Determine the form of a particular solution to the differential equations. Do not solve. (a) x" — x' – 2x = e^t cost – t^2 + cos 3t (b) y" – y' + 2y = (2x + 1)e^(x/2) cos (√7/2)x + 3(x^3 – x)e^(x/2) sin (√7/2) x

Part A :f has relative maxima at x = 1 and x = 3, and a relative minimum at x = 8, on the interval [0, 9].

Part B: the graph of f is concave up on the intervals (−∞, 1) and (8, ∞) and is concave down on the interval (1, 8).

Part C: x = 1 and x = 8 these are the points of inflection of f.

To find relative extrema, we want to find the basic places of the capability and afterward decide if they are greatest or least by really looking at the indication of the subsequent subordinate.

The point is a relative minimum when the second derivative is positive, and it is a relative maximum when the second derivative is negative. To determine the nature of the critical point, we must employ alternative strategies if the second derivative is zero.

Part A:

The values of x at which f'(x) is zero or undefined are the critical points of f. From the table, we see that f'(x) = 0 at x = 1 and x = 8, and f'(x) is unclear at x = 3.

At each critical point, we must now examine the sign of the second derivative to determine whether it is a maximum or a minimum.

Negative f''(1) = -2 is the case when x = 1. As a result, the relative maximum is the critical point at x = 1.

Because f''(3) is not defined, the second derivative test cannot be used to determine the nature of the critical point at x = 3. However, as the table demonstrates, f shifts from increasing to decreasing at x = 3, indicating that x = 3 is the relative maximum.

We have a positive value of f'(8) = 2 when x = 8. As a result, the relative minimum at x = 8 is the critical point.

Therefore, f has relative maxima at x = 1 and x = 3, and a relative minimum at x = 8, on the interval [0, 9].

Part B:

To determine where the graph of f is concave up and where it is concave down, we need to find the intervals where f''(x) > 0 and where f''(x) < 0, respectively.

From the table, we see that f''(x) > 0 for x < 1 and for x > 8, and f''(x) < 0 for 1 < x < 8. Therefore, the graph of f is concave up on the intervals (−∞, 1) and (8, ∞) and is concave down on the interval (1, 8).

Part C:

We must determine the values of x at the points on the graph where the concavity changes in order to locate any points of inflection of f. From part B, we see that the concavity changes at x = 1 and x = 8. Accordingly, these are the marks of expression of f.

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We cannot conclude that the Hessian matrix of f at (0,0) is necessarily negative definite.

False.

The Hessian matrix of a function f(x,y) at a critical point (a,b) is the matrix of second-order partial derivatives evaluated at (a,b). In this case, the Hessian matrix of f at (0,0) is:

H = [f_xx(0,0) f_xy(0,0)]

[f_xy(0,0) f_yy(0,0)]

Since f has a local maximum at (0,0), we know that f_x(0,0) = f_y(0,0) = 0, and that the leading term of f in the Taylor expansion around (0,0) is negative (because it's a local maximum). However, this information alone is not enough to determine the sign of the Hessian matrix.

For example, consider the function f(x,y) = -x^4 - y^4. This function has a local maximum at (0,0), and its Hessian matrix at (0,0) is:

H = [-12 0]

[ 0 -12]

This matrix is negative definite (i.e., it has negative eigenvalues), but there are also examples where the Hessian matrix is positive definite or indefinite. Therefore, we cannot conclude that the Hessian matrix of f at (0,0) is necessarily negative definite.

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G is non-planar as embedded in 3-dimensional space and it is not possible for a planar graph to have more than 2 faces that are not unbounded.

There are 5 homeomorphism classes of trees on 8 vertices:

Now, let's consider the graph G defined as follows:

V = {all 2-sets of [5]}

E = {(x,y) | x and y are adjacent iff x ∩ y = ∅}

To show that G is not planar, we will use Kuratowski's Theorem and the Euler identity.

(1) Kuratowski's Theorem:

A graph is non-planar if and only if it contains a subgraph that is a subdivision of K5 (the complete graph on 5 vertices) or K3,3 (the complete bipartite graph on 6 vertices with 3 vertices in each partition).

To show that G is non-planar using Kuratowski's Theorem, we need to find a subgraph of G that is a subdivision of K5 or K3,3. We can do this by considering the vertices of G as the sets {1,2}, {1,3}, {1,4}, {1,5}, {2,3}, {2,4}, {2,5}, {3,4}, {3,5}, and {4,5}. Now, we can construct a subgraph of G that is a subdivision of K5 as follows:

The resulting subgraph is a subdivision of K5, which means that G is non-planar.

(2) Euler identity:

In a planar graph, the number of vertices (n), edges (e), and faces (f) satisfy the identity n - e + f = 2.

To show that G is non-planar using the Euler identity, we need to find a contradiction in the identity. We can do this by counting the number of vertices, edges, and faces in G. G has 10 vertices and each vertex is adjacent to 8 other vertices, so there are a total of 40 edges in G. We can then use Euler's identity to calculate the number of faces:

[tex]n - e + f = 2\\10 - 40 + f = 2\\f = 32[/tex]

This means that G has 32 faces. However, this is a contradiction since G is a planar graph embedded in 3-dimensional space and it is not possible for a planar graph to have more than 2 faces that are not unbounded. Therefore, G is non-planar.

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The partial fraction decomposition of the integrand for the integral of x² - 2x - 1 / (x - 3)²(x² + 9) dx is of the form: A / (x - 3) + B / (x - 3)² + (Cx + D) / (x² + 9), where A, B, C, and D are constants.

First, factorize the denominator: (x - 3)²(x² + 9). This gives us three distinct linear factors: (x - 3), (x - 3), and (x² + 9).

Write the partial fraction decomposition using the distinct linear factors as denominators. In this case, we have two (x - 3) terms and one (x² + 9) term:

x² - 2x - 1 / (x - 3)²(x² + 9) = A / (x - 3) + B / (x - 3)² + (Cx + D) / (x² + 9).

Multiply both sides of the equation by the common denominator (x - 3)²(x² + 9) to eliminate the denominators.

Simplify the numerators and equate the corresponding coefficients on both sides of the equation.

Solve the resulting system of equations to find the values of A, B, C, and D.

Substitute the values of A, B, C, and D back into the original partial fraction decomposition.

Therefore, the partial fraction decomposition of the integrand for the given integral is: A / (x - 3) + B / (x - 3)² + (Cx + D) / (x² + 9), where A, B, C, and D are constants

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The answer of the given question based on the differential equation,  the answer is (C) 20,885.

A differential equation is equation that involves derivatives or differentials of unknown function. These equations describe how aquantity changes over time, space or some other variable. They are used to model a wide variety of phenomena in physics, engineering, biology, economics, and many other fields.

We are given the differential equation:

dy/dt = 0.4y

Utilising the separation of variables, we can resolve this.

dy/y = 0.4 dt

Integrating both sides:

ln|y| = 0.4t + C

where C is the constant of integration. To find C, we use the initial condition that the colony initially had 2000 bacteria, so when t = 0, y = 2000.

ln|2000| = 0 + C

C = ln|2000|

So the equation becomes:

ln|y| = 0.4t + ln|2000|

Simplifying, we get:

|y| = [tex]e^{(0.4t+ln|2000|)}[/tex] = [tex]2000e^{(0.4t)}[/tex]

Since the population of bacteria cannot be negative, we can drop the absolute value signs.

So, the solution to the differential equation is:

[tex]y = 2000e^{(0.4t)}[/tex]

To find the approximate number of bacteria at time t=7, we substitute t=7 into the equation:

[tex]y = 2000e^{(0.4(7)) }[/tex] = 20,885

Consequently, 20,885 bacteria are present at time t=7, which is a rough estimate.

So, the answer is (C) 20,885.

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a,b. We are given that the amount of time spent by North American adults watching television per day follows a normal distribution with mean μ = 6 hours and standard deviation σ = 1.5 hours.

c. Therefore, the probability that all five North American adults in the sample watch television for more than 7 hours per day is approximately 0.00001.

a. We need to find P(X > 7), where X is the random variable representing the amount of time spent watching TV. Using the standard normal distribution, we can standardize X as follows:

Z = (X - μ) / σ = (7 - 6) / 1.5 = 0.67

b. Using a standard normal table or calculator, we can find P(Z > 0.67) ≈ 0.2514. Therefore, the probability that a randomly selected North American adult watches television for more than 7 hours per day is approximately 0.2514.

c. We need to find:[tex]P(X_1 > 7 AND X_2 > 7 AND X_3 > 7 AND X_4 > 7 AND X_5 > 7)[/tex],

where [tex]X_1, X_2, X_3, X_4, & X_5[/tex] are the random variables representing the amount of time spent watching TV by each individual in the sample. Since the TV-watching times are independent and identically distributed, we have:

[tex]P(X_1 > 7 AND X_2 > 7 AND X_3 > 7 AND X_4 > 7 AND X_5 > 7) = P(X > 7)^5[/tex]

Using the value of P(X > 7) from part (a), we get:

[tex]P(X_1 > 7 AND X_2 > 7 AND X_3 > 7 AND X_4 > 7 AND X_5 > 7)[/tex] ≈ 0.2514^5 ≈ 0.00001

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There are 7,210,800 lattice paths from (0,0) to (17,15) through (7,5) calculated using the principle of inclusion-exclusion.

To begin with, we number the number of cross-section ways from (0,0) to (17,15) without any limitations. To do this, we have to take add up to 17 steps to the proper and 15 steps up, for a add up to 32 steps.

We will speak to each step by an R or U (for right or up), and so the issue decreases to checking the number of stages of 17 R's and 15 U's. This will be calculated as:

(32 select 15) = 8,008,015

Next, we check the number of grid ways from (0,0) to (7,5) and from (7,5) to (17,15). To tally the number of ways from (0,0) to (7,5), we have to take add up to 7 steps to the proper and 5 steps up, to add up to 12 steps.

The number of such ways is (12 select 5) = 792. To check the number of ways from (7,5) to (17,15), we have to take add up to 10 steps to the proper and 10 steps up, to add up to 20 steps.

The number of such ways is (20 select 10) = 184,756.

In any case, we have double-counted the ways that pass through (7,5).

To adjust for this, subtract the number of paths from (0,0) to (7.5) that pass through (7.5) and the number of paths from (7.5) to (17.15 ) that also pass through (7.5). 

To tally the number of ways from (0,0) to (7,5) that pass through (7,5), we got to take a add up to of 6 steps to the correct and 4 steps up, for a add up to 10 steps.

The number of such paths is (10 select 4) = 210. To count the number of ways from (7,5) to (17,15) that pass through (7,5), we have to take add up to 3 steps to the right and 5 steps up, to add up to 8 steps.

The number of such ways is (8 select 3) = 56.

Subsequently, the number of grid ways from (0,0) to (17,15) that pass through (7,5) is:

(32 select 15) - (12 select 5)(20 select 10) + (10 select 4)(8 select 3) = 7,210,800

So there are 7,210,800 grid paths from (0,0) to (17,15) through (7,5).

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The union symbol (∪) means that we are combining all three intervals into a single set.

The set of points from -6 to 0 but excluding -5 and 0 can be expressed as a union of intervals as follows:

(-6, -5) U (-5, 0) U (0, 6)

This means that the set includes all real numbers from -6 to 6, except for -5 and 0, which are excluded. The parentheses indicate that the endpoints (-6, -5, 0, and 6) are not included in the set. The union symbol (∪) means that we are combining all three intervals into a single set.

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Answer: 4 km

Step-by-step explanation:

You use the Pythagorean theorem: [tex]a^{2} +b^{2} =c^{2}[/tex]

So 2^2 + 3^2 = c^2

C=[tex]\sqrt{13}[/tex] or 3.60555

Then you round to the nearest km to get 4

The expression 1/1×2 + 1/2×3 + ... + 1/n(n+1) can be written as Σ(k=1 to n) 1/k(k+1). After examining the values of this expression for small values of n, we can conjecture that the formula for this expression is 1 - 1/(n+1).

To prove this formula, we can use mathematical induction.

We need to prove that 1/1×2 + 1/2×3 + ... + 1/n(n+1) = 1 - 1/(n+1) for all positive integers n.

First, we can show that the formula is true for n = 1:

1/1×2 = 1 - 1/2

Next, we assume that the formula is true for some positive integer k, and we want to prove that it is also true for k+1.

Assuming the formula is true for k, we have:

1/1×2 + 1/2×3 + ... + 1/k(k+1) = 1 - 1/(k+1)

Adding (k+1)/(k+1)(k+2) to both sides, we get:

1/1×2 + 1/2×3 + ... + 1/k(k+1) + (k+1)/(k+1)(k+2) = 1 - 1/(k+1) + (k+1)/(k+1)(k+2)

Simplifying the right side, we get:

1/1×2 + 1/2×3 + ... + 1/k(k+1) + (k+1)/(k+1)(k+2) = 1 - 1/(k+2)

Therefore, the formula is true for k+1 as well.

By mathematical induction, the formula is true for all positive integers n.

Thus, we have proved that 1/1×2 + 1/2×3 + ... + 1/n(n+1) = 1 - 1/(n+1) for all positive integers n.

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Answer:  Let's use "x" to represent the unknown quantity in grams:

We have:

3/10 x = 25% of 120g

Converting 25% to a fraction:

3/10 x = 25/100 * 120g

Simplifying 25/100:

3/10 x = 0.25 * 120g

Multiplying 0.25 by 120g:

3/10 x = 30g

To solve for "x", we can multiply both sides by the reciprocal of 3/10:

x = (10/3) * 30g

Simplifying:

x = 100g

Therefore, 3/10 of 100g is equal to 25% of 120g.

Step-by-step explanation:

Answer:

3/10 of 100g = 25% of 120g

Step-by-step explanation:

Let us assume that,

→ Missing quantity = x

Now we have to,

→ Find the required value of x.

Forming the equation,

→ 3/10 of x = 25% of 120

Then the value of x will be,

→ 3/10 of x = 25% of 120

→ (3/10) × x = (25/100) × 120

→ 3x/10 = 25 × 1.2

→ 3x/10 = 30

→ 3x = 30 × 10

→ 3x = 300

→ x = 300/3

→ [ x = 100 ]

Hence, the value of x is 100.

To determine which hybrid plant to introduce, we need to calculate the expected profits for each option. The profits for each option depend on the demand for the plant and the cost of producing it. Let's assume that the cost of producing each hybrid plant is the same and equal to $5,000.

a) Expected profits for Hybrid 1:

If demand is low: profit = (10,000 - 5,000) = $5,000

If demand is medium: profit = (10,000 - 5,000) = $5,000

If demand is high: profit = (30,000 - 5,000) = $25,000

Expected profit for Hybrid 1 = (4/10)*5,000 + (3/10)*5,000 + (3/10)*25,000 = $13,000

Expected profits for Hybrid 2:

If demand is low: profit = (15,000 - 5,000) = $10,000

If demand is medium: profit = (10,000 - 5,000) = $5,000

If demand is high: profit = (35,000 - 5,000) = $30,000

Expected profit for Hybrid 2 = (4/10)*10,000 + (3/10)*5,000 + (3/10)*30,000 = $16,500

Therefore, if Venus wants to maximize expected profits, they should introduce Hybrid 2.

b) To determine the most that Venus would pay for a highly reliable demand forecast, we need to calculate the expected value of perfect information (EVPI). The EVPI is the difference between the expected profits with perfect information and the expected profits under uncertainty.

With perfect information, Venus would know exactly which hybrid plant to introduce based on the demand. The expected profits with perfect information would be:

If demand is low: profit = (15,000 - 5,000) = $10,000

If demand is medium: profit = (10,000 - 5,000) = $5,000

If demand is high: profit = (35,000 - 5,000) = $30,000

Expected profit with perfect information = (4/10)*10,000 + (3/10)*5,000 + (3/10)*30,000 = $16,500

The expected profits under uncertainty for Hybrid 2 (the preferred option) are $16,500. Therefore, the EVPI is:

EVPI = Expected profit with perfect information - Expected profit under uncertainty = $16,500 - $16,500 = $0

This means that Venus should not be willing to pay anything for a highly reliable demand forecast since it would not increase their expected profits.

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Answer:

x = 2

Step-by-step explanation:

y = 3x - 7

y = 7 - x

следовательно,

3x - 7 = 7 - x

=> 2x = 14

=> x = 14/7

=> x = 2

Answer:80

Step-by-step explanation:

first, we can find out angle dbf which is 80 as angles on a straight line sum to 180, then we can enforce the alternate angles concept

The domain of g(x,y) = 1/xy is all real numbers except for x=0 and y=0.

This is because division by zero is undefined and would result in an error or undefined value. In other words, x and y cannot be zero in order for the function to have a valid output.

To understand this further, we can think about the function graphically. The function g(x,y) represents a three-dimensional surface where the height of the surface at any point (x,y) is given by 1/xy. However, we can see that the function is undefined at the points where x=0 or y=0.

At these points, the surface would have a "hole" or a "break" since the height of the surface is undefined. Therefore, the domain of the function is all real numbers except for x=0 and y=0.

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The probability of drawing two jacks in a row from a deck of 52 cards without replacement is equal to option(B) 0.005.

Total number of cards in a deck = 52

Number of Jack in deck of cards = 4

Probability of getting a jack on the first draw is

= 4/52

Now, there are only 3 jacks remaining in a deck of 51 cards.

This implies,

Probability of drawing another jack on the second draw given that the first card was a jack

= 3/51

Probability of drawing two jacks in a row,

Multiply the probability of drawing

= (a jack on first draw by another jack on second draw given first card was a jack)

⇒ P(two jacks)

= (4/52) × (3/51)

= 1/13 × 1/17

= 1/221

= 0.00452489

= 0.005 (rounded to three decimal places).

Therefore, the probability of drawing two jacks in a row is equal to option(B) 0.005.

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The probability of drawing two jacks in a row from a deck of 52 cards without replacement is equal to option(B) 0.005.

Total number of cards in a deck = 52

Number of Jack in deck of cards = 4

Probability of getting a jack on the first draw is

= 4/52

Now, there are only 3 jacks remaining in a deck of 51 cards.

This implies,

Probability of drawing another jack on the second draw given that the first card was a jack

= 3/51

Probability of drawing two jacks in a row,

Multiply the probability of drawing

= (a jack on first draw by another jack on second draw given first card was a jack)

⇒ P(two jacks)

= (4/52) × (3/51)

= 1/13 × 1/17

= 1/221

= 0.00452489

= 0.005 (rounded to three decimal places).

Therefore, the probability of drawing two jacks in a row is equal to option(B) 0.005.

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The length of the side of the triangle BC is 0. 97 cm

It is important to note that their are different trigonometric identities. These identities are;

From the information given, we have that;

cos θ = adjacent/hypotenuse

sin θ = opposite/hypotenuse

tan θ = opposite/adjacent

Then, we have;

sin 17 = BC/√11

cross multiply the values, we have;

BC = sin 17 (√11)

BC = 0. 97 cm

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The center of mass of the given system of point masses lying on the x-axis is (2.6, 0).

To find the center of mass, we need to use the formula:

xcm = (m1x1 + m2x2 + m3x3 + m4x4) / (m1 + m2 + m3 + m4)

Plugging in the values, we get:

xcm = (0.1 * 1 + 0.3 * 2 + 0.4 * 3 + 0.2 * 4) / (0.1 + 0.3 + 0.4 + 0.2) = 2.6

So the x-coordinate of the center of mass is 2.6.

Since all the masses are lying on the x-axis, the y-coordinate of the center of mass will be 0.

Therefore, the center of mass of the given system of point masses lying on the x-axis is (2.6, 0).

The center of mass is the point at which the entire mass of a system can be considered to be concentrated. It is the point at which a force can be applied to the system to cause it to move as a whole, without causing any rotation. To find the center of mass of a system of point masses, we use the formula that takes into account the masses and their positions. In this case, all the masses are lying on the x-axis, so we only need to consider the x-coordinates. By adding up the products of the masses and their respective x-coordinates, and dividing by the total mass, we can find the x-coordinate of the center of mass. The y-coordinate will be 0 since all the masses are on the x-axis.

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The center of mass of the given system of point masses lying on the x-axis is (2.6, 0).

To find the center of mass, we need to use the formula:

xcm = (m1x1 + m2x2 + m3x3 + m4x4) / (m1 + m2 + m3 + m4)

Plugging in the values, we get:

xcm = (0.1 * 1 + 0.3 * 2 + 0.4 * 3 + 0.2 * 4) / (0.1 + 0.3 + 0.4 + 0.2) = 2.6

So the x-coordinate of the center of mass is 2.6.

Since all the masses are lying on the x-axis, the y-coordinate of the center of mass will be 0.

Therefore, the center of mass of the given system of point masses lying on the x-axis is (2.6, 0).

The center of mass is the point at which the entire mass of a system can be considered to be concentrated. It is the point at which a force can be applied to the system to cause it to move as a whole, without causing any rotation. To find the center of mass of a system of point masses, we use the formula that takes into account the masses and their positions. In this case, all the masses are lying on the x-axis, so we only need to consider the x-coordinates. By adding up the products of the masses and their respective x-coordinates, and dividing by the total mass, we can find the x-coordinate of the center of mass. The y-coordinate will be 0 since all the masses are on the x-axis.

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To evaluate tα/2 for a confidence level of 99% and a sample size of 17, we need to find the t-value associated with a given confidence level and degrees of freedom (df). The  correct answer: 2.921

In this case, the degrees of freedom (df) can be calculated as: df = sample size - 1 => df = 17 - 1 => df = 16

Now, we need to find the t-value for a confidence level of 99%, which means α = 0.01 (1 - 0.99). Since we are looking for tα/2, we need to find the t-value associated with α/2 = 0.005 in the t-distribution table.

Looking up the t-distribution table for 16 degrees of freedom and α/2 = 0.005, we find the t-value to be approximately 2.921.

So, the tα/2 for a confidence level of 99% and a sample size of 17 is 2.921.

The  correct answer: 2.921

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To find the restricted range for the inverse function of sine, we represent y as follows: (y = sin⁻¹x) is [-π/2, π/2].

To find the restricted range for the inverse function of cosine, we would have;  (y = cos⁻¹x) is [0, π]

The restricted range refers to the ability to specify a function criterion such that the population data would meet that criterion. For the above problem, we are to get the inverse functions of sine and cosine by restricting the range.

This can be obtained as follows:

[-π/2, π/2] for the function sine and

[0, π] for the function cosine.

Thus, the restricted ranges are  [-π/2, π/2] and  [0, π] respectively.

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The height of the cone to the nearest centimeter is, 10 centimeters.

Therefore, option A is the correct answer.

Given that,

the surface area of a cone is 250 square centimeters. The height of the cone is double the length of its radius.

We need to find what is the height of the cone to the nearest centimeter.

If the radius of the base of the cone is "r" and the slant height of the cone is "l",

And, the surface area of a cone is given as total surface area,

SA = πr(r + l) square units

Now, let the radius of a cone be x.

Then the height of the cone is 2x.

Slant height=√x²+4x²

=√5x

So, the surface area of cone=πx(x+2.24x)

⇒250=3.14 × 3.24x²

⇒x²=24.57

⇒x=4.95≈5 centimeter

So, height=2x=10 centimeter

Hence, The height of the cone to the nearest centimeter is 10 centimeters.

Therefore, option A is the correct answer.

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To evaluate this iterated integral, we first need to integrate with respect to z from 0 to sin(y). This will give us an expression involving sin(y). Next, we integrate this expression with respect to x from 0 to y/7. Finally, we integrate the resulting expression with respect to y from 0 to π/2.

The integration steps involve some trigonometric substitutions and u-substitutions, which make the process quite lengthy. However, by carefully following the steps and simplifying the expressions, we can arrive at the final answer. In summary, the iterated integral evaluates a complicated expression involving sine and cosine functions, which can be obtained through a long explanation involving multiple integration steps. Overall, the process involves calculating the integral with respect to z, then x, and finally y, and simplifying the resulting expressions at each step.

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To evaluate this iterated integral, we first need to integrate with respect to z from 0 to sin(y). This will give us an expression involving sin(y). Next, we integrate this expression with respect to x from 0 to y/7. Finally, we integrate the resulting expression with respect to y from 0 to π/2.

The integration steps involve some trigonometric substitutions and u-substitutions, which make the process quite lengthy. However, by carefully following the steps and simplifying the expressions, we can arrive at the final answer. In summary, the iterated integral evaluates a complicated expression involving sine and cosine functions, which can be obtained through a long explanation involving multiple integration steps. Overall, the process involves calculating the integral with respect to z, then x, and finally y, and simplifying the resulting expressions at each step.

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Answer: B

Step-by-step explanation: 21+12= 33.

45 - 33 = 12.

red came 21 times, which is too much. blue came 12 times, which is exactly the same as green.

hope this helps, please make me the brainliest answer

Answer:

D

Step-by-step explanation:

The median class size, would be 40–50.

First, find the total frequency to be :

= 4 + 12 + 24 + 36 + 20+ 16 + 8 + 5

= 125

The median would be located at :

= (125 + 1 ) / 2

= 63 rd position

                  Cumulative frequency

10–20                4

20–30              16

30–40               40

This means that the median class would be 40–50 as this interval has a cumulative frequency of 76 which means the 63 rd number is there.

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The rest of the question is :
Find Median:- Class interval : 10–20 20–30 30–40 40–50 50–60 60–70 70–80 Frequency: 4 12 24 36 20 16 8 5​

The joint PDF which is uniform over the triangle with vertices  is:

f(x,y) = 2, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1-x.

Since the joint PDF is uniform over the triangle with vertices at (0,0), (0,1), and (1,0), the joint PDF can be expressed as:

f(x,y) = c, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1-x,

where c is a constant that ensures that the total probability over the entire region is equal to 1. To find c, we can integrate the joint PDF over the entire region:

[tex]\int \int f(x,y)dydx = \int ^1_0 \int _0^{(1-x)} c dydx[/tex]

[tex]= \int ^1_0 cx - cx^2/2 dx[/tex]

= c/2

Since the total probability over the entire region must be equal to 1, we have:

∫∫f(x,y)dydx = 1

Thus, we have:

c/2 = 1

c = 2

Therefore, the joint PDF is:

f(x,y) = 2, 0 ≤ x ≤ 1, 0 ≤ y ≤ 1-x.

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The probability of getting exactly 3 tails when tossing a coin 4 times is 25%.

From the question, we have the following parameters that can be used in our computation:

{HHHH, HHHT, HHTH, HHTT, HTHH, HTHT, HTTH, HTTT, THHH, THHT, THTH, THTT, TTHH, TTHT, TTTH, TTTT}.

There are 16 equally likely outcomes in the sample space.

Out of these, there are 4 outcomes that have exactly 3 tails: TTTH, TTHT, THTT, and HTTT.

Therefore, P(3 tails) = 4/16 = 1/4 = 0.25.

So, the probability of getting exactly 3 tails when tossing a coin 4 times is 0.25 or 25%.

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The Taylor series for f(x) = e^(7x) centered at c = -1 is e^(-7) - 7e^(-7)(x+1) + 49e^(-7)(x+1)^2/2! - 343e^(-7)(x+1)^3/3! + 2401e^(-7)(x+1)^4/4! - ...

The Taylor series for a function f(x) centered at c is given by

f(x) = f(c) + f'(c)(x-c)/1! + f''(c)(x-c)^2/2! + f'''(c)(x-c)^3/3! + ...

To find the Taylor series for f(x) = e^(7x) centered at c = -1, we will need to calculate the derivatives of f(x) at c = -1.

f(x) = e^(7x)

f'(x) = 7e^(7x)

f''(x) = 49e^(7x)

f'''(x) = 343e^(7x)

f''''(x) = 2401e^(7x)

...

Evaluating these derivatives at c = -1, we get

f(-1) = e^(-7)

f'(-1) = -7e^(-7)

f''(-1) = 49e^(-7)

f'''(-1) = -343e^(-7)

f''''(-1) = 2401e^(-7)

...

Substituting these values into the Taylor series formula, we get:

e^(7x) = e^(-7) - 7e^(-7)(x+1) + 49e^(-7)(x+1)^2/2! - 343e^(-7)(x+1)^3/3! + 2401e^(-7)(x+1)^4/4! - ...

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The given question is incomplete, the complete question is:

Find the Taylor series centered at c= -1, f(x) = e^(7x)

Answer: Yes, dilation centered at the origin with scale factor of 3.

Step-by-step explanation:

Two figures are similar if they have the same shape, but possibly different sizes. In order to check whether two triangles are similar, we need to check whether their corresponding angles are congruent and whether their corresponding side lengths are proportional.

We can see that triangle ACAT and triangle ABUG have corresponding angles that are congruent, and their corresponding side lengths are proportional with a ratio of 3 (i.e., AC = 3AB, AT = 3AU, and CT = 3UG). Therefore, triangle ACAT is similar to triangle ABUG.

To map triangle ACAT onto triangle ABUG, we need a transformation that scales each point by a factor of 3 about the origin (since the dilation is centered at the origin). Therefore, the correct answer is option (C).

Answer: yes

Step-by-step explanation THE Answer the length of the median

is 11.4 units.

Step 1. Given Information.

Given triangle CAT has vertices

,

and

. M is the midpoint of

.

The length of the median

is to be determined.

Step 2. Explanation.

The midpoint of two points

is given by

.

Plugging the values in the equation to find the point M:

The distance between two points

is given by

.

Plugging the given values in the equation to find the distance between C and M:

Step 3. Conclusion.

Hence, the length of the median

is 11.4 units.

The limit of the sequence as n approaches infinity is 4.

Therefore, lim n→[infinity] an = 4.

To determine whether the sequence converges or diverges, we need to find the limit of the sequence as n approaches infinity.

We can simplify the expression for the nth term of the sequence as follows:

an = 4 + 2n^2 / (2n + 3n^2)

= 4 + n / (1.5 + n)

As n approaches infinity, the denominator of the fraction approaches infinity much faster than the numerator. Therefore, the fraction approaches zero and the value of the nth term approaches 4.

In other words, as n becomes very large, the terms of the sequence become arbitrarily close to 4. Therefore, the sequence converges to 4.

Hence, the limit of the sequence as n approaches infinity is 4.

Therefore, lim n→[infinity] an = 4.

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The theorems that are necessary when proving that the opposite angles of a parallelogram are congruent are;

B. Angle Addition Postulate.

D. Corresponding parts of congruent triangles are congruent.

The pairs of alternate internal angles are congruent when two parallel lines are intersected by a transversal, such as a line that crosses through both lines.

When two sides of a parallelogram are parallel, the angles created by the transversal that cuts through them are alternate internal angles.

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Missing parts;

Which of the following are necessary when proving that the opposite angles of a parallelogram are congruent?

Check all that apply.

A. Corresponding parts of similar triangles are similar.

B. Angle Addition Postulate.

C. Segment Addition Postulate.

D. Corresponding parts of congruent triangles are congruent.