Create a tree diagram for flipping an unfair coin two times. The probability of H is 2/3 and probability of T is 1/3. Write the probabilities on each branch.

If two adjacent sides of parallelogram are 20 cm and 27 cm and the shorter diagonal is 23 cm then the measure of larger angles in the parallelogram is 123.75°.

Given Two adjacent sides are 20 cm and 27 cm. The shorter diagonal is 23 cm. and we need to find the measure of larger angle.

From law of cosines

[tex]c^{2} =a^{2} +b^{2} -2abcos d[/tex]

where c is the opposite side of angle, a and b are other sides and d is the angle.

[tex]23^{2} =20^{2} +27^{2} -2*20*27cos d[/tex]

where 23 is the length of shorter diagonal

529=400+729 - 1080 cos d

1080 cos d=600

cos d=600/1080

cos d=0.55

d=[tex]cos^{-}[/tex]0.55

d=56.25°

Adjacent angle=180-56.25

=123.75°

Largest angle=123.75°.

Hence the larger angle of parallelogram having sides 20 and 27cm is 123.75°.

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Since the histogram is not symmetric, the grades shown in the math class below are not normally distributed.

A histogram represents a normal distribution if it symmetric.

In this problem, we have that:

Since the percentages at the tails are different, the histogram is not symmetric, and  the grades shown in the math class below are not normally distributed.

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The triangle pairs that can be mapped to each other using a reflection and a translation is; Option B

Let us analyze each of the graphs;

Option A; This graph didn't use a reflection and a translation because we see that there was first a reflection across side QR and then another reflection across side AR.

Option B; This graph is correct as it made use of a reflection and a translation as seen in the attached graph.

Option C; This didn't use of a reflection and a translation because it instead carried out translation both in vertical and horizontal direction.

Option D; This carried out Translation and Rotation.

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The restriction of the expression as given in the task content is; x +y = 0.

The expression in the task content is rational;

(1-x-y)/(x+y).

On this note, the restriction to the expression is the values which render the denominator of the expression equal to 0 and consequently the expression value to undefined.

Hence, the restriction is; x+y = 0.

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The weighted average unit cost after the October 22 purchase is $13.70.

The weighted average unit cost determines the weighted average cost of all the purchased inventory.

[(300 x 12) + (390 x 15) ] / (300 + 390)

(3600 + 5850) / 690 = $13.70

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The value of g⁻¹(5) = 0, h⁻¹(x) = (x+10)/3, and the value of h(h⁻¹(5)) = 5 if  g = {(-4, 1), (0, 5), (5, -3), (8, -8)} and h(x) = 3x - 10

It is defined as a special type of relationship, and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.

We have:

g = {(-4, 1), (0, 5), (5, -3), (8, -8)}

As we know,

If f(x) has an ordered pair (x, y) then its inverse of a function has (y, x).

g⁻¹ = {(1, -4), (5, 0), (-3, 5), (-8, 8)}

g⁻¹(5) = 0

h(x) = 3x - 10

h⁻¹(x) = (x+10)/3

h⁻¹(5) = 15/3 = 5

h(h⁻¹(5)) = 3(5) - 10

h(h⁻¹(5)) = 5

Thus, the value of g⁻¹(5) = 0, h⁻¹(x) = (x+10)/3, and the value of h(h⁻¹(5)) = 5 if  g = {(-4, 1), (0, 5), (5, -3), (8, -8)} and h(x) = 3x - 10

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Two quantities are in the golden ratio if their ratio is the same as the ratio of their sum to the larger of the two quantities.

It should be noted that the Golden ratio is also called the golden mean or divine proportion.

The Golden ratio is refered to as the. most beautiful number in the universe.

It is extraordinary because it can be visualized everywhere from geometry to the human body.

In this case, quantities are in the golden ratio if their ratio is the same as the ratio of their sum to the larger of the two quantities.

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Answer: 154 m^3

Step-by-step explanation:

Volume = (5*2*7) + (3*7*4)

             = 70 + 84

             = 154 m^3

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Answer:

154 m^3

Step-by-step explanation:

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To collect data from a number of people in a sample, use a questionnaire

Questionnaires are quantitative method used in research for information collection purpose.

This questionnaires consists of several question necessary to provide answers and solution to research questions and for the purpose of analysis. These questions can be open or closed ended questions depending on the nature of research.

Hence we can conclude that. to collect data from a number of people in a sample, use a questionnaire

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The length and width of the rectangle is 15cm and 31cm respectively

The formula for calculating the perimeter of a rectangle is expressed as:

P = 2(L + W)

where

L is the length

W is the width

If its length is 1 cm more than twice its width, then;

L = 2W + 1

Substitute

92 = 2(2W + 1 + W)

46 = 3W + 1

3W = 45

W = 15cm

Determine the length

L = 2(15) + 1

L = 31cm

Hence the length and width of the rectangle is 15cm and 31cm respectively

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Answer:

it mean that the patient get 7mg drug in1 hour and infour hours he get 4×7= 28mg drug

The values of p and q in the function f(x) = 2x³ + 17x² - 3px - 5q is p = 8, q = 27

An equation is an expression that shows the relationship between two or more variables and numbers.

x - 3 (i.e. x = 3) and x + 9 (i.e. x = -9) are factors of f(x) = 2x³ + 17x² - 3px - 5q

Hence:

f(3) = 0

2(3)³ + 17(3)² - 3p(3) - 5q = 0  (1)

Also:

2(-9)³ + 17(-9)² - 3p(-9) - 5q = 0  (2)

Hence, p = 8, q = 27

The values of p and q in the function f(x) = 2x³ + 17x² - 3px - 5q is p = 8, q = 27

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The product of 3x² and 2x³y + 5xy⁴ is given by the expression 6x⁵y + 15x³y⁴

An equation is an expression that shows the relationship between two or more variables and numbers.

The product of 3x² and 2x³y + 5xy⁴ is:

= 3x² * (2x³y + 5xy⁴)

= 6x⁵y + 15x³y⁴

The product of 3x² and 2x³y + 5xy⁴ is given by the expression 6x⁵y + 15x³y⁴

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The exponential function which passes through (0,-2),(1,0),(2,2) (5,3) is negative on the interval (-∞,1) and positive on  the interval (1,∞).

Given Function f is negative on the interval (-∞,1) and positive on the interval (1,∞)

We have to find the statement for which the exponential function' s values are given.

First option is having the statement which says that exponential

function passes through points (0,-6)(0.5,-2),(1,0),(2,2) (5,3). These points are showing the domain and value of the function which is codomain.

for x=0 it has -6,

for x=1 it has 0,

for x=2 it has 2,

for x=5 it has 3.

for x=0.5 it has -2

The description says that value of function is negative in interval (-∞,1) and positive in (1,∞) which is true for option A as it has negative values of -2 for x=0 and for x=2,5 it has value of 2 and 3.

Hence the function f is an exponential function passes through  (0, minus 6), (0.5, minus 2), (1, 0), (2, 2), (5, 3).

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Recall that for all t,

cos²(t) + sin²(t) = 1

Now,

x = 5 cos(t) - 7   ⇒   (x + 7)/5 = cos(t)

y = 5 sin(t) + 9   ⇒   (y - 9)/5 = sin(t)

so that substituting into the identity above, we get

((x + 7)/5)² + ((y - 9)/5)² = 1

which we can rewrite as

(x + 7)²/25 + (y - 9)²/25 = 1

(x + 7)² + (y - 9)² = 25

and this is the equation of a circle centered at (-7, 9) with radius 5.

Step-by-step explanation:

Using the various theorems relating inscribed and external angles to intercepted arcs, we can write the following relations:

  angle A = 1/2(arc BP) . . . . . . . . . . . inscribed angle

  angle A = 1/2(arc CD -arc CP) . . . external angle at tangent/secant

  angle CPD = 1/2(arc CD) . . . . . . . inscribed angle

  angle CPB = 1/2(arc CP) + 1/2(arc BP) . . . . . sum of angles at the mutual tangent

Equating the expressions for angle A, we have ...

  1/2(arc BP) = 1/2(arc CD -arc CP)

Adding arc CP gives ...

  1/2(arc BP +arc CP) = 1/2(arc CD)

Substituting the last two equations for angles from above, this gives ...

  angle CPB = angle CPD

Hence PC bisects angle BPD.

Answer:

$ 1021.25

Step-by-step explanation:

FV = P ( 1 + .085 * 3/12)  = 1021.25

                      3/12 = 3 months out of a year

                       .085 = decimal interest       P = 1000

Answer:

[tex]A[/tex]

Step-by-step explanation:

Indeed, the graph of [tex]f(x)[/tex] underwent only one change:

[tex]f(x) = x^3 \Leftrightarrow g(x) = f(x) - 1 = x^3 - 1[/tex].

Take a look at the attachments in order to follow the process.

Answer:

y=2x+3 and y=-2x-3

Step-by-step explanation:

First situation:

2x-y=3

making y subject

y=2x+3

Second situation:

2x+y=-3

making y subject

y=-2x-3

Answer:

5

Step-by-step explanation:

f(x) = a(x-3)² - 2

When x = 4, y = 3, so:

3 = a(4-3)² - 2

5 = a

A 99% confidence interval for the population proportion is; CI = (0.164, 0.194)

We are given;

Sample size; n = 4096

Number that opposed transgender students; x = 733

Thus;

Proportion; p^ = x/n = 733/4096 = 0.179

Formula for confidence interval of proportions is;

CI = p^ ± z√[p^(1 - p^)/n]

The z-value for confidence level of 99% is z = 2.576

Thus;

CI = 0.179 ± 2.576√[0.179(1 - 0.179)/4096]

CI = 0.179 ± 0.015

CI = (0.164, 0.194)

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The simplified form of the difference quotient of equation [tex]9x^2+5x-1[/tex] . in the form 9x + 9h + 5.

In question for equation [tex]9x^2+5x-1[/tex], simplified to difference quotient in the form of Ax+Bh+C where A, B, C are integers

equation is the relationship between variable and represented as  [tex]9x^2+5x-1[/tex]  is example of polynomial equation.

We know that,
for difference quotient
[tex]=\frac{f(x+h)-f(x)}{h} \\\frac{9(x+h)^2+5(x+h)-1-9x^2-5x+1}{h}\\\frac{9h^2+9hx+5h}{h}\\9x+9h+5[/tex]
While, compared with Ax+Bh+C
we have A=9, B=9, C=5.

Thus, The required value of difference Quotient in the form Ax+Bh+c where A, B and C is 9, 9 and 5 respectively

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Answer:

145 m/s

Step-by-step explanation:

v = u + 2at

v = 19 + 2(3)(21)

v = 19 + 126

v = 145

answer

V=145

Step-by-step explanation:

V=U+2at

v=19+2×3×21

v=19+126

v=145

Answer:

-26730

Explanation:

To find the coefficient of [tex]x^7[/tex] in the expansion of [tex](3 -x)^{11}[/tex]

Use Binomial Expansion:

[tex](x+y)^n = \ ^n C_0 x^n + \ ^n C_1 x^{n-1} y + \ ^n C_2 x^{n-2}y^2 + ...+ \ ^n C_n y^n[/tex]

In this expansion,

[tex](3-x)^{11}[/tex]

The coefficient of [tex]x^7[/tex]

[tex]= 11C_{7} (3)^{11-7} (-x)^7[/tex]

[tex]= (330) (81) (-x^7)[/tex]

[tex]= -26730x^7[/tex]

Answer:

D) 62.5 pounds.

Step-by-step explanation:

The volume of the swimming pool = [tex]3\times50\times25 =3750[/tex]

[tex]3750\div15 = 250[/tex] lots of 15

[tex]250\times0.25=62.5[/tex] pounds of chlorine.

Hope this helps, have a nice day!

Answer:

trust me its c i did the test on edge for me

Step-by-step explanation:

i did the test on edge

Answer:

$63.83

Step-by-step explanation:

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