Determine the volume (in mL) of water that needs to be added to 50.0 mL of a 0.600 M LiBr to produce a 0.145 M solution. Assume the volumes are additive.

The components MaVa=MbVb is utilized in this

dilution problem. The preliminary 50.00 mL

answer desires to be diluted from 0.six hundred M to 0.145 M through the addition of 0.597 mL.

The components MaVa-MbVb is used

Ma = 0.6M

V_ = 50ml

Mb = 0.145M

Vb = (50 + Xml)

MaVa = MbVb

(0.six hundred)(50.00)=(0.one hundred forty five)(50.00+X)

30 - 0.one hundred forty five = (50 + x)

29.85/50 = X

X = 0.597 ml.

Dilution has no impact at the solute attention in an answer. The moles of the solute do now no longer alternate while a solvent is introduced to an answer, however the attention of the answer (in molarity and in all different units) and its quantity do. Taking an answer of better attention and step by step including water till the favored attention is acquired is an average approach for growing an answer of a particular attention. This method is called.

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A carbon atom has a relative atomic mass of
13.3. 60% of the carbon atom has a mass
number of 12.7, 30% of the carbon atom has a
mass number of 13.6, whilst the remaining 10%
has a mass number which is not known.
Calculate the mass number of the carbon isotope
which is 10% of the Carbon 13.3 atom.
Give your answer to 1 decimal place.