Density of solid copper is 8960 kg/metre cubed. Calculate the
volume of 5000 kg of copper to two significant figures.​

Answer: it eventually cracks the rock and breaks pieces of the rock off

Explanation:

Answer:

It is d

Explanation:

Answer:

D !!!!!

Explanation:

Answer:

d

Explanation:

it is never stated in science

Objects of the same size will accelerate equally if they have different forces applied to them. This statement (D) does NOT apply to Newton’s second Law of Motion.

Newton’s second law of motion states that “Force is equal to the rate of change of momentum. For a constant mass, force equals mass times acceleration.

As momentum is product of mass and velocity, the more mass something has, the more force it would take to accelerate it.  So option (A) is correct.

As rate of change of momentum of a body refers product of mass and acceleration of a body,  the more force applied to an object’s mass, the more it will accelerate and the force required to accelerate an object equals the objects mass times it’s acceleration. So, option (B) and (C) is correct.

But  force has no direct elation with size of the body. So, option (D) is not correct.

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Answer:

π/2 radians.

Explanation:

Angular Displacement

It's the angle expressed in radians, degrees, revolutions, etc. through which a point revolves around a point called the center.

To find the angular displacement, we must recall a full revolution, or turn around the center measures 360 degrees, or 2π radians.

The Earth completes a turn every 24 hours. This means that in 6 hours, it has given 6/24 = 1/4 of a turn.

This means that, measured in radians, the angular displacement of a person during 6 hours is:

1/4*2π radians

Simplifying:

π/2 radians.

Answer:

5m/s²

Explanation:

Given parameters:

Mass of wagon  = 10kg

Force of pull  = 70N

Frictional force = 20N

Unknown:

Acceleration of the wagon = ?

Solution:

Frictional force is a force that opposes motion.

The net force is given as:

   Net force  = mass x acceleration

 Force of pull  - Frictional force = mass x acceleration

 Insert the parameters and solve;

     70 - 20  = 10 x acceleration

       50  = 10 x acceleration

      Acceleration  = 5m/s²

Answer:

Explanation:

To find the amplitude of the sound, we must first determine the wavelength and the phase difference between the two speakers.

For the wavelength;

Recall that, the separation between two successive max. and min. intensity points are [tex]\dfrac{\lambda}{2}[/tex]

Thus; for both speakers; the wavelength of the sound is:

[tex]\dfrac{\lambda}{2} = (10+30) cm[/tex]

[tex]\dfrac{\lambda}{2} = (40) cm[/tex]

λ = 80 cm

The relation between the path difference(Δx) and the phase difference(Δ∅) is:

[tex]\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o[/tex]

where;

Δx = 10 cm

λ = 80 cm

Δ∅ = π rad

∴

[tex]\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o[/tex]

[tex]\pi \ rad = \dfrac{2 \pi}{80 \ cm}(10 \ cm) + \Delta \phi_o[/tex]

[tex]\pi \ rad = \dfrac{2 \pi}{8}+ \Delta \phi_o[/tex]

[tex]\pi \ rad = \dfrac{ \pi}{4}+ \Delta \phi_o[/tex]

[tex]\Delta \phi_o = \pi -\dfrac{ \pi}{4}[/tex]

[tex]\Delta \phi_o = \dfrac{ 4\pi - \pi}{4}[/tex]

[tex]\Delta \phi_o = \dfrac{ 3\pi}{4} \ rad[/tex]

Suppose both speakers are placed side-by-side, then the path difference between the two speakers is: Δx = 0 cm

Thus, we have:

[tex]\Delta \phi = \dfrac{2 \pi}{\lambda}\Delta x + \Delta \phi_o[/tex]

[tex]\Delta \phi = \dfrac{2 \pi}{\lambda}(0 \ cm ) + \dfrac{3 \pi}{4} \ rad[/tex]

[tex]\Delta \phi = \dfrac{3 \pi}{4} \ rad[/tex]

∴

The amplitude of the sound wave if the two speakers are placed side-by-side is:

[tex]A = 2a \ cos \bigg (\dfrac{\Delta \phi }{2} \bigg)[/tex]

[tex]A = 2a \ cos \bigg (\dfrac{\dfrac{3 \pi}{4} }{2} \bigg)[/tex]

[tex]A = 2a \ cos \bigg ({\dfrac{3 \pi}{8} } \bigg)[/tex]

A = 0.765a

The expressions for sound interference allows to find the amplitude for the wave when the two speakers are together is:

Given parameters

To find

The interference phenomenon occurs when two coherent waves have paths of different lengths to reach a point, we have two extreme cases:

                        Δr = [tex]2n \ \frac{\lambda}{2}[/tex]  

                        Δr = [tex](2n+1) \ \frac{\lambda}{2}[/tex]  

Where Δr₁ and Δr₂ are the path difference, λ is the wavelength and n is an integer.

Let's start by looking for the wavelength that the speakers emit, see attached.

Destructive Interference       Δr₂ = (2n + 1) la / 2

Constructive interference    Δr₁ = 2n lam / s

Let's solve the system.

               Δr₂ - Δr₁ = [tex]\frac{\lambda}{2}[/tex]  

Let's calculate

              30 - (-10) = [tex]\frac{\lambda}{2}[/tex]  

              λ = 80 cm

Now we can use the general relation for the path change and the phase.

             [tex]\frac{\delta r}{\lambda } = \frac{\phi - \phi_o}{2\pi }[/tex]

             [tex]\phi = \frac{\Delta r \ 2\pi }{\lambda } + \phi_o[/tex]fi = Dr 2pi / lam + fio

Where [tex]\phi[/tex] is the possible initial phase difference between the speakers.

Let's find the initial phase difference emitted by the two speakers, let's use destructive interference, for which the phase difference is:

             [tex]\phi = \pi \ rad[/tex]  

Let's calculate

             [tex]\pi = \frac{2\pi }{80} \ 10 + \phi_o \\\phi_o = \pi - \frac{\pi}{4}[/tex]

              [tex]\phi_o[/tex]  = ¾ [tex]\pi[/tex] rad

This value is kept constant, let's find the phase angle for when the speakers are together, so the path difference is zero Δr = 0      

            [tex]0= \frac{\phi - \phi_o}{2\pi }\\\phi = \phi_o[/tex]

            [tex]\phi[/tex] = ¾ pi

The amplitude of the sound wave is

            A = 2a cos [tex]\frac{\phi}{2}[/tex]  

            A = 2a cos ⅜ π

           A = 0.765 a

In conclusion using the expression for sound interference we can find the amplitude for the wave when the two speakers are together is:

           A = 0.765a

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Electromagnetic powers versus Molecules:  

Electrons are kept in the circle around the core by the electromagnetic power, in light of the fact that the core in the focal point of the particle is decidedly charged and pulls in the contrarily charged electrons.  

Solid Nuclear power versus Molecules:  

The solid atomic power holds most standard issue together on the grounds that it limits quarks into hadron particles, for example, the proton and neutron.  

Feeble power versus Molecules:  

In atomic material science and molecule physical science, the frail cooperation, which is additionally frequently called the powerless power or feeble atomic power, is the instrument of communication between subatomic particles that is liable for the radioactive rot of iotas.  

Gravity Vs. Particles:  

Gravity influences molecules a similar way it influences all other issue. Each iota makes its own gravitational field which draws in all other issue known to man.

Answer:

F = 5.9 N

Explanation:

Given that,

Mass of water, m₁ = 1000 kg

Mass of the Sun, [tex]m_2=1.99\times 10^{30}\ kg[/tex]

Distance between two bodies, [tex]r=1.5\times 10^{11}\ m[/tex]

We need to find the force of gravity between water and the Sun. The formula for the gravitational force between two bodies is given by :

[tex]F=G\dfrac{m_1m_2}{r^2}\\\\F=6.67\times 10^{-11}\times \dfrac{1000\times 1.99\times 10^{30}}{(1.5\times 10^{11})^2}\\\\F=5.89\ N[/tex]

or

F = 5.9 N

Hence, the correct option is (b).

Answer:

D. A difference in resistance

Answer:

Hi. U should do like this

Answer:

3.335641 nanoseconds for meters

Answer:

Explanation:

The mass of the car can be found by using the formula

[tex]m = \frac{2k}{ {v}^{2} } \\ [/tex]

From the question we have

[tex]m = \frac{2 \times 300000}{ {20}^{2} } = \frac{600000}{400} = \frac{6000}{4} \\ [/tex]

We have the final answer as

Hope this helps you

jsjshebsjsusunxndj 78

Answer:The answer is circular orbits I hope this helps

Explanation:

Answer:

Explanation:

(b) The initial velocity is added to that due to acceleration by gravity. The velocity is increased linearly by gravity at the rate of 9.8 m/s². The average velocity of the pebble will be its velocity halfway through the 2-second time period.* That is, it will be ...

  4 m/s + (9.8 m/s²)(2 s)/2 = 13.8 m/s . . . . average velocity

__

(a) The distance covered in 2 seconds at an average velocity of 13.8 m/s is ...

  d = vt

  d = (13.8 m/s)(2 s) = 27.6 m

The water is about 27.6 m below ground.

_____

* We have chosen to make use of the fact that the velocity curve is linear, so the average velocity is half the sum of initial and final velocities:

  vAvg = (vInit + vFinal)/2 = (vInit + (vInit +at))/2 = vInit +at/2

__

If you work this in a straightforward way, you would find distance as the integral of velocity, then find average velocity from the distance and time.

  [tex]\displaystyle d=\int_0^t{(v_0+at)}\,dt=v_0t+\dfrac{1}{2}at^2=t\left(v_0+a\dfrac{t}{2}\right)\\\\v_{avg}=\dfrac{d}{t}=v_0+a\dfrac{t}{2}\qquad\text{the formula we started with}[/tex]

The answer is infrared.

Answer:

The force must increase

Explanation:

According to newton's second law "force is the product of mass and acceleration".

      Force  = mass  x acceleration

Now, the mass of the sports car is lesser compared to that of the truck. Therefore, to take both automobiles to the same speed, enough force must be applied by the engine of the truck.

There must be an increase in the force in order to make both automobiles attain the same speed.

Answer:

27000 J

Explanation:

Answer:

37.5 N*m

Explanation:

w=fd

w=?

f=25 N

d=1.5 m

w=25N*1.5m=37.5 N*m

Answer:

Abiotic referfers to non-living and biotic factors are living or once living

Explanation:

Answer:it’s the graph starts on the origin but is going down

Explanation: khan academy

Answer:

Oppenheimer suggested that the bomb laboratory operate secretly in an isolated area but allow free exchange of ideas among the scientists on the staff.

Explanation:

Answer:

The answer is "[tex]\boxed{\boxed{\omega = \sqrt{\frac{2fd}{kmr^2}}}}[/tex]"

Explanation:

[tex]\to d= r \theta \\\\ \to \theta =\frac{d}{r}\\\\\to \omega^{r} - \omega_{0}^{r} = 2 \alpha \theta\\\\\to \omega^{r} = 2 \alpha \theta - \omega_{0}^{r} \\\\\to \omega^{r} = 2 (\frac{F}{Kmr}) \frac{d}{r}\\\\\to \omega = \sqrt{\frac{2fd}{kmr^2}}[/tex]

The angular velocity of the wheel is  [tex]\omega=\sqrt{\frac{Fd}{mkr^2} }[/tex]

Given that the force applied is F, and the displacement of the string is d.

If the radius of the wheel is r and the wheel has an angular displacement of θ, then:

d = rθ

θ = d/r

now, the angular acceleration is given by:

α = F/mkr

The initial angular velocity will be zero and let the final angular velocity is ω.

According to the third equation of motion:

ω² = 0 + 2αθ

ω² = 2(F/mkr)(d/r)

[tex]\omega=\sqrt{\frac{Fd}{mkr^2} }[/tex]

Learn more about angular velocity:

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Answer:

The kinetic coefficient of friction of the sled on the snow is 0.05

Explanation:

The given parameters are;

The weight of the sled Jill is pulling, W = 200 N

The force with which Jill is pulling the the sled = 10 Newtons

The nature of the speed with which the sled is pulled = Constant speed

Therefore, given that the only opposing force to the pulling of the sled = The force of kinetic friction, we have;

The force with which Jill is pulling the the sled = 10 Newtons = The force of kinetic friction, [tex]F_k[/tex]

The force of kinetic friction = The weight of the sled, W × The kinetic coefficient of friction of the sled on the snow, [tex]\mu _k[/tex]

[tex]F_k[/tex] = W × [tex]\mu _k[/tex]

[tex]\mu _k[/tex] = [tex]F_k[/tex]/W = 10 N/(200 N) = 0.05

The kinetic coefficient of friction of the sled on the snow = [tex]\mu _k[/tex] = 0.05.

Answer:

k nishant

Explanation:

the answer is option B

Answer:

nitric acid

Explanation:

because it is a solvent

Answer:

acetic acid

Explanation:

Not sure but I think so :) hope its right and helps