The sequence 1/2, 7/6, 11/6, 5/2 is an arithmetic sequence
The given sequence is:
[tex]\frac{1}{2}, \frac{7}{6},\frac{11}{6},\frac{5}{2}........[/tex]
A sequence is an arithmetic sequence if it has a common difference d
In the given sequence:
[tex]T_1=\frac{1}{2} , T_2 = \frac{7}{6}, T_3=\frac{11}{6}, T_4=\frac{5}{2}[/tex]
[tex]T_2-T_1=\frac{7}{6}-\frac{1}{2} \\\\T_2-T_1=\frac{2}{3} \\\\T_3-T_2=\frac{11}{6}-\frac{7}{6} \\\\T_3-T_2=\frac{2}{3}[/tex]
Since the sequence has a common difference of 2/3, it is an arithmetic sequence
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The blueprint for Moreno's living room has a scale of 2 inches equals 3 feet. The family wants to use a scale of 1 inch equals 2 feet. What is the width of the living room on the new blueprint? (The width is 8)
Answer:
Part a) The scale of the new blueprint is
Part b) The width of the living room in the new blueprint is
Step-by-step explanation:
we know that
The scale of the original blueprint is
and
the width of the living room on the original blueprint is 6 inches
so
Find the actual width of the living room, using proportion
Find the actual length of the living room, using proportion
Find the scale of the new blueprint, divide the length of the living room on the new blueprint by the actual length of the living room
simplify
Find the width of the living room in the new blueprint, using proportion
P = x y . Find P when: x = 8 and y = − 11
Answer:
P= -88
Step-by-step explanation:
Since P=xy (Or x times y)
We can solve it since we know that x and y is: 8 and -11
So 8 times -11
Which is -88
Thus P= -88
Hope this helps!
Three cubes each of side 3 cm each are joined end to end. Find the surface area of the resultant solid.
Answer:
126 cm^2
Step-by-step explanation:
The surface area of one cube face is (3 cm)^2 = 9 cm^2.
Each cube has 6 faces, but joining them together hides 4 of the faces. The surface area of the resultant solid is ...
(6·3 -4)·(9 cm^2) = 126 cm^2
the graph of linear function g is shown on the grid
what is the zero of g
-6
-9
0
-5
Answer:
Option A, - 6
Step-by-step explanation:
The zero of a function is the value on the x-axis when y is 0
Answer:
the answer is -9
Step-by-step explanation:
the answer is -9 becaise
Which congruence criteria is met in the following scenario
HL
AAS
SAS
ASA
SSS
Answer: SAS
Because there is a mark showing that one pair of sides are congruent, the stars showing that one pair of angles are congruent, then the triangles are sharing a line (which means that they are congruent)
A man left 1⁄2 of his property to his wife 1/3 of the remainder to his eldest
son and the rest to be divided equally among his five younger children,
each of whom got p60,000. How much did his wife get?
Answer: p800,000
Step-by-step explanation:
1/2 to wife
1/3 to eldest son, and
Rest(x) to 5 youngest children
(1/2) + (1/3) + x = 1 [The sum of the shares will equal 1 estate]
(3/6) + (2/6) + x = 1
(5/6) + x = 1
x = (1/6); to be divided among the 5 youngest children
We find that each young child receives p60,000. That group of five received 5*(60,000) = p300,000, which represents (1/6) of the total estate (Estate).
We can write: (1/6)*(Estate) = p300,000
Estate = p1,800,000
The wife hauled in 1/2 of this, so she received p800,000.
Change one digit from the number 238882 so that it is divisible by 3 not not divisible by 2
Answer:
238882 -> 238881
Step-by-step explanation:
To make it not divisable by 2, you have to change the rightmost digit.
Simply divide the number by 3, round it, then multiply it by 3 again.
HELP!! Scaler multiplication of vectors in component form
Answers:
<-6,8> <-3,3> <12,12> <21,4> <18,22> <17,30> <-36,-38> <16,20>===========================================================
Work Shown:
Problem 1
u = <-3,4>
2u = 2*<-3,4>
2u = <2(-3), 2(4)>
2u = <-6,8>
Effectively, we multiplied each coordinate by 2.
-----------------
Problem 2
g = <-1,1>
3g = 3*<-1,1>
3g = <3(-1),3(1)>
3g = <-3,3>
Same idea as problem 1, but we tripled each coordinate.
-----------------
Problem 3
z = <-3,-3>
-4z = -4*<-3,-3>
-4z = <-4(-3),-4(-3)>
-4z = <12,12>
-----------------
Problem 4
v = <6,8>
2v = <12,16> .... double both coordinates
u = <-3,4>
3u = <-9,12> .... triple both coordinates
2v-3u = <12,16>-<-9,12>
2v-3u = <12-(-9),16-12>
2v-3u = <12+9,16-12>
2v-3u = <21,4>
I subtracted the corresponding coordinates.
The general rule is <a,b>-<c,d> = <a-c,b-d>
-----------------
Problem 5
y = <1,1>
6y = <6,6> .... multiply each coordinate by 6
v = <6,8>
2v = <12,16>
6y+2v = <6,6>+<12,16> = <6+12,6+16> = <18,22>
This time we add the corresponding coordinates after scaling up the given vectors.
The general rule is <a,b>+<c,d> = <a+c,b+d>
-----------------
Problem 6
u = <-3,4>
v = <6,8>
3v = <18,24>
y = <1,1>
2y = <2,2>
u+3v+2y = <-3,4>+<18,24>+<2,2>
u+3v+2y = <-3+18+2,4+24+2>
u+3v+2y = <17,30>
-----------------
Problem 7
g = <-1,1>
4g = <-4,4>
y = <1,1>
A = 4g+y = <-4,4>+<1,1> = <-4+1,4+1> = <-3,5>
z = <-3,-3>
v = <6,8>
5v = <30,40>
B = z-5v = <-3,-3> - <30,40> = <-3-30,-3-40> = <-33,-43>
A+B = <-3,5>+<-33,-43> = <-36,-38>
-----------------
Problem 8
u = <-3,4>
v = <6,8>
2v = <12,16>
A = u+2v = <-3,4>+<12,16> = <-3+12,4+16> = <9,20>
w = <8,-1>
g = <-1,1>
B = w+g = <8,-1>+<-1,1> = <8+(-1),-1+1> = <7,0>
A+B = <9,20>+<7,0> = <9+7,20+0> = <16,20>
Solve for r.
√2/3r + 1 = 23
Answer:
2nd option
Step-by-step explanation:
[tex]\frac{\sqrt{2} }{3}[/tex] r + 1 = 23 ( subtract 1 from both sides )
[tex]\frac{\sqrt{2} }{3}[/tex] r = 22 ( multiply both sides by 3 to clear the fraction )
[tex]\sqrt{2}[/tex] r = 66 ( divide both sides by [tex]\sqrt{2}[/tex] )
r = [tex]\frac{66}{\sqrt{2} }[/tex] × [tex]\frac{\sqrt{2} }{\sqrt{2} }[/tex] ( rationalising the denominator )
r = [tex]\frac{66\sqrt{2} }{2}[/tex] = 33[tex]\sqrt{2}[/tex]
Answer:
B) r=33*sqrt(2)
Step-by-step explanation:
sqrt(2)/3r+1=23
sqrt(2)/3r=23-1
sqrt(2)/3r=22
sqrt(2)r=22*3
sqrt(2)r=66
r=66/sqrt(2)
r=66*sqrt(2)/(sqrt(2)*sqrt(2))
r=(66*sqrt(2)/2
r=33*sqrt(2)
X=-2y,x-y=6 solve by substitution show all work
Answer:
y=-3
x=3
Step-by-step explanation:
x=-2y
x-y=9
substitute -2y for x in the second equation
you get:
-2y-y=9
combine like terms
-3y=9
divide by -3 on both sides
y=-3
It took Mr. Jefferson 20 minutes to ride the 5-mile path along the lake at a constant speed on his bike. Which equation below could be used to determine the number of miles, x, Mr. Jefferson could ride in 12 minutes at that same constant speed?
Answer:
Part A. 4x
Part B. Mr. Jefferson could ride 3 miles in 12 minutes
Step-by-step explanation:
Part A. 4 being the time it takes him to travel 1 mile and x being the number of miles rode.
Part B. To find the time it took him to travel each mile I divided 20 by 5 which gave me four. Then to find the miles he could ride in 12 minutes I divided 12 from 4 which gave me three, stating that he could travel 3 miles in 12 minutes.
__________________________________________________________
Hope this helps!!!
If I am incorrect, please tell me; I enjoy learning form my mistakes:)
Can you please factorise 7-x²
Answer:
Can't factorize with rational numbers
Step-by-step explanation:
The best you could do is [tex](\sqrt{7}+x)(\sqrt{7}-x)[/tex] but [tex]\sqrt{7}[/tex] is irrational.
Answer:
Step-by-step explanation:
7-x²
If we treat this as the difference of 2 squares we get
(√7 - x)(√7 + x)
7/11 x 7/15 x 3 multiply and write your answer as a fraction in the simplest form.
Answer: 49/55
7/11 x 7/15 x 3
49/165 * 3
147/165
49/55
Please answer fast this is due soon
Step-by-step explanation:
multiply the first equation by 1, the second by -1 and add.
x + 2y = -16
-x - 6y = 28
--------------------
0 - 4y = 12
-4y = 12
y = -3
x + 2×-3 = -16
x - 6 = -16
x = -10
1. x^2 + 6x + 8 = 0
2. x^2 + 10x + 21 + 0
3. X^2 + 9x + 18 = 0
Answer:
545256
Step-by-step explanation:
Question
Water is added or drained from a tank each day. The first day, 910 of a gallon is added to the empty tank. The second day, 710 of a gallon is drained from the tank. The third day, 810 of a gallon is added to the tank. The fourth day, 610 of a gallon is drained from the tank. The amount of water in the tank after 15 days is given by
910+(−710)+810+(−610)+⋯+310+(−110)+210.
How much water is in the tank after 15 days? Write your answer as a decimal.
Answer:
ililil
Step-by-step explanation:
Visualise the representation of 5.37(Bar over 7).
Using number line.
[tex] \: \: \: [/tex]
[tex] \pink{ 5.37}[/tex]
To visualize 5.37 more accurately, divide line segment between 5.37 and 5.38 in ten equal parts. 5.37 lies between 5.377 and 5.378.Again use divide above portion between 5.377 and 5.378 into 10 equal parts, which shows 5.37 is located closer to 5.3778 than to 5.3777 so we can get the answerhope it helpsWrite the equation 5x + 2y = -6 in general form.
Answer:
[tex]5x+2y+6=0[/tex]
Step-by-step explanation:
General equations are in the form [tex]Ax + By + C = 0[/tex]
So you can add 6 to both sides to make:
[tex]5x+2y+6=0[/tex]
Complete the proof(using sas congruence)! Use to sas congruence to prove that two angles are congruent
How i can answer this question
60m
How?
5m × 3m × 4m
5m × 3m = 15m
15m × 4m = 60m
Therefore
the answer is 60
Adelle solved the equation, 4x/7 - 6 = -20 , as shown.
Fill in the following blanks with the correct justification for each step.
Answer:
Step 1: Given
Step 2: Add 6 on both sides
Step 3: Multiply 7 on both sides
Step 4: Divide by 4 on both sides
The value of x for the given linear equation is -24.5.
What is linear equation in one variable?
The linear equations in one variable is an equation which is expressed in the form of ax + b = 0, where a and b are two integers, and x is a variable and has only one solution.
According to the given question
We have, a linear equation in one variable
[tex]\frac{4x}{7} -6=-20[/tex]
We solve the above equation in following steps
Step I : Adding 6 both the sides
[tex]\frac{4x}{7} = -20 + 6[/tex]
⇒[tex]\frac{4x}{7} = -14[/tex]
Step II: Multiply 7 both the sides
⇒ [tex]4x = -14[/tex] ×[tex]7[/tex]
⇒ [tex]4x = -98[/tex]
Step III: Dividing both the sides by 4
⇒ [tex]\frac{4x}{4} = -\frac{98}{4}[/tex]
⇒ [tex]x = -24.5[/tex]
Therefore, the value of x for the given linear equation is -24.5
Learn more about the linear equation in one variable here:
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A swim team with 41 members decided to buy T-shirts that cost $15.75 each. 3. ___
What was the cost of the 41 T-shirts?
What is 87 x (495 - 475) + 1084 - 864
Answer:
1960
Step-by-step explanation:
First, carry out the operation inside the parentheses: 495-475= 20. Next, follow the order of operations and do 87*20= 1740. Then, go from left to right, adding 1740 + 1084= 2824. Now, subtract all of that by 864. 2824-864= 1960.
HELP! Rechal can play 8 instruments and Sarina can play 1/4 LESS than that. How many instruments can Sarina play?
8*1/4=2
sarina can play 2 instruments
Answer:
2
Step-by-step explanation:
8 divided by 4 is 2
1/4 of 8 is 2
Don’t answer just for points please !! I really need help~
This is going to take a while: get ready...
I like two-columns, so...
Statements_______________|_____Reasons___
l||m Given
angle 1 congruent angle 7 Given
angle 3 congruent angle 5 corresponding alternate angles
a||b CPCTC
I usually do proofs for triangles, not parallel lines, but I hope this helped!
7-3x=2x-8, How do you solved for x?
Answer:
x = 3
Step-by-step explanation:
7- 3x = 2x - 8
7 = 5x - 8 Add 3x on both sides
15 = 5x Add 8 on both sides
3 = x Divide both sides by 5
The cost of 2.25
pounds of grapes is
$6.75. The cost of 5
pounds of grapes is
$15. Find the slope in
dollars per pound.
Answer:
Hope this helps! <3
Step-by-step explanation:
The slope or increase in cost per pound is 3. (1 pound of grapes costs $3)
The admission fee to an amusement park is $28. It costs an additional p dollars to rent a locker to hold your belongings. The total cost for 5 people to enter the amusement park and each rent a locker is $180.How much does it cost for one person to rent a locker
Answer: 1040
Step-by-step explanation: 180+28=208
208 times 5 = 1040
James has $7.60 in nickels and quarters. He has 4 fewer nickels than quarters. How many of each coin does he have?
A print shop at a community college in Cupertino, California, employs two different contractors to maintain its copying machines. The print shop needs to have 12 IBM, 18 Xerox, and 20 Canon copying machines serviced. Contractor A can repair 2 IBM, 1 Xerox, and 2 Canon machines at a cost of $800 per month, while Contractor B can repair 1 IBM, 3 Xerox, and 2 Canon machines at a cost of $1000 per month. What is the minimum cost to employ the contractors? Round your answer to the nearest whole number. Do not include a dollar sign or comma in your answer.
The cost to employ the contractors is $11250
The general cost to employ someone is between 1.25 and 1.40 of their real wage. This means the real wage is lower than the cost to employ that person.
Moreover, to determine the cost to employ the contractors, we need to determine their total wage:
Contractor A: $800 (Includes the repairment of 2 IBM, 1 Xerox, and 2 Canon machines).Contractor B: $1000 (Includes the repairment of 1 IBM, 3 Xerox, and 2 Canon machines.Total: $1800 to repair 3 IBM, 4 Xerox, and 4 Canon machinesTotal machines to be repaired: 12 IBM, 18 Xerox, 20 Canon machines.Now, for all the machines to be repaired you will need to pay a total of $9000
$1800 x 5 = $ 9000 (Includes the repairment of 15 IBM, 20 Xerox, and 20 Canon machines, which will cover all the machines you need).Finally, let's find out the cost using the minimum rate.
$9000 x 1.25 = $11,250
Learn more about general cost in: https://brainly.com/question/3902215
Answer:
$8800
Step-by-step explanation:
Let x be the number of months contract A is employed and let y be the number of months contractor B is employed. Since we are trying to minimize cost, our objective function represents the total cost to employ contractor A and contract B. This function is defined by
C(x,y)=800x+1000y
The first constraint is that the company needs to have 12 IBM copying machines serviced and we know that contractor A can repair 2 IBM copying machines and contractor B can repair 1 IBM copying machines. This translates into the following inequality.
2x+y≥12
The second constraint is that the company needs 18 Xerox copying machines serviced and we know that contractor A can repair 1 Xerox copy machines while contractor B can repair 3 Xerox copy machines. This translates into the following inequality.
x+3y≥18
The third constraint is that the company needs 20 Canon copying machines serviced and we know that contractor A and contractor B can repair 2 Canon copy machines each. This translates into the following inequality.
2x+2y≥20
The fact that x and y must be positive numbers is represented by the following two constraints:
x≥0,y≥0
Using all of this information, our problem is as follows.
Minimize: C(x,y)=800x+1000y
Subject to: 2x+y≥12
x+3y≥18
2x+2y≥20
x≥0
y≥0
The corner points are:
(0,12),(18,0),(2,8),(6,4)
The point (6,4) gives lowest cost: $8800