Divide.

389.5÷1000

pls answer correctly

Answer:

Θ ≈ 28.07°

Step-by-step explanation:

using the sine ratio in the right triangle

sinΘ = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{8}{17}[/tex] , then

Θ = [tex]sin^{-1}[/tex] ( [tex]\frac{8}{17}[/tex] ) ≈ 28.07° ( to the nearest hundredth )

The chord length is approximately 1.397 centimeters where 0.7 centimeters is the separation from the center of the circle to the chord.

We can use the properties of circles to find the angle formed by the chord at the center of the circle to evaluate the length of the chord.

0.7 centimeters is the separation from the center of the circle to the chord. This remove is additionally the stature of the isosceles triangle shaped by the chord and the two radii of the circle. 

Let θ be the angle between the chord and the center of the circle. You can use trigonometry to find θ.

sin(θ/2) = 0.7/2.5

[tex]θ/2 = sin⁻¹(0.7/2.5)[/tex]

θ/2 = 0.2793

θ=2×0.2793

θ ≈ 0.5586 radians

Now that we know θ, we can use the formula for the chord length of a circle.

chord length = 2 × radius × sin(θ/2)

Chord Length = 2 × 2.5 × sin(0.2793)

String length ≈ 1.397 cm

Therefore, the chord length is approximately 1.397 centimeters.

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Answer:

2/3 pizza is left!

Step-by-step explanation:

You take 1/3 from a whole pizza (3/3), leaving 2/3 for ur 2 buddies :D

Therefore, the maximum displacement of the particle is 4 units, and it occurs at time t = 1.

To find the maximum displacement, we need to first determine the particle's velocity and acceleration.

The velocity of the particle is given by the derivative of its position function:

[tex]v(t) = y'(t) = 3t^2 - 12t + 9[/tex]

The acceleration of the particle is given by the derivative of its velocity function: a(t) = v'(t) = 6t - 12

Now, to find the maximum displacement, we need to find the time at which the particle comes to rest.

This occurs when its velocity is zero:

[tex]3t^2 - 12t + 9 = 0[/tex]

Simplifying this equation, we get:

[tex]t^2 - 4t + 3 = 0[/tex]

This quadratic equation factors as:

(t - 1)(t - 3) = 0

So the particle comes to rest at t = 1 or t = 3.

Next, we need to determine whether the particle is at a maximum or minimum at each of these times.

To do this, we look at the sign of the acceleration:

When t = 1, a(1) = 6(1) - 12 = -6, which is negative.

Therefore, the particle is at a maximum at t = 1.

When t = 3, a(3) = 6(3) - 12 = 6, which is positive.

Therefore, the particle is at a minimum at t = 3.

Finally, we need to find the displacement of the particle at each of these times:

[tex]y(1) = 1^3 - 6(1)^2 + 9(1) = 4[/tex]

[tex]y(3) = 3^3 - 6(3)^2 + 9(3) = 0.[/tex]

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The width of the river is approximately 45m.

Let's say the illustration may be explained as follows:

The big right triangle is located inside the river, with its base extending down one of its sides and its height spanning its breadth.

The base of the little right triangle lies on the opposite bank of the river, outside of it.

Triangles don't cross over one another. Their bases' endpoints contact, as does the end of their hypotenuses.

Let's assume the two right triangles are similar (which means they have proportional sides).

H1/B1 = H2/ B2

which is H1/55 = 21.4/26

=21.4/26 x 55

= 45.27

It is the larger triangle is the width of the river

If the smaller triangle represents the land on one side of the river and the larger triangle includes both the land and the river, we need to find the width of the river by subtracting the base of the smaller triangle from the base of the larger triangle:

Width of the river = 55 - 26 = 29 meters

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The equation in standard form is (x- (-12))² + (y - 0)²  = (√164)²

The standard form of the equation of a circle is

(x-a)² + (y-b)² = r²

where (a, b) is the center and r is the radius

Using the completing square method on the given equation:

24x + y² = -x² + 20

x²+ 24x + y² = 20

[x² + 24x + (12)²] + [y² + 0x + (0)²] = 20 + (12)²

(x + 12)² + (y + 0)² = 164

(x - (-12))² + (y - 0)² = 164

(x- (-12))² + (y-0)²  = (√164)²

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a) The polygon has 8 sides and is called an octagon.

b) The measure of each interior angle of the octagon measures 135 degrees.

c) The measure of each exterior angle of the octagon measures 45 degrees.

a. To classify the polygon by the number of sides, we can use the formula for the sum of the interior angles of a polygon:

Sum of interior angles = (n - 2) x 180 degrees

where n is the number of sides of the polygon.

In this case, we are given that the sum of the interior angles is 1080 degrees. So we can set up an equation as follows:

(n - 2) x 180 = 1080

Simplifying this equation, we get:

n - 2 = 6

n = 8

b. To find the measure of one interior angle of the polygon, we can use the formula for the measure of each interior angle of a regular polygon:

Measure of each interior angle = (n - 2) * 180 degrees / n

Substituting n = 8 into this formula, we get:

Measure of each interior angle = (8 - 2) * 180 degrees / 8

= 135 degrees

c. To find the measure of one exterior angle of the polygon, we can use the fact that the sum of the interior and exterior angles of a polygon is 180 degrees. Therefore, the measure of each exterior angle of a regular polygon is:

Measure of each exterior angle = 360 degrees / n

Substituting n = 8 into this formula, we get:

Measure of each exterior angle = 360 degrees / 8

= 45 degrees

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The angle of C is 161.4°.

Law of sines defines the ratio of sides of a triangle and their respective sine angles are equivalent to each other. The other names of the law of sines are sine law, sine rule and sine formula.

We have :

In the Triangle ABC,

Angle A is 9 º

Side of a is 44 m,

and side of b is 46 m

To find the angle of C

Now, use the law of sines to find angle B:

b/sin B  = a/sin A

Plug all the values in above formula :

=> 46/Sin B = 44/Sin 9°

=> 46 × Sin9°/ 44 = Sin B

Sin B = 0.164

[tex]B = Sin^-^10.164[/tex]

B = 9.555

Now, By angle sum of property of a triangle,

The sum of three angles of a triangle is 180°

So, Let's apply angle sum property to find angle C

=> ∠ A + ∠ B + ∠C = 180°

Put the value of B = 9.555 and angle A = 9°

=> 9° + 9.555 + ∠C = 180°

18.555 +∠C = 180°

∠C = 180°- 18.555

∠C = 161.4°

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By quadratic formula the equation that has the same solution(s) as X² − 12x + 49 = 22 is M. (x − 6)² = 9 since it has solutions x=3 and x=9 which are also solutions to X² − 12x + 49 = 22

The quadratic equation ax² + bx + c = 0 can be resolved using the quadratic formula.

that uses the constants (a, b, c) and the numerical coefficients.

When factoring cannot be utilized to solve the quadratic expressions, this approach of solving a quadratic equation is typically used.

x = √(b² - 4ac) / (-b √(b²) / (2a)

We must solve each of the preceding equations to determine which one has the same solution(s) as X²- 12x + 49 = 22 in order to determine which equation has the same solution(s) as X²- 12x + 49 = 22.

Let's start by figuring out X²- 12x + 49 = 22:

X² − 12x + 49 = 22

X² − 12x + 27 = 0

The quadratic formula can then be used to find the value of x:

x = √(b² - 4ac) / (-b√(b²) / (2a)

where a=1; b=-12; and c=27.

x = (-(-12) ±√((-12)² - 4(1)(27))) / (2(1))

x = (12 ±√(144 - 108)) / 2

x = (12 √(36))/ 2

x = (12 6) / 2

x = 6,3

So x = 6,3 is the answer to the equation X²- 12x + 49 = 22.

Let's now resolve each of the provided equations:

M. (x − 6)² = 9 (x -6)² -9=0

(x-6+3)(x-6-3)=0

(x-3)(x-9)=0, where x=3 or x=9

P. (x − 7)² = 22 (x-7)²-22=0

(x-7+√(22))=0

(x=7+√(22))

or (x=7-√(22))

R. (x + 7)² = 4.7 (x+7)²-4.7=0

(x+7+√(4.7))(x+7-√(4.7))=0

No effective remedies

S. (x − 12)²= −27 (x-12)²+27=0

No effective remedies

Therefore, the equation that has the same solution(s) as X² − 12x + 49 = 22 is M. (x − 6)² = 9

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Answer:

36

Step-by-step explanation:

Given:

1/6 of the marbles are red

1/3 of the marbles are blue

There are 18 green marbles in the jar

We can set up the following equations based on the given information:

Number of red marbles = 1/6 * x

Number of blue marbles = 1/3 * x

Number of green marbles = 18

Since the total number of marbles in the jar is "x", we can write the equation for the sum of all the marbles as:

(Number of red marbles) + (Number of blue marbles) + (Number of green marbles) = x

Substituting the values from the given information:

1/6 * x + 1/3 * x + 18 = x

Multiplying through by 6 to eliminate the fraction:

x/6 + 2x/6 + 18 = 6x/6

x + 2x + 108 = 6x

Combining like terms:

3x + 108 = 6x

Subtracting 3x from both sides of the equation:

3x + 108 - 3x = 6x - 3x

108 = 3x

Dividing both sides by 3 to solve for x:

108/3 = 3x/3

36 = x

The intercepts of the graph of y = x²- 25 are (-5, 0), (5, 0), and (0, -25).

Data can also be presented as a table. However, when the information is presented graphically, it is much easier to understand. There are many types of charts and each of them serves specific purposes in different fields.  

To find the x-intercepts of the graph, we need to set y = 0 and solve for x:

0 = x²- 25

Adding 25 to both sides gives:

25 = x²

Taking the square root of both sides gives us:

x = ±5

So the x-intercepts are (-5, 0) and (5, 0).  To find the y-intercept, we need to set x = 0 and solve for y:

y = 0²-25

y = -25

So the y-intercept is (0, -25).  

Therefore, the intercepts of the graph of y = x² - 25 are (-5, 0), (5, 0), and (0, -25).

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The least common multiple of two or more numbers is the smallest number that is a multiple of each of the given numbers. For example, the LCM of 2 and 3 is 6, because 6 is the smallest number that is a multiple of both 2 and 3.

For this problem, the number of packs bought is the least common multiple of 10 and 12, which is obtained by factoring them into prime numbers as follows:

10 - 12|2

5 - 6|2

5 - 3|3

5- 1|5

1 - 1

Hence:

lcm(10, 12) = 2² x 3 x 5 = 60.

Hence:

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The value of x that makes the equation true is 8

A linear equation is a type of equation that the highest power of it's variable is 1. Example of linear equation include, x+2 =y, x+7/2 =15.

The graph of a linear equation is a straight line and it is represented in form of y = mx+b. Where m is the slope and b is the y intercept.

Solving x-7 = (3/4)x -5

collecting like terms

x-(3/4)x = 7-5

x/4 = 2

x = 8

therefore the value of x that will make the equation x-7 = (3/4)x -5 true is 8.

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Answer:

10%

Step-by-step explanation:

Answer: True

Step-by-step explanation:

Answer:

Step-by-step explanation:

330/2 = 165

330/3 = 110

330/5 = 66

330/6 = 55

330/10 = 33

330/11 = 30

the answer is true

The null hypothesis is that the population mean weekly sales are $9820. The alternate hypothesis is that they are greater than $9820. The calculated t-value is 7.45, which is greater than the critical value of 1.677. Therefore, we reject the null hypothesis and conclude that the population mean weekly sales are higher than $9820.

To test whether the population mean weekly sales have increased after advertising, we can use a one-sample t-test.

The null hypothesis is that the population mean weekly sales have not increased, which means the population mean is still $9820:

H0: μ = $9820

The alternative hypothesis is that the population mean weekly sales have increased, which means the population mean is greater than $9820:

Ha: μ > $9820

The significance level is 0.05, so we need to calculate the critical value of t for a one-tailed test with 49 degrees of freedom (n-1), which is 1.677.

To calculate the test statistic, we can use the formula:

t = (X - μ) / (s / √n)

Where X is the sample mean, μ is the hypothesized population mean, s is the sample standard deviation, and n is the sample size.

Given that the sample mean is X = $10960, the hypothesized population mean is μ = $9820, the sample size is n = 50, and the population standard deviation is θ = $1580, we can calculate the sample standard deviation:

s = θ / √n = $1580 / √50 = $223.61

Now we can calculate the test statistic:

t = (X - μ) / (s / √n) = ($10960 - $9820) / ($223.61 / √50) = 7.45

Since the calculated t-value (7.45) is greater than the critical t-value (1.677), we reject the null hypothesis and conclude that there is sufficient evidence to suggest that the population mean weekly sales have increased after advertising.

Therefore, we can infer that the advertising campaign in the local newspaper has been effective in increasing the sales of the electronics store.

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--The given question is incomplete, the complete question is given

"  a small electronics store has begun to advertise in the local newspaper. before advertising, the long term average weekly sales $9820. a random of 50 weeks while the newspaper ads were running gave a sample mean weekly sale of x = $10960. Does this indicate that the population mean weekly sales is now more than $9820? test at the 5% level of significance. Assume theta = $1580.

A. state the null and alternate hypothesis.

B. Compute the   or t va;ue of the sample test statistic.

C. Find the critical value(s).

D. based on the answers to a-c, what is your conclusion?"--

The term that is not affected the standard error of an estimator is population size, from the provide data in options. So, option (c) is right one.

The standard error is a statistical term that used to measured the accuracy that a sample distribution represents a population by using standard deviation. The standard error(SE) is very similar to standard deviation of a distribution. Both are used to measure the spread of distribution. Higher the value SE, the more spread out your data is. In statistical way, standard error is also called standard error of mean, SEM, it represents the deviation of sample mean deviates from the actual mean of a population.

It is calculated simply by dividing the standard deviation by the square root of the sample size. That is [tex]SE = \frac{σ }{\sqrt{n}}[/tex]

where , n --> sample size

σ --> population standard deviations

Now, from the above formula it is clearly seen that standard error term or an estimator affected by sample size (n) and population standard deviations ( σ). So, right choice for answer is population size.

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Complete question:

standard error of an estimator is not affected by the multiple choice question.

a) population standard deviation

b) sample size

c) population size

l'exercice 3 est la boisson d'Andres. Je suis désolé si cela ne ressemble pas vraiment à un français parfait, je parle anglais et j'utilise Translate. passe une bonne journée!

The probability of drawing two aces from a well-shuffled deck of 52 cards without replacement is 0.45%.

The probability of drawing two aces from a well-shuffled deck of 52 cards without replacement can be calculated as follows:

First, we calculate the probability of drawing an ace on the first draw. Since there are four aces in the deck and 52 cards in total, the probability of drawing an ace on the first draw is:

P(Ace on first draw) = 4/52 = 1/13

Next, we need to calculate the probability of drawing an ace on the second draw, given that an ace was already drawn on the first draw. Since there are now only three aces remaining in the deck and 51 cards in total, the probability of drawing an ace on the second draw is:

P(Ace on second draw given an ace on first draw) = 3/51

To calculate the probability of drawing two aces, we multiply the probability of drawing an ace on the first draw by the probability of drawing an ace on the second draw, given that an ace was already drawn on the first draw:

P(Drawing two aces) = P(Ace on first draw) x P(Ace on second draw given an ace on first draw)

P(Drawing two aces) = (1/13) x (3/51)

P(Drawing two aces) = 0.0045 or approximately 0.45%.

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The claim that makes the most accurate statement regarding how many cookies the institution will require There will be 480 pupils who favour cookies at the college.

Decimals or fractions can also be used to represent percentages. Divide a percentage by 100 to turn it into a fraction.

If the sample of 225 students was truly random and not just selected from a certain group, we may calculate percentages depending on it.

As a result, "There will be roughly 640 pie-loving pupils at the college."

Thus, the claim that makes the most accurate forecast regarding how many cookies the institution will require There will be 480 pupils who favour cookies at the college.

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Taner will only need to run 3 km this week to complete his 6 km running goal.

If we require a definition, we may start by saying that fractional numbers are numbers that symbolize one or possibly more portions of a unit that has been subdivided into equal parts.

Given that, Taner's overall running goal is 6 km (including last week and this week)

So,

Taner's 2-week goal is 6 kilometres.

Now,

Taner's goal for the week is 3 kilometres = (6/2).

As the Taner completed 3 km of running last week. Taner can achieve his objective this week by running just 3 miles.

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Answer:

N'(2, 3)

Step-by-step explanation:

my trick is counting how many spaces away it is from the axis it's being reflected over. So for this one N was at (2, -3) so I counted upwards 3 spaces from the 2 and i got to (2,3). i hope that makes sense the way i explained it.

hope this helps ;)

Answer:

  see attached

Step-by-step explanation:

You want the image of point N(2, -3) after reflection in the y-axis, plotted on the graph.

A line of reflection is the perpendicular bisector of the segment between a point and its image. That is, the image point is as far from the line as the original point, but on the opposite side of it.

The attached figure shows the location of image point N'(-2, -3).

__

Additional comment

The coordinate transformation for reflection in the y-axis just changes the sign of the x-coordinate. That puts the image point as far to the left as the original is to the right:

  (x, y) ⇒ (-x, y) . . . . . . reflection in the y-axis

The value of the triple integral is 1920pi/3.

Here are five other iterated integrals that are equal to the given iterated integral:

[tex]\Integral^2_0 \Integral^y_0 \Integral^1_0 f(x, y, z) dx dy dz[/tex]

[tex]\Integral^2_0 \Integral^z_0 \Integral^1_z f(x, y, z) dx dz dy[/tex]

[tex]\Integral^1_0 \Integral^y_0 \Integral^1_z f(x, y, z) dx dz dy[/tex]

[tex]\Integral^1_0 \Integral^z_0 \Integral^1_y f(x, y, z) dx dy dz[/tex]

[tex]\Integral^z_0 \Integral^1_0 \Integral^y_z f(x, y, z) dx dy dz[/tex]

To evaluate the triple integral of[tex](4 + 5x^2yz^2) dV[/tex]over the cylindrical region [tex]x^2 + y^2[/tex] <= 4, -2 <= z <= 2, we can use geometric interpretation and symmetry.

Note that the integrand [tex](4 + 5x^2yz^2)[/tex] is an even function of x and y, and an odd function of z.

Therefore, the integral over the region where z is positive is equal in magnitude but opposite in sign to the integral over the region where z is negative.

Hence, we can evaluate the integral over the region 0 <= z <= 2, and then double the result.

The region of integration is a cylinder of radius 2 and height 4.

Since the integrand is not dependent on x and y, we can factor out[tex](4 + 5z^2)[/tex]  from the integrand, and evaluate the remaining integral over the unit disc in the x-y plane.

Thus, the triple integral can be written as:

[tex]8 * \Integral^2_0 \Integral^2pi_0 \Integral^2_0 (4 + 5z^2) r^3 sin(\theta) dr d(\theta) dz[/tex]

Integrating with respect to r from 0 to 2 and with respect to [tex]\theta[/tex] from 0 to [tex]2\pi[/tex], we get:

[tex]8 * \Integral^2_0 \Integral^2pi_0 (4 + 5z^2) sin(\theta) d(\theta) dz[/tex]

Integrating with respect to theta from 0 to 2pi, we get:

[tex]16pi * \Integral^2_0 (4 + 5z^2) dz[/tex]

Integrating with respect to z from 0 to 2, we get:

16pi * (32/3 + 80) = 1920pi/3.

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There is no solution to this system of equations. (option B).

What is equation?

An equation is a mathematical statement which is made by two expressions connected by an equal sign. For example, 3x – 8 = 16 is an equation. Solving this equation, we get the value of the variable x as x = 8.

There is no solution to the given graph of two linear equations or system of linear equations.

From the given graph it is clear that graph of the given two equations shows  two lines that are parallel to each other. They don't meet or intersect each other at any point.

Since no point is on both lines, there is no ordered pair that makes both equations true.

Hence, there is no solution to this system of equations.

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The gross death rate is 8.38%.

What is a Rate?

A rate is a measure of the frequency of an event or occurrence in relation to a specific population or time period. Rates are often expressed in terms of units per time or per population, such as cases per 100,000 people or births per year.

The gross death rate is the number of deaths in a given time period divided by the total population or, in this case, the total number of discharges.

To calculate the gross death rate for City Hospital in June, we need to subtract the eight deaths that occurred within 48 hours of admission from the total number of deaths:

Total deaths = 49 - 8 = 41

Then, we divide the total number of deaths (41) by the total number of discharges (489) and multiply by 100 to get the rate per 100 discharges:

Gross death rate = (41 ÷ 489) x 100 = 8.38%

Therefore, the gross death rate for City Hospital in June is 8.38%.

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By calculating the CDF of normal distribution, the percentage of scores that are greater than 90 are 14.6%.

The CDF function of a Normal distribution is calculated by translating the random variable to the Normal Standard, and then looking up a value from the precalculated "Phi" function (Φ), which is the cumulative density function of the normal standard. The Normal Standard, often written Z, is a Normal with mean 0 and variance 1. Thus, Z∼N(μ=0,σ²=1).

Let x1, x2, .... be the scores on the test.

X ~ N (82, 64)

P(90 < X < 100) = Φ(18/8) - Φ(1) = 0.146 (using norm.s.dist function in excel)

Step-by-step explanation:

cores Distribution and Percentile

The scores on a test are normally distributed, with a mean of 82 and a standard deviation of 8. What percent of scores are less than 90? Explain

To find the percentage of scores that are less than 90 in a normally distributed test with a mean of 82 and a standard deviation of 8, we can use the cumulative distribution function (CDF) of the normal distribution.

The CDF of a normal distribution gives the probability that a random variable falls below a particular value. In this case, we want to find the probability that a score is less than 90.

The formula for the CDF of a normal distribution is:

CDF(x) = (1/2) * (1 + erf((x - μ) / (σ * sqrt(2))))

where erf is the error function, μ is the mean, σ is the standard deviation, and x is the value we want to find the cumulative probability for.

Plugging in the given values:

μ = 82

σ = 8

x = 90

We can calculate the cumulative probability using the formula:

CDF(90) = (1/2) * (1 + erf((90 - 82) / (8 * sqrt(2))))

Using a calculator or statistical software that provides the error function, we can find that erf(1.0) is approximately 0.6827.

Plugging this value back into the formula, we get:

CDF(90) = (1/2) * (1 + 0.6827) = 0.8414

So, the cumulative probability that a score is less than 90 is approximately 0.8414, or 84.14%.

Therefore, about 84.14% of the scores are less than 90 in this normally distributed test.

The volume of the cone is 1960.64 cubic yards.

We have,

The formula for the volume of a cone is:

V = (1/3)πr²h

where π is approximately 3.14, r is the radius, and h is the height.

Substituting the given values, we get:

V = (1/3) x 3.14 x 12² x 13

V = (1/3) x 3.14 x 144 x 13

V = 1/3 x 3.14 x 1872

V = 1960.64

Rounding to the nearest hundredth, we get:

V = 1960.64

Therefore,

The volume of the cone is 1960.64 cubic yards.

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