Determine the maximum thickness of an aluminium sheet in which a 50 mm diameter hole is to be punched, if the compressive stress in the punch is not to exceed 80 MPa.

Determine The Maximum Thickness Of An Aluminium Sheet In Which A 50 Mm Diameter Hole Is To Be Punched,

Answers

Answer 1

Answer:

Area of punch = π * (diameter/2)^2

= π * (50/2)^2

= π * 25^2

= 1962.5 mm^2

The maximum compressive stress that the punch can withstand is 80 MPa. The thickness of the aluminium sheet can then be calculated using the following equation:

Stress = Force / Area

= (Force/Area) * (Thickness/Thickness)

= (80 MPa) * (Thickness/1962.5 mm^2)

Solving for thickness, we get:

Thickness = (80 MPa * 1962.5 mm^2) / 1

= 15700 mm

= 15.7 meters

Therefore, the maximum thickness of the aluminium sheet in which a 50 mm diameter hole can be punched without exceeding a compressive stress of 80 MPa is approximately 15.7 meters.


Related Questions

What is the objective of a network eavesdropping attack?

A.
to monitor traffic on the network as part of network administration
B.
to identify network vulnerabilities and fix them
C.
to identify the computers on which sensitive information resides
D.
to gain access to confidential information

Answers

NETWORK EAVESDROPPING

The objective of a network eavesdropping attack is to gain access to confidential information (D).

Network eavesdropping, also known as "sniffing," is the practice of intercepting and monitoring data transmitted over a network. It is typically done with the intention of stealing sensitive information, such as passwords, login credentials, or other confidential data.

In a network eavesdropping attack, an attacker may use specialized software or hardware to capture and analyze data transmitted over the network. The attacker may be looking for specific types of data, such as financial information or intellectual property, or may simply be trying to gather as much information as possible.

Option A, monitoring traffic on the network as part of network administration, is not the primary objective of a network eavesdropping attack.

Option B, identifying network vulnerabilities and fixing them, is not an accurate description of network eavesdropping.

Option C, identifying the computers on which sensitive information resides, may be a secondary objective of a network eavesdropping attack, but it is not the primary objective.

Hope This Helps You!

2. What is the maximum pressure that can be used when popping beads? OA. 25 psi OB. 35 psi LOC. 45 psi OD. 55 psi​

Answers

The maximum pressure that can be applied during popping beads is     35 psi LOC.

What makes a tire incapable of repair?

The tire cannot be repaired if the shoulder or sidewall have holes or other damage. The tire must be scrapped if the injuries are near enough together that the repairs would overlap or if they are straight across from one another.

How much tire pressure should I use?

Your tires have a tire pressure marking on the sidewall, but this is not the recommended tire pressure; rather, it is the maximum. The maximum pounds per square inch pressure, for instance, that your tire can withstand in order to hold the weight of its maximum load-bearing capability is indicated.

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Which of the following set of numbers belongs to the interval [7,9]

Answers

A group of real numbers called an interval are all real numbers that fall between two real numbers. Depending on whether, the endpoints should be included or excluded.

An interval set is what?

A set of all real numbers between a given pair of numbers is known as an interval. It might also be considered as a section of the actual number line. Any one of the two locations that designate the end of the line segment is an endpoint of an interval.

What is a range of numbers?

All actual values between those two are included in this range. The class interval is calculated by subtracting the class's lower limit from the upper bound. The following is the formula for the class interval: Upper limit - Lower limit equals the class interval.

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The complete question is -

Which of the following set of numbers belongs to the interval of the number [7,9] ?

Which type of large-sized asbestos operations, over 25 linear feet or 10 square feet in size, require a regulated area, an equipment room, a shower area, and a clean changing room? A. Class I B. Class II C. Class III D. Class IV

Answers

The type of large-sized asbestos operations, over 25 linear feet or 10 square feet in size, that require a regulated area, an equipment room, a shower area, and a clean changing room is option  C. Class III

What is the asbestos operations about?

Class I operations, which involve the removal of thermal system insulation or surfacing ACM, do not typically require a regulated area, an equipment room, a shower area, or a clean changing room. However, they may require certain protective measures to be taken, such as the use of respiratory protection and protective clothing.

Note that Class III asbestos operations, which involve the removal of asbestos-containing materials (ACM) from structures and equipment in a regulated area, require a regulated area, an equipment room, a shower area, and a clean changing room. Class III operations are defined as those that involve the removal of ACM that is over 25 linear feet or 10 square feet in size.

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Write a method that starts with 2 strings. If one string is odd and the other string is even then it will place the odd string in the middle of the even string. But if both Strings are of odd length then it will concatenate the first letter of the first string with the LAST letter of the second string. And finally, if the strings are both of Even length then it will take the first half of the first string and concatenate it with the second half on the second string.

Answers

Here is an example of a Python function that implements the logic you described:

Copy code

def string_manipulation(string1, string2):

if len(string1) % 2 != 0 and len(string2) % 2 == 0:

return string2[:len(string2)//2] + string1 + string2[len(string2)//2:]

elif len(string1) % 2 == 0 and len(string2) % 2 != 0:

return string1[:len(string1)//2] + string2 + string1[len(string1)//2:]

elif len(string1) % 2 != 0 and len(string2) % 2 != 0:

return string1[0] + string2[-1]

else:

return string1[:len(string1)//2] + string2[len(string2)//2:]

You can call this function and pass in the two strings as arguments, like this:

Copy code

string1 = "hello"

string2 = "world"

result = string_manipulation(string1, string2)

print(result)

You can also modify the function to print some debugging statements to better understand how the code is executing, or add more test cases, if you want to further debug it.

Uday Tahlan

_(what)_ cutting is a hand cutting technique that requires holding a torch at a slight
angle and keeping the torch in contact with the workpiece as a cut is made.
od to as

Answers

Drag cutting is the practice of cutting metal by dragging the plasma cutter's torch tip along the workpiece. The primary advantages of drag cutting are Because you don't need to keep a certain distance between the cutting tip.

What is a plasma cutter for drag cutting?

Metal is shaped with drag tips during the plasma cutting process known as drag cutting. This technique offers greater control than others like stand-off cuts and is typically used for thin metals like sheets. Additionally, the procedure produces a burr- and irregularity-free edge that is smooth.

Which two types of plasma cutters are there?

Conventional and Precision plasma systems make up the majority of plasma cutting systems. Typical shop air is used as the plasma gas in conventional plasma systems, and the torch's nozzle determines the form of the arc.

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