Determine, to the nearest tenth of a year, how long it would taken an investment to double at a 3 3/4% interest rate, compounded continuously

Answer:

10

Step-by-step explanation:

Using the distance formula,

[tex] \sqrt{ {( - 2 - ( - 8))}^{2} + { (- 4 - 4)}^{2} } = 10[/tex]

Answer:

Kelly has read more of the book

Answer:

A.

Step-by-step explanation:

1.5m + 6.5q > 100

✨♥️

Answer:

E 150

Step-by-step explanation:

The coordinates of the mid - point of the line AB is (-1, -5).

A midpoint is a point that divides a given line into two equal parts.

Given is that AB has endpoints at A(4, -8) and B(-6, -2). It is asked to find the coordinates of the midpoint of AB.

We can write the coordinates of the midpoint of AB as -

{x} = (x₁ + x₂)/2

{x} = (4 - 6)/2

{x} = - 2/2

{x} = -1

{y} = (y₁ + y₂)/2

{y} = (-8 - 2)/2

{y} = - 10/2

{y} = - 5

Therefore, the coordinates of the mid - point of the line AB is (-1, -5).

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Well, let's use the Euclidean algorithm:

164 = 4×37 + 16

37 = 2×16 + 5

16 = 3×5 + 1

Then working backwards,

1 = 16 - 3×5

1 = 16 - 3×(37 - 2×16) = 7×16 - 3×37

1 = 7×(164 - 4×37) - 3×37 = 7×164 - 31×37

so that x = 7 and y = -31.

Answer:

Alice

Step-by-step explanation:

14$ the amount he had - X the amount he lost (the unknown) is what is described by Alice

=========================================================

Explanation:

Points Q and R have the same y coordinate of 6.

This means they're on the same horizontal level and we can form a number line through these points. Think of Q and R being on the x axis.

Going from -4 to 8 is a distance of 12 units because either

-4-8 = -12 which flips to +12 or 12

8-(-4) = 8+4 = 12

Effectively I used absolute value for the first part to go from -12 to 12. Distance cannot be negative.

Alternatively, you can count out the number of horizontal spaces from -4 to 8 and you should count out 12 units.

--------------------------------

If you need to use the distance formula, then this is what the steps may look like:

[tex]Q = (x_1,y_1) = (-4,6) \text{ and } R = (x_2, y_2) = (8,6)\\\\d = \sqrt{(x_1 - x_2)^2 + (y_1 - y_2)^2}\\\\d = \sqrt{(-4-8)^2 + (6-6)^2}\\\\d = \sqrt{(-12)^2 + (0)^2}\\\\d = \sqrt{144 + 0}\\\\d = \sqrt{144}\\\\d = 12\\\\[/tex]

In my opinion, the distance formula is overkill because we can simply apply subtraction or count out the number of spaces. It's up to you which you prefer you like better. Of course be sure to follow all instructions your teacher mentions.

If the two points weren't on the same horizontal level, then we would have no choice and have to use the distance formula. Or you could use the pythagorean theorem which is effectively what the distance formula is derived from.

Answer:

[tex]x = 2, y = -1[/tex]

Step-by-step explanation:

We can add the 2 equations together to solve for y.

[tex](-3x + 5y) + (3x + 7y) = (-11) + (-1)\\-3x + 3x + 5y + 7y = -11 -1\\12y = -12\\y = -1[/tex]

Now we can solve for x by substituting y in one of the original equations.

[tex]3x + 7y = -1\\3x + 7(-1) = -1\\3x - 7 = -1\\3x = 6\\x = 2[/tex]

Those are the answers

- Kan Academy Advanced

The products of the polynomials are:

To do this, we multiply each pair of polynomial as follows:

Pair 1: (xy + 9y + 2) and (xy – 3)

(xy + 9y + 2) * (xy - 3)

Expand

(xy + 9y + 2) * (xy - 3) = x²y² - 3xy + 9xy² - 27y + 2xy - 6

Evaluate the like terms

(xy + 9y + 2) * (xy - 3) = x²y² - xy + 9xy² - 27y - 6

Pair 2: (2xy + x + y) and (3xy² - y)

(2xy + x + y) * (3xy² - y)

Expand

(2xy + x + y) * (3xy² - y) = 6x²y³ - 2xy² + 3x²y² -xy + 3xy³- y²

Pair 3: (x – y) and (x + 3y)

(x - y) * (x + 3y)

Expand

(x - y) * (x + 3y) = x² + 3xy - yx + 3y²

Evaluate the like terms

(x - y) * (x + 3y) = x² + 2xy + 3y²

Pair 4: (xy + 3x + 2) and (xy – 9)

(xy + 3x + 2) * (xy – 9)

Expand

(xy + 3x + 2) * (xy – 9)  = x²y² - 9xy + 3x²y - 27x + 2xy - 18

Evaluate the like terms

(xy + 3x + 2) * (xy – 9)  = x²y² - 7xy + 3x²y - 27x  - 18

Pair 5: (x² + 3xy - 2) and (xy + 3)

(x² + 3xy - 2) * (xy + 3)

Expand

(x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 9xy - 2xy - 6

Evaluate the like terms

(x² + 3xy - 2) * (xy + 3)  = x³y + 3x² + 3x²y² + 7xy - 6

Pair 6: (x + 3y) and (x – 3y)

(x + 3y) * (x – 3y)

Apply the difference of two squares

(x + 3y) * (x – 3y) = x² - 9y²

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Answer:

y=-15x+100

Step-by-step explanation:

Answer:

5.7 and 4.2

Step-by-step explanation:

Outside diagonal = √a² + a² = √4² + 4² = 4√2

= 5.7

Inside diagonal = √b² + b² = √3² + 3² = 3√2

= 4.2

Answer:

-4.25

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer: 123 boxes

Step-by-step explanation:

Find how many nails she used.

692-200=492

she used 492 nails

we know that 4 nails are needed to set up a box

so we divide.

492/4=123

Sally set up 123 boxes

Answer:

the unit cost per rubber tile is $$$$$$$$$$$$$6

Step-by-step explanation:

..

Answer:

132.84 is the answer as volume is area times length

Answer:

[tex]\underline{\boxed{\sf{2(x - 11)(x + 11)}}}[/tex]

Step-by-step explanation:

[tex]\sf{2x^2 - 242}[/tex]

Common factor :

[tex]\sf{2x^2 - 242}[/tex]

[tex]\sf{2(x^2 - 121)}[/tex]

[tex] \: \: \: \: \: \: \: \: \: \: \: \: [/tex]

Use the sum-product pattern :

[tex]\sf{2(x^2-121)}[/tex]

[tex]\sf{2(x^2 + 11x-11x - 121)}[/tex]

[tex]\: \: \: \: \: \: \: \: \: \: \: \: [/tex]

Common factor from the two pairs :

[tex]\sf{2(x^2 + 11x-11x - 121)}[/tex]

[tex]\sf{2(x(x+11) -11(x + 11))}[/tex]

[tex]\: \: \: \: \: \: \: \: \: \: \: \: [/tex]

Rewrite in factored form :

[tex]\sf{2(x(x+11)- 11(x + 11))}[/tex]

[tex]\sf{2(x - 11)(x + 11)}[/tex]

[tex]\: \: \: \: \: \: \: \: \: \: \: \: [/tex]

Solution :

[tex]\sf{2(x - 11)(x + 11)}[/tex]

Answer:

point B

Step-by-step explanation:

Answer:

It's Point B.

Go to 5 on the x-axis and then go up 3

The 5 is the x-axis and 3 is the y-axis

The amount that Theresa was charged in interest for the billing cycle is $5.30

By using the average daily balance, the amount will be:

= (350 × 12) + (520 × 19) / (12 + 19)

= (4200 + 9880)/31

= 454.19

Therefore, the interest will be:

= (454 × 0.14)/12

= $5.30

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Answer:

64in

Step-by-step explanation:

for a four sided figure, you do base x height. volume isn't squared in Math.

Answer:

V = 3053.63 mm^3

Step-by-step explanation:

radius : 9mm

V = 4/3 * pi * r^3

V = 4/3 * (3.1415926535898...) * 9^3

V = 3053.63 mm^3

Answer:

GCF=3[tex]x^{2}y[/tex]

Step-by-step explanation:

First, take a look at the numbers.

GCF of 15 and -18 = 3

Then, look at the variables.

GCF of (x^2)(y^3) and (x^3)(y)(z) = (x^2)(y)

Lastly, combine the two expressions

GCF = 3(x^2)(y)

Answer: 3(x^2)(y)

Hope this helps!

Answer:

x = 3

Step-by-step explanation:

the midsegment XW is half the sum of the parallel bases , that is

7x + 10 = [tex]\frac{1}{2}[/tex] (46 + 16 ) = [tex]\frac{1}{2}[/tex] × 62 = 31 ( subtract 10 from both sides )

7x = 21 ( divide both sides by 7 )

x = 3

The equations of the graphed line and function can be written as:

f(x) = 1/2x + 2

y - 3 = 1/2(x - 2)

y - 1 = 0.5(x + 2)

Equation of a graphed line can be expressed in:

Slope-intercept form as y = mx + b, where m = slope, b = y-intercept; or

Point-slope form as y - b = m(x - a), where (a, b) is a point and m = slope.

Find the slope (m) of the line:

Slope (m) = change in y / change in x = 1/2 = 0.5

y-intercept (b) = 2

To express the graphed line in slope-intercept form, substitute m = 1/2 and b = 2 into f(x) = mx + b:

f(x) = 1/2x + 2.

Using the point-slope form, write the equation by substituting m = 1/2 and (a, b) = (2, 3) into y - b = m(x - a):

y - 3 = 1/2(x - 2)

Or substitute m = 0.5 and (a, b) = (-2, 1) into y - b = m(x - a):

y - 1 = 0.5(x - (-2))

y - 1 = 0.5(x + 2)

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Add all the females together: 3 + 4 + 6 + 3 = 16

Female seniors = 3

Probability of picking a senior = 3/16 = 0.1875 x 100 = 18.75%

Rounded to the nearest whole number = 19%

Answer: 19%

Check the picture below.  so, that'd be the triangle's sides hmmm so let's use Heron's Area formula for it.

[tex]~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill~ \\\\[-0.35em] ~\dotfill\\\\ (\stackrel{x_1}{10}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{15}~,~\stackrel{y_2}{15}) ~\hfill a=\sqrt{[ 15- 10]^2 + [ 15- 5]^2} \\\\\\ ~\hfill \boxed{a=\sqrt{125}} \\\\\\ (\stackrel{x_1}{15}~,~\stackrel{y_1}{15})\qquad (\stackrel{x_2}{30}~,~\stackrel{y_2}{9}) ~\hfill b=\sqrt{[ 30- 15]^2 + [ 9- 15]^2} \\\\\\ ~\hfill \boxed{b=\sqrt{261}}[/tex]

[tex](\stackrel{x_1}{30}~,~\stackrel{y_1}{9})\qquad (\stackrel{x_2}{10}~,~\stackrel{y_2}{5}) ~\hfill c=\sqrt{[ 10- 30]^2 + [ 5- 9]^2} \\\\\\ ~\hfill \boxed{c=\sqrt{416}} \\\\[-0.35em] ~\dotfill[/tex]

[tex]\qquad \textit{Heron's area formula} \\\\ A=\sqrt{s(s-a)(s-b)(s-c)}\qquad \begin{cases} s=\frac{a+b+c}{2}\\[-0.5em] \hrulefill\\ a=\sqrt{125}\\ b=\sqrt{261}\\ c=\sqrt{416}\\ s\approx 23.87 \end{cases} \\\\\\ A\approx\sqrt{23.87(23.87-\sqrt{125})(23.87-\sqrt{261})(23.87-\sqrt{416})}\implies \boxed{A\approx 90}[/tex]

Answer:

0.267

Step-by-step explanation:

4/15 as a decimal is 0.26 repeating so rounded to the nearest thousandth would be 0.267

Answer:

.35 < 38% < 3/5

Step-by-step explanation:

.35 is the same as 35 percent which is less than 38, and 3/5 when divides is .60 turned into percent is 60 percent

Answer:

38% is your answer boss. hope that helps :)

The percentage of people who supported the home team is 38 %

What is an Equation?

Equations are mathematical statements with two algebraic expressions flanking the equals (=) sign on either side.

It demonstrates the equality of the relationship between the expressions printed on the left and right sides.

Coefficients, variables, operators, constants, terms, expressions, and the equal to sign are some of the components of an equation. The "=" sign and terms on both sides must always be present when writing an equation.

Given data ,

The total number of people attending the baseball game = 3500 people

The number of people supporting the home team = 1300 people

The number of people supporting the visiting team is = 2170

Now , the equation will be

The percentage of people supporting the home team is = number of people supporting the home team / total number of people attending the baseball game

Now , the equation will be

The percentage of people supporting the home team is A = ( 1300 / 3500 ) x 100

The percentage of people supporting the home team is A = 0.38 x 100

The percentage of people supporting the home team is A = 38 %

Therefore , the value of A is 38 %

Hence , The percentage of people who supported the home team is 38 %

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