Answer:
Read it carefully below
Step-by-step explanation:
Based on the formula you provided, the function appears to model exponential decay. In general, exponential decay occurs when the growth rate of a quantity is proportional to its current value, and the growth rate is a fixed constant less than 1.
In this case, the growth rate is given by the constant factor 7/3 (which is less than 1), and the function uses the variable t as the exponent. As t increases, the value of the function decreases exponentially.
(7×107)(8 x 10²) what is the anwser
Answer:
The correct answer would be 5000 x ^108
Step-by-step
marquis has some quarters and dimes. he has 26 coins worth a total of $ 3.80 . how many of each type of coin does he have?
Each type of coin marquis have is 18
The value of a dime is ten cents. The value of a quarter is 25 cents. Dimes are smaller than quarters. Fun fact: Copper and nickel, the metal used to create quarters and dimes, are the same. One dime is equal to ten cents. The value of a penny, often known as a one-cent coin, is one cent.
A dime coin is equivalent to 10 one-cent coins in value (pennies). The word "dime" derives from the Latin word "decimus," which means "one tenth." When they came up with the concept of money being split into ten parts in the 1500s, the French adopted the word "disme." The spelling was altered from "disme" to "dime" in America.
Here d = number of dimes
Here q = number of quarters and
Number equation: d + q = 26
Value equation: 0.10d + 0.25q = 3.80
Here the value for the equation is multiplied by 100: 10d + 25q = 380
the two equations:
d + q + 26 ---> multipling by -10 ---> -10d - 10q = -260
10d + 25q = 380 ---> 10d + 25q = 380
Adding the columns: 15q = 120
q = 120/15
q = 8
d + q = 26
d+8=26 ;
d=26-8
d = 18
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The drama club i elling ticket to their play to raie money for the how' expene. Each tudent ticket ell for $5 and each adult ticket ell for $7. 50. The auditorium can hold at mot 125 people. The drama club mut make no le than $790 from ticket ale to cover the how' cot. If 73 adult ticket were old, determine all poible value for the number of tudent ticket that the drama club mut ell in order to meet the how' expene. Your anwer hould be a comma eparated lit of value. If there are no poible olution, ubmit an empty anwer
This means that in order to make at least $790, the drama club must sell 47 number of student tickets. 47,48,49,50,51
The first equation is 5x + 7(73) = 790, where x is the number of student tickets. We can solve this equation to determine that x = 47. This means that in order to make at least $790, the drama club must sell 47 student tickets. Then, we can check the other possible values of x to see how many tickets they must sell. The other possible values are 48, 49, 50, and 51. Therefore, the answer is 47, 48, 49, 50, 51.
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The dimensions of a rectangle are StartRoot 50 a cubed b squared EndRoot and StartRoot 200 a cubed EndRoot. A student found the perimeter as follows: 2 StartRoot 50 a cubed b squared EndRoot + StartRoot 200 a cubed EndRoot = 2 times 5 a b StartRoot 2 a EndRoot times 10 a StartRoot 2 a EndRoot. = 10 a b StartRoot 2 a EndRoot + 20 a StartRoot 2 a EndRoot. = 30 a b StartRoot 2 a EndRoot.
What is the student’s error?
The correction made by the student is incorrect simplification of 30ab√2a+20a√2a
What is perimeter?The perimeter of a polygon is the sum of its, all the side lengths.
Given that, the dimension of a rectangle is given by, √50a³b² and √200a³
The perimeter of the rectangle is = 2(length + width)
Solving for the perimeter,
2(√50a³b²+√200a³)
= 2(5ab√2a+10a√2a)
= 10ab√2a+20a√2a
The student solved it as 30ab√2a,
Which is incorrect, because 'b' is not there in both the expressions, hence, we cannot add them.
Hence, The correction made by the student is incorrect simplification of 30ab√2a+20a√2a
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Answer:
Step-by-step explanation:
Answer is D on Edge,
The student incorrectly simplified 10ab sqrt 2a + 20a sqrt 2a
Given mn, find the value of x.
149⁰
write the percent and the decimal shown by the model
percent: __ %
decimal: __
please please please help meee :>
The percentage represented is 72%, and the decimal is 0.72
How to write the percent and the decimal?
First lets find the decimal, it will be equal to the quotient between the total number of shaded squares and the total number of squares.
There are 200 squares in total, and of these 200, there are 144 shaded ones, then the decimal is:
d = 144/200 = 0.72
To find the percentage, you only need to multiply the decimal by 100%, we will get:
p = 100%*0.72 = 72%
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Increase by
50%
Decrease by
5%
A number went into this machine and 57 came out.
What number went in?
Answer:
Step-by-step explanation:
Let x be the number that went in,
[x(1+50%)]x(1-5%)=57
x(1+50%)=60
x=40
The solution is, the number went in is 40.
What is percentage?A percentage is a number or ratio that can be expressed as a fraction of 100. A percentage is a number or ratio expressed as a fraction of 100. It is often denoted using the percent sign, "%", although the abbreviations "pct.", "pct" and sometimes "pc" are also used. A percentage is a dimensionless number; it has no unit of measurement.
here, we have,
given that,
when a number Increase by 50% & Decrease by 5%,
then, A number went into this machine and 57 came out.
Let x be the number that went in,
so, using the given condition, we get,
[x(1+50%)]x(1-5%)=57
x(1+50%)=60
x=40
Hence, The solution is, the number went in is 40.
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Write the equation for a parabola with a focus at (-2, 5) and a directrix at x = 3.
Solid chance this is way above your knowledge level
A parabola is a curve in the shape of a U that is defined as the set of all points that are equidistant to a fixed point (called the focus) and a fixed line (called the directrix).
To write the equation of a parabola with a focus at (-2, 5) and a directrix at x = 3, we can use the standard form of the equation of a parabola, which is:
y = (1/(4f))x^2 + k
Where f is the distance between the focus and the vertex (the point where the parabola changes direction), and k is a constant that determines the position of the parabola along the y-axis.
To find the value of f, we can use the distance formula:
f = sqrt((x2 - x1)^2 + (y2 - y1)^2)
Where (x1, y1) is the coordinate of the focus and (x2, y2) is the coordinate of the vertex.
Since the focus is at (-2, 5) and the directrix is at x = 3, we can use the y-coordinate of the focus as the y-coordinate of the vertex, and the x-coordinate of the directrix as the x-coordinate of the vertex. Therefore, the coordinate of the vertex is (3, 5).
Substituting these values into the distance formula, we get:
f = sqrt((3 - (-2))^2 + (5 - 5)^2)
= sqrt((5)^2 + (0)^2)
= sqrt(25)
= 5
Now that we have the value of f, we can substitute it into the standard form of the equation of a parabola to get:
y = (1/(4*5))x^2 + k
= (1/20)x^2 + k
This is the equation for a parabola with a focus at (-2, 5) and a directrix at x = 3. The constant k determines the position of the parabola along the y-axis.
I'll give brainliest for the correct answers!!
Using proportions and constant of proportionality, the train always move the same distance and the cost is always the same
What is ProportionsProportion can defined as the comparison between two numbers or ratios. Using proportions, when two sets of given numbers are increasing or decreasing in the same ratio, then the ratios are said to be directly proportional to each other.
The proportional relationship between two numbers can be represented as
y = kx
k = constant of proportionalityi)
In this question, let's determine if they have the same constant of proportionality.
y = kx
6 = k(2)
k = 3
12 = k(4)
k = 3
Since they have the same constant of proportionality, the train always go the same distance each minute.
ii)
The time travelled in 10 minutes
y = 3x
y = 3(10)
y = 30
The distance in 10 minutes is 30km
b)
Using constant of proportionality to determine if they have a proportional relationship;
y = kx
21 = k(3)
k = 7
42 = k(6)
k = 7
The equation is y = 7x and the constant of proportionality is 7.
The cost for each person is always the same
ii) From y = 7x
63 = 7x
x = 63 / 7
x = 9
The predicted number for a cost of $63 is 9
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A medical clinic is reducing the number of incoming patients by giving vaccines before flu season. during week 5 of flu season, the clinic saw 85 patients. in week 10 of flu season, the clinic saw 65 patients. assume the reduction in the number of patients each week is linear. write an equation in function form to show the number of patients seen each week at the clinic.
What is the coefficient of the x¹y³ term in the expansion of (x - 2y)'?
X
-8
560
-280
35
5. Write the following Arithmetic Sequence using an Explicit Formula: a₁ = 8, an = an-1-2
an = 8+2(n-1)
an=8-2(n-1)
an=2-8(n-1)
an=2+8(n-1)
The explicit formula of the sequence is (b) a(n) = 8 - 2(n - 1)
How to determine the explicit formulaFrom the question, we have the following parameters that can be used in our computation:
a₁ = 8,
aₙ = aₙ₋₁ - 2
In the above sequence, we can see that the 2 is subtracted from the previous term to get the current term
This means that
first term, a = 8
common difference, d = -2
The nth term is then represented as
a(n) = a + (n - 1)d
Substitute the known values in the above equation, so, we have the following representation
a(n) = 8 + (n - 1) * -2
Evaluate
a(n) = 8 - 2(n - 1)
Hence, the explicit is (b) a(n) = 8 - 2(n - 1)
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Helpppppp pleaseeee thank you
find the area enclosed by the curve x = t2 − 3t, y = t and the y-axis.
The area enclosed by the curve x = t2 − 3t, y = t and the y-axis is 9/2
In this question we have been given parametric equations x = t^2 − 3t, y = t
In this question we need to find the area enclosed by the curve x = t2 − 3t, y = t and the y-axis.
The curve has intersects with y-axis.
Consider x = 0
So, t^2 − 3t = 0
t(t - 3) = 0
t = 0 or t = 3
Let f(t) = t^2 − 3t and g(t) = t
Now we have to draw the graph,
Differentiate the curve f(t) with respect to t.
f'(t) = 2t - 3
Now, find the area under the curve using the above formula
A = ∫[a to b] g(t)f'(t) dt
so, A = ∫[0 to 3] t (2t - 3) dt
A = ∫[0 to 3] (2t^2 - 3t) dt
A = [2/3 t^3 - 3/2 t^2]_[t = 0, t = 3]
A = 2/3 3^3 - 3/2 3^2
A = 18 - (3^3)/2
A = 18 - 27/2
A = 9/2
Therefore, the area of the curve is 9/2.
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lilyana runs a cake decorating business, for which 10\, percent of her orders come over the telephone. let ccc be the number of cake orders lilyana receives in a month until she first gets an order over the telephone. assume the method of placing each cake order is independent. find the probability that it takes fewer than 555 orders for lilyana to get her first telephone order of the month.
The Probability of getting less than 555 orders = x<555/ccc
What is independent probability?
Suppose we discuss about two events which can be occurred at any time but the occurrence of one event is not dependent on other event. In such case the probability of occurring each event is called independent probability.
How to calcualte independent probability?The probability of two independent events is calculated by the formula
probability of one event × probability of another event
If A and B are two events occurred independently
probability of happening two events = P(A)×P(B)
In our problem, order for cake over telephone is one event
order for cake manually is another event
10 percent order get over telephone
So, percent of probability to get order from phone = 10/100 = 1/10
She got total ccc cake order in a month before getting order over phone
let. X is a number of orders she got before getting her first telephone order.
Therefore, the probability that it takes fewer than 555 orders for Lilyana to get her first telephone order = X<555/ccc
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imagine that we rolled a fair, six-sided die 1,000 times. out of 1,000 rolls, how many times do you think the die would come up even (2, 4, or 6)?
Probability of Number of outcome is an even in likely situation is given as 512
Given that;
Number of time die roll = 1,000
Find:
Probability of Number of outcome is an even
Computation:
Probability of an even = 3 / 6
Probability of an even = 1 / 2
Probability of Number of outcome is an even = [Probability of an even]1000
Probability of Number of outcome is an even = [1/2]1000
Probability of Number of outcome is an even = 500
So most likely outcome is 512
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The length of the Bolden
Boat is 5.2 x 102 inches
long. The length of Riggin
is double the length of the
Bolden. How long is the
Riggin boat?
Answer:
This is answer of 530.4 Q
show that f is continuous on (−[infinity], [infinity]). f(x) = 1 − x2 if x ≤ 1 ln(x) if x > 1
The function f is continuous on (-∞, ∞).
What are Continuous Functions?A function f is said to be continuous at a point 'a' if,
lim ₓ→a f(x) = f(a).
f(x) = [tex]\left \{ {{1-x^2 if x\leq 1} \atop {ln x if x > 1}} \right.[/tex]
That is, if x ≤ 1, f(x) = 1 - x² and if x > 1, f(x) = ㏑ x
Taking interval (-∞, 1], f(x) is a polynomial 1 - x².
Polynomials are continuous everywhere. So f is continuous at (-∞, 1].
Now take the interval (1, ∞).
[tex]\lim_{x \to \infty} f(x)[/tex] = [tex]\lim_{x \to \infty} lnx[/tex] = ㏑ ∞ = ∞ = f(∞)
So f is continuous at the interval (1, ∞)
To check for continuity at 1,
lim x → 1⁻ f(x) = lim x → 1⁻ [1 - x²] = 1 - 1² = 0
lim x → 1⁺ f(x) = lim x → 1⁺ ㏑ x = ㏑ 1 = 0
So, lim x → 1⁻ f(x) = lim x → 1⁺ f(x)
So f is continuous in the whole interval (-∞, ∞).
Hence the function f(x) = [tex]\left \{ {{1-x^2 if x\leq 1} \atop {ln x if x > 1}} \right.[/tex] is continuous on the interval (-∞, ∞).
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Hello help please
14+2n - -4(n-5)
Answer:8
Step-by-step explanation:
Find the Area of the figure below, composed of a rectangle and a semicircle. The radius of the circle is shown. Round to the nearest tenths place.
Answer:
13 × 10 = 130 ( it's a rectangle)
5² π /2 ≈ 12.5 × 3.14 = 39.25 ( semicircle)
130 + 39.25 = 169.25 ≈ 170
What is the circumference of a circle whose radius is 16 feet leave answer in term of pi please show ur work Bc I have too !!
Answer:
Step-by-step explanation:
Formula for Circumference of a circle is 2* pi * radius
If r=16
C= 2*π*16
C=32π
A kangaroo chae a rabbit that tart 150 feet ahead of the kangaroo. For every 12-foot leap of the kangaroo, the rabbit leap 7 feet. How many leap would the kangaroo have to make to catch up to the rabbit?
Rabbit leaps two feet. Kangaroo leaps sixteen feet. sEight time as far as the rabbit, the kangaroo jumps.
What is unitary method?The unitary technique involves first determining the value of a single unit, followed by the value of the necessary number of units. what kinds of values and units
Let's say you go to the store to buy six apples.
You are informed by the shopkeeper that he is offering 10 apples for Rs 100. In this instance, the value and the units are the price of the apples. Recognizing the units and values is crucial when using the unitary technique to a problem.
Always write the items that need to be computed on the right side and the things that are known on the left side to simplify things.
We are aware of the quantity of apples and the amount of money in the aforesaid problem.
According to our question-
A bunny leaps two feet. The kangaroo leaps 16 feet. The kangaroo leaps eight times farther than the rabbit.
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Given the inequality -6 (1 + 2x) ≥ 6 (2x - 1) + 2, which of the following are included in the solution? Select ALL that apply.
Ps. I chose just the answer 0 and only received a 1/3
Answer:
A, C, E
Step-by-step explanation:
You want the values from the list that are included in the solution set of -6(1 + 2x) ≥ 6(2x - 1) + 2x.
SolutionSimplifying the inequality, we get ...
-6 -12x ≥ 12x -6 +2x
0 ≥ 26x . . . . . . . . . . . . . add 12x+6
x ≤ 0 . . . . . . . . . . . . divide by 26
The solution set includes 0 (choice C) and all negative values (choices A and E).
Determine wheather the graphs of y=2x+1 and y=-1/2x-7 are parallel, perpendicular, coincident, or none of these. PLEASE HELP ASAP!!!! will mark brainlest.
Answer:
b
Step-by-step explanation:
the equation of a line in slope- intercept form is
y = mx + c ( m is the slope and c the y- intercept )
y = 2x + 1 ← is in slope- intercept form
with slope m = 2
y = - [tex]\frac{1}{2}[/tex] x - 7 ← is in slope- intercept form
with slope m = - [tex]\frac{1}{2}[/tex]
• Parallel lines have equal slopes
the slopes are not equal thus not parallel
• the product of the slopes of perpendicular lines is equal to - 1
2 × - [tex]\frac{1}{2}[/tex] = - 1
Thus the 2 lines are perpendicular to each other.
help me solve this please
The inequality or number of units produced per hour is 15.50<10+0.50x.
What is Inequality?Mathematical expressions with inequalities are those in which the two sides are not equal. Contrary to equations, we compare two values in inequality. Less than (or less than or equal to), greater than (or greater than or equal to), or not equal to signs are used in place of the equal sign.
Given:
According to the question the inequality can be
15.50<10+0.50x
15.50-10<0.50x
5.50<0.50x
5.50/0.50x
x> 11
For checking the Inequality
Let x=12.
15.50<10+.50*12
15.50+10+6
15.50<16
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Find the dimensions of a right triangle if it’s area is 40m^2 where the height is 2 meters less than the base.
base = _ meters
height= _ meters
Answer:
The dimensions of the right triangle are 9 meters by 7 meters.
or
The base of the triangle is 9 meters, and the height is 7 meters (since the height is 2 meters less than the base).
Step-by-step explanation:
To find the dimensions of the right triangle, we can use the formula for the area of a triangle, which is:
A = 1/2 * b * h
Where b is the base and h is the height of the triangle. In this case, we know that the area of the triangle is 40 square meters, and the height is 2 meters less than the base, so we can write the equation as:
40 = 1/2 * b * (b - 2)
To solve for b, we can rearrange the equation to get b by itself:
40 = 1/2 * b^2 - b
Then, we can move all the terms involving b to the left-hand side of the equation and all the constants to the right-hand side:
1/2 * b^2 - b - 40 = 0
Next, we can use the quadratic formula to solve for b:
b = (-(-1) +/- sqrt((-1)^2 - 4 * (1/2) * -40)) / (2 * (1/2))
Which simplifies to:
b = (1 +/- sqrt(1 + 80)) / 1
Since b must be a positive number, we take the positive solution:
b = (1 + sqrt(81)) / 1
Therefore, the base of the triangle is 9 meters, and the height is 7 meters (since the height is 2 meters less than the base). Thus, the dimensions of the right triangle are 9 meters by 7 meters.
let f=(y2+z3,x3+z2,xz). evaluate ∬∂wf⋅ds for each of the following regions w:
For ∬∂WF⋅dS differentiable each of the following regions is 0, [tex]\frac{18 \sqrt{2}}{15}, -\frac{16 \sqrt{2}}{15}[/tex]
Let the f=[tex]\left(y^2+z^3, x^3+z^2, x z\right) \\[/tex],
Differentiability of Function: For a function to be differentiable at any point x=a in its domain, it must be continuous at that particular point but vice-versa is not always true. In complex analysis, complex-differentiability is defined using the same definition as single-variable real functions. This is allowed by the possibility of dividing complex numbers
Solution: For checking the continuity, we need to check the left hand and right-hand limits and the value of the function at a point x=a.
This means that f'(a) must exist, or equivalently:
[tex]$$\lim _{x \rightarrow a^{+}} f^{\prime}(x)=\lim _{x \rightarrow a^{-}} f^{\prime}(x)=\lim _{x \rightarrow a} f^{\prime}(x)=f^{\prime}(a)$$[/tex]
(A).
[tex]& x^{2 / t} y^2 \leq z \leq 2 \\\\& \int_{\theta=0}^{2 \pi} \int_{\gamma=0}^{\sqrt{2}} \int_{z=\gamma^2}^2 \gamma \cos \theta d z d \gamma d \theta \\\\&=\int_{\theta=0}^{2 \pi} \int_{\gamma=0}^{\sqrt{2}}[\gamma \cos \theta][z]_{\gamma^2}^2 d \gamma d \theta \\[/tex]
[tex]&=\int_{\theta=0}^{2 \pi} \int_{\gamma=0}^{\sqrt{2}}\left(2-\gamma^2\right) \gamma \cos \theta d \gamma d \theta \\\\&=\int_{\theta=0}^{2 \pi}\left[\gamma^2-\frac{\gamma^4}{4}\right]_0^{\sqrt{2}} \cos \theta d \theta \\\\&=\int_{\theta=0}^{2 \pi} \cos \theta d \theta \\\\&=[\sin \theta]_0^{2 \pi} \\&=0[/tex]
(B).
[tex]& \ x^2+y^2 \leq 2 \leq 2 . \quad, x \geqslant 0 \\[/tex]
[tex]& \int_{0=-\frac{\pi}{2}}^{\frac{\pi}{2}} \int_{\gamma=0}^{\sqrt{2}} \int_{z=\gamma^2}^2 \gamma^2 \cos \theta d z d \gamma d \theta . \\\\& =\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \int_0^{\sqrt{2}} \gamma^2 \cos \theta[z]^2 \gamma^2 \cdot d \gamma d \theta \text {. } \\[/tex]
[tex]& =\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \int_0^{\sqrt{2}} \cos \theta\left(2-\gamma^2\right) \gamma^2 d \gamma d \theta . \\\\& =\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \cos \theta\left[\frac{2}{3} \gamma^3-\frac{\gamma^5}{5}\right]_0^{\sqrt{2}} d \theta \text {. } \\[/tex]
[tex]& =\int_{-\frac{\pi}{2}}^{\frac{\pi}{2}} \cos \theta\left[\frac{4}{3} \sqrt{2}-\frac{4 \sqrt{2}}{5}\right] d \theta . \\\\& =[\sin \theta]_{-\frac{\pi}{2}}^{\frac{\pi}{2}} d \theta\left[\frac{4}{4} \sqrt{2}-\frac{4 \sqrt{2}}{5}\right] \\\\& =\left[\frac{4 \sqrt{2}}{3}-\frac{4 \sqrt{2}}{5}\right] \\[/tex]
[tex]& =\left[\frac{4 \sqrt{2}}{3}-\frac{4 \sqrt{2}}{5}\right] \\\\& =\left[\frac{20 \sqrt{2}-12 \sqrt{2}}{15}\right]=2\left[\frac{8 \sqrt{2}}{15}\right] \\\\& =\frac{18 \sqrt{2}}{15}[/tex]
(C).
[tex]x^2+y^2 & \leqslant z \leqslant 2, x \leq 0 \\[/tex]
A+B+C
0=B+C
B=-C or C=-B
C=[tex]-\frac{16 \sqrt{2}}{15}[/tex]
Therefore, the differentiable of each function is 0, [tex]\frac{18 \sqrt{2}}{15}, -\frac{16 \sqrt{2}}{15}[/tex].
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Let F=[tex]\left(y^2+z^3, x^3+z^2, x z\right) \\[/tex]) . Evaluate ∬∂WF⋅dS for each of the following regions W:
A.[tex]& x^{2 / t} y^2 \leq z \leq 2 \\\\ \\[/tex]
B. [tex]& \ x^2+y^2 \leq 2 \leq 2 . \quad, x \geqslant 0 \\[/tex]
C. [tex]x^2+y^2 & \leqslant z \leqslant 2, x \leq 0 \\[/tex]
Hello can i get a little help giveing 20 points to who ever help and bralyles so yeh help
Answer:
a) n less than or equal to 21
b) n greater than or equal to 5
c) n > 3/5
Step-by-step explanation:
i hope this helps!!
Answer:
A.) n ≤ 21
B.) n ≥ 5
C.) n > 3/5
Step-by-step explanation:
For the first question it says that the number is no more than 21, so it could be equal to or less than 21
For the second question, it says that the number is at least 5, so it could be equal to or greater than 5
Finally, for the last question it says that the number is more than 3/5, so greater than would be the correct inequality symbol to use
slope: 3; y-intercept: -8
Answer:
Use desmos to help with slopes and finished equations its a graphing calculator and its very helpful
Step-by-step explanation:
Answer:
y=3x-8
Step-by-step explanation:
slope, or m (3), is always next to an x. y-intercept (-8) goes always after the mx
Work out the area of a rectangle with base B= 38mm and perimeter, P = 88mm
Answer: the area of the rectangle is 456 square millimeters.
Step-by-step explanation:
the perimeter is 88 mm, so if we let L be the length of the rectangle and W be the width, we can write the following equation to find the perimeter:
2L + 2W = 88 mm
Since the base of the rectangle is 38 mm, we know that the width of the rectangle is 38 mm, so we can substitute that value into the equation above to get:
2L + 2(38 mm) = 88 mm
Solving for L, we get:
2L = 88 mm - 2(38 mm)
2L = 88 mm - 76 mm
2L = 12 mm
Therefore, the length of the rectangle is 12 mm. Now that we know both the length and the width, we can find the area by multiplying the length and the width:
Area = L * W
Area = 12 mm * 38 mm
Area = 456 mm^2
Thus, the area of the rectangle is 456 square millimeters.
Answer:
A=228mm
Step-by-step explanation:
What formulas do we know?
Parameter= 2(length)+2(width)
Area= length x width
We can just substitute in values for parameters so,
88=2(length) + 2(38)
88=2L + 78 ------> 12=2L -------> L=6
Now we know width (which is just B) and Length (what we calculated)
Now we use area ----> Area= length x width
Area= (38)(6)-----> 228mm