does iodine occur naturally in salt ? yes or no​

Answer:

Cyclohexane (C6H12) Is Soluble In Benzene (C6H) And Insoluble In Water. This Is Because Benzene Has A Lower Density Than Water Lower Heat Capacity Than Water Lower Boiling Point Than Water Lower Polarity Than Water.

Cyclohexane is insoluble in water solvents, but it is soluble in Benzene, because it is a nonpolar Solvent.

Solubility in chemistry depend upon the nature of the solvent and the solute "like dissolves like".

Cyclohexane  and  Benzene both  are  a nonpolar solute  and only dissolve in nonpolar solvent.

Hence, water is a polar solvent cyclohexane  it is not soluble in water.

Learn more about solubility.

https://brainly.com/question/5173732

#SPJ2

Answer:

Experiment 1

Explanation:

I don’t know if this is right

Answer:

The elements present in calcium phosphate-based on molecular formula are calcium, phosphorus, and oxygen. The molecular mass of Ca or calcium is 40.08 grams per mole, the molecular mass of P or phosphorus is 30.97 grams per mole, and the molecular mass of oxygen is 16.00 grams per mole. So, in combination, the molecular mass of Ca₃(PO₄)₂ is, = (3 × 40.08 + 2 ×3 0.97 + 8 × 16) = 310.18 grams per mole

Now, the mass percent of calcium is, = n × molecular mass of calcium/ molecular mass of Ca₃(PO₄)₂ × 100% = 3 × 40.08 / 310.18 × 100 = 38.76 % Thus, the mass percent of the calcium in calcium phosphate is 38.76%.  

The mass percent of phosphorus (P), = n × molecular mass of phosphorus/molar mass of Ca₃(PO₄)₂ × 100% = 2 × 30.97/310.18 × 100 = 19.97% Thus, the mass percent of phosphorus in calcium phosphate is 19.97%.  

The mass percent of oxygen (O), = n × molecular mass of oxygen/molar mass of Ca₃(PO₄)₂ × 100% = 8 × 16/310.18 × 100% = 41.27% Thus, the mass percent of oxygen in calcium phosphate is 41.27%.

Answer:

no

Explanation:

because its just no lol.

Light acting as 'packets' of exact amounts of energy (a particle-like quality) called quanta led to the development of quantum mechanics. Light also has wave qualities (wavelength, frequency, amplitude) which is referred to as particle-wave duality.

Answer:

pH = 4.42

Explanation:

HN3, a weak acid reacts with NaOH as follows:

HN3 + NaOH  → H2O + NaN3

Where 1mol HN3 reacts with 1mol NaOH

After the reaction of only a part of HN3, you will have in solution HN3 (Weak acid) and NaN3 (Conjugate base). This mixture produce a buffer that follows H-H equation:

pH = pKa + log [Conjugate base] / [Weak acid)

Where pH is the pH of the buffer

The hydrazoic acid is a weak acid with pKa = 4.6

And [] could be taken as the moles of each species

After the reaction, the moles of NaOH added = Moles NaN3 produced

And moles HN3 = Initial moles HN3 - Moles NaOH

Moles NaOH = Moles NaN3:

5x10⁻³L * (0.200mol / L) = 1x10⁻³ mol NaN3

Initial moles HN3:

0.025L * (0.100mol / L) = 2.5x10⁻³ moles HN3

final moles: 2.5x10⁻³ moles HN3 - 1x10⁻³ mol = 1.5x10⁻³ moles HN3

Replacing in H-H equation is:

pH = 4.6 + log [1x10⁻³ mol NaN3] / [1.5x10⁻³ moles HN3]

Answer:

0.5447

Explanation:

The atomic packing fraction factor is given by

APF = Volume of sphere/ Volume of unit cell

[tex]APF = \frac{N\times V_N}{V_C}[/tex]

The atomic radius = 0.135 nm

The Density of the metal = 3.55 g/cm^3

To calculate the number of atoms

= desnsity/(atomic radius×Avagadro's number)

Putting values and solving we get

the number of atoms = 4

Now,

[tex]APF = \frac{4\times 4/3\pi(0.135\times10^{-9})^3}{(0.545\times10^{-9})^2(0.255\times10^{-9})}[/tex]

Solving we get

APF = 0.54427

1.2 × 10²⁴ atoms C

Chemistry

Atomic Structure

Stoichiometry

Math

Pre-Algebra

Order of Operations: BPEMDAS

Step 1: Define

Identify variables

[Given] 24 g C

[Solve] atoms C

Step 2: Identify Conversions

Avogadro's Number

[PT] Molar Mass of C: 12.01 g/mol

Step 3: Convert

Step 4: Check

Follow sig fig rules and round. We are given 2 sig figs.

1.2034 × 10²⁴ atoms C ≈ 1.2 × 10²⁴ atoms C

Answer:

0.16 L

Explanation:

Step 1: Write the balanced equation

C₃H₈(g) + 5 O₂(g) → 3 CO₂(g) + 4 H₂O(g)

Step 2: Calculate the moles of CO₂ produced from 0.012 moles of O₂

The molar ratio of O₂ to CO₂ is 5:3. The moles of CO₂ produced are 3/5 × 0.012 mol = 0.0072 mol.

Step 3: Calculate the volume occupied by 0.0072 moles of CO₂ at standard temperature and pressure

At STP, 1 mole of CO₂ occupies 22.4 L.

0.0072 mol × 22.4 L/1 mol = 0.16 L

Answer:

Explanation:

A chemical bond formed when two atoms share three pairs of electrons is a triple bond; it is best described as covalent.

Answer:

TRUE

Explanation:

The total length of the wires will affect the amount of resistance. The longer the wire, the more resistance that there will be.

Answer:

true

Explanation:

Answer:

5.0 moles of water per one mole of anhydrate

Explanation:

To solve this question we must find the moles of the anhydrate. The difference in mass between the dry and the anhydrate gives the mass of water. Thus, we can find the moles of water and the moles of water per mole of anhydrate:

Moles Anhydrate:

7.58g  * (1mol / 84.32g) = 0.0899 moles XCO3

Moles water:

15.67g - 7.58g = 8.09g * (1mol / 18.01g) = 0.449 moles H2O

Moles of water per mole of anhydrate:

0.449 moles H2O / 0.0899 moles XCO3 =

5.0 moles of water per one mole of anhydrate

Answer:

At the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

Explanation:

At cathode, reduction reaction takes place.

The dissociation of MgI2 in aqueous solution is Mg2+(aq) and 2I−(aq)

Here, the Iodine reduces to 2I−(aq) from state of 0 (MgI2) to state of -1 (2I−(aq))

Hence, at the cathode during the electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced

Answer:

During electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced at the cathode

Explanation:

Electrolysis is a process whereby ionic compound is broken down or degraded into smaller substances when electric current flow through it.

During electrolysis of magnesium iodide, At the cathode reduction reaction occur .

MgI2 is dissociated to is Mg2+(aq) and 2I−(aq)

Then Iodine is reduced to 2I−(aq) which is 0 in (MgI2) then change to -1 (2I−(aq))

Therefore;

During electrolysis of an aqueous solution of magnesium iodide, MgI2 , 2I−(aq) is produced at the cathode.

AAnswer:

Explanation:

Answering:

It is D

Explanation:

Just took the test

The concentration of hydronium ion [H₃O⁺] and hydroxide ion [OH¯] are:

The pH of a solution is simply a measure of the acidic or alkalinity of the solution.

The concentration of hydronium ion [H₃O⁺] and hydroxide ion [OH¯] can be obtained as illustrated below:

Data obtained from the question

pH = 10.2

Determination of the concentration of hydronium ion [H₃O⁺]

pH = 10.2

pH = –log[H₃O⁺]

10.2 =  –log[H₃O⁺]

Multiply though by –1

–10.2 = log[H₃O⁺]

Take antilog of –10.2

[H₃O⁺] = antilog(–10.2)

Determination of the pOH

pH = 10.2

pOH =?

pH + pOH = 14

10.2 + pOH = 14

Collect like terms

pOH = 14 – 10.2

Determination of the concentration of Hydroxide ion [OH¯].

pOH = 3.8

pOH = –log[OH¯]

3.8 = –log[OH¯]

Multiply through by –1

–3.8 = log[OH¯]

Take the antilog of –3.8

[OH¯] = antilog(–3.8)

1. Concentration of hydronium ion [H₃O⁺] = 6.3×10¯¹¹ M

2. Concentration of Hydroxide ion [OH¯] = 1.6×10¯⁴ M

Learn more: https://brainly.com/question/13387755

Answer:

7.16x10⁻⁸M = [Ag+]

Explanation:

Using the equation:

E(Cell) =E⁰ - 0.0592/2 • log ([Cu2+]/[Ag+]²)

Where E⁰= 0.4249V

E(Cell) = -(-0.0019V) -Measured value-

[Cu2+] = 1M

Replacing:

0.0019V = 0.4249V - 0.0592/2 • log (1M/[Ag+]²)

-0.423V = - 0.0296 • log (1M/[Ag+]²)

14.29 = log (1M/[Ag+]²)

1.95x10¹⁴ = 1M / [Ag+]²

[Ag+]² = 5.12x10⁻¹⁵M

7.16x10⁻⁸M = [Ag+]

Answer:

4 moles of O2 are consumed if 8moles of H2

Answer:

B. Cu + AgNO3 → CuNO3 + Ag

C. 2NaBr + Cl2 → 2NaCl + Br2

D. F2 + 2NaBr → 2NaF + Br2

Explanation:

There are several types of reactions in chemistry, of which one of them is the SINGLE DISPLACEMENT REACTION. Single displacement reaction is that reaction in which only one element in a compound is displaced/replaced by another element.

The following reactions given in this question are examples of single displacement reactions;

- Cu + AgNO3 → CuNO3 + Ag

- 2NaBr + Cl2 → 2NaCl + Br2

- F2 + 2NaBr → 2NaF + Br2

* In the first reaction, silver (Ag) is displaced by copper (Cu)

* In the second reaction, bromine (Br) is displaced by chlorine (Cl)

* In the third reaction, bromine (Br) is displaced by fluorine (F)

The single replacement reaction are;

A single displacement reaction is one in which one of the reactants replaces another. A typical example is the reaction; A + BC ---> AB + C.

Having this in mind, we can see that the reactions that correspond to a single replacement reaction are;

Learn more about single replacement reaction: https://brainly.com/question/1984022

Answer:

yea

Explanation:

Answer:1.Owen

2.By dropping the balls from the same height

3.She dropped the balls from different heights

4. Perform a second trial

Explanation: sub to technoblade plz

Answer:

A molecule is the smallest particle of a substance that is made up of 2 or more atoms

An atom is the smallest particle of any pure element

An element is a substance that cannot be broken chemical and physical processes

A molecule is known as the building block of matter

A compound is a chemical substance that is made up of 2 more more different atoms bonded together

Answer:

B. Most energy comes from non-renewable sources

Explanation:

A P E X

In United States Most energy comes from non-renewable energy sources, as petroleum  coal and others has the highest consumption in the given chart

In the given chart, the energy consumption in US is based on Petroleum, coal and others  the highest consumption pattern as compared to other energy sources

Hence, most energy in the US is from non-renewable energy sources

Learn about renewable energy sources.

https://brainly.com/question/4038933

#SPJ2

Answer:

10573.9K

Explanation:

Using pressure law equation;

P1/T1 = P2/T2

Where;

P1 = initial pressure (mmHg)

P2 = final pressure (mmHg)

T1 = initial temperature (K)

T2 = final temperature (K)

According to the information provided in this question,

P1 = 46mmHg

P2 = 760mmHg

T1 = 640K

T2 = ?

Using P1/T1 = P2/T2

46/640 = 760/T2

Cross multiply

640 × 760 = 46 × T2

486400 = 46T2

T2 = 486400 ÷ 46

T2 = 10573.9K

Answer:

2 moles of NO

Explanation:

Our reaction is:

4NH₃ + 5O₂  →   6H₂O  +  4NO  

4 moles of ammonia react to 5 moles of oxygen in order to produce 6 moles of water and 4 moles of NO

We need to determine the limiting reactant:

Ratio is 4:5, As 4 moles of ammonia react to 5 moles of oxygen and we have 4 moles, we definetely need 5 moles, but the problem is, we only have 2.5 moles of O₂. Oxygen is the limting reagent.

5 moles of O₂ produce 4 moles of NO, according to stoichiometry

2.5 moles of O₂ may produce (2.5 . 4) / 5 = 2 moles of NO

Answer: Type A are cardiac muscles Type B are skeletal muscles, and Type C are smooth muscles.

Explanation: sub to technoblade :P

Answer:

11

∘

C

Explanation:

As far as solving this problem goes, it is very important that you do not forget to account for the phase change underwent by the solid water at

0

∘

C

to liquid at

0

∘

C

.

The heat needed to melt the solid at its melting point will come from the warmer water sample. This means that you have

q

1

+

q

2

=

−

q

3

(

1

)

, where

q

1

- the heat absorbed by the solid at

0

∘

C

q

2

- the heat absorbed by the liquid at

0

∘

C

q

3

- the heat lost by the warmer water sample

The two equations that you will use are

q

=

m

⋅

c

⋅

Δ

T

, where

q

- heat absorbed/lost

m

- the mass of the sample

c

- the specific heat of water, equal to

4.18

J

g

∘

C

Δ

T

- the change in temperature, defined as final temperature minus initial temperature

and

q

=

n

⋅

Δ

H

fus

, where

q

- heat absorbed

n

- the number of moles of water

Δ

H

fus

- the molar heat of fusion of water, equal to

6.01 kJ/mol

Use water's molar mass to find how many moles of water you have in the

100.0-g

sample

100.0

g

⋅

1 mole H

2

O

18.015

g

=

5.551 moles H

2

O

So, how much heat is needed to allow the sample to go from solid at

0

∘

C

to liquid at

0

∘

C

?

q

1

=

5.551

moles

⋅

6.01

kJ

mole

=

33.36 kJ

This means that equation

(

1

)

becomes

33.36 kJ

+

q

2

=

−

q

3

The minus sign for

q

3

is used because heat lost carries a negative sign.

So, if

T

f

is the final temperature of the water, you can say that

33.36 kJ

+

m

sample

⋅

c

⋅

Δ

T

sample

=

−

m

water

⋅

c

⋅

Δ

T

water

More specifically, you have

33.36 kJ

+

100.0

g

⋅

4.18

J

g

∘

C

⋅

(

T

f

−

0

)

∘

C

=

−

650

g

⋅

4.18

J

g

∘

C

⋅

(

T

f

−

25

)

∘

C

33.36 kJ

+

418 J

⋅

(

T

f

−

0

)

=

−

2717 J

⋅

(

T

f

−

25

)

Convert the joules to kilojoules to get

33.36

kJ

+

0.418

kJ

⋅

T

f

=

−

2.717

kJ

⋅

(

T

f

−

25

)

This is equivalent to

0.418

⋅

T

f

+

2.717

⋅

T

f

=

67.925

−

33.36

T

f

=

34.565

0.418

+

2.717

=

11.026

∘

C

Rounded to two sig figs, the number of sig figs you have for the mass of warmer water, the answer will be

T

f

=

11

∘

C

Explanation:

The question is incomplete, the complete question is shown in the image attached to this answer

Answer:

B

Explanation:

A Lewis acid is specie that has vacant orbitals and is able to accept a lone pair of electrons while a Lewis base is any specie having a lone pair of electrons which can be donated to another chemical specie.

Hence a Lewis acid accepts a lone pair of electrons while a Lewis base donates a lone pair of electrons.

From the resonance structure shown, the carbon atom in the carbonyl compound ought to function as the Lewis acid since it is electrophilic (electron deficient).

Answer: The Carbon atom in the carbonyl will act as a lewis acid and will accept a pair of electrons

Explanation:

In the minor resonance structure for the carbonyl group, we observe a positive formal charge on the carbon atom. Because of its positive formal charge, the carbon atom will act as a Lewis acid and accept a pair of electrons to stabilize that formal charge.

Answer:

its option 3

Explanation:

the molarity of the solution increases

If more powdered Kool-Aid is added to the same amount of water, then the molarity of the solution increases because there are more solute particles in the solution.

Molarity of a given solution is known as the total number of moles of solute per litre of the solution.  A solution that is 1.00 molar (written 1.00 M) contains 1.00 mole of solute for every liter of solution.

Molarity = (No. of moles of solute ÷ Volume of solution in liters)

The unit of molarity is mol L⁻¹.

Molarity is temperature dependent because as temperature changes, volume of the solution also changes.

Therefore, If more powdered Kool-Aid is added to the same amount of water, then the molarity of the solution increases because there are more solute particles in the solution.

Learn more about molarity, here:

https://brainly.com/question/8732513

#SPJ2

Answer: The molar concentration of 29 g of [tex]Mg(OH)_{2}[/tex] dissolved in 1.00 L of water is 0.497 M.

Explanation:

Given: Mass = 29 g

Volume = 1.00 L

Moles is the mass of substance divided by its molar mass. So, moles of [tex]Mg(OH)_{2}[/tex] is as follows.

[tex]Moles = \frac{mass}{molar mass}\\= \frac{29 g}{58.32 g/mol}\\= 0.497 mol[/tex]

Molarity is the number of moles of a substance divided by volume in liter.

Hence, molarity of the given solution is as follows.

[tex]Molarity = \frac{moles}{Volume (in L)}\\= \frac{0.497 mol}{1.00 L}\\= 0.497 M[/tex]

Thus, we can conclude that the molar concentration of 29 g of [tex]Mg(OH)_{2}[/tex] dissolved in 1.00 L of water is 0.497 M.

Answer:

Red litmus turns blue

Explanation:

Hope it helps