Daisy estimated a certain expression to have a value of 300. Which of these
expressions could be the one Daisy estimated?
Select the two that apply.
A. 10x2
B. 30x2
C. 100x
D. 300
E. (5x)?

Answers

Answer 1

Answer:

C and D

Step-by-step explanation:

C). With the X right by the 100 means that it could be anything there, so you would put a 3 at the end so then 100 x 3 = 300.
D). The value is already 300 so no need to do work there.

Answer 2

Using Multiplication, 100 × 3 is this expressions could be the one daisy estimated.

What is multiplication?

Multiplication is an "operation that represents the basic idea of repeated addition of the same number. The numbers that are multiplied are called the factors and the result that is obtained after the multiplication of two or more numbers is known as the product of those numbers".

According to the question.

Daisy estimated a certain expression to have a value is 300 using Multiplication we have,

100 × x =300

x = 300/100

x = 3.

Hence, 100 × 3 is this expressions could be the one daisy estimated using Multiplication.

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Related Questions

Samantha bought a purse for $72.25. It normally sells for $91.89. How much money did she save?

Answers

Answer:

19.64$

Step-by-step explanation:

91.89-72.25

Answer:

$19.64

Step-by-step explanation:

Work out the size of angle EDF, giving a reason for your answer

Answers

Answer:

∠ EDF = 23°

Step-by-step explanation:

angles on the circumference of a circle ( inscribed angles) subtended by the same arc are congruent.

∠ FGE and ∠ EDF are inscribed angles subtended by arc EF

then ∠ EDF = ∠ FGE = 23°

A circle is a curve sketched out by a point moving in a plane so that its distance from a given point is constant. The size of ∠EDF is 23°.

What is a circle?

A circle is a curve sketched out by a point moving in a plane so that its distance from a given point is constant; alternatively, it is the shape formed by all points in a plane that are at a set distance from a given point, the centre.

As it is known that the angles made from the same chord in a circle are of equal measurement.

Since EF is the chord of the circle and the measure of ∠EGF is 23°, the measure of ∠EDF will be 23° as well.

Hence,  the size of ∠EDF is 23°.

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A water tank has a radius 5 feet and height 11 feet. How much water can it hold?

Answers

Answer:

I think it is 275πcm^3 or 863.94cm^3

Step-by-step explanation:

please correct me if I'm wrong

if u want to u can answer question 16 and 17 but if u don’t just answer 16

Answers

Answer:

the answer to 16 is C i know cause i had the same thing and the answer for 17 is A.

Step-by-step explanation:

Hope thi helps

8.
A circular plate has a diameter of 11 inches. An ant walking along the edge makes 1.5 revolutions in 4
minutes. Approximately how many inches does the ant travel in one minute? Round your answer to the
nearest tenth of an inch.

Answers

Answer:

[tex]12.95 \: inches[/tex]

Step-by-step explanation:

We were told that the diameter of the circular plate is 11 inches. In order to find the distance the ants travel to make one revolution we have to first find the circumference of the circular plate. Circumference is:

[tex]2\pi \: r[/tex]

The radius would be half of the diameter (11). Therefore the radius is 5.5.

[tex]r = 5.5 \: \: \: \: \: \pi = 3.14 \\ cir = 2(3.14) \: (5.5) \\ cir = 6.28 \times 5.5 \\ cir = 34.54[/tex]

Since we found the circumference of the circular plate that means that we know how much one revolution made by the ants would be (34.54). Since the ant made 1.5 revolutions we have to multiply 34.54 by 1.5.

[tex]34.54 \times 1.5 = 51.81[/tex]

So we now know that the ant walked 51.81 inches in 4 minutes, now we have to find the distance he would walk in 1 minute.

Let x be the unknown value*

[tex] 51.81 \:inches = 4 \:minutes \\ x \:inches = 1 \: minutes\\ \\ 51.81=4x \\ \\\frac{51.81}{4} = x \\ \\ 12.95 = x[/tex]

If alpha and beta are zeroes of polynomial fx = 4x2-5x-1. Pls answer full questiob

Answers

...................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................................I like 15 yr old girls.

There are three sets. A = {1,2,3}, B = {4,5} and C = {6,7,8}

What is the probability of A∩B∩C

Answers

The three sets are independent sets and the value of the probability of A∩B∩C is: 0

How to determine the probability?

The sets are given as:

A = {1,2,3}, B = {4,5} and C = {6,7,8}

The total number of elements in the three sets is:

Total = 8

The number of elements of A∩B∩C is 0, because the sets do not have a common element.

So, the probability of A∩B∩C is:

P = 0/8

Evaluate

P = 0

Hence, the probability of A∩B∩C is: 0

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Can someone please help me

Answers

Answer:

1. a=3

2. a=3

3. a=9

Step-by-step explanation:

1. 9/a+9-4=12-56/8+3

We move all terms to the left:

9/a+9-4-(12-56/8+3)=0

Domain of the equation: a=0

a∈R

We add all the numbers together, and all the variables

9/a+9-4-8=0

We add all the numbers together, and all the variables

9/a-3=0

We multiply all the terms by the denominator

-3*a+9=0

We add all the numbers together, and all the variables

-3a+9=0

We move all terms containing a to the left, all other terms to the right

-3a=-9

a=-9/-3

a=+3

Find the zeroes of the polynomial 100x^2 - 81

Answers

Answer:

x = ±0.9

Step-by-step explanation:

The algebraic identity to be used here :

a² - b² = (a + b)(a - b)

We know that :

100x² = (10x)²81 = 9²

Therefore,

100x² - 81 (10x + 9)(10x - 9)

The zeros are :

10x + 9 = 0 ⇒ 10x = -9 ⇒ x = -9/10 ⇒ x = -0.910x - 9 = 0 ⇒ 10x = 9 ⇒ x = 9/10 ⇒ x = 0.9

Answer:

[tex]x=-\dfrac{9}{10} \quad x=\dfrac{9}{10}[/tex]

Step-by-step explanation:

[tex]\begin{aligned}100x^2-81 & =(10^2)x^2-9^2\\ & = (10x)^2-9^2\end{aligned}[/tex]

[tex]\textsf{Difference of Two Squares Formula}: \quad a^2-b^2=\left(a+b\right)\left(a-b\right)[/tex]

[tex]\implies a=10x \: \textsf{ and } \: b=9[/tex]

[tex]\implies 100x^2-81=(10x+9)(10x-9)[/tex]

[tex]\begin{aligned}\textsf{To find the zeros}: \quad 100x^2-81 & = 0\\\\\implies (10x+9)(10x-9) & =0\\\implies 10x+9 & =0 \implies x=-\dfrac{9}{10}\\\implies 10x-9 & =0 \implies x=\dfrac{9}{10}\end{aligned}[/tex]

Write a problem that can be
solved using a line plot. Draw and label the
line plot and solve the problem.

Answers

Answer:

0/5 1/5 2/5 3/5 4/5 5/5  hope this helps

what is the gfc of 8 and 24

Answers

the greatest common factor is 8

The radius of circle a is 5 cm. the radius if circle b is 5 cm greater than the radius of circle a. the radius of circle c is 3 cm greater than the radius of circle b. the radius of circle d is 1 cm less than the radius of circle c. what is the area of each circle? how many times greater than the area of circle a is the area of circle d? the area of circle a is ___ cm2.

Answers

Answer:

Theres a lot going on in this question but i tried my best to answer it all, correctly. Sorry if something is wrong or i misread the question. check explanation for answer.

Step-by-step explanation:

I'm not sure to use pi or 3.14 so i just did both.

Circle A's radius = 5cm

Circle B's radius = 10cm

Circle C's radius = 13cm

Circle D's = 12cm

(circle A)

π = 3.14

A = πr²

A = 3.14(5²)

A = 3.14(25)

A = 78.5cm²

π = π

A = πr²

A = π(5²)

A = π(25)

A = 78.54cm²

(circle B)

π = 3.14

A = πr²

A = 3.14(10²)

A = 3.14(100)

A = 314cm²

π = π

A = πr²

A = π(10²)

A = π(100)

A = 314.16cm²

(circle C)

π = 3.14

A = πr²

A = 3.14(13²)

A = 3.14(169)

A = 530.7cm²

π = π

A = π(13²)

A = π(169)

A = 530.9cm²

(circle D)

π = 3.14

A = πr²

A = 3.14(12²)

A = 3.14(144)

A = 452.2cm²

π = π

A = πr²

A = π(12²)

A = π(144)

A = 452.4cm²

452.2 / 78.5 =5.8

circle d is 5( almost 6) times greater than circle A

Can someone help me with this

Answers

Ans57 , 58 , 59

Step-by-step explanation:

Select all the correct answers.

If the measure of angle is 0 is 7pi/4, which statements are true?
The measure of the reference angle is 45°.
The measure of the reference angle is 30°.
tan(0) = -1
The measure of the reference angle is 60°.
cos(0) = -√2/2
sin(0) = -√2/2

Answers

The statement(s) that are true is that the measure of the reference angle is 45°.

What is the conversion of radians to degrees?

The conversion of an angle in radian to a degree can be determined by the multiplication of the given angle in radian by 180/π.

From the given information:

[tex]\mathbf{\theta = \dfrac{7 \pi}{4}}[/tex]

To degrees, we have:

[tex]\mathbf{\theta = \dfrac{7 \pi}{4} \times \dfrac{180}{\pi}}[/tex]

[tex]\mathbf{\theta =315^0}[/tex]

A reference angle is an angle that measures the remaining distance (called the terminal distance) to the x-axis.

315° is in the 4th quadrant, i.e.

= 360° - 315°

= 45°

Therefore, the statement(s) that is true is:

The measure of the reference angle is 45°.

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Answer:

sin(0)=-√2/2

tan(0) = -1

The measure of the reference angle is 45°

Step-by-step explanation:

I took the test

x² + y² = 8
x - y = 0
Select all of the following that are solutions to the system shown.
O (2, 2)
O (2,-2)
O (-2,2)
0 (-2,-2)

Answers

Answer:

[tex](2,2)~ \text{and}~ (-2,-2)[/tex]

Step by step explanation:

[tex]x^2 +y^2 =8~~~~~~...(i)\\\\x-y=0~~~~~~~~~...(ii)\\\\\text{From (ii):}\\\\x-y = 0 \implies x = y\\\\\text{Substitute x = y in eq (i):}\\\\~~~~~~y^2 +y^2 =8\\\\\implies 2y^2 = 8\\ \\\implies y^2 = \dfrac 82\\\\\implies y^2 = 4\\\\\implies y = \pm\sqrt 4\\\\\implies y = \pm 2\\\\\text{Substitute y = x in equation (i):}\\ \\~~~~~~x^2 +x^2 = 8\\ \\\implies 2x^2 = 8\\\\\implies x^2 = \dfrac 82\\\\\implies x^2 = 4\\\\\implies x = \pm\sqrt 4\\\\\implies x = \pm2\\\\[/tex]

[tex]\text{Hence,}~ (x,y) = (\pm2, \pm 2)[/tex]

use Demoiure's Theorem to find (-2-2√3i)³

Answers

Let z = -2 - 2√3 i.

Find the modulus of z :

|z| = √((-2)² + (-2√3)²) = √16 = 4

Find the argument of z (note that z lies in the third quadrant):

arg(z) = arctan(2√3/2) - π = arctan(√3) - π = -2π/3

Then in polar form, we have

[tex]z = -2 - 2\sqrt 3\, i = 4 \exp\left(-i\dfrac{2\pi}3\right)[/tex]

By DeMoivre's theorem, the cube of z is

[tex]z^3 = \left(4 \exp\left(-i\dfrac{2\pi}3\right)\right)^3 = 4^3 \exp(-i 2\pi) = \boxed{64}[/tex]

A piece of ribbon is 63 inches long. it is cut into pieces that are each 7 inches long. how many pieces of ribbon are there?

Answers

63/7 = 9

Answer is 9 ribbons

Which graph represents the function 3x – 2y = 6?

Answers

Answer:

graph 19 because since it is that means also like the thingy equals that number si then like when the thing is at the highest point it cab maybe actually it will equal that number

I need help!! Thanks

Answers

[tex]\text{Given that,}~ f(x) = 3x+5~ \text{and}~ g(x)=\sqrt{x^2 +3}\\\\(g \circ f)(-1)\\\\=g(f(-1))\\\\=g(3(-1) +5)\\\\=g(-3+5)\\\\=g(2)\\\\=\sqrt{2^2+3}\\\\=\sqrt{4+3}\\\\=\sqrt{7}[/tex]

The equation of the trend line is y = -0.36x + 12.6 use the equation to of the trend line to predict the wind chill for a wind speed of 23 mi/h round your answer to the nearest degree. The wind chill at 23 mi/h​

Answers

Answer:

4°C

Explanation:

Equation: y = -0.36x + 12.6

To find wind chill at 23 mi/hInsert x = 23

Simplify

y = -0.36(23)+12.6

y = 4.32°C

y = 4°C       (rounded to nearest degree)

find arc JK

BRAINLIEST,POINTS,THANKS AND RATING GIVEN!!!

Answers

Answer:

164°

Step-by-step explanation:

By the property of intersecting chords, we have:

[tex]m\angle JNK =\frac{1}{2}[m\widehat {JK}+m\widehat{LM}][/tex]

[tex]\implies 2*125\degree =(7x+31)\degree+86\degree[/tex]

[tex]\implies 250\degree =(7x+31)\degree+86\degree[/tex]

[tex]\implies 250\degree -86\degree=(7x+31)\degree[/tex]

[tex]\implies 164\degree=(7x+31)\degree[/tex]

[tex]\implies 164=7x+31[/tex]

[tex]\implies 164-31=7x[/tex]

[tex]\implies 133=7x[/tex]

[tex]\implies x = \frac{133}{7}[/tex]

[tex]\implies x = 19[/tex]

[tex]m\widehat{JK}=(7x+31)\degree [/tex]

[tex]\implies m\widehat{JK}=(7*19+31)\degree [/tex]

[tex]\implies \huge{\orange{m\widehat{JK}=164\degree}} [/tex]

6. Which statement is justified by the
transitive property of equality?
F. (x+y)+ z = x + (y+z)
G. If 7x = 14, then 14 = 7x
H. If -3x = y, and y = 8z, then -3x = 8z
J. x(y-z) = xy - xz

Answers

Answer:

h

Step-by-step explanation:

Please help. I dont understand a thing. lol

Answers

Answer:

39 in²

Step-by-step explanation:

Area of triangle = 1/2 * b * h, where,

b = Base of Triangle

h = Height of triangle

Area of 4 triangles = 4 * 1/2 * 3 in * 5in

Area of 4 triangles = 2 * 3 in * 5 in

Area of 4 triangles = 30 in²

Area of square = a², where,

a = Each side of square.

Area of square = (3 in) ²

Area of square = 9 in²

Total surface area of pyramid = 30 inch² + 9 inch²

Total surface area of pyramid = 39 in²

Answer:

39 in^2 (Please mark me brainliest)

Step-by-step explanation:

3*3+3*2*5

=39

What is the percent change 3.9 to 0

Answers

Answer:

a decrease of 100%

Step-by-step explanation:

im not fully sure butni hope it helps

PLEASE HELP ILL MARK BRAINEST!!!!

Answers

Answer:

1, 6, 11, and 16 in that order

Step-by-step explanation:

every time the x value increases by 1, the f(x) value increased by 5

Its a math problem Please help me !!! For the data sets below, which of the following statements is FALSE?

Answers

Answer:

fist bubble i am pretty sure

Step-by-step explanation:

Which of the following has the same value as the expression?

(-3+5)+2

Answers

Answer:

Answer(s):

1x4

2+2

2x2

Step-by-step explanation:

Hope this helps!

HELP I DONT GET THIS AND ITS DUE IN AN HOUR! PLEASE SHOW YOUR WORK IN PART B BECAUSE I DONT KNOW WHAT TO DO! I’LL GIVE BRAINLIEST AND 20 POINTS!!

Last year’s winner set a school record by completing 37 sit-ups. Amelia wants to know how many weeks she will need to train to beat this record.

Part A

Why is Amelia’s goal of breaking the school record best described by an inequality? Explain.

Part B

Write the inequality and graph the solution. How many weeks of training
will it take for Amelia to beat the record? Show your work.

Answers

An inequality is used to show two values that are different and to show that the two values are unequal.

What is an Inequality?

This refers to the mathematical relation that is used to show the comparison between two numbers that are unequal.

We can note that because there is a previous record, for a person to beat the record, he would have to perform better than the record and be faster than the previous record holder.

Therefore, if a record of Amelia was given, this would be used to find the relation between her record and the current record of 37 sit-ups and how many weeks of training would be needed to break the record.

Hence, we can see that the question is incomplete so I gave you a general overview to help you get a better understanding.

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Two paper cones are mathematically similar. The capacity of the larger cone is 8 times the capacity of the smaller cone. The surface area of the smaller cone is 50 cm². Find the surface area of the larger cone.​

Answers

Answer:

  200 cm²

Step-by-step explanation:

The scale factor for areas of similar figures is the square of the scale factor relating their linear dimensions. For volumes of similar figures, the scale factor is the cube of the linear dimension scale factor. Together, these relations mean the area scale factor is the 2/3 power of the area scale factor.

__

The larger surface area is ...

  (50 cm²) × 8^(2/3) = (50 cm²) ×4 = 200 cm²

_____

Additional comment

The linear dimension scale factor is the cube root, or 1/3 power, of the volume scale factor. The area scale factor is the square of that or the 1/3 power times 2, the 2/3 power.

  sf = ∛(v2/v1) = (v2/v1)^(1/3)

  a2/a1 = sf^2 = ((v2/v1)^(1/3))^2 = (v2/v1)^(2/3)


A truck's engine needs 1 gallons of oil for an oil change. How many quarts of oil are needed? (Hint: 1 quart
gallon)

Answers

Answer:

4 quarts

Step-by-step explanation:

1 gallon is equal to 4 quarts

Other Questions
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