Answer:
mę břöőda I dunno this answer
Explanation:
hope you find it
Incisors (front teeth) act as wedges in the human body. Which change would increase the mechanical advantage of incisors?
1 a decrease in the distance of the teeth from the fulcrum,
2 an increase in the distance of the teeth from the fulcrum,
3 an increase in the thickness at the widest part of the teeth and no change in the length of the teeth,
4 an increase in the length of the teeth and no change in the thickness at the widest part of the teeth
To increase the mechanical advantage of incisors (front teeth) so that they act as wedges in the human body is through 2. an increase in the distance of the teeth from the fulcrum.
The decrease in the distance will decrease the mechanical advantage of incisors. The increase in the thickness at the widest part of the teeth will not necessarily support the incisors to become more effective wedges.
Thus, incisors will acquire some mechanical advantage by increasing the force that it exerts. This advantage can be achieved by increasing the distance of incisors from the fulcrum.
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Answer:
4 aka D
Explanation:
can anyone heelp me pls pls
Answer:
Lotion : semisolid
Suspension : liquid
capsule : solid
Explanation:
what is the difference between soldering and solder?
Answer:
Soldering is a technique or a process to bond metals with the help of solder. Solder is a metal alloy with a low melting point and is often regarded as the base metal for soldering. The piece or structure that is being bonded together does not get hot enough to melt and this is where solder (base metal) comes into play and creates the connection.
Explanation:
Hope this helps :)
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And have an amazing day <3
A chemical system is considered to have reached dynamic equilibrium when:__________.
a. the frequency of collisions between the reactant molecules is equal to the frequency of collisions between the product molecules.
b. the rate of production of each of the product species is equal to the rate of consumption of each of the reactant species. c. the rate of production of each of the products is equal to the rate of their consumption by the reverse reaction.
d. the sum of the concentrations of each of the reactant species is equal to the sum of the concentrations of each of the product species.
e. the activation energy of the forward reaction is equal to the activation energy of the reverse reaction.
Answer:
D
Explanation:
Sum of the concentrations of each of reactant species is equal to the sum of the concentrations of each of the product species
Adam and Bobby are twins who have the same weight. Adam drops to the ground from a tree at the same time that Bobby begins his descent down a frictionless slide. If they both start at the same height above the ground, how do their kinetic energies compare when they hit the ground
Answer:
They are the same.
Both have potential energy of M g H and that is the energy that will be converted to kinetic energy for each twin,
Verificar
El gráfico de la velocidad de una bola que rueda por un canal se muestra en la
figura:
a) La velocidad de la bola luego de 5 s.
0.6m/s
b) La distancia recorrida en el intervalo t : (0-5) s
1.5m
c) La distancia recorrida en el intervalo t: (5-10) s
3m
d) La aceleración de la bola en el intervalo t: (10-12) s.
-0.4m/s^2
e) La distancia total recorrida.
6.9m
f) La rapidez media de la bola
0.58m/s
El análisis de un grafico de velocidad versus tiempo permite encontrar los resultados para las preguntas son:
a) La velocidad es v= 0,6 m/s
b) La distancia recorrida dₐ = 1,5 m
c) La distancia recorrida entre t= 5 y 10 s es [tex]d_b[/tex] = 3,0 m
d) La aceleración a = -0,4 m/s²
e) La distancia total recorrida es [tex]d_{total}[/tex] = 5,3 m
f) La velocidad media es [tex]v_{media}[/tex] = 0,44 m/s
La cinemática estudia el movimiento de los cuerpos, buscando relaciones entre la posición, la velocidad y la aceleración de los cuerpos.
La velocidad es definida como el cambio de la posición en función del tiempo y la aceleración es el cambio de la velocidad en el intervalo de tiempo.
.[tex]v= \frac{\Delta x}{t} \\a = \frac{\Delta v}{t}[/tex]
Donde v y a son la velocidad y aceleración, respectivamente, t es el tiempo y Δx y Δv son la variación de la posición y la velocidad, respectivamente.
En el adjunto muestran un grafico de la velocidad en función del tiempo, donde del área bajo la curva obtenemos la distancia recorrida y la pendiente corresponde a la aceleración del cuerpo.
Respondamos las preguntas:
a) La velocidad de la bola a los 5 s.
Como es un grafico de velocidad versus tiempo, la velocidad puede ser leída directamente, en el grafico tenemos un valor de
v= 0,6 m/s
b) La distancia recorrida corresponde al área bajo la curva.
[tex]d_a = \frac{v_f - v_o}{2} t \\d_a = \frac{0.6-0}{ 2}\ 5[/tex]
d = 1,5 m
c) La distancia en el intervalo de 5 a 10 s.
En este intervalo la velocidad es constante, el área es
[tex]d_b = v \Delta t\\d_b = 0.6 \ 5\\[/tex]
d = 3 m
d) La aceleración en el intervalo 10 a 12 s.
La aceleracion es la pendiente del grafico
a = [tex]\frac{\Delta v}{\Delta t}[/tex]
a = [tex]\frac{-0.2 - 0.6}{12-10}[/tex]
a = -0,4 m/s²
El signo negativo indica que la aceleración se opone a la velocidad del cuerpo.
e) La distancia total recorrida
[tex]d_{total} = d_a + d_b + d_c[/tex]
dₐ = 1,5 m
[tex]d_b[/tex] = 3,0 m
Busquemos la distancia en el ultimo intervalo
[tex]d_c = \frac{0.6 + 0.2}{2} ( 12-10)[/tex]
[tex]d_c[/tex] = 0,8 m
Substituimos
[tex]d_{total}[/tex] = 1,5 + 3,0 + 0,8
[tex]d_{total}[/tex] = 5,3 m
f) La rapidez de la bola
La rapidez prmedio es la relación entre la distancia recorrida en el tiempo.
[tex]v_{avg} = \frac{\Delta x}{\Delta t }[/tex]
[tex]v_{avg} = \frac{5.3}{12}[/tex]
[tex]v_{avg}[/tex] =0,44 m/s
En conclusión usando el análisis de un grafico de velocidad versus tiempo podemos encontrar los resultados para las preguntas son:
a) La velocidad es v= 0,6 m/s
b) La distancia recorrida da = 1,5 m
c) La distancia recorrida entre t= 5 y 10 s es db = 3,0 m
d) La aceleración a = -0,4 m/s²
e) La distancia total recorrida es [tex]d_{total}[/tex] = 5,3 m
f) La velocidad media es [tex]v_{avg}[/tex] = 0,44 m/s
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help with this question please.
Answer: Yes Because it matches with the mass and the amount of force Hope this helps :>
Explanation:
What is the net force on a cart being pushed with an applied force of 23 N with a frictional force of 23 N?
Answer:
1N
Explanation:
Pretty simple Divide 23 by 23 which gives you 1.
23N ÷ 23N = 1N
Answer:
[tex]\sf \longmapsto \: 1 \: N[/tex]
Explanation:
[tex]\sf \longmapsto \frac{23N}{23N} [/tex]
[tex]\sf \longmapsto1 \: N[/tex]
Which material(s) listed below is an example of a persistent organic pollutant?
(*select all that apply)
Select 4 correct answer(s)
Ricin
PCBs
DDT
Mercury
Arsenic
Answer:
mercury
arsenic
ricin
ddt
Explanation:
pls mark me as brainliest
Among the materials listed, examples of persistent organic pollutants (POPs) are PCBs (Polychlorinated Biphenyls) DDT (Dichlorodiphenyltrichloroethane). The correct option is (2) and (3).
Persistent Organic Pollutants (POPs) are a class of chemicals that are long-lasting, bioaccumulative, and harmful to humans and wildlife. These pollutants are resistant to degradation and can persist in the environment for long periods of time, resulting in long-distance transport and bioaccumulation in the food chain.
PCBs (Polychlorinated Biphenyls): Once utilized in a variety of industrial applications such as electrical transformers and capacitors, PCBs are now prohibited in many countries due to their toxicity.
DDT (Dichlorodiphenyltrichloroethane): An pesticide that was widely used for agricultural and public health objectives in the past but is now restricted or banned due to its environmental and health effects.
Hence, the correct answer is PCBs and DDT. The correct option is (2) and (3).
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Gravity will apply a different amount of force to objects with different mass. The force of gravity can also be called
a. weight.
b. inertia.
c. kilograms.
d. resistance.
e. Mass
Answer:
E.Mass
Explanation:
Since the gravitational force is directly proportional to the mass of both interacting objects, more massive objects will attract each other with a greater gravitational force. So as the mass of either object increases, the force of gravitational attraction between them also increases.
how much work is done by a crane that lowers 1000 N of material a distance of 150 m?
Answer:
Force= 1000 Newtons. Distance= 150 metres. Work= 150000 Joules. So, the work done by crane that lowers 1000 Newton's of a material a distance of 150 meters is 150000 Joules.
I DO NOT WANT LINKES OR …………..
2. Calculate; The acceleration of any object due to Earth's gravity is -9.81 m/s. For every
second an object falls, its velocity changes by 9.81 meters per second. For several different
times on the table, multiply the time by the acceleration
A. What do you notice:
I
As the time of motion increases, the velocity of the object increases downwards.
The given parameters;
acceleration due to gravity, g = -9.81 m/s²velocity of the object, v₀ = 9.8 m/sThe final velocity of the object at different time is calculated as follows;
when the time = 1 second;
v = v₀ - gt
v = 9.8 - 9.8(1)
v = 0
when the time = 2 second;
v = v₀ - gt
v = 9.8 - 9.8(2)
v = -9.8 m/s
when the time = 3 second;
v = v₀ - gt
v = 9.8 - 9.8(3)
v = -19.6 m/s
Thus, we can conclude that as the time of motion increases, the velocity of the object increases downwards.
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part A
Explain how the students can measure the distance the cars travel.
part B
Explain how the students could measure the time it takes the cars to travel the distance you explained in the first part.
Answer:
Part A: By using the formula, distance = speed x time
Part B: By using the formula, time = distance ( calculated in the first part) ÷ speed
WILL GIVE BRAINLIEST
An object with mass m dropped from height H, after travelling a distance and emerged horizontally from the bottom of the track with a velocity v and height of h. what is The work done due to friction while traveling through the track. could someone also please explain the difference between h and H
Answer:
I think d
Explanation:
Please help with this question, it’s for physical science
Answer:
s times t
Explanation:
The equation for distance is D = st
Answer:
D is the correct answer (D=S*T)
This is an algebraic law; if you are to move the denominator or numerator to the other side of the equation, you must multiply it by the other side.
S=D/T is the same as D=S*T.
so distance=speed times time.
so if you are going 50 miles per hour, you multiply that times time, say one hour. you get your D distance which is 50 miles.
How do I do these three parts ?what are the answers I’ve been trying for days
Answer:
Explanation:
ASSUMING the clay is moving horizontally and friction is negligible.
momentum is mass times velocity
9a)
m₁v + m₂(0) = m₁vf + m₂vf
m₁v = (m₁ + m₂)vf
vf = m₁v / (m₁ + m₂)
9b)
ASSUMING the positive direction is also the original direction of the clay ball
m₁v + m₂vb = (m₁ + m₂)vf
vf = (m₁v + m₂vb) / (m₁ + m₂)
9c)
vf = (0.37(25) + 4.6(3.4)) / (0.37 +4.6)
vf = (9.25 + 15.64) / 4.97
vf = 5.0080482897...
vf = 5.0 m/s
A boy of mass 43.2 kg runs and jumps onto a stationary skateboard.The boy lands on the skateboard with a horizontal velocity of 4.10 m/s.The skateboard has a mass of 2.50 kg.
Using ideas about conservation of momentum, calculate the combined
velocity of the boy and skateboard just after the boy lands on it.
Answer:
= 3.87 m/s
Explanation:
Since momentum is conserved, momentum right before and after the boy jumps onto the skateboard should be the same.
Initial momentum = momentum of boy = 43.2 x 4.10 = 177 kg·m/s
Final momentum = momentum of boy and skateboard = (43.2 + 2.50) x v = 45.7v
177 = 45.7v
v = 177 / 45.7 = 3.87 m/s
(Hope this helps can I pls have brainlist (crown)☺️)
The combined velocity of the boy and the skateboard just after the boy lands on it will be equal to 3.87 m/s.
What is momentum?Momentum is the product of a particle's mass and velocity. Being a vector quantity, momentum possesses both direction and magnitude. According to Isaac Newton's second equation of motion, the force applied on a particle is equivalent to the temporal rate at which momentum changes.
According to Newton's second law, the product of the energy and the time interval is equal to the shift in momentum if a constant force acts on a molecule for a specified amount of time.
Momentum should be the same both before and after the boy gets onto the skateboard because it is preserved.
Initial momentum = momentum of boy
= 43.2 × 4.10 = 177 kg m/s
Final momentum = momentum of boy as well as skateboard
= (43.2 + 2.50) × v = 45.7 v
177 = 45.7 v
v = 177 / 45.7 = 3.87 m/s
Therefore, the combined velocity of boy and skateboard is 3.87 m/s.
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why do the star constellations seem to move across the sky
Answer: These apparent star tracks are in fact not due to the stars moving, but to the rotational motion of the Earth. As the Earth rotates with an axis that is pointed in the direction of the North Star, stars appear to move from east to west in the sky.
Explanation: why do the star constellations seem to move across the sky
Answer:
because the world moves around and around rotating in a circle and circling around the sun so as we move the stars stay the same but to our view it looks like their moving but in reality we are.
Explanation:
What is the mass of an object that is experiencing a net force of 225 N and an acceleration of 3.0 m/s^2?
Answer:
Mass of a object 75 Kilograms
Explanation:
Net force acting on an object, [tex]Fnet = 225N[/tex]
Acceleration produced, [tex]a = 3.0m/s^2[/tex]
According to Newton's second law :
F = m a
[tex]M =\frac{F}{a}[/tex]
[tex]m =\frac{225N}{300m/s^2}[/tex]
[tex]m= 75 Kg[/tex]
So, the mass of an object is 75kg.
Hence, this is the required solution.
Answer:
75 kg.
Explanation:
Net Force
[tex]\sf \longmapsto F_{net} = 225N[/tex]
Acceleration produced
[tex]\sf \longmapsto \: a = 3 .0 m / {s}^{2}[/tex]
According to Newton's 2nd Law –
F = m•a
[tex]\sf \longmapsto \: M = \frac{F}{A} [/tex]
[tex]\sf \longmapsto \: M = \frac{225N}{300m/s ^{2} } [/tex]
[tex]\sf \longmapsto \: M = \: 75 \: kg[/tex]
Therefore, the mass of an object is 75 kg.
describe in the relationships between all four spheres hydrosphere,atmosphere,biosphere and geosphere support your response with examples
Answer:
The spheres interact with one another, and a change in one might result in a change in another. Humans (biosphere) plough the fields with agricultural machinery made of geosphere materials, while the atmosphere (hydrosphere) provides precipitation to water the plants. The biosphere is home to all living organisms on the earth.
Explanation:
don't ask qestionsmm
How long does it take light from a camera to travel to the face of someone standing 7 meters away?
The time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s
Speed is simply defined as the distance travelled per unit time. Mathematically, it is expressed as:
Speed = distance / timeWith the above formula, we can obtain the time taken for the light to travel from the camera to someone standing 7 m away. This can be obtained as follow:
Distance = 7 m
Speed of light = 3×10⁸ m/s
Time =?Time = Distance / speed
Time = 7 / 3×10⁸
Time = 2.33×10¯⁸ sTherefore, the time taken for the light to travel from the camera to someone standing 7 m away is 2.33×10¯⁸ s
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Shearing is done in case of Processing of __________ ( Silk / Wool / Jute ).
Answer:
wool maybe, I was a bit confused in silk and wool but wool
You are having a snowball fight with your best friend on a frosty winter day. You are standing on the roof of your 5 m tall house with a 0.4 kg snowball. You drop the snowball downward from rest toward your friend,
who is making snow angels below you. Ignoring air resistance, solve for the gravitational potential energy of
the snowball before it is released.
a) 12.5 J
b) 19.6J
c) 5J
d) 2J
Answer: B 19.6J
Explanation: The equation for Potential energy is PE=mgh
PE is the potential energy
m=Mass=0.4kg
g=Gravity=9.81m/[tex]s^{2}[/tex]
h=Height=5 metres
(0.4 kg)*(9.81m/[tex]s^{2}[/tex])*(5 metres)=19.62J
Indicate whether each of the following statements about car collisions is true or false. Select all that are True.
a. If two identical cars with identical speeds collide head on, the magnitude of the impulse received by each car and each driver is the same as if one car at the same speed had collided head on with a concrete wall.
b. Car 1 has mass m, and car 2 has mass 2m. In a head-on collision of these cars while moving at identical speeds in opposite directions, car 1 experiences a bigger acceleration than car 2.
c. The essential safety benefit of crumple zones (parts of the front of a car designed to receive maximum deformation during a head-on collision) is due to their absorbing kinetic energy, converting it into deformation, and lengthening the effective collision time, thus reducing the average force experienced by the driver.
d. Car 1 has mass m, and car 2 has mass 2m. In a head-on collision of these cars while moving at identical speeds in opposite directions, car 1 receives an impulse of bigger magnitude than that received by car 2. If car 1 has mass m and speed v, and car 2 has mass 0.5m and speed 1.5v, then both cars have the same momentum.
Answer:
True statements a, b, and c
Explanation:
Answer d is false because in any collision, each object receives the same impulse. Also the momentum of car 1 is mv, while the momentum of car 2 is 0.5m(1.5v) = 0.75mv
The impulse of collision of cars depends on the mass and velocity of the cars. The statements which are true about the car collisions are option a, b, c.
What is impulse?Impulse is a physical quantity expressed as the product of force and time. The change in momentum mΔV is numerically equals to the impulse F t.
If two identical cars with identical speeds collide head on, the magnitude of the impulse received by each car and each driver is the same as if one car at the same speed had collided head on with a concrete wall. Because they have equal mass and velocity.
The bigger acceleration is experienced by the one which have lighter mass thus car 1 with lower mass experience higher acceleration .
The essential safety benefit of crumple zones (parts of the front of a car designed to receive maximum deformation during a head-on collision) is due to their absorbing kinetic energy.
Converting this energy into deformation, and lengthening the effective collision time, thus reducing the average force experienced by the driver.
The momentum change is proportional to the velocity. The one which have higher velocity is having the higher momentum. Thus car 2 have higher velocity. Thus option d is false.
Therefore, the statements which are true are a, b and c.
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Which graph uses bars to show data that are broken into intervals?
O A. Scatter plot
O B. Bar graph
O C. Box-and-whisker plot
O D. Histogram
Answer:
A. scatter plot?
Explanation:
I dont really know if I'm right... sorry.
a block starts from rest and begins sliding down an incline. The block reaches a speed of 12 meters per second as it slides a distance of 50 meters. calculate the blocks rate of acceleration
Vf² = V₁² + 2ad
(12 m/s) ² = (0 m/s) ² + 2 (a) (50m)
a = 1.44 m/s ²
Answer:
[tex]\boxed {\boxed {\sf 1.44 \ m/s^2}}[/tex]
Explanation:
We are asked to find the block's rate of acceleration.
We are given the final velocity, initial velocity, and distance. Therefore, we will use the following kinematic equation:
[tex]{v_f}^2={v_i}^2+2ad[/tex]
The block starts at rest or 0 meters per second. The block reaches a final velocity of 12 meters per second. The distance traveled is 50 meters.
[tex]v_i[/tex]= 0 m/s [tex]v_f[/tex]= 12 m/s [tex]d[/tex]= 50 mSubstitute the values into the formula.
[tex](12 \ m/s)^2 = (0 m/s)^2 + 2a (50 \ m)[/tex]
Solve the exponents.
(12 m/s)² = 12 m/s * 12 m/s = 144 m²/s²(0 m/s)² = 0 m/s * 0 m/s = 0 m²/s²[tex]144 \ m^2/s^2= 0 m^2/s^2 + 2a (50 \ m)[/tex]
The 0 can be subtracted from both sides, or simply canceled.
[tex]144 \ m^2/s^2 = 2a (50 \ m)[/tex]
Multiply 2 and 50 meters.
[tex]144 \ m^2/s^2 = (2 *50 \ m)* a[/tex]
[tex]144 \ m^2/s^2 = (100 \ m)* a[/tex]
We are solving for a, so we must isolate the variable. It is being multiplied by 100 meters. The inverse of multiplication is division, so we divide both sides by 100 meters.
[tex]\frac {144 \ m^2/s^2}{100 \ m}= \frac{(100 \ m)*a}{100 \ m}[/tex]
[tex]\frac {144 \ m^2/s^2}{100 \ m}=a[/tex]
[tex]1.44 \ m/s^2 =a[/tex]
The block's rate of acceleration is 1.44 meters per second squared.
9) A policeman investigating an accident measures the skid marks left by a car. He determines that 9) the distance between the point that the driver slammed on the brakes and the point where the car came to a stop was 28.0 m. From a reference manual he determines that the coefficient of kinetic friction between the tires and the road under the prevailing conditions was 0.300. How fast was the car going wh~er applied the brakes? (This car was not equipped with anti-lock brakes.)
Answer:
Explanation:
Provided the car did not collide with anything during its slide,
Kinetic energy will convert to work of friction
½mv² = Fd
½mv² = μmgd
v = √(2μgd)
v = √(2(0.300)(9.81)(28.0))
v = 12.8377...
v = 12.8 m/s
When a straw with liquid is covered by a finger and raised, the liquid does not leak
from the straw. Explain this using ideas of pressure exerted by particles.
Answer:
lol I don't know think u could help me with my mathematics
Um cubo fechado com 1 m3 de um líquido (d=0,8; =21 000 kgf/cm2
) é submetido a um aumento de pressão de
20107 N/m2
. Calcule, no Sistema Internacional, as seguintes grandezas:
a) massa final;
b) peso final;
c) volume final;
d) massa volúmica final;
e) peso volúmico final.
Answer:
a. massa final
Explanation:
eu escolhi isso porque essa é a resposta espero que ajude você pode me dar uma ideia?