Childhood participation in sports, cultural groups, and youth groups appears to be related to improved self-esteem for adolescents (McGee, Williams, Howden-Chapman, Martin, & Kawachi, 2006). In a representative study, a sample of n = 100 adolescents with a history of group participation is given a standardized self-esteem questionnaire. For the general population of adolescents, scores on this questionnaire form a normal distribution with a mean of μ = 50 and a standard deviation of σ = 15. The sample of group-participation adolescents had an average of M = 53.8.
Does this sample provide enough evidence to conclude that self-esteem scores for these adolescents are significantly different from those of the general population? Use a two-tailed test with α = .05.
Testing the hypothesis, we can conclude that since the p-value of the test is 0.0114 < 0.05, which means that the sample provides enough evidence to conclude that self-esteem scores for these adolescents are significantly different from those of the general population.
At the null hypothesis, we test if the mean is the same of the general population, that is:
[tex]H_0: \mu = 50[/tex]
At the alternative hypothesis, we test if it is different, that is:
[tex]H_1: \mu \neq 50[/tex]
The test statistic is given by:
[tex]z = \frac{M - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
For this problem, the parameters are:
[tex]M = 53.8, \mu = 50, \sigma = 15, n = 100[/tex]
Then, the value of the test statistic is:
[tex]z = \frac{M - \mu}{\frac{\sigma}{\sqrt{n}}}[/tex]
[tex]z = \frac{53.8 - 50}{\frac{15}{\sqrt{100}}}[/tex]
[tex]z = 2.53[/tex]
Two tailed test, so the p-value is P(|z| < 2.53), which is 2 multiplied by the p-value of z = -2.53.
Looking at the z-table, z = -2.53 has a p-value of 0.0057
2(0.0057) = 0.0114
The p-value of the test is 0.0114 < 0.05, which means that the sample provides enough evidence to conclude that self-esteem scores for these adolescents are significantly different from those of the general population.
A similar problem is given at https://brainly.com/question/25147864
7 1/3 or 6 2/3 pls help
Answer:
7 3/3
Step-by-step explanation:
+3221654236583217089
Evaluate.
38−(7+2×4)+182
Enter your answer in the box.
the answer is 32
[tex]205[/tex]
hope it helps
use double number lines to find the missing number
Answer:
320
Step-by-step explanation:
80 is 25% of:
ok how we do this is 25% of something is 1/4 of something
so 80 is 1/4 of:
yep, 80 x 4.
80 x 4 is 320, there is your answer!
Yw :D
Anyone know the answer ? Please help asap :((
Answer:
Point B
Step-by-step explanation:
Answer:
the answer is point b...
Let's Create
Fill in the blank with the value that will make the equation true.
1) __+2/3= -1/4
2) __-3/4= -7/12
3) __÷3/4= -2
4) __÷0.04=800
5) (____)(5.6)= -6.72
Let's Analyze
Fill in the blank with the value that will make the equation true.
1) 1/4+___=7/12
2) 5/8-___= -3/8
3) 1/3÷___= 1/9
4) (2.1)(____)=0.63
5)_____-0.98= -7.65
Answer:
.
1) 1/4+___=7/12
2) 5/8-___= -3/8
3) 1/3÷___= 1/9
4) (2.1)(____)=0.63
value
The denominator of a fraction is two more than the numerator. If both numerator and denominator are increased by one, the simplified result is 6/7. Find the original fraction.
Answer:
10/12
Step-by-step explanation:
Let's work backwards.
We decrease both 6 and 7 by one, then we get 5 and 6. So our new fraction is 5/6. We know that the denominator is two more than the numerator, so we have to pick numbers that are multiples of 5 and 6 and make it so the denominator is two more than the numerator.
Lucky for us we only have to multiply 5 and 6 by 2 to get an answer that works:
10/12
Three times the sum of a number and 9 is 12 find the number
Answer:
324
Step-by-step explanation:
9 x 12 = 108 x 3 = 324....yay
Consider the following formula used to find the volume of a cone.
h
V = ir2
3
Which of the following represents the formula that could be used to find the height of the cone?
[tex]\\ \sf\longmapsto V=\pi r^2\dfrac{h}{3}[/tex]
[tex]\\ \sf\longmapsto \dfrac{h}{3}=\dfrac{V}{\pi r^2}[/tex]
[tex]\\ \sf\longmapsto h=\dfrac{3V}{\pi r^2}[/tex]
Option B
Answer:
[tex] \hookrightarrow \: { \rm{V = \pi {r}^{2} \frac{h}{3} }} \\ [/tex]
• simplify making h the subject:
[tex]{ \rm{3V = \pi {r}^{2} h}} \\ \\ { \boxed{ \boxed{ \rm{h = \frac{3V}{\pi {r}^{2} } \: }}}}[/tex]
There are 28 students in a class. Sixteen of the students are men. What percent of the class are women? Round to the nearest tenth.
Answer:
42.9%
Step-by-step explanation:
If 16 are men, this means 12 of the students are women (28 - 16 = 12)
So, 12 out of 28 are women = 12 ÷ 28 = 0.42857... = 42.857...% = 42.9%
A number is doubled and then increased by seven. The result is fifty-one. What is the original number?
Answer: I believe it's 22
Step-by-step explanation:
51 - 7 = 44
If the result is 55 and was increased by 7, you'll subtract 7 from 55 and you'll get 44.
44/2 = 22
To find the number that is doubled and makes up 44, you'll divide 2 from 44 and you'll get 22
The endpoints of are A(2, 2) and B(3, 8). is dilated by a scale factor of 3.5 with the origin as the center of dilation to give image . What are the slope (m) and length of ? Use the distance formula to help you decide: .
A.
m = 6, A'B' =
B.
m = 21, A'B' = 3.5
C.
m = 21, A'B' =
D.
m = 6, A'B' = 3.5
Answer:
Step-by-step explanation:
4(3M - 2) + 2(2M - 1) when M = 5
Answer:
70
Step-by-step explanation:
4(3m-2)+2(2m-1)
4(3×5-2)+2(2×5-1)
4×13+2×9
52+2×9
52+18
what is 1\4y+3/8 factored
Answer:
[tex] \frac{1}{4} (y + \frac{3}{2} )[/tex]
My work is already late because I was suppose to turn it in at 9:30 PM sooo like help?
The sum of two numbers is
17. Their difference is 41. Find the numbers.
Answer:
The numbers are 12 and −29.
Mark me as the brainlist
12345678910121314151617181920 so i can know answer my question yeet help me
Answer:
1) 529
2) 20.5
3) 7,216
4) 13238.2
5) 254.75
Step-by-step explanation:
1) Multiplication 2) Subtraction and Addition 3) Addition and Multiplication 4) Subtraction 5) Multiplication and Subtraction
-ROR
Answer:
1) 529
2) 20.5
3) 720.6
4) 13238.2
5) 254.75
Step-by-step explanation:
You either multiply, add, subtract or divide the numbers.
is it normal to forget things almost 4 months after a concussion?
Answer:
Yes I've had that too
Step-by-step explanation:
I had mine for about 5-6 months
Answer:
Yes, a concussion can cause long-term memory loss and recurring short-term memory loss, even weeks, months, or years after the head trauma. Usually, this is known as a symptom of post-concussion syndrome
hi! ❤️ I’m looking for help here thanks.
Answer:
CBA = 88
BCA = 44
Step-by-step explanation:
Hope this helps! Pls give brainliest!
Help!!!! I need this due my 9:30
Answer:
D. Subtract 15 cents and add 29 cents
Step-by-step explanation:
He should subtract 15 cents and add 29 cents. This is because at 33.85 we estimated to 34 dollars which was 15 cents higher, so we must subtract by 15 to get to the exact cost. We also need to add 29 cents since we rounded down from 16.29 to 16.
HELP LAST ATTEMPT to ( get marked brainliest show work !
Answer:
B. 5 3/4 feet
Step-by-step explanation:
33 sq ft is the total area so you need the side lengths, its a square rug, so you just square the number
sqrt 33 = 5 3/4
Answer:
B. 5 3/4 feet
Step-by-step explanation:
33 sq ft is the total area so you need the side lengths, its a square rug, so you just square the number
sqrt 33 = 5 3/4
HELP LAST ATTEMPT ( get marked brainliest show work
Answer:
D
Step-by-step explanation:
Area of H = 25pi
Area of J = 225pi
225pi/25pi = 9
Please answer!no links!!
Picture is included
I selected b but not sure…
Answer:
B is the correct answer darling
Step-by-step explanation:
don't doubt yourself :)
have a lovely day <3
Answer:
B
Step-by-step explanation:
[tex]\dfrac{-1}{5}(30x-10)=15\\\\ \dfrac{-1}{5}*30x -10* \dfrac{-1}{5}=15\\\\-6x + 2 = 15[/tex]
Select the correct answer from each drop-down menu.
Kurt deposited money into his bank account every month. The amount of money he deposited in the first 5 months of 2014 is listed in the table.
Month Amount Deposited
(dollars)
January 1,200.32
February 985.43
March 1,200.65
April 1,987.34
May 1,000.98
The total amount of money that Kurt had deposited into his account at the end of May is
$6,374.72
. The total amount of money that he had deposited into his account at the end of March is
.
Reset
9514 1404 393
Answer:
$3386.40
Step-by-step explanation:
The amount at the end of March can be found two ways:
add up the deposits for Jan, Feb, Mar:
1200.32 +985.43 +1200.65 = 3386.40
subtract Apr and May from the May total:
6374.72 -1000.98 -1987.34 = 3386.40
The total amount of money that he had deposited into his account at the end of March is $3386.40.
Deon plans to ride a 15 mile bicycle trail. If his average speed is 20mi/h, which equation can he use to find the time t, in hours, for the ride?
Answer
15=20t
Step-by-step explanation:
Answer:
t = 15 / 20
Step-by-step explanation:
Given:
Distance traveled by Deon to ride a bicycle trail = 15 mile
Average speed of Deon to ride a bicycle trail = 20 mi/hour
Step-by-Step:
Let 'T' be the time taken to ride the bicycle trail.
We will use distance speed formula to write the equation to find the time 'T' in hours, for the ride.
[tex]Distance=\frac{Speed}{Time}[/tex]
Distance = 15 miles
Speed = 20 miles / hour
Time = 15 / 20
Assuming time is t, the formula would be:
t = 15 / 20
"t = 15 mi/ 20 mi/hr " will help Deon calculate the time he will take.
Therefore, t = 15 / 20
Find the 16th term of the arithmetic sequence whose common difference is d=9 and whose first term is a, = 1.
Answer:
136
Step-by-step explanation:
Common difference of 9 means that each term is 9 apart from each other:
1 + 9 = 10 + 9 = 19 + 9 = 28 ...
We can then find the nth term
The difference is 9 → 9n
The 0th term is 1 - 9 = -8
nth term = 9n - 8
Finally plug in (substitute) 16 for n
9(16) - 8 = 144 - 8 = 136
The 16th term is 136
Find the 16th term of the arithmetic sequence whose common difference is d=9 and whose first term is a, = 1.
Given : - common difference ( d ) = 9first term ( a ) = 1To Find : -We have to find the 16th term of Arithmetic Progression or sequence .
Concept : -Concept of this question belongs to arithmetic progression ( sequence ) where we can find the values of a , d , nth term by using nth term formula .
So Starting the Solution : -We know that 16th term of a.p. is ,
a + ( 16 - 1 ) da + 15 d --------- ( 1 )Here value of ,
a = 1d = 9Substituting, value of a and d in equation 1 :
1 + 15 ( 9 )1 + 135136Therefore , 16th term of the given arithmetic progression is 136 .
# [tex] \rm{Keep \: Learning}[/tex]What term describes the amount you must pay in order to be considered “up-to-date” with your credit card payments?
Interest
Minimum payment
Closing balance
Manuel the trainer has two solo workout plans that he offers his clients: Plan A and Plan B. Each client does either one or the other (not both). On Monday there were 12 clients who did Plan A and 2 who did Plan B. On Tuesday there were 3 clients who did Plan A and 5 who did Plan B. Manuel trained his Monday clients for a total of 21 hours and his Tuesday clients for a total of 12 hours. How long does each of the workout plans last?
HELP. FIND X AND EXPLAIN THE ANSWER
ANSWER CHOICES:
A. x=-3
B. x=4
C. x=48
D. x=29
Answer:
D. x=29
Step-by-step explanation:
(2x-10)+(4x+16)=180
6x+6=180
6x=174
x=29
Salaries for teachers in a particular elementary school district are normally distributed with a mean of $41,000 and a standard deviation of $7,200. We randomly survey ten teachers from that district. (Round your answers to the nearest dollar.)
(a) Find the 90th percentile for an individual teacher's salary.
$
(b) Find the 90th percentile for the average teacher's salary.
$
Using the normal distribution and the central limit theorem, it is found that:
a) The 90th percentile for an individual teacher's salary is $50,216.
b) The 90th percentile for the average teacher's salary is $43,914.
In a normal distribution with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the z-score of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
It measures how many standard deviations the measure is from the mean. After finding the z-score, we look at the z-score table and find the p-value associated with this z-score, which is the percentile of X.By the Central Limit Theorem, the sampling distribution of sample means of size n has standard deviation given by [tex]s = \frac{\sigma}{\sqrt{n}}[/tex].In this problem:
Mean of $41,000, thus [tex]\mu = 41000[/tex].Standard deviation of $7,200, thus [tex]\sigma = 7200[/tex].Item a:
The 90th percentile is X when Z has a p-value of 0.9, so X when Z = 1.28. Thus:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]1.28 = \frac{X - 41000}{7200}[/tex]
[tex]X - 41000 = 1.28(7200)[/tex]
[tex]X = 50216[/tex]
The 90th percentile for an individual teacher's salary is $50,216.
Item b:
Average for a sample of 10, thus [tex]n = 10, s = \frac{7200}{\sqrt{10}}[/tex].
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
By the Central Limit Theorem
[tex]Z = \frac{X - \mu}{s}[/tex]
[tex]1.28 = \frac{X - 41000}{\frac{7200}{\sqrt{10}}}[/tex]
[tex]X - 41000 = 1.28\frac{7200}{\sqrt{10}}[/tex]
[tex]X = 43914[/tex]
The 90th percentile for the average teacher's salary is $43,914.
A similar problem is given at https://brainly.com/question/24663213