics. An element is a unique component of a bigger system or set in computers and mathematics.

Any material that cannot be broken down into simpler compounds by regular chemical processes is a chemical element, often known as an element.

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BH3,CH4,PCl5,and H2 have zero dipole moment whereas the H2O and HF have permanent dipole moment.

what is dipole moment?

The bond dipole moment is the moments but property of the chemical bond that is used to measure the polarity of the bond within a molecule.

BH3 a non-polar molecule owing to its symmetric structure.

CH4 forms a regular tetrahedral structure and has very small electronegativity difference between the atoms that cancels out each other due to their directional vectors. Thus CH4 is non polar.

PCl5 is made up of polar P−Cl bonds that form a trigonal bipyramidal molecular which is arranged symmetrically thus the PCl5 molecule is nonpolar.

H2O is a polar compound with a bent shape, which is the reason for the polarity of the compound.

HF is a polar molecule owing to higher electronegativity difference and no other bonds to cancel the polarity thus formed.

H2 is a diatomic molecule and hence it is non-polar.

Thus, the atoms that possess dipole moments are H2O,HF .

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With this method, a sample is burned in a bomb calorimeter at a constant volume. Equation q = -CT, where C is the calorimeter's heat capacity and T is the temperature change, can be used to determine how much heat is released during the reaction.

If 1.000 g of benzoic acid burns in a bomb calorimeter to produce 26.38 kJ of heat, 0.550 g of benzoic acid will produce the following amount of heat:Conventionally, heat release is denoted by a negative sign.The sum of the heat emitted by combustion (Qc) and the heat absorbed by the bomb calorimeter (Qb) equals zero, according to the Law of Conservation of Energy.

The temperature of the bomb calorimeter rose from 22.01 °C to 24.27 °C after absorbing 14.5 kJ. Using the following expression, we can determine the calorimeter's (C) heat capacity.

In a bomb calorimeter, the combustion of 0.550 g of benzoic acid raises the temperature from 22.01 °C to 24.27 °C.

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The chemical element KMnO4 is the same as potassium permanganate. Manganese is in the +7 oxidation state in this salt. The salt is also referred to as "potash permanganate." The ion of permanganate is a potent oxidizer.

Another popular technique for treating water to remove sulfur is manganese greensand. It is often advised for water with less hydrogen sulfide than 6.0 mg/l. A unique coating on a manganese greensand filter causes hydrogen sulfide gas to oxidize into solid sulfur particles, which are then filtered. Potassium permanganate is used to rejuvenate the greensand after all of the manganese oxide has been used up. Potassium permanganate is a purple oxidizing chemical that is added to the untreated water to maintain the manganese greensand filter.

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Answer:

The nucleus is surrounded by a double unit membrane from all sites. The chromosomes and genes which have genetical characters and transmit from one generation to another are found in the nucleus.

Explanation:

We would dilute 10mL of this concentrated solution to make 500ml of a 1x TAE buffer solution.

Dilution is one of the easiest ways to make buffers. This is only applicable, though, if the working solution, which is the desired solution, has the same pH as the stock solution, which is the readily available, more concentrated solution. The dilution equation is employed in the preparation of buffer by dilution:

[tex]C_{1} V_{1} = C_{2} V_{2}[/tex]

where V refers to volume and C represents concentration. The subscripts 1 and 2 often denote the working solution and stock, respectively. Notably, both sides of the equation must always use the same units for concentration and volume.

From a stock of 50X TAE buffer, make 500mL of 1.0X TAE buffer as follows:

[tex]C_{1} V_{1} = C_{2} V_{2}[/tex]

(50X)V1=(1.0X)(500mL)

∴V1=10mL of 50X TAE Buffer

Calculating the volume of the water-based solvent is also necessary to finish the preparation. The remaining amount of water is needed to make the appropriate amount of working solution, which is 500mL.

[tex]V_{water}[/tex]=500mL−10mL=490mL

As a result, 490mL of water is used to dilute 10mL of 50X TAE Buffer.

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The process that is represented by this redox equation

6 H₂O + 6 CO₂ --->  C₆H₁₂O₆ + 6 O₂ is  photosynthesis.

The correct option is C.

A redox reaction is a reaction in which oxidation and reduction occur simultaneously at the same time and to the same extent.

In a redox reaction, electrons are transferred from one species to another.

The species that transferred electrons becomes oxidized whereas the species that accepts electrons becomes reduced.

Hence, a reduction reaction is a reaction in which a chemical species accepts electrons while an oxidation reaction is a reaction in which a chemical species donates electrons.

Considering the given reaction:

6 H₂O + 6 CO₂ --->  C₆H₁₂O₆ + 6 O₂

In the given reaction, carbon is reduced while oxygen is oxidized.

The reaction shows the process of photosynthesis where carbon dioxide is reduced to produce glucose.

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122 L of oxygen is produced at STP when water is decomposed to the reactants. here decomposition reaction occurs.

Decomposition Reaction is the process or effect of simplifying a single chemical entity into two or more fragments. Chemical decomposition is usually regarded and defined as the exact opposite of chemical synthesis. Decomposition reaction of water can be written as,

        2H2O  → 2H2 + O2

Oxygen is produced at STP when 6.58 x 1024 molecules of water is decomposed. So there will be,

      0.5 × 6.58 × 1024

     = 3.29 × 1024  O2 molecules.

1mole = 6.02×1023 particles, so the amount produced is:

     = 3.29×1024 / 6.02×1023

     = 5.47mole

At an STP of 273K, 1atm the volume is 22.4L/mole

So the volume of oxygen is 5.47 × 22.4 = 122L

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Answer:

71.9 L

Explanation:

PV = nRT

STP means 273K and 1.00 atm

(1.00 atm)(V) = (3.21 mol)(0.08206 L*atm/mol*K)(273K)

V = 71.9 L

The pOH of the resulting solution is 1.38 as the resulting solution is basic in nature.

M HCl= 0.250 M

M NaOH= 0.250 M

V HCl=25.0 ml

V NaOH=35.0 ml

In order to calculate the pOH of the solution,

M mix= 0.250x25*0.250x35/25+35

M mix=6.25-8.75/60

=2.5/60

=0.0416 M

The solution will be more basic as the milliequivalent of the base is more., thus calculate pOH.

pOH or potential of hydroxide ion is a scale used to determine the hydroxide ion (OH–) concentration in a solution.

[OH-]=Mxnx∝

[OH-]=0.04167x1x1

[OH-]=0.04167 M

pOH=-log[OH-]

pOH=-log 4.167x10^-2

pOH=2-log 4.167

pOH=2-0.62

pOH=1.38

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Suppose that 0.08 m^3 of a gas has a gauge pressure of 2 atm and a temperature of 300 k. Approx 27 x 10^20 molecules are there in the gas.

To find the number of molecules in the gas, we can use the ideal gas law equation:

PV = nRT

where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature.

In this case, we know that the pressure is 2 atm, the volume is 0.08 m3, the temperature is 300 K, and the ideal gas constant is 8.31 J/mol*K. We can solve for the number of moles by rearranging the equation and substituting the known values:

n = (PV) / (RT)

= (2 atm * 0.08 m3) / (8.31 J/mol*K * 300 K)

= 0.0046 mol

Since there are Avogadro's number (6.022 x 10^23) of molecules in one mole of a substance, the number of molecules in the gas is:

Number of molecules = number of moles * Avogadro's number

= 0.0046 mol * 6.022 x 10^23 molecules/mol

= 27 x 10^20 molecules

Therefore, there are approximately 27 x 10^20 molecules in the gas.

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The mass of a neutron in atomic mass units is 1.008665 amu

Because neutrons are atomic particles, neutrons are a component of atoms. The English physicist James Chadwick discovered neutrons for the first time in 1932. He found the presence of a particle with no electric charge while conducting radioactivity studies, and he named it the neutron which typically has zero charge.

The atomic mass unit or AMU is a unit of mass used to express the masses of atoms and molecules. The mass of a neutron is almost the same as the mass of a proton whereas the electron is much less massive. In terms of AMU, the mass of a neutron in atomic mass units is 1.008665 amu

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There would be more of the bicarbonate ion present in the solution at low pH.

We know that the pH has to do with the degree of the acidity of the alkalinity of a given solution. We know that carbonic acid can be able to dissociate in solution via a reversible reaction.

In this case, when the pH is low, we know that there would now be more of the bicarbonate ion as the acid would  begin to dissociate so as to counter the constraint of the pH that has been imposed on the system.

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Octahedral type of molecular geometries are possible for the complex ion [Co(en)(H2O)4]2+.

In chemistry, an octahedral molecular geometry (also called a square bipyramid) is a compound with six atoms or groups of atoms or ligands arranged symmetrically around a central atom and defining the vertices of the octahedron represents the shape of The octahedron has eight faces, so the prefix is ​​okta. The octahedral shape is characterized by Octahedral bond angle values of 90° and 180° define the octahedral shape. The angles between the four atoms forming the square bases of the two pyramids of the octahedral structure are 90°, as is the angle between each of these atoms and one of the apex atoms.

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Complete question :

Which of the following geometries for the complex ion [Co(en)(H2O)4]2+ are possible?

Check all that apply

trigonal bipyramidal or square pyramidal

octahedral

linear

tetrahedral or square planar

trigonal planar

Answer:

twice

Explanation:

Answer: 2.)black

3.)red

4.)yellow

5.) I don't know I am very sorry

6.) I don't know I am very sorry

7.) light blue

8.) purple

9.) dark green

10.)purple

The amount of nickel(ii) iodide that should be added for making the solution is 71.3 kilograms.

As the molality and weight of water is given, we will use the formula of molality to find the mass of nickel(ii) iodide.

Molality = number of moles of nickel(ii) iodide/weight of solvent in kilograms

Number of moles = mass/molar mass

Molar mass = 312.5 grams

Keep the values -

0.643 = moles/355

Moles = 228.3

Mass = 228.3 × 312.5

Performing multiplication on Right Hand Side of the equation

Mass = 71,332.8 grams

Mass = 71.3 kilograms

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H3O+ is present in aqueous solutions with a concentration of 8.8 1012 M at 25 °C. Determine the amount of OH present. Please include significant digits in your response. OH ([OH]) concentration: Take water's ability to ionize itself as an example. 2 H2O(aq), H3O+(aq), and OH (aq)

Kw = [H3O+] [OH] = 1.0 1014 [OH] = 1.0 1014 / [H3O+][OH] = 1.0 1014 / 8.8 1012 [OH] = 1.1 103 M is the equilibrium constant for this reaction.

In pure water, there are 10-6mol dm-3 H3O + ions present.

The hydronium ion concentration in moles per liter must be known in order to compute the pH of an aqueous solution (molarity). After that, the pH is determined using the formula pH = - log [H3O+].

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The 0.118 moles are the mass Iron(III) oxide reacts with carbon monoxide gas to form solid iron metal and carbon dioxide gas: Fe2O3+3CO→2Fe+3CO2.

Limiting and Excess Reactants:There are sorts of reactants which can be utilized in a chemical response process, those are the proscribing reactant and the extra reactant. There is continually a leftover quantity of the extra reactant after a response. The most quantity of merchandise that may be produced relies upon at the proscribing reactant.

First, we convert the loads of the reactants into moles the usage of their molecular weight:

Solving for moles of Fe2O3, nFe2O3,

nFe2O3=mFe2O3MWFe2O3=23.0g159.69gmolnFe2O3=zero.144molesSolving for moles of CO, nCO,nCO=mCOMWCO=15.4g28gmolnCO=zero.55molesIn figuring out the proscribing and extra reactants, we decide the moles required for every reactant if we used all of the given moles adjusted consistent with their mole ratio withinside the balanced response.

The moles ecess reactant =nCO−nCOx=zero.fifty five−zero.432=0.118 molThe mass of the extra reactant left is calculated the usage of its moles and molecular weight,

massexcessreactantleft=mCO×M.

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The student then mixes in 20ml of NaOH into the solution. The resulting mixture has a ph of 1.8. 0.135 M was the concentration of the NaOH solution that was added to the HCl.

To determine the concentration of the sodium hydroxide (NaOH) solution that was added to the hydrochloric acid (HCl) solution, we need to know the volume of the NaOH solution and the resulting pH of the mixture. The pH of a solution is a measure of its acidity or basicity. It is defined as the negative logarithm of the concentration of hydrogen ions (H+) in the solution. The concentration of H+ ions is directly related to the concentration of the acid (for an acidic solution) or the concentration of the base (for a basic solution).

In this case, we are given that the resulting mixture has a pH of 1.8 and that 20 mL of NaOH was added to the HCl solution. We can use the pH of the mixture and the volume of the NaOH solution to calculate the concentration of the NaOH solution as follows:

First, we need to convert the pH of the mixture to the concentration of H+ ions. To do this, we can use the formula:

[H+] = 10^(-pH)

Plugging in the value for pH, we get:

[H+] = 10^(-1.8)

= 0.135 M

Next, we need to use the volume of the NaOH solution and the concentration of H+ ions to calculate the concentration of the NaOH solution. Since the NaOH solution neutralized the HCl solution, the concentration of H+ ions in the mixture must be equal to the concentration of the NaOH solution. Therefore, the concentration of the NaOH solution is 0.135 M.

Therefore, the concentration of the NaOH solution that was added to the HCl solution is 0.135 M.

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It is crucial to be able to extend out a line diagram to a condensed formula, therefore the first step in this process.

The next step is to begin sketching the various scenarios as we switch out one hydrogen on a propane cylinder for a chlorine atom. It should be obvious that there are only two options for chlorinating propane: C-1 or C-2 (chlorination at C-3 would give the same product as that at C-1).

Monochlorination means the addition of a chlorine atom. When chlorine atom is added to the below structure. Chlorine will substitute at one of the hydrogens.

Constitutional isomers of these two substances are 1-chloropropane and 2-chloropropane.

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