Could someone quickly sum up how to calculate probability? I’m taking a course on it and don’t understand.

The reflection of segment AB over the line x = 1, will be the line segment EF. Then the correct option is B.

A spatial transformation is each mapping of feature shapes to itself, and it maintains some spatial correlation between figures.

Reflection does not change the size and shape of the geometry.

The line segment AB is given.

Then the reflection of segment AB over the line x = 1, will be the line segment EF.

Then the correct option is B.

The missing diagram is given below.

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Answer:

Step-by-step explanation:

Reflecting a Line Segment Across the X-axis or Y-axis

Step 1: Identify the endpoints of the line segment.

Step 2: Reflect the endpoints of the line segment.

Step 3: Connect the reflected endpoints in a straight line to form the reflected line segment.

A reflection across line moves each point to such that line is the perpendicular bisector of the segment connecting

The graph which represents the solution to the compound inequality is; -2 ≤ x < 5.

The inequalities given in the task content can be solved as follows;

For –2x + 4 ≤ 8

-2x ≤ 8 -4

x >= -2

For –2x + 4 > –6

–2x > –6 -4

x < 5

Hence, the graph which represents the solution to the compound inequality is; -2 ≤ x < 5.

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Answer:

there is no ans that is the ans

Answer:

x³ + y³ + z³ = [ (x +y +z)(x² + y² + z² -xy - yz - xz) ] + 3xyz

Step-by-step explanation:

x³ + y³ + z³ = [ (x +y +z)(x² + y² + z² -xy - yz - xz) ] + 3xyz

Answer:

80

Step-by-step explanation:

mean = 140+20=160

160/2

= 80

Answer: 160

Step-by-step explanation:

Just took it

Using the Poisson distribution, it is found that there is a 0.507 = 50.7% probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours.

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

The parameters are:

Considering the average of 15 birds every 2 hours during daylight hours, the mean for a 45-minute period is given by:

[tex]\mu = 15 \times \frac{45}{120} = 5.625[/tex]

The probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours is given by:

[tex]P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5)[/tex]

In which:

[tex]P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}[/tex]

[tex]P(X = 0) = \frac{e^{-5.625}(5.625)^{0}}{(0)!} = 0.004[/tex]

[tex]P(X = 1) = \frac{e^{-5.625}(5.625)^{1}}{(1)!} = 0.02[/tex]

[tex]P(X = 2) = \frac{e^{-5.625}(5.625)^{2}}{(2)!} = 0.057[/tex]

[tex]P(X = 3) = \frac{e^{-5.625}(5.625)^{3}}{(3)!} = 0.107[/tex]

[tex]P(X = 4) = \frac{e^{-5.625}(5.625)^{4}}{(4)!} = 0.150[/tex]

[tex]P(X = 5) = \frac{e^{-5.625}(5.625)^{5}}{(5)!} = 0.169[/tex]

Then:

[tex]P(X \leq 5) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) = 0.004 + 0.02 + 0.057 + 0.107 + 0.15 + 0.169 = 0.507[/tex]

0.507 = 50.7% probability that the bird feeder will be visited by at most 5 birds in a 45 minute period during daylight hours.

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Step-by-step explanation:

[tex]f(x) = {x}^{4} + 4 {x}^{3} - 2 {x}^{2} + 11x - 6[/tex]

[tex]f(3) = {3}^{4} + 4. {3}^{3} - 2. {3}^{2} + 11.3 - 6[/tex]

[tex]f(3) = 81 + 4.27 - 2.9 + 33 - 6[/tex]

[tex]f(3) = 81 + 108 - 18 + 33 - 6[/tex]

[tex]f(3) = 198[/tex]

Answer:

Step-by-step explanation:

x4 + 4x3 - 2x2 + 11x - 6 for x = 3

3^4 + 4 * 3^3 - 2 * 3^2 + 11 * 3 - 6 =

81 + 4 * 27 - 2 * 9 + 11 * 3 - 6 =

81 + 108 - 18 + 33 - 6 =

198

Answer:

The correct answer would be B) 2

Answer:

C 1/2

Step-by-step explanation:

Since the angels of these triangles are same,they are totally similar.

The ratios of their sides are

10/20=1/2

8/16=1/2

6/12=1/2

So, The scale factor is 1/2.

Answer:

the widths of the wire :)

Step-by-step explanation:

Parallel lines are lines in a plane that are always the same distance apart.

☆...hope this helps...☆

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Lines with the same slope that never touch each other.

Parallel lines share the same slope (direction). Attached is an example of two lines parallel to each other, [tex]y=2x-1[/tex] in red and [tex]y=2x+1[/tex] in green. They both have a slope of [tex]2[/tex], which is what makes them parallel.

The gradient of the given graph is 1.5

From the question, we are to determine the gradient of the graph

Gradient is given by the formula

[tex]m = \frac{y_{2}-y_{1} }{x_{2}-x_{1} }[/tex]

Where m is the gradient

Picking the points (-2, -2) and (2, 4) on the line

Then,

x₁ = -2

y₁ = -2

x₂ = 2

y₂ = 4

Putting the parameters into the equation, we get

[tex]m = \frac{4--2}{2--2}[/tex]

[tex]m = \frac{4+2}{2+2}[/tex]

[tex]m = \frac{6}{4}[/tex]

m = 1.5

Hence, the gradient of the given graph is 1.5

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Answer:

[tex]a_n = 5 + (n-1)(-4)[/tex]

Step-by-step explanation:

So the explicit formula is generally defined as [tex]a_n = a_1 + d(n-1)[/tex]. where d is essentially the "slope", basically how much it's changing from term to term. anyways if you look at the recursive formula you'll notice it's taking the previous term and subtracting 4. This is what d is going to be, -4 and since a_1 is given you plug that in as well. This gives you the equation

[tex]a_n = 5 -4(n-1)[/tex] which can also be written as [tex]a_n = 5 + (n-1)(-4)[/tex]

Answer:Empirical probabilities.
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Answer:

[tex]\boxed{Circuit_{\Delta ABC} = 15~cm }[/tex]

Step-by-step explanation:

The ABC triangle is an equilateral triangle.

[tex]\mid AB\mid = \mid BC\mid = \mid AC\mid[/tex]

The drawing in the attachment.

I am entering meaningfully:

a - side length of an equilateral triangle

[tex]a=\mid AB\mid = \mid BC\mid = \mid AC\mid[/tex]

[tex]P_{\Delta} =\dfrac{a^{2} \sqrt{3} }{4}[/tex]  -   equilateral triangle area formula

[tex]P_{\Delta} =\dfrac{25 \sqrt{3} }{4}~~\land~~P_{\Delta} =\dfrac{a^{2} \sqrt{3} }{4}~~\Rightarrow~~\dfrac{a^{2} \sqrt{3} }{4}=\dfrac{25 \sqrt{3} }{4}\\\\\\\dfrac{a^{2} \sqrt{3} }{4}=\dfrac{25 \sqrt{3} }{4}~~\mid~~\div ~~\dfrac{\sqrt{3} }{4} \\\\\\\dfrac{a^{2} \sqrt{3} }{4}\cdot \dfrac{4}{\sqrt{3} } =\dfrac{25 \sqrt{3} }{4}\cdot \dfrac{4}{\sqrt{3} } \\\\a^{2} =25~~\\\\a^{2} =5^{2} ~~\land~~a > 0~~\Rightarrow~~\boxed{a=5~cm}\\\\\\[/tex]

[tex]Circuit_{\Delta ABC} =a+a+a\\\\Circuit_{\Delta ABC} =3a~~\land~~a=5~cm\\\\\boxed{Circuit_{\Delta ABC} =3\cdot 5 = 15~cm }[/tex]

There is no solution for the equation | 3x+7|-5.

When asked to explain why there is no solution to |3x+7|-5 Jack said, "It is not a solution because the 5 is negative." Jack is on the right track but his reasoning is incomplete

equation are format of a link which process over mathematical operators like addition, subtraction etc.

| 3x+7|-5 has no solution because the data is incomplete. Without know there limits or equal to zero, less than zero or greater than zero this system of equation cannot be defined. That is why there is no solution for | 3x+7|-5.

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Answer:

9cm

Step-by-step explanation:

The CIRCUMFERENCE OF A CIRCLE is the distance round the circle.

It has the formular 2πr.

were r = radius

C = 2πr

72 = 2 × 3.142 × r

72 = 6.284r

dividing bothsides by 6.284

r = 72/ 6.284

r = 11.457

AB is an arc.

Lenght of an arc

[tex] \frac{ \alpha }{360} \times 2\pi \: r \\ \\ \frac{45}{360} \times 2 \times 3.142 \times 11.457 \\ \\ \frac{45}{360} \times 71.995 \\ \\ = 8.999 \\ \\ = 9cm[/tex]

1+3-2+0=2

-3-2+1+2=-2

Answer:

d.-½ ,represent change of y with respect to x

Step-by-step explanation:

The values of y with respect to x are :-

Thus, -½ in the value of the change in y with respect to x.

Answer:

3 < QS < 13.

I just did it on edge

The Triangle inequality theorem of a triangle says that the sum of any of the two sides of a triangle is always greater than the third side. The length of QS can lie between 3 < QS < 13.

The Triangle inequality theorem of a triangle says that the sum of any of the two sides of a triangle is always greater than the third side.

Suppose a, b and c are the three sides of a triangle. Thus according to this theorem,

Here, we have,

As per the given law of triangle inequality, the sum of the two sides of the triangle is greater than the third side.

x + 8 > 5

x > -3

x + 5 > 8

x > 3

8 + 5 > x

13 > x

Hence, In triangle QRS the length of QS can lie between 3 < QS < 13.

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The longest possible altitude of the third altitude (if it is a positive integer) is 83.

According to statement

Let h is the length of third altitude

Let a, b, and c be the sides corresponding to the altitudes of length 12, 14, and h.

From Area of triangle

A = 1/2*B*H

Substitute the values in it

A = 1/2*a*12

a = 2A / 12 -(1)

Then

A = 1/2*b*14

b = 2A / 14 -(2)

Then

A = 1/2*c*h

c = 2A / h -(3)

Now, we will use the triangle inequalities:

2A/12 < 2A/14 + 2A/h

Solve it and get

h<84

2A/14 < 2A/12 + 2A/h

Solve it and get

h > -84

2A/h < 2A/12 + 2A/14

Solve it and get

h > 6.46

From all the three inequalities we get:

6.46<h<84

So, the longest possible altitude of the third altitude (if it is a positive integer) is 83.

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Answer:

the second one I think, as it is clearer and makes more sense

The jump will be from 0 to 0.8, and the other jump from 0.8 to 1.1 in the right direction. Then the correct option is B.

A number line refers to a straight line in mathematics that has numbers arranged at regular intervals or portions along its width. A number line is often shown horizontally and can be postponed in any direction.

The expression is given below.

⇒ 0.8 + 0.3

The sign of both terms are similar that is positive.

If the sign of the number is positive, then we move rightward. Similarly, if the sign of the number is negative, then we move leftward.

First, the jump will be from 0 to 0.8, and the other jump from 0.8 to 1.1 in the right direction. Then the correct option is B.

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The information about the triangle shows that

TRS ≅ △SUT because of SAS, CPCTC.

It should be noted that from the information given, W is the intersection point of line segments TS and RU.

Also, RWS and UWT are equal because they're vertical angles.

Therefore, by AAS, TUW and SRW are equal. Also, TRS ≅ △SUT because of SAS, CPCTC.

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Answer: SAS and CPCTC

Step-by-step explanation:

Because of SAS, △TRS ≅ △SUT, and because of CPCTC, ∠RST ≅ ∠UTS.

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If you are working on Edge the answer is correct. The proof is down below. I hope someone finds this helpful.

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The sample size which will produce sample proportion of 0.3 and 95% confidence interval is 36.

Given sample proportion of 0.3, confidence level 95%.

A confidence interval of proportions is given by:

π±z[tex]\sqrt{}[/tex]π(1-π)/n

In which :

π is the sample proportion,

z is the critical value

n is the sample size.

Margin of error=z[tex]\sqrt{}[/tex]π(1-π)/n

z value for confidence level of 95% is 1.96

Margin of error=1.96[tex]\sqrt{0.3*0.7/n}[/tex]

The widest interval has the highest margin of error, since the margin of error and since the margin of error is inversely proportional to the sample size , a lower sample size generates a higher margin of error.

Hence sample size which is correct is 36.

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Question is incomplete as it also includes options like:

a)46

b)68

c)56

d)36.  

Answer:

24p^2q^2 - 42pq + 15

Step-by-step explanation:

Answer:

Hence the expression [tex]$$(6pq-3)(4pq-5)=24p^2q^2-42pq+15$$[/tex]

Step-by-step explanation:

Explanation

[tex]$$\begin{matrix}{} & {} & {} & {} & 6pq & - & 3 \\ \times & {} & {} & {} & 4pq & - & 5 \\ \end{matrix}$$[/tex]

_________________

[tex]$$\begin{matrix}{} & {} & {} & - & 30pq & + & 15 \\ {} & {} & 24{{p}^2}{{q}^2} & - & 12pq & {} & {} \\ \end{matrix}$$[/tex]

___________________

[tex]$$\begin{matrix}{} & {} & 24{{p}^2}{{q}^2} & - & 42pq & + & 15 \\ \end{matrix}$$[/tex]

The number of possible passwords is 26^4 * 10^4.

We will make 4 picks from each category (letters and numbers).

We can duplicate them (i.e., pick each character more than once.)

so, for your 4 picks from the letters, you'll have

26 * 26 * 26 * 26 = 26^4 possible selections.

For each of these, you'll have 4 picks from the digits. Similar reasoning, this works out to

10^4 combinations of digits.

This means you'll have 26^4 * 10^4

Possible combinations of 4 letters and 4 digits, and, for each of these, you now need to work out how many unique ways to arrange them.

We will have 8 possible choices for the 1st character, 7 for the second, 6 for the third, etc. This works out to 8!

different orderings for each of your

26^4 * 10^4

The number of possible passwords is 26^4 * 10^4.

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Considering the problem described, we have that:

a) The normal distribution can be used, as both [tex]np \geq 10[/tex] and [tex]n(1-p) \geq 10[/tex].

b) There is a 0.0132 = 1.32% probability that proportion in the random sample of 200 orders is the same as the proportion found in the audit sample or less.

The z-score of a measure X of a normally distributed variable with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex] is given by:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

The parameters of the binomial distribution are:

n = 2000, p = 0.92.

Hence:

Since both [tex]np \geq 10, n(1 - p) \geq 10[/tex], a normal approximation can be used. The mean and the standard deviation of the approximation are given as follows:

The probability that proportion in the random sample of 200 orders is the same as the proportion found in the audit sample or less, using continuity correction, is P(X < 175.5), which is the p-value of Z when X = 175.5, hence:

[tex]Z = \frac{X - \mu}{\sigma}[/tex]

[tex]Z = \frac{175.5 - 184}{3.8367}[/tex]

Z = -2.22.

Z = -2.22 has a p-value of 0.0132.

0.0132 = 1.32% probability that proportion in the random sample of 200 orders is the same as the proportion found in the audit sample or less.

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Answer: 5.22

Step-by-step explanation:

The apothem = 87 cm = 0.87 m.

Using the formula [tex]A=\frac{1}{2}ap[/tex] to find the area of the base, where a is the apothem and p is the perimeter, we get [tex]A=\frac{1}{2}(0.87)(6)=2.61[/tex]

So, using the formula [tex]V=Bh[/tex], we get the volume to be [tex]2.61(2)=5.22 \text{ m}^{3}[/tex]

Answer:

0.3 gallon

Step-by-step explanation:

To do this problem, we must divide the amount of cement by the number of feet to see how much cement he used for each foot.

15/50 = 0.3 gallon

Answer:

0.3 gallons per foot

Step-by-step explanation:

We know that he used 15 gallons of cement for 50 feet.

We want to find the amount per foot or the amount per each 1 foot.

So we have to divide the 15 gallons by the 50 feet.

15 / 50 = 0.3 gallons per foot.

Answer:

55

Step-by-step explanation:

[tex] \frac{n(n + 1)}{2} \\ n = 10 \\ substitutig \\ \frac{10(10 + 1)}{2} \\ \\ \frac{10(11)}{2} \\ \\ \frac{110}{2} = 55 [/tex]

The multiplicative rate of change of the exponential function is 0.5.

In this problem we have three that are part of a exponential function, whose form is shown below:

[tex]y = a\cdot r^{x}[/tex]     (1)

Where:

We notice that for Δx = 1, the value of y is halved. Hence, the multiplicative rate of change of the exponential function is 0.5.

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A circle and a triangle can intersect in a point.

This refers to the fact that two lines are able to meet at a given point. The point where they meet is the point of intersection.

A circle is known to be able to intersect with a triangle in three different ways and at one point.

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Answer:

b) The two triangles are similar by SAS

Step-by-step explanation:

From the diagram below, we can tell that

SAS similarity (Side-Angle-Side similarity) is a criterion used to determine whether two triangles are similar.

It states that if two sides of one triangle are proportional to two sides of another triangle, and the included angles between these sides are congruent, then the two triangles are similar.

In other words, if in two triangles, the ratio of the lengths of corresponding sides is equal, and the included angles between these sides are congruent, then the two triangles are considered similar.

The corresponding angles are congruent and the sides are in proportion

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