Doing science by inquiry always involves:​

Explanation:

[tex]from \: the \: wave \: equation \\ Speed \: \: V = f \lambda \\ = 350 \times 0.971 \\ = 339 850 \: {ms}^{ - 1} [/tex]

Answer:

The automobile's acceleration in that time interval is -2 m/s^2

Explanation:

The acceleration is defined as the rate of change of the velocity.

The average acceleration in a given lapse of time is calculated as:

A = (final velocity - initial velocity)/time.

In this case, we have:

initial velocity = 31 m/s

final velocity = 15 m/s

time = 8 seconds.

Then the average acceleration is:

A = (15m/s - 31m/s)/8s = -2 m/s^2

Answer:

Well. the law says "an object in motion stays in motion" So seatbelts could be one. they stop us humans from continuing to move when the car stops.

Answer:

  r2 = 1 m

therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m

Explanation:

For this exercise we must use conservation of energy

the electric potential energy is

          U = [tex]k \frac{q_1q_2}{r_{12}}[/tex]

for the proton at x = -1 m

          U₁ =[tex]- k \frac{e^2 }{r+1}[/tex]

for the electron at x = 1 m

          U₂ = [tex]k \frac{e^2 }{r-1}[/tex]

starting point.

        Em₀ = K + U₁ + U₂

        Em₀ = [tex]\frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1}[/tex]

final point

         Em_f = [tex]k e^2 ( -\frac{1}{r_2 +1} + \frac{1}{r_2 -1})[/tex]

energy is conserved

        Em₀ = Em_f

        \frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e^2 (- \frac{1}{r_2 +1} + \frac{1}{r_2 -1})              

        \frac{1}{2} m v^2 - k \frac{e^2}{r+1} + k \frac{e^2}{r-1} = k e²(  [tex]\frac{2}{(r_2+1)(r_2-1)}[/tex] )

we substitute the values

½ 9.1 10⁻³¹ 450 + 9 10⁹ (1.6 10⁻¹⁹)² [ [tex]- \frac{1}{20+1} + \frac{1}{20-1}[/tex] ) = 9 109 (1.6 10-19) ²( [tex]\frac{2}{r_2^2 -1}[/tex] )

          2.0475 10⁻²⁸ + 2.304 10⁻³⁷ (5.0125 10⁻³) = 4.608 10⁻³⁷ ( [tex]\frac{1}{r_2^2 -1}[/tex] )

          2.0475 10⁻²⁸ + 1.1549 10⁻³⁹ = 4.608 10⁻³⁷     [tex]\frac{1}{r_2^2 -1}[/tex]

          [tex]\frac{2.0475 \ 10^{-28} }{1.1549 \ 10^{-37} } = \frac{1}{r_2^2 -1}[/tex]

          r₂² -1 = (4.443 10⁸)⁻¹

          r2 = [tex]\sqrt{1 + 2.25 10^{-9}}[/tex]

          r2 = 1 m

therefore the electron that comes with velocity does not reach the origin, it stops when it reaches the position of the electron at x = 1m

Answer:

As the car travels up the coaster it is gaining potential energy.

Explanation:

Because It has the greatest in amount of potential energy at the top of the coaster. when the car travels down the roller coaster it obtains speed and kinetic energy.

Answer: The electrons flowing through the wire are referred to as a quantity of electricity, and the flow of electricity is referred to as “an electric current.”

Explanation: Hope it Helps have a blessed day

Answer: [tex]0.708\ mA[/tex]

Explanation:

Given

[tex]E_o=20\ V/m[/tex]

[tex]\omega =10^7\ s^{-1}[/tex]

Cross-sectional area [tex]A=0.40\ m^2[/tex]

Current density is given by

[tex]J=\epsilon_o \dfrac{dE}{dt}[/tex]

Displacement current

[tex]\Rightarrow I=JA\\\Rightarrow I=8.854\times 10^{-12}\times 20\times 10^7\times 0.4\\\Rightarrow I=0.708\times 10^{-3}\ A[/tex]

The required value of the maximum displacement current of the given space is  [tex]7.08 \times 10^{-4} \;\rm A[/tex].

Given data:

The intensity of electric field is, [tex]E_{0}=20 \;\rm V/m[/tex].

The angular frequency of electric field is, [tex]\omega=1.0 \times 10^{7} \;\rm s^{-1}[/tex].

The cross-sectional area of space is, [tex]A =0.40 \;\rm m^{2}[/tex].

In the given problem, the instantaneous electric field is given by [tex]E = E_{0} \times cos(\omega t)[/tex]

So, the expression for the current density is,

[tex]J= \epsilon_{0} \times \dfrac{dE}{dt}[/tex]

Here, [tex]\epsilon_{0}[/tex]  is the permittivity of free space. Solving as,

[tex]J= \epsilon_{0} \times \dfrac{d(E_{0} \times cos(\omega t))}{dt}\\\\J= -\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)[/tex]

And the expression for the maximum displacement current is,

[tex]I = J \times A[/tex]

And the maximum displacement current is possible only when, J is positive and J will be positive for  [tex]sin(\omega t)=-1[/tex].

Then solving as,

[tex]I = (-\epsilon_{0} \times E_{0} \times \omega \times sin(\omega t)) \times A\\\\I = (-8.85 \times 10^{-12} \times 20 \times (1.0 \times 10^{7}) \times (-1)) \times 0.40\\\\I = 7.08 \times 10^{-4} \;\rm A[/tex]

Thus, we can conclude that the required value of the maximum displacement current of the given space is  [tex]7.08 \times 10^{-4} \;\rm A[/tex].

Learn more about the displacement current here:

https://brainly.com/question/20344850

Physics is the study of nature and law

Answer:

Physics is the science of matter and how matter interacts. Matter is any physical material in the universe. Everything is made of matter. Physics is used to describe the physical universe around us, and to predict how it will behave.

Answer:

3000 cm

Explanation:

Answer:

Yes my name is Axelrod I can help you

Answer:

3920 N.

Explanation:

that's what the answer is..

Answer: GPS

Explanation:

I took the test 2021

Answer:

okkkkkkkkkkkkkkkkkkkk

Answer:

please find the answer in the attached image, divided in 2 parts.

Answer:I think it’s Velocity plot.

Explanation:

I hope i can help you, have a great day and good like with everything.

Answer: inverse plot

Explanation: lucky guess lmk if its right

Answer:

Yes, its true

Explanation:

hdheheishdhieijzuwhs

Answer: yes its true

Explanation:

nmo

Answer:

15.1 m/s²

Explanation:

Step 1: Calculate the force exerted by the friction

Friction exerts a force against the direction of the movement. On a horizontal plane, we can calculate the value of that force using the following expression.

Ff = μ × m × g

where,

μ: coefficient of kinetic friction

m: mass of the block

g: gravity

Ff = 0.50 × 10 kg × 9.81 m/s² = 49 N

Step 2: Calculate the resulting force

The horizontal force F and the friction force Ff are vectors that act in opposite directions. We can calculate the resulting force (R) by doing the subtraction.

R = F - Ff = R = 200 N - 49 N = 151 N

Step 3: Calculate the acceleration of the block

We will use Newton's second law of motion.

R = m × a

a = R/m

a = 151 N/10 kg = 15.1 m/s²

Answer:

force is of the LINEAR type

Explanation:

In simple harmonic movements the restoring force is of the Hooke e-force type, which has the form

            F = - k (x-x₀)

where x₀ is the initial length of the spring.

Therefore we can see this force is of the LINEAR type

Answer:

0.2 Hz

Explanation:

f = v / λ.

Where f = frequency,

v = velocity/speed,

λ = wavelength.

f = v / λ →

f = 2.2m/s / 11 m

f = 2.2 / 11 [1 / s]

f = 1 / 5 [Hz]

f = 0.2 Hz

Answer:

Heres the link!

Explanation:

https://www.bbc.co.uk/news/science-environment-56491033

Answer:

here's the link you asked for: https://www.nyas.org/ebriefings/the-physics-of-everything/ and here's the info inside the link: During the second quarter of 2016, the Academy hosted a series of evening panel discussions boldly titled "." With grant support from The John Templeton Foundation, the six panels addressed how physics is addressing grand questions and the potential limitations on what we may be able to learn using physics to address those questions.

The first session posed the question "" Three physicists explored the frontiers of cosmology and quantum physics. There may always be limits to our understanding in areas such as string theory, dark matter, and multiverses. But the panelists agreed that it is best to proceed as if explanations based in physics can be found.

The second session asked "" The panelists argued that philosophy has much to offer physics, in contrast to the assertions of some prominent physicists. In such areas as the role of observations in quantum mechanics and the experimental validation of theory, the panelists illustrated the power of a critical, interdisciplinary approach to understanding not only the facts but the significance of physics ideas.

Physics has achieved its success in part by selecting problems that can be addressed by reducing them to simple parts following simple laws. Less amenable subjects were discussed in the third session, "" Biology, ecology, and social phenomena such as cities are all not easily described with simple equations, but still show amazing regularities. The panelists, including two physicists, a philosopher, and a computer scientist, sketched their hopes for unifying principles that explain these regularities.

One complex phenomenon that has so far evaded physical analysis was the topic of the fourth session, "." Two of the panelists, a neuroscientist and a roboticist, did not even regard consciousness as a distinct phenomenon but rather as a byproduct of systems that model themselves. In contrast, a philosopher and a physicist felt that this behavioral description misses something essential about what consciousness "feels like." Both groups expressed hope for experimental tests of their views.

The fifth session addressed the question, "" Recent experimental observations of thousands of planets orbiting other stars bolster the expectation that ours is not the first civilization. The panelists explored how we might look for others and why we have not encountered any yet. One troubling possibility is that civilizations that achieve global scale inevitably encounter challenges such as climate change that they fail to overcome.

The sixth session was entitled "." Two physicists and a computer scientist discussed amazing developments at the intersection of quantum gravity (as manifested in black holes) and quantum information. Trying to reconcile these disparate observations has overturned the traditional view of black holes, with no clear resolution so far. At the same time, an abstract connection between gravitational models and quantum models in one fewer dimension is providing insight into both fields, including new methods for error correction in quantum computing as well as benchtop tests of black hole physics.

The wide ranging discussions of the six panels illustrate the power of physics to explain the universe as well as the vast frontiers of that universe that still remain to be explored.

Explanation:

hope this helped plz give brainliest and rating ^_^

Answer:

1.439 × 10¹¹ m is the answer.

Explanation:

1 light-second = 2.998 × 10⁸m

480 light-seconds = 480 × 2.998 × 10⁸

= 1439.04 × 10⁸

= 1.439 × 10¹¹

∴ 1.439 × 10¹¹ m is the answer.

The distance converted into the meter will be 1.439×10¹¹ m.In one light second, there are 2.998 ×10⁸ m.

Distance is a numerical representation of the distance between two objects or locations.

The distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.

The given data in the problem is;

The  distance between the sun and moon is,d= 480 light second

[tex]\rm d_m[/tex] is the distance in meter

As we know,

[tex]\rm 1\ light\ second = 2.998 \times 10^8m \\\\ 480\ light\ seconds = 480 \times 2.998 \times 10^8\ m \\\\ d_m= 1439.04 \times 10^8 \\\\ d_m = 1.439 \times 10^{11}[/tex]

Hence the distance converted into the meter will be 1.439×10¹¹ m.

To learn more about the distance refer to the link;

https://brainly.com/question/26711747

Convection currents in the mantle are slowly causing the plates to move.

Answer:

An egg raised above the ground has potential energy due to the force of gravity. When dropped, the egg's potential energy is converted into the kinetic energy of motion. :)

Explanation:

Answer:

Work = Force × Distance

Explanation:

Work = Force × Distance

The SI unit of work is Joule

-TheUnknownScientist

Answer:

18 ohms

Explanation:

V = I(R1 + R2)

5V = (0.167A)(12 ohms + R2)

Solving for R2

R2 = 18 ohms