To find the total transportation cost, the allocation cost for each cell is multiplied by the unit cost, and the sum is taken. The sum of these costs is $12,800.
Transportation Problem: A manufacturing firm has three warehouses supplying to four retail outlets. The following table shows the unit transportation costs (in $) from each warehouse to each outlet and the units of demand and supply at each location.
The transportation algorithm can be used to solve this problem with the Vogel approximation method being the starting solution. Below is the transportation table (in dollars):
| | Retail Outlet 1 | Retail Outlet 2 | Retail Outlet 3 | Retail Outlet 4 | Supply |
Warehouse 1 | 6 | 5 | 3 | 7 | 300 |
Warehouse 2 | 9 | 7 | 4 | 6 | 200 |
Warehouse 3 | 2 | 8 | 5 | 9 | 250 |
Demand | 200 | 150 | 100 | 200 | |
The Vogel approximation method is an iterative procedure that selects the smallest difference between the two smallest costs for each row or column and then assigns the maximum possible allocation to it.
Step 1:
Subtract the smallest cost from the second-smallest cost and record the differences for each row and column. The difference is written in the same row or column as the subtracted number. The differences are calculated as follows:
| | Retail Outlet 1 | Retail Outlet 2 | Retail Outlet 3 | Retail Outlet 4 | Supply |
Warehouse 1 | 6 | 5 | 3 | 7 | 300 |
Warehouse 2 | 9 | 7 | 4 | 6 | 200 |
Warehouse 3 | 2 | 8 | 5 | 9 | 250 |
Demand | 200 | 150 | 100 | 200 | |
The differences are as follows:
| | Retail Outlet 1 | Retail Outlet 2 | Retail Outlet 3 | Retail Outlet 4 | Supply |
Warehouse 1 | 1 | 2 | 0 | 4 | 300 |
Warehouse 2 | 3 | 1 | 0 | 2 | 200 |
Warehouse 3 | 3 | 1 | 0 | 4 | 250 |
Demand | 200 | 150 | 100 | 200 | |
Step 2:
Identify the largest difference for each row or column and then select the smallest number in that row or column for the next allocation. The Vogel approximation method is used to determine the maximum allocation for that row or column. The total cost is then multiplied by the unit cost. The table below shows the maximum allocation and cost for each row or column.
The cost of transportation is shown below:
| | Retail Outlet 1 | Retail Outlet 2 | Retail Outlet 3 | Retail Outlet 4 | Supply |
Warehouse 1 | 6 | 5 | 3 | 7 | 300 |
Warehouse 2 | 9 | 7 | 4 | 6 | 200 |
Warehouse 3 | 2 | 8 | 5 | 9 | 250 |
Demand | 200 | 150 | 100 | 200 | |
To find the total transportation cost, the allocation cost for each cell is multiplied by the unit cost, and the sum is taken. The sum of these costs is $12,800.
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The final solution to the given transportation problem, with a minimum cost of 2050 units, is shown below:
D1 | D2 | D3 | D4 | S1 | 30 | 20 | 30 | 20 | S2 | 0 | 60 | 20 | 30 | S3 | 10 | 0 | 10 | 40 | Total Cost | 1800 | 600 | 650 | 2050 |
Explanation:
A transportation problem is one of the most fundamental optimization problems that exist. In this problem, goods are transported from various supply sources to various demand locations in the most efficient and cost-effective manner possible. When demand and supply quantities are known, transportation issues occur.
Let us now build a transportation problem with at least four demand and three supply units. We'll solve it using the transportation algorithm, and we'll use the Vogel App method to begin.
The problem is as follows:
Let us suppose that there are three factories (supply locations), S1, S2, and S3, and four warehouses (demand locations), D1, D2, D3, and D4. The supply amounts available at each factory and the requirements of each warehouse are shown below.
Supply (units) | Demand (units) | S1 | S2 | S3 | D1 | 60 | 30 | 40 | 50 | D2 | 30 | 70 | 20 | 30 | D3 | 40 | 20 | 10 | 40 | D4 | 20 | 60 | 30 | 10 |
To begin, let us generate the initial table below, which includes the amount of units available from each source to each destination.
Supply (units) | Demand (units) | S1 | S2 | S3 | Availability | D1 | 60 | 30 | 40 | 130 | D2 | 30 | 70 | 20 | 120 | D3 | 40 | 20 | 10 | 70 | D4 | 20 | 60 | 30 | 110 |
Requirement | 50 | 30 | 40 | 120 |
We'll begin by calculating the difference between the two smallest costs for each supply and demand row. Then we'll choose the row with the biggest difference as our starting point.
In this case, the differences for the supply rows are:
Supply (units) | Demand (units) | S1 | S2 | S3 | Availability | D1 | 60 | 30 | 40 | 130 | 20 | D2 | 30 | 70 | 20 | 120 | 30 | D3 | 40 | 20 | 10 | 70 | 10 | D4 | 20 | 60 | 30 | 110 | 20 |
Requirement | 50 | 30 | 40 | 120 |
Difference | 10 | 20 | 30 | |
We'll choose the third row (supply from S3) as our starting point since it has the largest difference of 30. We'll provide as much as possible to the minimum cost cell (D2, S1), which is 20. We'll update the availability column and the demand row and cross out the cell.
D1 | D2 | D3 | D4 | S1 | 40 | 0 | 40 | 20 | S2 | 30 | 70 | 20 | 30 | S3 | 0 | 0 | 0 | 50 |
Availability | 20 | 50 | 10 | 90 |
Requirement | 50 | 10 | 40 | 120 |
We'll now update the differences based on the available cells (we only have two remaining).
Supply (units) | Demand (units) | S1 | S2 | S3 | Availability | D1 | 40 | 0 | 40 | 110 | 20 | D2 | 0 | 50 | 0 | 100 | 10 | D3 | 40 | 20 | 10 | 70 | 10 | D4 | 20 | 10 | 30 | 100 | 20 |
Requirement | 50 | 20 | 40 | 120 |
Difference | 10 | 40 | 20 | |
The second row (supply from S2) has the largest difference, so we'll select it.
The minimum cost cell with the highest availability is (D2, S3), and we'll give it as much as possible (10).
D1 | D2 | D3 | D4 | S1 | 40 | 10 | 30 | 20 | S2 | 30 | 60 | 20 | 30 | S3 | 0 | 0 | 10 | 40 |
Availability | 20 | 40 | 0 | 80 |
Requirement | 50 | 30 | 40 | 120 |
We'll now update the differences based on the available cells (we only have one remaining).
Supply (units) | Demand (units) | S1 | S2 | S3 | Availability | D1 | 40 | 0 | 30 | 110 | 20 | D2 | 0 | 60 | 0 | 90 | 20 | D3 | 30 | 20 | 0 | 50 | 10 | D4 | 20 | 0 | 10 | 90 | 30 |
Requirement | 50 | 0 | 40 | 120 |
Difference | 10 | 10 | 10 | |
There is only one available row left, so we'll select the first one and provide as much as possible to the minimum cost cell (D1, S2), which is 10.
We'll cross it out and update the availability and demand rows.
D1 | D2 | D3 | D4 | S1 | 30 | 20 | 30 | 20 | S2 | 30 | 50 | 20 | 30 | S3 | 0 | 0 | 10 | 40 |
Availability | 10 | 30 | 0 | 60 |
Requirement | 40 | 0 | 40 | 120 |
The final solution, with a minimum cost of 2050 units, is shown below:
D1 | D2 | D3 | D4 | S1 | 30 | 20 | 30 | 20 | S2 | 0 | 60 | 20 | 30 | S3 | 10 | 0 | 10 | 40 | Total Cost | 1800 | 600 | 650 | 2050 |
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Please show that a code of distance 2t + 1 can correct t or
fewer transmission errors when the minimum distance decoding
criteria is considered.
A code with distance 2t + 1 can correct t or fewer errors using the minimum distance decoding criteria.
When considering the minimum distance decoding criteria, a code with a minimum distance of 2t + 1 can correct t or fewer transmission errors.
The minimum distance of a code refers to the smallest number of bit flips or symbol errors needed to transform one valid codeword into another. In this case, the distance is 2t + 1, which means that any two valid codewords in the code will have a minimum Hamming distance of at least 2t + 1.
By choosing the minimum distance decoding criteria, the decoder can identify and correct up to t or fewer transmission errors. This is because if the received codeword differs from the transmitted codeword by t or fewer errors, it will still be closer to the intended codeword than any other codeword in the code.
Therefore, the decoder can successfully correct these errors and recover the original transmitted message.
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How do we find the factors of x2 – 64
Find numbers that multiply to be O but adds to be -64
O Find numbers that multiply to be 1 but adds to be -64
Find numbers that multiply to be -64 but adds to be 1
Find numbers that multiply to be -64 but adds to be 0
Answer:
The factors of x²-64 is equal to (x-8)(x+8).
Step-by-step explanation:
The given expression is:
x²-64
we know that, 8² = 64
So,
(x²-8²) = (x-8)(x+8) [As (a-b)(a+b) = a²-b²]
So, the factors of x²-64 i equal to (x-8)(x+8).
Find a sufficient statistics for 8. Problem 7 Let X₁.... X be iid according to a uniform continuous distribution over the open interval (0,0+1), for 0> 0. Find a minimally sufficient statistics for 0.
Given that X₁, X₂, ..., Xₙ are iid according to a uniform continuous distribution over the open interval (0,0+1).
Now, we have to find a sufficient statistics for 8.Let T = ∑Xᵢ, then T ~ U(n*0,n).Thus, T is a sufficient statistic for θ.Hence, T is a sufficient statistics for 8.
Given that X₁, X₂, ..., Xₙ are iid according to a uniform continuous distribution over the open interval (0,0+1).
We have to find a minimally sufficient statistics for
Let T = (X(n), X(1)), where X(n) = max{X₁,X₂, .... Xₙ} and X(1) = min{X₁,X₂, .... Xₙ}.As Xᵢ follows uniform distribution, so T can take any value in [0, 1].
Let Y = nX(n)/(1-X(n)), thenY = (nX(n))/(1-X(n)) = (nX(n))/(X(n)-X(1)) = 1/[(X(n)-X(1))/n].Now, 0 < X(1) ≤ X(n) < 1. Therefore, 0 < (X(n)-X(1))/n ≤ 1/n. Then, Y takes values in [0,∞).Thus, Y is a one-to-one function of T.
Hence, T is a minimally sufficient statistics for 8.
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A cubic polynomial with a critical point at x=2, an inflection point at (1,4), and a leading coefficient of 1
If a critical point at x=2, an inflection point at (1,4), and a leading coefficient of 1, the final formula for the cubic polynomial is f(x) = x³ - 3x² + 12x - 6.
To find the formula for a cubic polynomial with specific properties, we can start by considering the critical point and the inflection point.
Given that the critical point is at x = 2, we know that the derivative of the cubic polynomial should be equal to zero at x = 2. This means that the slope of the polynomial at x = 2 is zero. Taking the derivative of the cubic polynomial, we have:
f'(x) = 3ax² + 2bx + c.
Setting this equal to zero and substituting x = 2, we get:
3a(2)² + 2b(2) + c = 0.
12a + 4b + c = 0.
Now, let's consider the inflection point at (1,4). We know that the second derivative of the cubic polynomial should be zero at x = 1. Taking the second derivative, we have:
f''(x) = 6ax + 2b.
Setting this equal to zero and substituting x = 1, we get:
6a(1) + 2b = 0.
6a + 2b = 0.
Solving the system of equations consisting of 12a + 4b + c = 0 and 6a + 2b = 0, we find a = -1/2, b = 3/2, and c = -6.
Therefore, the formula for the cubic polynomial is:
f(x) = -1/2x³ + 3/2x² - 6x + d.
The leading coefficient is 1, so we have:
f(x) = x³ - 3x² + 12x + d.
To determine the value of d, we can use the fact that the inflection point is (1,4). Substituting x = 1 and y = 4 into the equation, we get:
4 = 1 - 3 + 12 + d.
4 = 10 + d.
d = -6.
Therefore, the final formula for the cubic polynomial is:
f(x) = x³ - 3x² + 12x - 6.
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Complete question is:
Find the formula for a cubic polynomial, ax³+bx²+cx+d, with a critical point at x=2, an inflection point at (1,4), and a leading coefficient of 1.
HELP HELP HELP HELP HEPL HELP
Answer:
The answer would be Y= 1/4X -3
Step-by-step explanation:
Hope it was helpful .
Good luck ^.^
please help me understand this.Will mark brainlyist to right answer no links!!!
A radiograph technician has a technique of 30 mAs and 120 kV at 100 cm SID with a 5:1 grid, and produces an intensity of 100 mR. If she wants to keep maintain exposure at: 200 cm, a 10:1 grid, with 138 kV , what should the new mAs be?
The new mAs should be approximately 45 mAs.
The intensity of radiation at a given distance can be calculated using the inverse square law:
Intensity2 = Intensity1 × (Distance1/Distance2)^2
Given:
Intensity1 = 100 mR
Distance1 = 100 cm
Distance2 = 200 cm
Using the above formula, we can calculate the new intensity at 200 cm:
Intensity2 = 100 mR × (100 cm/200 cm)^2
Intensity2 = 100 mR × (1/4)
Intensity2 = 25 mR
To maintain the same exposure at the new distance, the new mAs needs to be adjusted accordingly. We can use the exposure maintenance formula:
mAs2/mAs1 = (kVp2/kVp1) × (Distance1/Distance2)^2 × (Gridratio2/Gridratio1)^2
Given:
mAs1 = 30 mAs
kVp1 = 120 kV
kVp2 = 138 kV
Gridratio1 = 5:1
Gridratio2 = 10:1
Substituting the given values into the formula, we can solve for mAs2:
mAs2/30 mAs = (138 kV/120 kV) × (100 cm/200 cm)^2 × (10/5)^2
mAs2/30 mAs = (1.15) × (0.5)^2 × (4)
mAs2/30 mAs = 1.15 × 0.25 × 4
mAs2/30 mAs = 0.115
Simplifying, we find:
mAs2 = 30 mAs × 0.115
mAs2 ≈ 3.45 mAs
Therefore, the new mAs should be approximately 45 mAs (rounded to the nearest whole number) to maintain exposure at 200 cm with a 10:1 grid and 138 kV.
To maintain exposure at a new distance of 200 cm with a 10:1 grid and 138 kV, the radiograph technician should set the new mAs to approximately 45 mAs. This adjustment takes into account the changes in distance, kV, and grid ratio while ensuring that the radiation intensity remains consistent.
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Prove or disprove each of the following statements. (a) Let x be an integer. If 4x² + 3x + 7 is odd, then x must be even. (b) Let A, B and C be sets. If A - C ≤ B - C, then A ≤ B.
The statement is False.
(a) Let x be an integer. If 4x² + 3x + 7 is odd, then x must be even.Statement (a) is false.
Here is the explanation:We know that an integer is odd if and only if it can be represented in the form of 2k + 1, where k is any integer.Let us assume that x is an odd integer. Then, we can write x as 2k + 1, where k is any integer.Substituting the value of x in 4x² + 3x + 7, we get;4x² + 3x + 7 = 4(2k + 1)² + 3(2k + 1) + 7= 4(4k² + 4k + 1) + 6k + 3 + 7= 16k² + 16k + 4 + 6k + 10= 16k² + 22k + 14= 2(8k² + 11k + 7)which is an even integer as it is a multiple of 2.
Therefore, we have proven that if x is odd, then 4x² + 3x + 7 is even.So, we have disproved the statement as it is not true for all integers. It's only true for odd integers only. Therefore, statement (a) is false.
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When the data are interval, the parameters of interest are the population mean μ and the population variance σ².
state whether the following statement is True or False ( if false, motivate your answer).
The statement is true that:
When the data are interval, the parameters of interest are the population mean μ and the population variance σ² .
Given,
Mean and standard variance .
Here,
An interval estimator provides a range of values as an estimate of a parameter, considering uncertainty, while a point estimator provides a single value estimate. The Student's t-distribution is used when the population standard deviation is unknown, and the z-distribution is used when it is known.
Support for the statement:
True: When the data are interval, the parameters of interest are the population mean (μ) and the population variance (σ^2). The population mean represents the average value of the variable of interest in the population, while the population variance measures the variability or spread of the variable in the population.
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Marcie Ann Weber, age 32, takes out $15,000 of a term insurance for a ten year term.
a. annual premium: $ a0
b. monthly premium: $ a1
Answer:
Step-by-step explanation:
a. annual premium: 79.35
b. monthly premium: 7.14
Marcie Ann Weber, age 32, takes out $15,000 of a term insurance for a ten-year term. Annual premium = $1,500 per year and monthly premium = $125 per month.
What is division?One type of operation is division in mathematics. In this procedure, the phrases or numbers are divided into the same number of components.
Given: Marcie Ann Weber,
insured amount of term insurance plan = $15,000.
Number of year = 10 year
To find the amount of annual premium:
Divide the total insured amount by number of years.
Annual premium = Insured amount of term insurance plan / Number of year
Annual premium = $15,000 / 10
Annual premium = $1,500 per year
To find the amount of monthly premium:
Monthly premium = Insured amount of term insurance plan / Number of month in 10 year
Monthly premium = 15,000 / (10 x 12)
Monthly premium = 15,000 / 120
Monthly premium = $125 per month.
Therefore, annual premium = $1,500 per year and monthly premium = $125 per month.
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PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE PLEASE HELPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
The value of ∠FGJ = x⁰ is 45⁰.
What is Linear pair angle?Linear pair of angles are formed when two lines intersect each other at a single point. The angles are said to be linear if they are adjacent to each other after the intersection of the two lines. The sum of angles of a linear pair is always equal to 180°.
Here, we know that sum of angles on linear pair is 180⁰.
∠FGJ = x⁰ and ∠JGH = 135⁰
∠FGJ + ∠JGH = 180⁰
x⁰ + 135⁰ = 180⁰
x⁰ = 180⁰ - 135⁰
x⁰ = 45⁰
Thus, the value of ∠FGJ = x⁰ is 45⁰.
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what is the solution to the inequality of x+2<5
Answer:
Any number below 3
(2, negative infinity)
Answer:
here's the answer with steps
x + 2 < 5
-2 -2
x < 3
I am sorry i am wasting your time please help!
Step-by-step explanation:
True
false
false
true
i think its that I'm sorry if its wrong
Erika pours 6 cups of milk into 8 glasses. Each glass has the same amount of milk. How many cups of milk are in each glass?
Answer:
each glass will have 0.75 of a cup or 3/4 of a cup * 0.75 and 3/4 is the same*
how many total elements are in an array with 4 rows and 7 columns?
a. 4
b. 7
c. 28
d. 11
The total number of elements in an array is indeed equal to the product of its number of rows and columns. In this case, since the array has 4 rows and 7 columns, the total number of elements is 4 x 7 = 28.
The total number of elements in an array is equal to the product of its number of rows and columns. In this case, the array has 4 rows and 7 columns, so the total number of elements is:
4 x 7 = 28
Therefore, the answer is (c) 28.
The total number of elements in an array is indeed equal to the product of its number of rows and columns. In this case, since the array has 4 rows and 7 columns, the total number of elements is 4 x 7 = 28.
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define isometric angle
Answer:
it's just a angle that is 3D
Step-by-step explanation:
write an equation that states (x,y) is the same distance from (4,1) as it is from the x-axis.
The equation that states (x, y) is equidistant from (4, 1) and the x-axis is -8x - 2y + 17 = 0.
To express that the point (x, y) is equidistant from both the point (4, 1) and the x-axis, we can set up an equation using the distance formula.
The distance formula states that the distance between two points (x₁, y₁) and (x₂, y₂) is given by:
d = √((x₂ - x₁)² + (y₂ - y₁)²)
In this case, we want the distance from (x, y) to (4, 1) to be equal to the distance from (x, y) to the x-axis. The x-axis can be represented by the equation y = 0.
Let's set up the equation:
√((x - 4)² + (y - 1)²) = √((x - x)² + (y - 0)²)
Simplifying, we get:
√((x - 4)² + (y - 1)²) = √(x² + y²)
To remove the square roots, we can square both sides of the equation:
((x - 4)² + (y - 1)²) = (x² + y²)
Expanding and simplifying further, we have:
x² - 8x + 16 + y² - 2y + 1 = x² + y²
Combining like terms, we obtain:
-8x - 2y + 17 = 0
Therefore, the equation that states (x, y) is equidistant from (4, 1) and the x-axis is -8x - 2y + 17 = 0.
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Please help!!! I’ll mark you as brainliest!!!!!!
0.138613961 as a percent rounded to the nearest tenth
Answer:
13.9%
Step-by-step explanation :
Converting from a decimal to a percentage is done by multiplying the decimal value by 100 and adding %.
0.138613961 ------ when multiplying by 100 you move two spots the decimal point: 13.8613961 %
The tenth digit is 8 the number after that is 6
If the digit after tenth is greater than or equal to 5, add 1 to tenth. Else remove the digit.
6 is greater than 5 so we add 1 to 8 and becomes 9
If the digit after the tenth was 4 instead 6, for example,then it would be 13.8%
The Great Knightrola Small Monster Association has four chartered positions: President, Vice President, Treasurer, and Secretary; it also has 12 officers chosen at large. All of these seats must be filled by members of GKSMA, of which there are 50. No member may hold more than 1 position. How many different ways are there to fill the positions
Answer:
Number of different ways of filling the position is 8961115245946500
Step-by-step explanation:
There are total of 4 positions which can be arranged in 4! Ways
Like wise there are 12 positions. Hence the number of arrangements for these 12 positions would be 12!
Overall there are 12+4 = 16 positions in which 50 people needs to be arranged
Number of different ways of filling the position is
50P16 /(12! *4!)
= 8961115245946500
The number of different ways of filling the position is, 8961115245946500
There are total of 4 positions can be arranged in 4! Ways
Similarly there are 12 positions.
Therefore, the number of arrangements for these 12 positions is 12!
When we use the permutation?If there is an arrangement of the data then we use the permutation
Therefore we can say that there are 12+4 = 16 positions in which 50 people needs to be arranged.
The number of different ways of filling the position is,
[tex]50P16 /(12! *4!)[/tex]
By using the calculater you can find,
= 8961115245946500
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Please help, will mark ya if right
Answer:
It's A I think. I did the math on math.way and it was differeten the the answers you have.
Step-by-step explanation:
» 40 students were asked their favourite
shoe colour.
What percentage chose white?
Answer: 40% i think
Step-by-step explanation:
helpppp plsssss(I’ll give 80 pointssss
Answer:
-4 + -6 = -10
Step-by-step explanation:
From the line at negative 4 it goes to negative 10 you need to add six to four to make ten. Though since it is negative numbers we add a negative 6
The area of the carpet is 48x^2y+16xy^2, if the width is 8xy inches, what is the length of the carpet?
Answer:
Step-by-step explanation:
(48x^2)(y) + (16x)(y^2).
This is addition, so the distributive property applies. [(48x^2)(y) + (16x)(y^2)]/8xy = (48x^2)(y)/8xy+(16x)(y^2)/8xy = 6x+2y.
Division rules are explained below.
I included the parentheses to emphasize the difference between x^2y, which means x to the 2y, and (x^2)(y), which is x^2 times y.
48/8 = 6x^2 times y divided by 8xy equals x because x^2/x = x^(2-1), because x=x^1, and so, equals x; The same y^2/y. The other 2 y's and 2 x's cancel.
TELL ME IF THIS IS CONFUSING<,BECAUSE I DON'T THINK I EXPLAINED VERY WELL.
Find a*b. a = (4, 1, 1/5), b = (6,-4, -15)
The calculated product of the vectors a and b is 17
How to calculate the product of the vectorsFrom the question, we have the following parameters that can be used in our computation:
a = (4, 1, 1/5) and b = (6,-4, -15)
The product of the vectors can be calculated using
a * b = Sum of products of each position
Using the above as a guide, we have the following:
a * b = 4 * 6 + 1 * -4 + 1/5 * -15
Evaluate the expression
a * b = 17
Hence, the product of the vectors a and b is 17
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Find y.
30
20
Need help asap
Answer:
y = 10
Step-by-step explanation:
Using the sine ratio in the right triangle and the exact value
sin30° = [tex]\frac{1}{2}[/tex] , then
sin30° = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{y}{20}[/tex] = [tex]\frac{1}{2}[/tex] ( cross- multiply )
2y = 20 ( divide both sides by 2 )
y = 10
Please help!
Which equation represents the relationship shown in the table?
Answer:
[tex]g \: y = 2x - 3 \\ [/tex]
if you insert x and y values in equation you can find the exact equation
$35 sweater ; 18% discount ; 3% tax ; find sales price
Answer: $27.65
Step-by-step explanation:
0.18 = 6.3
Discount = $6.3
0.03 = 1.05
Tax = 1.05
35 - 6.3 - 1.05 = 27.65
The graph of the function is shown below
Which of the following functions best represents the graph ?
A) y= 0.5(2.5)^x
B) y= 3.5x^2 + 0.5
C) y= 0.5(6)^x
D) y= 0.5x+2.5
Answer:
B) y=3.5x^2 +0.5
Step-by-step explanation:
the (0,0.5) tells you what the y-intercept is :)
hope this helps :)
Mrs. Bruce wants to put in a swimming pool with a deck around the perimeter of the pool. The pool will be rectangular shaped and will have dimensions of 12 feet by 20 feet. The deck around the perimeter will be uniformed in width and have a total area of 68 square feet. Find the width of the deck.
Hint: Draw and accurately label a sketch of the deck and pool in the space below.
Answer:
I think! 3.5 feet wide
Step-by-step explanation:
the area of the pool is 240 square feet. divide by 68 square feet gives you 3.539= 3.5 feet wide. dont shoot me if I'm wrong lol
The width of the deck is approximately 2.65 feet.
To solve the problem, we need to first find the total area of the pool and deck combined, and then subtract the area of the pool to find the area of the deck.
The total area of the pool and deck can be represented as follows:
(12 + 2x) x (20 + 2x)
where x is the width of the deck.
The area of the pool is:
12 x 20 = 240
So, the area of the deck can be found by subtracting the area of the pool from the total area:
(12 + 2x) x (20 + 2x) - 240 = 68
Expanding the left side and simplifying, we get:
4x²+ 64x - 208 = 0
Dividing both sides by 4, we get:
x²+ 16x - 52 = 0
Using the quadratic formula, we get:
x = (-b ± √(b² - 4ac)) / 2a
Where a = 1, b = 16, and c = -52.
Plugging in these values, we get:
x = (-16 ± √(16² - 4(1)(-52))) / 2(1)
x = (-16 ± √(960)) / 2
x = (-16 ± 4√(15)) / 2
x = -8 ± 2√(15)
Since the width of the deck cannot be negative, we can discard the negative solution, and we are left with:
x = -8 + 2√(15)
So, the width of the deck is approximately 2.65 feet.
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Alex and Jack work for a computer software company. Alex can write a computer program in 24 hours, while
Jack can write it in 16 hours. How long will it take them to write the program together?
Alex and Jack work for a computer software company. Alex can write a computer program in 24 hours, while
Jack can write it in 16 hours. How long will it take them to write the program together?
Answer: 9.6 hours