Determine which of the following elements would gain electrons when becoming ions: I. Hydrogen II. Helium III. Sulfur IV. Fluorine V. Gallium A. III and IV B. II, III, and IV C. I and V D. I and II

The law of conservation of mass say that, in a chemical reaction, the mass of the reagents will always be equal to the mass of the products.

If we have 29.5 g of HBr, we must have 100 g of H2 and Br2 together, so:

The half-life of the reaction is determined as 22.4 hr.

The half life of the reaction is calculated as follows

rate of reaction, k = Δ[A]/3t = Δ[B]/2t

t = Δ[A]/3k = Δ[B]/2k

where;

t = (3)/(3 x 0.0447) = (2)/(2 x 0.0447) = 22.4 hr

Thus, the half-life of the reaction is determined as 22.4 hr.

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The Ka of the solution is 8.1 * 10^-9.

The pH of a solution is the concentration of hydrogen ions in the solution.

Number of moles of the acid =  26.816g/153.483g/mol = 0.175 moles

Concentration of the acid =  0.175 moles/0.5 L = 0.35 M

Now we know that the acid reacts with water as follows;

HA(aq)  + H2O(l) ------> H3O^+(aq) + A^-(aq)

[H3O^+] = Antilog (-4.274)

[H3O^+] = 5.32 * 10^-5 M

Since;

[H3O^+]  = [A^-] = x

Ka = x^2/[HA]

Ka = (5.32 * 10^-5)^2/( 0.35)

Ka = 8.1 * 10^-9

Hence, the Ka of the solution is 8.1 * 10^-9.

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Answer:

electrolysis is the process by which electric current is passed through a substance to effect a chemical change

The mass in kg of the water on the roof after the rainstorm is mathematically given as

The mass of the water on the roof after a rainstorm is 1.1 *10^{10}g  or 1.1*10^{7}kg

Generally, the equation for the Area of the roof is  mathematically given as

[tex]A=0.20 \times 10^{10} \mathrm{~cm}^{2}[/tex]

height of the rain =5.5cm

the volume of the rain on the roof =1.1 * 10^{10} CC

Generally, the equation for mass is  mathematically given as

mass=volume*density

[tex]&=\left(1.1 \times 10^{10} \mathrm{cC} \times 1 \mathrm{~g} / \mathrm{cc}\right) \\&=1.1 \times 10^{10} \mathrm{~g}[/tex]

In conclusion, the Mass of the water on the roof after a rainstorm is 1.1 *10^{10}  or $1.1*10^{7}

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Answer:

A  group 1

Explanation:

Group 1

reactivity decreases as you go from L to R or downward on the periodic table

Answer:

j

Explanation:

becaisdbyhe wrl is so not goood

Answer:

Answer choices A, B, and C all contain a certain level (or amount, if you will) of Calcium Carbonate, but B. chalk contains the most amount out of all three.

Explanation:

I hope that this was helpful! (✿◠‿◠)

Thank you!

The volume of [tex]Ba(OH)_2[/tex] required will be 83.33 mL

The equation of the reaction is as follows:

[tex]Ba(OH)_2 + 2HBr --- > 2H_2O + BaBr_2[/tex]

Mole ratio of reactants = 1:2

Mole of 50 mL, 0.05 M HBr = 0.05 x 0.05 = 0.0025 moles

Equivalent mole of  [tex]Ba(OH)_2[/tex] = 0.0025/2 = 0.00125 moles

Volume of 0.015 M, 0.00125 moles  [tex]Ba(OH)_2[/tex] = 0.00125/0.015 = 0.0833 L

0.0833 L = 83.33 mL

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Considering the combined law, the volume of the sample is 81.639 L at 423 K and 1.00 atm.

Charles's law establishes the relationship between the temperature and the volume of a gas when the pressure is constant. This law says that the volume is directly proportional to the temperature of the gas: if the temperature increases, the volume of the gas increases while if the temperature of the gas decreases, the volume decreases.

Mathematically, Charles's law states:

[tex]\frac{V}{T}=k[/tex]

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant. That is, if the pressure increases, the volume decreases while if the pressure decreases, the volume increases.

Mathematically, this law is expressed as:

P×V= k

Gay-Lussac's law establishes the relationship between the temperature and pressure of a gas when the volume is constant. This law says that the pressure of a gas is directly proportional to its temperature: if the temperature increases, the pressure will increase, while if the temperature decreases, the pressure will decrease.

Mathematically, Gay-Lussac's law states:

[tex]\frac{P}{T}=k[/tex]

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

[tex]\frac{VxP}{T}=k[/tex]

Considering an initial state 1 and a final state 2, it is fulfilled:

[tex]\frac{V1xP1}{T1}=\frac{V2xP2}{T2}[/tex]

In this case, you know:

Replacing in combined law equation:

[tex]\frac{57.9 Lx1 atm}{300 K}=\frac{V2x1 atm}{423 K}[/tex]

Solving:

[tex]V2= \frac{423 K}{1 atm} \frac{57.9 Lx1 atm}{300 K}[/tex]

V2= 81.639 L

Finally, the volume of the sample is 81.639 L at 423 K and 1.00 atm.

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The ratio of diffusion rates of ¹H₂ to ²H₂ is 1.4 while the ratio of diffusion rates of O₂ to O₃ is 1.2.

Graham’s law states can be described as the rate of diffusion of a gas is inversely proportional to the square root of its molecular weight of the gas.

According to this Law, molecules with lower molecular mass will diffuse faster than those with higher molecular mass molecules at constant pressure and temperature.

The mathematical formula is utilized to compare the rates of diffusion of two different gases at pressures and temperatures.

[tex]{\displaystyle \frac{R_1}{R_2} =\sqrt{\frac{M_2}{M_1} }[/tex]

Where M₁ and M₂ represent the molar mass of gas 1 and gas 2.

Given, the molar mass of  ¹H₂  = 2.0 g/mol

The molar mass of to ²H₂ = 4.0 g/mol

The ratio of the rate of diffusion of ¹H₂ to ²H₂:

[tex]{\displaystyle \frac{R_{^1H_2}}{R_{^2H_2}} =\sqrt{ \frac{M_{^2H_2}}{M_{^1H_2}} }[/tex]

[tex]{\displaystyle \frac{R_{^1H_2}}{R_{^2H_2}} =\sqrt{ \frac{4}{2} }[/tex]

[tex]{\displaystyle \frac{R_{^1H_2}}{R_{^2H_2}} =1.4[/tex]

Given, the molar mass of  O₂  = 32.0 g/mol

The molar mass of to O₃ = 48.0 g/mol

The ratio of the rate of diffusion of O₂ to O₃:

[tex]{\displaystyle \frac{R_{O_2}}{R_{O_3}} =\sqrt{ \frac{M_{O_3}}{M_{O_2}} }[/tex]

[tex]{\displaystyle \frac{R_{O_2}}{R_{O_3}} =\sqrt{ \frac{48}{32} }[/tex]

[tex]{\displaystyle \frac{R_{O_2}}{R_{O_3}} =1.2[/tex]

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The molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L is 84.16g/mol.

The molecular mass can be calculated by first calculating the number of moles using the following formula:

PV = nRT

Where;

1.112 × 0.7 = n × 0.0821 × 300

0.7784 = 24.63n

n = 0.032mol

molecular mass = 2.66g ÷ 0.032mol

molecular mass = 84.16g/mol

Therefore, the molecular mass of a 2.66g sample of gas at a temperature of pressure of 845torr and occupying a volume of 0.70L is 84.16g/mol.

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Answer:

C- both!

Explanation:

In a chemical reaction, the total mass and total charge has to be balanced on both sides of the "equation", therefore both are conserved

Answer:

100 KJ

Explanation:

yep yep cool is that correct

A cofactor is an organic or inorganic molecule or ion necessary for proper functioning of some biological catalysts (option E).

A cofactor in biochemistry is a molecule that binds to and regulates the activity of a protein.

A cofactor is a metal or coenzyme responsible for the functioning of an enzyme and must be present.

Therefore, a cofactor is an organic or inorganic molecule or ion necessary for proper functioning of some biological catalysts.

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Answer: A. The particles move faster

Explanation:

Increasing the temperature increases the kinetic energy of the particles, causing them to move faster.

Answer:

See below

Explanation:

.75 = 1/2^(40/h)      

log .75 / ( log 1/2) = 40 / h

h = half life =   96.37683 min

To solve this type of question we must know the concept of rate law. The half-life of a compound is 23 years for 75% of a given sample of the compound decomposes in 40 minutes.

There are two kinds of rate law in chemical kinetics one is differential rate law and other is integrated rate law

The rate law for first order kinetics is

[tex]k=\frac{2.303}{t}log\frac{a}{a-x}[/tex]

Where

k - rate constant

t - time passed by the sample

a - initial amount of the reactant

a-x - amount left after the decay process

The expression for the half-life of the compound is

[tex]t_{1/2} = \frac{0.693}{K}[/tex]

Where k is the rate constant

t = 40 minutes

a = 100 g

a-x = 100 g - 75g = 25 g

(Since it is given that 75% of the given compound decomposes)

Then,

[tex]k=\frac{2.303}{40}log\frac{100}{25}[/tex]

=0.03years⁻¹

[tex]t_{1/2} = \frac{0.693}{0.03}[/tex]

=23 years

Therefore, the half-life of the given compound is 23years.

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[tex]K_2CO_3 + CaBr_2[/tex] → [tex]KBr + CaCO_3[/tex]  is the net ionic equation for this reaction.

An ionic equation is a synthetic equation where electrolytes are composed as separated particles.

[tex]K_2CO_3 + CaBr_2[/tex] → [tex]KBr + CaCO_3[/tex] is the net ionic equation for this reaction.

A balanced ionic equation. shows the reacting ions. in a chemical reaction. These equations can be used to represent what happens in precipitation reactions.

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Whether a living or non-living object, everyone has a particular life cycle. It starts right from the birth and ends upon the death of that object. Just like others, stars also have their own life cycle and that has different stages.

Nebula ⇒ Protostar ⇒ Supergiant ⇒ Supernova ⇒ Neutron Star

In the initial stage, a star is in the form of a nebula. At this stage, it is a huge cloud of gas and dust. The changes occur in the star and the final size totally depends upon the size of that star.

In a massive star, the fuel is used very quickly because of its life span of a few hundred thousand years. The second stage is the Protostar.

The next stage is the Supergiant. At this stage, the nuclear reactions that occur because of the hydrogen will gradually run out and the star will enter the final phase of its life span. The bigger star will have more massiveness.

Following this, the star will enter the next stage, i.e., supernova, and after that, neutron star. In a supernova, the star will have a very energetic and violent end. In the last stage, when the dust particles clear, a neutron star will be visible.

For better understanding, an image is attached at the end.

Thus, the life cycle of a high-mass star is arranged from its birth to its death.

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The stages of a high-mass star's life cycle in the correct order, from a star's birth to its death are-

Nebula

Protostar

Supergiant

Supernova

Neutron star

The life cycle of a high-mass star begins with a nebula, a cloud of gas and dust in space. As gravity pulls the nebula together, it forms a protostar—a young, hot, and dense object. The protostar continues to gather mass and becomes a main-sequence star, burning hydrogen in its core.

Once the hydrogen is exhausted, the star expands into a supergiant and starts fusing helium into heavier elements. Eventually, it undergoes a supernova explosion, releasing an enormous amount of energy and leaving behind a dense core known as a neutron star. This process showcases the incredible transformations that high-mass stars undergo throughout their life cycle.

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The molecular formula of fructose is C₆H₁₂O₆.

The molecular formula is derived in the following steps:

Step 1. the molality of the solution is determined first

Molality = Change in boiling point/Kb

Molality = (78.59 - 78.35)/1.2 = 0.2 molal

Step 2. Moles of solute is determined.

Moles of solute = molality * mass of solvent (kg)

moles = 0.2 * 0.325 = 0.065

Step 3. Molar mass of fructose = mass/moles

Molar mass of fructose = 11.7/0.065 = 180 g/mol

Step 4: Mole ratio of constituent elements

Carbon = 40% * 180/12 = 6

Hydrogen = 6.7% * 180/1 = 12

Oxygen = 53.3% * 180/16 = 6

Therefore, the molecular formula of fructose is C₆H₁₂O₆.

In conclusion, the molecular formula of fructose is derived from the molality of the solution.

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The three words which best describe the composition of the inner planets are rocky, solid, and dense.

A planet classified as an inner planet is one that is rocky, solid, and dense by nature, such as Mercury, Venus, Earth, and Mars. Inner planets are those that are nearest to the Sun.

There are two types of planets:

Based on astronomical information and records, there are two main types of planets :

The moons of the inner planets are either absent or limited to one (Earth) or two (Mars). The inner planets don't have any rings. The inner planets have shorter orbits around the Sun than the outer planets, but they all rotate more slowly.

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Answer:rocky soild and dense

Explanation:

Answer:

Adsorption is the adhesion of atoms, ions or molecules from a gas, liquid or dissolved solid to a surface. This process creates a film of the adsorbate on the surface of the adsorbent. This process differs from absorption, in which a fluid is dissolved by or permeates a liquid or solid.

while ,

Absorption is a physical or chemical phenomenon or a process in which atoms, molecules or ions enter some bulk phase – liquid or solid material. This is a different process from adsorption, since molecules undergoing absorption are taken up by the volume, not by the surface

[tex] \\ [/tex]

-,-

Wastewater can be treated using series of eight steps which would be clarified below.

Wastewater is the type of water that is used for four different purposes in homes,offices, industries and factories.

These wastewater contain human waste, food scraps, oils, soaps and chemicals which can be treated and reused through the following means:

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The number of molecules will depend on the molar mass of the compound.

According to Avogadro, 1 mole of any substance contains 6.022 x [tex]10^{23}[/tex].

To find the number of moles in a substance:

Mole = mass/molar mass.

In this case, we do not know the compound but we know the mass. Hence, we cannot know the molar mass.

Assuming the molar mass is X.

Mole = 84.7/X

Number of molecules in 84.7 grams of the compound =

              84.7/X x 6.022 x [tex]10^{23}[/tex] molecules.

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The Capillary effect means water can "climb" up thin tubes and water plants. This is due to the surface tension nature of water.

Hope this helps:)

The capillary effect means water can "climb" up thin tubes and water plants. This is due to the adhesive nature of water.

The capillary effect is a phenomenon where liquids, like water, can rise against gravity in narrow tubes or spaces, such as the stems of plants. This effect is possible due to the adhesive nature of water, which allows it to stick to the walls of the tube or surface it comes into contact with.

The cohesive forces between water molecules create a sort of "pull" that allows the water to climb up the tube, defying gravity. This property is essential for plants, as it helps them transport water and nutrients from their roots to their leaves and other parts of the plant, supporting their growth and survival.

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Answer:

38

Explanation:

that I believe is correct

The amount of Al required will be 15.77 grams

First, the equation of the reaction:

[tex]2Al +3 FeO -- > Al_2O_3 + 3Fe[/tex]

The mole ratio is 2:3.

Mole of 63.0 g of FeO = 63/71.84 = 0.8769 moles

Equivalent moles of Al = 0.8769 x 2/3 = 0.5846 moles

Mass of 0.5846 moles Al = 0.5846 x 26.98 = 15.77 grams

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Taking into account the reaction stoichiometry, 13.28 grams of Al is required to react with 63 grams of FeO.

In first place, the balanced reaction is:

2 Al + 3 FeO → 3 Fe + Al₂O₃

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: If by reaction stoichiometry 215.55 grams of FeO react with 54 grams of Al, 53 grams of FeO react with how much mass of Al?

[tex]mass of Al= \frac{53 grams of FeOx54 grams of Al}{215.55 grams of FeO}[/tex]

mass of Al= 13.28 grams

Finally, 13.28 grams of Al is required to react with 63 grams of FeO.

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Answer:

The bright side of the moon will become less and less and will eventually be covered in complete darkness :)

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Answer:

24.0 g C₃H₈

Explanation:

To find the mass of C₃H₈, you need to (1) convert grams CO/H₂ to moles CO/H₂ (via molar mass), then (2) convert moles CO/H₂ to moles C₃H₈ (via mole-to-mole ratio from reaction coefficients), and then (3) convert moles C₃H₈ to grams C₃H₈ (via molar mass). It is important to arrange the conversions/ratios in a way that allows for the cancellation of units (the desired unit should be in the numerator). The final answer should have 3 sig figs to reflect the sig figs in the given values.

Molar Mass (CO): 12.011 g/mol + 15.998 g/mol

Molar Mass (CO): 28.009 g/mol

Molar Mass (H₂): 2(1.008 g/mol)

Molar Mass (H₂): 2.016 g/mol

Molar Mass (C₃H₈): 3(12.011 g/mol) + 8(1.008 g/mol)

Molar Mass (C₃H₈): 44.097 g/mol

3 CO + 7 H₂ ----> 1 C₃H₈ + 3 H₂O
^           ^              ^

45.8 g CO           1 mole              1 mole C₃H₈          44.097 g
-----------------  x  ------------------  x  --------------------  x  ------------------  =
                           28.009 g           3 moles CO            1 mole

=  24.0 g C₃H₈

87.3 g H₂           1 mole           1 mole C₃H₈          44.097 g
----------------  x  ---------------  x  ---------------------  x  -----------------  =  
                          2.016 g           7 moles H₂             1 mole

=  273 g C₃H₈

It was necessary to find the mass of the products from both of the reactants because you did not know which one was the limiting reagent. The limiting reagent is the reactant which is completely used up first. Because CO produced the smaller amount of product, it must be the limiting reagent. Therefore, the actual amount of C₃H₈ produced is 24.0 grams.